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  • php facebook delete feeds

    - by meAtStackOverflow
    Hi there, I have manage to grab all the photos posted to my app wall. Now I am trying to add a function to my facebook app where it will delete all the feeds posted on the wall. <?php include_once 'facebook.php'; include_once 'config.php'; $feed = $facebook->api('/me/feed'); foreach($feed['data'] as $feeds) { echo "Feeds secion", "<br />"; echo $feeds["picture"], "<br />"; echo "<img src='{$feeds['picture']}' />", "<br />"; $target_path = "uploads/"; $target_path = $target_path . basename($feeds["picture"]); $content = file_get_contents($feeds["picture"]); file_put_contents($target_path, $content); } ? This is how i grab the photos and push them into my server. Please guide me on how i could delete all the feeds. I have went through some online examples but i could not figure out how to go about doing it. I kept receving errors. Thanks!

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  • Remove in between folder structure from the url in a php website

    - by pabz
    I have a php website having following folder structure (basic structure). project_name app controller model view css js img index.php So when I view index.php in WAMP the url is http://localhost/project_name/ But when I go inside the site (eg. login.php which resides under view folder) url is like this. http://localhost/project_name/app/view/login.php I found that using .htaccess we can change the urls. So I tried this (in .htaccess). RewriteEngine on RewriteBase / Redirect 301 /project_name/app/view/login.php /project_name/login.php RewriteRule ^/project_name/login.php$ /project_name/app/view/login.php [L] Now url is http://localhost/project_name/login.php It is correct. But it seems php does not use the original link to grab the file (ie. from /project_name/app/view/login.php) but from here /project_name/login.php So it throws 404 error. What should I change? Please help me, i am just trying to hide /app/view/ part from the url so that user won't see my folder structure. I have read about various ways of doing that for about 9hrs today but still couldn't get anything working correctly. Hope my question is clear enough. Any help is greatly appreciated!

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  • How to store a captured image into MySQL database using JavaScript

    - by R J.
    I am capturing image using canvas and i want to store a captured image in MySQL Database using Javascript. This is my code: <html> <head> <meta charset="utf-8"> <meta name="viewport" content="width=device-width, maximum-scale=1.0"> <style> body {width: 100%;} canvas {display: none;} </style> <title>Instant Camera - Remote</title> <script> var video, canvas, msg; var load = function () { video = document.getElementById('video'); canvas = document.getElementById('canvas'); msg = document.getElementById('error'); if( navigator.getUserMedia ) { video.onclick = function () { var context = canvas.getContext("2d"); context.drawImage(video, 0, 0, 240, 320); var image1 = canvas.toDataURL("image/png"); document.write('<img src="' + image1 + '" />'); }; } else { msg.innerHTML = "Native web camera not supported :("; } }; window.addEventListener('DOMContentLoaded', load, false); </script> </head> <body> <video id="video" width="240" height="320" autoplay> </video> <p id="error">Click on the video to send a snapshot to the receiving screen</p> <canvas id="canvas" width="240" height="320"> </canvas> </body> </html>

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  • Layering Images & Click to Choose Using Javascript

    - by rneal
    So I'm making a gallery of fabrics and backgrounds for letters for a fraternity/sorority store in my college's town. If you don't know what I'm talking about, this is a fabric letter. You can see how it has a white outline (background) and a red inside (foreground). WELL, I want to make it so you can change both the foreground and background, simply by clicking it's similar image. This is what I have so far <script type="text/javascript">// <![CDATA[ function changeImage(filename) { document.mainimage.src = filename; }// ]]></script> with these for each fabrics: <a href="javascript:changeImage('/wp-content/themes/collegiateconnectionbg/images/fabrics/foregrounds/37.jpg')"> <img src="/wp-content/themes/collegiateconnectionbg/images/fabrics/foregrounds/37.jpg" alt="" width="100px" height="50px" /></a> I really like how this works, but it's only good for one layer. Is there anyway I can add a layer below it, but still make it show at the top of the page? I know I'll have to use photoshop and transparency for both options, thats no problem, but I wanted to make sure I can do this before I start creating 600+ images. I know I can play with z-index and css, but since I'm using wordpress the one example I read about here wasn't working or I didn't completely understand it, and messed up my entire page. Also here's my tester webpage to see the current code in work. (if you click the navy&white stars image, you can see a very rough makeshift "A") Thanks in advance!

