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  • Losing session after Login - Java

    - by Patrick Villela
    I'm building an application that needs to login to a certain page and make a navigation. I can login, provided that the response contains a string that identifies it. But, when I navigate to the second page, I can't see the page as a logged user, only as anonymous. I'll provide my code. import java.net.*; import java.security.*; import java.security.cert.*; import javax.net.ssl.*; import java.io.*; import java.util.*; public class PostTest { static HttpsURLConnection conn = null; private static class DefaultTrustManager implements X509TrustManager { @Override public void checkClientTrusted(X509Certificate[] arg0, String arg1) throws CertificateException {} @Override public void checkServerTrusted(X509Certificate[] arg0, String arg1) throws CertificateException {} @Override public X509Certificate[] getAcceptedIssuers() { return null; } } public static void main(String[] args) { try { SSLContext ctx = SSLContext.getInstance("TLS"); ctx.init(new KeyManager[0], new TrustManager[] {new DefaultTrustManager()}, new SecureRandom()); SSLContext.setDefault(ctx); String data = URLEncoder.encode("txtUserName", "UTF-8") + "=" + URLEncoder.encode(/*username*/, "UTF-8"); data += "&" + URLEncoder.encode("txtPassword", "UTF-8") + "=" + URLEncoder.encode(/*password*/", "UTF-8"); data += "&" + URLEncoder.encode("envia", "UTF-8") + "=" + URLEncoder.encode("1", "UTF-8"); connectToSSL(/*login url*/); conn.setDoOutput(true); OutputStreamWriter wr = new OutputStreamWriter(conn.getOutputStream()); wr.write(data); wr.flush(); BufferedReader rd = new BufferedReader(new InputStreamReader(conn.getInputStream())); String line; String resposta = ""; while((line = rd.readLine()) != null) { resposta += line + "\n"; } System.out.println("valid login -> " + resposta.contains(/*string that assures me I'm looged in*/)); connectToSSL(/*first navigation page*/); rd = new BufferedReader(new InputStreamReader(conn.getInputStream())); while((line = rd.readLine()) != null) { System.out.println(line); } } catch(Exception e) { e.printStackTrace(); } } private static void connectToSSL(String address) { try { URL url = new URL(address); conn = (HttpsURLConnection) url.openConnection(); conn.setHostnameVerifier(new HostnameVerifier() { @Override public boolean verify(String arg0, SSLSession arg1) { return true; } }); } catch(Exception ex) { ex.printStackTrace(); } } } Any further information, just ask. Thanks in advance.

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  • Webdevelopement : Login Specification

    - by mr.bio
    Hi there , i just started with PHP and i wanted to implement a Login. Rather than inventing the Wheel : is there any Online Specification for a Login System ? Things a should care about : detect Brute Force attacks implement password recovery maybe openID and/or with facebook account prevent SQL injection ..... So i think this has been done more than 1000 times. Where can i read about it ?

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  • Login system and sessions (php)

    - by Jonathan
    I've created a login page and registration page and now I want to use that to password protect pages and have pages which show information specific to that user. Would storing the user ID of the user logged in in a Session variable be a safe and correct way of doing this? How easy would it be for a user to change the session variable to a different ID and access another user's information, and not having to type the users login details in?

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  • Get return values from a stored procedure in c# (login process)

