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  • status update error (null field)

    - by ejah85
    hai guys... i .ve the problem that i cannot be recovered yet... i have one form where admin need to approve or reject the booking request... i've set the b_status field in table usage IN PROCESS default value... i want to update the b_status value BOOKING APPROVED when user click APPROVE button.. otherwise, the b_status will update the value as BOOKING REJECTED when user click on the REJECT button here's is the form code: <?php $db = mysql_connect('localhost','root') or die ("unable to connect"); mysql_select_db('fyp',$db) or die ("able to select"); $sql="SELECT * FROM vehicle WHERE v_status='READY'"; $result = mysql_query($sql) or die ("Query failed!"); ?> <tr><td>&nbsp;</td></tr> <tr> <tr> <td width="200"><font face="Arial" size="2" font color="#000000">Registration Number </font></td> <td><select name="regno"> <option value="" selected>--Registration No--</option> <?php while($row = mysql_fetch_array($result)){?> <option value="<?php echo $row['regno']; ?>"><?php echo $row['regno']; ?></option> <?php } ?> </select></td> <td><font face="Arial" size="2" font color="#000000">Reason</font></td> <td><textarea name="reason" rows="3" cols="50 "value = ""></textarea></td> </tr> <?php $db = mysql_connect('localhost','root') or die ("unable to connect"); mysql_select_db('fyp',$db) or die ("able to select"); $sql="SELECT * FROM driver WHERE d_status='READY'"; $result = mysql_query($sql) or die ("Query failed!"); ?> <tr> <td><font face="Arial" size="2" font color="#000000">Driver</font></td> <td><select id = "d_name" name="d_name"> <option value="" selected>--Driver Name--</option> <?php while($row = mysql_fetch_array($result)){?> <option value="<?php echo $row['d_name']; ?>"><?php echo $row['d_name']; ?></option> <?php } ?> </select></td> </tr> <tr> <?php mysql_close($db); ?> </table> <p></p> <center><input name="APPROVED" type="submit" id="APPROVED" value="APPROVED"> <input name="REJECT" type="submit" id="REJECT" value="REJECT"> </center> </div> </center> and this is the process page code: <?php $db = mysql_connect('localhost','root') or die ("unable to connect"); mysql_select_db('fyp',$db) or die ("able to select"); $bookingno=mysql_real_escape_string($_POST['bookingno']); $username=mysql_real_escape_string($_POST['username']); $name=mysql_real_escape_string($_POST['name']); $department=mysql_real_escape_string($_POST['department']); $g_date=mysql_real_escape_string($_POST['g_date']); $g_time=mysql_real_escape_string($_POST['g_time']); $r_date=mysql_real_escape_string($_POST['r_date']); $r_time=mysql_real_escape_string($_POST['r_time']); $destination=mysql_real_escape_string($_POST['destination']); $pass_num=mysql_real_escape_string($_POST['pass_num']); $trip_purpose=mysql_real_escape_string($_POST['trip_purpose']); $regno=mysql_real_escape_string($_POST['regno']); $d_name=mysql_real_escape_string($_POST['d_name']); $reason=mysql_real_escape_string($_POST['reason']); $b_status=mysql_real_escape_string($_POST['b_status']); $sql = "INSERT INTO `usage` VALUES('$bookingno','$username','$name','$department','$g_date','$g_time','$r_date','$r_time','$destination', '$pass_num','$trip_purpose','$regno','$d_name','$reason','$b_status')"; $query = "INSERT INTO `usage` VALUES b_status ='BOOKING APPROVED'"; $result = @mysql_query($query); $query1 = "UPDATE driver SET d_status ='OUT' WHERE '$d_name'=d_name"; $result1 = @mysql_query($query1); if(isset($_POST['APPROVED'])) { $query2 = "UPDATE `usage` SET b_status ='BOOKING APPROVED' WHERE '$b_status'='IN PROCESS'"; $result2 = @mysql_query($query2); } if (isset($_POST['REJECT'])) { $query3 = "UPDATE `usage` SET b_status ='BOOKING REJECTED' WHERE '$b_status'='IN PROCESS'"; $result3 = @mysql_query($query3); } //$result = mysql_query($sql) or die ("error!"); $result = mysql_query($sql) or trigger_error (mysql_error().' in '.$sql); i.ve the problem on the b_status field.. plz guys... help me ya :-)

