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  • book "Programming Role Playing Games with DirectX 2nd edition" and newer DirectX api

    - by numerical25
    I got the book "Programming Role Playing Games with DirectX 2nd edition" and I notice there are things in the book that are now considered deprecated. There is a whole Section on DirectPlay. And as much as I would like to avoid this section, I am afraid it might screw up the entire engine he is trying to build. So I was just curious to know even though DirectPlay is considered deprecated by XNA, and directX10. Is it possible to use it still in DirectX 9 ??

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  • Transpose a file in bash

    - by Thrawn
    Hi all, I have a huge tab-separated file formatted like this X column1 column2 column3 row1 0 1 2 row2 3 4 5 row3 6 7 8 row4 9 10 11 I would like to transpose it in an efficient way using only using commands (I could write a ten or so lines Perl script to do that, but it should be slower to execute than the native bash functions). So the output should look like X row1 row2 row3 row4 column1 0 3 6 9 column2 1 4 7 10 column3 2 5 8 11 I thought of a solution like this cols=`head -n 1 input | wc -w` for (( i=1; i <= $cols; i++)) do cut -f $i input | tr $'\n' $'\t' | sed -e "s/\t$/\n/g" >> output done But it's slow and doesn't seem the most efficient solution. I've seen a solution for vi in this post, but it's still over-slow. Any thoughts/suggestions/brilliant ideas? :-)

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  • disown a process in ksh

    - by fahdshariff
    The "disown" command works in bash, but not in ksh. If I have started a process in ksh, how can I "disown" it, so I can exit my shell. (I know about nohup, but the process has already started!)

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  • dynamic linking:change of the linking path.

    - by benjamin button
    Normally it happens that when ever the path of the library that has to be linked dynamically is defined in LD_LIBRARY_PATH or it it will be mentioned with -L flag while creating the binary. In actual scenario if ,lets say the binary has been built and deployed at the client place. Now if there is a change in the path of one of the dynamic link library path. then we need to supply a new make file to all the clients where the binary was deployed. is there any other method where we need not tell all the clients to change their makefiles and can something can be done in the code itself? if yes...could anybody please suggest how? This was ironically an interview question that was asked to me and i didnot have the answer for it.

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  • Why can't my Apache see my media folder?

    - by alex
    Alias /media/ /home/matt/repos/hello/media <Directory /home/matt/repos/hello/media> Options -Indexes Order deny,allow Allow from all </Directory> WSGIScriptAlias / /home/matt/repos/hello/wsgi/django.wsgi /media is my directory. When I go to mydomain.com/media/, it says 403 Forbidden. And, the rest of my site doesn't work because all static files are 404s. Why? Edit: hello is my project folder

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  • Learning Linux screencasts

    - by Dmitriy Nagirnyak
    Hi, I am trying to get started with Linux. There are number of books (many of which are just man pages), some of them provide good overview so I can dig deeper online then. What I would like is to find number of screencasts that would cover basics of Linux commands, server administration, commonly performed tasks etc (no GUI, only terminal). I want to watch the screencasts to "get it quicker" and then use a book or online resources to "dig it deeper". Any recommendations? Thanks, Dmitriy.

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  • How to speed up calculation of length of longest common substring?

    - by eSKay
    I have two very large strings and I am trying to find out their Longest Common Substring. One way is using suffix trees (supposed to have a very good complexity, though a complex implementation), and the another is the dynamic programming method (both are mentioned on the Wikipedia page linked above). Using dynamic programming The problem is that the dynamic programming method has a huge running time (complexity is O(n*m), where n and m are lengths of the two strings). What I want to know (before jumping to implement suffix trees): Is it possible to speed up the algorithm if I only want to know the length of the common substring (and not the common substring itself)?

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  • Why does fprintf start printing out of order or not at all?