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  • supplied argument is not a valid MySQL result

    - by jasmine
    I have written a function: function selectWithPaging($where){ $pg = (int) (!isset($_GET["pg"]) ? 1 : $_GET["pg"]); $pg = ($pg == 0 ? 1 : $pg); $perpage = 10;//limit in each page $startpoint = ($pg * $perpage) - $perpage; $result = mysql_query("SELECT * FROM $where ORDER BY id ASC LIMIT $startpoint,$perpage"); return $result; } but when inserting in this function : function categories() { selectWithPaging('category') $text .='<h2 class="mainH">Categories</h2>'; $text .= '<table><tr class="cn"><td>ID</td><td class="name">Category</td> <td>Durum</td>'; while ($row = mysql_fetch_array($result)) { $home = $row['home']; $publish = $row['published']; $ID = $row['id']; $src = '<img src="'.ADMIN_IMG.'homec.png">'; ------------- } there is this error: supplied argument is not a valid MySQL result What is wrong in my first function? Thanks in advance

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  • highlight page selected in pagination?

    - by Mahmoud
    Hey There i have a php page, that shows all products that are stored on the database, so everything in fine, but my problem is that i am trying to highlight or give a color when a selected number is clicked, example, let say i all my product are showing and there are 2 pages, so when the user clicks on next the next fade and number 2 is colored yellow this well help the user to on which page he is below is my php code <?php echo"<a style:'color:#FFF;font-style:normal;'> "; include "im/config.php"; include('im/ps_pagination.php'); $result = ("Select * from product "); $pager = new PS_Pagination($conn, $result, 5, 6, "product=product"); $rs = $pager->paginate(); echo"<div id='image_container'>"; echo $pager->renderFullNav(); echo "<br /><br />\n"; while($row = mysql_fetch_array($rs)){ echo" <div class='virtualpage hidepiece'><a href='gal/".$row['pro_image']."' rel='lightbox[roadtrip]' title='".$row['pro_name']." : ".$row['pro_mini_des']."' style='color:#000'><img src='thumb/".$row['pro_thumb']."' /> </a></div>"; } echo"</div>"; echo "<br /><br />\n"; echo $pager->renderFullNav(); echo"</a>"; ?> Thank everyone

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  • Calling Multiple functions simultaneously

    - by Noob
    I'm trying to call two different functions for two different HTML elements at the same time, but the second function isn't being read at all. I'm also trying to use the id to specify which corresponding elements to grab data from. Here's what I have: function changeImage(id) { var s = document.getElementById('showcase'); var simg = s.getElementsByTagName('img'); var slen = simg.length; for(i=0; i < slen; i++) { simg[i].style.display = 'none'; } $('#' + id).fadeIn('slow', 0); function createComment(jim) { //alert('hello?'); var d = document.getElementById('description'); var dh = document.getElementsByTagName('p'); var dlen = dh.length; //alert(dh); for(i=0; i < dlen; i++) { alert(dh); dh[i].style.display = 'none'; } $('#' + jim).fadeIn('slow', 0); }

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  • JQuery to PHP function and back Ajaxed

