Search Results

Search found 88594 results on 3544 pages for 'vc project file'.

Page 152/3544 | < Previous Page | 148 149 150 151 152 153 154 155 156 157 158 159  | Next Page >

  • How to load an ImageView from a png file?

    - by Peter vdL
    I take a picture with the camera using Intent intent = new Intent(android.provider.MediaStore.ACTION_IMAGE_CAPTURE ); startActivityForResult( intent, 22 ); When the activity completes, I write the bitmap picture out to a PNG file. java.io.FileOutputStream out = openFileOutput("myfile.png", Context.MODE_PRIVATE); bmp.compress(Bitmap.CompressFormat.PNG, 90, out); That goes OK, and I can see the file is created in my app private data space. I'm having difficulty when I later want to display that image using an ImageView. Can anyone suggest code to do this? If I try to create a File with path separators in, it fails. If I try to create a Uri from a name without separators, that fails. I can open the file OK using: java.io.FileInputStream in = openFileInput("myfile.png"); But that doesn't give me the Uri I need to set an image with iv.setImageURI(u) Summary: I have the picture in a png file in private app data. What's the code to set that into an ImageView? Thanks.

    Read the article

  • How to know the next temp file to be created in windows?

    - by Mike
    I am by no means a programmer but currently am wondering if an application creates a temp file that windows names. For example the file it creates is tmp001, is there a way i can take that name tmp001 and ask windows to give me the next temp file it would create before it creates it. Thanks, Mike

    Read the article

  • While try to open the project - getting error.

    - by Gopal
    Using Visual Studio 2008 I have .net file name like UPS.Tek, version - Visual Studio 2005 C# files are UPSReport.cs (Visual C# Source File) UPSConn.Cs (Visual C# Source File) UPSBase.cs (Visual C# Source File) ...., When i try to open the C# files individually in VS 2008, the C# files are opening But When I try to open this UPS.Tek in Visual Studio 2008, It showing error as "make sure the application for the project type .csproj is installed" How to solve this error.

    Read the article

  • I am unable to upload file to my local host folder in php.

    - by Nauman khan
    Hi, I have the follwing code <form enctype="multipart/form-data" action="upload.php" method="POST"> Please choose a file: <input name="uploaded" type="file" /><br /> <input type="submit" value="Upload" /> </form> <?php $target = "upload/"; $target = $target . basename( $_FILES['uploaded']['name']) ; $ok=1; if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)) { echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded"; } else { echo "Sorry, there was a problem uploading your file."; } ?> my page is in http://localhost/nausal/upload.php now I am having the follwing error though i have created a folder in site with name upload. Notice: Undefined index: uploaded in C:\wamp\www\Nausal\upload.php on line 15 Notice: Undefined index: uploaded in C:\wamp\www\Nausal\upload.php on line 17 Sorry, there was a problem uploading your file. Please help me I am very new to php. :(

    Read the article

  • Eclipse cannot find existing project in build path

    - by PNS
    Here is probably one of the idiosyncrasies of Eclipse and its handling of build paths, which cannot be fixed despite all sorts of workarounds tested so far. The issue relates to a workspace of several projects, each of which compiles into its own JAR. Dependencies among the projects are resolved by adding the relevant ones to the build path (no Maven or other external tool or plugin is used), via Project -> Properties -> Java Build Path -> Projects Among all these projects, a couple (say, com.example.p1 and com.example.p2) refuse to recognize a third (and simple) one (say, com.example.p3), while all other projects do. So, although P3 is added to the build path, all related classes from P3 are imported properly and the source code of each such class is accessible by hitting F3, Eclipse keeps complaining that The import com.example.p3 cannot be resolved and SomeClass cannot be resolved to a type where com.example.p3.SomeClass is one of the P3 classes. If instead of the P3 project I put its compiled JAR in the build path, the issue disappears. However, code in P3 changes frequently and it is a time waste to keep compiling and refreshing the workspace so that the change is picked up, not to mention that this should not happen in an IDE anyway (and it does not for the other projects using P3). Among the workarounds tried are things like: Removing and adding again P1, P2, P3 Cleaning up and recompiling everything Checking whether any other project loads the P3 JAR Putting P3 at the top of the Eclipse build path "Order and Export" list Using the "Fix project setup" suggestion of Eclipse (available when hovering the mouse over the red-underlined-error compilation line). Actually, this option offers adding to the build path either P3 or its JAR, but if P3 is added, the issue reappears. Any ideas?

