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• download mbox files over https using python

  - by VenkatS

  I was trying to find the right module for downloading kernel patches from kernel.org site For example,to download the file at https://patchwork.kernel.org/patch/62948/mbox/ I understand urlgrabber has a problem with https on debian. urllib2 seems to have problem with this url as well (says getaddrinfo failed, even though there are no problems reaching other urls) Any help would be appreciated

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• Sorting elements in string with Python

  - by prosseek

  I need to sort string, and I came up with the following function. def mysort(comb_): str = [] size = len(comb_) for c in comb_: str.append(c) str.sort() return ''.join(str) Is there any way to make it compact?

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• Python: Converting a tuple to a string with 'err'

  - by skylarking

  Given this : import os import subprocess def check_server(): cl = subprocess.Popen(["nmap","10.7.1.71"], stdout=subprocess.PIPE) result = cl.communicate() print result check_server() check_server() returns this tuple: ('\nStarting Nmap 4.53 ( http://insecure.org ) at 2010-04-07 07:26 EDT\nInteresting ports on 10.7.1.71:\nNot shown: 1711 closed ports\nPORT STATE SERVICE\n21/tcp open ftp\n22/tcp open ssh\n80/tcp open http\n\nNmap done: 1 IP address (1 host up) scanned in 0.293 seconds\n', None) Changing the second line in the method to result, err = cl.communicate() results in check_server() returning : Starting Nmap 4.53 ( http://insecure.org ) at 2010-04-07 07:27 EDT Interesting ports on 10.7.1.71: Not shown: 1711 closed ports PORT STATE SERVICE 21/tcp open ftp 22/tcp open ssh 80/tcp open http Nmap done: 1 IP address (1 host up) scanned in 0.319 seconds Looks to be the case that the tuple is converted to a string, and the \n's are being stripped.... but how? What is 'err' and what exactly is it doing?

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• String concatenation produces incorrect output in Python?

  - by Brian

  I have this code: filenames=["file1","FILE2","file3","fiLe4"] def alignfilenames(): #build a string that can be used to add labels to the R variables. #format goal: suffixes=c(".fileA",".fileB") filestring='suffixes=c(".' for filename in filenames: filestring=filestring+str(filename)+'",".' print filestring[:-3] #now delete the extra characters filestring=filestring[-1:-4] filestring=filestring+')' print "New String" print str(filestring) alignfilenames() I'm trying to get the string variable to look like this format: suffixes=c(".fileA",".fileB".....) but adding on the final parenthesis is not working. When I run this code as is, I get: suffixes=c(".file1",".FILE2",".file3",".fiLe4" New String ) Any idea what's going on or how to fix it?

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• Get Path of Uploaded File using Python

  - by Ali

  Is it possible to get the full path of the file on the user's computer being uploaded to my site? Using os.path.abspath(fileitem.filename) simply gets me the address of where my script is executing from on my shared hosting server. FYI: fileitem = form['file'] and form = cgi.FieldStorage()

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• finding max in python as per some custom criterion

  - by MK

  Hi, I can do max(s) to find the max of a sequence. But suppose I want to compute max according to my own function , something like so - currmax = 0 def mymax(s) : for i in s : #assume arity() attribute is present currmax = i.arity() if i.arity() > currmax else currmax Is there a clean pythonic way of doing this? Thanks!

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• Best practice for Python Assert

  - by meade

  Is there a performance or code maintenance issue with using assert as part of the standard code instead of using it just for debugging purposes? Is assert x >= 0, 'x is less then zero' and better or worse then if x < 0: raise Exception, 'x is less then zero' Also, is there anyway to set a business rule like if x < 0 raise error that is always checked with out the try, except, finally so, if at anytime throughout the code x is < 0 an error is raised, like if you set assert x < 0 at the start of a function, anywhere within the function where x becomes less then 0 an exception is raised?

