Under Win32, it is a common technique to generate a monochrome bitmask from a bitmap for transparency use by doing the following:
SetBkColor(hdcSource, clrTransparency);
VERIFY(BitBlt(hdcMask, 0, 0, bm.bmWidth, bm.bmHeight, hdcSource, 0, 0, SRCCOPY));
This assumes that hdcSource is a memory DC holding the source image, and hdcMask is a memory DC holding a monochrome bitmap of the same size (so both are 32x32, but the source is 4 bit color, while the target is 1bit monochrome).
However, this seems to fail for me when the source is 32 bit color + alpha. Instead of getting a monochrome bitmap in hdcMask, I get a mask that is all black. No bits get set to white (1). Whereas this works for the 4bit color source.
My search-foo is failing, as I cannot seem to find any references to this particular problem.
I have isolated that this is indeed the issue in my code: i.e. if I use a source bitmap that is 16 color (4bit), it works; if I use a 32 bit image, it produces the all-black mask.
Is there an alternate method I should be using in the case of 32 bit color images? Is there an issue with the alpha channel that overrides the normal behavior of the above technique?
Thanks for any help you may have to offer!
ADDENDUM: I am still unable to find a technique that creates a valid monochrome bitmap for my GDI+ produced source bitmap.
I have somewhat alleviated my particular issue by simply not generating a monochrome bitmask at all, and instead I'm using TransparentBlt(), which seems to get it right (but I don't know what they're doing internally that's any different that allows them to correctly mask the image).
It might be useful to have a really good, working function:
HBITMAP CreateTransparencyMask(HDC hdc, HBITMAP hSource, COLORREF crTransparency);
Where it always creates a valid transparency mask, regardless of the color depth of hSource.
Ideas?