    Read the article

  • How can I asynchronously monitor a file in Perl?

    - by Hussain
    I am wondering if it is possible, and if so how, one could create a perl script that constantly monitors a file/db, and then call a subroutine to perform text processing if the file is changed. I'm pretty sure this would be possible using sockets, but this needs to be used for a webchat application on a site running on a shared host, and I'm not so sure sockets would be allowed on it. The basic idea is: create a listener for a chat file/database when the file is updated with a new message, call a subroutine the called subroutine will send the new message back to the browser to be displayed Thanks in advance.

    Read the article

  • invalid file name in matlab when using file split

    - by klijo
    here jj will be the value of FN, but the trouble is iam getting a error message ??? Error using == fopen Invalid filename. DirName = 'Samples\mattest\jj'; FileName = split('\\',DirName); [a,b] = size(FileName); FN = FileName(b); file_1 = fopen(FN,'w'); split method was found at http://www.mathworks.com/matlabcentral/fileexchange/4873 Doesnt the code seem correct ? Could someone please help me ?

    Read the article

  • Php efficiency question --> Database call vs. File Write vs. Calling C++ executable

    - by JP19
    Hi, What I wish to achieve is - log all information about each and every visit to every page ofmy website (like ip address, browser, referring page, etc). Now this is easy to do. What I am interested is doing this in a way so as to cause minimum overhead (runtime) in the php scripts. What is the best approach for this efficiency-wise: 1) Log all information to a database table 2) Write to a file (from php directly) 3) Call a C++ executable, that will write this info to a file in parallel [so the script can continue execution without waiting for the file write to occur ...... is this even possible] I may be trying to optimize unnecessarily/prematurely, but still - any thoughts / ideas on this would be appreciated. (I think efficiency of file write/logging can really be a concern if I have say 100 visits per minute...) Thanks & Regards, JP

    Read the article

  • Error running web project in eclipse

    - by DarkKnight
    I am a newbie to servlets. I created a dynamic web project in eclipse. I have following files in my project home.html validateServlet.java I have defined validated servlet as an action in home.html form. However when I run it, I get http status 404. Below is the hierarchy of my project Project Java Resources src com.servlets ValidateServlet.java build WebContent META-INF WEB-INF web.xml hello.html Contents of my web.xml are as follows: <?xml version="1.0" encoding="UTF-8"?> <web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web- app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0"> <display-name>Website</display-name> <servlet> <description></description> <display-name>ValidateServlet</display-name> <servlet-name>validate</servlet-name> <servlet-class>com.oracle.coen235.servlets.ValidateServlet</servlet-class> </servlet> </web-app> In my hello.html, action is specified as , What might be the issue? I guess I am not able to generate the class file for my servlet. Can anyone guide me through this problem?

    Read the article

  • vb.net project template how can I leave the root namesapce empty

    - by Wietze Veld
    I have been tinkering with the VS 2010 template. So far I am able to create a vb.net class library project from my template. However, one small thing is bugging me. In my project template the default assembly name is the same as the default file name. I have left the root namespace empty. But when I create a new project from the template, VS 2010 automatically fills the root namespace with the same name as my assembly name. My template project (vbproj) for the assembly name and root namespace looks like this: <AssemblyName>$safeprojectname$</AssemblyName> <!-- RootNameSpace should always be empty. --> <RootNamespace></RootNamespace> But as said, when I leave this empty it is always overwritten with the assembly name. Even if I create a custom parameter with an empty string as value to replace the root namespace, it is still overridden. Any help is appreciated.

