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  • How to draw line inside a scatter plot

    - by ruffy
    I can't believe that this is so complicated but I tried and googled for a while now. I just want to analyse my scatter plot with a few graphical features. For starters, I want to add simply a line. So, I have a few (4) points and like in this plot [1] I want to add a line to it. http://en.wikipedia.org/wiki/File:ROC_space-2.png [1] Now, this won't work. And frankly, the documentation-examples-gallery combo and content of matplotlib is a bad source for information. My code is based upon a simple scatter plot from the gallery: # definitions for the axes left, width = 0.1, 0.85 #0.65 bottom, height = 0.1, 0.85 #0.65 bottom_h = left_h = left+width+0.02 rect_scatter = [left, bottom, width, height] # start with a rectangular Figure fig = plt.figure(1, figsize=(8,8)) axScatter = plt.axes(rect_scatter) # the scatter plot: p1 = axScatter.scatter(x[0], y[0], c='blue', s = 70) p2 = axScatter.scatter(x[1], y[1], c='green', s = 70) p3 = axScatter.scatter(x[2], y[2], c='red', s = 70) p4 = axScatter.scatter(x[3], y[3], c='yellow', s = 70) p5 = axScatter.plot([1,2,3], "r--") plt.legend([p1, p2, p3, p4, p5], [names[0], names[1], names[2], names[3], "Random guess"], loc = 2) # now determine nice limits by hand: binwidth = 0.25 xymax = np.max( [np.max(np.fabs(x)), np.max(np.fabs(y))] ) lim = ( int(xymax/binwidth) + 1) * binwidth axScatter.set_xlim( (-lim, lim) ) axScatter.set_ylim( (-lim, lim) ) xText = axScatter.set_xlabel('FPR / Specificity') yText = axScatter.set_ylabel('TPR / Sensitivity') bins = np.arange(-lim, lim + binwidth, binwidth) plt.show() Everything works, except the p5 which is a line. Now how is this supposed to work? What's good practice here?

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  • CSS Rotation & IE: absolute positioning seems to break IE

    - by user263900
    I'm trying to rotate a variety of text blocks so they are vertically oriented, and position them in very specific locations on a diagram which will be previewed and then printed. CSS rotates the text very nicely in IE, FF, even Opera. But when I try to position a rotated element, IE 7 & 8 (not worried about 6) breaks completely and the element stays in its original location. Any way around this? I really need to-the-pixel control of where these labels are located. HTML <div class="content rotate"> <div id="Div1" class="txtblock">Ardvark Avacado<br />Awkward</div> <div id="Div2" class="txtblock">Brownies<br />Bacteria Brussel Sprouts</div> </div> CSS div.content { position: relative; width: 300px; height: 300px; margin: 30px; border-top: black 4px solid; border-right: blue 4px solid; border-bottom: black 4px dashed; border-left: blue 4px dashed; } .rotate { -webkit-transform: rotate(-90deg); -moz-transform: rotate(-90deg); -o-transform: rotate(-90deg); filter: progid:DXImageTransform.Microsoft.BasicImage(rotation=3); } .txtblock { width: auto; position: absolute; } #Div1 { left:44px; top:70px; border:red 3px solid; } #Div2 { left:13px; top:170px; border:purple 3px solid; }

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  • IE8 developer tools missing some styles

    - by Craig Warren
    Hi, I'm having some problems with some CSS properties in IE8. I've tested my site in IE7, Chrome and Firefox and they work fine but IE8 is having some layout issues. I inspect the developer tool option on ie8 and I've noticed that some of the properties I set in CSS are being ignored by ie8. For example: #header { position: relative; padding: 20px; height: 100px; background:url(header.png); } In this header IE8 ignored the height property: If I inspect the element in developer tools it is missing that property and it's crushed into another line: background:url;HEIGHT: 100PX The same thing happens for floats too: #logon { float: left; text-align:right; width:20%; height: 40px; padding-left: 0px; padding-right:7px; border:0; margin:0; background: url(navgradient.gif); } This ignores the float value: background: url(navgradient.gif); FLOAT:left; What is happening here and how can I fix it?

