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  • Values are not returning from MY SQL database to my java class

    - by sam
    Hi, This is my Query DELIMITER $$ DROP PROCEDURE IF EXISTSdiscoverdb.getuser_info$$ # MySQL returned an empty result set (i.e. zero rows). `CREATE PROCEDURE discoverdb.getuser_info ( IN name VARCHAR(100), IN pass VARCHAR(100) ) BEGIN SELECT * FROM ad_user WHERE sLogin = name AND sPassHash=password(pass); END $$ # MySQL returned an empty result set (i.e. zero rows). DELIMITER ; This is my calling method public Authentication getAuthentication (String username,String password) { //TODO write your implementation code here: Authentication ack = new Authentication(); try{ String simpleProc = "{ call getuser_infosam(?,?)}"; java.sql.CallableStatement cs = con.prepareCall(simpleProc); cs.setString(1, username); cs.setString(2, password); java.sql.ResultSet rs = cs.executeQuery(); while (rs.next()) { System.out.println(rs.getString("sLogin")); System.out.println(rs.getString("sPassHash")); System.out.println(rs.getString("sForename")); System.out.println(rs.getString("sName")); System.out.println(rs.getString("company")); System.out.println(rs.getString("sEmail")); rs.close();} }catch ( Exception e) { e.printStackTrace(); System.out.print(e); } return ack; }

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  • how to automate the testing of a text based menu

    - by Reagan Penner
    Hi there, I have a text based menu running on a remote Linux host. I am using expect to ssh into this host and would like to figure out how to interact with the menus. Interaction involves arrowing up, down and using the enter and back arrow keys. For example, Disconnect Data Collection > Utilities > Save Changes When you enter the system Disconnect is highlighted. So simply pressing enter twice you can disconnect from the system. Second enter confirms the disconnect. The following code will ssh into my system and bring up the menu. If I remove the expect eof and try to send "\r" thinking that this would select the Disconnect menu option I get the following error: "write() failed to write anything - will sleep(1) and retry..." #!/usr/bin/expect set env(TERM) vt100 set password abc123 set ipaddr 162.116.11.100 set timeout -1 match_max -d 100000 spawn ssh root@$ipaddr exp_internal 1 expect "*password:*" send -- "$password\r" expect "Last login: *\r" expect eof I have looked at the virterm and term_expect examples but cannot figure out how to tweak them to work for me. If someone can point me in the right direction I would greatly appreciate it. What I need to know is can I interact with a text based menu system and what is the correct method for doing this, examples if any exist would be great. thanks, -reagan

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  • authentication question (security code generation logic)

    - by Stick it to THE MAN
    I have a security number generator device, small enough to go on a key-ring, which has a six digit LCD display and a button. After I have entered my account name and password on an online form, I press the button on the security device and enter the security code number which is displayed. I get a different number every time I press the button and the number generator has a serial number on the back which I had to input during the account set-up procedure. I would like to incorporate similar functionality in my website. As far as I understand, these are the main components: Generate a unique N digit aplha-numeric sequence during registration and assign to user (permanently) Allow user to generate an N (or M?) digit aplha-numeric sequence remotely For now, I dont care about the hardware side, I am only interested in knowing how I may choose a suitable algorithm that will allow the user to generate an N (or M?) long aplha-numeric sequence - presumably, using his unique ID as a seed Identify the user from the number generated in step 2 (which decryption method is the most robust to do this?) I have the following questions: Have I identified all the steps required in such an authentication system?, if not please point out what I have missed and why it is important What are the most robust encryption/decryption algorithms I can use for steps 1 through 3 (preferably using 64bits)?

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  • Rails 4, not saving @user.save when registering new user

