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  • Making a query result equal to zero when a condition is null

    - by John
    Hello, I believe the query below should work. However, when I run it, the results are blank. I think this is happening since for now, the table "comment" is empty. So there is no instance where s.submissionid = c.submissionid. I would like to have the query below to work even if there if no s.submissionid that equals a c.submissionid. In this case, I would like countComments to equal zero. How can I do this? Thanks in advance, John $sqlStr = "SELECT s.loginid, s.submissionid s.title, s.url, s.displayurl, l.username, count(c.comment) AS countComments FROM submission AS s, login AS l, comment AS c, WHERE s.loginid = l.loginid AND s.submissionid = c.submissionid GROUP BY s.loginid, s.submissionid s.title, s.url, s.displayurl, l.username ORDER BY s.datesubmitted DESC LIMIT 10"; $result = mysql_query($sqlStr); $arr = array(); echo "<table class=\"samplesrec\">"; while ($row = mysql_fetch_array($result)) { echo '<tr>'; echo '<td class="sitename1"><a href="http://www.'.$row["url"].'">'.$row["title"].'</a></td>'; echo '</tr>'; echo '<tr>'; echo '<td class="sitename2"><a href="http://www...com/sandbox/members/index.php?profile='.$row["username"].'">'.$row["username"].'</a><a href="http://www...com/sandbox/comments/index.php?submission='.$row["title"].'">'.$row["countComments"].'</a></td>'; echo '</tr>'; } echo "</table>";

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  • Numerating Comments

    - by John
    The code below prints out all comments for a given "submissionid" in chronological order. How could I numerate these comments? (In other words, how do I print out a "1." next to the oldest comment, a "2." next to the second-oldest comment, etc.?) $submission = mysql_real_escape_string($_GET['submission']); $submissionid = mysql_real_escape_string($_GET['submissionid']); $sqlStr = "SELECT comment.comment, comment.datecommented, login.username FROM comment LEFT JOIN login ON comment.loginid=login.loginid WHERE submissionid=$submissionid ORDER BY comment.datecommented ASC LIMIT 100"; $result = mysql_query($sqlStr); $arr = array(); echo "<table class=\"commentecho\">"; while ($row = mysql_fetch_array($result)) { echo '<tr>'; echo '<td class="commentname1">'.stripslashes($row["comment"]).'</td>'; echo '</tr>'; echo '<tr>'; echo '<td class="commentname2"><a href="http://www...com/sandbox/members/index.php?profile='.$row["username"].'">'.$row["username"].'</a>'.date('l, F j, Y &\nb\sp &\nb\sp g:i a &\nb\sp &\nb\sp \N\E\W &\nb\sp \Y\O\R\K &\nb\sp \T\I\M\E', strtotime($row["datecommented"])).'</td>'; echo '</tr>'; } echo "</table>"

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  • Django Testing: Faking User Creation

    - by Ygam
    I want to better write this test: def test_profile_created(self): self.client.post(reverse('registration_register'), data={ 'username':'ygam', 'email':'[email protected]', 'password1':'ygam', 'password2':'ygam' }) """ Test if a profile is created on save """ user = User.objects.get(username='ygam') self.assertTrue(UserProfile.objects.filter(user=user).exists()) and I just came upon this code on django-registration tests that does not actually "create" the user: def test_registration_signal(self): def receiver(sender, **kwargs): self.failUnless('user' in kwargs) self.assertEqual(kwargs['user'].username, 'bob') self.failUnless('request' in kwargs) self.failUnless(isinstance(kwargs['request'], WSGIRequest)) received_signals.append(kwargs.get('signal')) received_signals = [] signals.user_registered.connect(receiver, sender=self.backend.__class__) self.backend.register(_mock_request(), username='bob', email='[email protected]', password1='secret') self.assertEqual(len(received_signals), 1) self.assertEqual(received_signals, [signals.user_registered]) However he used a custom function for this "_mock_request": class _MockRequestClient(Client): def request(self, **request): environ = { 'HTTP_COOKIE': self.cookies, 'PATH_INFO': '/', 'QUERY_STRING': '', 'REMOTE_ADDR': '127.0.0.1', 'REQUEST_METHOD': 'GET', 'SCRIPT_NAME': '', 'SERVER_NAME': 'testserver', 'SERVER_PORT': '80', 'SERVER_PROTOCOL': 'HTTP/1.1', 'wsgi.version': (1,0), 'wsgi.url_scheme': 'http', 'wsgi.errors': self.errors, 'wsgi.multiprocess':True, 'wsgi.multithread': False, 'wsgi.run_once': False, 'wsgi.input': None, } environ.update(self.defaults) environ.update(request) request = WSGIRequest(environ) # We have to manually add a session since we'll be bypassing # the middleware chain. session_middleware = SessionMiddleware() session_middleware.process_request(request) return request def _mock_request(): return _MockRequestClient().request() However, it may be too long of a function for my needs. I want to be able to somehow "fake" the account creation. I have not much experience on mocks and stubs so any help would do. Thanks!

