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  • jquery find() function not working on ie. (ie 8) not tested on others

    - by Val
    I have a tiny problem: I am trying to use the find function to get data from an external page. here is the code can some one please help me why doesnt it work on ie? index.php <div id="testing">Hello Worlds</div> jquery var txt=$('<div id="Temp"></div>').hide().appendTo('body'); var t; $('#Temp').load('index.php',null,function (t){ t = $('#Temp').find('#testing').text(); alert(t); }) Please help me... it works well on fireworks and chrome result should be to alert "Hello Worlds" instead its blank.

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  • kelvinluck jQuery datePicker: 2 inline calendars - i need to set EndDate of 2nd on selecting 1st cal

    - by lance
    Hi all I'm stuck. Tried all the angles but i cant seem to get it working. I have 2 inline calendars. When i select a date from the dtFrm calendar it sets the date on the dtTo calendar as expected. I just cant seem to set the EndDate of the dtTo calendar. Anyone manage to solve this one? Thanks! Lance using:jquery.datePicker.min-2.1.2.js <script type="text/javascript"> $(function() { $('.dtFrm').datePicker({ inline: true }) .bind( 'dateSelected', function(e, selectedDate, $td) { $('.dtTo').dpSetSelected(selectedDate.addDays(10).asString());//works $('.dtTo').dpSetEndDate(selectedDate.addDays(11).asString());//doesnt work } ); $('.dtTo').datePicker({ inline: true }); }); </script> <div class="dtFrm" style="float:left"></div> <div class="dtTo" style="float:left"></div>

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  • Trying to change img src if another element is visible with jQuery

    - by R.J.
    I have a div ("panel" class) on my page that toggles open/closed on the click of a paragraph element ("flip" class), which has an image inside of it. Here's the HTML: <div class="panel">Contact info</div> <p class="flip"><img src="images/contactExpand.png" />Expand</p> And the jQuery: $(".flip").click(function(){ $(".panel").slideToggle("slow"); }); Everything works fine so far, but I want the image src to change to "contactCollapse.png" when the panel div is visible. This doesn't seem to do anything (image just stays the same): if ($(".panel").is(":visible") == true) { $(".flip img").attr("src","../images/contactCollapse.png") } else { $(".flip img").attr("src","../images/contactExpand.png") } Am I missing something? Thanks for any help!

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  • jQuery Draggable Problem

    - by Jimbo
    Im trying to get a div to be movable within the constrains of the browser window, by dragging the titlebar inside the div. My code is as follows: <div id='container'> <h3 class='title' id='titlebar'>My Title</h3> </div> <script type='text/javascript'> $(document).ready(function(){ $("#titlebar").draggable({ containment: 'window', scroll: false, helper: $('#container') }); }); </script> Something is wrong with this (it wont do anything at all) but I cant see the problem!

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  • How to make this jQuery snippet work in Internet Explorer?

    - by George Edison
    If there was ever a time to hate IE, this is it. This code begins with a box with content. When the button is clicked, the box is supposed to drop down and fade-in. <html> <script type="text/javascript" src="jquery.js"></script> <script type='text/javascript'> function Test() { var item_height = $('#test').height(); $('#test').height(0); $('#test').css('opacity','0'); $('#test').animate({ height: item_height, opacity: '1' },400); } </script> <body> <!-- The div below holds the sample content --> <div id="test" style='border: 1px solid black;'> Content<br> Content<br> Content<br> Content<br> Content </div> <!-- The button to test the animation --> <br><br> <div style='position: absolute; top: 150px; left: 10px;'> <button onclick='Test();'>Test</button> </div> </body> </html> This very simple example works on Chrome, Safari, and Opera. But Internet Explorer? No. How can I (if it's even possible) fix this so that it works in IE?

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  • How to make bottom half of a page take up remaining height?

    - by RobVious
    I've searched and tried a bunch of different things. I have a variable-height tophalf, and the bottom half should fill up the remaining space. A JSfiddle: http://jsfiddle.net/UCJmQ/ CSS: .top { background-color: lightblue; height: 300px; } .bottom { background-color: green; min-height: 100px; overflow: hidden; height: 100%; } html, body { height: 100%; } HTML: <div class="top"></div> <div class="bottom"> </div> What I'm seeing now is the green page taking up the entire window's height, not the remaining height. How can I make it take the remaining height instead?

