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  • Using Zend_Navigation, how do I create image-based navigation?

    - by SimpleCoder
    (I'm assuming my navigation should be in a layout script.) I have a navigation bar composed of rollover images. The image corresponding to the page that is active should be a different color, though. I do this by changing the image. My question is, where and how should I implement this using Zend_Navigation? Details: The menu itself is just a stack of divs that are floated to the left within a container. Each div has a background image. Thank you for your help,

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  • Which Java MVC frameworks integrate easily with StringTemplate?

    - by Daniel Jomphe
    It's hard to see how StringTemplate integrates easily (or not) with popular Java web MVC frameworks. Which Java MVC frameworks integrate easily with StringTemplate? A good answer: mentions one solution to integrate with a framework, includes a link to something useful and applicable, like: a tutorial, or documentation, or a reference to source code: free, and open source or public domain. Readers/Voters, please vote for a solution if you know it's true and great. In the scope of this question, I am not interested in any other templating engine than StringTemplate.

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  • SQL CREATE TABLE Error

    - by Adam M-W
    Hi, I've been stuck on this one simple(ish) thing for the last 1/2 hour so I thought I might try to get a quick answer here. What exactly is incorrect about my SQL syntax, assuming I'm using mysql 5.1 CREATE TABLE 'users' ( 'id' MEDIUMINT(8) UNSIGNED NOT NULL AUTO_INCREMENT PRIMARY KEY, 'username' VARCHAR(20) NOT NULL, 'password' VARCHAR(40) NOT NULL, 'salt' VARCHAR(40) DEFAULT NULL, 'email' VARCHAR(80) NOT NULL, 'created_on' INT(11) UNSIGNED NOT NULL, 'last_login' INT(11) UNSIGNED DEFAULT NULL, 'active' TINYINT(1) UNSIGNED DEFAULT NULL, ) ENGINE InnoDB; Also, does anyone have any good tutorials about how to use Zend_Auth for complete noobs? Thanks.

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  • [ZF] set/add view from controller action

    - by user359650
    Hi all, I'm trying to set a view script to be executed in addition to the currently requested action view script. I want to do this from the controller action itself in a way that this new view script output will be available from the layout $this-layout()-content helper. I found the setView() method but don't know how to use it from the controller. Thanks a lot.

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  • problem in custom error message on zend_element

    - by user1400
    hello all i created a text element like following code $test = $this->createElement('text', 'test'); $test->setLabel('test:'); $test->addValidator(new Zend_Validate_Int()); $test->addErrorMessages(array('isEmpty'=>'u should enter a number','%value% is not integer')); $shomare->setRequired(true); $this->addElement($test); when i set empty or non integer number to textbox , it show both its own error message , if its empty errormessage="u should enter a number" and when it is not a valid integer it shows '%value% is not integer' thanks

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  • How to dynamically order many-to-many relationship with JPA or HQl?

    - by Indrek
    I have a mapping like this: @ManyToMany(cascade = CascadeType.PERSIST) @JoinTable( name="product_product_catalog", joinColumns={@JoinColumn(name="product_catalog", referencedColumnName="product_catalog")}, inverseJoinColumns={@JoinColumn(name="product", referencedColumnName="product")}) public List<Product> products = new ArrayList<Product>(); I can fetch the products for the catalog nicely, but I can't (dynamically) order the products. How could I order them? I probably have to write a many-to-many HQL query with the order-by clause? I though of passing the orderBy field name string to the query, or is there a better solution? Tables are: products, product_catalog, product_product_catalog (associative table) P.S. Using Play! Framework JPASupport for my entities.

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  • Retrieve Domain Name instead of IP

    - by Vincent
    All, I am using the following command to retrieve the domain name of my server. $_SERVER['HTTP_HOST'] This seems to return the IP address instead of domain name like www.example.com. I looked at PHPInfo and it also lists an IP address for HTTP_HOST instead of Domain name. What do I need to change to make the domain name appear instead of IP? Thanks

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  • findBy(x) Using Zend_Navigation with custom route

    - by Stephen
    I am creating my navigation from a db generated array and defining which route to use for some of the uris. when I set the route i am no longer able to use findByUri() as the uri seems to be moved under the properties key example array being used: [id] => 7 [label] => Legal [controller] => index [uri] => /legal [route] => cmsPage [visible] => 1 [params] => Array ( [first] => legal ) snippet of the output: [_properties:protected] => Array ( [uri] => /legal [created] => 2012-10-20 10:23:23 ) When I don't define the route I am able to use findByUri() successfully. currently I am looping through each to find the property that matches the request but it seems a long / wrong approach Is there a way to search by the nested param - or am i doing something wrong with the setup (everything else behaves as expected)

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  • Current state of Erlang web development? Frameworks, Template languages

    - by pommonico
    Django is to Python as Rails is to Ruby. What is the current front-runner for Erlang? Recent Erlang web activity has resulted in many new frameworks but they are all still moving targets. ErlyWeb is very far along but now seems to be dead. If you were to invest significant capital into a new web product (i.e. not a hobby, you use your own money and you use other's investment in you with expectation of payback), would you choose Erlang as a web platform? If so, what framework and technologies would you choose?

