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  • What's the best way to implement news system without using wordpress ?

    - by Tristan
    Hello, I'm a little afraid of using Wordpress because of his connotation "all made", plus my website is 100% hand coded, actually, i use the phpBB but it's not what I want cause visitors have to go out of the website to go to the forum to see the news. So how/what can I do to have my own news system management (publish/review/moderate comments).... Are there tools (i mean except WYSIWYG) / PHP class I can use to implement myself ? I hope you understand what i mean. Thank you :)

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  • How to add facebook like in multiple blog post like your index file in wordpress?

    - by Kleigh Heart Garcia
    i would like to implement or add a facebook like button in my wordpress blog. But this time, i want it on my index file or in a multiple blog post. The problem is when I copy pasted what facebook is generating for me is it only "likes" my domain name or my index file, not the blog post which is suppose to be liked. What should i do to correctly add the facebook like button to work? thank you very much!

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  • Custom Upload Advanced Scripting CMS

    - by bradlis7
    I am looking for a specific content management platform that would display themes for my application. Requirements are as folllows: Any user can upload content, but has to be approved by an administrator When the user uploads the content, an external application is called to generate a thumbnail I could create this using codeigniter or something, but I would much prefer to use an existing system. I have experience with Drupal (seems a little bloated for my needs), and Wordpress (I'm using it as main website right now). Maybe I need a plugin for WordPress instead of another CMS. WordPress currently blocks uploads of my file type. I can modify it, but it's a pain to update it every time WordPress has a new release.

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  • Index page content identical to page 1 of a gallery-type website

    - by WordPress Developer
    I have a gallery type website, e.g. a site that lists blog posts or pictures in a paginated manner. However, I have 2 pages that have identical content: example.com/index.html example.com/page/1 Page 2, 3 and so on have different content naturally. However, for SEO purposes, what is the best way of telling Google that page 1 is identical to index.html? Should I 302 redirect index.html to /page/1 so index.html is non-existent, so to say or should I put a canonical tag in /page/1 (but not on /page/2) that points to index.html?

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  • Server Migration Checklist II

    - by merrillaldrich
    Easy Breezy Login Audit for your Ol’ 2000 Server In the last post on this topic I put up the preparatory steps I’ve been using for server migrations. Here I am posting some code that has worked well for us to trace who/what is connecting to our older SQL Server 2000 machines. It’s a simple audit of login events, tracing the login name, host name, database, and last login time for connections to the server, and gave us valuable insight into who was really using the machines and which databases might...(read more)

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  • Mod Rewrite not working on my addon domain

    - by Ogugua Belonwu
    have a wordpress website on my main domain For the wordpress website i have this in my .htaccess file # BEGIN WordPress <IfModule mod_rewrite.c> RewriteEngine On RewriteBase / RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule . /index.php </IfModule> # END WordPress I just created an addon domain and wanted to use new rules for it I created a .htaccess file and put it inside the addon folder eg /newaddon In the .htaccess file i have: Options -Indexes <IfModule mod_rewrite.c> RewriteEngine On RewriteBase / RewriteRule ^readjob/(.*)/(.*)/(.*)/$ readjob.php?id=$1&amp;cat=$2&amp;title=$3 </IfModule> The url stucture i have is this: http://www.website.com/readjob/3/jobs/web-designers-potech-integrated-services/ But it keeps telling me link is broken I dont know what to do, pls i need assistance (pls i just learnt mod rewriting today, so clarity will be highly appreciated) Thanks

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  • Avoid pagination pages from appearing higher than real content in SERPS

    - by WordPress Developer
    I have a gallery-type website that has about 20k of pages and naturally it uses pagination. However, sometimes /page/2 appears higher in search results than /post/201339 for example. I'd like to give emphasis to the actual content (posts, videos, whatever the site is about) and not on pages that merely list this content in a paginated matter. What is the best way to avoid this issue? Maybe a NOINDEX,FOLLOW meta tag on the paginated pages?

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  • Long 'Wait' Time for three php/CSS files. Is something blocking them?

    - by William Pitcher
    I have been speed optimizing a Wordpress site to little effect. There are three files CSS-related php files from the Wordpress theme that are delaying page loads on the site. One of the three files is basically one line of custom CSS from the custom CSS feature in the theme. You can see what I am talking about with this Pingdom speed test: The yellow is 'Wait'. There are no slow items in the cut-off portion of the image. The full results are here: Pingdom Results Page 1. Any thoughts on what might be causing this? I understand that I have blocking CSS or JS files, but I don't see anything that would be causing that long of a wait. When I ran the P3 Plugin Profiler, Wordpress and all plugins appeared fine -- it is the theme that is taking all the time. GTmetrix recommends avoiding dynamic queries. I assume all the ver=3.61 references are to the version of Wordpress (which I am using). I noticed that my Wordpress sites using other themes don't make this query (at least not over and over). 2. Is this typical coding practice? 3. How much negative impact do these query-strings have -- a little or a lot? I tried searching for similar questions here, please excuse me if I missed something. Sometimes, I know just enough to be dangerous.

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  • How to create a script which opens the browser and logins to a particular Gmail account?