    - by Jin
    Hi all, I am trying to use a Stored Procedure which takes two parameters (login, pw) and returns the user info. If I execute the SP manually, I get Session_UID User_Group_Name Sys_User_Name ------------------------------------ -------------------------------------------------- - NULL Administrators NTMSAdmin No rows affected. (1 row(s) returned) @RETURN_VALUE = 0 Finished running [dbo].[p_SYS_Login]. But with the code below, I only get the return value. do you know how to get the other values shown above like Session_UID, User_Group_Name, and Sys_User_Name ? if you see the commented part below code. I tried to add some output parameters but it doesn't work with incorrect number of parameters error. string strConnection = Settings.Default.ConnectionString; using (SqlConnection conn = new SqlConnection(strConnection)) { using (SqlCommand cmd = new SqlCommand()) { SqlDataReader rdr = null; cmd.Connection = conn; cmd.CommandText = "p_SYS_Login"; //cmd.CommandText = "p_sys_Select_User_Group"; cmd.CommandType = CommandType.StoredProcedure; SqlParameter paramReturnValue = new SqlParameter(); paramReturnValue.ParameterName = "@RETURN_VALUE"; paramReturnValue.SqlDbType = SqlDbType.Int; paramReturnValue.SourceColumn = null; paramReturnValue.Direction = ParameterDirection.ReturnValue; //SqlParameter paramGroupName = new SqlParameter("@User_Group_Name", SqlDbType.VarChar, 50); //paramGroupName.Direction = ParameterDirection.Output; //SqlParameter paramUserName = new SqlParameter("@Sys_User_Name", SqlDbType.VarChar, 50); //paramUserName.Direction = ParameterDirection.Output; cmd.Parameters.Add(paramReturnValue); //cmd.Parameters.Add(paramGroupName); //cmd.Parameters.Add(paramUserName); cmd.Parameters.AddWithValue("@Sys_Login", textUserID.Text); cmd.Parameters.AddWithValue("@Sys_Password", textPassword.Text); try { conn.Open(); object result = cmd.ExecuteNonQuery(); int returnValue = (int)cmd.Parameters["@RETURN_VALUE"].Value; if (returnValue == 0) { Hide(); Program.MapForm.Show(); } else if (returnValue == 1) { MessageBox.Show("The username or password you entered is incorrect", "NTMS Login", MessageBoxButtons.OK, MessageBoxIcon.Warning); } else if (returnValue == 2) { MessageBox.Show("This account is disabled", "NTMS Login", MessageBoxButtons.OK, MessageBoxIcon.Warning); } else { MessageBox.Show("Database error. Please contact administrator", "NTMS Login", MessageBoxButtons.OK, MessageBoxIcon.Warning); } } catch (Exception ex) { string message = ex.Message; string caption = "MAVIS Exception"; MessageBoxButtons buttons = MessageBoxButtons.OK; MessageBox.Show( message, caption, buttons, MessageBoxIcon.Warning, MessageBoxDefaultButton.Button1); } } } Thanks for your help.

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  • Tab Controls effecting other Controls.

    - by VBeginner
    Hopefully I've explained myself good enough this time. Can't seem to get a real answer. Trying to make it so when I select certain tabs, certain controls on the left will disappear or reappear. http://img43.imageshack.us/img43/7533/scrnshotg.jpg Also, when "Stats" is selected, I need it to auto-select "Frequency" Ex. On click/focus/select (whatever, nothing seems to work)... ComboBox.Visible = True Thank you.

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  • Advanced donut caching: using dynamically loaded controls