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  • Is there a jQuery plugin for making a step-by-step type presentation?

    - by Earlz
    Hello, I was making a small thing in HTML and basically I have some "frames" like <div id="frame_1"> ... </div> <div id="frame_2"> ... </div> ... Basically what I want is for only one frame to be visible at one time and to navigate between frames easily with previous and next buttons (navigation by frame number a plus, but not required) Before I set out to write it myself I figured someone had already done it so has it been done?

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  • PHP while loop, table row

    - by Elliott
    Hi, I'm trying to loop through a database and output data into a div, if there are 3 divs horizontally accross it will the start a new tr until it reaches another 3 etc. It is currently outputted like : [] [] [] [] [] [] Currently I have it working when it reaches 3 it starts a new row, but I don't know how I can only echo a new tr once? As it creates a new table row each time. echo '<table><tr>'; while ($result) { $i ++; if ($i&3) { echo '<td> <div>Row Data</div> </td>'; } else { echo '<tr> <td> <div>Row Data</div> </td></tr>'; } } echo '</tr></table>'; The $result variable is the recordset from my sql query, everything works fine I just don't know how to only create a new table row once? Thanks

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  • JQuery, AJAX: Trying AJAX for the first time but cant get this to work...

    - by fwaokda
    Trying to get the code below to work but the success doesn't execute - the error does. How can I get more detailed information on what is exactly going wrong? I'll include the code for next.php in a pastebin link also. Thanks. [next.php: http://pastebin.com/Gnu2AfU8 ] $("a#next").click(function() { $.ajax({ type : 'POST', url : 'next.php', dataType : 'json', data : { nextID : $("a#next").attr("rel") }, success : function ( data ) { $("img#spotlight").attr("src",data.spotlightimage); $("div#showcase h1").text(data.title); $("div#showcase h2").text(data.subtitle); for(var i=0; i < data.size; i++) { $("ul#features").append("<li>").text(data.feature+i).append("</li>"); } $("div#showcase p").text(data.description); for(i=1; j < data.picsize; i++) { $("div.thumbnails ul").append("<li>").text(data.image+i).append("</li>"); } $("a#next").attr("rel", $a("a#next").attr("rel") + 1); }, error : function ( XMLHttpRequest, textStatus, errorThrown) { $("div#showcase h1").text("An error has occured."); } }); });

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  • Array of an array (Database)

    - by Anne Mah Li'en
    I am trying to print out an array of an array from database Below are my codes. I am able to retrieve all the values from the first array. But error occurs when I am trying to retrieve the 2nd array from database. <% ArrayList<Questionnaire> allCategories =QuestionnaireController.getQuestionnaireByCategoryAll(); for(int i=0;i<allCategories.size();i++){ Questionnaire allCategoriesQuestionnaire=allCategories.get(i); out.println("<div class=\"silverheader\">" + "<a href= \"\">" + allCategoriesQuestionnaire.getCategory() + "</a>" + "</div>" + "<div class=\"submenu\">" + "ArrayList<Questionnaire> CategoriesSustainability =QuestionnaireController.getQuestionnaireByCategorySustainability();" + out.println(CategoriesSustainability.get(0).getCategory()); + "<br />" + "</div>"); } %>

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  • Loop each x elements

    - by Cimm
    What's the beste way to show a list with 20 images in rows of 5? Or, in other words, how do I clean up this ugly snippet? <div class="row"> <% @images.each_with_index do |image, index| %> <%= image_tag image.url %> <% if index != 0 && index % 5 == 0 %> </div><div class="row"> <% end %> <% end %> </div>

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  • [JQuery] Edit Css with animation effect

    - by Pennywise83
    Hi, I've a div in a absolute position with a default "top" value set to "-200px". When i click on the div the "top" value is updated to "0". In this way I see the entire Div. This is the js: $(document).ready(function(){ $("#search_bar").click(function () { $(this).css("top","0"); }); }); Is there a way to achieve this result but with an animation? For example, a slide down effect? Also, when i click another time to the div I'd like that the "top" value will be restored to "-200px".