    - by TechGuru
    I have created a bash script login.sh. I want it to open the browser and login to my Gmail account. I tried using the following command to open the browser with www.gmail.com. xdg-open http://gmail.com It opens Gmail home page perfectly. But I don't know how to pass the username and password for login to Gmail from the bash script. Is it possible to open the browser and login to Gmail from a script?

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  • Tips on Using Joomla SEO

    Joomla is one of the most popular content management systems on the web along with WordPress. It's much more complicated than WordPress, however, it provides a wide variety of features for small and medium size businesses. While WordPress is more of a blogging tool that can be customized to be a website, Joomla is a true content management system.

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  • visusal studio embedded crystal report keeps prompting database login?

    - by phill
    I'm using visual studio 2005 to develop a form with a combobox passing a value into the parameter of an embedded crystal report. I'm trying to figure out why it keeps prompting me for a database login every single time you try to run the report with a different combobox selection. Here is my code: private Sub Form1_load... Dim ConnName As String Dim ServerName As String Dim DBName As String Dim user As String Dim pass As String Dim gDBA As ADODB.Connection Dim records As ADODB.Recordset Dim datver As ADODB.Recordset Dim query As String '---OPEN THE DATABASE CONNECTIONS gDBA = New ADODB.Connection ': gDBA.CursorLocation = adUseServer 'Added to prevent time out error gDBA.CommandTimeout = 1000 : gDBA.ConnectionTimeout = 1000 gDBA.ConnectionString = "Server=svr13;Database=subscribers;User ID=KViews;Password=Solution;Trusted_Connection=True;" gDBA.Open("Data Source=Kaseya;Initial Catalog=subscribers;User Id=KViews;Password=Solution;", "KViews", "Solution") records = New ADODB.Recordset query = "select distinct groupname from _v_k order by groupname desc" 'records.ActiveConnection = gDBA.ConnectionString records.CursorType = CursorTypeEnum.adOpenForwardOnly records.LockType = LockTypeEnum.adLockReadOnly records.Open(query, gDBA) Do While Not records.EOF ComboBox1.Items.Add(records.Fields("groupname").Value) records.MoveNext() Loop end Sub Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click Dim selected As String selected = ComboBox1.Text Dim cryRpt As New ReportDocument cryRpt.Load("C:\Visual Studio 2005\Projects\WindowsApplication1\WindowsApplication1\CrystalReport1.rpt") cryRpt.SetDatabaseLogon("KViews", "Solutions", "svr13", "subscribers") cryRpt.SetParameterValue("companyname", selected) CrystalReportViewer1.ReportSource = cryRpt CrystalReportViewer1.Refresh() End Sub I looked at this previous posting http://stackoverflow.com/questions/1132314/database-login-prompt-with-crystal-reports but this wasn't very helpful. I couldn't find where a CMC was to disable the prompt. Any ideas? thanks in advance

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  • Login failed for user ''. The user is not associated with a trusted SQL Server connection

    - by Tony_Henrich
    My web service app on my Windows XP box is trying to log in to my sql server 2005 database on the same box. The machine is part of a domain. I am logged in in the domain and I am an admin on my machine. I am using Windows Authentication in my connection string as in "Server=myServerAddress;Database=myDataBase;Trusted_Connection=True". SQLServer is configured for both types of authentication (mixed mode) and accepts remote connections and accepts tcp and named pipes protocols. Integrated authentication is enabled in IIS and with and without anonymous access. 'Everyone' has access to computer from network setting in local security settings. ASPNET is a user in the sql server and has access to the daatabase. user is mapped to the login. The app works fine for other developers which means the app shouldn't be changed (It's not new code). So it seems it's my machine which has an issue. I am getting the error "Login failed for user ''. The user is not associated with a trusted SQL Server connection" Note the blank user name. Why am I getting this error when both the app and database are on my machine? I can use SQL Server authentication but don't want to. I can connect to the database using SSMS and my Windows credentials. It might be related to setspn, kerberos, delegation, AD. I am not sure what further checks to make?

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  • does red5 read tomcat-users.xml