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  • Zend_Router requirements mismatch

    - by elbicho
    Hello you all: I have two routes that match a url with the same apparent pattern, the difference lies in the $actionRoute, this should only be matched if the variable :action on it equals 'myaction'. If I go to /en/mypage/whatever/myaction it goes as expected through $actionRoute. If I go to /en/mypage/whatever/blahblah it gets rejected by $actionRoute and matched by $genRoute. If I go to /en/mypage/whatever it should be matched by $genRoute but it gets matched by $actionRoute instead throwing and exception because the action noactionAction() does not exist. Don't know what I'm doing wrong, I'd appreciate your help. $genRoute = new Zend_Controller_Router_Route( ':lang/mypage/:var1/:var2', array( 'lang' => '', 'module' => 'mymodule', 'controller' => 'index', 'action' => 'index', 'var1' => 'noone', 'var2' => 'no' ), array( 'var1' => '[a-z\-]+?', 'lang' => '(es|en|fr|de){1}' ) ); $actionRoute = new Zend_Controller_Router_Route( ':lang/mypage/:var1/:action', array( 'lang' => '', 'module' => 'mymodule', 'controller' => 'index', 'action' => 'noaction', 'var1' => 'noone', ), array( 'action' => '(myaction)+?', 'var' => '[a-z\-]+?', 'lang' => '(es|en|fr|de){1}', ) ); $router->addRoute('genroute',$genRoute); $router->addRoute('actionroute',$actionRoute);

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  • in .net, what programming model would be good for prototyping, but then reusable for production (for

    - by Greg
    Hi, In .NET land what would be a good approach for quick prototyping of a concept (i.e. development just on my PC) that could then be extended out to product (users across LAN/WAN), BUT in a fashion that the model/business logic code and data access layer code can be used as is? One thought for example I had as to do: (a) WinForms with business logic and Entity Framework layer to SQL Server Express on my PC, then (b) Go then to ASP.net (using the business logic / data library) with SQL Server/IIS Any comments? Other suggestions?

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  • My store returns no code id and breaks 404 error. Magento

    - by numerical25
    I know what the issue is but I dont know how to fix it. I just migrated my magento store locally and I guess possibly some data may have been lost when transferring the DB. the DB is very large. Anyhow, when I login to my admin page, I get a 404 error, page was not found. I debugged the issue and got down to the wire. The exception is thrown in Mage/Core/Model/App.php. Line 759 to be exacted. The following is a snippet. Mage/Core/Model/App.php if (empty($this->_stores[$id])) { $store = Mage::getModel('core/store'); /* @var $store Mage_Core_Model_Store */ if (is_numeric($id)) { $store->load($id); // THIS ID IS FROM Mage_Core_Model_App::ADMIN_STORE_ID and its empty which causes the error } elseif (is_string($id)) { $store->load($id, 'code'); } if (!$store->getCode()) { // RETURNS FALSE HERE BECAUSE NO ID Specified $this->throwStoreException(); } $this->_stores[$store->getStoreId()] = $store; $this->_stores[$store->getCode()] = $store; } The store returns null because $id is null so it therefore does not load any model which explains why it returns false when calling getCode() [EDIT] If you want clarification, please ask for more before voting my post down. Remember I am still trying to get help not get neglected. I am using Version 1.4.1.1. When I type in the URL for admin, I get a 404 page. I walked through the code thouroughly and found that the Model MAGE_CORE_MODEL_STORE::getCode(); Returns Null which triggers the exception. and ends the script. I do not have any other detail. I further troubleshooted the issue by checking the database and that is what the screen shot is. Showing that there is infact data in the Code Colunn. So my question is why is the Model returning a empty column when the column clearly has a value. What can I do to further troubleshoot and figure out why its not working [EDIT UPDATE NEW] I did some research. the reason its returning NULL is because the store ID is null being passed Mage::getStoreConfigFlag('web/secure/use_in_adminhtml', Mage_Core_Model_App::ADMIN_STORE_ID); // THIS IS THE ID being specified Mage_Core_Model_App::ADMIN_STORE_ID has no value in it, so this method throws the exception. Not sure why how to fix this.

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  • PHP-How to choose XML section based on an attribute?