    - by Yuichi
    When I try to register an user, it does not give me any error but just cannot save the user. I don't have attr_accessible. I'm not sure what I am missing. Please help me. user.rb class User < ActiveRecord::Base has_secure_password validates :email, presence: true, uniqueness: true, format: { with: /\A([^@\s]+)@((?:[-a-z0-9]+\.)+[a-z]{2,})\Z/i } validates :password, presence: true, length: {minimum: 6} validates :nickname, presence: true, uniqueness: true end users_controller.rb class UsersController < ApplicationController def new @user = User.new end def create @user = User.new(user_params) # Not saving @user ... if @user.save flash[:success] = "Successfully registered" redirect_to videos_path else flash[:error] = "Cannot create an user, check the input and try again" render :new end end private def user_params params.require(:user).permit(:email, :password, :nickname) end end Log: Processing by UsersController#create as HTML Parameters: {"utf8"=>"?", "authenticity_token"=>"x5OqMgarqMFj17dVSuA8tVueg1dncS3YtkCfMzMpOUE=", "user"=>{"email"=>"[email protected]", "password"=>"[FILTERED]", "nickname"=>"example"}, "commit"=>"Register"} (0.1ms) begin transaction User Exists (0.2ms) SELECT 1 AS one FROM "users" WHERE "users"."email" = '[email protected]' LIMIT 1 User Exists (0.1ms) SELECT 1 AS one FROM "users" WHERE "users"."nickname" = 'example' LIMIT 1 (0.1ms) rollback transaction

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  • MSSQL in ASP.NET application getting unstable after a certain period

    - by Barslett
    Hello, I have an ASP.NET 2.0 application that I made to keep track of disruption reports about our public transport system. The architecture is pretty straight-forward; an MSSQL Express 2008 database, ADO.NET and a DataSet/DAL with a few methods to access the database. There is a set of .aspx pages for the UI in use by our dispatchers and on our public website, as well as a set of SOAP and REST webservices and an RSS feed. Everything worked just fine for more than a year, until two weeks ago. Now and then, it seems as the database enters an unstable mode, and the application starts responding something right, something wrong. The typical error is that apparently, an empty DataTable is returned to the public disruption overview or to the RSS generator. Thus, the user gets e.g. an empty GridView, but no exception is thrown AFAIK, and nothing is written to the Windows Application log. After a restart of the MSSQL Express service, the situation is back to normal. It has to be said that the situation first time appeared a few days after I made a new minor upgrade of the application. The RSS generator was slightly rewritten, and I added a WCF REST service. But the DAL and the database schema were untouched... Any hints of how we could keep the database stable? It is a bit annoying not to have a clue ;-)

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  • ajax login problem

    - by rdanee
    $(document).ready(function() { $("form#login_form").submit(function() { var login_username = $('#login_username').attr('value'); var login_password = $('#login_password').attr('value'); type: "POST", $.ajax({ url: "login.php", data: "username="+ login_username +"& password="+ login_password, success: function(data){ alert(data); if (data == "ok"){ $('form#login_form').hide(function(){$('div.success').fadeIn();}); } } }); return false; }); Login.php: <?php include("settings.php"); $query = "select * from users where username = '{$_POST['login_username']}' and password = md5('{$_POST['login_password']}')"; $query = mysql_query($query, $connection); if ( mysql_num_rows($query) == 1 ) { print "ok"; $array = mysql_fetch_array($query); if ( $_POST['stay'] ) { $time = time()+2592000; } else { $time = 0; } } else { print "no"; } mysql_close($connection); ?> My problem: In the alert the message always "no" whether username/password is correct, however on the site "ok" appears when username/pw is correct. I have read the other questions in connection with this problem, but I couldn't solve the response problem from login.php with Json. Could you help me how should I response to the ajax calling? ( with a code if it is possible) Thank you very much, and sorry for questioning again.

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  • How to implement a Client-side Ajax Login on Asp.Net MVC (A link to the solution for Asp.Net Webform

    - by Matt
    Hi, I'm trying to implement a client-side ajax login on Asp.Net MVC. I used to have this set up just fine on WebForms, but now that I've moved to MVC it's giving me some troubles. If you'd like a tutorial on Client-side Ajax Login for Asp.Net Webforms, it can be found here -- Easy, A++ Now... for some reason it's not working for Asp.Net MVC. I used the exact same tutorial as for the Webforms, except when it executes the ssa.login() (equivalently: Sys.Services.AuthenticationService.login()) it's not doing anything. I have alerts in both the onLoginComplete() function and the onError() function. As well I have an alert before the ssa.login gets called and right after... function loginHandler() { var username = $("#login_UserName").val(); var password = $("#login_Password").val(); var isPersistent = $("#login_RememberMe").attr("checked"); var customInfo = null; var redirectUrl = null; // Log them in. alert("try login"); ssa.login(username, password, isPersistent, customInfo, redirectUrl, onLoginComplete, onError); alert("made it here"); } The first alert fires but the second one doesn't which means the function is failing. Here's the function I pulled from Asp.Net Ajax to show you: function(c, b, a, h, f, d, e, g) { this._invoke(this._get_path(), "Login", false, { userName: c, password: b, createPersistentCookie: a }, Function.createDelegate(this, this._onLoginComplete), Function.createDelegate(this, this._onLoginFailed), [c, b, a, h, f, d, e, g]); } Anyone have any idea of why it's failing?