    - by DigiMortal
    Yesterday I solved one caching problem with local community portal. I enabled output cache on SharePoint Server 2007 to make site faster. Although caching works fine I needed to do some additional work because there are some controls that show different content to different users. In this example I will show you how to use “donut caching” with user controls – powerful way to drive some content around cache. About donut caching Donut caching means that although you are caching your content you have some holes in it so you can still affect the output that goes to user. By example you can cache front page on your site and still show welcome message that contains correct user name. To get better idea about donut caching I suggest you to read ScottGu posting Tip/Trick: Implement "Donut Caching" with the ASP.NET 2.0 Output Cache Substitution Feature. Basically donut caching uses ASP.NET substitution control. In output this control is replaced by string you return from static method bound to substitution control. Again, take a look at ScottGu blog posting I referred above. Problem If you look at Scott’s example it is pretty plain and easy by its output. All it does is it writes out current user name as string. Here are examples of my login area for anonymous and authenticated users:    It is clear that outputting mark-up for these views as string is pretty lame to implement in code at string level. Every little change in design will end up with new version of controls library because some parts of design “live” there. Solution: using user controls I worked out easy solution to my problem. I used cache substitution and user controls together. I have three user controls: LogInControl – this is the proxy control that checks which “real” control to load. AnonymousLogInControl – template and logic for anonymous users login area. AuthenticatedLogInControl – template and logic for authenticated users login area. This is the control we render for each user separately because it contains user name and user profile fill percent. Anonymous control is not very interesting because it is only about keeping mark-up in separate file. Interesting parts are LogInControl and AuthenticatedLogInControl. Creating proxy control The first thing was to create control that has substitution area where “real” control is loaded. This proxy control should also be available to decide which control to load. The definition of control is very primitive. <%@ Control EnableViewState="false" Inherits="MyPortal.Profiles.LogInControl" %> <asp:Substitution runat="server" MethodName="ShowLogInBox" /> But code is a little bit tricky. Based on current user instance we decide which login control to load. Then we create page instance and load our control through it. When control is loaded we will call DataBind() method. In this method we evaluate all fields in loaded control (it was best choice as Load and other events will not be fired). Take a look at the code. public static string ShowLogInBox(HttpContext context) {     var user = SPContext.Current.Web.CurrentUser;     string controlName;       if (user != null)         controlName = "AuthenticatedLogInControl.ascx";     else         controlName = "AnonymousLogInControl.ascx";       var path = "~/_controltemplates/" + controlName;     var output = new StringBuilder(10000);       using(var page = new Page())     using(var ctl = page.LoadControl(path))     using(var writer = new StringWriter(output))     using(var htmlWriter = new HtmlTextWriter(writer))     {         ctl.DataBind();         ctl.RenderControl(htmlWriter);     }     return output.ToString(); } When control is bound to data we ask to render it its contents to StringBuilder. Now we have the output of control as string and we can return it from our method. Of course, notice how correct I am with resources disposing. :) The method that returns contents for substitution control is static method that has no connection with control instance because hen page is read from cache there are no instances of controls available. Conclusion As you saw it was not very hard to use donut caching with user controls. Instead of writing mark-up of controls to static method that is bound to substitution control we can still use our user controls.

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  • Best jQuery Libraries, Plug-Ins and Controls

    - by schnieds
    Worried About The Loss Of ASP.NET Controls in MVC? Don’t BeIf you are hesitant of moving to ASP.NET MVC because you are worried about losing all of the awesome ASP.NET controls that you are so used to using, don’t be. Wonderful client side controls already exist to replace most, if not all, of the most used ASP.NET controls (and these controls provide a MUCH BETTER user experience.) Here is a list of my favorite jQuery plug-ins and libraries that make user interface development so much easier... [Read More Here]Aaron Schniederhttp://www.churchofficeonline.com

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  • How do I create a popup banner before login with Lightdm?

    - by Rich Loring
    When Ubuntu was using gnome I was able to create a popup banner like the banner below before the login screen using zenity in the /etc/gdm/Init/Default. The line of code would be like this: if [ -f "/usr/bin/zenity" ]; then /usr/bin/zenity --info --text="`cat /etc/issue`" --no-wrap; else xmessage -file /etc/issue -button ok -geometry 540X480; fi How can I accomplish this with Unity? NOTICE TO USERS This is a Federal computer system (and/or it is directly connected to a BNL local network system) and is the property of the United States Government. It is for authorized use only. Users (authorized or unauthorized) have no explicit or implicit expectation of privacy. Any or all uses of this system and all files on this system may be intercepted, monitored, recorded, copied, audited, inspected, and disclosed to authorized site, Department of Energy, and law enforcement personnel, as well as authorized officials of other agencies, both domestic and foreign. By using this system, the user consents to such interception, monitoring, recording, copying, auditing, inspection, and disclosure at the discretion of authorized site or Department of Energy personnel. Unauthorized or improper use of this system may result in administrative disciplinary action and civil and criminal penalties. By continuing to use this system you indicate your awareness of and consent to these terms and conditions of use. LOG OFF IMMEDIATELY if you do not agree to the conditions stated in this warning.