    Read the article

  • Hello world/Console Project in Visual Studio 2008 64 bit

    - by grobartn
    So I am trying to run console 64 bit Hello World program. I have Windows 7 Enterprise x64 bit version. I have installed Visual Studio 2008 and have added all of components needed for 64 bit. I want to create simple console application. It turns out to be a problem. I have simple standard hello world project. I have created it using New Project - Empty project. I added main.cpp that contains this: #include <iostream> using namespace std; int main() { cout << "howdy\n"; } I added new configuration to the project by clicking on Config Manager and added x64 config. Compiled and it compiles. Tried running it and cmd.exe shoots up with following error: "The application has failed to start because its side-by-side configuration is in correct. Please see the application event log or use the command-line sxstrace.e xe tool for more detail. Press any key to continue . . . " Which set-up step if any I am missing. What am I doing wrong and how should I go about setting simple console hello world in 64 bit world. Thanks for any help

    Read the article

  • Apache and linux file permissions can't browse file or directories

    - by dardub
    I just copied my magento site over to a local server running CentOS 5.4. The browser said it can't locate the location of the stylesheets. The stylesheets are within /skin/frontend/my_new_interface/design2/css. I tried to view in the browser and I can't view any of the files within the css directory. I verified a million times that I'm typing in the correct location. I can view files within /skin/frontend/my_new_interface/design2. Can't browse directories within browser however. I typed in ls -l css and get: -rwxr-xr-x 1 apache apache listed for all the files I tried chmod -R 755 and the directories I changed the apache conf Options Indexes But still when I browse the directories I get Forbidden. However, in another fresh installation of magento in the same www dir, I am able to browse directories. As far as I can tell both installations have same ownership and permissions. I also tried find . -type f -exec chmod 644 {} \; find . -type d -exec chmod 755 {} \; which was recommended in the magento wiki I've just run out of ideas.

    Read the article

  • How to check for a dynamically created file in Java?

    - by Moev4
    I have an application where I need to check for a file which may be created dynamically during my execution, I will give up after some MAX time where the file has yet to show up. I wanted to know if there was a more efficient method in Java of checking for the file other than polling for it and then sleeping every X seconds? If not what would be the most efficient manner of doing this?

    Read the article

  • Linux file names & file globbing

    - by John Lelos
    I have a list of files named: file000 file001 file002 file003 ... file1100 How can I match all files that have a number greater than 800 but less than 1000 ? I am using linux bash Thank you Edit Actually, my files are named like: ab869.enc cp936.enc g122345.enc x2022.enc abc8859-14.enc aax5601.enc cp936-1.enc so the first solution dont match the correct files :( How can I match files that have number between 800-999 ?

    Read the article

  • How to read a file line using php in a javascript variable without the breakline character ?

    - by coolboycsaba
    I have a txt file on the server which contains 10 lines of text. The text file is rewritten sometimes, and I get new lines using "\r\n". My problem shows when I want to load the lines in javascript variables. I do it like this, but this work only for numbers or for the last line of the file, because its not using the breakline tag: var x = '<?php echo $file[0]; ?>'; Ive tried to alert(x) but it`s not working.... (working only if I read the last line) Any idead ?

    Read the article

  • Python library to detect if a file has changed between different runs?

    - by Stefano Borini
    Suppose I have a program A. I run it, and performs some operation starting from a file foo.txt. Now A terminates. New run of A. It checks if the file foo.txt has changed. If the file has changed, A runs its operation again, otherwise, it quits. Does a library function/external library for this exists ? Of course it can be implemented with an md5 + a file/db containing the md5. I want to prevent reinventing the wheel.

    Read the article

  • How to add authentication property for login to directory path when running batch file in WCF?

    - by blankon91
    I have class in my WCF service to execute batch file. when I test to run the batch file in shared directory, everything is fine, the batch was executed, but when I try to run the batch file from secure diretory, I get error "ACCESS DENIED". How to add login property so I can access my secured directory to execute my batch file? here is my code: public string ExecuteBat() { string hasil = ""; ProcessStartInfo processInfo = new ProcessStartInfo(@"D:\Rpts\SSIS_WeeklyFlash_AAF_1.bat"); processInfo.CreateNoWindow = true; processInfo.UseShellExecute = false; Process process = Process.Start(processInfo); process.WaitForExit(); if (process.ExitCode == 0) { hasil = "BAT EXECUTED!"; } else { hasil = "EXECUTE BAT FAILED"; } return hasil; }

    Read the article

  • In java can i have more than one class/object in a file?

