copying program arguments to a whitespace separated std::string
- by PaulH
I have a Visual Studio 2008 C++ application where I would like to copy all of program arguments in to a string separated by a whitespace " ". i.e., if my program is called as foo.exe \Program Files, then my folder string below would contain \Program Files
Below is an example of what I'm doing now. I was wondering if there was a shorter or easier method of doing this. Is there an easy way to eliminate the std::wstringstream variable?
int _tmain( int argc, _TCHAR* argv[] )
{
std::wstringstream f;
std::copy( argv + 1,
argv + argc,
std::ostream_iterator< std::wstring, wchar_t >( f, L" " ) );
std::wstring folder = f.str();
// ensure the folder begins with a backslash
if( folder[ 0 ] != L'\\' )
folder.insert( 0, 1, L'\\' );
// remove the trailing " " character from the end added by the std::copy() above
if( *folder.rbegin() == L' ')
folder.erase( folder.size() - 1 );
// ...
}
Thanks,
PaulH
