I want to know which file (or even project is enough) is opened in eclipse editor? I know we can do this once we get IEditorPart from doSetInput method,
IFile file = ((IFileEditorInput) iEditorPart).getFile();
But I want the name of file without using IEditorPart, how can I do the same?
Checking which is the selected file in project explorer is not of much help because, user can select multiple files at once and open all simultaneously and I did not way to distinguish which file opened at what time.
Adding more info:
I have an editor specified for a particular type of file, now every time it opens, during intializing editor I have some operation to do based on project properties.
While initializing editor, I need the file handle (of the one which user opened/double clicked) or the corresponding project handle.
I have my editor something this way:
public class MyEditor extends TextEditor{
@Override
protected void initializeEditor() {
setSourceViewerConfiguration(new MySourceViewerConfiguration(
CDTUITools.getColorManager(), store,
"MyPartitions", this));
}
//other required methods
@Override
protected void doSetInput(IEditorInput input) throws CoreException {
if(input instanceof IFileEditorInput)
{
IFile file = ((IFileEditorInput) input).getFile();
}
}
}
as I have done in the doSetInput() method , I want the file handle(even project handle is sufficient). But the problem is in initializeEditor() function there is no reference to editorInput, hence I am unable to get the file handle.
In the source viewer configuration file, I set the code scanners and this needs some project specific information that will set the corresponding rules.