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  • Parse Facebook API data using loop for getting fan page ID#s?

    - by Brandon Lee
    I've been learning how to parse json data returned from the facebook-api. I've figured out how to fetch fan pages from a specific profile id and want to parse them using a loop! Heres the code and example I have below: This is the data I get back from the facebook-api Array ( [0] => Array ( [page_id] => XXXXXX60828 ) [1] => Array ( [page_id] => XXXXXX0750 ) [2] => Array ( [page_id] => XXXXXX91225 ) [3] => Array ( [page_id] => XXXXXX1960343 ) [4] => Array ( [page_id] => XXXXXX60863 ) [5] => Array ( [page_id] => XXXXXX8582 ) ) I need to be able to put this data in a loop and extract the page_id#s out... still getting familiar with json and am having issues figuring this out? How can I get this in a loop using for each and strip out the page id#s?

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  • Django Image Upload: IOErrno2 Could not find path -- and yet it's saving the image there anyway?

    - by Rob
    I have an issue where the local version of django is handling image upload as expected but my server is not. Note: I am using a Django Container on MediaTemple.net (grid server) Here is my code. def view_settings(request): <snip> if request.POST: success_msgs = () mForm = MainProfileForm(request.POST, request.FILES, instance = mProfile) pForm = ChangePasswordForm(request.POST) eForm = ChangeEmailForm(request.POST) if mForm.is_valid(): m = mForm.save(commit = False) if mForm.cleaned_data['avatar']: m.avatar = upload_photo(request.FILES['avatar'], settings.AVATAR_SAVE_LOCATION) m.save() success_msgs += ('profile pictured updated',) <snip> def upload_photo(data,saveLocation): savePath = os.path.join(settings.MEDIA_ROOT, saveLocation, data.name) destination = open(savePath, 'wb+') for chunk in data.chunks(): destination.write(chunk) destination.close() return os.path.join(saveLocation, data.name) Here's where it gets whacky and I was hoping someone could shed a light on this error, because either a) it's the wrong error code, or b) something is happening with the file before it's completely handled. To recap, the file was actually uploaded to the server in the intended directory - and yet this err msg continues to persist. IOError at /user/settings [Errno 2] No such file or directory: u'/home/user66666/domains/example.com/html/media/images/avatars/DSC03852.JPG' Environment: Request Method: POST Request URL: http://111.111.111.111:2011/user/settings Django Version: 1.0.2 final Python Version: 2.4.4 Installed Applications: ['django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.sites', 'ctrlme', 'usertools', 'easy_thumbnails'] Installed Middleware: ('django.middleware.common.CommonMiddleware', 'django.contrib.sessions.middleware.SessionMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware') Traceback: File "/home/user6666/containers/django/leonidas/usertools/views.py" in view_settings m.avatar = upload_photo(request.FILES['avatar'], settings.AVATAR_SAVE_LOCATION) File "/home/user666666/containers/django/leonidas/usertools/functions.py" in upload_photo destination = open(savePath, 'wb+')

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  • register device at run time

    - by user177893
    In the App ID section of the Program Portal, locate the App ID you wish to use with the Apple Push Notification service. Only App IDs with a specific bundle ID can be used with the APNs. You cannot use a “wild-card” application ID. You must see “Available” under the Apple Push Notification service column to register this App ID and configure a certificate for this App ID. Click the ‘Configure’ link next to your desired App ID. In the Configure App ID page, check the Enable Push Notification Services box and click the Configure button. Clicking this button launches the APNs Assistant, which guides you through the next series of steps that create your App ID specific Client SSL certificate. Download the Client SSL certificate file to your download location. Navigate to that location and double-click the certificate file (which has an extension of cer) to install it in your keychain. When you are finished, click Done in the APNS Assistant. Double-clicking the file launches Keychain Access. Make sure you install the certificate in your login keychain on the computer you are using for provider development. The APNs SSL certificate should be installed on your notification server. When you finish these steps you are returned to the Configure App ID page of the iPhone Dev Center portal. The certificate should be badged with a green circle and the label “Enabled”. To complete the APNs set-up process, you will need to create a new provisioning profile containing your APNs-enabled App ID. IS it posssible to do theses steps through code.