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  • How to get a TextBlock to wrap text inside a DockPanel area?

    - by Edward Tanguay
    What do I have to do to get the inner TextBlock below to wrap its text without defining an absolute width? I've tried Width=Auto, Stretch, TextWrapping, putting it in a StackPanel, nothing seems to work. XAML: <UserControl x:Class="Test5.MainPage" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:tk="clr-namespace:System.Windows.Controls;assembly=System.Windows.Controls.Toolkit" Width="800" Height="600"> <tk:DockPanel LastChildFill="True"> <StackPanel tk:DockPanel.Dock="Top" Width="Auto" Height="50" Background="#eee"> <TextBlock Text="{Binding TopContent}"/> </StackPanel> <StackPanel tk:DockPanel.Dock="Bottom" Background="#bbb" Width="Auto" Height="50"> <TextBlock Text="bottom area"/> </StackPanel> <StackPanel tk:DockPanel.Dock="Right" Background="#ccc" Width="200" Height="Auto"> <TextBlock Text="info panel"/> </StackPanel> <StackPanel tk:DockPanel.Dock="Left" Background="#ddd" Width="Auto" Height="Auto"> <ScrollViewer HorizontalScrollBarVisibility="Auto" Padding="10" BorderThickness="0" Width="Auto" VerticalScrollBarVisibility="Auto"> <tk:DockPanel HorizontalAlignment="Left" Width="Auto" > <StackPanel tk:DockPanel.Dock="Top" HorizontalAlignment="Left"> <Button Content="Add More" Click="Button_Click"/> </StackPanel> <TextBlock tk:DockPanel.Dock="Top" Text="{Binding MainContent}" Width="Auto" TextWrapping="Wrap" /> </tk:DockPanel> </ScrollViewer> </StackPanel> </tk:DockPanel> </UserControl>

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  • Dynamic controls not creating with RSS reader function

    - by TuxMeister
    Hello, I am working on a test project for an RSS reader. I am using Chilkat's module for .NET 3.5. What I am trying to do is this: For each item in the RSS feed, I want to dynamically create some controls (labels) that contain stuff like the title, the link and the publication date. The problem is that only the first control comes up "rssTitle", but not the rest and it's definitely not creating the rest, nor cycling through the RSS items. Any ideas where I'm wrong in my code? Imports Chilkat Public Class Form1 Dim rss As New Chilkat.Rss Dim success As Boolean Dim rssTitle As New Label Dim rssLink As New Label Dim rssPubDate As New Label Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click success = rss.DownloadRss("http://www.engadget.com/rss.xml") If success <> True Then MessageBox.Show(rss.LastErrorText) Exit Sub End If Dim rssChannel As Chilkat.Rss rssChannel = rss.GetChannel(0) If rssChannel Is Nothing Then MessageBox.Show("No channel found.") Exit Sub End If Dim numItems As Long numItems = rssChannel.NumItems Dim i As Long For i = 0 To numItems - 1 Dim rssItem As Chilkat.Rss rssItem = rssChannel.GetItem(i) Me.Controls.Add(rssTitle) With rssTitle .Name = "rssTitle" & Me.Controls.Count.ToString + 1 .Text = "Title: " & rssItem.GetString("title") .Left = 12 .Top = 12 End With Me.Controls.Add(rssLink) With rssLink .Name = "rssLink" & Me.Controls.Count.ToString + 1 .Text = "Link: " & rssItem.GetString("link") .Left = 12 .Top = 12 End With Me.Controls.Add(rssPubDate) With rssPubDate .Name = "rssPubDate" & Me.Controls.Count.ToString + 1 .Text = "Pub date: " & rssItem.GetString("pubDate") .Left = 12 .Top = 12 End With Next End Sub End Class I'm grateful for any help. Thanks!