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• python file manipulation

  - by lakshmipathi

  I have a directory /tmp/dir with two types of file names /tmp/dir/abc-something-server.log /tmp/dir/xyz-something-server.log .. .. and /tmp/dir/something-client.log I need append a few lines (these lines are constant) to files end with "client.log" line 1 line 2 line 3 line 4 append these four lines to files end with "client.log" and For files end with "server.log" I needed to append after a keyword say "After-this". "server.log " file has multiple entries of "After-this" I need to find the first entry of "After-this" and append above said four lines keep the remaining file as it is. Any help will be great appreciated :) Thanks in advance.

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• python: can't terminate a thread hung in socket.recvfrom() call

  - by Dihlofos

  Hello, everyone I cannot get a way to terminate a thread that is hung in a socket.recvfrom() call. For example, ctrl+c that should trigger KeyboardInterrupt exception can't be caught. Here is a script I've used for testing: from socket import * from threading import Thread from sys import exit class TestThread(Thread): def __init__(self,host="localhost",port=9999): self.sock = socket(AF_INET,SOCK_DGRAM) self.sock.bind((host,port)) super(TestThread,self).__init__() def run(self): while True: try: recv_data,addr = self.sock.recvfrom(1024) except (KeyboardInterrupt, SystemExit): sys.exit() if __name__ == "__main__": server_thread = TestThread() server_thread.start() while True: pass The main thread (the one that executes infinite loop) exits. However the thread that I explicitly create, keeps hanging in recvfrom(). Please, help me resolve this.

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• Python singleton pattern

  - by Javier Garcia

  Hi, someone can tell me why this is incorrect as a singleton pattern: class preSingleton(object): def __call__(self): return self singleton = preSingleton() a = singleton() b = singleton() print a==b a.var_in_a = 100 b.var_in_b = 'hello' print a.var_in_b print b.var_in_a Edit: The above code prints: True hello 100 thank you very much

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• Python begineer confused by a piece of code

  - by Protean

  I understand the gist of the code, that it forms permutations; however, I was wondering if someone could explain exactly what is going on in the return statement. def perm(l): sz = len(l) print (l) if sz <= 1: print ('sz <= 1') return [l] return [p[:i]+[l[0]]+p[i:] for i in range(sz) for p in perm(l[1:])]

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• Python: For loop problem

  - by Yasmin

  I have a simple for loop problem, when i run the code below it prints out series of 'blue green' sequences then a series of 'green' sequences. I want the output to be; if row[4] is equal to 1 to print blue else print green. for row in rows: for i in `row[4]`: if i ==`1`: print 'blue ' else: print 'green ' Any help would be grateful thanks Yas

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• Match HTML tags in two strings using regex in Python

  - by jack

  I want to verify that the HTML tags present in a source string are also present in a target string. For example: >> source = '<em>Hello</em><label>What's your name</label>' >> verify_target(’<em>Hi</em><label>My name is Jim</label>') True >> verify_target('<label>My name is Jim</label><em>Hi</em>') True >> verify_target('<em>Hi<label>My name is Jim</label></em>') False

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• Take the intersection of an arbitrary number of lists in python

  - by thepandaatemyface

  Suppose I have a list of lists of elements which are all the same (i'll use ints in this example) [range(100)[::4], range(100)[::3], range(100)[::2], range(100)[::1]] What would be a nice and/or efficient way to take the intersection of these lists (so you would get every element that is in each of the lists)? For the example that would be: [0, 12, 24, 36, 48, 60, 72, 84, 96]

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• Small Python optional arguments question

  - by ooboo

  I have two functions: def f(a,b,c=g(b)): blabla def g(n): blabla c is an optional argument in function f. If the user does not specify its value, the program should compute g(b) and that would be the value of c. But the code does not compile - it says name 'b' is not defined. How to fix that? Someone suggested: def g(b): blabla def f(a,b,c=None): if c is None: c = g(b) blabla But this doesn't work, because maybe the user intended c to be None and then c will have another value.