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  • How do I get Ctrl-Backspace to delete a word in vim within gnome-terminal?

    - by Michael Gundlach
    I'd like Ctrl-Backspace to delete the current word in vim insert mode. From within xterm I can pull this off via :inoremap <C-H> <C-W> but in gnome-terminal I cannot figure out a way to make it happen. When in vim insert mode, if I type control-v and then press backspace, I get ^H in xterm, and ^? in gnome-terminal. Unfortunately, :inoremap <C-?> <C-W> doesn't do the trick in gnome-terminal; control-backspace just erases a single character no matter what. Regarding ASCII codes: Gnome-terminal lets you change the backspace character under Edit - Profile Preferences - Compatibility. Unfortunately, no option works, as far as I can tell: whatever character I apply to Backspace via the settings, if I try mapping the character itself, like :inoremap <C-H> <C-W> then regular backspace and control-backspace both erase an entire word; and if I try mapping control plus that character, like :inoremap <C-^H> <C-W> then regular backspace and control-backspace just erase a single character.

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  • Django - how to write users and profiles handling in best way?

    - by SpankMe
    Hey, I am writing simple site that requires users and profiles to be handled. The first initial thought is to use django's build in user handling, but then the user model is too narrow and does not contain fields that I need. The documentation mentions user profiles, but user profiles section has been removed from djangobook covering django 1.0 (ideally, the solution should work with django 1.2), and the Internet is full of different solutions, not making the choice easier (like user model inheritance, user profiles and django signals, and so on). I would like to know, how to write this in good, modern, fast and secure way. Should I try to extend django builtin user model, or maybe should I create my own user model wide enough to keep all the information I need? Below you may find some specifications and expectations from the working solution: users should be able to register and authenticate every user should have profile (or model with all required fields) users dont need django builtin admin panel, but they need to edit their profiles/models via simple web form Please, let me know how do you solve those issues in your applications, and what is the best current way to handle users with django. Any links to articles/blogs or code examples are highly appreciated!

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  • Join Query Not Working

    - by John
    Hello, I am using three MySQl tables: comment commentid loginid submissionid comment datecommented login loginid username password email actcode disabled activated created points submission submissionid loginid title url displayurl datesubmitted In these three tables, the "loginid" correspond. I would like to pull the top 10 loginids based on the number of "submissionid"s. I would like to display them in a 3-column HTML table that shows the "username" in the first column, the number of "submissionid"s in the second column, and the number of "commentid"s in the third column. I tried using the query below but it did not work. Any idea why not? Thanks in advance, John $sqlStr = "SELECT l.username ,l.loginid ,c.commentid ,count(s.commentid) countComments ,c.comment ,c.datecommented ,s.submissionid ,count(s.submissionid) countSubmissions ,s.title ,s.url ,s.displayurl ,s.datesubmitted FROM comment AS c INNER JOIN login AS l ON c.loginid = l.loginid INNER JOIN submission AS s ON c.loginid = s.loginid GROUP BY c.loginid ORDER BY countSubmissions DESC LIMIT 10"; $result = mysql_query($sqlStr); $arr = array(); echo "<table class=\"samplesrec1\">"; while ($row = mysql_fetch_array($result)) { echo '<tr>'; echo '<td class="sitename1"><a href="http://www...com/.../members/index.php?profile='.$row["username"].'">'.stripslashes($row["username"]).'</a></td>'; echo '</tr>'; echo '<td class="sitename1">'.stripslashes($row["countSubmissions"]).'</td>'; echo '</tr>'; echo '</tr>'; echo '<td class="sitename1">'.stripslashes($row["countComments"]).'</td>'; echo '</tr>'; } echo "</table>";

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  • Using Client Application Services in windows forms not working