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  • Single-player pong game

    - by Jam
    I am just starting out learning pygame and livewires, and I'm trying to make a single-player pong game, where you just hit the ball, and it bounces around until it passes your paddle (located on the left side of the screen and controlled by the mouse), which makes you lose. However, I keep getting the error: "Cannot have more than on Screen object", which I can find no references to online really, and I can't make sense of it. I want to eventually make the game more complicated, but I need to make it work first. Help please! Here's the code so far: from livewires import games games.init(screen_width=640, screen_height=480, fps=50) class Paddle(games.Sprite): image=games.load_image("paddle.bmp") def __init__(self): super(Paddle, self).__init__(image=Paddle.image, y=games.mouse.y, left=0) self.score=games.Text(value=0, size=25, top=5, right=games.screen.width-10) games.screen.add(self.score) def update(self): self.y=games.mouse.y self.check_collide() def check_collide(self): for ball in self.overlapping_sprites: self.score.value+=1 self.score.right=games.screen.width-10 ball.handle_collide() class Ball(games.Sprite): image=games.load_image("ball.bmp") speed=1 def __init__(self, x, y=90): super(Ball, self).__init__(image=Ball.image, x=x, y=y, dx=Ball.speed, dy=Ball.speed) def update(self): if self.left<0: self.end_game() self.destroy() def handle_collide(self): if self.right>games.screen.width: self.dx=-self.dx if self.bottom>games.screen.height or self.top<0: self.dy=-self.dy def ball_destroy(self): self.destroy() def main(): background_image=games.load_image("background.bmp", transparent=False) games.screen.background=background_image the_ball=Ball() games.screen.add(the_ball) the_paddle=Paddle() games.screen.add(the_paddle) games.mouse.is_visible=False games.screen.event_grab=True games.screen.mainloop() main()

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  • jQuery fadeIn/fadeOut loop problem

    - by liebgott
    Hi. I'm trying to do a sequentiall animation with a loop....but i can't accomplish it in a smooth way (some "lag" problems). jQuery var i = 0; var b = 0; var fades = function(){$(".caja").stop(0).each(function(){ $(this).delay(i * 500).fadeIn('slow', function(){ $(this).delay(5000).fadeOut('slow', function(){ $(".cajar").delay(1000).each(function(){ $(this).delay(b * 500).fadeIn('slow', function(){ $(this).delay(5000).fadeOut('slow', fades()); }); b++; }); }); }); i++; })} fades(); CSS .caja{ width: 150px; height: 150px; background-color: black; float: left; margin: 0 10px 0 0; display: none; } .cajar{ width: 150px; height: 150px; background-color: red; float: left; margin: 0 10px 0 0; display: none; } .cajav{ width: 150px; height: 150px; background-color: green; float: left; margin: 0 10px 0 0; display: none; } HTML <div class="caja"></div> <div class="caja"></div> <div class="caja"></div> <div class="cleaner"></div> <div class="cajar"></div> <div class="cajar"></div> <div class="cajar"></div> Thanks!

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  • jQuery: Multiple animations with a delay on a set of divs

    - by Waleed
    Hey there, I have a group of 4 divs and I'm looking to use jQuery to animate them once, then have a delay using delay(), and then run another set of animations on them, putting the divs back to their original configuration. Here's the code that I have: //only selectors called 'option1' are affected by delay, and not 'option1 img' or 'option2' $("#option1").showOption1().delay(3000).hideOption1(); //if i don't attach to #option1, delay doesn't work, but the animations that need to happen simultaneously work $(document).showOption1().delay(3000).hideOption1(); jQuery.fn.showOption1 = function(){ $("#option2, #option3, #leftColumn").fadeOut(1000); $("#option1").css("zIndex", "5"); $("#option1").animate({ left: "370px", }, 1500); $("#option1 img").animate({ width: "500px", }, 1500, function(){ $("p.optionText").text('hello'); }); return this; } jQuery.fn.hideOption1 = function(){ $("#option1 img").animate({ width: "175px", }, 1500); $("#option1").animate({ left: "743px", }, 1500); $("#option2, #option3, #leftColumn").fadeIn(2000); $("#option1").css("zIndex", "1"); return this; } I've tried two ways of running these two functions, as seen on lines 2 and 5. In the case of line 2, showOption1() will run fine, but then only $("#option1").animate({ left: "743px", }, 1500); will work from hideOption1() after the delay. The rest of hideOption1() is fired immediately after showOption1() finishes, ignoring the delay. On the other hand, if I run line 5, all the code in hideOption1() runs simultaneously as desired, but ignores the delay entirely, running immediately after showOption1() finishes. How can I have all the code in hideOption1() run simultaneously after the delay? Thanks much in advance!