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  • Background is flashing upon load momentarily

    - by goongagaloonga22
    I have a div (.header) contained within other divs. When my page loads, momentarily just that one .header div "flashes" white as the page is loading, especially in in Firefox, but a little bit in IE8 too. I can't find what kind of CSS or lack thereof is causing this - there's no images or background color associated with that div. There is a logo.png within the .header. Thoughts? http://dev.bwmsnow.co.nz/

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  • Javascript BBcode function not working

    - by Dave
    I have a string I want to convert to divs but it doesn't close the div properly. The example string i am using is this: [quote]Quote by: user1 [quote]Quote by: user2 ads[/quote]Test[/quote]Testing 2. This results in: <div class="quote" style="margin-left:10px;margin-top:10px;"> Quote by: user1 [quote]Quote by: user2 ads </div> Test[/quote]Testing 2. But it will not convert the internal quotes properly. My Javascript function is like this: function bbcode_parser(str) { search = new Array( /\[b\](.*?)\[\/b\]/g, /\[i\](.*?)\[\/i\]/g, /\[quote](.*?)\[\/quote\]/g, /\[\*\]\s?(.*?)\n/g); replace = new Array( "<strong>$1</strong>", "<em>$1</em>", "<div class='quote' style='margin-left:10px;margin-top:10px;'>$1</div>"); for (i = 0; i < search.length; i++) { str = str.replace(search[i], replace[i]); } return str; } I have provided a JSFiddle for you to see it in action: http://jsfiddle.net/gRaFW/2/ Please help :)

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  • Weird behaviour of jquery's hide/show with the 'slide' effect. How to change?

    - by Tommy
    When doing $('.mydiv').show('slide', {direction:up}, 1500); //syntax may be a little off jQuery seems to - just before starting the animation - make room for the soon to be showed div. This creates a non-smooth effect making all elements below the showed div shift away in one big go. I would like to see the elements below the div move away as the div is animated/showed. The jQuery native hide()/show() function works like this, how come the slide effect of hide/show doesn't? Anyone knows how to fix it?

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  • Two Overlapping divisions, but upper one is unscrollable

    - by FREAKENGINEER
    I have two divisions in my html page with their respective css <html> <head> #lowerone {position:absolute; bottom:25px; right:25px; height:300px; width:300px;} #upperone {position:absolute; bottom:25px; right:25px; height:300px; width:300px; overflow:scroll;} </head> <body> <div id="lowerone"> </div> <div id="upperone"> <img src="/bg.3.jpg" /> </div> </body> </html> But the upper div i.e. the UPPERONE is unscrollabe.. How to make it scrollable?

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  • Cannot get document.getElementById() to find my textarea

    - by Slruh
    Maybe I've been working on my site for to long, but I can't get the following to work. I am having my textarea fire an onkeyup() event called limiter which is supposed to check the textarea and limit the text in the box, while updated another readonly input field that shows the amount of characters left. This is the javascript code: <script type="text/javascript"> var count = "500"; function limiter(){ var comment = document.getElementById("comment"); var form = this.parent; var tex = comment.value; var len = tex.length; if(len > count){ tex = tex.substring(0,count); comment.value =tex; return false; } form.limit.value = count-len; } </script> The form looks like this: <form id="add-course-rating" method="post" action="/course_ratings/add/8/3/5/3" accept- charset="utf-8"><div style="display:none;"><input type="hidden" name="_method" value="POST" /> //Other inputs here <div id="comment-name" style="margin-top:10px"> <div id="comment-name-text"> <b>Comments</b><br /> Please leave any comments that you think will help anyone else. </div> <style type="text/css"> .rating-form-box textarea { -moz-border-radius:5px 5px 5px 5px; } </style> <div class="rating-form-box"> <textarea name="data[CourseRatings][comment]" id="comment" onkeyup="limiter()" cols="115" rows="5" ></textarea> <script type="text/javascript"> document.write("<input type=text name=limit size=4 readonly value="+count+">"); </script> </div> <input type="submit" value="Add Rating" style="float: right;"> </form> If anyone can help that would be great.

