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  • PHP & MySQL form question.

    - by peakUC
    How do I allow all users to have there username field empty without having them to enter a username when they submit the form using PHP and MySQL? Here is part my PHP and MySQL code. $username = mysqli_real_escape_string($mysqli, $purifier->purify(htmlentities(strip_tags($_POST['username'])))); if(isset($_POST['username'])) { // Make sure the username address is available: $u = "SELECT * FROM users WHERE username = '$username' AND user_id <> '$user_id'"; $r = mysqli_query ($mysqli, $u) or trigger_error("Query: $q\n<br />MySQL Error: " . mysqli_error($mysqli)); if (mysqli_num_rows($r) == TRUE) { // Unavailable. echo '<p class="error">Your username is unavailable!</p>'; $username = NULL; } else if(mysqli_num_rows($r) == 0) { // Available. $username = mysqli_real_escape_string($mysqli, $purifier->purify(htmlentities(strip_tags($_POST['username'])))); } }

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  • status update error (null field)

    - by ejah85
    hai guys... i .ve the problem that i cannot be recovered yet... i have one form where admin need to approve or reject the booking request... i've set the b_status field in table usage IN PROCESS default value... i want to update the b_status value BOOKING APPROVED when user click APPROVE button.. otherwise, the b_status will update the value as BOOKING REJECTED when user click on the REJECT button here's is the form code: <?php $db = mysql_connect('localhost','root') or die ("unable to connect"); mysql_select_db('fyp',$db) or die ("able to select"); $sql="SELECT * FROM vehicle WHERE v_status='READY'"; $result = mysql_query($sql) or die ("Query failed!"); ?> <tr><td>&nbsp;</td></tr> <tr> <tr> <td width="200"><font face="Arial" size="2" font color="#000000">Registration Number </font></td> <td><select name="regno"> <option value="" selected>--Registration No--</option> <?php while($row = mysql_fetch_array($result)){?> <option value="<?php echo $row['regno']; ?>"><?php echo $row['regno']; ?></option> <?php } ?> </select></td> <td><font face="Arial" size="2" font color="#000000">Reason</font></td> <td><textarea name="reason" rows="3" cols="50 "value = ""></textarea></td> </tr> <?php $db = mysql_connect('localhost','root') or die ("unable to connect"); mysql_select_db('fyp',$db) or die ("able to select"); $sql="SELECT * FROM driver WHERE d_status='READY'"; $result = mysql_query($sql) or die ("Query failed!"); ?> <tr> <td><font face="Arial" size="2" font color="#000000">Driver</font></td> <td><select id = "d_name" name="d_name"> <option value="" selected>--Driver Name--</option> <?php while($row = mysql_fetch_array($result)){?> <option value="<?php echo $row['d_name']; ?>"><?php echo $row['d_name']; ?></option> <?php } ?> </select></td> </tr> <tr> <?php mysql_close($db); ?> </table> <p></p> <center><input name="APPROVED" type="submit" id="APPROVED" value="APPROVED"> <input name="REJECT" type="submit" id="REJECT" value="REJECT"> </center> </div> </center> and this is the process page code: <?php $db = mysql_connect('localhost','root') or die ("unable to connect"); mysql_select_db('fyp',$db) or die ("able to select"); $bookingno=mysql_real_escape_string($_POST['bookingno']); $username=mysql_real_escape_string($_POST['username']); $name=mysql_real_escape_string($_POST['name']); $department=mysql_real_escape_string($_POST['department']); $g_date=mysql_real_escape_string($_POST['g_date']); $g_time=mysql_real_escape_string($_POST['g_time']); $r_date=mysql_real_escape_string($_POST['r_date']); $r_time=mysql_real_escape_string($_POST['r_time']); $destination=mysql_real_escape_string($_POST['destination']); $pass_num=mysql_real_escape_string($_POST['pass_num']); $trip_purpose=mysql_real_escape_string($_POST['trip_purpose']); $regno=mysql_real_escape_string($_POST['regno']); $d_name=mysql_real_escape_string($_POST['d_name']); $reason=mysql_real_escape_string($_POST['reason']); $b_status=mysql_real_escape_string($_POST['b_status']); $sql = "INSERT INTO `usage` VALUES('$bookingno','$username','$name','$department','$g_date','$g_time','$r_date','$r_time','$destination', '$pass_num','$trip_purpose','$regno','$d_name','$reason','$b_status')"; $query = "INSERT INTO `usage` VALUES b_status ='BOOKING APPROVED'"; $result = @mysql_query($query); $query1 = "UPDATE driver SET d_status ='OUT' WHERE '$d_name'=d_name"; $result1 = @mysql_query($query1); if(isset($_POST['APPROVED'])) { $query2 = "UPDATE `usage` SET b_status ='BOOKING APPROVED' WHERE '$b_status'='IN PROCESS'"; $result2 = @mysql_query($query2); } if (isset($_POST['REJECT'])) { $query3 = "UPDATE `usage` SET b_status ='BOOKING REJECTED' WHERE '$b_status'='IN PROCESS'"; $result3 = @mysql_query($query3); } //$result = mysql_query($sql) or die ("error!"); $result = mysql_query($sql) or trigger_error (mysql_error().' in '.$sql); i.ve the problem on the b_status field.. plz guys... help me ya :-)