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  • Getting 404 page not found connecting to webDAV

    - by Cragly
    I am trying to connect to a secure webDAV folder and download a file. I am having problems just trying to get a response from the server and as it keeps giving me a 404 page not found error as soon as I call Request.GetResponse(). I can connect to the webDAV folder using Windows Explorer by mapping a drive but cannot seem to do this in code. I have looked at other post on this site and others online but most seem to concentrate on connecting to Outlook. Has anybody else had this issue? The code I am using is as follows: string URI = "https://transfer.mycompany.com/myDirectory/myFile.csv"; string username = "username"; string password = "password"; Request = (HttpWebRequest) WebRequest.Create(URI); Request.Credentials = new NetworkCredential(username, password); Request.Method = WebRequestMethods.Http.Get; Request.Headers.Add("Translate", "f"); Response = (HttpWebResponse) Request.GetResponse(); contentLength = Convert.ToInt64(Response.GetResponseHeader("Content-Length"));

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  • POSTmethod and PHP- login verification

    - by Neethusha
    I wrote a code for login verification..I got output with GET. But i need output with POST since it is more secure.pls let me know if there is any error in my code. javascript code: var xml; function verifyusernamepasswd(pass) { //pass is password that will be passed as parameter xml=new XMLHttpRequest(); var url="http://localhost/loginvalidate.php"; var para="q="+username+"&p="+pass;//username is global xml.setRequestHeader("Content-type", "application/x-www-form-urlencoded"); xml.setRequestHeader("Content-length", para.length); xml.setRequestHeader("Connection", "close"); xml.open("POST",url,true); xml.onreadystatechange=statechanged1; xml.send(para); } function statechanged1() { if(xml.readyState==4) alert(xml.responseText); } php code: <?php $username=$_POST["q"]; $password=$_POST["p"]; $con=mysql_connect("localhost","root","blaze"); if(!$con) { die('Could not connect: '.mysql.error()); } mysql_select_db("BLAZE",$con) or die("No such Db"); $result=mysql_query("SELECT Passwword FROM USERTABLE WHERE Userhandle='$username'"); if($result==null) echo "false"; else if($result!=null) { $row=mysql_fetch_array($result); if((strcmp($row['Passwword'],$password)==0)) echo "true"; else echo "false"; } ?> the verification does not return anything, cos my alert is not displayed at all...pls tell me whats wrong....

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  • Parameters lost on login form submitted with post in JBoss

    - by Supowski
    My login page contains two forms: one for logging in and one for signing up. Shorten like this: <form name="LoginForm" id="LoginForm" method="post" action="j_security_check" > <input type="text" name="j_username" /> <input type="text" name="j_password" /> <input type="submit" value="Sing In" /> <form> <form name="SignUpForm" id="SignUpForm" method="post" action="/homepage" > <input type="text" name="loginName" /> <input type="password" name="password1" /> <input type="password" name="password2" /> <input type="submit" value="Sing Up" /> <form> I If 'Sing Up', than values of input are lost during processing and not passed into my Servlet. It works fine with GET, but than there is password in URL, so it's not the right solution :) Similar problem has been posted to community.jboss.org, but with no response: http://community.jboss.org/message/7150#7150. I'm using JBoss 4.3eap. Any help?

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  • populate checkboxes with database.

