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  • Python re module becomes 20 times slower when called on greater than 101 different regex

    - by Wiil
    My problem is about parsing log files and removing variable parts on each lines to be able to group them. For instance: s = re.sub(r'(?i)User [_0-9A-z]+ is ', r"User .. is ", s) s = re.sub(r'(?i)Message rejected because : (.*?) \(.+\)', r'Message rejected because : \1 (...)', s) I have about 120+ matching rules like those above. I have found no performances issues while searching successively on 100 different regex. But a huge slow down comes when applying 101 regex. Exact same behavior happens when replacing my rules set by for a in range(100): s = re.sub(r'(?i)caught here'+str(a)+':.+', r'( ... )', s) Got 20 times slower when putting range(101) instead. # range(100) % ./dashlog.py file.bz2 == Took 2.1 seconds. == # range(101) % ./dashlog.py file.bz2 == Took 47.6 seconds. == Why such thing is happening ? And is there any known workaround ? (Happens on Python 2.6.6/2.7.2 on Linux/Windows.)

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  • Regex Replacing only whole matches

    - by Leen Balsters
    I am trying to replace a bunch of strings in files. The strings are stored in a datatable along with the new string value. string contents = File.ReadAllText(file); foreach (DataRow dr in FolderRenames.Rows) { contents = Regex.Replace(contents, dr["find"].ToString(), dr["replace"].ToString()); File.SetAttributes(file, FileAttributes.Normal); File.WriteAllText(file, contents); } The strings look like this _-uUa, -_uU, _-Ha etc. The problem that I am having is when for example this string "_uU" will also overwrite "_-uUa" so the replacement would look like "newvaluea" Is there a way to tell regex to look at the next character after the found string and make sure it is not an alphanumeric character? I hope it is clear what I am trying to do here. Here is some sample data: private function _-0iX(arg1:flash.events.Event):void { if (arg1.type == flash.events.Event.RESIZE) { if (this._-2GU) { this._-yu(this._-2GU); } } return; } The next characters could be ;, (, ), dot, comma, space, :, etc.

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  • regex match css class name from single string containing multiple classes

    - by effectica
    I have a long string that contains multiple css classes. With regex I would like to match every class name as I then need to replace these class names like so: <span>CLASSNAME</span> I have tried for hours to come up with a solution and I think I am close however for certain class names I am not able to exclude closing curly brackets from the match. Here is a sample string I have been carrying out testing on: #main .items-Outer p{ font-family:Verdana; color: #000000; font-size: 50px; font-weight: bold; }#footer .footer-inner p.intro{ font-family:Arial; color: #444444; font-size: 30; font-weight: normal; }.genericTxt{ font-family:Courier; color: #444444; font-size: 30; font-weight: normal; } And here is the the regex I came up with so far: ((^(?:.+?)(?:[^{]*))|((?:\})(?:.+?)(?:[^{]*))) Please look at the screenshot I am attaching as it will show more clearly the matches I get. My problem is that I would obviously like to exclude curly brackets from any match.

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  • Javascript Regex: Testing string for intelligent query

    - by Shyam
    Hi, I have a string that holds user input. This string can contain various types of data, like: a six digit id a zipcode that contains out of 4 digits and two alphanumeric characters a name (characters only) As I am using this string to search through a database, the query type is determined on the type of search, which i want to handle serverside using JavaScript (yes, I am using JavaScript serverside). Searching on StackOverflow, brought me some interesting information, like the .test-method, which seems perfect for my needs. The test-method returns either true or false based on the evaluation on the string using a regex object. I am using this page as a reference: http://www.javascriptkit.com/jsref/regexp.shtml So I am trying to determine the zipcode, by using the following very noobish regex. var r = /[A-Za-z]{2,2}/ As far I can understand, this should limit the amount of occurrences of alphanumeric characters to a maximum of two. See beneath the output of my JavaScript console. > var r = /[A-Za-z]{2,2}/ > var x = "2233AL" > r.test(x) true > var x = "2233A" > r.test(x) false > var x = "2233ALL" > r.test(x) true /* i want this to be false */ > A little help would be really appreciated!