    - by baba
    Hi, I have been busy creating an app for Red5. Imagine what was my surprise when I tried to configure basic/digest authentication and I couldn't. What struck me as strange is that I have a running tomcat instance that works and authenticates correctly with the following xmls: web.xml (part of) <security-constraint> <web-resource-collection> <web-resource-name>A Protected Page</web-resource-name> <url-pattern>/stats.jsp</url-pattern> </web-resource-collection> <auth-constraint> <description/> <role-name>tomcat</role-name> </auth-constraint> </security-constraint> <login-config> <auth-method>DIGEST</auth-method> <realm-name>BLAAAAAAAAAAAAAAAAA</realm-name> </login-config> <security-role> <description/> <role-name>tomcat</role-name> </security-role> and a tomcat-users.xml in /conf that looks kinda like this: <?xml version="1.0" encoding="UTF-8"?> <tomcat-users> <role rolename="tomcat"/> <user username="ide" password="bogus" roles="tomcat"/> </tomcat-users> The annoying thing is that configuration authenticates correctly when on tomcat's servlet container, but on the red5's modified one, it just keeps asking for authentication. Am I becoming mad or it should work like a charm? Red5 is version 0_9_1 The stats.jsp is accessible in both servlet containers, the only difference is that when you input the correct password and username in tomcat, you are logged in, and in red5 you are not, it just keeps asking you for the password. Any pointers? Am I missing something? Here is a stack trace of the error I receive AT the moment I try the login: Caused by: java.io.IOException: Unable to locate a login configuration at com.sun.security.auth.login.ConfigFile.init(ConfigFile.java:250) [na:1.6.0_22] at com.sun.security.auth.login.ConfigFile.<init>(ConfigFile.java:91) [na:1.6.0_22] ... 27 common frames omitted [ERROR] [http-127.0.0.1-5080-1] org.apache.catalina.realm.JAASRealm - Cannot find message associated with key jaasRealm.unexpectedError java.lang.SecurityException: Unable to locate a login configuration at com.sun.security.auth.login.ConfigFile.<init>(ConfigFile.java:93) [na:1.6.0_22] at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method) [na:1.6.0_22] at sun.reflect.NativeConstructorAccessorImpl.newInstance(NativeConstructorAccessorImpl.java:39) [na:1.6.0_22] at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(DelegatingConstructorAccessorImpl.java:27) [na:1.6.0_22] at java.lang.reflect.Constructor.newInstance(Constructor.java:513) [na:1.6.0_22] at java.lang.Class.newInstance0(Class.java:355) [na:1.6.0_22] at java.lang.Class.newInstance(Class.java:308) [na:1.6.0_22] at javax.security.auth.login.Configuration$3.run(Configuration.java:247) [na:1.6.0_22] at java.security.AccessController.doPrivileged(Native Method) [na:1.6.0_22] at javax.security.auth.login.Configuration.getConfiguration(Configuration.java:242) [na:1.6.0_22] at javax.security.auth.login.LoginContext$1.run(LoginContext.java:237) [na:1.6.0_22] at java.security.AccessController.doPrivileged(Native Method) [na:1.6.0_22] at javax.security.auth.login.LoginContext.init(LoginContext.java:234) [na:1.6.0_22] at javax.security.auth.login.LoginContext.<init>(LoginContext.java:403) [na:1.6.0_22] at org.apache.catalina.realm.JAASRealm.authenticate(JAASRealm.java:394) [catalina-6.0.24.jar:na] at org.apache.catalina.realm.JAASRealm.authenticate(JAASRealm.java:357) [catalina-6.0.24.jar:na] at org.apache.catalina.authenticator.DigestAuthenticator.findPrincipal(DigestAuthenticator.java:283) [catalina-6.0.24.jar:na] at org.apache.catalina.authenticator.DigestAuthenticator.authenticate(DigestAuthenticator.java:176) [catalina-6.0.24.jar:na] at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:523) [catalina-6.0.24.jar:na] at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127) [catalina-6.0.24.jar:na] at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102) [catalina-6.0.24.jar:na] at org.apache.catalina.valves.AccessLogValve.invoke(AccessLogValve.java:555) [catalina-6.0.24.jar:na] at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109) [catalina-6.0.24.jar:na] at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:298) [catalina-6.0.24.jar:na] at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:852) [tomcat-coyote-6.0.24.jar:na] at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:588) [tomcat-coyote-6.0.24.jar:na] at org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:489) [tomcat-coyote-6.0.24.jar:na] at java.lang.Thread.run(Thread.java:662) [na:1.6.0_22] Caused by: java.io.IOException: Unable to locate a login configuration at com.sun.security.auth.login.ConfigFile.init(ConfigFile.java:250) [na:1.6.0_22] at com.sun.security.auth.login.ConfigFile.<init>(ConfigFile.java:91) [na:1.6.0_22] ... 