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  • php open_socket

    - by sea_1987
    Hello, I am trying to open a socket to use with secure tradings xpay api, however when I check to see if the socket is open I get error returned, Can't assign requested address I need to open up 127.0.0.1:5000 is there something wring with my code that means I cannot do this? if (isset($xpay_port) and ($socket=socket_create(AF_INET, SOCK_STREAM, SOL_TCP)) and (socket_connect($socket, $address, $port))) { $text="Connection successful on IP $address, port $port"; socket_close($socket); } else $text="Unable to connect<pre>".socket_strerror(socket_last_error())."</pre>"; echo "<html><head></head><body>". $text. "</body></html>";

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  • [PHP] using the magic __set() method with 2D arrays

    - by Spoonface
    If I have the following registry class: Class registry { private $_vars; public function __construct() { $this->_vars = array(); } public function __set($key, $val) { $this->_vars[$key] = $val; } public function __get($key) { if (isset($this->_vars[$key])) return $this->_vars[$key]; } public function printAll() { print "<pre>".print_r($this->_vars,true)."</pre>"; } } $reg = new registry(); $reg->arr = array(1,2,3); $reg->arr = array_merge($reg->arr,array(4)); $reg->printAll(); Would there be an easier way to push a new item onto the 'arr' array? This code: 'array[] = item' doesn't work with the magic set method, and I couldn't find any useful info with google. Thanks for your time!

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  • jQuery getting these functions to work together