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  • java regex for alpha and spaces is including [ ] \

    - by JayAvon
    This is my regex for my JTextField to not be longer than x characters and to not include anything other than letters or spaces. For some reason it is allowing [ ] and \ characters. This is driving me crazy. Is my regex wrong?? package com.jayavon.game.helper; import java.awt.Toolkit; import javax.swing.text.AttributeSet; import javax.swing.text.BadLocationException; import javax.swing.text.PlainDocument; public class CharacterNameCreationDocument extends PlainDocument { private static final long serialVersionUID = 1L; private int limit; public CharacterNameCreationDocument(int limit) { super(); this.limit = limit; } public void insertString(int offset, String str, AttributeSet attr) throws BadLocationException { if (str == null || (getLength() + str.length()) > limit || !str.matches("[a-zA-z\\s]*")){ Toolkit.getDefaultToolkit().beep(); return; } else { super.insertString(offset, str, attr); } } }

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  • Regex for ignoring consecutive quotation marks in string

    - by will-hart
    I have built a parser in Sprache and C# for files using a format I don't control. Using it I can correctly convert: a = "my string"; into my string The parser (for the quoted text only) currently looks like this: public static readonly Parser<string> QuotedText = from open in Parse.Char('"').Token() from content in Parse.CharExcept('"').Many().Text().Token() from close in Parse.Char('"').Token() select content; However the format I'm working with escapes quotation marks using "double doubles" quotes, e.g.: a = "a ""string""."; When attempting to parse this nothing is returned. It should return: a ""string"". Additionally a = ""; should be parsed into a string.Empty or similar. I've tried regexes unsuccessfully based on answers like this doing things like "(?:[^;])*", or: public static readonly Parser<string> QuotedText = from content in Parse.Regex("""(?:[^;])*""").Token() This doesn't work (i.e. no matches are returned in the above cases). I think my beginners regex skills are getting in the way. Does anybody have any hints? EDIT: I was testing it here - http://regex101.com/r/eJ9aH1

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  • Spring security request matcher is not working with regex