27 common frames omitted In addition, here is the configuration of red5-web.properties webapp.contextPath=/project Even futher information: Seems to me like it is using the right realm: MemoryRealm [INFO] [main] org.red5.server.tomcat.TomcatLoader - Setting connector: org.apache.catalina.connector.Connector [INFO] [main] org.red5.server.tomcat.TomcatLoader - Address to bind: /127.0.0.1:5080 [INFO] [main] org.red5.server.tomcat.TomcatLoader - Setting realm: org.apache.catalina.realm.MemoryRealm [INFO] [main] org.red5.server.tomcat.TomcatLoader - Loading tomcat context [INFO] [main] org.red5.server.tomcat.TomcatLoader - Server root: C:/Program Files/Red5 [INFO] [main] org.red5.server.tomcat.TomcatLoader - Config root: C:/Program Files/Red5/conf [INFO] [main] org.red5.server.tomcat.TomcatLoader - Application root: C:/Program Files/Red5/webapps [INFO] [main] org.red5.server.tomcat.TomcatLoader - Starting Tomcat servlet engine [INFO] [main] org.apache.catalina.startup.Embedded - Starting tomcat server [INFO] [main] org.apache.catalina.core.StandardEngine - Starting Servlet Engine: Apache Tomcat/6.0.26 However, immediately after bootstraping Tomcat, I am presented with the following error: Exception in thread "Launcher:/administration" org.springframework.beans.factory.BeanDefinitionStoreException: Could not resolve bean definition resource pattern [/WEB-INF/red5-*.xml]; nested exception is java.io.FileNotFoundException: ServletContext resource [/WEB-INF/] cannot be resolved to URL because it does not exist at org.springframework.beans.factory.support.AbstractBeanDefinitionReader.loadBeanDefinitions(AbstractBeanDefinitionReader.java:190) at org.springframework.beans.factory.support.AbstractBeanDefinitionReader.loadBeanDefinitions(AbstractBeanDefinitionReader.java:149) at org.springframework.web.context.support.XmlWebApplicationContext.loadBeanDefinitions(XmlWebApplicationContext.java:124) at org.springframework.web.context.support.XmlWebApplicationContext.loadBeanDefinitions(XmlWebApplicationContext.java:93) at org.springframework.context.support.AbstractRefreshableApplicationContext.refreshBeanFactory(AbstractRefreshableApplicationContext.java:130) at org.springframework.context.support.AbstractApplicationContext.obtainFreshBeanFactory(AbstractApplicationContext.java:458) at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:388) at org.red5.server.tomcat.TomcatLoader$1.run(TomcatLoader.java:594) Caused by: java.io.FileNotFoundException: ServletContext resource [/WEB-INF/] cannot be resolved to URL because it does not exist at org.springframework.web.context.support.ServletContextResource.getURL(ServletContextResource.java:132) at org.springframework.core.io.support.PathMatchingResourcePatternResolver.isJarResource(PathMatchingResourcePatternResolver.java:414) at org.springframework.core.io.support.PathMatchingResourcePatternResolver.findPathMatchingResources(PathMatchingResourcePatternResolver.java:343) at org.springframework.core.io.support.PathMatchingResourcePatternResolver.getResources(PathMatchingResourcePatternResolver.java:282) at org.springframework.context.support.AbstractApplicationContext.getResources(AbstractApplicationContext.java:1156) at org.springframework.beans.factory.support.AbstractBeanDefinitionReader.loadBeanDefinitions(AbstractBeanDefinitionReader.java:177) ... 7 more This error is kinda strange, because after this it seems that /WEB-INF/ is found by the rest of the program by the following output: [INFO] [Launcher:/SOSample] org.springframework.beans.factory.config.PropertyPlaceholderConfigurer - Loading properties file from ServletContext resource [/WEB-INF/red5-web.properties] [INFO] [Launcher:/installer] org.springframework.beans.factory.config.PropertyPlaceholderConfigurer - Loading properties file from ServletContext resource [/WEB-INF/red5-web.properties] [INFO] [Launcher:/] org.springframework.beans.factory.config.PropertyPlaceholderConfigurer - Loading properties file from ServletContext resource [/WEB-INF/red5-web.properties] [INFO] [Launcher:/LiveMedia] org.springframework.beans.factory.config.PropertyPlaceholderConfigurer - Loading properties file from ServletContext resource [/WEB-INF/red5-web.properties] What really annoys me is that, as you can see in the output, when I try to login, I get a JAASRealm-related exception, but in the debug output when Tomcat is loading, it is clear to me that it expects a MemoryRealm. I was wondering where and how in red5.xml should I specify bean properties such that I force red5 to use MemoryRealm that is under /conf/tomcat-users.xml, because it certainly doesn't do so now. It seems like the biggest question I have posted so far, but I tried to explain it as fully as possible as to avoid confusion.