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  • [PHP] using the magic __set() method with 2D arrays

    - by Spoonface
    If I have the following registry class: Class registry { private $_vars; public function __construct() { $this->_vars = array(); } public function __set($key, $val) { $this->_vars[$key] = $val; } public function __get($key) { if (isset($this->_vars[$key])) return $this->_vars[$key]; } public function printAll() { print "<pre>".print_r($this->_vars,true)."</pre>"; } } $reg = new registry(); $reg->arr = array(1,2,3); $reg->arr = array_merge($reg->arr,array(4)); $reg->printAll(); Would there be an easier way to push a new item onto the 'arr' array? This code: 'array[] = item' doesn't work with the magic set method, and I couldn't find any useful info with google. Thanks for your time!

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  • php open_socket

    - by sea_1987
    Hello, I am trying to open a socket to use with secure tradings xpay api, however when I check to see if the socket is open I get error returned, Can't assign requested address I need to open up 127.0.0.1:5000 is there something wring with my code that means I cannot do this? if (isset($xpay_port) and ($socket=socket_create(AF_INET, SOCK_STREAM, SOL_TCP)) and (socket_connect($socket, $address, $port))) { $text="Connection successful on IP $address, port $port"; socket_close($socket); } else $text="Unable to connect<pre>".socket_strerror(socket_last_error())."</pre>"; echo "<html><head></head><body>". $text. "</body></html>";

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  • Making a Link Appear if a Condition is Met

    - by John
    Hello, The PHP code below echoes a link if the "loginid" of the logged-in user is on a list determined by getEditorList();. It works fairly well, but I think it might work better if I were to do it with Javascript instead. How could I accomplish the same thing with Javascript? Thanks in advance, John $editors = getEditorsList(); foreach($editors as $editor) { $editorids[] = $editor['loginid']; } if(in_array($_SESSION['loginid'], $editorids)) { echo "<div class='footervote'><a href='http://www...com/.../footervote.php'>Vote</a></div>"; } Login function: <?php if (!isLoggedIn()) { if (isset($_POST['cmdlogin'])) { if (checkLogin($_POST['username'], $_POST['password'])) { show_userbox(); } else { echo "Incorrect Login information !"; show_loginform(); } } else { show_loginform(); } } else { show_userbox(); } ?>

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  • Rewriting usort function because of fatal error (PHP bug)

    - by Lionel
    The two following usort functions throw fatal error Base lambda function for closure not found in our productive environment (PHP 5.4). This seems to be a known PHP bug that should be fixed by now (https://bugs.php.net/bug.php?id=52144), but it still occurs for us. Anyway, we unfortunately don't have time to figure out what's wrong with our PHP configurations etc. We would like to rewrite these two functions without the use of anonymous functions, so that the error doesn't occur anymore. Ordering of a multidimensional array ($array) by value of key "position": usort($array, function($a, $b) { return $a['position'] - $b['position']; }); Ordering of a multidimensional array ($array) according to the order of a second array ($position_order): usort($array, function($a, $b) use($position_order) { return (isset($position_order[$a['ftid']]) ? ($position_order[$a['ftid']] - $position_order[$b['ftid']]) : 1); }); Especially the latter causes some headache, as we don't know how to pass the "outside" array $position_order.

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  • jQuery getting these functions to work together