    - by amby
    Hi, I have to poulate checkboxes with data coming from database but no checkbox is showing on my page. please give me correct way to do that. in C# file page_load method i m doing this: public partial class dbTest1 : System.Web.UI.Page { protected void Page_Load(object sender, EventArgs e) { string Server = "al2222"; string Username = "hshshshsh"; string Password = "sjjssjs"; string Database = "database1"; string ConnectionString = "Data Source=" + Server + ";"; ConnectionString += "User ID=" + Username + ";"; ConnectionString += "Password=" + Password + ";"; ConnectionString += "Initial Catalog=" + Database; string query = "Select * from Customer_Order where orderNumber = 17"; using (SqlConnection conn = new SqlConnection(ConnectionString)) { using (SqlCommand cmd = new SqlCommand(query, conn)) { conn.Open(); SqlDataReader dr = cmd.ExecuteReader(); while (dr.Read()) { if (!IsPostBack) { Interests.DataSource = dr; Interests.DataTextField = "OptionName"; Interests.DataValueField = "OptionName"; Interests.DataBind(); } } conn.Close(); conn.Dispose(); } } } } and in .aspx using this: <asp:CheckBoxList ID="Interests" runat="server"></asp:CheckBoxList> please tell me correct way to do that.

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  • advanced winform framework

    - by alfredo dobrekk
    Hi, i m starting a new project that would basically take input from user and save them to database among about 30 screens, and i would like to find a framework that will allow the maximum number of these features out of the box : .net c#. windows form. unit testing continuous integration screens with lists, combo boxes, text boxes, add, delete, save, cancel that are easy to update when you add a property to your classes or a field to your database. auto completion on controls to help user find its way use of an orm like nhibernate easy multithreading and display of wait screens for user easy undo redo tabbed child windows search forms ability to grant access to some functionnalities according to user profiles mvp/mvvm or whatever design patterns either some code generation from database to c# classe or generation of database schema from c# classes some kind of database versioning / upgrade to easily update database when i release patches to application once in production code metrics analysis some code generator i can use against my entities that would generate some rough form i can rearrange after code documentation generator ... Any ideas ? I know its lot but i really would like to use existing code to build upon so i can focus on business rules. Do u have any suggestion to add to the list before starting ? What open source tools would u use to achieve these ?

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  • (Android) Seems like my JSON query is getting double encode

    - by A Gardner
    Hi, I am getting some weird errors with my Android App. It appears that this code is double encoding the JSON string. What should be sent is ?{"email":"[email protected]","password":"asdf"} or ?%7B%22email%22:%22..... what the server is seeing is %257B%2522email%2522:%2522 .... which means the server sees %7B%22email%22:%22 ..... This confuses the server. Any ideas why this is happening? Thanks for your help Code: DefaultHttpClient c = new DefaultHttpClient(); if(cookies!=null) c.setCookieStore(cookies); if(loginNotLogout){ jso.put("email", userData.email); jso.put("password", userData.password); } URI u = null; if(loginNotLogout) u= new URI("HTTP","www.website.com","/UserService",jso.toString(),""); else u= new URI("HTTP","www.website.com","/UserService",jso.toString(),""); HttpGet httpget = new HttpGet(u); HttpResponse response = c.execute(httpget); ret.jsonString = EntityUtils.toString(response.getEntity());

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  • Comparing all properties of an object using expression trees

    - by stringargs
    Hi, I'm trying to write a simple generator that uses an expression tree to dynamically generate a method that compares all properties of an instance of a type to the properties of another instance of that type. This works fine for most properties, like int an string, but fails for DateTime? (and presumably other nullable value types). The method: static Delegate GenerateComparer(Type type) { var left = Expression.Parameter(type, "left"); var right = Expression.Parameter(type, "right"); Expression result = null; foreach (var p in type.GetProperties()) { var leftProperty = Expression.Property(left, p.Name); var rightProperty = Expression.Property(right, p.Name); var equals = p.PropertyType.GetMethod("Equals", new[] { p.PropertyType }); var callEqualsOnLeft = Expression.Call(leftProperty, equals, rightProperty); result = result != null ? (Expression)Expression.And(result, callEqualsOnLeft) : (Expression)callEqualsOnLeft; } var method = Expression.Lambda(result, left, right).Compile(); return method; } On a DateTime? property it fails with: Expression of type 'System.Nullable`1[System.DateTime]' cannot be used for parameter of type 'System.Object' of method 'Boolean Equals(System.Object)' OK, so it finds an overload of Equals that expects object. So why can't I pass a DateTime? into that, as it's convertible to object? If I look at Nullable<T>, it indeed has an override of Equals(object o). PS: I realize that this isn't a proper generator yet as it can't deal with null values, but I'll get to that :)