    - by Steve Melvin
    This code should take an integer, create pipes, spawn two children, wait until they are dead, and start all over again. However, around the third time around the loop I lose my prompt to enter a number and it no longer prints the number I've entered. Any ideas? #include <stdio.h> #include <stdlib.h> #include <unistd.h> #include <errno.h> #define WRITE 1 #define READ 0 int main (int argc, const char * argv[]) { //Pipe file-descriptor array unsigned int isChildA = 0; int pipeA[2]; int pipeB[2]; int num = 0; while(1){ fprintf(stderr,"Enter an integer: "); scanf("%i", &num); if(num == 0){ fprintf(stderr,"You entered zero, exiting...\n"); exit(0); } //Open Pipes if(pipe(pipeA) < 0){ fprintf(stderr,"Could not create pipe A.\n"); exit(1); } if(pipe(pipeB) < 0){ fprintf(stderr,"Could not create pipe B.\n"); exit(1); } fprintf(stderr,"Value read: %i \n", num); fprintf(stderr,"Parent PID: %i\n", getpid()); pid_t procID = fork(); switch (procID) { case -1: fprintf(stderr,"Fork error, quitting...\n"); exit(1); break; case 0: isChildA = 1; break; default: procID = fork(); if (procID<0) { fprintf(stderr,"Fork error, quitting...\n"); exit(1); } else if(procID == 0){ isChildA = 0; } else { write(pipeA[WRITE], &num, sizeof(int)); close(pipeA[WRITE]); close(pipeA[READ]); close(pipeB[WRITE]); close(pipeB[READ]); pid_t pid; while (pid = waitpid(-1, NULL, 0)) { if (errno == ECHILD) { break; } } } break; } if (procID == 0) { //We're a child, do kid-stuff. ssize_t bytesRead = 0; int response; while (1) { while (bytesRead == 0) { bytesRead = read((isChildA?pipeA[READ]:pipeB[READ]), &response, sizeof(int)); } if (response < 2) { //Kill other child and self fprintf(stderr, "Terminating PROCID: %i\n", getpid()); write((isChildA?pipeB[WRITE]:pipeA[WRITE]), &response, sizeof(int)); close(pipeA[WRITE]); close(pipeA[READ]); close(pipeB[WRITE]); close(pipeB[READ]); return 0; } else if(!(response%2)){ //Even response/=2; fprintf(stderr,"PROCID: %i, VALUE: %i\n", getpid(), response); write((isChildA?pipeB[WRITE]:pipeA[WRITE]), &response, sizeof(int)); bytesRead = 0; } else { //Odd response*=3; response++; fprintf(stderr,"PROCID: %i, VALUE: %i\n", getpid(), response); write((isChildA?pipeB[WRITE]:pipeA[WRITE]), &response, sizeof(int)); bytesRead = 0; } } } } return 0; } This is the output I am getting... bash-3.00$ ./proj2 Enter an integer: 101 Value read: 101 Parent PID: 9379 PROCID: 9380, VALUE: 304 PROCID: 9381, VALUE: 152 PROCID: 9380, VALUE: 76 PROCID: 9381, VALUE: 38 PROCID: 9380, VALUE: 19 PROCID: 9381, VALUE: 58 PROCID: 9380, VALUE: 29 PROCID: 9381, VALUE: 88 PROCID: 9380, VALUE: 44 PROCID: 9381, VALUE: 22 PROCID: 9380, VALUE: 11 PROCID: 9381, VALUE: 34 PROCID: 9380, VALUE: 17 PROCID: 9381, VALUE: 52 PROCID: 9380, VALUE: 26 PROCID: 9381, VALUE: 13 PROCID: 9380, VALUE: 40 PROCID: 9381, VALUE: 20 PROCID: 9380, VALUE: 10 PROCID: 9381, VALUE: 5 PROCID: 9380, VALUE: 16 PROCID: 9381, VALUE: 8 PROCID: 9380, VALUE: 4 PROCID: 9381, VALUE: 2 PROCID: 9380, VALUE: 1 Terminating PROCID: 9381 Terminating PROCID: 9380 Enter an integer: 102 Value read: 102 Parent PID: 9379 PROCID: 9386, VALUE: 51 PROCID: 9387, VALUE: 154 PROCID: 9386, VALUE: 77 PROCID: 9387, VALUE: 232 PROCID: 9386, VALUE: 116 PROCID: 9387, VALUE: 58 PROCID: 9386, VALUE: 29 PROCID: 9387, VALUE: 88 PROCID: 9386, VALUE: 44 PROCID: 9387, VALUE: 22 PROCID: 9386, VALUE: 