    - by brett
    I'm new to jQuery and have tried looking around for an answer on how to do this. I have 2 functions and I would like both to work together. The one function is submitHandler and its used to hide a form and at the same time add a class to a hidden element to unhide it - ie a thank you for submitting h1. The other function is to grab the input data and display it onsubmit in the form. So the problem is that I can get that one to work but then the other doesnt. Ie on form submit I can see the data input but not the h1 Thank you message. Here are the functions: SubmitHandler: submitHandler: function() { $("#content").empty(); $("#content").append( "<p>If you want to be kept in the loop...</p>" + "<p>Or you can contact...</p>" ); $('h1.success_').removeClass('success_').addClass('success_form'); $('#contactform').hide(); }, onsubmit="return inputdata()" function inputdata(){ var usr = document.getElementById('contactname').value; var eml = document.getElementById('email').value; var msg = document.getElementById('message').value; document.getElementById('out').innerHTML = usr + " " + eml + msg; document.getElementById('out').style.display = "block"; return true; }, The form uses PHP and jQuery - I dont know about AJAX but after some reading even less sure. Please help me out I dont know what I'm doing and at the moment I am learning but its a long road for me still. Thank you The form: <form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>" id="contactform" onsubmit="return inputdata()"> <div class="_required"><p class="label_left">Name*</p><input type="text" size="50" name="contactname" id="contactname" value="" class="required" /></div><br/><br/> <div class="_required"><p class="label_left">E-mail address*</p><input type="text" size="50" name="email" id="email" value="" class="required email" /></div><br/><br/> <p class="label_left">Message</p><textarea rows="5" cols="50" name="message" id="message" class="required"></textarea><br/> <input type="submit" value="submit" name="submit" id="submit" /> </form> The PHP bit: <?php $subject = "Website Contact Form Enquiry"; //If the form is submitted if(isset($_POST['submit'])) { //Check to make sure that the name field is not empty if(trim($_POST['contactname']) == '') { $hasError = true; } else { $name = trim($_POST['contactname']); } //Check to make sure sure that a valid email address is submitted if(trim($_POST['email']) == '') { $hasError = true; } else if (!eregi("^[A-Z0-9._%-]+@[A-Z0-9._%-]+\.[A-Z]{2,4}$", trim($_POST['email']))) { $hasError = true; } else { $email = trim($_POST['email']); } //Check to make sure comments were entered if(trim($_POST['message']) == '') { $hasError = true; } else { if(function_exists('stripslashes')) { $comments = stripslashes(trim($_POST['message'])); } else { $comments = trim($_POST['message']); } } //If there is no error, send the email if(!isset($hasError)) { $emailTo = '[email protected]'; //Put your own email address here $body = "Name: $name \n\nEmail: $email \n\nComments:\n $comments"; $headers = 'From: My Site <'.$emailTo.'>' . "\r\n" . 'Reply-To: ' . $email; mail($emailTo, $subject, $body, $headers); $emailSent = true; } } ? The Jquery Validate bit: $(document).ready(function(){ $('#contactform').validate({ showErrors: function(errorMap, errorList) { //restore the normal look $('#contactform div.xrequired').removeClass('xrequired').addClass('_required'); //stop if everything is ok if (errorList.length == 0) return; //Iterate over the errors for(var i = 0;i < errorList.length; i++) $(errorList[i].element).parent().removeClass('_required').addClass('xrequired'); }, Here is the full jQuery bit: $(document).ready(function(){ $('#contactform').validate({ showErrors: function(errorMap, errorList) { //restore the normal look $('#contactform div.xrequired').removeClass('xrequired').addClass('_required'); //stop if everything is ok if (errorList.length == 0) return; //Iterate over the errors for(var i = 0;i < errorList.length; i++) $(errorList[i].element).parent().removeClass('_required').addClass('xrequired'); }, submitHandler: function() { $('h1.success_').removeClass('success_').addClass('success_form'); $("#content").empty(); $("#content").append('#sadhu'); $('#contactform').hide(); }, }); }); Latest edit - Looks like this: $(document).ready(function(){ $('#contactform').validate({ showErrors: function(errorMap, errorList) { //restore the normal look $('#contactform div.xrequired').removeClass('xrequired').addClass('_required'); //stop if everything is ok if (errorList.length == 0) return; //Iterate over the errors for(var i = 0;i < errorList.length; i++) $(errorList[i].element).parent().removeClass('_required').addClass('xrequired'); }, function submitHandler() { $('h1.success_').removeClass('success_').addClass('success_form'); $("#content").empty(); $("#content").append('#sadhu'); $('#contactform').hide(); }, function inputdata() { var usr = document.getElementById('contactname').value; var eml = document.getElementById('email').value; var msg = document.getElementById('message').value; document.getElementById('out').innerHTML = usr + " " + eml + msg; document.getElementById('out').style.display = "block"; }, $(document).ready(function(){ $('#contactForm').submit(function() { inputdata(); submitHandler(); }); }); });

