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  • R glm standard error estimate differences to SAS PROC GENMOD

    - by Michelle
    I am converting a SAS PROC GENMOD example into R, using glm in R. The SAS code was: proc genmod data=data0 namelen=30; model boxcoxy=boxcoxxy ~ AGEGRP4 + AGEGRP5 + AGEGRP6 + AGEGRP7 + AGEGRP8 + RACE1 + RACE3 + WEEKEND + SEQ/dist=normal; FREQ REPLICATE_VAR; run; My R code is: parmsg2 <- glm(boxcoxxy ~ AGEGRP4 + AGEGRP5 + AGEGRP6 + AGEGRP7 + AGEGRP8 + RACE1 + RACE3 + WEEKEND + SEQ , data=data0, family=gaussian, weights = REPLICATE_VAR) When I use summary(parmsg2) I get the same coefficient estimates as in SAS, but my standard errors are wildly different. The summary output from SAS is: Name df Estimate StdErr LowerWaldCL UpperWaldCL ChiSq ProbChiSq Intercept 1 6.5007436 .00078884 6.4991975 6.5022897 67911982 0 agegrp4 1 .64607262 .00105425 .64400633 .64813891 375556.79 0 agegrp5 1 .4191395 .00089722 .41738099 .42089802 218233.76 0 agegrp6 1 -.22518765 .00083118 -.22681672 -.22355857 73401.113 0 agegrp7 1 -1.7445189 .00087569 -1.7462352 -1.7428026 3968762.2 0 agegrp8 1 -2.2908855 .00109766 -2.2930369 -2.2887342 4355849.4 0 race1 1 -.13454883 .00080672 -.13612997 -.13296769 27817.29 0 race3 1 -.20607036 .00070966 -.20746127 -.20467944 84319.131 0 weekend 1 .0327884 .00044731 .0319117 .03366511 5373.1931 0 seq2 1 -.47509583 .00047337 -.47602363 -.47416804 1007291.3 0 Scale 1 2.9328613 .00015586 2.9325559 2.9331668 -127 The summary output from R is: Coefficients: Estimate Std. Error t value Pr(>|t|) (Intercept) 6.50074 0.10354 62.785 < 2e-16 AGEGRP4 0.64607 0.13838 4.669 3.07e-06 AGEGRP5 0.41914 0.11776 3.559 0.000374 AGEGRP6 -0.22519 0.10910 -2.064 0.039031 AGEGRP7 -1.74452 0.11494 -15.178 < 2e-16 AGEGRP8 -2.29089 0.14407 -15.901 < 2e-16 RACE1 -0.13455 0.10589 -1.271 0.203865 RACE3 -0.20607 0.09315 -2.212 0.026967 WEEKEND 0.03279 0.05871 0.558 0.576535 SEQ -0.47510 0.06213 -7.646 2.25e-14 The importance of the difference in the standard errors is that the SAS coefficients are all statistically significant, but the RACE1 and WEEKEND coefficients in the R output are not. I have found a formula to calculate the Wald confidence intervals in R, but this is pointless given the difference in the standard errors, as I will not get the same results. Apparently SAS uses a ridge-stabilized Newton-Raphson algorithm for its estimates, which are ML. The information I read about the glm function in R is that the results should be equivalent to ML. What can I do to change my estimation procedure in R so that I get the equivalent coefficents and standard error estimates that were produced in SAS? To update, thanks to Spacedman's answer, I used weights because the data are from individuals in a dietary survey, and REPLICATE_VAR is a balanced repeated replication weight, that is an integer (and quite large, in the order of 1000s or 10000s). The website that describes the weight is here. I don't know why the FREQ rather than the WEIGHT command was used in SAS. I will now test by expanding the number of observations using REPLICATE_VAR and rerunning the analysis.

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  • Pass encrypted querystring between php and asp.net (c#)

    - by Paul
    I need to pass a single variable in a querystring from one application (in PHP) to another (in ASP.NET). It's a one way transfer...That is I need to encrypt it in PHP and decrypt it in ASP.NET (c#). I'm barely a newbie on PHP and I'd like not to have to do more than add a tag to the page that needs to do the passing. The data will be anywhere from 5 - 15 characters..only letters and numbers. Thanks!

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  • Return a number between 0 and 4

    - by munchine
    How do I return a number between 0 and 4, depending the input number? For example if I pass it number 23 it will return 3. The number set should look like 0 5 10 15 20 .. 1 6 11 16 21 .. 2 7 12 17 22 .. 3 8 13 18 23 .. 4 9 14 19 24 What's the math for this?

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  • How do I program hardware?

    - by Arlen Beiler
    What would I need to program a piece of hardware to do something for me? Let's say I have something with 15 relays (or equivalent) and I want to tell it to turn off relay 10. Or better yet, when sensor 10 is activated, toggle relay 10.