    - by Xaris
    Hi all, i have a set of php function that i want to call on different events mostly onclick with jquery async (ajax). The first function is called on load $(document).ready(function() { $("#div2").hide('slow'); $("#div1").empty().html('<img src="ajax-loader.gif" />'); $.ajax( { type: "POST", url: "WebFunctions.php", data: {'func':'1'}, success: function(html) { $("#div1").show('slow').html(html) } }); The Data: {'func':'1'} -- is a switch statement on the php side switch($_POST['func']) { case '1': getParents(); break; case '2': getChilds(params); break; case '3': getChildObjects(params); break; default: } "This functions are calls to a soap server" <-- irrelevant. So when that function finishes i get an array which contains IDs and Names. I echo the names but i want the ID for reference so when i click on the echoed name i can call an other php function with parameter the ID of the name... How do i get rid of the switch statement?? How do i call properly php functions and pass params to it??? How can i save this IDs so when i click on an item with that id an other php function is called?? Plz feel free to ask any question, any answer is welcome :)

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  • Is it possible to get multiple forms to work with one ajax post function

    - by Scarface
    Hey guys I have a system where there is one form for each friend you have and I used to have an ajax post function for each form, but I want to save code and was wondering if it was possible to get multiple forms to work with just one post function. If anyone has any advice on how to achieve this I would appreciate it. For example <div id="message"> <form id='submit' class='message-form' method='POST' > <input type='hidden' id='to' value='friend1' maxlength='255' > Subject<br><input type='text' id='subject' maxlength='50'><br> Message<br><textarea id='message2' cols='50' rows='15'></textarea> <input type='submit' id='submitmessage' class='responsebutton' value='Send'> </form> </div> $(document).ready(function(){ $(".message-form").submit(function() { $("#submitmessage").attr({ disabled:true, value:\"Sending...\" }); var to = $('#to').attr('value'); var subject = $('#subject').attr('value'); var message = $('#message2').attr('value'); $.ajax({ type: "POST", url: "messageprocess.php", data: 'to='+ to + '&subject=' + subject + '&message=' + message, success: function(response) { if(response == "OK") { $('.message-form').html("<div id='message'></div>"); $('#message').html("<h2>Email has been sent!</h2>") .append("<p>Please wait...</p>") .hide() .fadeIn(1500, function() { $('#message').append(\"<img id='checkmark' src='images/check.png' />\"); });

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  • LINQ2SQL: How to let a column accept null values as zero (0) in Self-Relation table

    - by Remon
    As described in the img, I got a parent-Children relation and since the ParentID not accepting null values (and I can't change to nullabel due to some restriction in the UI I have), how can I remove an existence relation between ReportDataSources in order to change the parent for them (here i want to set the parentId for one of them = 0) how could i do that since i cant change the ParentID directly and setting Parent = null is not valid public void SetReportDataSourceAsMaster(ReportDataSource reportDataSource) { //Some logic - not necessarily for this scenario //Reset Master this.ReportDataSources.ToList().ForEach(rds => rds.IsMaster = false); //Set Master reportDataSource.IsMaster = true; //Set Parent ID for the rest of the Reports data sources this.ReportDataSources.Where(rds => rds.ID != reportDataSource.ID).ToList().ForEach(rds => { //Change Parent ID rds.Parent = reportDataSource; //Remove filttering data rds.FilteringDataMembers.Clear(); //Remove Grouping Data rds.GroupingDataMembers.Clear(); }); //Delete parent HERE THE EXCEPTION THROWN AFTER CALLING SUBMITCHANGES() reportDataSource.Parent = null; //Other logic } Exception thrown after calling submitChanges An attempt was made to remove a relationship between a ReportDataSource and a ReportDataSource. However, one of the relationship's foreign keys (ReportDataSource.ParentID) cannot be set to null.

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  • why my image and first name disappears in this code?

    - by udaya
    Hi This is my foreach function <? foreach($Selected as $row) $value = $row['dPath']; $imgp = base_url()."images"."/".$value; {?> <td> <?=$row['dFrindName'].'</br>';?> <?php */?> <img src="<?=$imgp ?>" name="b1" width="90" height="80" border="0"/> </td> <? }}?> Print_r($Selected); results in `Array ( [0] => Array ( [dFrindName] => chandruCP [dPath] => m11on.gif ) [1] => Array ( [dFrindName] => udaya [dPath] => logo.jpg ) )` but only my last value of the array is displayed on image I can get the name udaya and logo.jpg on the screen But i cant get chandruCP and m11on.gif why it is so how can i get all the values and image on scrren

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  • CSS: position:absolute inside position:relative, but not affecting parent?