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  • PropertyPlaceholderConfigurer vs Filters -- Spring Beans

    - by John
    Hi there. I've got a question regarding the difference between PropertyPlaceholderConfigurer (org.springframework.beans.factory.config.PropertyPlaceholderConfigurer) and normal filters defined in my pom.xml. I've been looking at examples, and it seems that even though filters are defined and marked to be active by default in the pom.xml they still make use of PropertyPlaceholderConfigurer in Spring's applicationContext.xml. This means that the pom.xml has a reference to a filter-LOCAL.properties while applicationContext.xml has a reference to application.properties and they both contain the same settings. Why is that? Is that how it is supposed to be done? I'm able to run the goal mvn jetty:run without the application.properties present, but if I add settings to the application.properties that differ from the filter-LOCAL.properties they don't seem to override. Here's an example of what I mean: pom.xml <profiles <profile <idLOCAL <activation <activeByDefaulttrue </activation <properties <envLOCAL </properties </profile </profiles applicationContext.xml <bean id="propertyConfigurer" class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer" <property name="locations" <list <valueclasspath:application.properties </list </property <property name="ignoreResourceNotFound" value="true"/ </bean <bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close" <property name="driverClassName" value="${jdbc.driver}"/ <property name="url" value="${jdbc.url}"/ <property name="username" value="${jdbc.username}"/ <property name="password" value="${jdbc.password}"/ </bean an example of the content of application.properties and filters-LOCAL.properties jdbc.driver=org.postgresql.Driver jdbc.url=jdbc:postgresql://localhost/shoutbox_dev jdbc.username=tester jdbc.password=tester Can I remove the propertyConfigurer from the applicationContext, create a PROD filter and disregard the application.properties file, or will that give me issues when deploying to the production server?

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  • Multi-Column Join in Hibernate/JPA Annotations

    - by bowsie
    I have two entities which I would like to join through multiple columns. These columns are shared by an @Embeddable object that is shared by both entities. In the example below, Foo can have only one Bar but Bar can have multiple Foos (where AnEmbeddableObject is a unique key for Bar). Here is an example: @Entity @Table(name = "foo") public class Foo { @Id @Column(name = "id") @GeneratedValue(generator = "seqGen") @SequenceGenerator(name = "seqGen", sequenceName = "FOO_ID_SEQ", allocationSize = 1) private Long id; @Embedded private AnEmbeddableObject anEmbeddableObject; @ManyToOne(targetEntity = Bar.class, fetch = FetchType.LAZY) @JoinColumns( { @JoinColumn(name = "column_1", referencedColumnName = "column_1"), @JoinColumn(name = "column_2", referencedColumnName = "column_2"), @JoinColumn(name = "column_3", referencedColumnName = "column_3"), @JoinColumn(name = "column_4", referencedColumnName = "column_4") }) private Bar bar; // ... rest of class } And the Bar class: @Entity @Table(name = "bar") public class Bar { @Id @Column(name = "id") @GeneratedValue(generator = "seqGen") @SequenceGenerator(name = "seqGen", sequenceName = "BAR_ID_SEQ", allocationSize = 1) private Long id; @Embedded private AnEmbeddableObject anEmbeddableObject; // ... rest of class } Finally the AnEmbeddedObject class: @Embeddable public class AnEmbeddedObject { @Column(name = "column_1") private Long column1; @Column(name = "column_2") private Long column2; @Column(name = "column_3") private Long column3; @Column(name = "column_4") private Long column4; // ... rest of class } Obviously the schema is poorly normalised, it is a restriction that AnEmbeddedObject's fields are repeated in each table. The problem I have is that I receive this error when I try to start up Hibernate: org.hibernate.AnnotationException: referencedColumnNames(column_1, column_2, column_3, column_4) of Foo.bar referencing Bar not mapped to a single property I have tried marking the JoinColumns are not insertable and updatable, but with no luck. Is there a way to express this with Hibernate/JPA annotations? Thank you.