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  • alternative ways to display a list

    - by joshua
    Hi everyone, I know on how to display a list by using loop. For example, choice(a):-write('This is the top 15 countries list:'),nl, loop(X). loop(X):-country(X),write(X),nl,fail. Unfortunately,I don't know on how to display list by using list.anyone can guide me?

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  • sql server modify error

    - by Jaspal
    hi, i m not able to modify table in SQL server. i m new to databases. use work go alter table employee modify id varchar(20) error message is- Msg 102, Level 15, State 1, Line 1 Incorrect syntax near 'modify' here is an screenshot thanks

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  • how to break outer loop from switch case

    - by Ravisha
    I have below code , enter code here for(int i=0;i<15;i++) { switch(i) { case 6: break; case 7: //Want to break the outer loop } } enter code here Is there a way to break the loop inside case statement? I know of one way is to use labels and goto .

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  • [NSIS] Custom radio-buttom INI page via Eclipse

    - by Omegazero
    I'm using Eclipse's create InstallOptions menu to create a custom INI page with radio-buttons for repackaging the Blackberry Desktop installer. There are 2 sections for each type: "Internet" and "Enterprise". I need a user to select 1 of the 2 options and depending on their selection, the page will carry over the selection chosen in the custom page, jump to the INSTFILES page, and continue onto the end. I couldn't find any concrete documentation on getting INI pages to load in the script (I'm probably searching incorrectly), and then pass data from one page to the next (according to fields I guess?) Any help is appreciated. Even if it's to tell me I'm blind and can't read a doc (though a link would help :) ) Here's the INI code: ; Auto-generated by EclipseNSIS InstallOptions Script Wizard ; Jul 29, 2009 5:42:56 PM [Settings] NumFields=7 Title=RIM BlackBerry Desktop 5.0 installation CancelEnabled=1 [Field 1] Type=RadioButton Left=15 Top=28 Right=100 Bottom=38 Text=Internet State= Flags=NOTIFY [Field 4] Type=RadioButton Left=15 Top=95 Right=100 Bottom=105 Text=Enterprise Flags=NOTIFY [Field 2] Type=GroupBox Left=0 Top=10 Right=300 Bottom=75 Text= [Field 5] Type=Label Left=30 Top=42 Right=235 Bottom=52 Text=For users who are NOT on the Enterprise (Exchange) server [Field 6] Type=Label Left=30 Top=111 Right=235 Bottom=121 Text=Choose this only if you are on the Exchange server [Field 3] Type=GroupBox Left=0 Top=75 Right=300 Bottom=140 [Field 7] Type=Label Left=0 Top=0 Right=130 Bottom=10 Text=Please choose your installation method ...And here's the NSI code: Auto-generated by EclipseNSIS Script Wizard Jul 29, 2009 5:42:16 PM Name "BlackBerry Desktop" RequestExecutionLevel admin General Symbol Definitions !define VERSION 5.0.0.11 !define COMPANY RIM !define URL http://www.blackberry.com MUI Symbol Definitions !define MUI_ICON BBD.ico !define MUI_LICENSEPAGE_RADIOBUTTONS Included files !include Sections.nsh !include MUI2.nsh Reserved Files ReserveFile "${NSISDIR}\Plugins\AdvSplash.dll" Installer pages !insertmacro MUI_PAGE_WELCOME !insertmacro MUI_PAGE_LICENSE license.txt !insertmacro MUI_PAGE_COMPONENTS !insertmacro MUI_PAGE_INSTFILES !insertmacro MUI_PAGE_FINISH Installer languages !insertmacro MUI_LANGUAGE English Installer attributes OutFile RIM_BlackBerry_Desktop_5.0.exe InstallDir "$TEMP\RIM BlackBerry Desktop 5.0 Setup Files" CRCCheck on XPStyle on ShowInstDetails hide VIProductVersion 5.0.0.11 VIAddVersionKey /LANG=${LANG_ENGLISH} ProductName "BlackBerry Desktop" VIAddVersionKey /LANG=${LANG_ENGLISH} ProductVersion "${VERSION}" VIAddVersionKey /LANG=${LANG_ENGLISH} CompanyName "${COMPANY}" VIAddVersionKey /LANG=${LANG_ENGLISH} CompanyWebsite "${URL}" VIAddVersionKey /LANG=${LANG_ENGLISH} FileVersion "${VERSION}" VIAddVersionKey /LANG=${LANG_ENGLISH} FileDescription "" VIAddVersionKey /LANG=${LANG_ENGLISH} LegalCopyright "" Installer sections Section /o Main SEC0000 SetOutPath $INSTDIR SetOverwrite ifdiff ; TESTING PHASE SectionEnd SectionGroup /e "BlackBerry Desktop Section" Section /o Internet SEC0001 SetOutPath $INSTDIR\DRIVERS SetOverwrite ifdiff ; Execwait 'msiexec /i "$INSTDIR\BlackBerry USB and Modem Drivers_ENG (DM5.0b28).msi" /passive' SetOutPath $INSTDIR SetOverwrite ifdiff ; File /r * ; ExecWait '"$INSTDIR\Setup.exe" /S/v/qb!' SectionEnd Section /o Enterprise SEC0002 SetOutPath $INSTDIR\DRIVERS SetOverwrite ifdiff ; Execwait 'msiexec /i "$INSTDIR\BlackBerry USB and Modem Drivers_ENG (DM5.0b28).msi" /passive' SetOutPath $INSTDIR SetOverwrite ifdiff ; File /r * ; Delete /REBOOTOK "$INSTDIR\Setup.ini" ; Rename /REBOOTOK "$INSTDIR\Setup_Enterprise.ini" "$INSTDIR\Setup.ini" ; ExecWait '"$INSTDIR\Setup.exe" /S/v/qb!' SectionEnd SectionGroupEnd Section Descriptions !insertmacro MUI_FUNCTION_DESCRIPTION_BEGIN !insertmacro MUI_DESCRIPTION_TEXT ${SEC0000} $(SEC0000_DESC) !insertmacro MUI_DESCRIPTION_TEXT ${SEC0001} $(SEC0001_DESC) !insertmacro MUI_FUNCTION_DESCRIPTION_END Installer Language Strings TODO Update the Language Strings with the appropriate translations. LangString SEC0000_DESC ${LANG_ENGLISH} "Installation for non-Exchange/Enterprise BlackBerry Users" LangString SEC0001_DESC ${LANG_ENGLISH} "Installation for Exchange/Enterprise BlackBerry Users"