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  • Using Facebook Login to create a user?

    - by andbeyond
    I've read this SO post which led me to this FB policy page, which seemed to include some pertinent information, but I'd like more of a community response, maybe some experienced FB API people who know the limits. My question is if I can use Facebook's Login api to, essentially, create a new user on my website. I really would just like to allow users to easily "transfer" some data from FB in order to more easily create a new account on my site. I realize, first and foremost, that I would obviously announce to the user that by click "submit" in the form, that they are creating a separate account on my site. Pertinent blocks on the policy page state: You may cache data you receive through use of the Facebook API in order to improve your application’s user experience, but you should try to keep the data up to date. This permission does not give you any rights to such data. Which doesn't look good for me, but also this: If you stop using Platform or we disable your application, you must delete all data you have received through use of the Facebook API unless: (a) it is basic account information; or (b) you have received explicit consent from the user to retain their data. Which, in my case, I would be satisfying part B. I would be asking the user's permission to retain the data, as I am simply using Facebook as a conveience to the user when creating an account. I also realize that Facebook has a registration API, but this would require a Facebook styled login form, along with my own sites login form, and I'd rather one interface, as this makes it easier for me on the front and back end. Any thoughts?

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  • ajax login problem

    - by rdanee
    $(document).ready(function() { $("form#login_form").submit(function() { var login_username = $('#login_username').attr('value'); var login_password = $('#login_password').attr('value'); type: "POST", $.ajax({ url: "login.php", data: "username="+ login_username +"& password="+ login_password, success: function(data){ alert(data); if (data == "ok"){ $('form#login_form').hide(function(){$('div.success').fadeIn();}); } } }); return false; }); Login.php: <?php include("settings.php"); $query = "select * from users where username = '{$_POST['login_username']}' and password = md5('{$_POST['login_password']}')"; $query = mysql_query($query, $connection); if ( mysql_num_rows($query) == 1 ) { print "ok"; $array = mysql_fetch_array($query); if ( $_POST['stay'] ) { $time = time()+2592000; } else { $time = 0; } } else { print "no"; } mysql_close($connection); ?> My problem: In the alert the message always "no" whether username/password is correct, however on the site "ok" appears when username/pw is correct. I have read the other questions in connection with this problem, but I couldn't solve the response problem from login.php with Json. Could you help me how should I response to the ajax calling? ( with a code if it is possible) Thank you very much, and sorry for questioning again.

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  • OAuth in Rails - google, twitter, facebook, connect for login like stackoverflow login

    - by Sam
    Rails has the rest autho plugin which works well but is there a solution for incorporating twitter, facebook, google, yahoo, etc... Seems like each on has its own plugin and demands and mixing them is going to be a mess. This is for logging in users like how Stackoverflow gets things done not for using the robust features of the APIs. What I want to do is do what stackoverflow did for login but in rails.

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  • Dynamic controls lost when postback

    - by Joren
    Hi I load my self-made webuser controls dynamically. A user chooses a template and depending on that template I load some self-made webuser controls (.ascx) that are defined in a sql server database. When the user fills in the TextBoxes and clicks on the submit button, the entries in the TextBoxes should be saved in my database. The problem is that when clicking the submit button, the TextBox entries are erased. I searched a lot to fix this problem, for example I tried to load every control again every postback by putting the code in the Page_Init event but unfortunately it won't work.