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  • ASP.NET MVC Membership, Get new UserID

    - by Vishal Bharakhda
    I am trying to register a new user and also understand how to get the new userID so i can start creating my own user tables with a userID mapping to the asp.net membership user table. Below is my code: [AcceptVerbs(HttpVerbs.Post)] public ActionResult Register(string userName, string email, string position, string password, string confirmPassword) { ViewData["PasswordLength"] = MembershipService.MinPasswordLength; ViewData["position"] = new SelectList(GetDeveloperPositionList()); if (ValidateRegistration(userName, email, position, password, confirmPassword)) { // Attempt to register the user MembershipCreateStatus createStatus = MembershipService.CreateUser(userName, password, email); if (createStatus == MembershipCreateStatus.Success) { FormsAuth.SignIn(userName, false /* createPersistentCookie */); return RedirectToAction("Index", "Home"); } else { ModelState.AddModelError("_FORM", ErrorCodeToString(createStatus)); } } // If we got this far, something failed, redisplay form return View(); } I've done some research and many sites inform me to use Membership.GetUser().ProviderUserKey; but this throws an error as Membership is NULL. I placed this line of code just above "return RedirectToAction("Index", "Home");" within the if statement. Please can someone advise me on this... Thanks in advance

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  • Mapping an instance of IList in NHibernate

    - by Martin Kirsche
    I'm trying to map a parent-child relationship using NHibernate (2.1.2), MySql.Data (6.2.2) and MySQL Server (5.1). I figured out that this must be done using a <bag> in the mapping file. I build a test app which is running without yielding any errors and is doing an insert for each entry but somehow the foreign key inside the children table (ParentId) is always empty (null). Here are the important parts of my code... Parent public class Parent { public virtual int Id { get; set; } public virtual IList<Child> Children { get; set; } } <class name="Parent"> <id name="Id"> <generator class="native"/> </id> <bag name="Children" cascade="all"> <key column="ParentId"/> <one-to-many class="Child"/> </bag> </class> Child public class Child { public virtual int Id { get; set; } } <class name="Child"> <id name="Id"> <generator class="native"/> </id> </class> Program using (ISession session = sessionFactory.OpenSession()) { session.Save( new Parent() { Children = new List<Child>() { new Child(), new Child() } }); } Any ideas what I did wrong?

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  • Ant telnet is hanging on a simple task

    - by Sagar
    <?xml version="1.0" ?> <project name="test" default="root"> <target name="telnet"> <telnet server="10.1.1.1"> <read>login:</read> <write>root</write> <read>password:</read> <write>${PASSWORD}</write> <read>#</read> <write>ls</write> <read>#</read> </telnet> </target> </project> That is the code I have in a build.xml file. When I run ant (version 1.8, in bash) (I have downloaded and copied over the jars for commons-net-2.0 and jakarta-oro-2.0.8 already), this is the output I get: Buildfile: /home/sagar/build.xml telnet: and then it just sits there. When I do a "who" on my server, I can see "System" waiting on login. But there is no progress after this. I can telnet into the server using normal telnet means (putty, bash, etc). I even tried the full telnet command instead of read/write: <telnet server="10.1.1.1" userid="root" password="root"> Any help is much appreciated! Note: JRE 1.5, Ant 1.8, commons-net version 2.0, jakarta version 2.0.8

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  • Php 5 and mysql connecting gives error ...code and error in there check out and plz..plz help....

    - by user309381
    **mysql_query() [function.mysql-query]: Access denied for user 'SYSTEM'@'localhost' (using password: NO) in C:\wamp\www\photo_gallery\includes\database.php on line 56 Warning: mysql_query() [function.mysql-query]: A link to the server could not be established in C:\wamp\www\photo_gallery\includes\database.php on line 56 The Query has problemAccess denied for user 'SYSTEM'@'localhost' (using password: NO) i have set the password for root and grant privilege all for root.Why it soes show like SYSTEM@localhost i dont have SYSTEM .** class MySQLDatabase { public $connection; function _construct() { $this-open_connection(); } public function open_connection() { /* $DB_SERVER = "localhost"; $DB_USER = "root"; $DB_PASS = ""; $DB_NAME = "photo_gallery";*/ $this-connection = mysql_connect($DBSERVER,$DBUSER,$DBPASS); if(!$this-connection) { die("Database Connection Failed" . mysql_error()); } else { $db_select = mysql_select_db($DBNAME,$this-connection); if(!$db_select) { die("Database Selection Failed" . mysql_error()); } } } function mysql_prep($value) { if (get_magic_quotes_gpc()) { $value = stripslashes($value); } // Quote if not a number if (!is_numeric($value)) { $value = "'" . mysql_real_escape_string($value) . "'"; } return $value; } public function close_connection() { if(isset($this->connection)) { mysql_close($this->connection); unset($this->connection); } } public function query($sql) { //$sql = "SELECT*FROM users where id = 1"; $result = mysql_query($sql); $this->confirm_query($result); //$found_user = mysql_fetch_assoc($result); //echo $found_user; return $found_user; } private function confirm_query($result) { if(!$result) { die("The Query has problem" . mysql_error()); } } } $database = new MySQLDatabase(); ?