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• Access static class variable of parent class in Python

  - by fuenfundachtzig

  I have someting like this class A: __a = 0 def __init__(self): A.__a = A.__a + 1 def a(self): return A.__a class B(A): def __init__(self): # how can I access / modify A.__a here? A.__a = A.__a + 1 # does not work def a(self): return A.__a Can I access the __astatic variable in B? It's possible writing a instead of __a, is this the only way? (I guess the answer might be rather short: yes :)

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• How to permanently change a variable in a Python game loop

  - by Wehrdo

  I have a game loop like this: #The velocity of the object velocity_x = 0.09 velocity_y = 0.03 #If the location of the object is over 5, bounce off. if loc_x > 5: velocity_x = (velocity_x * -1) if loc_y > 5: velocity_y = (velocity_y * -1) #Every frame set the object's position to the old position plus the velocity obj.setPosition([(loc_x + velocity_x),(loc_y + velocity_y),0]) Basically, my problem is that in the if loops, I change the variable from its original value to the inverse of its old value. But because I declare the variable's value at the beginning of the script, the velocity variables don't stay on what I change it to. I need a way to change the variable's value permanently. Thank you!

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• Python datetime to Unix timestamp

  - by Off Rhoden

  I have to create an "Expires" value 5 minutes in the future, but I have to supply it in UNIX Timestamp format. I have this so far, but it seems like a hack. def expires(): '''return a UNIX style timestamp representing 5 minutes from now''' epoch = datetime.datetime(1970, 1, 1) seconds_in_a_day = 60 * 60 * 24 five_minutes = datetime.timedelta(seconds=5*60) five_minutes_from_now = datetime.datetime.now() + five_minutes since_epoch = five_minutes_from_now - epoch return since_epoch.days * seconds_in_a_day + since_epoch.seconds Is there a module or function that does the timestamp conversion for me?

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• Plotting 3D Polygons in python-matplotlib

  - by Developer

  I was unsuccessful browsing web for a solution for the following simple question: How to draw 3D polygon (say a filled rectangle or triangle) using vertices values? I have tried many ideas but all failed, see: from mpl_toolkits.mplot3d import Axes3D from matplotlib.collections import PolyCollection import matplotlib.pyplot as plt fig = plt.figure() ax = Axes3D(fig) x = [0,1,1,0] y = [0,0,1,1] z = [0,1,0,1] verts = [zip(x, y,z)] ax.add_collection3d(PolyCollection(verts),zs=z) plt.show() I appreciate in advance any idea/comment. Updates based on the accepted answer: import mpl_toolkits.mplot3d as a3 import matplotlib.colors as colors import pylab as pl import scipy as sp ax = a3.Axes3D(pl.figure()) for i in range(10000): vtx = sp.rand(3,3) tri = a3.art3d.Poly3DCollection([vtx]) tri.set_color(colors.rgb2hex(sp.rand(3))) tri.set_edgecolor('k') ax.add_collection3d(tri) pl.show() Here is the result:

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• Python File Search Line And Return Specific Number of Lines after Match

  - by Simos Anderson

  I have a text file that has lines representing some data sets. The file itself is fairly long but it contains certain sections of the following format: Series_Name INFO Number of teams : n1 | Team | # | wins | | TeamName1 | x | y | . . . | TeamNamen1 | numn | numn | Some Irrelevant lines Series_Name2 INFO Number of teams : n1 | Team | # | wins | | TeamName1 | num1 | num2 | . where each section has a header that begins with the Series_Name. Each Series_Name is different. The line with the header also includes the number of teams in that series, n1. Following the header line is a set of lines that represents a table of data. For each series there are n1+1 rows in the table, where each row shows an individual team name and associated stats. I have been trying to implement a function that will allow the user to search for a Team name and then print out the line in the table associated with that team. However, certain team names show up under multiple series. To resolve this, I am currently trying to write my code so that the user can search for the header line with series name first and then print out just the following n1+1 lines that represent the data associated with the series. Here's what I have come up with so far: import re print fname = raw_input("Enter filename: ") seriesname = raw_input("Enter series: ") def findcounter(fname, seriesname): logfile = open(fname, "r") pat = 'INFO Number of teams :' for line in logfile: if seriesname in line: if pat in line: s=line pattern = re.compile(r"""(?P<name>.*?) #starting name \s*INFO #whitespace and success \s*Number\s*of\s*teams #whitespace and strings \s*\:\s*(?P<n1>.*)""",re.VERBOSE) match = pattern.match(s) name = match.group("name") n1 = int(match.group("n1")) print name + " has " + str(n1) + " teams" lcount = 0 for line in logfile: if line.startswith(name): if pat in line: while lcount <= n1: s.append(line) lcount += 1 return result The first part of my code works; it matches the header line that the person searches for, parses the line, and then prints out how many teams are in that series. Since the header line basically tells me how many lines are in the table, I thought that I could use that information to construct a loop that would continue printing each line until a set counter reached n1. But I've tried running it, and I realize that the way I've set it up so far isn't correct. So here's my question: How do you return a number of lines after a matched line when given the number of desired lines that follow the match? I'm new to programming, and I apologize if this question seems silly. I have been working on this quite diligently with no luck and would appreciate any help.