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  • Incrmenting a Cookies with PHP (Beginner Question)

    - by BandonRandon
    Hello, I have used sessions before but never cookies. I would like to use cookies for two reasons: 1) it's something new to learn 2) I would like to have the cookie expire in an hour or so (i know in the code example it expires in 40 sec) I am trying to write a basic if statement that if($counter=="1") { //do this second } elseif ($counter >="2") { //do this every time after the first and second } else {// this is the first action as counter is zero } Here is the code I'm using to set the cookie: // if cookie doesnt exsist, set the default if(!isset($_COOKIE["counter_cookie"])) { $counter = setcookie("counter_cookie", 0 ,time()+40); } // increment it $counter++; // save it setcookie("counter_cookie", $counter,time()+40); $counter = $_COOKIE["counter_cookie"]; The problem is that the counter will be set from 0 to 1 but won't be set from 1 to 2 and so on. Any help would be great I know this is a really simple stupid question :| Thanks!

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  • Sending mail from a contact form. Simple but challenging!

    - by ekalaivan
    I've set up a contact form in the Greet Us page in http://swedsb.com When I submit the form, it says mail sent successfully. But I'm not getting the mail, checked the spam folder. I've set a similar form at http://ibsolutions.in. It is working perfectly. Been breaking my head for the past 4 hours. Here's my contact.php <?phpif(isset($_POST['submit'])) { $to = "[email protected]"; $subject = $_POST['posRegard']; $name = $_POST['posName']; $email = $_POST['posEmail']; $message = $_POST['posText']; $body = "$name has sent you a greeting. \n E-Mail: $email\nMessage:\n $message"; mail($to, $subject, $body); header( 'Location: http://swedsb.com/' ); } else {echo "blarg!";}?

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  • form Validation white page not showing errors

    - by Jess McKenzie
    In the example below I am wanting to do all of the 'safety' checks on the $_POST variables but it seems when I click submit I get a white page why? I am wanting it to show the errors etc Form Process: /* check if the form is submitted */ if (isset($_POST['submitButton'])) { $fullName = $_POST['fullname']; if($_SERVER['REQUEST_METHOD'] == 'POST' && !empty($fullName)) { if (!ctype_alpha(str_replace(array("'", "-"), "",$fullName))) { $errorfullName .= '<span class="errorfullName">*First name should be alpha characters only.</span>'; } if (strlen($fullName) < 3 OR strlen($fullName) > 40) { $errorfullName .= '<span class="errorfullName">*First name should be within 3-40 characters long.</span>'; } } }

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  • click multiple times a submit button

    - by Olga Anastasiadou
    Hi all, I encountered a problem that I can't solve. My point is to "click" my sybmit button and every time increase a counter, while this counter reach 10. For the first time it works, but this is it! My test code is below : <form name="testForm" method="post"> <?php $cnt=0; ?> <input type="submit" name="next" id="next" value="NEXT"/> <?php if(isset($_POST['next'])){ if($cnt< 10){ echo $cnt.' --> '; $cnt++; echo $cnt; } } ?> </form> Only 0 -- 1 is printed, every time... please help!! Thanks

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  • How to test if a user has uploaded a file ?

    - by Tristan
    Hello, on a page, i have : if (!empty($_FILES['logo']['name'])) { $dossier = 'upload/'; $fichier = basename($_FILES['logo']['name']); $taille_maxi = 100000; $taille = filesize($_FILES['logo']['tmp_name']); $extensions = array('.png', '.jpg', '.jpeg'); $extension = strrchr($_FILES['logo']['name'], '.'); //Début des vérifications de sécurité... if(!in_array($extension, $extensions)) { $erreur = 'ERROR you must upload the right type'; } if($taille>$taille_maxi) { $erreur = 'too heavy'; } if(!empty($erreur)) { ....................... } The problem is, if the users wants to edit information WITHOUT uploading a LOGO, it raises an error : 'error you must upload the right type' So, if a user didn't put anything in the inputbox in order to upload it, i don't want to enter in these conditions test. i tested : if (!empty($_FILES['logo']['name']) and if (isset($_FILES['logo']['name']) but both doesn't seems to work. Any ideas? thanks.