    - by JP
    <style> #special p { display:none; } #special:hover p { display:block; } </style> <table> <tr> <td style="width:200px">Things</td> <td style="position:relative; width:220px"> <div style="position:absolute;right:0" id="special"> <img id="shows" /> <p>Variable width upto, say 600px (Will be hidden until this td is :hovered</p> </div> </td> </tr> </table> Can I make this work? Ie, can I make the #special p expand over the top of 'Things'? As I currently have it set up #special won't ever grow outside the 220px wide td. Any ideas?

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  • [jQuery] How to load vtip tooltip on a dynamically generated element?

    - by adaneko
    I'm new to jQuery and trying to combine the use of a tooltip plugin and a lightbox plugin. More specifically, I am using Colorbox (http://colorpowered.com/colorbox/) and vtip. Colorbox generates a div which displays an image like this: <div id="cboxLoadedContent" style="display: block; width: 400px; overflow: auto; height: 498px;"> <img src="image.jpg" id="cboxPhoto" style="margin: 49px auto auto; border: medium none; display: block; float: none; cursor: pointer;"> </div> I next add class="vtip" title="This is a tip." in order to use the vtip style, but for some reason it does not work when it's a title tag on an element dynamically generated by Colorbox, but works on anything already loaded on the page. Can anyone explain to me why this is and possibly offer some solutions to fix this problem?

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  • PHP: Problem with reading Files

    - by mathiregister
    hello guys, i wonder what i'm doing wrong! i want to read a folder and run through the existing files, checking if they are either images or textfiles. if there are textfiles they should be put into a div, if there are images the should be output as an image. <?php $path = 'thumbs'; if ($handle = opendir($path)) { while (false !== ($file = readdir($handle))) { $ext = pathinfo($file, PATHINFO_EXTENSION); if ($ext == "jpg" || $ext == "jpeg" || $ext == "gif" || $ext == "png") { print "<img class='thumb' src='$path/$file'/>"; } else if ($ext == "txt" || $ext == "rtf") { //read text $lines = file_get_contents($file); $lines = str_replace("\n","<br/>",$lines); print "<div class='text'>" . $lines . "</div>"; //read text } } closedir($handle); } ?> there seems to be a problem i can't find, because ALL IMAGES get put out, however only ONE of a few textfiles gets printed. Any ideas why it only prints out one textfile??? thank you for your help!

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  • Dereferencing possible null pointer in java

    - by Nealio
    I am just starting to get into graphics and when I am trying to get the graphics, I get the error"Exception in thread "Thread-2" java.lang.NullPointerException" and I have no clue on what is going on! Any help is greatly appreciated. //The display class for the game //Crated: 10-30-2013 //Last Modified: 10-30-2013 package gamedev; import gamedev.Graphics.Render; import gamedev.Graphics.Screen; import java.awt.Canvas; import java.awt.Dimension; import java.awt.Graphics; import java.awt.Toolkit; import java.awt.image.BufferStrategy; import java.awt.image.BufferedImage; import java.awt.image.DataBufferInt; import javax.swing.JFrame; private void tick() { } private void render() { System.out.println("display.render"); BufferStrategy bs = this.getBufferStrategy(); if (bs == null) { createBufferStrategy(3); } for (int i = 0; i < GAMEWIDTH * GAMEHEIGHT; i++) { pixels[i] = screen.PIXELS[i]; } screen.Render(); //The line of code that is the problem Graphics g = bs.getDrawGraphics(); //end problematic code g.drawImage(img, 0, 0, GAMEWIDTH, GAMEHEIGHT, null); g.dispose(); bs.show(); }