11 PROCID: 9387, VALUE: 34 PROCID: 9386, VALUE: 17 PROCID: 9387, VALUE: 52 PROCID: 9386, VALUE: 26 PROCID: 9387, VALUE: 13 PROCID: 9386, VALUE: 40 PROCID: 9387, VALUE: 20 PROCID: 9386, VALUE: 10 PROCID: 9387, VALUE: 5 PROCID: 9386, VALUE: 16 PROCID: 9387, VALUE: 8 PROCID: 9386, VALUE: 4 PROCID: 9387, VALUE: 2 PROCID: 9386, VALUE: 1 Terminating PROCID: 9387 Terminating PROCID: 9386 Enter an integer: 104 Value read: 104 Parent PID: 9379 Enter an integer: PROCID: 9388, VALUE: 52 PROCID: 9389, VALUE: 26 PROCID: 9388, VALUE: 13 PROCID: 9389, VALUE: 40 PROCID: 9388, VALUE: 20 PROCID: 9389, VALUE: 10 PROCID: 9388, VALUE: 5 PROCID: 9389, VALUE: 16 PROCID: 9388, VALUE: 8 PROCID: 9389, VALUE: 4 PROCID: 9388, VALUE: 2 PROCID: 9389, VALUE: 1 Terminating PROCID: 9388 Terminating PROCID: 9389 105 Value read: 105 Parent PID: 9379 Enter an integer: PROCID: 9395, VALUE: 316 PROCID: 9396, VALUE: 158 PROCID: 9395, VALUE: 79 PROCID: 9396, VALUE: 238 PROCID: 9395, VALUE: 119 PROCID: 9396, VALUE: 358 PROCID: 9395, VALUE: 179 PROCID: 9396, VALUE: 538 PROCID: 9395, VALUE: 269 PROCID: 9396, VALUE: 808 PROCID: 9395, VALUE: 404 PROCID: 9396, VALUE: 202 PROCID: 9395, VALUE: 101 PROCID: 9396, VALUE: 304 PROCID: 9395, VALUE: 152 PROCID: 9396, VALUE: 76 PROCID: 9395, VALUE: 38 PROCID: 9396, VALUE: 19 PROCID: 9395, VALUE: 58 PROCID: 9396, VALUE: 29 PROCID: 9395, VALUE: 88 PROCID: 9396, VALUE: 44 PROCID: 9395, VALUE: 22 PROCID: 9396, VALUE: 11 PROCID: 9395, VALUE: 34 PROCID: 9396, VALUE: 17 PROCID: 9395, VALUE: 52 PROCID: 9396, VALUE: 26 PROCID: 9395, VALUE: 13 PROCID: 9396, VALUE: 40 PROCID: 9395, VALUE: 20 PROCID: 9396, VALUE: 10 PROCID: 9395, VALUE: 5 PROCID: 9396, VALUE: 16 PROCID: 9395, VALUE: 8 PROCID: 9396, VALUE: 4 PROCID: 9395, VALUE: 2 PROCID: 9396, VALUE: 1 Terminating PROCID: 9395 Terminating PROCID: 9396 105 Value read: 105 Parent PID: 9379 Enter an integer: PROCID: 9397, VALUE: 316 PROCID: 9398, VALUE: 158 PROCID: 9397, VALUE: 79 PROCID: 9398, VALUE: 238 PROCID: 9397, VALUE: 119 PROCID: 9398, VALUE: 358 PROCID: 9397, VALUE: 179 PROCID: 9398, VALUE: 538 PROCID: 9397, VALUE: 269 PROCID: 9398, VALUE: 808 PROCID: 9397, VALUE: 404 PROCID: 9398, VALUE: 202 PROCID: 9397, VALUE: 101 PROCID: 9398, VALUE: 304 PROCID: 9397, VALUE: 152 PROCID: 9398, VALUE: 76 PROCID: 9397, VALUE: 38 PROCID: 9398, VALUE: 19 PROCID: 9397, VALUE: 58 PROCID: 9398, VALUE: 29 PROCID: 9397, VALUE: 88 PROCID: 9398, VALUE: 44 PROCID: 9397, VALUE: 22 PROCID: 9398, VALUE: 11 PROCID: 9397, VALUE: 34 PROCID: 9398, VALUE: 17 PROCID: 9397, VALUE: 52 PROCID: 9398, VALUE: 26 PROCID: 9397, VALUE: 13 PROCID: 9398, VALUE: 40 PROCID: 9397, VALUE: 20 PROCID: 9398, VALUE: 10 PROCID: 9397, VALUE: 5 PROCID: 9398, VALUE: 16 PROCID: 9397, VALUE: 8 PROCID: 9398, VALUE: 4 PROCID: 9397, VALUE: 2 PROCID: 9398, VALUE: 1 Terminating PROCID: 9397 Terminating PROCID: 9398 106 Value read: 106 Parent PID: 9379 Enter an integer: PROCID: 9399, VALUE: 53 PROCID: 9400, VALUE: 160 PROCID: 9399, VALUE: 80 PROCID: 9400, VALUE: 40 PROCID: 9399, VALUE: 20 PROCID: 9400, VALUE: 10 PROCID: 9399, VALUE: 5 PROCID: 9400, VALUE: 16 PROCID: 9399, VALUE: 8 PROCID: 9400, VALUE: 4 PROCID: 9399, VALUE: 2 PROCID: 9400, VALUE: 1 Terminating PROCID: 9399 Terminating PROCID: 9400 ^C Another thing that's strange, when ran from within XCode it behaves normally. However, when ran from bash on Solaris or OSX it acts up.