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  • how to update mysql with inputs and checkboxes

    - by Ronnie Chester Lynwood
    hi. with this code: <? if (isset($_POST['onay'])) { foreach ($_POST['secilen'] as $zuha) { $olay = mysql_query("update mp3 SET aktif = '1' WHERE id = '$zuha'"); } if ($olay) { echo "islem tamam"; exit; } } ?> and with this form: (select * from mp3 aktif = '0') <form name="form" method="post"> <input readonly type="text" name="id" value="<?=$haciosman['id']?>" /> <input type="text" name="baslik" value="<?=$haciosman['baslik']?> <input type="checkbox" name="secilen[]" value="<?=$haciosman['id']?>"> <input type="submit" name="onay" value="Onayla" /> I can set "aktif to 1" for each row that i checked. but i want to update "baslik" too! how can i update each "baslik" with that php code?

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  • php session variable

    - by Idealflip
    Hi Everyone, my session variable seems to keep dropping its array values. What could I be doing wrong? Is it my object? if(isset($_SESSION['locations'])){ $_SESSION['locations']->listItems($_POST['companyLocation']); echo "session exists"; }else{ $_SESSION['locations'] = new Location(); $_SESSION['locations']->listItems($_POST['companyLocation']); echo "session does not exist"; } class Location { function listItems($location){ $array; $array[] = $location; print_r($array); }

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  • having trouble with a mysql query

    - by chuck akers
    this keeps saying Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in directory here the error is near the login_query variable, can someone help me fix it. <?php if (isset($_POST['login_username'], $_POST['login_password'])) { $login_username = trim(mysql_real_escape_string(htmlentities($_POST['login_username']))); $login_password = md5(trim(mysql_real_escape_string(htmlentities($_POST['login_password'])))); if (!empty($login_username) && !empty($login_password)) { $login_query = mysql_query("SELECT user_id FROM username WHERE username='".$login_username."' AND password='".$login_password."'"); if (mysql_num_rows($login_query)==1) { $user_id = mysql_result($login_query, 0, 'user_id'); $_SESSION['user_id'] = $user_id; header('Location: index.php'); die(); } }} ?

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  • Cookie Value not available, why?

    - by Camran
    I have tested this on my development computer, but now I have uploaded everything to the production server and I cant read out the value of the cookie. I think the problem lies in the Serialization and Unserialization. if (isset($_COOKIE['watched_ads'])){ $expir = time()+1728000; //20 days $ad_arr = unserialize($_COOKIE['watched_ads']); // HERE IS THE PROBLEM $arr_elem = count($ad_arr); if (in_array($ad_id, $ad_arr) == FALSE){ if ($arr_elem>10){ array_shift($ad_arr); } $ad_arr[]=$ad_id; setcookie('watched_ads', serialize($ad_arr), $expir, '/'); } } When I echo this: count($ad_arr) I receive the expected nr, 1 in this case, so there is a value there. But when I echo the value: echo $ad_arr[0]; I get nothing. Completely blank. No text at all. Anybody have a clue? if you need more info about something let me know...

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  • Cookie is setting twice (dublicated)

    - by Erik Larsson
    I'm new to cookies, and im trying to set a cookie where to store the referer (the org ref). But when i try this function: function do_it_cookie() { // Check if cookie exists if (isset($_COOKIE['ref'])) { // It dose exist, do nothing or anything... } else { setcookie ('ref', $_SERVER['HTTP_REFERER'], time() + 60, '/'); header ("Location: http://www.nyttforetag.com/mind-your-own-business/"); } } I want to store the cookie on the user computer for 30 days, if the return i want to know the initial refereeing url. But when i use this and lets say i go to another page in my site and then go back to the homepage its sets a new cookie with the exact same name and with the ref of the previous page. Is there away to avoid this?

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  • Codeigniter Template library, add_js() method

    - by Karl
    using This Template Library when i try and use the add_js() function it errors out. I add the regions $_scripts to the template header file but when i load the page it says undefined variable _scripts. any thoughts? changed <?= $_scripts ?> to <?= (isset($_scripts)) ? $_scripts : “”; ?> and obviously i lose the error but the js file still isnt loading. I did an echo at each step though the add_js() method and the output is correct. I also did an output of $this-js and they both had the corret output. So it gets through the get_js method fine and sets the class variable fine but i dont get anything added to the actual page.

