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  • Linq, how to specify timestamp condition?

    - by 5YrsLaterDBA
    I have a logins table which records all login and logout activities. I want to look at all login activities of a particular user within 24 hrs. how to do it? something like this: var records = from record in db.Logins where record.Users.UserId == userId && record.Timestamp <= (DateTime.Now + 24) select record; record.Timestamp <= (DateTime.Now + 24) is wrong here. I am using C# 3 + L2E.

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  • Django message framework and login_required

    - by Brandon
    I'm using the Django Message Framework to show messages to users as well as the @login_required decorator on one of my views. So if a user tries to access a certain view without being logged in, they get kicked to the login page. How would I go about adding an error message to the login page saying "In order to do ... you must be logged in". I can't add it in the view like you normally would because the non-logged in user would never get to there.

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  • How to programmatically logout in acegi plugin in Grails?

    - by firnnauriel
    Is there a similar logic for logout using this login code: // login account def autht = new AuthToken(username, password) def authtoken = daoAuthenticationProvider.authenticate(autht) SecurityContextHolder.context.authentication = authtoken I checked LogoutController and this is the only logic for logout: redirect(uri: '/j_spring_security_logout') Any idea? Thanks

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  • extended permission using php sdk

    - by Awais Qarni
    Hello, I am developing a facebook application using php-sdk. i want to take some extended permissions from user of my application. As this is application where user comes after login into facebook, so how can i take extended permission when user visit my page? We cannot place login button in which we can take permissions. now any one can guide me how to take and where to place that code? Thanks in advance. Regards, Awais Qarni

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  • failed to load source for

    - by ohana
    hi, I have a php project which used to work well, yesterday it suddenly failed, from the login page i cannot actually get into the system with the right username/password. i checked it in Firebug, it said: failed to load source for the php file that's supposed to load after login.what could be wrong? anyone have any idea? Thanks.

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  • how to clear the the activity stack in android.

    - by Sam
    Hi, im having following application flow in my android app, Login-Home-screen1-screen2-screen3-screen4- logout In the screen4 i've a log out button,which allow user to logout from the application and re login.when i re-logn to the app previous data still be shown,is there way to start the application in fresh when user log out from the app NOTE: all the above activities launch mode set to "single task", regards, Sam.

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  • Using @Secured Annotation causes IS_FULLY_AUTHENTICATED problem in grails

    - by TripWired
    I'm using Acegi/Spring Security in grails and when i use the annotations like @Secured(['ROLE_ADMIN']) it denies my login even though the user is part of ROLE_ADMIN. In looking through the login is it seems that it's getting an IS_AUTHENTICATED_FULLY role also but I have never added that to a page so i'm not sure how to bypass that. I read somewhere to preauthorize the user, but i'm not sure how to do that with grails.

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  • PHP: Check if URL redirects?

    - by Industrial
    Hi everybody, I have built a secured login backend that controls if a user is logged in or not. If not, the user is redirected to a login page. I would like to make a PHP function that iterates through a number of set url:s (array with url:s) to see if they are redirected or not. How could this be done? Thanks

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  • Changing GORM table name

    - by Matthias Hryniszak
    Hi I'm fighting to get the following mapping working in Grails 1.3.1 and MySQL: class Login { int id String email static mappings = { table 'my_table' id column: "Mgr_id" version: false } } No matter what I do the queries that are being issued refer to "schema.login" table instead of "schema.my_table". This is very frustrating... Can anyone answer why this might not be working?

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  • How to use type: "POST" in jsonp ajax call

    - by MKS
    Hi Guy, I am using JQuery ajax jsonp. I have got below JQuery Code: $.ajax({ type:"GET", url: "Login.aspx", // Send the login info to this page data: str, dataType: "jsonp", timeout: 200000, jsonp:"skywardDetails", success: function(result) { // Show 'Submit' Button $('#loginButton').show(); // Hide Gif Spinning Rotator $('#ajaxloading').hide(); } }); The above code is working fine, I just want to send the request as "POST" instead of "GET", Please suggest how can I achieve this. Thanks

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  • Error creating new user by Admin

    - by rahul
    I am creating a web application using Form Authentication of Asp.Net with C# and back end Sql Server. Here in my application administrator login and creates new users. I am using the create user wizard under login controls. My problem is when the new user is created by Admin he is automatically logged out and logged in with new user credentials which he has just created. Any help would be highly appreciated.