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  • Need help implementing simple socket server using GIOService (GLib, Glib-GIO)

    - by Mark Renouf
    I'm learning the basics of writing a simple, efficient socket server using GLib. I'm experimenting with GSocketService. So far I can only seem to accept connections but then they are immediately closed. From the docs I can't figure out what step I am missing. I'm hoping someone can shed some light on this for me. When running the following: # telnet localhost 4000 Trying 127.0.0.1... Connected to localhost. Escape character is '^]'. Connection closed by foreign host. # telnet localhost 4000 Trying 127.0.0.1... Connected to localhost. Escape character is '^]'. Connection closed by foreign host. # telnet localhost 4000 Trying 127.0.0.1... Connected to localhost. Escape character is '^]'. Connection closed by foreign host. Output from the server: # ./server New Connection from 127.0.0.1:36962 New Connection from 127.0.0.1:36963 New Connection from 127.0.0.1:36965 Current code: /* * server.c * * Created on: Mar 10, 2010 * Author: mark */ #include <glib.h> #include <gio/gio.h> gchar *buffer; gboolean network_read(GIOChannel *source, GIOCondition cond, gpointer data) { GString *s = g_string_new(NULL); GError *error; GIOStatus ret = g_io_channel_read_line_string(source, s, NULL, &error); if (ret == G_IO_STATUS_ERROR) g_error ("Error reading: %s\n", error->message); else g_print("Got: %s\n", s->str); } gboolean new_connection(GSocketService *service, GSocketConnection *connection, GObject *source_object, gpointer user_data) { GSocketAddress *sockaddr = g_socket_connection_get_remote_address(connection, NULL); GInetAddress *addr = g_inet_socket_address_get_address(G_INET_SOCKET_ADDRESS(sockaddr)); guint16 port = g_inet_socket_address_get_port(G_INET_SOCKET_ADDRESS(sockaddr)); g_print("New Connection from %s:%d\n", g_inet_address_to_string(addr), port); GSocket *socket = g_socket_connection_get_socket(connection); gint fd = g_socket_get_fd(socket); GIOChannel *channel = g_io_channel_unix_new(fd); g_io_add_watch(channel, G_IO_IN, (GIOFunc) network_read, NULL); return TRUE; } int main(int argc, char **argv) { g_type_init(); GSocketService *service = g_socket_service_new(); GInetAddress *address = g_inet_address_new_from_string("127.0.0.1"); GSocketAddress *socket_address = g_inet_socket_address_new(address, 4000); g_socket_listener_add_address(G_SOCKET_LISTENER(service), socket_address, G_SOCKET_TYPE_STREAM, G_SOCKET_PROTOCOL_TCP, NULL, NULL, NULL); g_object_unref(socket_address); g_object_unref(address); g_socket_service_start(service); g_signal_connect(service, "incoming", G_CALLBACK(new_connection), NULL); GMainLoop *loop = g_main_loop_new(NULL, FALSE); g_main_loop_run(loop); }