    - by David
    So the way i've been told to do things is you have your file and the file name is Classname.java and then the code is something like this: class ClassName { SOME METHODS main {} } and then thats all. I'd like to have two objects defined and used within the same .java file. (i don't want to have to put the other class in a difernt file just because i'd like to send this to someone and i want to avoid hasstle of atatching multiple files to an email [the lazy do make good programers though if you think about it]) is it possible to do this? do i have to do anything special and if so what? what are some mistakes i'm likely to make or that you have made in the past when doing this?

    Read the article

  • Can the Visual Studio (2010) Command Window handle "external tools" with project/solution relative p

    - by ee
    I have been playing with the Command Window in Visual Studio (View-Other Windows-Command Window). It is great for several mouse-free scenarios. (The autocompleting file "Open" command rocks in a non-trivial solution.) That success got me thinking and experimenting: Possibility 1.1: You can use the Alias commands to create custom commands Possibility 1.2: You can use the Shell command to run arbitrary executables and specify parameters (and pipe the result to the output or command windows) Possibility 2: A previously setup external tool definition (with project-relative path variables) could be run from the command window What I am stuck on is: There doesn't appear to be a way to send parameters to an aliased command (and thus the underlying Shell call) There doesn't appear to be a way to use project/solution relative paths ($SolutionDir/$ProjectDir) on a Shell call Using absolute paths in Shell works, but is fragile and high-maintenance (one alias for each needed use case). Typically you want the command to run against a file relative to your project/solution. It seems you can't run the traditional external tools (Tools-External Tools...) in the command window Ultimately I want the external tool functionality in the command window in some way. Can anyone see a way to do this? Or am I barking up the wrong tree? So my questions: Can an "external tool" of some sort (using relative project/solution path parameters) be used in the Command Window? If yes, How? If no, what might be a suitable alternative?

    Read the article

  • PHP - Open or copy a file when knowing only part of its name?

    - by Gary Willoughby
    I have a huge repository of files that are ordered by numbered folders. In each folder is a file which starts with a unique number then an unknown string of characters. Given the unique number how can i open or copy this file? for example: I have been given the number '7656875' and nothing more. I need to interact with a file called '\server\7656800\7656875 foobar 2x4'. how can i achieve this using PHP?

    Read the article

  • A file's web address is different from the local file structure

    - by allanb
    I'm not sure how best to describe this (as you can clearly tell from the title) so I'll give you an example: I have a multisite Drupal installation. Each of the sites' sitemap.xml files are located on the server at /sites/example.com/files though with a browser (and to search engines) it is accessible at example.com/sitemap.xml I was wondering how this was achieved? Is this called Virtual Directory? Thank you

    Read the article

  • Could I return a FileStream as a generic interface to a file?

    - by Eric
    I'm writing a class interface that needs to return references to binary files. Typically I would provide a reference to a file as a file path. However, I'm considering storing some of the files (such as a small thumbnail) in a database directly rather then on a file system. In this case I don't want to add the extra step of reading the thumbnail out of the database onto the disc and then returning a path to the file for my program to read. I'd want to stream the image directly out of the database into my program and avoid writing anything to the disc unless the user explicit wants to save something. Would having my interface return a FileStreamor even a Imagemake sense? Then it would be up to the implementing class to determine if the source of the FileStream or Image is a file on a disc or binary data in a database. public interface MyInterface { string Thumbnail {get;} string Attachment {get;} } vs public interface MyInterface { Image Thumbnail {get;} FileStream Attachment {get;} }

    Read the article

  • How do I create an empty file in emacs?

    - by Singletoned
    How can I create an empty file from emacs, ideally from within a dired buffer? For example, I've just opened a Python module in dired mode, created a new directory, opened that in dired, and now need to add an empty __init__.py file in the directory. If I use C-x C-f __init__.py RET C-x C-s then emacs doesn't create the file because no changes have been made to it. I would have to type in the file, save it, delete my typing and then save it again for that to work. Thanks

    Read the article

< Previous Page | 148 149 150 151 152 153 154 155 156 157 158 159  | Next Page >