    - by brett
    I'm new to jQuery and have tried looking around for an answer on how to do this. I have 2 functions and I would like both to work together. The one function is submitHandler and its used to hide a form and at the same time add a class to a hidden element to unhide it - ie a thank you for submitting h1. The other function is to grab the input data and display it onsubmit in the form. So the problem is that I can get that one to work but then the other doesnt. Ie on form submit I can see the data input but not the h1 Thank you message. Here are the functions: SubmitHandler: submitHandler: function() { $("#content").empty(); $("#content").append( "<p>If you want to be kept in the loop...</p>" + "<p>Or you can contact...</p>" ); $('h1.success_').removeClass('success_').addClass('success_form'); $('#contactform').hide(); }, onsubmit="return inputdata()" function inputdata(){ var usr = document.getElementById('contactname').value; var eml = document.getElementById('email').value; var msg = document.getElementById('message').value; document.getElementById('out').innerHTML = usr + " " + eml + msg; document.getElementById('out').style.display = "block"; return true; }, The form uses PHP and jQuery - I dont know about AJAX but after some reading even less sure. Please help me out I dont know what I'm doing and at the moment I am learning but its a long road for me still. Thank you The form: <form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>" id="contactform" onsubmit="return inputdata()"> <div class="_required"><p class="label_left">Name*</p><input type="text" size="50" name="contactname" id="contactname" value="" class="required" /></div><br/><br/> <div class="_required"><p class="label_left">E-mail address*</p><input type="text" size="50" name="email" id="email" value="" class="required email" /></div><br/><br/> <p class="label_left">Message</p><textarea rows="5" cols="50" name="message" id="message" class="required"></textarea><br/> <input type="submit" value="submit" name="submit" id="submit" /> </form> The PHP bit: <?php $subject = "Website Contact Form Enquiry"; //If the form is submitted if(isset($_POST['submit'])) { //Check to make sure that the name field is not empty if(trim($_POST['contactname']) == '') { $hasError = true; } else { $name = trim($_POST['contactname']); } //Check to make sure sure that a valid email address is submitted if(trim($_POST['email']) == '') { $hasError = true; } else if (!eregi("^[A-Z0-9._%-]+@[A-Z0-9._%-]+\.[A-Z]{2,4}$", trim($_POST['email']))) { $hasError = true; } else { $email = trim($_POST['email']); } //Check to make sure comments were entered if(trim($_POST['message']) == '') { $hasError = true; } else { if(function_exists('stripslashes')) { $comments = stripslashes(trim($_POST['message'])); } else { $comments = trim($_POST['message']); } } //If there is no error, send the email if(!isset($hasError)) { $emailTo = '[email protected]'; //Put your own email address here $body = "Name: $name \n\nEmail: $email \n\nComments:\n $comments"; $headers = 'From: My Site <'.$emailTo.'>' . "\r\n" . 'Reply-To: ' . $email; mail($emailTo, $subject, $body, $headers); $emailSent = true; } } ? The Jquery Validate bit: $(document).ready(function(){ $('#contactform').validate({ showErrors: function(errorMap, errorList) { //restore the normal look $('#contactform div.xrequired').removeClass('xrequired').addClass('_required'); //stop if everything is ok if (errorList.length == 0) return; //Iterate over the errors for(var i = 0;i < errorList.length; i++) $(errorList[i].element).parent().removeClass('_required').addClass('xrequired'); }, Here is the full jQuery bit: $(document).ready(function(){ $('#contactform').validate({ showErrors: function(errorMap, errorList) { //restore the normal look $('#contactform div.xrequired').removeClass('xrequired').addClass('_required'); //stop if everything is ok if (errorList.length == 0) return; //Iterate over the errors for(var i = 0;i < errorList.length; i++) $(errorList[i].element).parent().removeClass('_required').addClass('xrequired'); }, submitHandler: function() { $('h1.success_').removeClass('success_').addClass('success_form'); $("#content").empty(); $("#content").append('#sadhu'); $('#contactform').hide(); }, }); }); Latest edit - Looks like this: $(document).ready(function(){ $('#contactform').validate({ showErrors: function(errorMap, errorList) { //restore the normal look $('#contactform div.xrequired').removeClass('xrequired').addClass('_required'); //stop if everything is ok if (errorList.length == 0) return; //Iterate over the errors for(var i = 0;i < errorList.length; i++) $(errorList[i].element).parent().removeClass('_required').addClass('xrequired'); }, function submitHandler() { $('h1.success_').removeClass('success_').addClass('success_form'); $("#content").empty(); $("#content").append('#sadhu'); $('#contactform').hide(); }, function inputdata() { var usr = document.getElementById('contactname').value; var eml = document.getElementById('email').value; var msg = document.getElementById('message').value; document.getElementById('out').innerHTML = usr + " " + eml + msg; document.getElementById('out').style.display = "block"; }, $(document).ready(function(){ $('#contactForm').submit(function() { inputdata(); submitHandler(); }); }); });

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  • Making a Link Appear if a Condition is Met

    - by John
    Hello, The PHP code below echoes a link if the "loginid" of the logged-in user is on a list determined by getEditorList();. It works fairly well, but I think it might work better if I were to do it with Javascript instead. How could I accomplish the same thing with Javascript? Thanks in advance, John $editors = getEditorsList(); foreach($editors as $editor) { $editorids[] = $editor['loginid']; } if(in_array($_SESSION['loginid'], $editorids)) { echo "<div class='footervote'><a href='http://www...com/.../footervote.php'>Vote</a></div>"; } Login function: <?php if (!isLoggedIn()) { if (isset($_POST['cmdlogin'])) { if (checkLogin($_POST['username'], $_POST['password'])) { show_userbox(); } else { echo "Incorrect Login information !"; show_loginform(); } } else { show_loginform(); } } else { show_userbox(); } ?>