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  • Sample twitter application

    - by Jack
    I have installed WAMP and running PHP scripts on localhost. I have enabled cURL. Here is my code. <?php function updateTwitter($status) { // Twitter login information $username = 'xxxxx'; $password = 'xxxxx'; // The url of the update function $url = 'http://twitter.com/statuses/update.xml'; // Arguments we are posting to Twitter $postargs = 'status='.urlencode($status); // Will store the response we get from Twitter $responseInfo=array(); // Initialize CURL $ch = curl_init($url); // Tell CURL we are doing a POST curl_setopt($ch, CURLOPT_PROXY,"localhost:80"); curl_setopt ($ch, CURLOPT_POST, true); // Give CURL the arguments in the POST curl_setopt ($ch, CURLOPT_POSTFIELDS, $postargs); // Set the username and password in the CURL call curl_setopt($ch, CURLOPT_USERPWD, $username.':'.$password); // Set some cur flags (not too important) curl_setopt($ch, CURLOPT_VERBOSE, 1); curl_setopt($ch, CURLOPT_NOBODY, 0); curl_setopt($ch, CURLOPT_HEADER, 0); curl_setopt($ch, CURLOPT_FOLLOWLOCATION,1); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); // execute the CURL call $response = curl_exec($ch); if($response === false) { echo 'Curl error: ' . curl_error($ch); } else { echo 'Operation completed without any errors<br/>'; } // Get information about the response $responseInfo=curl_getinfo($ch); // Close the CURL connection curl_close($ch); // Make sure we received a response from Twitter if(intval($responseInfo['http_code'])==200){ // Display the response from Twitter echo $response; }else{ // Something went wrong echo "Error: " . $responseInfo['http_code']; } curl_close($ch); } updateTwitter("Just finished a sweet tutorial on http://brandontreb.com"); ?> Here's my output Operation completed without any errors Error: 404 Here's what error 404 means 404 Not Found: The URI requested is invalid or the resource requested, such as a user, does not exists. Please help.

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  • Doctrine2 - relationship

    - by Filip Golonka
    I'm developing an application, which is looking for optimal route and timetable in public transport. I have some experience about Doctrine1, but it's my first time with Doctrine2. There is soem new fields to describe relations (mappedBy and inversedBy) and also some new ways of mapping. I have following code: $query = $this->em->createQuery("SELECT partial cls.{stop}, partial t.{arriveTime, departureTime} FROM \Entities\Timetable t JOIN t.ride r JOIN t.carrierLineStop cls WHERE t.departureTime>=:time AND r.idCarrierLine=:carrierLine AND (cls.idStop=:firstStop OR cls.idStop=:lastStop)"); $query->setParameters(array( 'time' => $time, 'carrierLine' => $path->getLine(), 'firstStop' => $path->getFirstStop(), 'lastStop' => $path->getLastStop() )); When I try to execute that script I've got an error: [Semantical Error] line 0, col 24 near '}, partial t.{arriveTime,': Error: There is no mapped field named 'stop' on class Entities\CarrierLineStop. Mapping files: Entities\CarrierLineStop: type: entity table: carrier_line_stop fields: idCarrierLineStop: id: true type: integer unsigned: false nullable: false column: id_carrier_line_stop generator: strategy: IDENTITY nextStop: type: integer unsigned: false nullable: true column: next_stop manyToOne: idCarrierLine: targetEntity: Entities\CarrierLine cascade: { } mappedBy: null inversedBy: null joinColumns: id_carrier_line: referencedColumnName: id_carrier_line orphanRemoval: false stop: column: id_stop targetEntity: Entities\Stop cascade: { } mappedBy: null inversedBy: carrierLineStop joinColumns: id_stop: referencedColumnName: id_stop orphanRemoval: false lifecycleCallbacks: { } - Entities\Stop: type: entity table: stop fields: idStop: id: true type: integer unsigned: false nullable: false column: id_stop generator: strategy: IDENTITY name: type: string length: 45 fixed: false nullable: true miejscowosc: type: string length: 45 fixed: false nullable: true latitude: type: decimal nullable: true longitude: type: decimal nullable: true oneToMany: carrierLineStop: targetEntity: Entities\CarrierLineStop cascade: { } mappedBy: stop inversedBy: null joinColumns: id_stop: referencedColumnName: id_stop orphanRemoval: false lifecycleCallbacks: { } I have no idea about where the problem is...