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  • What are the best programming articles?

    - by lillq
    Part of being a good software developer is keeping current with what people are saying in the community. There are many good articles out there on the Internet about the wide subject of computer programming. What articles have you found worth your time? Please provide the article's title, author and a link if possible.

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  • Bash alias to open Vim at last edit mark

    - by Pierre LaFayette
    The mark " in Vim takes you to your last edit position. I want to create an alias that will open my Vim instance and jump to that mark; something which is obviously extremely useful. This works from the command line: $ vim -c "'\"" File.cpp Now I want to make an alias for this: $ alias v='vim -c "'\"" File.cpp' Well that's not going to work! You need to escape the first single quote you say... $ alias v='vim -c "\'\"" File.cpp' Hmm. That didn't work either... So I try a whole lot of variations of single quoted and double quoted madness, bang my head against the table and load up stackoverflow in my browser, and here we are. How do I properly escape this alias?

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  • Portable shebang line

    - by Mike
    #!/usr/bin/perl This is the shebang line to a lot of scripts I'm writing lately. Hard coding the path of the binary seems like it could create some problems. For instance, if one of my users has Perl installed at /something_else/bin then they'd have to change all the shebangs. I've seen some tools that will automatically replace the shebangs, but I'm wondering if there is something simpler.

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  • Display contents of a file in the parent directory

    - by Sharjeel Sayed
    I have a command which lists Weblogic instances directories on a server.I want to display contents of a file in the parent directory of each directory listed. An additional feature would be to display the name of the file in addition to displaying the contents /usr/ucb/ps auwwx | grep weblogic | tr ' ' '\n' | grep security.policy | grep domain | awk -F'=' '{print $2}' | sed -e 's/weblogic.policy//' -e 's/security\///' | sort The output of the above command looks like this /opt/<some_directory>/<domain_name>/<app_name>/ /opt/<some_directory>/<domain_name>/<app_name>/ I want to cat a file somefile.cf in the directory

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  • Verifying regular expression for malware removal

    - by Legend
    Unfortunately, one of my web servers was compromised recently. I have two questions. Is there a way I can scan the downloaded directory for backdoors? Is there anything I can do to ensure that at least known vulnerabilities do not exist anymore? Secondly, the malware put up the following in all index.* files on my webserver: <script>/*GNU GPL*/ try{window.onload = function(){var Hva23p3hnyirlpv7 = document.createElement('script');Hva23p3hnyirlpv7.setAttribute('type', 'text/javascript');Hva23p3hnyirlpv7.setAttribute('id', 'myscript1');Hva23p3hnyirlpv7.setAttribute('src',.... CODE DELETED FOR SAFETY.... );}} catch(e) {}</script> Obviously, this snippet seems to download some rogue file onto the user's machine. I downloaded an entire backup of the web server and am currently trying to remove this snippet from all file. For this I am doing: find ./ -name "index.*" -exec sed -i 's/<script>\/\*GNU GPL\*.*Hva23p3hnyirlpv7.*<\/script>//g' {} \; Just wanted to verify if this does the trick. I verified it with a few files but I want to be sure that this doesn't delete some valid code. Anyone suggests any other modifications?