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  • Image not rendering in dompdf

    - by Venkat
    I am using codeIgniter and dompdf for my application for generating pdfs. The below code is the code which i am using to display an image. <div class=\"block_head\"> <h2>Image display</h2>"; $image_location = "/images/xxx.png"; $html .="<img src=\"".$image_location."\" width=\"200\" height=\"200\" /> </div>"; I tested and debugged all ways whether i am doing something wrong. Like this first i checked whether the path is wrong. This is path on the server. It's correct. I tested by echoing $html also it's showing perfectly path. When i clicked on that path image is displaying. But when i am trying to render it in pdf it's not displaying. Note: PDF is generating perfectly without image.

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  • How would i stop this foreach loop after 3 iterations?

    - by Tapha
    Here is the loop. foreach($results->results as $result){ echo '<div id="twitter_status">'; echo '<img src="'.$result->profile_image_url.'" class="twitter_image">'; $text_n = $result->text; echo "<div id='text_twit'>".$text_n."</div>"; echo '<div id="twitter_small">'; echo "<span id='link_user'".'<a href="http://www.twitter.com/'.$result->from_user.'">'.$result->from_user.'</a></span>'; $date = $result->created_at; $dateFormat = new DateIntervalFormat(); $time = strtotime($result->created_at); echo "<div class='time'>"; print sprintf('Submitted %s ago', $dateFormat->getInterval($time)); echo '</div>'; echo "</div>"; echo "</div>"; Thanks!!!! alot.

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  • getting parameter value from a table using javascript

    - by kawtousse
    hi every one; I want to get the parameter in my table(HTLML) table every time the user click edit button. The table contains in each row an edit button like following: retour.append("<td>"); retour.append("<button id=edit name=edit type=button onClick= editarow()>"); retour.append("<img src=edit.gif />"); retour.append("</button>"); retour.append("</td>"); to get the value of each row where edit is clicked using javascript I do the following: function editarow(){ var table = document.getElementById("sheet"); var buttons = table.getElementsByTagName("button"); for(var i=0; i<buttons.length; i++) { if(buttons[i].name=="edit") { buttons[i].onclick = function() { var buttonCell = this.parentNode;//cell var editThisRow = buttonCell.parentNode;//td var er=editThisRow.parentNode.attributes[1].value; alert(er); } } } } but i didn't get the values expected. thanks for help

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  • JavaScript Fails to load content correctly on start

    - by Gaz_Edge
    I have inherited an image gallery constructed using javascript. I believe it uses a variation of JQuery, but it seems to have been heavily edited. The gallery loads the first image on page load. Each image has comments below them. There are forward and backward arrows that move between images. The problem I seem to have is that if there is a comment on image one, it is not loaded on page start, the only way to get it to display is to click forward to the next image, then click back to image one. The comment is then shown. All the comments are loaded into a script in the header under var sent_comments = [{COMMENTS}] The comment HTML code on loading is as follows; <div id="comments_container"> <div id="comments"> </div> </div> Once I have clicked to image two and then back to image one, the code is; <div id="comments_container"> <div id="comments"> SOME COMMENT </div> </div> Previous image button is: <a class="prev save_state" href="#"> <img src="/next.png?" alt="Next"> </a> Im new to javascript so not really sure what I will need to do to ensure the comment is loaded for the first image when the page loads. Code here: http://static.albumexposure.net/assets/presentation-9f47b054d96f9ec2459e89619a5fe9b4.js http://static.albumexposure.net/assets/presentations/book-699d82a2beb39df264e54c5d2578e0e4.js

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  • How to serialize each item in IEnumerable for ajax post