    - by Nickson
    i am trying to implement asp.net membership, profile and role based security in a windows application by configuring client Application Services for my windows forms application. I have followed both these articles http://www.dotnetbips.com/articles/e863aa3c-0dd6-468d-bd35-120a334c5030.aspx and http://msdn.microsoft.com/en-us/library/bb546195.aspx step-by-step but for some reason i can't get the authentication working. I have a deployed intranet asp.net website which is already using an asp.net membership database for authentication and want to use that same database for authenitcation in my windows forms application. The site URL is http://myServer_Name:My_Port and i am specifying that URL as the both the Authentication service location and Roles service location in the windows application services property tab. But in the windows application login form, when i say Dim msg As String = "Welcome " If Not Membership.ValidateUser(UsernameTextBox.Text), PasswordTextBox.Text)) Then MessageBox.Show("Invalid User ID or Password!") Else msg = msg + UsernameTextBox.Text End If i get my "Invalid User ID or Password!" message even when i supply a valid user name with the corresponding password. i am able to login with the same credentials from the asp.net site. How can i test if the Authentication service location is being reached from the windows application?? Or what other information can i provide here such that one is able to help me get this working??

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  • Translating PHP language file

    - by Cudos
    Hello. I have a language file like this: <?php $lng_imagepath = "images/"; $lng_imageext = "gif"; $lng_characset = "iso-8859-1"; $lng_prefix = "en_"; $lng_tabhome = "Home"; $lng_tabmyavenue = "My Profile"; $lng_tabregister = "Register"; $lng_tabhelp = "Help"; $lng_tabbuybids = "Buy Bids"; ?> When I convert into a .html file and run Google translate it looks like this: Glemt brugernavn eller adgangskode? "; $ lng_invaliddata =" Ugyldig brugernavn og password. "$ lng_accountsuspend =" Din konto er suspenderet af vindetbud.dk. "$ lng_accountdelete =" Din konto er blevet slettet af vindetbud.dk. "$ lng_enterdata = "Angiv brugernavn og adgangskode." $ lng_enterpassword = "Angiv adgangskoden." / / slut login side variabel / / Language variabler for registrering side $ lng_frregistration = "Gratis registrering"; $ lng_vouchermessage = "voucher, indløses mod første auktion du vinder "; $ lng_amazingproducts =" Chancen for at vinde fantastiske produkter til fantastiske priser "; $ lng_registrationdata =" Du kan tilmelde med vindetbud.dk, bedes du udfylde følgende "; $ lng_personalinfo =" Personlige oplysninger "; $ lng_firstname =" Første Name "; $ lng_lastname =" Efternavn "; $ lng_birthdate =" Fødselsdato "; Do you have any clever ideas how to translate the file? P.S. I know that grammar won't be perfect, but it would help alot to use google translate.

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  • Code Organization Connundrum: Web Project With Multiple Supporting DLLs?

    - by Code Sherpa
    Hi. I am trying to get a handle on the best practice for code organization within my project. I have looked around on the internet for good examples and, so far, I have seen examples of a web project with one or multiple supporting class libraries that it references or a web project with sub-folders that follow its namespace conventions. Assuming there is no right answer, this is what I currently have for code organization: MyProjectWeb This is my web site. I am referencing my class libraries here. MyProject.DLL As the base namespace, I am using this DLL for files that need to be generally consumable. For example, my class "Enums" that has all the enumerations in my project lives there. As does class MyProjectException for all exception handling. MyProject.IO.DLL This is a grouping of maybe 20 files that handle file upload and download (so far). MyProject.Utilities.DLL ALl my common classes and methods bunched up together in one generally consumable DLL. Each class follows a "XHelper" convention such as "SqlHelper, AuthHelper, SerializationHelper, and so on... MyProject.Web.DLL I am using this DLL as the main client interface. Right now, the majority of class files here are: 1) properties (such as School, Location, Account, Posts) 2) authorization stuff ( such as custom membership, custom role, & custom profile providers) My question is simply - does this seem logical? Also, how do I avoid having to cross reference DLLs from one project library to the next? For example, MyProject.Web.DLL uses code from MyProject.Utilities.DLL and MyProject.Utilities.DLL uses code from MyProject.DLL. Is this solved by clicking on properties and selecting "Dependencies"? I tried that but still don't seem to be accessing the namespaces of the assembly I have selected. Do I have to reference every assembly I need for each class library? Responses appreciated and thanks for your patience.