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  • Formatting Controls in ASP.NET

    - by Brian
    I feel as though this this is a simple question, but can't find an answer anywhere. We've got an interface we're trying to move to an ASP.NET control. It currently looks like: <link rel=""stylesheet"" type=""text/css"" href=""/Layout/CaptchaLayout.css"" /> <script type=""text/javascript"" src=""../../Scripts/vcaptcha_control.js""></script> <div id="captcha_background"> <div id="captcha_loading_area"> <img id="captcha" src="#" alt="" /> </div> <div id="vcaptcha_entry_container"> <input id="captcha_answer" type="text"/> <input id="captcha_challenge" type="hidden"/> <input id="captcha_publickey" type="hidden"/> <input id="captcha_host" type="hidden"/> </div> <div id="captcha_logo_container"></div> </div> However all the examples I see of ASP.NET controls that allow for basical functionality - i.e. public class MyControl : Panel { public MyControl() { } protected override void OnInit(EventArgs e) { ScriptManager.RegisterScript( ... Google script, CSS, etc. ... ); TextBox txt = new TextBox(); txt.ID = "text1"; this.Controls.Add(txt); CustomValidator vld = new CustomValidator(); vld.ControlToValidate = "text1"; vld.ID = "validator1"; this.Controls.Add(vld); } } Don't allow for the detailed layout that we need. Any suggestions on how I can combine layout and functionality and still have a single ASP control we can drop in to pages? The ultimate goal is for users of the control to just drop in: <captcha:CaptchaControl ID="CaptchaControl1" runat="server" Server="http://localhost:51947/" /> and see the working control. Sorry for the basic nature of this one, any help is greatly appreciated.

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  • Adding dynamic controls to Silverlight application after WCF Service Asynchronous Callback

    - by Birk
    I'm trying to add some dynamic controls to my Silverlight page after a WCF call. When I try to add a control to I get an error: Object reference not set to an instance of an object. Here is a simplified version of my code: using edm = SilverlightBusinessApplication.ServiceRefrence; public partial class ListWCF : Page { edm.ServiceClient EdmClient = new ServiceClient(); public ListWCF() { EdmClient.GetTestCompleted += EdmGetTestCompleted; EdmClient.GetTestAsync(); } private void EdmGetTestCompleted(object sender, edm.GetTestCompletedEventArgs e) { //This is where I want to add my controls Button b = new Button(); LayoutRoot.Children.Add(b); //Error: Object reference not set to an instance of an object } } Is it not possible to modify the page after it has been loaded? What am I missing? Thanks

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  • Framework 4 Features: Login Id Support

    - by Anthony Shorten
    Given that Oracle Utilities Application Framework 4 is available as part of Mobile Work Force Management and other product progressively I am preparing a number of short but sweet blog entries highlighting some of the new functionality that has been implemented. This is the first entry and it is on a new security feature called Login Id. In past releases of the Oracle Utilities Application Framework, the userid used for authentication and authorization was limited to eight (8) characters in length. This mirrored what the market required in the past with LAN userids and even legacy userids being that length. The technology market has since progressed to longer userid lengths. It is very common to hear that email addresses are being used as credentials for production systems. To achieve this in past versions of the Oracle Utilities Application Framework, sites had to introduce a short userid (8 characters in length) as an alias in your preferred security store. You then configured your J2EE Web Application Server to use the alias as credentials. This sometimes was a standard feaure of the security store and/or the J2EE Web Application Server, if you were lucky. If not, some java code has to be written to implement the solution. In Oracle Utilities Application Framework 4 we introduced a new attribute on the user object called Login Id. The Login Id can be up to 256 characters in length and is an alternative to the existing userid stored on the user object. This means the Oracle Utilities Application Framework can support both long and short userids. For backward compatibility we use the Login Id for authentication but the short userid for authorization and auditing. The user object within the Oracle Utilities Application Framework holds the translation. Backward compatibility is always a consideration in any of our designs for future or changed functionality. You will see reference to this fact in the blog entries I will be composing over the next few months. We have also thought about the flexibility in implementing this feature. The Login Id can be the same value of the Userid (the default for backward compatibility) or can be different. Both the Login Id and Userid have to be unique. This avoids sharing of credentials and is also backward compatible. You can manually enter the Login Id or provision it from Oracle Identity Manager (or other tool). If you use the Login Id only, then we will not autogenerate a short userid automatically as the rules for this can vary from site to site. You have a number of options there. Most Identity provisioning tools can generate a short userid at user creation time and this can be used. If you do not use provisioning tools, then you can write a class extension using the SDK to autoegenerate the userid based upon your sites preference. When we designed the feature there were lots of styles of generating userids (random, initial and surname, numbers etc). We could not really see a clear winner in that respect so we just allowed the extension to be inserted in if necessary. Most customers indicated to us that identity provisioning was the preferred way. This is why we released an Oracle Identity Manager integration with the framework. The Login id is case sensitive now which was not supported under userid. The introduction of the Login Id allows the product to offer flexible options when configuring security whilst maintaining backward compatibility.