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  • Codeigniter view file looping query

    - by user2505513
    Right, I'm unsure about how to code my view file to generate following query results WITHOUT compromising the principles of mvc. Query in model: SELECT * FROM events GROUP BY country, area ORDER BY country, area View: <?php if (isset($query)):?> <?php foreach ($query as $row):?> <h2><?=$row->country?></h2> <h3><?=$row->area?></h3> <?php endforeach;?> <?php endif;?> I want the results to display: England North South West - utilising the GROUP BY parameter As opposed to: England North England South England West Has anybody any advice as to how to achieve this?

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  • mysql_fetch_assoc data to COOKIE in user browser

    - by Gowtham Raj
    I had data in mysql, where it does not need any security. I had a sql query string to get the data out every time using mysql_fetch_assoc. So, I planed to store data in users browser.To reduce no of quires to sql. if (!isset($_COOKIE['countries'])){ $query = "SELECT iso,name FROM sel_country"; $countries = mysql_query($query); setcookie('countries', serialize($countries), time()+3600); }else{ $countries = $unserialize($_COOKIE['countries']); } while ($row = mysql_fetch_assoc($countries)) {echo $row['name']} But, When cookie is set it is showing following error Fatal error: Function name must be a string in /home/worlds/public_html/index/ctrl.php on line 15 My cookie in browser displaying content as i%3A0%3B Please help me out, how should i go?

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  • Cookie is setting twice (duplicated)

    - by Erik Larsson
    I'm new to cookies, and im trying to set a cookie where to store the referrer (the org ref). But when i try this function: function do_it_cookie() { // Check if cookie exists if (isset($_COOKIE['ref'])) { // It dose exist, do nothing or anything... } else { setcookie ('ref', $_SERVER['HTTP_REFERER'], time() + 60, '/'); header ("Location: http://www.nyttforetag.com/mind-your-own-business/"); } } I want to store the cookie on the user computer for 30 days, if the return i want to know the initial refereeing url. But when i use this and lets say i go to another page in my site and then go back to the homepage its sets a new cookie with the exact same name and with the ref of the previous page. Is there away to avoid this?

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  • Having trouble comparing a range of dates entered in a form with records in a mySQL database

    - by Andrew Fox
    I have a table called schedule and a column called Date where the column type is date. In that column I have a range of dates, which is currently from 2012-11-01 to 2012-11-30. I have a small form where the user can enter a range of dates (input names from and to) and I want to be able to compare the range of dates with the dates currently in the database. This is what I have: //////////////////////////////////////////////////////// //////First set the date range that we want to use////// //////////////////////////////////////////////////////// if(isset($_POST['from']) && ($_POST['from'] != NULL)) { $startDate = $_POST['from']; } else { //Default date is Today $startDate = date("Y-m-d"); } if(isset($_POST['to']) && ($_POST['to'] != NULL)) { $endDate = $_POST['to']; } else { //Default day is one month from today $endDate = date("Y-m-d", strtotime("+1 month")); } ////////////////////////////////////////////////////////////////////////////////////// //////Next calculate the total amount of days selected above to use as a limiter////// ////////////////////////////////////////////////////////////////////////////////////// $dayStart = strtotime($startDate); $dayEnd = strtotime($endDate); $total_days = abs($dayEnd - $dayStart) / 86400 +1; echo "Start Date: " . $startDate . "<br>End Date: " . $endDate . "<br>"; echo "Day Start: " . $dayStart . "<br>Day End: " . $dayEnd . "<br>"; echo "Total Days: " . $total_days . "<br>"; //////////////////////////////////////////////////////////////////////////////////// //////Then we're going to see if the dates selected are in the schedule table////// //////////////////////////////////////////////////////////////////////////////////// //Select all of the dates currently in the schedule table between the range selected. $sql = ("SELECT Date FROM schedule WHERE Date BETWEEN '$startDate' AND '$endDate' LIMIT $total_days"); //Run a check on the query to make sure it worked. If it failed then print the error. if(!$result_date_query = $mysqli->query($sql)) { die('There was an error getting the dates from the schedule table [' . $mysqli->error . ']'); } //Set the dates to an array for future use. // $current_dates = $result_date_query->fetch_assoc(); //Loop through the results while a result is being returned. while($row = $result_date_query->fetch_assoc()) { echo "Row: " . $row['Date'] . "<br>"; echo "Start day: " . date('Y-m-d', $dayStart) . "<br>"; //Set this loop to add 1 day to the Start Date until it reaches the End Date for($i = $dayStart; $i <= $dayEnd; $i = strtotime('+1 day', $i)) { $date = date('Y-m-d',$i); echo "Loop Start day: " . date('Y-m-d', $dayStart) . "<br>"; //Run a check to see if any of the dates selected are in the schedule table. if($row['Date'] != $date) { echo "Current Date: " . $row['Date'] . "<br>"; echo "Date: " . $date . "<br>"; echo "It appears as though you've selected some dates that are not in the schedule database.<br>Please correct the issue and try again."; return; } } } //Free the result so something else can use it. $result_date_query->free(); As you can see I've added in some echo statements so I can see what is being produced. From what I can see it looks like my $row['Date'] is not incrementing and staying at the same date. I originally had it set to a variable (currently commented out) but I thought that could be causing problems. I have created the table with dates ranging from 2012-11-01 to 2012-11-15 for testing and entered all of this php code onto phpfiddle.org but I can't get the username provided to connect. Here is the link: PHP Fiddle I'll be reading through the documentation to try and figure out the user connection problem in the meantime, I would really appreciate any direction or advice you can give me.