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  • iphone navigation

    - by Rona
    function handleClickEvent(event) { var linkFrom = $(event.target); if (typeof linkFrom.attr("href") == 'undefined') { linkFrom = $(event.target).parent(); } var targetPage = linkFrom.attr("href"); if (linkFrom.hasClass('submit')) { handleSubmitEvent(event); // if we want to stop processing: return false; } if (linkFrom.hasClass('backbutton')) { targetPage = historyStack.pop(); if (historyStack.length == 0) { lastPage = "index.html"; } } else { historyStack.push(lastPage); } lastPage = targetPage; $(event.target).css({ 'background-color': '#194fdb', 'color': '#ffffff' }); loadingWindowON(); // Add new unique div prevPageId = "page" + pageIdCounter; pageIdCounter = parseInt(pageIdCounter) + 1 nextPageId = "page" + pageIdCounter; nextPageDiv = "<div id='" + nextPageId + "' class='nextpage' /></div>"; $("body").append(nextPageDiv); if (linkFrom.attr("target") != "_blank") { event.preventDefault(); document.getElementById(nextPageId).addEventListener('webkitAnimationEnd', function () { // remove prev div element = document.getElementById(prevPageId); if (element) { element.parentNode.removeChild(element); } // set next div as current document.getElementById(nextPageId).className = 'currentpage'; }, false); document.getElementById(nextPageId).className += ' slideleftIn'; document.getElementById(prevPageId).className += ' slideleftOut'; loadContent(targetPage, nextPageId); } I use this javascript with a twitter app I had to do and when I click a button, instead of sliding the new page from the side it adds it to the existing page at the bottom. It works fine when i open it on my computer using google chrome but when I try to open it with my iphone it doesn't work. Any ideas?

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  • pagination panel should remain static

    - by fusion
    i've a search form in which a user enters the keyword and the results are displayed with pagination. everything works fine except for the fact that when the user clicks on the 'Next' button, the pagination panel disappears as well when the page loads to retrieve the data through ajax. how do i make the pagination panel static, while the data is being retrieved? search.html: <form name="myform" class="wrapper"> <input type="text" name="q" id="q" onkeyup="showPage();" class="txt_search"/> <input type="button" name="button" onclick="showPage();" class="button"/> <p> </p> <div id="txtHint"></div> </form> ajax: var url="search.php"; url += "?q="+str+"&page="+page+"&list="; url += "&sid="+Math.random(); xmlHttp.onreadystatechange=stateChanged; xmlHttp.open("GET",url,true); xmlHttp.send(null); function stateChanged(){ if (xmlHttp.readyState==4 || xmlHttp.readyState=="complete"){ document.getElementById("txtHint").innerHTML=xmlHttp.responseText; } //end if } //end function search.php: $self = $_SERVER['PHP_SELF']; $limit = 3; //Number of results per page $adjacents = 2; $numpages=ceil($totalrows/$limit); $query = $query." ORDER BY idQuotes LIMIT " . ($page-1)*$limit . ",$limit"; $result = mysql_query($query, $conn) or die('Error:' .mysql_error()); ?> <div class="search_caption">Search Results</div> <div class="search_div"> <table class="result"> <?php while ($row= mysql_fetch_array($result, MYSQL_ASSOC)) { $cQuote = highlightWords(htmlspecialchars($row['cQuotes']), $search_result); ?> <tr> . . .display results. . . </tr> <?php } ?> </table> </div> <hr> <div class="searchmain"> <?php //Create and print the Navigation bar $nav=""; $next = $page+1; $prev = $page-1; if($page > 1) { $nav .= "<a onclick=\"showPage('','$prev'); return false;\" href=\"$self?page=" . $prev . "&q=" .urlencode($search_result) . "\">< Prev</a>"; $first = "<a onclick=\"showPage('','1'); return false;\" href=\"$self?page=1&q=" .urlencode($search_result) . "\"> << </a>" ; } else { $nav .= "&nbsp;"; $first = "&nbsp;"; } for($i = 1 ; $i <= $numpages ; $i++) { if($i == $page) { $nav .= "<span class=\"no_link\">$i</span>"; }else{ $nav .= "<a onclick=\"showPage('',$i); return false;\" href=\"$self?page=" . $i . "&q=" .urlencode($search_result) . "\">$i</a>"; } } if($page < $numpages) { $nav .= "<a onclick=\"showPage('','$next'); return false;\" href=\"$self?page=" . $next . "&q=" .urlencode($search_result) . "\">Next ></a>"; $last = "<a onclick=\"showPage('','$numpages'); return false;\" href=\"$self?page=$numpages&q=" .urlencode($search_result) . "\"> >> </a>"; } else { $nav .= "&nbsp;"; $last = "&nbsp;"; } echo $first . $nav . $last; ?> </div>

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  • jquery to create array from form data