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  • form Validation white page not showing errors

    - by Jess McKenzie
    In the example below I am wanting to do all of the 'safety' checks on the $_POST variables but it seems when I click submit I get a white page why? I am wanting it to show the errors etc Form Process: /* check if the form is submitted */ if (isset($_POST['submitButton'])) { $fullName = $_POST['fullname']; if($_SERVER['REQUEST_METHOD'] == 'POST' && !empty($fullName)) { if (!ctype_alpha(str_replace(array("'", "-"), "",$fullName))) { $errorfullName .= '<span class="errorfullName">*First name should be alpha characters only.</span>'; } if (strlen($fullName) < 3 OR strlen($fullName) > 40) { $errorfullName .= '<span class="errorfullName">*First name should be within 3-40 characters long.</span>'; } } }

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  • Sending mail from a contact form. Simple but challenging!

    - by ekalaivan
    I've set up a contact form in the Greet Us page in http://swedsb.com When I submit the form, it says mail sent successfully. But I'm not getting the mail, checked the spam folder. I've set a similar form at http://ibsolutions.in. It is working perfectly. Been breaking my head for the past 4 hours. Here's my contact.php <?phpif(isset($_POST['submit'])) { $to = "[email protected]"; $subject = $_POST['posRegard']; $name = $_POST['posName']; $email = $_POST['posEmail']; $message = $_POST['posText']; $body = "$name has sent you a greeting. \n E-Mail: $email\nMessage:\n $message"; mail($to, $subject, $body); header( 'Location: http://swedsb.com/' ); } else {echo "blarg!";}?

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  • Incrmenting a Cookies with PHP (Beginner Question)

    - by BandonRandon
    Hello, I have used sessions before but never cookies. I would like to use cookies for two reasons: 1) it's something new to learn 2) I would like to have the cookie expire in an hour or so (i know in the code example it expires in 40 sec) I am trying to write a basic if statement that if($counter=="1") { //do this second } elseif ($counter >="2") { //do this every time after the first and second } else {// this is the first action as counter is zero } Here is the code I'm using to set the cookie: // if cookie doesnt exsist, set the default if(!isset($_COOKIE["counter_cookie"])) { $counter = setcookie("counter_cookie", 0 ,time()+40); } // increment it $counter++; // save it setcookie("counter_cookie", $counter,time()+40); $counter = $_COOKIE["counter_cookie"]; The problem is that the counter will be set from 0 to 1 but won't be set from 1 to 2 and so on. Any help would be great I know this is a really simple stupid question :| Thanks!

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  • having trouble with a mysql query

    - by chuck akers
    this keeps saying Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in directory here the error is near the login_query variable, can someone help me fix it. <?php if (isset($_POST['login_username'], $_POST['login_password'])) { $login_username = trim(mysql_real_escape_string(htmlentities($_POST['login_username']))); $login_password = md5(trim(mysql_real_escape_string(htmlentities($_POST['login_password'])))); if (!empty($login_username) && !empty($login_password)) { $login_query = mysql_query("SELECT user_id FROM username WHERE username='".$login_username."' AND password='".$login_password."'"); if (mysql_num_rows($login_query)==1) { $user_id = mysql_result($login_query, 0, 'user_id'); $_SESSION['user_id'] = $user_id; header('Location: index.php'); die(); } }} ?

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  • Codeigniter view file looping query

    - by user2505513
    Right, I'm unsure about how to code my view file to generate following query results WITHOUT compromising the principles of mvc. Query in model: SELECT * FROM events GROUP BY country, area ORDER BY country, area View: <?php if (isset($query)):?> <?php foreach ($query as $row):?> <h2><?=$row->country?></h2> <h3><?=$row->area?></h3> <?php endforeach;?> <?php endif;?> I want the results to display: England North South West - utilising the GROUP BY parameter As opposed to: England North England South England West Has anybody any advice as to how to achieve this?

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  • How to test if a user has uploaded a file ?