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  • form not showing for empty records

    - by Chris Hodges
    I have a relatively simple PHP page called editcustomers with 3 columns. The problem I'm having is that the form will show when there is a record in the database and the fields will be populated with that info. When no such records exists, the form is not even shown, eliminating the possibility to insert a record. My page layout is as follows: Column 1 shows a form containing customer information, allowing it to be edited. Column 2 allows ordering of products and showing how many products were ordered Column 3 shows the total paid so far, and the total owing. The code for the page I have at present: <html> <?php $id = $_GET['id']; require_once('connect.php'); $sth = $dbh->query("SELECT * FROM users where id = '$id';"); $sth->setFetchMode(PDO::FETCH_ASSOC); $eth = $dbh->query("SELECT * FROM purchases where id = '$id';"); $eth->setFetchMode(PDO::FETCH_ASSOC); ?> <div id="main"> <div id="left"> <form name="custInfo" action ="process.php" method ="post" > <input type = "hidden" name ="formType" value="custInfo"/> <?php while($row = $sth->fetch()){ ?> <p><input type = "hidden" name ="id" value="<?php echo $row["id"] ?>"/> <p><input type = "text" name ="firstName" size ="30" value=" <?php echo $row["firstName"]?>"/> <p><input type = "text" name ="lastName" size ="30" value="<?php echo $row["lastName"]?>"/> <p><input type = "text" name ="country" size ="30" value="<?php echo $row["country"]?>"/> <p></p> <input type="submit" value="Update" /> <?php }?> </div> <div id="mid"> <form name="custCosts" action ="process.php" method ="post" > <input type = "hidden" name ="formType" value="custCosts"/> <?php while($row = $eth->fetch()){ ?> <p><input type = "hidden" name ="id" value="<?php echo $row["id"] ?>"/> <p><input type = "text" name ="amountOwed" size ="30" value=" <?php echo $row["amountOwed"]?>"/> <p><input type = "text" name ="numAaa" size ="30" value="<?php echo $row["numAaa"]?>"/> <p><input type = "text" name ="numBbb" size ="30" value="<?php echo $row["numBbb"]?>"/> <p></p> <input type="submit" value="Update" /> <?php }?> </div> <div id="right"> <b>Total Balance</b> <p> Money owed: </p> <p> aaa total: </p> <p> bbb total: </p> <p> Total: </p> <input type = "text" name ="pay" size ="20" /></p> <input type="submit" value="Make Payment" /> </div> <?php $dbh =null; ?> </body> </html> And the code for all the database trickery: <?php require_once 'connect.php'; $formType = $_POST['formType']; $id = $_POST['id']; $firstName = $_POST['firstName']; $lastName = $_POST['lastName']; $country = $_POST['country']; $amountOwed = $_POST['amountOwed ']; $numAaa = $_POST['numAaa']; $numBbb = $_POST['numBbb']; if(empty($_POST['id'])) { $sth = $dbh->prepare("INSERT INTO customers (firstName, lastName, country) VALUES ('$firstName', '$lastName', '$country')"); $sth->execute(); } elseif(!empty($_POST['id']) && !isset($_POST['stayCost']) && $_POST['formType'] == 'guestInfo'){ $sth = $dbh->prepare("UPDATE customers SET firstName = '$firstName', lastName = '$lastName', country = '$country' WHERE id = '$id'"); $sth->execute(); }elseif(!empty($_POST['id']) && isset($_POST['stayCost']) && $_POST['formType'] == 'guestInfo'){ $sth = $dbh->prepare("INSERT INTO purchases (id, amountOwed, numAaa, numBbb) VALUES ('$id', '$amountOwed', '$numAaa', '$numBbb'"); $sth->execute(); }elseif(!empty($_POST['id']) && $_POST['formType'] == 'guestCosts'){ $sth = $dbh->prepare("UPDATE purchases SET amountOwed= '$amountOwed', numAaa = '$numAaa', numBbb= '$numBbb' WHERE id = '$id'"); $sth->execute(); } $dbh =null; ?> Why does the form not even display if there is no record? An error or something I might understand....but the form is still in the HTML and should still be being output, from what I can see. Why is this not the case?