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  • HTTP status 405 - HTTP method POST is not supported by this URL

    - by Wont Say
    I am getting this "HTTP method POST is not supported by this URL" error when I run my project. The funny thing is, it was running perfectly fine two days ago. After I made a few changes to my code but then restored my original code and its giving me this error. Could you please help me? Here is my index.html: <form method="post" action="login.do"> <div> <table> <tr><td>Username: </td><td><input type="text" name="e_name"/> </td> </tr> <tr><td> Password: </td><td><input type="password" name="e_pass"/> </td> </tr> <tr><td></td><td><input type="submit" name ="e_submit" value="Submit"/> Here is my Login servlet: public class Login extends HttpServlet { /** * Processes requests for both HTTP * <code>GET</code> and * <code>POST</code> methods. * * @param request servlet request * @param response servlet response * @throws ServletException if a servlet-specific error occurs * @throws IOException if an I/O error occurs */ protected void processRequest(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException, SQLException { response.setContentType("text/html;charset=UTF-8"); PrintWriter out = response.getWriter(); try { /* * TODO output your page here. You may use following sample code. */ int status; String submit = request.getParameter("e_submit"); String submit2 = request.getParameter("a_submit"); out.println("Here1"); String e_name = request.getParameter("e_name"); String e_password = request.getParameter("e_pass"); String a_name = request.getParameter("a_name"); String a_password = request.getParameter("a_pass"); out.println(e_name+e_password+a_name+a_password); Author author = new Author(a_name,a_password); Editor editor = new Editor(e_name,e_password); // If it is an AUTHOR login: if(submit==null){ status = author.login(author); out.println("Author Login"); //Incorrect login details if(status==0) { out.println("Incorrect"); RequestDispatcher view = request.getRequestDispatcher("index_F.html"); view.forward(request, response); } //Correct login details --- AUTHOR else { out.println("Correct login details"); HttpSession session = request.getSession(); session.setAttribute(a_name, "a_name"); RequestDispatcher view = request.getRequestDispatcher("index_S.jsp"); view.forward(request, response); } } //If it is an EDITOR login else if (submit2==null){ status = editor.login(editor); //Incorrect login details if(status==0) { RequestDispatcher view = request.getRequestDispatcher("index_F.html"); view.forward(request, response); } //Correct login details --- EDITOR else { out.println("correct"); HttpSession session = request.getSession(); session.setAttribute(e_name, "e_name"); session.setAttribute(e_password, "e_pass"); RequestDispatcher view = request.getRequestDispatcher("index_S_1.html"); view.forward(request, response); } } out.println("</body>"); out.println("</html>"); } finally { out.close(); } } @Override protected void doPost(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException { super.doPost(req, resp); } @Override protected void doGet(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException { super.doGet(req, resp); }} And my web.xml looks like this: <?xml version="1.0" encoding="UTF-8"?> <servlet> <servlet-name>action</servlet-name> <servlet-class>org.apache.struts.action.ActionServlet</servlet-class> <init-param> <param-name>config</param-name> <param-value>/WEB-INF/struts-config.xml</param-value> </init-param> <init-param> <param-name>debug</param-name> <param-value>2</param-value> </init-param> <init-param> <param-name>detail</param-name> <param-value>2</param-value> </init-param> <load-on-startup>2</load-on-startup> </servlet> <servlet> <servlet-name>Login</servlet-name> <servlet-class>controller.Login</servlet-class> </servlet> <servlet-mapping> <servlet-name>action</servlet-name> <url-pattern>*.do</url-pattern> </servlet-mapping> <servlet-mapping> <servlet-name>Login</servlet-name> <url-pattern>/login.do</url-pattern> </servlet-mapping> <session-config> <session-timeout> 30 </session-timeout> </session-config> <welcome-file-list> <welcome-file>index.html</welcome-file> </welcome-file-list> I use Glassfish v3 server - let me know anything else you need to know

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  • Outlook 2007 Does Not Accept Login Credentials, OWA Webmail Does. Troubleshooting Advice?

    - by Chris
    I am trying to connect Outlook 2007 to Exchange (Hosted Exchange from Rackspace). Soon, I will need to roll this out for our entire office. With the Exchange account added to Outlook, Outlook starts up and asks for the user's username and password. Unfortunately, it doesn't like the password I use for it. I can confirm this username (email address) and password combo works by using Outlook WebMail, and another user (in another network/office) confirmed the Exchange account does work within his Outlook client. In my network/office, I can confirm that an Outlook 2007 client (under Windows 7) can connect to the Hosted Exchange server from Rackspace. However, I have not been able to get Outlook 2007 (under Windows XP SP3) to connect to the very same Exchange server Outlook 2007 (under Windows 7) can connect to. Outlook continuously prompts me for the username and password and does not accept the correct combination. Now, regarding the Outlook client that cannot connect/login to Exchange: The user has full admin rights on the workstation We do not run a domain controller/LDAP The firewall on the workstation has been disabled Real time file scanning in Microsoft Security Essentials has been disabled There are no virus scanning applications that would interface with Outlook or an email server. The Exchange account is setup to run on a newly created Outlook profile The network firewall does not log any blocked attempts A packet capture at the router reveals communication between the workstation and the Exchange server or proxy (though, this is SSL encrypted, so I don't know what the computers are saying) I have applied a fix (Added DWORD value of 0 for DefConnectOpts under HKEY_CURRENT_USER\Software\Microsoft\Office\12.0\Outlook\RPC) that was recommended to make RPC function when the workstation does not have a default gateway set. Workstation is configured as DHCP. This fix did nothing, and it may be worth noting the RPC subkey was not present until I added it. RPC service is running on the workstation The program is not running under any compatibility mode. Side note: Outlook 2007 installs with compatibility mode for XP enabled by default in windows 7. Outlook 2007 will not even try to connect to exchange if this compatibility mode is checked. In windows xp, I tried checking compatibility mode for windows 2000, and was unable to connect to exchange as well. Here is the specific configuration I've used in a blank outlook profile: Microsoft Exchange Server: ##MASKED##-MBX-C18.mex07a.mlsrvr.com Username: (Full Email Address: [email protected]) Password: ##MASKED## Outlook Anywhere: Connect to Microsoft Exchange using HTTP Exchange Proxy Settings: Proxy Server: mex07a.emailsrvr.com Check "Connect using SSL only" Under "Only connect to proxy servers...", enter: msstd:mex07a.emailsrvr.com Check "On fast networks, connect using HTTP first, then connect using TCP/IP" Check "On slow networks, connect using HTTP first, then connect using TCP/IP" Proxy authentication settings: Basic Authentication Notes: mex07a.mlsrvr.com and mex07a.emailsrvr.com may look incorrect at first glance, but this is not a typo - these instructions were handed down from rackspace and are confirmed to be working, just not on this workstation. I have tried to use the RpcPing utility but must have been using it wrong. I got as far as "Bad Interface Descriptor". It would seem to me getting Outlook and Exchange to work together would be a breeze, especially since everything is done over port 80 with web services. Unfortunately, the user is stuck with WebMail access only, because Outlook won't accept the Exchange credentials. Do you have any ideas of other things I could try to debug this issue further? Any and all help is greatly appreciated. Thank you! -Chris

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  • System.AccessViolationException when calling DLL from WCF on IIS.