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  • How can I get the post text to be beside the avatar and not below it?

    - by William
    So I'm trying to create a forum with avatars, but right now the text is going below the avatars and not beside them. How can I fix this? Here is the CSS: .postbox{ text-align: left; margin: auto; background-color: #dbfef8; border: 1px solid #82FFCD; width: 100%; margin-top: 10px; } .postfooter{ width: 100%; border-top: 1px solid #82FFCD; } .postheader{ width: 100%; border-bottom: 1px solid #82FFCD; } .posttext{ width: 70%; text-align: left; border: 1px solid #82FFCD; } .postavi{ width: 20%; text-align: left; border: 1px solid #82FFCD; } and here is the html: <div class="postbox"><div class="postheader"> <b><span>CyanPrime!!~::##Admin##::~</span></b> </div> <div class="postavi"><img src="http://prime.programming-designs.com/test_forum/images/avatars/hacker.png" alt="hacker"/></div><div class="posttext">Let's test the Hacker Avatar.</div> <div class="postfooter"> [<a href="http://prime.programming-designs.com/test_forum/viewthread.php?thread=25">Reply</a>] 0 posts omitted. </div> </div>

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  • Perl Imager::Screenshot not doing screenshot with default parameters

    - by Grigor
    I have the following code: use Imager::Screenshot 'screenshot'; my $img = screenshot(hwnd => 'active', left => 450, right => 200, top => 50, bottom => 50); $img->write(file => 'screenshot.png', type => 'png' ) || print "Failed: ", $img->{ERRSTR} , "\n"; it returns: "Can't call method "write" on undefined value at line 3" but when I do: use Imager::Screenshot 'screenshot'; my $img = screenshot(hwnd => 'active', left => 100, right => 300, top => 100, bottom => 300); $img->write(file => 'screenshot.png', type => 'png' ) || print "Failed: ", $img->{ERRSTR} , "\n"; it does take a screenshot. Why would the left, right, top and bottom values matter here?

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  • 2 listbox to exchange value with DBML

    - by Garcia Julien
    Hi, i'have two Listbox. the think is i do the transfert like : click on field in the left listbox, hit "move right" button and it wll display in the right list box.' The other think it's the first Listbox is bind on Dataset and the second on Entity (Linq-to sql). So when i click on the move next i do that : Dim newSite As New List(Of vw_SiteList) For Each row As SitesDataset.FDDSTRow In SiteAdsListBox.SelectedItems newSite.Add(New vw_SiteList With { _ .SITECODE = row.DEST_COD, _ .SiteDisplay = row.SiteDisplay, _ .CREATEDBY = Environment.GetEnvironmentVariable("USERNAM"), _ .DATECREATED = Now _ }) Next JCDataContext.vw_SiteLists.InsertAllOnSubmit(NewSite) I would like to see now the new field in the right listbox but it isn't there because the field itr's not yet added in the database. How can i do that? Thanks Ju

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  • Windows mobile phone for business application - or design way out of scrolling problem

    - by Peter
    We have a business application written for Windows mobile. It has people doing inventories. The fastest way to do this is to keep one hand on the product being counted and the other on the phone. The five-way lets you hit enter to accept the current correct inventory (the norm) or to move one left to remove one. This is very fast. If I am two low, I have a quick glance at the phone- move my eyes back to count the next row - and with my right hand hit the five way "left left enter". Very fast. Our problem is that with I-Mate out of business, we cannot find a modern cell phone that has a decent size screen and a five way. Everyone is going to candy bar and flicks. That works great if it is two hands and you are looking at the phone, but not efficient for us. Other than the $1,500 ruggadized units, is there anybody who makes a business style Windows Mobile with a five way? If not, any ideas on how to design the phone to make it easier without a five way to quickly enter data like this?