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  • Devise routes to only use custom sign in page

    - by eblume
    I am trying to learn Devise and seem to have hit a problem that is nearly the same as many, many questions here on SO but just slightly different enough that I am not getting much traction following those questions' threads. I have a very simple application. Users can sign in and sign out (and also the devise 'forgot password' stuff is enabled - I am not concerned about it at this time) and that is it. They can't register, they can't edit their profile other than to change their password, they can't do anything except sign in and sign out. (Account creation will, for now, be handled manually at the command line.) I would vastly prefer that the only page that users can log in from was "/" (root_path). I already have it working where you can log in from "/", and that is great. The problem I am having is that if you type in your user/password combination incorrectly from the root_path login page, it automatically sends you to the Devise sign-in page to continue trying to sign in. How can I make Devise redirect to root_path on sign-in failure? Here are my routes - they are probably not optimal or correctly configured and I would appreciate pointers on fixing them: root to: "core_pages#splash" devise_for :users, skip: [:sessions] as :user do # get 'signin' => 'devise/sessions#new', as: :new_user_session post 'signin' => 'devise/sessions#create', as: :user_session delete 'signout' => 'devise/sessions#destroy', as: :destroy_user_session, via: Devise.mappings[:user].sign_out_via end match '/home' => 'core_pages#home' Note the commented-out 'get signin' line. The system works without this line but, surprisingly (to me), "GET /signin" results in a HTTP 400 (OK) response and renders the Devise login template. I would prefer it return some sort of 'invalid request' or just silently redirect the user to root_path. Running rake routes on these routes gives: root / core_pages#splash user_password POST /users/password(.:format) devise/passwords#create new_user_password GET /users/password/new(.:format) devise/passwords#new edit_user_password GET /users/password/edit(.:format) devise/passwords#edit PUT /users/password(.:format) devise/passwords#update user_session POST /signin(.:format) devise/sessions#create destroy_user_session DELETE /signout(.:format) devise/sessions#destroy home /home(.:format) core_pages#home Thanks!

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  • Setting routes in application.ini in Zend Framework

    - by Paul Watson
    I'm a Zend Framework newbie, and I'm trying to work out how to add another route to my application.ini file. I currently have my routes set up as follows: resources.router.routes.artists.route = /artists/:stub resources.router.routes.artists.defaults.controller = artists resources.router.routes.artists.defaults.action = display ...so that /artists/joe-bloggs uses the "display" action of the "artists" controller to dipslay the profile the artist in question - that works fine. What I want to do now is to set up another route so that /artists/joe-bloggs/random-gallery-name goes to the "galleries" action of the "artists" controller. I tried adding an additional block to the application.ini file (beneath the block above) like so: resources.router.routes.artists.route = /artists/:stub/:gallery resources.router.routes.artists.defaults.controller = artists resources.router.routes.artists.defaults.action = galleries ...but when I do that the page at /artists/joe-bloggs no longer works (Zend tries to route it to the "joe-bloggs" controller). How do I set up the routes in application.ini so that I can change the action of the "artists" controller depending on whether "/:gallery" exists? I realise I'm probably making a really stupid mistake, so please point out my stupidity and set me on the right path (no pun intended).

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  • How to make images hosted on Amazon S3 less public but not completely private?

    - by Jay Godse
    I fired up a sample application that uses Amazon S3 for image hosting. I managed to coax it into working. The application is hosted at github.com. The application lets you create users with a profile photo. When you upload the photo, the web application stores it on Amazon S3 instead of your local file system. (Very important if you host at heroku.com) However, when I did a "view source" in the browser of the page I noticed that the URL of the picture was an Amazon S3 URL in the S3 bucket that I assigned to the app. I cut & pasted the URL and was able to view the picture in the same browser, and in in another browser in which I had no open sessions to my web app or to Amazon S3. Is there any way that I could restrict access to that URL (and image) so that it is accessible only to browsers that are logged into my applications? Most of the information I found about Amazon ACLs only talk about access for only the owner or to groups of users authenticated with Amazon or AmazonS3, or to everybody anonymously.