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  • C++: compute a number's complement and its number of possible mismatches

    - by Eagle
    I got a bit stuck with my algorithm and I need some help to solve my problem. I think an example would explain better my problem. Assuming: d = 4 (maximum number of allowed bits in a number, 2^4-1=15). m_max = 1 (maximum number of allowed bits mismatches). kappa = (maximum number of elements to find for a given d and m, where m in m_max) The main idea is for a given number, x, to compute its complement number (in binary base) and all the possible combinations for up to m_max mismatches from x complement's number. Now the program start to scan from i = 0 till 15. for i = 0 and m = 0, kappa = \binom{d}{0} = 1 (this called a perfect match) possible combinations in bits, is only 1111 (for 0: 0000). for i = 0 and m = 1, kappa = \binom{d}{1} = 4 (one mismatch) possible combinations in bits are: 1000, 0100, 0010 and 0001 My problem was to generalize it to general d and m. I wrote the following code: #include <stdlib.h> #include <iomanip> #include <boost/math/special_functions/binomial.hpp> #include <iostream> #include <stdint.h> #include <vector> namespace vec { typedef std::vector<unsigned int> uint_1d_vec_t; } int main( int argc, char* argv[] ) { int counter, d, m; unsigned num_combination, bits_mask, bit_mask, max_num_mismatch; uint_1d_vec_t kappa; d = 4; m = 2; bits_mask = 2^num_bits - 1; for ( unsigned i = 0 ; i < num_elemets ; i++ ) { counter = 0; for ( unsigned m = 0 ; m < max_num_mismatch ; m++ ) { // maximum number of allowed combinations num_combination = boost::math::binomial_coefficient<double>( static_cast<unsigned>( d ), static_cast<unsigned>(m) ); kappa.push_back( num_combination ); for ( unsigned j = 0 ; j < kappa.at(m) ; j++ ) { if ( m == 0 ) v[i][counter++] = i^bits_mask; // M_0 else { bit_mask = 1 << ( num_bits - j ); v[i][counter++] = v[i][0] ^ bits_mask } } } } return 0; } I got stuck in the line v[i][counter++] = v[i][0] ^ bits_mask since I was unable to generalize my algorithm to m_max1, since I needed for m_max mismatches m_max loops and in my original problem, m is unknown until runtime.

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  • How many significant digits should I use for double literals in Java?

    - by M. Dudley
    How many significant digits should I use when defining a double literal in Java? This is assuming that I am trying to represent a number with more significant figures than a double can hold. In Math.java I see 20 and 21: public static final double E = 2.7182818284590452354; public static final double PI = 3.14159265358979323846; This is more than the 15-17 significant digits provided by IEEE 754. So what's the general rule-of-thumb?