    - by Wodzu
    Hi guys. I've created just a test WCF service in which I need to call an external DLL. Everything works fine under Visutal Studio development server. However, when I try to use my service on IIS I am getting this error: Exception: System.AccessViolationException Message: Attempted to read or write protected memory. This is often an indication that other memory is corrupt. The stack trace leeds to the call of DLL which is presented below. After a lot of reading and experimenting I am almost sure that the error is caused by wrong passing strings to the called function. Here is how the wrapper for DLL looks like: using System; using System.Runtime.InteropServices; using System.Text; using System; using System.Security; using System.Security.Permissions; using System.Runtime.InteropServices; namespace cdn_api_wodzu { public class cdn_api_wodzu { [DllImport("cdn_api.dll", CharSet=CharSet.Ansi)] // [SecurityPermission(SecurityAction.Assert, Unrestricted = true)] public static extern int XLLogin([In, Out] XLLoginInfo _lLoginInfo, ref int _lSesjaID); } [Serializable, StructLayout(LayoutKind.Sequential)] public class XLLoginInfo { public int Wersja; public int UtworzWlasnaSesje; public int Winieta; public int TrybWsadowy; [MarshalAs(UnmanagedType.ByValTStr, SizeConst = 0x29)] public string ProgramID; [MarshalAs(UnmanagedType.ByValTStr, SizeConst = 0x15)] public string Baza; [MarshalAs(UnmanagedType.ByValTStr, SizeConst = 9)] public string OpeIdent; [MarshalAs(UnmanagedType.ByValTStr, SizeConst = 9)] public string OpeHaslo; [MarshalAs(UnmanagedType.ByValTStr, SizeConst = 200)] public string PlikLog; [MarshalAs(UnmanagedType.ByValTStr, SizeConst = 0x65)] public string SerwerKlucza; public XLLoginInfo() { } } } this is how I call the DLL function: int ErrorID = 0; int SessionID = 0; XLLoginInfo Login; Login = new XLLoginInfo(); Login.Wersja = 18; Login.UtworzWlasnaSesje = 1; Login.Winieta = -1; Login.TrybWsadowy = 1; Login.ProgramID = "TestProgram"; Login.Baza = "TestBase"; Login.OpeIdent = "TestUser"; Login.OpeHaslo = "TestPassword"; Login.PlikLog = "C:\\LogFile.txt"; Login.SerwerKlucza = "MyServ\\MyInstance"; ErrorID = cdn_api_wodzu.cdn_api_wodzu.XLLogin(Login, ref SessionID); When I comment all the string field assigments the function works - it returns me an error message that the program ID has not been given. But when I try to assign a ProgramID (or any other string fields, or all at once) then I am getting the mentioned exception. I am using VS2008 SP.1, WinXP and IIS 5.1. Maybe the ISS itself is a problem? I've tried all the workarounds that has been described here: http://forums.asp.net/t/675515.aspx Thansk for your time. After edit: Installing Windows 2003 Server and IIS 6.0 solved the problem.

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  • Why does the interpretted order seem different from what I expect?

    - by inspectorG4dget
    I have a problem that I have not faced before: It seems that the order of interpretation in my program is somehow different from what I expect. I have written a small Twitter client. It takes a few seconds for my program to actually post a tweet after I click the "GO" button (which can also be activated by hitting ENTER on the keyboard). I don't want to click multiple times within this time period thinking that I hadn't clicked it the first time. Therefore, when the button is clicked, I would like the label text to display something that tells me that the button has been clicked. I have implemented this message by altering the label text before I send the tweet across. However, for some reason, the message does not display until the tweet has been attempted. But since I have a confirmation message after the tweet, I never get to see this message and my original problem goes unsolved. I would really appreciate any help. Here is the relevant code: class SimpleTextBoxForm(Form): def init(self): # set window properties self.Text = "Tweeter" self.Width = 235 self.Height = 250 #tweet away self.label = Label() self.label.Text = "Tweet Away..." self.label.Location = Point(10, 10) self.label.Height = 25 self.label.Width = 200 #get the tweet self.tweetBox = TextBox() self.tweetBox.Location = Point(10, 45) self.tweetBox.Width = 200 self.tweetBox.Height = 60 self.tweetBox.Multiline = True self.tweetBox.WordWrap = True self.tweetBox.MaxLength = 140; #ask for the login ID self.askLogin = Label() self.askLogin.Text = "Login:" self.askLogin.Location = Point(10, 120) self.askLogin.Height = 20 self.askLogin.Width = 60 self.login = TextBox() self.login.Text= "" self.login.Location = Point(80, 120) self.login.Height = 40 self.login.Width = 100 #ask for the password self.askPass = Label() self.askPass.Text = "Password:" self.askPass.Location = Point(10, 150) self.askPass.Height = 20 self.askPass.Width = 60 # display password box with character hiding self.password = TextBox() self.password.Location = Point(80, 150) self.password.PasswordChar = "x" self.password.Height = 40 self.password.Width = 100 #submit button self.button1 = Button() self.button1.Text = 'Tweet' self.button1.Location = Point(10, 180) self.button1.Click += self.update self.AcceptButton = self.button1 #pack all the elements of the form self.Controls.Add(self.label) self.Controls.Add(self.tweetBox) self.Controls.Add(self.askLogin) self.Controls.Add(self.login) self.Controls.Add(self.askPass) self.Controls.Add(self.password) self.Controls.Add(self.button1) def update(self, sender, event): if not self.password.Text: self.label.Text = "You forgot to enter your password..." else: self.tweet(self.tweetBox.Text, self.login.Text, self.password.Text) def tweet(self, msg, login, password): self.label.Text = "Attempting Tweet..." # this should be executed before sending the tweet is attempted. But this seems to be executed only after the try block try: success = 'Tweet successfully completed... yay!\n' + 'At: ' + time.asctime().split()[3] ServicePointManager.Expect100Continue = False Twitter().UpdateAsXML(login, password, msg) except: error = 'Unhandled Exception. Tweet unsuccessful' self.label.Text = error else: self.label.Text = success self.tweetBox.Text = ""