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  • What's the Easiest Way to Learn Programming?

    - by Chris
    If a friend of yours wanted to get into development and didn't have any experience, what would you suggest? What language/resources would you suggest to break into programming? With all of the technologies out right now and buzz words where should one even start explaining this stuff to people?

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  • How do I change apache2 DocumentRoot (default snow leopard install) and not get "You don't have perm

    - by David Peek
    I'm trying to point DocumentRoot at a directory in my user folder. While I can happily point DocumentRoot at /Library/WebServer/Documents and ~/Sites I keep getting "You don't have permission to access / on this server." when I point it anywhere else. OK, I just found a solution mid-question (stack overflow is just that good) by changing the user/group apache runs under to myuser/admin. I'm sure there must be a better way though. Surely some kind of permissions magic on the directory I'm pointing at?

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  • Introduction to 3D Graphics Programming

    - by Jacob Relkin
    Hi everyone! I'm a self-taught programmer with absolutely nil 3D programming experience. A client of mine has related to me an idea for an iPhone app that requires OpenGL ES 2.0 for it's inherently complex 3D structure and animations. Where do I start on this ( albeit long ) journey toward OpenGL ES competence? I'm willing to put in a tremendous amount of time and effort into learning, and if i could please get some pointers to where I should start and what to expect, that would be awesome!

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  • Create ntp time stamp from gettimeofday

    - by krunk
    I need to calculate an ntp time stamp using gettimeofday. Below is how I've done it with comments on method. Look good to you guys? (minus error checking). Also, here's a codepad link. #include <unistd.h> #include <sys/time.h> const unsigned long EPOCH = 2208988800UL; // delta between epoch time and ntp time const double NTP_SCALE_FRAC = 4294967295.0; // maximum value of the ntp fractional part int main() { struct timeval tv; uint64_t ntp_time; uint64_t tv_ntp; double tv_usecs; gettimeofday(&tv, NULL); tv_ntp = tv.tv_sec + EPOCH; // convert tv_usec to a fraction of a second // next, we multiply this fraction times the NTP_SCALE_FRAC, which represents // the maximum value of the fraction until it rolls over to one. Thus, // .05 seconds is represented in NTP as (.05 * NTP_SCALE_FRAC) tv_usecs = (tv.tv_usec * 1e-6) * NTP_SCALE_FRAC; // next we take the tv_ntp seconds value and shift it 32 bits to the left. This puts the // seconds in the proper location for NTP time stamps. I recognize this method has an // overflow hazard if used after around the year 2106 // Next we do a bitwise AND with the tv_usecs cast as a uin32_t, dropping the fractional // part ntp_time = ((tv_ntp << 32) & (uint32_t)tv_usecs); }

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  • Bash Shell; read command; using Cygwin on Windows 7

    - by user312397
    Okay so I am having this problem. I write up a script to be run in cygwin on Windows. I've tried a bunch of basic example scripts in case it was my scripts problem. So I tried this: #!/bin/bash echo -e "Enter your name and press [ENTER]: \c" read var_name echo "Your name is: $var_name" Then I will run it and I enter a name for var_name. I get this: $ ./project1.sh Enter your name and press [ENTER]: Jake ': not a valid identifierad: `var_name Your name is: So as far as I understand it I am having a problem with read. I am trying to work on a project for my class, but I can't seem to figure out why it won't read it. I followed the book with no triumph then resorted to these examples on the web that do not seem to work for me either. Does anyone have any idea if it is my setup or if I am missing something, thanks.

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