    - by Tristan
    Hello, on a page, i have : if (!empty($_FILES['logo']['name'])) { $dossier = 'upload/'; $fichier = basename($_FILES['logo']['name']); $taille_maxi = 100000; $taille = filesize($_FILES['logo']['tmp_name']); $extensions = array('.png', '.jpg', '.jpeg'); $extension = strrchr($_FILES['logo']['name'], '.'); //Début des vérifications de sécurité... if(!in_array($extension, $extensions)) { $erreur = 'ERROR you must upload the right type'; } if($taille>$taille_maxi) { $erreur = 'too heavy'; } if(!empty($erreur)) { ....................... } The problem is, if the users wants to edit information WITHOUT uploading a LOGO, it raises an error : 'error you must upload the right type' So, if a user didn't put anything in the inputbox in order to upload it, i don't want to enter in these conditions test. i tested : if (!empty($_FILES['logo']['name']) and if (isset($_FILES['logo']['name']) but both doesn't seems to work. Any ideas? thanks.

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  • how to update mysql with inputs and checkboxes

    - by Ronnie Chester Lynwood
    hi. with this code: <? if (isset($_POST['onay'])) { foreach ($_POST['secilen'] as $zuha) { $olay = mysql_query("update mp3 SET aktif = '1' WHERE id = '$zuha'"); } if ($olay) { echo "islem tamam"; exit; } } ?> and with this form: (select * from mp3 aktif = '0') <form name="form" method="post"> <input readonly type="text" name="id" value="<?=$haciosman['id']?>" /> <input type="text" name="baslik" value="<?=$haciosman['baslik']?> <input type="checkbox" name="secilen[]" value="<?=$haciosman['id']?>"> <input type="submit" name="onay" value="Onayla" /> I can set "aktif to 1" for each row that i checked. but i want to update "baslik" too! how can i update each "baslik" with that php code?

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  • click multiple times a submit button

    - by Olga Anastasiadou
    Hi all, I encountered a problem that I can't solve. My point is to "click" my sybmit button and every time increase a counter, while this counter reach 10. For the first time it works, but this is it! My test code is below : <form name="testForm" method="post"> <?php $cnt=0; ?> <input type="submit" name="next" id="next" value="NEXT"/> <?php if(isset($_POST['next'])){ if($cnt< 10){ echo $cnt.' --> '; $cnt++; echo $cnt; } } ?> </form> Only 0 -- 1 is printed, every time... please help!! Thanks

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  • mysql_fetch_assoc data to COOKIE in user browser

    - by Gowtham Raj
    I had data in mysql, where it does not need any security. I had a sql query string to get the data out every time using mysql_fetch_assoc. So, I planed to store data in users browser.To reduce no of quires to sql. if (!isset($_COOKIE['countries'])){ $query = "SELECT iso,name FROM sel_country"; $countries = mysql_query($query); setcookie('countries', serialize($countries), time()+3600); }else{ $countries = $unserialize($_COOKIE['countries']); } while ($row = mysql_fetch_assoc($countries)) {echo $row['name']} But, When cookie is set it is showing following error Fatal error: Function name must be a string in /home/worlds/public_html/index/ctrl.php on line 15 My cookie in browser displaying content as i%3A0%3B Please help me out, how should i go?

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  • form not showing for empty records