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  • Why does the interpreted order seem different from what I expect?

    - by inspectorG4dget
    I have a problem that I have not faced before: It seems that the order of interpretation in my program is somehow different from what I expect. I have written a small Twitter client. It takes a few seconds for my program to actually post a tweet after I click the "GO" button (which can also be activated by hitting ENTER on the keyboard). I don't want to click multiple times within this time period thinking that I hadn't clicked it the first time. Therefore, when the button is clicked, I would like the label text to display something that tells me that the button has been clicked. I have implemented this message by altering the label text before I send the tweet across. However, for some reason, the message does not display until the tweet has been attempted. But since I have a confirmation message after the tweet, I never get to see this message and my original problem goes unsolved. I would really appreciate any help. Here is the relevant code: class SimpleTextBoxForm(Form): def __init__(self): # set window properties self.Text = "Tweeter" self.Width = 235 self.Height = 250 #tweet away self.label = Label() self.label.Text = "Tweet Away..." self.label.Location = Point(10, 10) self.label.Height = 25 self.label.Width = 200 #get the tweet self.tweetBox = TextBox() self.tweetBox.Location = Point(10, 45) self.tweetBox.Width = 200 self.tweetBox.Height = 60 self.tweetBox.Multiline = True self.tweetBox.WordWrap = True self.tweetBox.MaxLength = 140; #ask for the login ID self.askLogin = Label() self.askLogin.Text = "Login:" self.askLogin.Location = Point(10, 120) self.askLogin.Height = 20 self.askLogin.Width = 60 self.login = TextBox() self.login.Text= "" self.login.Location = Point(80, 120) self.login.Height = 40 self.login.Width = 100 #ask for the password self.askPass = Label() self.askPass.Text = "Password:" self.askPass.Location = Point(10, 150) self.askPass.Height = 20 self.askPass.Width = 60 # display password box with character hiding self.password = TextBox() self.password.Location = Point(80, 150) self.password.PasswordChar = "x" self.password.Height = 40 self.password.Width = 100 #submit button self.button1 = Button() self.button1.Text = 'Tweet' self.button1.Location = Point(10, 180) self.button1.Click += self.update self.AcceptButton = self.button1 #pack all the elements of the form self.Controls.Add(self.label) self.Controls.Add(self.tweetBox) self.Controls.Add(self.askLogin) self.Controls.Add(self.login) self.Controls.Add(self.askPass) self.Controls.Add(self.password) self.Controls.Add(self.button1) def update(self, sender, event): if not self.password.Text: self.label.Text = "You forgot to enter your password..." else: self.tweet(self.tweetBox.Text, self.login.Text, self.password.Text) def tweet(self, msg, login, password): self.label.Text = "Attempting Tweet..." # this should be executed before sending the tweet is attempted. But this seems to be executed only after the try block try: success = 'Tweet successfully completed... yay!\n' + 'At: ' + time.asctime().split()[3] ServicePointManager.Expect100Continue = False Twitter().UpdateAsXML(login, password, msg) except: error = 'Unhandled Exception. Tweet unsuccessful' self.label.Text = error else: self.label.Text = success self.tweetBox.Text = ""

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  • java.lang.ClassCastException: java.lang.Integer cannot be cast