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  • Cross-site request forgery protections: Where do I put all these lines?

    - by brilliant
    Hello, I was looking for a python code that would be able to log in from "Google App Engine" to some of my accounts on some websites (like yahoo or eBay) and was given this code: import urllib, urllib2, cookielib url = "https://login.yahoo.com/config/login?" form_data = {'login' : 'my-login-here', 'passwd' : 'my-password-here'} jar = cookielib.CookieJar() opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(jar)) form_data = urllib.urlencode(form_data) # data returned from this pages contains redirection resp = opener.open(url, form_data) # yahoo redirects to http://my.yahoo.com, so lets go there instead resp = opener.open('http://mail.yahoo.com') print resp.read() Unfortunately, this code didn't work, so I asked another question here and one supporter among other things said this: "You send MD5 hash and not plain password. Also you'd have to play along with all kinds of CSRF protections etc. that they're implementing. Look: <input type="hidden" name=".tries" value="1"> <input type="hidden" name=".src" value="ym"> <input type="hidden" name=".md5" value=""> <input type="hidden" name=".hash" value=""> <input type="hidden" name=".js" value=""> <input type="hidden" name=".last" value=""> <input type="hidden" name="promo" value=""> <input type="hidden" name=".intl" value="us"> <input type="hidden" name=".bypass" value=""> <input type="hidden" name=".partner" value=""> <input type="hidden" name=".u" value="bd5tdpd5rf2pg"> <input type="hidden" name=".v" value="0"> <input type="hidden" name=".challenge" value="5qUiIPGVFzRZ2BHhvtdGXoehfiOj"> <input type="hidden" name=".yplus" value=""> <input type="hidden" name=".emailCode" value=""> <input type="hidden" name="pkg" value=""> <input type="hidden" name="stepid" value=""> <input type="hidden" name=".ev" value=""> <input type="hidden" name="hasMsgr" value="0"> <input type="hidden" name=".chkP" value="Y"> <input type="hidden" name=".done" value="http://mail.yahoo.com"> <input type="hidden" name=".pd" value="ym_ver=0&c=&ivt=&sg="> I am not quite sure where he got all these lines from and where in my code I am supposed to add them. Do You have any idea? I know I was supposed to ask him this question first, and I did, but he never returned, so I decided to ask a separate question here.

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  • Right way to access the Google Cloud Storage bucket via Public API

    - by SyBer
    I'm trying the following request to access the bucket by using curl, via the public API: curl -X POST -H 'Content-Type: image/jpeg' -d @xxx.jpeg 'https://www.googleapis.com/upload/storage/v1/b/clips.eyecam.com/o?uploadType=media&name=x.jpeg&key=XXX' With XXX being the generated key in the Public API. However I'm getting an authorization failure: { "error": { "errors": [ { "domain": "global", "reason": "required", "message": "Login Required", "locationType": "header", "location": "Authorization" } ], "code": 401, "message": "Login Required" } } Seems the request is incorrect and does not pass the authorization key, any idea what would be the right form of the request?

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  • How do I make a page aware that the viewer is logged in or not?

    - by Joann
    I am building a membership site... I just got thru the login page and I can now login and logout. However that alone doesn't protect all my pages in the root.. How do I go about this? I'd like to set it up like so when the viewer isn't log-in, the page that's being opened would say "Log in first blah3x"... Any help pls??? :-(

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  • How to you password protect a page with Wicket?

    - by Kane
    I want to password protect a webpage in Wicket so the user may only access it if he/she has logged in. I'd also like the page to show the login page, and then after logging in the original page the user was trying to get to. How is this done with wicket? I've already created a login page and extended the session class.