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  • Creating an SQL variable character column > 255 characters supporting multiple databases

    - by Piers
    I have an application that stores data through an ODBC data source of the user's choosing. So far it has worked well on a range of database systems (e.g. JET, Oracle, SQL Server), as the SQL syntax is fairly simple. Now I am running into a problem where I need to store more than 255 characters in my strings. Previously I created the table using column type VARCHAR (255). Now if I try to create a table using, e.g. VARCHAR (512) then it falls over on Access databases. I know that I can use the MEMO type for Access, but this is non-standard SQL and will thus likely fail on other database systems (e.g. Oracle). Is there any widely supported SQL standard for creating text columns wider than 255 characters, or do I need to find another solution? The alternatives seem to me to be: 1) Profile the database system and customise the SQL CREATE TABLE command based on the database system. I don't like this as it defeats the purpose of using ODBC. 2) Add extra columns of 255 chars as required (e.g. LONGSTRING1, LONGSTRING2, ...) and concatenate after reading. I don't like this because it means the number of columns can vary between tables and it complicates read/write. Are there any other viable alternatives to these two options? Or is it possible to have an SQL compliant CREATE TABLE command supported by the majority of database vendors, that supports strings longer than 255 chars?

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  • jQuery: Stop browser scrolling on event update beyond the fold?

    - by neezer
    I have several links at the bottom of my page that update content at the top of my page (more than a viewport away). Here's the gist of what the update looks like: $('#private-photo div').fadeOut(function() { $(this).html('<%= escape_javascript(image_tag current_user.private_photo.image.url(:profile)) %>'); }).fadeIn(); Basically it's just fading out the old content and fading in the new content. My problem is that when this happens, the browser window automatically scrolls up just far enough so that the bottom of the updated content (#private-photo div) appears at the top of the browser viewport. I do not want this to happen. I want the content to be updated (still fading in and out), but without the browser viewport realigning its focus. I want to keep the animation because if the user has a big enough screen, or if they are using a link closer to the top of the page, I still want them to see the animation. Any ideas about how to prevent the browser from scrolling as described? If not, any suggestions for workarounds? FYI, I have this same problem in Safari 4, Chrome (for Mac), & Firefox 3.5. EDIT: Here's the link that calls the update action, which is itself inside a Colorbox: $('a.edit-photo').colorbox({ title: function() { return 'Edit Photo in ' + $(this).attr('rel'); }, overlayClose: false, onComplete: function() { $('#edit-photo-modal').submit(function(e) { $('#photo_submit').after('<span id="saving">Saving...</span>'); e.preventDefault(); $.post($(this).attr('action'), $(this).serialize(), function() { $('#edit-photo-modal #saving').text('Saved!'); }, "script"); }); } }); The lightbox opens, presents a form fetched through an AJAX request, then (on submit) triggers the update action mentioned above. I had these links outside of the Colorbox in an earlier design revision, and they exhibited the same problem, so I've ruled out Colorbox itself as a cause. If you need anymore info, let me know!

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  • Installation failed for Scala eclipse plugin

    - by Ramesh Vel
    Hi, I am Scala newbie. Just started playing. Today i started to install scala plugin for eclipse (in ubuntu machine), but its failed everytime. Below the error message. An error occurred while collecting items to be installed session context was:(profile=PlatformProfile, phase=org.eclipse.equinox.internal.provisional.p2.engine.phases.Collect, operand=, action=). No repository found containing: osgi.bundle,ch.epfl.lamp.sdt.aspects,2.7.7.final No repository found containing: osgi.bundle,ch.epfl.lamp.sdt.core,2.7.7.final No repository found containing: org.eclipse.update.feature,ch.epfl.lamp.sdt,2.7.7.final No repository found containing: osgi.bundle,org.aspectj.runtime,1.6.4.20090304172355 No repository found containing: osgi.bundle,org.aspectj.weaver,1.6.4.20090304172355 No repository found containing: org.eclipse.update.feature,org.eclipse.contribution.weaving,1.6.4.20090313172428 No repository found containing: osgi.bundle,org.eclipse.contribution.weaving.jdt,1.6.4.20090313172428 No repository found containing: osgi.bundle,org.eclipse.equinox.weaving.aspectj,1.0.0.200902241436 No repository found containing: osgi.bundle,org.eclipse.equinox.weaving.hook,1.0.0.200902121956 No repository found containing: osgi.bundle,scala.library,2.7.7.final No repository found containing: osgi.bundle,scala.tools.nsc,2.7.7.final Can someone clarify me what was the problem. Cheer

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  • zend framework controller not found ?