    - by AndrewStevens
    I've been wrestling with this problem for a couple hours now. Essentially, what I need to do is take the following or similar HTML: <div id="excpdivs"> <div class="excpdiv" id="excpdiv0"> Date: <input name="excp[0][date]"> Open: <input name="excp[0][open]"> Close: <input name="excp[0][close]"> </div> <div class="excpdiv" id="expdiv1"> Date: <input name="excp[1][date]"> Open: <input name="excp[1][open]"> Close: <input name="excp[1][close]"> </div> and get an array similar to the following to a php script: Array ( [0] => Array ( [date] => 2012-09-15 [open] => 3:00 [close] => 5:00 ) [1] => Array ( [date] => 2012-09-16 [open] => 2:00 [close] => 5:00 ) ) My main problem is getting the values from the input elements. My latest attempt is the following: var results = []; $(".excpdiv").each(function(){ var item = {}; var inpts = $(this).find("input"); item.date = $(inpts.get(0)).val(); item.open = $(inpts.get(1)).val(); item.close = $(inpts.get(2)).val(); results.push(item); }); Am I on the right track or am I hopelessly lost?

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  • JQuery tab Selection problem?

    - by PeAk
    New to JQuery and I was wondering how do I keep any tabbed selected when a user reloads the web page? What part of my code do I need to change? Here is my JQuery code. $(document).ready(function() { //When page loads... $(".form-content").hide(); //Hide all content var firstMenu = $("#home-menu ul li:first"); firstMenu.show(); firstMenu.find("a").addClass("selected-link"); //Activate first tab $(".form-content:first").show(); //Show first tab content //On Click Event $("#home-menu ul li").click(function() { $("#home-menu ul li a").removeClass("selected-link"); //Remove any "selected-link" class $(this).find("a").addClass("selected-link"); //Add "selected-link" class to selected tab $(".form-content").hide(); //Hide all tab content var activeTab = $(this).find("a").attr("href"); //Find the href attribute value to identify the selected-link tab + content $(activeTab).fadeIn(); //Fade in the selected-link ID content return false; }); }); Here is the XHTML code. <div id="home-menu"> <ul> <li><a href="#personal-info-form" title="Personal Info Form Link">Personal Info</a></li> <li><a href="#contact-info-form" title="Contact Info Form Link">Contact Info</a></li> </ul> </div> <div> <div id="personal-info-form" class="form-content"> <h2>Personal Information</h2> <form method="post" action="index.php"> <fieldset> <ul> <li><label for="first_name">First Name: </label><input type="text" name="first_name" id="first_name" size="25" class="input-size" value="<?php if(!empty($first_name)){ echo $first_name; } ?>" /></li> <li><label for="middle_name">Middle Name: </label><input type="text" name="middle_name" id="middle_name" size="25" class="input-size" value="<?php if(!empty($middle_name)){ echo $middle_name; } ?>" /></li> <li><label for="last_name">Last Name: </label><input type="text" name="last_name" id="last_name" size="25" class="input-size" value="<?php if(!empty($last_name)){ echo $last_name; } ?>" /></li> <li><label for="password-1">Password: </label><input type="password" name="password1" id="password-1" size="25" class="input-size" /></li> <li><label for="password-2">Confirm Password: </label><input type="password" name="password2" id="password-2" size="25" class="input-size" /></li> <li><input type="submit" name="submit" value="Save Changes" class="save-button" /> <input type="submit" name="submit" value="Preview Changes" class="preview-changes-button" /></li> </ul> </fieldset> </form> </div> <div id="contact-info-form" class="form-content"> <h2>Contact Information</h2> <form method="post" action="index.php" id="contact-form"> <fieldset> <ul> <li><label for="address">Address 1: </label><input type="text" name="address" id="address" size="25" class="input-size" value="<?php if (isset($_POST['address'])) { echo $_POST['address']; } else if(!empty($address)) { echo $address; } ?>" /></li> <li><label for="address_two">Address 2: </label><input type="text" name="address_two" id="address_two" size="25" class="input-size" value="<?php if (isset($_POST['address_two'])) { echo $_POST['address_two']; } else if(!empty($address_two)) { echo $address_two; } ?>" /></li> <li><label for="city_town">City/Town: </label><input type="text" name="city_town" id="city_town" size="25" class="input-size" value="<?php if (isset($_POST['city_town'])) { echo $_POST['city_town']; } else if(!empty($city_town)) { echo $city_town; } ?>" /></li> <li><input type="submit" name="submit" value="Save Changes" class="save-button" /> <input type="hidden" name="contact_info_submitted" value="true" /> <input type="submit" name="submit" value="Preview Changes" class="preview-changes-button" /></li> </ul> </fieldset> </form> </div> </div>