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• How to read a file with variable multi-row data in Python

  - by dr.bunsen

  I have a file that is about 100Mb that looks like this: #meta data 1 skadjflaskdjfasljdfalskdjfl sdkfjhasdlkgjhsdlkjghlaskdj asdhfk #meta data 2 jflaksdjflaksjdflkjasdlfjas ldaksjflkdsajlkdfj #meta data 3 alsdkjflasdjkfglalaskdjf This file contains one row of meta data that corresponds to several, variable length data containing only alpha-numeric characters. What is the best way to read this data into a simple list like this: data = [[#meta data 1, skadjflaskdjfasljdfalskdjflsdkfjhasdlkgjhsdlkjghlaskdjasdhfk], [#meta data 2, jflaksdjflaksjdflkjasdlfjasldaksjflkdsajlkdfj], [#meta data 3, alsdkjflasdjkfglalaskdjf]] My initial idea was to use the read() method to read the whole file into memory and then use regular expressions to parse the data into the desired format. Is there a better more pythonic way? All metadata lines start with an octothorpe and all data lines are all alpha-numeric. Thanks!

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• how to build good python web application

  - by Moayyad Yaghi

  hello i never worked with web programming and i've been asked lately to write a web-based software to manage assets and tasks. to be used by more than 900 persons what are the recommended modules , frameworks , libraries for this task. and it will be highly appreciated if you guyz recommend some books and articles that might help me. thanks in advance

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• Are there any alternatives to Mechanize in Python?

  - by user319723

  Could someone point me to some?

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• Working with multiple input and output files in Python

  - by Morlock

  I need to open multiple files (2 input and 2 output files), do complex manipulations on the lines from input files and then append results at the end of 2 output files. I am currently using the following approach: in_1 = open(input_1) in_2 = open(input_2) out_1 = open(output_1, "w") out_2 = open(output_2, "w") # Read one line from each 'in_' file # Do many operations on the DNA sequences included in the input files # Append one line to each 'out_' file in_1.close() in_2.close() out_1.close() out_2.close() The files are huge (each potentially approaching 1Go, that is why I am reading through these input files one at a time. I am guessing that this is not a very Pythonic way to do things. :) Would using the following form good? with open("file1") as f1: with open("file2") as f2: # etc. If yes, could I do it while avoiding the highly indented code that would result? Thanks for the insights!

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• How to get unique numbers using randomint python?

  - by user2519572

  I am creating a 'Euromillions Lottery generator' just for fun and I keep getting the same numbers printing out. How can I make it so that I get random numbers and never get the same number popping up: from random import randint numbers = randint(1,50) stars = randint(1,11) print "Your lucky numbers are: ", numbers, numbers, numbers, numbers, numbers print "Your lucky stars are: " , stars, stars The output is just: >>> Your lucky numbers are: 41 41 41 41 41 >>> Your lucky stars are: 8 8 >>> Good bye! How can I fix this? Regards

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