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  • Zend Framework url redirect

    - by Uffo
    <?php class PI_Controller_Plugin_AssetGrabber extends Zend_Controller_Plugin_Abstract { public function dispatchLoopStartup(Zend_Controller_Request_Abstract $request) { /* The module name */ $moduleName = $request->getModuleName(); /* This modules requires the user to be loggedin in order to see the web pages! */ $loginRequiredModules = array('admin'); if (in_array($moduleName,$loginRequiredModules)) { $adminLogin = new Zend_Session_Namespace('adminLogin'); if (!isset($adminLogin->loggedin)) { /*-------------------------------------- Here I want to redirect the user */ $this->_redirect('/something'); } } } } I'm trying to do a redirect $this->_redirect('/something') but doesn't work! Do you know how can I do a redirect in this case? Best Regards,

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  • How to refresh site if $_SESSION variable has changed

    - by 4ndro1d
    I'm writing in my $_SESSION variable from a database, when i clicked a link. public function getProjectById($id){ $query="SELECT * FROM projects WHERE id=\"$id\""; $result=mysql_query($query); $num=mysql_numrows($result); while ($row = mysql_fetch_object($result)) { $_SESSION['projectid'] = $row->id; $_SESSION['projecttitle'] = $row->title; $_SESSION['projectinfo'] = $row->info; $_SESSION['projecttext'] = $row->text; $_SESSION['projectcategory'] = $row->category; } } Now my variable is overwritten and I want to show these variables in my index.php like this: <div id="textContent"> <?php if(isset($_SESSION['projecttext']) && !empty($_SESSION['projecttext'])) { echo $_SESSION['projecttext']; }else { echo 'No text'; } ?></div> But of course, my page will not refresh automatically. How can I do that?

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  • PHP Security checklist (injection, sessions etc)

    - by NoviceCoding
    So what kind of things should a person using PHP and MySql be focused on to maximize security. Things I have done: -mysql_real_escape_string all inputs -validate all inputs after escaping em -Placed random alpha numerics before my table names -50character salt + Ripemd passwords Heres where I think I am slacking: -I know know nothing about sessions and securing them. How unsafe/safe is it if all you are doing is: session_start(); $_SESSION['login']= $login; and checking it with: session_start(); if(isset($_SESSION['login'])){ -I heard something about other forms of injection like cross site injection and what not... -And probably many other things I dont know about. Is there a "checklist"/Quicktut on making php secure? I dont even know what I should be worried about.I kinda regret now not building off cakephp since I am not a pro.

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