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  • PHP setcookie warning

    - by Ranking
    Hello guys, I have a problem with 'setcookie' in PHP and I can't solve it. so I receive this error "Warning: Cannot modify header information - headers already sent by (output started at C:\Program Files\VertrigoServ\www\vote.php:14) in C:\Program Files\VertrigoServ\www\vote.php on line 86" and here is the file.. line 86 is setcookie ($cookie_name, 1, time()+86400, '/', '', 0); is there any other way to do this ?? <html> <head> <title>Ranking</title> <link href="style.css" rel="stylesheet" type="text/css"> </head> <body bgcolor="#EEF0FF"> <div align="center"> <br/> <div align="center"><div id="header"></div></div> <br/> <table width="800" border="0" align="center" cellpadding="5" cellspacing="0" class="mid-table"> <tr><td height="5"> <center> <table border="0" cellpadding="0" cellspacing="0" align="center" style="padding-top:5px;"> <tr> <td align="center" valign="top"><img src="images/ads/top_banner.png"></td> </tr> </table> </center> </td></tr> <tr><td height="5"></td></tr> </table> <br/> <?php include "conf.php"; $id = $_GET['id']; if (!isset($_POST['submitted'])) { if (isset($_GET['id']) && is_numeric($_GET['id'])) { $id = mysql_real_escape_string($_GET['id']); $query = mysql_query("SELECT SQL_CACHE id, name FROM s_servers WHERE id = $id"); $row = mysql_fetch_assoc($query); ?> <form action="" method="POST"> <table width="800" height="106" border="0" align="center" cellpadding="3" cellspacing="0" class="mid-table"> <tr><td><div align="center"> <p>Code: <input type="text" name="kod" class="port" /><img src="img.php" id="captcha2" alt="" /><a href="javascript:void(0);" onclick="document.getElementById('captcha2').src = document.getElementById('captcha2').src + '?' + (new Date()).getMilliseconds()">Refresh</a></p><br /> <p><input type="submit" class="vote-button" name="vote" value="Vote for <?php echo $row['name']; ?>" /></p> <input type="hidden" name="submitted" value="TRUE" /> <input type="hidden" name="id" value="<?php echo $row['id']; ?>" /> </div></td></tr> <tr><td align="center" valign="top"><img src="images/ads/top_banner.png"></td></tr> </table> </form> <?php } else { echo '<font color="red">You must select a valid server to vote for it!</font>'; } } else { $kod=$_POST['kod']; if($kod!=$_COOKIE[imgcodepage]) { echo "The code does not match"; } else { $id = mysql_real_escape_string($_POST['id']); $query = "SELECT SQL_CACHE id, votes FROM s_servers WHERE id = $id"; $result = mysql_query($query) OR die(mysql_error()); $row = mysql_fetch_array($result, MYSQL_ASSOC); $votes = $row['votes']; $id = $row['id']; $cookie_name = 'vote_'.$id; $ip = $_SERVER['REMOTE_ADDR']; $ltime = mysql_fetch_assoc(mysql_query("SELECT SQL_CACHE `time` FROM `s_votes` WHERE `sid`='$id' AND `ip`='$ip'")); $ltime = $ltime['time'] + 86400; $time = time(); if (isset($_COOKIE['vote_'.$id]) OR $ltime > $time) { echo 'You have already voted in last 24 hours! Your vote is not recorded.'; } else { $votes++; $query = "UPDATE s_servers SET votes = $votes WHERE id = $id"; $time = time(); $query2 = mysql_query("INSERT INTO `s_votes` (`ip`, `time`, `sid`) VALUES ('$ip', '$time', '$id')"); $result = mysql_query($query) OR die(mysql_error()); setcookie ($cookie_name, 1, time()+86400, '/', '', 0); } } } ?> <p><a href="index.php">[Click here if you don't want to vote]</a></p><br/> <p><a href="index.php">Ranking.net</a> &copy; 2010-2011<br> </p> </div> </body> </html> Thanks a lot!

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