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  • Python and mechanize login script

    - by Perun
    Hi fellow programmers! I am trying to write a script to login into my universities "food balance" page using python and the mechanize module... This is the page I am trying to log into: http://www.wcu.edu/11407.asp The website has the following form to login: <FORM method=post action=https://itapp.wcu.edu/BanAuthRedirector/Default.aspx><INPUT value=https://cf.wcu.edu/busafrs/catcard/idsearch.cfm type=hidden name=wcuirs_uri> <P><B>WCU ID Number<BR></B><INPUT maxLength=12 size=12 type=password name=id> </P> <P><B>PIN<BR></B><INPUT maxLength=20 type=password name=PIN> </P> <P></P> <P><INPUT value="Request Access" type=submit name=submit> </P></FORM> From this we know that I need to fill in the following fields: 1. name=id 2. name=PIN With the action: action=https://itapp.wcu.edu/BanAuthRedirector/Default.aspx This is the script I have written thus far: #!/usr/bin/python2 -W ignore import mechanize, cookielib from time import sleep url = 'http://www.wcu.edu/11407.asp' myId = '11111111111' myPin = '22222222222' # Browser #br = mechanize.Browser() #br = mechanize.Browser(factory=mechanize.DefaultFactory(i_want_broken_xhtml_support=True)) br = mechanize.Browser(factory=mechanize.RobustFactory()) # Use this because of bad html tags in the html... # Cookie Jar cj = cookielib.LWPCookieJar() br.set_cookiejar(cj) # Browser options br.set_handle_equiv(True) br.set_handle_gzip(True) br.set_handle_redirect(True) br.set_handle_referer(True) br.set_handle_robots(False) # Follows refresh 0 but not hangs on refresh > 0 br.set_handle_refresh(mechanize._http.HTTPRefreshProcessor(), max_time=1) # User-Agent (fake agent to google-chrome linux x86_64) br.addheaders = [('User-agent','Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/535.11 (KHTML, like Gecko) Chrome/17.0.963.56 Safari/535.11'), ('Accept', 'text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8'), ('Accept-Encoding', 'gzip,deflate,sdch'), ('Accept-Language', 'en-US,en;q=0.8'), ('Accept-Charset', 'ISO-8859-1,utf-8;q=0.7,*;q=0.3')] # The site we will navigate into br.open(url) # Go though all the forms (for debugging only) for f in br.forms(): print f # Select the first (index two) form br.select_form(nr=2) # User credentials br.form['id'] = myId br.form['PIN'] = myPin br.form.action = 'https://itapp.wcu.edu/BanAuthRedirector/Default.aspx' # Login br.submit() # Wait 10 seconds sleep(10) # Save to a file f = file('mycatpage.html', 'w') f.write(br.response().read()) f.close() Now the problem... For some odd reason the page I get back (in mycatpage.html) is the login page and not the expected page that displays my "cat cash balance" and "number of block meals" left... Does anyone have any idea why? Keep in mind that everything is correct with the header files and while the id and pass are not really 111111111 and 222222222, the correct values do work with the website (using a browser...) Thanks in advance EDIT Another script I tried: from urllib import urlopen, urlencode import urllib2 import httplib url = 'https://itapp.wcu.edu/BanAuthRedirector/Default.aspx' myId = 'xxxxxxxx' myPin = 'xxxxxxxx' data = { 'id':myId, 'PIN':myPin, 'submit':'Request Access', 'wcuirs_uri':'https://cf.wcu.edu/busafrs/catcard/idsearch.cfm' } opener = urllib2.build_opener() opener.addheaders = [('User-agent','Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/535.11 (KHTML, like Gecko) Chrome/17.0.963.56 Safari/535.11'), ('Accept', 'text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8'), ('Accept-Encoding', 'gzip,deflate,sdch'), ('Accept-Language', 'en-US,en;q=0.8'), ('Accept-Charset', 'ISO-8859-1,utf-8;q=0.7,*;q=0.3')] request = urllib2.Request(url, urlencode(data)) open("mycatpage.html", 'w').write(opener.open(request)) This has the same behavior...