    - by Felipe Cardoso Martins
    Using Spring MVC + Security I have a business requirement that the users from SEC (Security team) has full access to the application and FRAUD (Anti-fraud team) has only access to the pages that URL not contains the words "block" or "update" with case insensitive. Bellow, all spring dependencies: $ mvn dependency:tree | grep spring [INFO] +- org.springframework:spring-webmvc:jar:3.1.2.RELEASE:compile [INFO] | +- org.springframework:spring-asm:jar:3.1.2.RELEASE:compile [INFO] | +- org.springframework:spring-beans:jar:3.1.2.RELEASE:compile [INFO] | +- org.springframework:spring-context:jar:3.1.2.RELEASE:compile [INFO] | +- org.springframework:spring-context-support:jar:3.1.2.RELEASE:compile [INFO] | \- org.springframework:spring-expression:jar:3.1.2.RELEASE:compile [INFO] +- org.springframework:spring-core:jar:3.1.2.RELEASE:compile [INFO] +- org.springframework:spring-web:jar:3.1.2.RELEASE:compile [INFO] +- org.springframework.security:spring-security-core:jar:3.1.2.RELEASE:compile [INFO] | \- org.springframework:spring-aop:jar:3.0.7.RELEASE:compile [INFO] +- org.springframework.security:spring-security-web:jar:3.1.2.RELEASE:compile [INFO] | +- org.springframework:spring-jdbc:jar:3.0.7.RELEASE:compile [INFO] | \- org.springframework:spring-tx:jar:3.0.7.RELEASE:compile [INFO] +- org.springframework.security:spring-security-config:jar:3.1.2.RELEASE:compile [INFO] +- org.springframework.security:spring-security-acl:jar:3.1.2.RELEASE:compile Bellow, some examples of mapped URL path from spring log: Mapped URL path [/index] onto handler 'homeController' Mapped URL path [/index.*] onto handler 'homeController' Mapped URL path [/index/] onto handler 'homeController' Mapped URL path [/cellphone/block] onto handler 'cellphoneController' Mapped URL path [/cellphone/block.*] onto handler 'cellphoneController' Mapped URL path [/cellphone/block/] onto handler 'cellphoneController' Mapped URL path [/cellphone/confirmBlock] onto handler 'cellphoneController' Mapped URL path [/cellphone/confirmBlock.*] onto handler 'cellphoneController' Mapped URL path [/cellphone/confirmBlock/] onto handler 'cellphoneController' Mapped URL path [/user/update] onto handler 'userController' Mapped URL path [/user/update.*] onto handler 'userController' Mapped URL path [/user/update/] onto handler 'userController' Mapped URL path [/user/index] onto handler 'userController' Mapped URL path [/user/index.*] onto handler 'userController' Mapped URL path [/user/index/] onto handler 'userController' Mapped URL path [/search] onto handler 'searchController' Mapped URL path [/search.*] onto handler 'searchController' Mapped URL path [/search/] onto handler 'searchController' Mapped URL path [/doSearch] onto handler 'searchController' Mapped URL path [/doSearch.*] onto handler 'searchController' Mapped URL path [/doSearch/] onto handler 'searchController' Bellow, a test of the regular expressions used in spring-security.xml (I'm not a regex speciality, improvements are welcome =]): import java.util.Arrays; import java.util.List; public class RegexTest { public static void main(String[] args) { List<String> pathSamples = Arrays.asList( "/index", "/index.*", "/index/", "/cellphone/block", "/cellphone/block.*", "/cellphone/block/", "/cellphone/confirmBlock", "/cellphone/confirmBlock.*", "/cellphone/confirmBlock/", "/user/update", "/user/update.*", "/user/update/", "/user/index", "/user/index.*", "/user/index/", "/search", "/search.*", "/search/", "/doSearch", "/doSearch.*", "/doSearch/"); for (String pathSample : pathSamples) { System.out.println("Path sample: " + pathSample + " - SEC: " + pathSample.matches("^.*$") + " | FRAUD: " + pathSample.matches("^(?!.*(?i)(block|update)).*$")); } } } Bellow, the console result of Java class above: Path sample: /index - SEC: true | FRAUD: true Path sample: /index.* - SEC: true | FRAUD: true Path sample: /index/ - SEC: true | FRAUD: true Path sample: /cellphone/block - SEC: true | FRAUD: false Path sample: /cellphone/block.* - SEC: true | FRAUD: false Path sample: /cellphone/block/ - SEC: true | FRAUD: false Path sample: /cellphone/confirmBlock - SEC: true | FRAUD: false Path sample: /cellphone/confirmBlock.* - SEC: true | FRAUD: false Path sample: /cellphone/confirmBlock/ - SEC: true | FRAUD: false Path sample: /user/update - SEC: true | FRAUD: false Path sample: /user/update.* - SEC: true | FRAUD: false Path sample: /user/update/ - SEC: true | FRAUD: false Path sample: /user/index - SEC: true | FRAUD: true Path sample: /user/index.* - SEC: true | FRAUD: true Path sample: /user/index/ - SEC: true | FRAUD: true Path sample: /search - SEC: true | FRAUD: true Path sample: /search.* - SEC: true | FRAUD: true Path sample: /search/ - SEC: true | FRAUD: true Path sample: /doSearch - SEC: true | FRAUD: true Path sample: /doSearch.* - SEC: true | FRAUD: true Path sample: /doSearch/ - SEC: true | FRAUD: true Tests Scenario 1 Bellow, the important part of spring-security.xml: <security:http entry-point-ref="entryPoint" request-matcher="regex"> <security:intercept-url pattern="^.*$" access="ROLE_SEC" /> <security:intercept-url pattern="^(?!.*(?i)(block|update)).*$" access="ROLE_FRAUD" /> <security:access-denied-handler error-page="/access-denied.html" /> <security:form-login always-use-default-target="false" login-processing-url="/doLogin.html" authentication-failure-handler-ref="authFailHandler" authentication-success-handler-ref="authSuccessHandler" /> <security:logout logout-url="/logout.html" success-handler-ref="logoutSuccessHandler" /> </security:http> Behaviour: FRAUD group **can't" access any page SEC group works fine Scenario 2 NOTE that I only changed the order of intercept-url in spring-security.xml bellow: <security:http entry-point-ref="entryPoint" request-matcher="regex"> <security:intercept-url pattern="^(?!.*(?i)(block|update)).*$" access="ROLE_FRAUD" /> <security:intercept-url pattern="^.*$" access="ROLE_SEC" /> <security:access-denied-handler error-page="/access-denied.html" /> <security:form-login always-use-default-target="false" login-processing-url="/doLogin.html" authentication-failure-handler-ref="authFailHandler" authentication-success-handler-ref="authSuccessHandler" /> <security:logout logout-url="/logout.html" success-handler-ref="logoutSuccessHandler" /> </security:http> Behaviour: SEC group **can't" access any page FRAUD group works fine Conclusion I did something wrong or spring-security have a bug. The problem already was solved in a very bad way, but I need to fix it quickly. Anyone knows some tricks to debug better it without open the frameworks code? Cheers, Felipe