    - by bflemi3
    I have a PartialView that displays IEnumerable<Movie>. _MoviePartial.cshtml @foreach(var movie in Model) { <div class="content"> <span class="image"><img src="@movie.Posters.Profile" alt="@movie.Title"/></span> <span class="title">@movie.Title</span> <div class="score`"> <span class="critics-score">@movie.Ratings.CriticsScore</span> <span class="audience-score">@movie.Ratings.AudienceScore</span> </div> @Html.ActionLink("Add Movie", "Add", "MyMovies") </div> } When the user clicks the "Add Movie" ActionLink I am going to do an ajax post to add the selected movie to the users collection. My problem is that I would like to send the entire selected Movie class to the "Add" action but not sure how to serialize each movie since the entire Movie class is not rendered in the PartialView, just a few properties. I know I can serialize something like this... <script type="text/javascript"> var obj = @Html.Raw(Json.Encode(movie)); </script> But I'm not sure how that would work inside a foreach loop that renders html, especially inside a PartialView. So, just to be clear, when a user clicks the "Add Movie" ActionLink I would like to send the serialized Movie class for that respective movie to my controller via ajax. My questions is... Is there a better way to serialize each movie and append it to it's respective anchor? I know there's the data- html5 attribute but I thought they only allow string values, not json objects. I also know I could use jQuery's .data() function but I'm struggling to think through how to get that to run from a PartialView, especially since the html rendered by _MoviePartial.cshtml may be returned from a controller via ajax.

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  • My method is too specific. How can I make it more generic?

    - by EricBoersma
    I have a class, the outline of which is basically listed below. import org.apache.commons.math.stat.Frequency; public class WebUsageLog { private Collection<LogLine> logLines; private Collection<Date> dates; WebUsageLog() { this.logLines = new ArrayList<LogLine>(); this.dates = new ArrayList<Date>(); } SortedMap<Double, String> getFrequencyOfVisitedSites() { SortedMap<Double, String> frequencyMap = new TreeMap<Double, String>(Collections.reverseOrder()); //we reverse order to sort from the highest percentage to the lowest. Collection<String> domains = new HashSet<String>(); Frequency freq = new Frequency(); for (LogLine line : this.logLines) { freq.addValue(line.getVisitedDomain()); domains.add(line.getVisitedDomain()); } for (String domain : domains) { frequencyMap.put(freq.getPct(domain), domain); } return frequencyMap; } } The intention of this application is to allow our Human Resources folks to be able to view Web Usage Logs we send to them. However, I'm sure that over time, I'd like to be able to offer the option to view not only the frequency of visited sites, but also other members of LogLine (things like the frequency of assigned categories, accessed types [text/html, img/jpeg, etc...] filter verdicts, and so on). Ideally, I'd like to avoid writing individual methods for compilation of data for each of those types, and they could each end up looking nearly identical to the getFrequencyOfVisitedSites() method. So, my question is twofold: first, can you see anywhere where this method should be improved, from a mechanical standpoint? And secondly, how would you make this method more generic, so that it might be able to handle an arbitrary set of data?

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  • Saving image to the existing file throws "A generic error occurred in GDI+" error.

    - by ryan
    i am trying to create a overlapped image using different images,then saving to a particular location. so that i can use generated image(overlapped img) in my telerik reporting. it is important to me to save the overlapped image to the same location with same name. but generating this overlapped image second time throws throws "A generic error occurred in GDI+" error. Please help me with this. It seems i can not override the existing image file. i tried deleting the existing image every time i generate the new one. but its not allowing me deleting the file ,may be it is used by telerik reporting. Here is the image create method which takes the baseimage path, sectionimage path and the reportimage path (this is the target locationenter code here) public static void Creat(List<string> sectionNames, string reportImagePath, string baseImagePath) { var file = Image.FromFile(baseImagePath); Graphics g = Graphics.FromImage(file); foreach (var sectionName in sectionNames) { var image = Image.FromFile(sectionName); g.DrawImage(image, new PointF(0.0F, 0.0F)); } file.Save(reportImagePath, ImageFormat.Png); file.Dispose(); }

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  • Read all sub directories within a certain folder to display a random image.