    - by Chris Hodges
    I have a relatively simple PHP page called editcustomers with 3 columns. The problem I'm having is that the form will show when there is a record in the database and the fields will be populated with that info. When no such records exists, the form is not even shown, eliminating the possibility to insert a record. My page layout is as follows: Column 1 shows a form containing customer information, allowing it to be edited. Column 2 allows ordering of products and showing how many products were ordered Column 3 shows the total paid so far, and the total owing. The code for the page I have at present: <html> <?php $id = $_GET['id']; require_once('connect.php'); $sth = $dbh->query("SELECT * FROM users where id = '$id';"); $sth->setFetchMode(PDO::FETCH_ASSOC); $eth = $dbh->query("SELECT * FROM purchases where id = '$id';"); $eth->setFetchMode(PDO::FETCH_ASSOC); ?> <div id="main"> <div id="left"> <form name="custInfo" action ="process.php" method ="post" > <input type = "hidden" name ="formType" value="custInfo"/> <?php while($row = $sth->fetch()){ ?> <p><input type = "hidden" name ="id" value="<?php echo $row["id"] ?>"/> <p><input type = "text" name ="firstName" size ="30" value=" <?php echo $row["firstName"]?>"/> <p><input type = "text" name ="lastName" size ="30" value="<?php echo $row["lastName"]?>"/> <p><input type = "text" name ="country" size ="30" value="<?php echo $row["country"]?>"/> <p></p> <input type="submit" value="Update" /> <?php }?> </div> <div id="mid"> <form name="custCosts" action ="process.php" method ="post" > <input type = "hidden" name ="formType" value="custCosts"/> <?php while($row = $eth->fetch()){ ?> <p><input type = "hidden" name ="id" value="<?php echo $row["id"] ?>"/> <p><input type = "text" name ="amountOwed" size ="30" value=" <?php echo $row["amountOwed"]?>"/> <p><input type = "text" name ="numAaa" size ="30" value="<?php echo $row["numAaa"]?>"/> <p><input type = "text" name ="numBbb" size ="30" value="<?php echo $row["numBbb"]?>"/> <p></p> <input type="submit" value="Update" /> <?php }?> </div> <div id="right"> <b>Total Balance</b> <p> Money owed: </p> <p> aaa total: </p> <p> bbb total: </p> <p> Total: </p> <input type = "text" name ="pay" size ="20" /></p> <input type="submit" value="Make Payment" /> </div> <?php $dbh =null; ?> </body> </html> And the code for all the database trickery: <?php require_once 'connect.php'; $formType = $_POST['formType']; $id = $_POST['id']; $firstName = $_POST['firstName']; $lastName = $_POST['lastName']; $country = $_POST['country']; $amountOwed = $_POST['amountOwed ']; $numAaa = $_POST['numAaa']; $numBbb = $_POST['numBbb']; if(empty($_POST['id'])) { $sth = $dbh->prepare("INSERT INTO customers (firstName, lastName, country) VALUES ('$firstName', '$lastName', '$country')"); $sth->execute(); } elseif(!empty($_POST['id']) && !isset($_POST['stayCost']) && $_POST['formType'] == 'guestInfo'){ $sth = $dbh->prepare("UPDATE customers SET firstName = '$firstName', lastName = '$lastName', country = '$country' WHERE id = '$id'"); $sth->execute(); }elseif(!empty($_POST['id']) && isset($_POST['stayCost']) && $_POST['formType'] == 'guestInfo'){ $sth = $dbh->prepare("INSERT INTO purchases (id, amountOwed, numAaa, numBbb) VALUES ('$id', '$amountOwed', '$numAaa', '$numBbb'"); $sth->execute(); }elseif(!empty($_POST['id']) && $_POST['formType'] == 'guestCosts'){ $sth = $dbh->prepare("UPDATE purchases SET amountOwed= '$amountOwed', numAaa = '$numAaa', numBbb= '$numBbb' WHERE id = '$id'"); $sth->execute(); } $dbh =null; ?> Why does the form not even display if there is no record? An error or something I might understand....but the form is still in the HTML and should still be being output, from what I can see. Why is this not the case?

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  • php session variable

    - by Idealflip
    Hi Everyone, my session variable seems to keep dropping its array values. What could I be doing wrong? Is it my object? if(isset($_SESSION['locations'])){ $_SESSION['locations']->listItems($_POST['companyLocation']); echo "session exists"; }else{ $_SESSION['locations'] = new Location(); $_SESSION['locations']->listItems($_POST['companyLocation']); echo "session does not exist"; } class Location { function listItems($location){ $array; $array[] = $location; print_r($array); }

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  • Cookie Value not available, why?