    - by theJava
    When i click on login, it checks the DB if there is a value matching then i get this error, else it does print me null. public Login authenticate(Login login) { String query = "SELECT 1 FROM Login AS l WHERE l.email=? AND l.password=?"; Object[] parameters = { login.getEmail(), login.getPassword() }; List resultsList = getHibernateTemplate().find(query,parameters); if (resultsList.isEmpty()) { } else if (resultsList.size() > 1) { } else { Login login1 = (Login) resultsList.get(0); System.out.println("Hello" + login1); return login1; } return null; } Error below Cause: java.lang.ClassCastException: java.lang.Integer cannot be cast to com.intermedix.domain.Login at com.vaadin.event.ListenerMethod.receiveEvent(ListenerMethod.java:507) at com.vaadin.event.EventRouter.fireEvent(EventRouter.java:161) at com.vaadin.ui.AbstractComponent.fireEvent(AbstractComponent.java:1154) at com.vaadin.ui.Button.fireClick(Button.java:371) at com.vaadin.ui.Button.changeVariables(Button.java:193) at com.vaadin.terminal.gwt.server.AbstractCommunicationManager.handleVariables(AbstractCommunicationManager.java:1094) at com.vaadin.terminal.gwt.server.AbstractCommunicationManager.doHandleUidlRequest(AbstractCommunicationManager.java:590) at com.vaadin.terminal.gwt.server.CommunicationManager.handleUidlRequest(CommunicationManager.java:266) at com.vaadin.terminal.gwt.server.AbstractApplicationServlet.service(AbstractApplicationServlet.java:476) at javax.servlet.http.HttpServlet.service(HttpServlet.java:820) at org.mortbay.jetty.servlet.ServletHolder.handle(ServletHolder.java:511) at org.mortbay.jetty.servlet.ServletHandler.handle(ServletHandler.java:390) at org.mortbay.jetty.security.SecurityHandler.handle(SecurityHandler.java:216) at org.mortbay.jetty.servlet.SessionHandler.handle(SessionHandler.java:182) at org.mortbay.jetty.handler.ContextHandler.handle(ContextHandler.java:765) at org.mortbay.jetty.webapp.WebAppContext.handle(WebAppContext.java:418) at org.mortbay.jetty.handler.ContextHandlerCollection.handle(ContextHandlerCollection.java:230) at org.mortbay.jetty.handler.HandlerCollection.handle(HandlerCollection.java:114) at org.mortbay.jetty.handler.HandlerWrapper.handle(HandlerWrapper.java:152) at org.mortbay.jetty.Server.handle(Server.java:326) at org.mortbay.jetty.HttpConnection.handleRequest(HttpConnection.java:542) at org.mortbay.jetty.HttpConnection$RequestHandler.content(HttpConnection.java:943) at org.mortbay.jetty.HttpParser.parseNext(HttpParser.java:756) at org.mortbay.jetty.HttpParser.parseAvailable(HttpParser.java:218) at org.mortbay.jetty.HttpConnection.handle(HttpConnection.java:404) at org.mortbay.io.nio.SelectChannelEndPoint.run(SelectChannelEndPoint.java:410) at org.mortbay.thread.QueuedThreadPool$PoolThread.run(QueuedThreadPool.java:582) Caused by: java.lang.ClassCastException: java.lang.Integer cannot be cast to com.intermedix.domain.Login at com.intermedix.services.LoginService.authenticate(LoginService.java:34) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) at java.lang.reflect.Method.invoke(Method.java:597) at org.springframework.aop.support.AopUtils.invokeJoinpointUsingReflection(AopUtils.java:301) at org.springframework.aop.framework.ReflectiveMethodInvocation.invokeJoinpoint(ReflectiveMethodInvocation.java:182) at org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(ReflectiveMethodInvocation.java:149) at org.springframework.transaction.interceptor.TransactionInterceptor.invoke(TransactionInterceptor.java:106) at org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(ReflectiveMethodInvocation.java:171) at org.springframework.aop.framework.JdkDynamicAopProxy.invoke(JdkDynamicAopProxy.java:204) at $Proxy32.authenticate(Unknown Source) at com.intermedix.ui.LoginDailog.checkLogin(LoginDailog.java:106) at com.intermedix.ui.LoginDailog.access$0(LoginDailog.java:102) at com.intermedix.ui.LoginDailog$1.buttonClick(LoginDailog.java:52) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) at java.lang.reflect.Method.invoke(Method.java:597) at com.vaadin.event.ListenerMethod.receiveEvent(ListenerMethod.java:487) ... 26 more

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  • Screen-scraping a site with a asp.net form login in C#?

    - by Ajit
    Hi Friends, i've created a web application in asp.net so far. where i've tried to get some data(site scraping) from secure page of a web site.I've used the HttpWebRequest class for this functionality but i haven't accessed the secure page yet. Every time the login pages was scraped not secure page.I have the site user id and password and don't know that which language site has been developed in. Please advice what should i do ?

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  • Python - create blacklist file of IP addresses that have more than 5 failed login attempts in the au

    - by oz_babe
    Basically I have an authlog/syslog file with a list of log in attempts and IP addresses - I need to make a Python program that will create a txt file with all the IP addresses that have more than 5 failed login attempts - a sort of "blacklist". So basically something like: if "uniqueipaddress" and "authentication failure" appear more than 5 times, add uniqueipaddress to txt file. Any help would be greatly appreciated - please try and make it simple as I am very, very inexperienced in programming in Python! Thanks.

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  • Do you think it's a good idea to create a login box as a user control?

    - by Sergio Tapia
    Hi there guys! I'm starting out learning some ASP.Net programming and I'm going to be making a little community website for my friends and myself. I'm trying to pick up some good habits along the way. I was thinking of having a usercontrol and have that 'loginBox' shows the appropriate textboxes and login button, but also show his username when he is logged in. Do you think I should handle this as a user control or am I missing something as an ASP.Net newbie?

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