    - by user284503
    I downloaded the latest version of Zend framework, added a controller and I can not get it to load.. Here is what I did: C:\zend\Apache2\htdocs>zf create project myproject Creating project at C:/zend/Apache2/htdocs/myproject Note: This command created a web project, for more information setting up your V HOST, please see docs/README C:\zend\Apache2\htdocs>cd myproject C:\zend\Apache2\htdocs\myproject>zf create controller mycontroller Note: The canonical controller name that is used with other providers is "Mycont roller"; not "mycontroller" as supplied Creating a controller at C:\zend\Apache2\htdocs\myproject/application/controller s/MycontrollerController.php Creating an index action method in controller Mycontroller Creating a view script for the index action method at C:\zend\Apache2\htdocs\myp roject/application/views/scripts/mycontroller/index.phtml Creating a controller test file at C:\zend\Apache2\htdocs\myproject/tests/applic ation/controllers/MycontrollerControllerTest.php Updating project profile 'C:\zend\Apache2\htdocs\myproject/.zfproject.xml' C:\zend\Apache2\htdocs\myproject> Then I tried to hit the controller from the browser.. http://localhost/myproject/public/mycontroller/ and I get the error: Not Found The requested URL /myproject/public/mycontroller/ was not found on this server. I have no idea how to resolve this, and I'm sort of shocked I'm having problems with the Zend Server.

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  • How to restrict text search to a certain subset of the database ?

    - by Nikhil Garg
    I have a large central database of around 1 million heavy records. In my app, for every user I would have a subset of rows from central table, which would be very small (probably 100 records each).When a particular user has logged in , I would want to search on this data set only. Example: Say I have a central database of all cars in the world. I have a user profile for General Motors(GM) , Ferrari etc. When GM is logged in I just want to search(a full text search and not fire a sql query) for those cars which are manufactured by GM. Also GM may launch/withdraw a model in which case central db would be updated & so would be rowset associated with GM. In case of acquisitions, db of certain profiles may change without launch/removal of new car. So central db wont change then , but rowsets may. Whats the best way to implement such a design ? These smaller row sets would need to be dynamic depending on user activities. We are on Rails 2.3.5 and use thinking_sphinx as the connector and Sphinx/MySQL for search and relational associations.

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  • Passing options in autospec with Cucumber in Ruby on Rails Development

    - by TK
    I always run autospec to run features and RSpec at the same time, but running all the features is often time-consuming on my local computer. I would run every feature before committing code. I would like to pass the argument in autospec command. autospec doesn't obviously doesn't accept the arguments directly. Here's the output of autospec -h: autotest [options] options: -h -help You're looking at it. -v Be verbose. Prints files that autotest doesn't know how to map to tests. -q Be more quiet. -f Fast start. Doesn't initially run tests at start. I do have a cucumber.yml in config directory. I also have rerun.txt in the Rails root directory. cucumber -h gives me a lot of information about arguments. How can I run autospec against features that are tagged as @wip? I think I can make use of config/cucumber.yml. There are profile definitions. I can run cucumber -p wip to run only @wip-tagged features, but I'd like to do this with autospec. I would appreciate any tips for working with many spec and feature files.

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  • SWT - Table Row - Changing font color

    - by jkteater
    Is it possible to change the font color for a row based on a value in one of the columns? My table has a column that displays a status. The value of the column is going to either be Failed or Success. If it is Success I would like for that rows font be green. If the status equals Failed, I want that rows font be red. Is this possible, if so where would I put the logic. EDIT Here is my Table Viewer code, I am not going to show all the columns, just a couple private void createColumns() { String[] titles = { "ItemId", "RevId", "PRL", "Dataset Name", "Printer/Profile" , "Success/Fail" }; int[] bounds = { 100, 75, 75, 150, 200, 100 }; TableViewerColumn col = createTableViewerColumn(titles[0], bounds[0], 0); col.setLabelProvider(new ColumnLabelProvider() { public String getText(Object element) { if(element instanceof AplotResultsDataModel.ResultsData) { return ((AplotResultsDataModel.ResultsData)element).getItemId(); } return super.getText(element); } }); col = createTableViewerColumn(titles[1], bounds[1], 1); col.setLabelProvider(new ColumnLabelProvider() { public String getText(Object element) { if(element instanceof AplotResultsDataModel.ResultsData) { return ((AplotResultsDataModel.ResultsData)element).getRevId(); } return super.getText(element); } }); --ETC

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  • Rails: Multi-Step New User Signup Form (FSM?)