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  • jQuery Youtube URL Validation with regex

    - by Mithun
    I know there is plenty of question answered over here http://stackoverflow.com/questions/tagged/youtube+regex, but not able find a question similar to me. Any body has the JavaScript Regular expression for validating the YouTube VIDEO URL's line below listed. Just want to know where such a URL can be possible http://www.youtube.com/watch?v=bQVoAWSP7k4 http://www.youtube.com/watch?v=bQVoAWSP7k4&feature=popular http://www.youtube.com/watch?v=McNqjYiFmyQ&feature=related&bhablah http://youtube.com/watch?v=bQVoAWSP7k4

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  • Regex: Comma delimited integers

    - by Metju
    Hi Guys, I'm trying to create a regex that accept: An empty string, a single integer or multiple integers separated by a comma but can have no starting and ending comma. I managed to find this, but I cannot undertsand how to remove the digit limit ^\d{1,10}([,]\d{10})*$

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  • Python 3: regex to split on successions of newline characters

    - by Beau Martínez
    I'm trying to split a string on newline characters (catering for Windows, OS X, and Unix text file newline characters). If there are any succession of these, I want to split on that too and not include any in the result. So, for when splitting the following: "Foo\r\n\r\nDouble Windows\r\rDouble OS X\n\nDouble Unix\r\nWindows\rOS X\nUnix" The result would be: ['Foo', 'Double Windows', 'Double OS X', 'Double Unix', 'Windows', 'OS X', 'Unix'] What regex should I use?

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  • Regex Replace Between Quotations

    - by Kyle Rozendo
    Hi All, I am wondering on where to begin to perform the following replace in regex: Read file (.cs file) Replace anything between quotations ("e.g:") with its uppercase version ("E.G:") By example: string m = "stringishere"; Becomes string m = "STRINGISHERE"; Thanks in advance, Kyle

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  • C# string "search and replace" using a regex

    - by rsturim
    I need to do a 2 rule "replace" -- my rules are, replace all open parens, "(" with a hyphen "-" and strip out all closing parens ")". So for example this: "foobar(baz2)" would become "foobar-baz2" I currently do it like this -- but, my hunch regex would be cleaner. myString.Replace("(", "-").Replace(")", "");

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  • Escaping '“' with regular double quotes using Ruby regex

    - by DavidP6
    I have text that has these fancy double quotes: '“' and I would like to replace them with regular double quotes using Ruby gsub and regex. Here's an example and what I have so far: sentence = 'This is a quote, “Hey guys!”' I couldn't figure out how to escape double quotes so I tried using 34.chr: sentence.gsub("“",34.chr). This gets me close but leaves a back slash in front of the double quote: sentence.gsub("“",34.chr) => 'This is a quote, \"Hey guys!”'