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  • Sub-classing TreeView in WinForms for mouse over tool tips

    - by Matt
    Ok, this is a weird one. The expected behaviour for a TreeView control is that, if ShowNodeToolTips is set to false, then, when a label for a tree node exceeds the width of the control (or, more accurately, it's right hand edge is past the right hand edge of the client area), then a tooltip is shown above the node showing the full item's text. I'd like to disable that, because the above semantic doesn't always work, depending on what the treeview is contained within. So I have rolled my own, and got the tooltips to work (and line up better than the default one!) - but I would like to be able to disable the 'default' behaviour for situations where it would work natively. So, can anyone point me in the right direction as to which message to post to the TreeView in order to disable that behaviour? I have looked at the windows control reference, but couldn't find anything that looked like it might be the one.

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  • Java bitshift strangeness

    - by Martin
    Java has 2 bitshift operators for right shifts: >> shifts right, and is dependant on the sign bit for the sign of the result >>> shifts right and shifts a zero into leftmost bits http://java.sun.com/docs/books/tutorial/java/nutsandbolts/op3.html This seems fairly simple, so can anyone explain to me why this code, when given a value of -128 for bar, produces a value of -2 for foo: byte foo = (byte)((bar & ((byte)-64)) >>> 6); What this is meant to do is take an 8bit byte, mask of the leftmost 2 bits, and shift them into the rightmost 2 bits. Ie: initial = 0b10000000 (-128) -64 = 0b11000000 initial & -64 = 0b10000000 0b10000000 >>> 6 = 0b00000010 The result actually is -2, which is 0b11111110 Ie. 1s rather than zeros are shifted into left positions

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  • noweb dpp filter and latex not printing curly braces

    - by Dervin Thunk
    Hello. Well, this smells like a tumbleweed, but I will ask it anyway. Suppose you have a noweb file with some c# code. You also have the c++ pretty-print filter dpp. If you run the command noweave -filter ./dpp -x test.nw > csharp.tex on the file below, it will print everything except for the curly braces. Instead of them, I get an em-dash and a closing quotations marks (i.e. ?) in the dvi. The tex source looks fine... Any ideas? @ C\# test file <<test.c>>= while( (a[right] >= pivot) && (left < right) ) { right--; }

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  • iPhone UIView frame animation inconsistent why?

    - by Rick
    I have an app that uses an image loaded in from an UIImagePickerController instance. Once the picker is dismissed so as to reduce the jarring transition from the picker layout to the layout of the next function I initially have the UIImageView for the image fill the whole screen and then when the picker is dismissed the image 'squeezes' up to the top left of the screen. from the initWithFrame... targetPicView = [[UIImageView alloc] initWithFrame:CGRectMake(0.0, 0.0, 320.0, 480.0)]; [targetPicView setContentMode:UIViewContentModeScaleToFill]; this in a function called after dismissing the picker... [UIView beginAnimations:@"squeeze" context:context]; [UIView setAnimationCurve:UIViewAnimationCurveEaseInOut]; [UIView setAnimationDuration:0.75]; [targetPicView setFrame:CGRectMake(20.0, 20.0, 130.0, 150.0)]; [UIView commitAnimations]; The weird thing is that this works great when the image has been chosen from the library, the view shrinks down with the top left corner in place just as I planned but... If the image comes from the camera then the view shrinks with the top right corner in place instead and appears to come in from the left side of the screen. Can anyone shed any light on this?