    - by neezer
    I've read the "Create Multi-Step Wizard" in Advanced Rails Recipes. I've also read and re-read the documentation for the updated FSM I'm using called Workflow, and looked here and here. The Advanced Rails Recipe focuses on records (quizzes) that already exist, and doesn't cover creating new ones. The Workflow docs don't cover any code for controllers or views, so I've no idea what to do with all this model magic, and the last two links barely touch on implementation either. From the aforementioned resources, I have a good understanding of what a FSM in Rails is and how to play with it in the console or IRB, but I've got very little direction or understanding how to implement one into my Rails app. What I would like is this: a simple, multi-step user signup process. Step 1: User enters in their critical details (with validations). Step 2: User enters in their search criteria, for their profile (with validations). Step 3: User agrees to the Terms of Service (with validations). Step 4: User is greeted by a confirmation page, including a link that takes them to their newly created account. I'd also like full navigation between the steps and full capture (saves to the database) with each transition. Can someone please give me a clear implementation of something similar to this? I would LOVE an example app that includes a multi-step signup process where I can look at the code (FULL source code--models AND controllers and views) under the hood, but I've been unable to find anything like that. Any guidance would be appreciated! EDIT: Please help make this a Railscast! Ryan B. (a.k.a. Superman), if you're reading this, we need you! http://feedback.railscasts.com/forums/77-episode-suggestions/suggestions/35553-multi-step-forms-and-wizards

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  • Modeling objects with multiple table relationships in Zend Framework

    - by andybaird
    I'm toying with Zend Framework and trying to use the "QuickStart" guide against a website I'm making just to see how the process would work. Forgive me if this answer is obvious, hopefully someone experienced can shed some light on this. I have three database tables: CREATE TABLE `users` ( `id` int(11) NOT NULL auto_increment, `email` varchar(255) NOT NULL, `username` varchar(255) NOT NULL default '', `first` varchar(128) NOT NULL default '', `last` varchar(128) NOT NULL default '', `gender` enum('M','F') default NULL, `birthyear` year(4) default NULL, `postal` varchar(16) default NULL, `auth_method` enum('Default','OpenID','Facebook','Disabled') NOT NULL default 'Default', PRIMARY KEY (`id`), UNIQUE KEY `email` (`email`), UNIQUE KEY `username` (`username`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 CREATE TABLE `user_password` ( `user_id` int(11) NOT NULL, `password` varchar(16) NOT NULL default '', PRIMARY KEY (`user_id`), UNIQUE KEY `user_id` (`user_id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 CREATE TABLE `user_metadata` ( `user_id` int(11) NOT NULL default '0', `signup_date` datetime default NULL, `signup_ip` varchar(15) default NULL, `last_login_date` datetime default NULL, `last_login_ip` varchar(15) default NULL, PRIMARY KEY (`user_id`), UNIQUE KEY `user_id` (`user_id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 I want to create a User model that uses all three tables in certain situations. E.g., the metadata table is accessed if/when the meta data is needed. The user_password table is accessed only if the 'Default' auth_method is set. I'll likely be adding a profile table later on that I would like to be able to access from the user model. What is the best way to do this with ZF and why?

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  • Starting and stopping firefox from c#

    - by Lucas Meijer
    When I start /Applications/Firefox.app/Contents/MacOS/firefox-bin on MacOSX using Process.Start() using Mono, the id of the process that gets returned does not match the process that firefox ends up running under. It looks like firefox quickly decides to start another process, and kill the current one. This makes it difficult to stop firefox, and to detect if it is still running. I've tried starting firefox using the -no-remote flag, to no avail. Is there a way to start firefox in such a way that it doesn't do this "I'll quickly make a new process for you" dance? The situation can somewhat be detected by making sure Firefox keeps on running for at least 3 seconds after its start, and when it does not, scan for other firefox processes. However, this technique is shaky at best, as on slow days it might take a bit more than 3 seconds, and then all tests depending on this behaviour fail. It turns out, that this behaviour only happens when asking firefox to start a specific profile using -P MyProfile. (Which I need to do, as I need to start firefox with specific proxyserver settings) If I start firefox "normally" it does stick to its process.

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