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  • set difference in SQL query

    - by TheObserver
    I'm trying to select records with a statement SELECT * FROM A WHERE LEFT(B, 5) IN (SELECT * FROM (SELECT LEFT(A.B,5), COUNT(DISTINCT A.C) c_count FROM A GROUP BY LEFT(B,5) ) p1 WHERE p1.c_count = 1 ) AND C IN (SELECT * FROM (SELECT A.C , COUNT(DISTINCT LEFT(A.B,5)) b_count FROM A GROUP BY C ) p2 WHERE p2.b_count = 1) which takes a long time to run ~15 sec. Is there a better way of writing this SQL?

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  • PHP array help getting a value from the key

    - by sea_1987
    I have a variable that looks likes this, $rslt['expected_salary_level'] This returns a string similar to LEVEL_3, in another array that looks like this I have a set of salaries, Array ( [LEVEL_1] => Array ( [nice_name] => under &pound;10,000 [low] => 1 [high] => 10000 ) [LEVEL_2] => Array ( [nice_name] => &pound;10,000 - &pound;15,000 [low] => 10000 [high] => 15000 ) [LEVEL_3] => Array ( [nice_name] => &pound;15,000 - &pound;20,000 [low] => 15000 [high] => 20000 ) [LEVEL_4] => Array ( [nice_name] => &pound;20,000 - &pound;25,000 [low] => 20000 [high] => 25000 ) [LEVEL_5] => Array ( [nice_name] => &pound;25,000 - &pound;30,000 [low] => 25000 [high] => 30000 ) [LEVEL_6] => Array ( [nice_name] => &pound;30,000 - &pound;40,000 [low] => 30000 [high] => 40000 ) [LEVEL_7] => Array ( [nice_name] => &pound;40,000 - &pound;50,000 [low] => 40000 [high] => 50000 ) [LEVEL_8] => Array ( [nice_name] => &pound;50,000 - &pound;100,000 [low] => 50000 [high] => 100000 ) [LEVEL_9] => Array ( [nice_name] => &pound;100,000 or more [low] => 100000 [high] => 9999999 ) [LEVEL_VOLUNTARY] => Array ( [nice_name] => Voluntary [low] => [high] => ) [LEVEL_UNSPECIFIED] => Array ( [nice_name] => Not specified [low] => [high] => ) ) How do I get at the associated nice name?

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  • What's wrong with this date behavior in C#?

    - by Jane McDowell
    If I output a formatted date as follows: DateTime.Parse("2010-06-02T15:26:37.789 +01:00").ToString("HH:mm:sszzz") I get the expected result: 15:26:37+01:00 However, if I parse the same date, convert to UTC and output with the same format as follows: DateTime.Parse("2010-06-02T15:26:37.789 +01:00").ToUniversalTime().ToString("HH:mm:sszzz") I get this: 14:26:37+01:00 Now those two dates, the local and UTC versions, should be exactly the same but the outputted text represents two different times. Why is this?

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  • Jruby rspec to be run parallely

    - by Priyank
    Hi. Is there something like Spork for Jruby too? We want to parallelize our specs to run faster and pre-load the classes while running the rake task; however we have not been able to do so. Since our project is considerable in size, specs take about 15 minutes to complete and this poses a serious challenge to quick turnaround. Any ideas are more than welcome. Cheers

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  • Date object javascript

    - by Isis
    Hello. var date = new Date();//Mon Mar 15 2010 12:40:05 GMT+0300 (MSK) var omg = date.getDate() + 19;// 34 date.setDate(omg); document.write(date.toLocaleString()); //Sat 03 Apr 2010 12:43:00 PM MSK How do I echo the values 3 (ie: day of month), 4 (April) and the current year? alert(day); // Need 3 alert(month); // Need 4 Thank you

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  • Having problem with decimal points in MS Excel 2007

    - by Eishita
    I want to generate a graph with a large decimal number like -106.63633167743683 or 52.132235169410706. But whenever I'm entering the value in Excel sheet it is giving me value like -106.63633167743600 (as I have formatted cell with 15 decimal places). It is replacing the value of last two digits by 0. Can anyone help regarding this please?

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  • Linux ls[] command

    - by pedro
    ubuntu@ubuntu:/$ ls /dev/tty[15-24]* /dev/tty1 /dev/tty13 /dev/tty17 /dev/tty40 /dev/tty44 /dev/tty48 /dev/tty10 /dev/tty14 /dev/tty18 /dev/tty41 /dev/tty45 /dev/tty49 /dev/tty11 /dev/tty15 /dev/tty19 /dev/tty42 /dev/tty46 what is wrong?

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  • How to switch from MSSQL to MySQL for using with Excel pivot

    - by Sim
    Hi all, I have a table that contains sales transaction (~20 mil rows). Previously I used MSSQL and export it to an Excel pivot. Data refresh took 10-15 minutes but still do-able. However, after I migrated to MySQL (using XamppLite & ODBC), it took forever to refresh the data in the Excel pivot. Maybe I didn't optimize the MySQL good enough ? Anyone can share some thoughts 'bout this ? Thanks

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