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  • PHP MySQL Zend-ACL - Find all inherited items (Children / Parents)

    - by Scoobler
    I have one MySQL DB table like the following, the resources table: id | name | type 1 | guest | user 2 | member | user 3 | moderator | user 4 | owner | user 5 | admin | user 6 | index | controller Onto the next table, the rules table: id | user_id | rule | resource_id | extras 1 | 2 | 3 | 1 | null 2 | 3 | 3 | 2 | null 3 | 4 | 3 | 3 | null 4 | 5 | 3 | 4 | null 5 | 6 | 1 | 1 | index,login,register 6 | 6 | 2 | 2 | login,register 7 | 6 | 1 | 2 | logout OK, sorry for the length, but I am trying to give a full picture of what I am trying to do. So the way it works, a role (aka user) can be granted (rule: 1) access to a controller, a role can inherit (rule: 3) access from another role or a role and be denied (rule: 2) access to a controller. (A user is a resource and a controller is a resource) Access to actions are granted / denied using the extras column. This all works, its not a problem with setting up the ACL within zend. What I am now trying to do is show the relationships; to do that I need to find the lowest level a role is granted access to a controller stopping if it has explicitly been removed. I plan on listing the roles. When I click a role, I want it to show all the controllers that role has access to. Then clicking on a controller shows the actions the role is allowed to do. So in the example above, a guest is allowed to view the index action of the index controller along with the login action. A member inherits the same access, but is then denied access to the login action and register action. A moderator inherits the rules of a member. So if I were to select the role moderator. I want to see the controller index listed. If I click on the controller, it should show the allowed actions as being action: index. (which was originally granted to the guest, but hasn't since been dissallowed) Is there any examples to doing this. I am obviously working with the Zend MVC (PHP) and MySQL. Even just a persudo code example would be a helpful starting point - this is one of the last parts of the jigsaw I am putting together. P.S. Obviously I have the ACL object - is it going to be easier to interigate that or is it better to do it my self via PHP/MySQL? The aim will be, show what a role can access which will then allow me to add or edit a role, controller and action in a GUI style (that is somewhat the easy bit) - currently I am updating the DB manually as I have been building the site.

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  • how to connect j2me application with gtalk

    - by Rishabh
    Hi, I have created a login page on mobile. after login with google username and password, i want connect it with g-talk. I need to see my all gtalk contacts on mobile application. How I authenticate and get contacts here, Is there any web service url for user authentication ? Please help me!

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  • ASP.NET: Using Session to store authentication?

    - by Niels Bosma
    I'm having a lot of problems with FormsAuthentication (http://stackoverflow.com/questions/2964342/problem-with-asp-net-authentication) and as as potential work around I'm thinking about storing the login in the Session? Login: Session["Auth.ClientId"] = clientId; IsAuthenticated: Session["Auth.ClientId"] != null; Logout; Session["Auth.ClientId"] == null; I'm not really using most of the bells and whistles of FormsAuthentication anyway. Is this a bad idea?

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  • Tomcat does not persist Session during restart

    - by mabuzer
    How to force Tomcat to serialize Session so that the user is kept logged in when Tomcat has restarted? Right now the user has to login again everytime. Added the following lines into web-app context.xml: <Manager className="org.apache.catalina.session.PersistentManager"> <Store className="org.apache.catalina.session.FileStore"/> </Manager> but still I see login page after Tomcat restart, I use Tomcat 6.0.24

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  • OpenID authentication error

    - by Raindog
    When I try to login to this site using my yahoo openid, it takes me to the yahoo site, I click "continue" meaning that i want to send my authentication details to stackoverflow.com and stackoverflow.com gives me the following error underneath the login text field: Unable to log in with your OpenID provider: failed to authenticate, returning Failed. Please ensure your identifier is correct and try again.

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  • How to display the output of command which run in machine Y.and program is written in machine X?

    - by Rahul
    *I have two Linux Machine,1st is machine X ,other is machine Y i want to write a java program which will run in machine X..eq test.java ..and when i run that java program it should ask for login credential of machine Y and will execute some command for example ls -l in machine Y automatically after login. and it should display the output of ls -l in machine X. How to do it please help me????*

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