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  • Can't login into Fedora 14 (XFCE) desktop. For the second time.

    - by bubba88
    Hello. I'm experiencing a problem with my Fedora 14 XFCE spin, which doesn't seem to let me pass the login screen: I enter my password for my user record, authentication passes (no 'Authentication Failure' message, which was when I tried to login as 'root' without root login enabled), and the screen becomes black (command line) for a couple of seconds and (voila!) my login screen emerges again. I did nothing to cause that, it just suddenly logged me out when I was editing window manager settings via XFCE's built-in GUI utility (choosing window decorations style, from the listbox on the left) For the first time, I had to boot from live CD and do a fresh install, but I don't really want to do that again :) Is there some way to repair this (maybe login via command line and reset window manager settings, I don't know really)? Thank you very much in advance!

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  • Can't login to Guest Session or Standard Account?

    - by Rory
    Thanks in advance for any help. Ubuntu 12.04 Up until recently my mother has been using the Guest Session when she logs on; now, the Guest Session will not login. When I try to login to it, it bounces me back to the login screen. I then tried to login on a Standard account (Alberta) which I made prior to not being able to login to Guest, and it turns out I cannot login - it gives the "Invalid Password" error. So then I tried to change her password from my own account (Rory) which is the master account. Under the Login Options where the Password option is, it says "Account disabled" and it will not let me change this; I try to apply a password, get no error, but it just still says "Account disabled". Then I tried to delete the Alberta account altogether, but got this error: I also tried sudo userdel -r Alberta but got this error: "userdel: cannot lock /etc/shadow; try again later." I don't know what to do now. Any help appreciated.

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  • How to throttle login attemps in Java webapp?

    - by Jörn Zaefferer
    I want to implement an efficient mechanism to throttle login attemps in my Java web application, to prevent brute-force attacks on user accounts. Jeff explained the why, but not the how. Simon Willison showed an implementation in Python for Django: That doesn't really help me along as I can't use memcached nor Django. Porting his ideas from scratch doesn't seem like a great either - I don't want to reinvent the wheel. I found one Java implementation, though it seems rather naiive: Instead of a LRU cache, it just clears all entries after 15 minutes. EHCache could be an alternative for memcached, but I don't have any experience with it and don't really want to intoduce yet another technology if there are better alternatives for this task. So, whats a good way to implement login throttling in Java?

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  • ExtJS: Login with 'Remember me' functionality

    - by Chau
    I'm trying to create a simple login window with the very common 'Remember me' functionality. The login validation is done AJAX style, thus the browser won't remember my input. My approach is to use the built-in state functionality, but how to use it confuses me. Ext.state.Manager.setProvider(new Ext.state.CookieProvider({ expires: new Date(new Date().getTime()+(1000*60*60*24*7)), //7 days from now })); ... { xtype: 'textfield', fieldLabel: 'User name', id: 'txt-username', stateful: true, stateId: 'username' }, { xtype: 'textfield', fieldLabel: 'Password', id: 'txt-password', inputType: 'password', stateful: true, stateId: 'password' }, { xtype: 'button', text: 'Validate', stateEvents: 'click' } I know I have to implement the getState method, but on what component (my guess is on the two textfields)? Another thing I fail to realize is, how is my click event on the button connected to the state properties of my textfields?

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