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  • Can't use my form

    - by Alexandr
    I have class with my form in folder /application/forms/Auth.php it looks like class Form_Auth extends Zend_Form { public function __construct() { $this->setName(); parent::__construct(); $username = new Zend_Form_Element_Text('username'); $password = new Zend_Form_Element_Password('password'); $mail = new Zend_Form_Element_Text('mail'); $submit = new Zend_Form_Element_Submit('submit'); $this->addElements(array($username,$password,$mail,$submit)); } } When i try create object $this->view->form = new Form_Auth(); is see exeption Application error Exception information: Message: Invalid name provided; must contain only valid variable characters and be non-empty Stack trace: D:\WWW\zends\application\Forms\Auth.php(8): Zend_Form-setName() d:\WWW\zends\application\controllers\RegistrationController.php(49): Form_Auth-__construct() D:\WebServer\ZendFramework\ZendFramework\library\Zend\Controller\Action.php(513): RegistrationController-indexAction() D:\WebServer\ZendFramework\ZendFramework\library\Zend\Controller\Dispatcher\Standard.php(289): Zend_Controller_Action-dispatch('indexAction') D:\WebServer\ZendFramework\ZendFramework\library\Zend\Controller\Front.php(954): Zend_Controller_Dispatcher_Standard-dispatch(Object(Zend_Controller_Request_Http), Object(Zend_Controller_Response_Http)) D:\WebServer\ZendFramework\ZendFramework\library\Zend\Application\Bootstrap\Bootstrap.php(97): Zend_Controller_Front-dispatch() D:\WebServer\ZendFramework\ZendFramework\library\Zend\Application.php(366): Zend_Application_Bootstrap_Bootstrap-run() D:\WWW\zends\public\index.php(26): Zend_Application-run() {main} Request Parameters: array ( 'controller' = 'registration', 'action' = 'index', 'module' = 'default', ) the version zf is 1.10.3 what i do wrong ?

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  • Integrate OpenId into an existing site

    - by Andrea
    I have a working web application which already has a login and registration system. I'm looking for some advice on how to do it. Until now, users have a username, an email, a password and some optional fields. The registrartion is the usual process with email confirmation. Now I'd like to allow users to use OpenId. So I have added an openid field to the table. There are two different login forms, and users which are already registered can add their openid info and use either login form. The problem is with new users who come on the site for the first time and try to login with OpenId. I create a new user for them, and I don't need a password, but still I need at least a username, which is used on the site (I'm not sure if the email is needed). So my problems are: 1) How do I manage validation? Some fields are required for some users, (e.g. a password) but not for some others. I mean, I can do this, but it immediately gets messy. 2) Should I ask for a username and email on the first OpenId login? On the one hand I'd say yes, but I fear this vanishes the advantages of using OpenId, that is, not having to provide details. 3) I could get the details via SReg or AttributeExchange, but most providers have a bad support for those. For instance my Gmail OpenId account does not tell the email (!). Is there some place to learn more about the current support for these extensions?

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  • Vertically Aligning Divs

    - by Crays
    Hi, i'm trying to make a small username and password input box. I would like to ask how do you vertically align a div? What i have is a <div id="Login" class="BlackStrip floatright"> <div id="Username" class="floatleft">Username<br>Password</div> <div id="Form" class="floatleft"> <form action="" method="post"> <input type="text" border="0"><br> <input type="password" border="0"> </form> </div> </div> and how can i make the div with id Username and Form to vertically align itself to the center? I tried putting vertical-align: middle; in css for the div with id Login. But doesn't seem to work. Any help would be appreciated. Thanks.

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