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  • jQuery regex over multiple lines

    - by Fuxi
    I have the following string: <img alt="over 40 world famous brandedWATCHES BRANDs to choose from " src="http://www.fastblings.com/images/logo.jpg"></strong></a><br> I want to define a regex pattern like <img alt="(.+?)" src="http://(.+?).(jpg|gif)">, but as you can see the target string has a linebreak in the alt attribute - so how can i incorporate this? the rule should be like "anything in the alt-attribute including linebreaks".

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  • Regex to Match White Space or End of String

    - by Kirk
    I'm trying to find every instance of @username in comment text and replace it with a link. Here's my PHP so far: $comment = preg_replace('/@(.+?)\s/', '<a href="/users/${1}/">@${1}</a> ', $comment); The only problem is the regex is dependent upon there being whitespace after the @username reference. Can anyone help me tweak this so it will also match if it is at the end of the string?

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  • Codeigniter Routes regex

    - by esryl
    want to route all underscored urls to the dashed equivalent. what would be the codeigniter route regex. url /controller-name/method-name-which-is-long/ would speak to /controller_name/method_name_which_is_long/ see: http://codeigniter.com/forums/viewreply/696690/ which gave me the idea to ask :)

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  • Regex not operator

    - by Erik Goens
    I need to use a regex to pull a value out a url domain that will exclude everything but the host (ex: wordpress) and domain type (ex .com). The urls are dynamic and contain 2-3 values for each result (www.example.com or example.org). I am trying to use this expression, but I am only getting back the first letter of every item I am attempting to exclude: Expresssion (?!wordpress|com|www)(\w+|\d+) String example.wordpress.com Results example ordpress om Desired Result example Any assistance would be greatly appreciated

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  • visual studio Regex Find/Replace error

    - by rockinthesixstring
    I'm working on using Find/Replace to change a bunch of labels to DataBound text. Here's my regex <asp:Label ID="lbl{\d*}" runat="server" /> Here's my replace <%# Eval("\1")%> Here's my Error Unknown argument for ':' operator. Complete Regular Expression required in the search string. How would I resolve this?

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  • Regex negative match query

    - by Matt
    Hey guys, I've got a regex issue, Im trying to ignore just the number '41', I want 4, 1, 14 etc to all match. I've got this [^\b41\b] which is effectively what I want but this also ignores all single iterations of the values 1 and 4. As an example, this matches "41", but I want it to NOT match: \b41\b

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  • Python Regex To VB.net

    - by user316758
    Hi everyone, I made a program in Python and now I whant to transfert it to vb.net. But I have some difficulties with the vb.net regular expression.... Someone can help me please? There are my Python regex: id = re.search('(?<=watch\?v\=)[\w|-]+|(?<=/v/)[\w|-]+', src) id = id.group(0) t = re.search('(?<=\&t\=)[\w|-]+', src) t = t.group() It's supposed to fin the value of ?v=Value&SomeOtherContent and &t=Value&SomeOtherContent Thank you

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  • Regarding parser DOM and REGEX

    - by giri
    Hi I am writing an application in java I need to fetch specific data from website.I do not know which one to use whether REGEX or Parser.Can anybody please advise me how to get this done? and which one is prefered. Thanks

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  • Regex to parse youtube yid

    - by novaurora
    Example URLs http://www.youtube.com/user/Scobleizer#p/u/1/1p3vcRhsYGo http://www.youtube.com/watch?v=cKZDdG9FTKY&feature=channel http://www.youtube.com/watch?v=yZ-K7nCVnBI&playnext_from=TL&videos=osPknwzXEas&feature=sub Any regex that will pull the correct YID from all 3 of these use cases? The first case is especially odd. Thank you.

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