    - by Andy
    I have this code i have been using....but i need a conditional where it will read all the sub directories of /bg to select an image as opposed to a specific folder if they were on a subpage. Heres my code so far which works perfectly for all subpages to display specific images: //This would tell us its on the homepage if it helps: $this->level() == 0 //This is the code so far $path = '/home/sites/mydomain.co.uk/public_html/public/images/bg/'.$this->slug; $homepagefile = URL_PUBLIC.'public/images/bg/'.$this->slug.'/main.jpg'; $bgimagearray = array(); $iterator = new DirectoryIterator($path); foreach ($iterator as $fileinfo) { if ($fileinfo->isFile() && !preg_match('\.jpg$/', $fileinfo->getFilename())) { $bgimagearray[] = "'" . $fileinfo->getFilename() . "'"; } } $bgimage = array_rand($bgimagearray); ?> <div id="bg"> <div> <table cellspacing="0" cellpadding="0"> <tr> <td><img src="<?php echo $file.trim($bgimagearray[$bgimage], "'"); ?>" alt=""/></td> </tr> </table> </div> </div> Any help would be appreciated, im sure its not rocket science but ive tried a few ways and cant get my head around it. Thanks in advance.

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  • Image on mouseover takes space on PageLoad.

    - by Ram
    Hello, I am trying to show an image on Mouseover and hide it on Mouseout. I am successful in mouseover and mouseout but the image is actually taking the space around the text though i have visibility as hidden.. The text is surrounded with the space of image but the image is displayed on mouseover. Here is the code: <td valign="middle" class="table_td td top" style="width: 347px"> <div id="Style16" style="position:relative; height:100%; left:50%; bottom:700%; visibility:hidden; border:solid 0px #CCC; padding:5px"><img src="images/window-decal-image.gif"></div> <span class="feature_text" style="cursor:pointer" onmouseover="ShowPicture('Style16',1)" onmouseout="ShowPicture('Style16',0)" id="a16">Storefront Window Decal</span> <span class="feature_text_small">(5"x3.5" double sided decal)</span></td> <script language="javascript" type="text/javascript"> function ShowPicture(id,Source) { var vis, elem; if (1 == Source) { vis = "visible"; } else if (0 == Source) { vis = "hidden"; } else { throw new RangeError("Unknown Flag"); } if (elem = document.getElementById(id)) { elem.style.visibility = vis; } else { throw new TypeError("Element with id '"+id+"' does not exist."); } return vis; } </script>

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  • Image download from mysql results

    - by rozatrra
    i need to give my users the opportunity to download all the images I display in my project. images are displayed from a mysql query like this: $query = mysql_query("SELECT tl.customername, tl.visitdate, tl.employeename, pz.webpath from table tl inner join pictures pz on pz.visitid = tl.visitid and pz.groupid = tl.groupid inner join agenti ag on ag.idh = tl.employeeid WHERE tl.visitdate >= '$from' AND tl.visitdate <= '$to' AND tl.employeename like '$r_employee' AND tl.customerowner like '$r_customer' AND tl.customername like '$r_customername' AND tl.visitdate like '$r_date' group by pz.webpath order by tl.customername") or die(mysql_error()); while( $associate = mysql_fetch_assoc($query)) { echo '<li> <figure> <img src="../core/includes/timthumb.php?src='.$associate['webpath'].'&w=200&h=200" /> <figcaption> <h3>'.$associate['customername'].'</h3> <h6>'.$associate['employeename'].'</h6> <h6>'.$associate['visitdate'].' </h6> '; echo '<a class="fancybox" rel="gallery" href="'.$associate['webpath'].'" title=" '.$associate['visitdate'].' / '.$associate['customername'].'">Big picture</i></a>'; echo '</figcaption> </figure> </li>'; $zip->addFromString(pathinfo ( urldecode($associate['webpath']), PATHINFO_BASENAME), urldecode($associate['webpath'])); } How can i add a download button which will save all the images as zip on user computer?

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