    - by Camran
    I have tested this on my development computer, but now I have uploaded everything to the production server and I cant read out the value of the cookie. I think the problem lies in the Serialization and Unserialization. if (isset($_COOKIE['watched_ads'])){ $expir = time()+1728000; //20 days $ad_arr = unserialize($_COOKIE['watched_ads']); // HERE IS THE PROBLEM $arr_elem = count($ad_arr); if (in_array($ad_id, $ad_arr) == FALSE){ if ($arr_elem>10){ array_shift($ad_arr); } $ad_arr[]=$ad_id; setcookie('watched_ads', serialize($ad_arr), $expir, '/'); } } When I echo this: count($ad_arr) I receive the expected nr, 1 in this case, so there is a value there. But when I echo the value: echo $ad_arr[0]; I get nothing. Completely blank. No text at all. Anybody have a clue? if you need more info about something let me know...

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  • Cookie is setting twice (dublicated)

    - by Erik Larsson
    I'm new to cookies, and im trying to set a cookie where to store the referer (the org ref). But when i try this function: function do_it_cookie() { // Check if cookie exists if (isset($_COOKIE['ref'])) { // It dose exist, do nothing or anything... } else { setcookie ('ref', $_SERVER['HTTP_REFERER'], time() + 60, '/'); header ("Location: http://www.nyttforetag.com/mind-your-own-business/"); } } I want to store the cookie on the user computer for 30 days, if the return i want to know the initial refereeing url. But when i use this and lets say i go to another page in my site and then go back to the homepage its sets a new cookie with the exact same name and with the ref of the previous page. Is there away to avoid this?

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  • Codeigniter Template library, add_js() method

    - by Karl
    using This Template Library when i try and use the add_js() function it errors out. I add the regions $_scripts to the template header file but when i load the page it says undefined variable _scripts. any thoughts? changed <?= $_scripts ?> to <?= (isset($_scripts)) ? $_scripts : “”; ?> and obviously i lose the error but the js file still isnt loading. I did an echo at each step though the add_js() method and the output is correct. I also did an output of $this-js and they both had the corret output. So it gets through the get_js method fine and sets the class variable fine but i dont get anything added to the actual page.

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  • How to refresh site if $_SESSION variable has changed

    - by 4ndro1d
    I'm writing in my $_SESSION variable from a database, when i clicked a link. public function getProjectById($id){ $query="SELECT * FROM projects WHERE id=\"$id\""; $result=mysql_query($query); $num=mysql_numrows($result); while ($row = mysql_fetch_object($result)) { $_SESSION['projectid'] = $row->id; $_SESSION['projecttitle'] = $row->title; $_SESSION['projectinfo'] = $row->info; $_SESSION['projecttext'] = $row->text; $_SESSION['projectcategory'] = $row->category; } } Now my variable is overwritten and I want to show these variables in my index.php like this: <div id="textContent"> <?php if(isset($_SESSION['projecttext']) && !empty($_SESSION['projecttext'])) { echo $_SESSION['projecttext']; }else { echo 'No text'; } ?></div> But of course, my page will not refresh automatically. How can I do that?

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  • Having trouble comparing a range of dates entered in a form with records in a mySQL database