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  • Top Container Background Problem

    - by Norbert
    Here's a screenshot: http://dl.getdropbox.com/u/118004/Screen%20shot%202010-04-13%20at%202.50.49%20PM.png The red bar on the left is the background I set for the #personal div and I would like it to align to the top of the container, vertically. The problem is that I have a background for the #container-top div on top of the #container div with absolute positioning. Is there any way to move the #personal div up so there would be no space left? HTML <div id="container"> <div id="container-top"></div> <div id="personal"> <h1>Jonathan Doe</h1> <p>Lorem ipsum dolor sit amet, consectetuer adipiscing elit, sed diam nonummy nibh euismod tincidunt ut laoreet dolore magna aliqua erat volutpat.</p> </div> <!-- end #personal --> </div> <!-- end #container --> CSS #container { background: url(images/bg-mid.png) repeat-y top center; width: 835px; margin: 40px auto; position: relative; } #container-top { background: url(images/bg-top.png) no-repeat top center; position: absolute; height: 12px; width: 835px; top: -12px; } #container-bottom { background: url(images/bg-bottom.png) no-repeat top center; position: absolute; height: 27px; width: 835px; bottom: -27px; } #personal { background: url(images/personal-info.png) no-repeat 0px left; }

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  • How do I use a different image for each JQuery UI Slider handle

    - by Tom
    I'm using a JQuery UI slider which has two handles (a.k.a range slider). I know how to style the first handle: .ui-slider-horizontal .ui-slider-handle {background: white url(http://stackoverflow.com/content/img/so/vote-arrow-down.png) no-repeat scroll 50% 50%;} But how do I style the second handle differently? Using Firebug I can see Jquery does not uniquely identify each handle: <div id="hourlyRateSlider" class="ui-slider ui-slider-horizontal ui-widget ui-widget-content ui-corner-all"> <div class="ui-slider-range ui-widget-header" style="left: 26%; width: 46%;"/> <a class="ui-slider-handle ui-state-default ui-corner-all" href="#" style="left: 26%;"/> <a class="ui-slider-handle ui-state-default ui-corner-all" href="#" style="left: 72%;"/> </div> So I imagine I have to use either a CSS child selector which could be cross-browser problematic. Or I could use some JQuery trickery to add a CSS class to the second handle? Anyone done this in a neat way before?

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  • Perspective Rotation about Y axis

    - by N.A.Reddy
    Hello Experts, I have a 2D image and I want to create a anaglyph image for this single 2D image. To do this I need to create Left and Right views. I will considar my 2D image as Left view and I want to create Right View now. I came to know that the perspective rotation (about Y axis) and perspective skews will give the right image. I know that the perspective projection is related to 3D. Basically I am new to 3D programming. Can you plz explain how to do perspective rotation abuout Y-axis. And how can I apply this to my 2D image.I am using C++. Thank you verymuch N.A.Reddy.

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  • Why can't execute GRUB command on Debian Squeeze 2.6 with GRUB already installed?

    - by Mikalaj
    I installed Debian Squeeze 2.6 (on a recently bought server) with a software RAID1. During installation I installed GRUB loader (1.9 version). System boots OK with GRAB loader BUT right after authorization it cannot execute GRUB command (I want to copy the GRUB from the SDA to SDB). System warning right after GRUB command invocation looks as: root@servername:~# grub -bash: grub: command not found How it could be? (GRUB already installed and no any other OS was installed at all)

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  • Beginner question about CSS and layout and height

    - by vtortola
    Hi, I'm trying to create a very simple page that contains a container, a header, a left column and a footer: [containter] [header /] [content /] [leftBar /] [footer /] [/containter] (Sorry, I cannot paste the code properly, only appears the tag "body" and the rest disapears :S ... ) As you can see, very simple stuff. I want to use the 100% of the height, as I can do with the width, but I simply don`t get it work :S At his moment I'm using min-height, but how could I use the height:100% ? What I like is that the footer is always visible, and you scroll the content. This is what I have till the moment: body { font-family: Verdana; font-size: 0.8em; background-color:#f1f1f1; } container { border:solid 2px Black; position:absolute; left:10%; width:80%; margin:auto; } header { height:20px; background: #DDDDDD; } leftBar { width: 20%; background: #669966; min-height:600px; postion:absolute; top:20px; bottom:20px; } content { float:right; background-color: #cdcde6; position:absolute; left:20%; right:0px; bottom:20px; top:20px; padding:5px; } footer { position:absolute; height:20px; } I'm reading a book about CSS, but I still don't get the part about the height :S Thanks in advance.

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