    - by Andrew Fox
    I have a table called schedule and a column called Date where the column type is date. In that column I have a range of dates, which is currently from 2012-11-01 to 2012-11-30. I have a small form where the user can enter a range of dates (input names from and to) and I want to be able to compare the range of dates with the dates currently in the database. This is what I have: //////////////////////////////////////////////////////// //////First set the date range that we want to use////// //////////////////////////////////////////////////////// if(isset($_POST['from']) && ($_POST['from'] != NULL)) { $startDate = $_POST['from']; } else { //Default date is Today $startDate = date("Y-m-d"); } if(isset($_POST['to']) && ($_POST['to'] != NULL)) { $endDate = $_POST['to']; } else { //Default day is one month from today $endDate = date("Y-m-d", strtotime("+1 month")); } ////////////////////////////////////////////////////////////////////////////////////// //////Next calculate the total amount of days selected above to use as a limiter////// ////////////////////////////////////////////////////////////////////////////////////// $dayStart = strtotime($startDate); $dayEnd = strtotime($endDate); $total_days = abs($dayEnd - $dayStart) / 86400 +1; echo "Start Date: " . $startDate . "<br>End Date: " . $endDate . "<br>"; echo "Day Start: " . $dayStart . "<br>Day End: " . $dayEnd . "<br>"; echo "Total Days: " . $total_days . "<br>"; //////////////////////////////////////////////////////////////////////////////////// //////Then we're going to see if the dates selected are in the schedule table////// //////////////////////////////////////////////////////////////////////////////////// //Select all of the dates currently in the schedule table between the range selected. $sql = ("SELECT Date FROM schedule WHERE Date BETWEEN '$startDate' AND '$endDate' LIMIT $total_days"); //Run a check on the query to make sure it worked. If it failed then print the error. if(!$result_date_query = $mysqli->query($sql)) { die('There was an error getting the dates from the schedule table [' . $mysqli->error . ']'); } //Set the dates to an array for future use. // $current_dates = $result_date_query->fetch_assoc(); //Loop through the results while a result is being returned. while($row = $result_date_query->fetch_assoc()) { echo "Row: " . $row['Date'] . "<br>"; echo "Start day: " . date('Y-m-d', $dayStart) . "<br>"; //Set this loop to add 1 day to the Start Date until it reaches the End Date for($i = $dayStart; $i <= $dayEnd; $i = strtotime('+1 day', $i)) { $date = date('Y-m-d',$i); echo "Loop Start day: " . date('Y-m-d', $dayStart) . "<br>"; //Run a check to see if any of the dates selected are in the schedule table. if($row['Date'] != $date) { echo "Current Date: " . $row['Date'] . "<br>"; echo "Date: " . $date . "<br>"; echo "It appears as though you've selected some dates that are not in the schedule database.<br>Please correct the issue and try again."; return; } } } //Free the result so something else can use it. $result_date_query->free(); As you can see I've added in some echo statements so I can see what is being produced. From what I can see it looks like my $row['Date'] is not incrementing and staying at the same date. I originally had it set to a variable (currently commented out) but I thought that could be causing problems. I have created the table with dates ranging from 2012-11-01 to 2012-11-15 for testing and entered all of this php code onto phpfiddle.org but I can't get the username provided to connect. Here is the link: PHP Fiddle I'll be reading through the documentation to try and figure out the user connection problem in the meantime, I would really appreciate any direction or advice you can give me.

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  • php session_start() warning

    - by Eniasharmila Karunakaran
    I'm new to php.. Im trying to get value from session. Below is my code. Set session in login page session_start(); $_SESSION["username"] = $username ; $_SESSION["password"] = $password ; $_SESSION["companycode"] = $companycode; Get the session if(! isset($_SESSION)) session_start(); $a=$_SESSION["companycode"]; echo $a; But i got the warning in my page: Warning: session_start() [function.session-start]: Cannot send session cache limiter - headers already sent (output started at C:\xampp\htdocs\lucent\clientlogin.php:216) in C:\xampp\htdocs\lucent\clientlogin.php on line 219 Please help. Thanks

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  • Cookie is setting twice (duplicated)

    - by Erik Larsson
    I'm new to cookies, and im trying to set a cookie where to store the referrer (the org ref). But when i try this function: function do_it_cookie() { // Check if cookie exists if (isset($_COOKIE['ref'])) { // It dose exist, do nothing or anything... } else { setcookie ('ref', $_SERVER['HTTP_REFERER'], time() + 60, '/'); header ("Location: http://www.nyttforetag.com/mind-your-own-business/"); } } I want to store the cookie on the user computer for 30 days, if the return i want to know the initial refereeing url. But when i use this and lets say i go to another page in my site and then go back to the homepage its sets a new cookie with the exact same name and with the ref of the previous page. Is there away to avoid this?

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  • empty() returning TRUE on object's non-empty property

    - by Michal M
    I've got a very weird and unexpected problem. empty() is returning TRUE on a non-empty property for a reason unknown to me. class MyObject { private $_property; public function __construct($property) { $this->_property = $property; } public function __get($name) { $priv_name = "_{$name}"; if (isset($this->$priv_name)) { return $this->$priv_name; } else { return NULL; } } } $obj = new MyObject('string value'); echo $obj->property; // Output 'string value' echo empty($obj->property); // Output 1 (means, that property is empty) Would this mean, that the __get() magic function is not called when using empty()? btw. I'm running PHP version 5.0.4

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