    - by Vincent
    All, I have a config xml file in the following format: <?xml version="1.0"?> <configdata> <development> <siteTitle>You are doing Development</siteTitle> </development> <test extends="development"> <siteTitle>You are doing Testing</siteTitle> </test> <production extends="development"> <siteTitle>You are in Production</siteTitle> </production> </configdata> To read this config file to apply environment settings, currently I am using, the following code in index.php file: $appEnvironment = "production"; $config = new Zend_Config_Xml('/config/settings.xml', $appEnvironment ); To deploy this code on multiple environments, as user has to change index.php file. Instead of doing that, is it possible to maintain an attribute in the xml file, "say active=true". Based on which the Zend_Config_Xml will know which section of the xml file settings to read? Thanks

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  • Zend_Registry: real life examples

    - by takeshin
    Do you find Zend_Registry useful? For which tasks it should be used? For which not? Global state for variables is not a good practice. Main objects may have global state injected via $front->setParam('paramName', $object), so what's the purpose of Zend_Registry?.

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  • how to have two controller actions, one shared view for Zend_Controller_Action Class?

    - by arendn
    Hi Guys, How do you specify a custom view script for a given Controller Action method? For example: Class UserGalleryController extends Zend_Controller_Action { public function fooAction() { $this->view->actionMsg = 'foo'; // (uses foo.phtml automagically) } public function barAction() { $this->view->actionMsg = 'bar'; //use foo's view script ????? } } I basically want to have one view script (foo.phtml) Thanks :-)

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  • encode array to JSON in PHP to get [elm1,elm2,elm3] instead of {elm1:{},elm2:{},elm3:{}}

    - by Itay Moav
    I am trying to json_encode an array, which is what returns from a Zend_DB query. var_dump gives: (Manually adding 0 member does not change the picture). array(3) { [1]=> array(3) { ["comment_id"]=> string(1) "1" ["erasable"]=> string(1) "1" ["comment"]=> string(6) "test 1" } [2]=> array(3) { ["comment_id"]=> string(1) "2" ["erasable"]=> string(1) "1" ["comment"]=> string(6) "test 1" } [3]=> array(3) { ["comment_id"]=> string(1) "3" ["erasable"]=> string(1) "1" ["comment"]=> string(6) "jhghjg" } } The encoded string looks: {"1":{"comment_id":"1","erasable":"1","comment":"test 1"}, "2":{"comment_id":"2","erasable":"1","comment":"test 1"}, "3":{"comment_id":"3","erasable":"1","comment":"jhghjg"}} While I need it as: [{"comment_id":"1","erasable":"1","comment":"test 1"}, {"comment_id":"2","erasable":"1","comment":"test 1"}, {"comment_id":"3","erasable":"1","comment":"jhghjg"}] As the php.ini/json__encode documentation says it should. Any ideas?

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  • Can you automatically remove characters from entities created?

    - by JamesStuddart
    Hi, In my sql database I have tables with name which include underscores, for readability. Just to try and make it clearer see below: TableFoo TableFoo_TableBah Where TableFoo has a key linking to TableFoo_TableBah, this is done so you can quickly see what the table TableBah relates to. I have used this naming convention before with tools such as CodeSmith which give the option to remove the underscores, but I cannot see how to do this in Entity Framework 4. Is there a way to do this, or am I stuck with either renaming my tables or having objets such as TableFoo_TableBah? Thanks,

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  • Linq to Entities strange deploying behavior.

    - by SO give me back my rep
    Hi I started building apps with this technology and I am facing a weird problem... on some machines I need to add theese lines to the app.config to get to work: <system.data> <DbProviderFactories> <add name="MySQL Data Provider" invariant="MySql.Data.MySqlClient" description=".Net Framework Data Provider for MySQL" type="MySql.Data.MySqlClient.MySqlClientFactory, MySql.Data, Version=6.3.0.0, Culture=neutral, PublicKeyToken=c5687fc88969c44d" /> </DbProviderFactories> </system.data> while in other machines it runs well without theese lines.... the thing is that when I add theese lines the app wont run on machines that did not needed theese lines in the firs place, and I would like not to publish to versions of the app, is there a way to solve this?

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  • Show data relationship in gridview with dropdownlist or similar?

    - by Anders Svensson
    I have data coming from two tables with a foreign key relationship - one User table containing users of the web application, and one Page table containing details about pages visited by each user. I would like to be able to view these data in a gridview or the like on a page. It's easy enough to just show the User table data like so (I'm using the Entity Framework and LINQ): UserDBEntities context = new UserDBEntities(); GridView1.DataSource = from user in context.UserSet select new { user.Ip, user.Count, user.Description, user.Referer }; GridView1.DataBind(); But how can I show the Page details? I'm not bent on any particular way of showing it, but the only idea I've been able to come up with is to have a dropdown list for each user in a column. But I can't figure out how to get the page data into such a dropdown list. The tables are associated with the primary/foreign key UserID. Any ideas would be welcome (dropdownlist solution or other)!

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  • Serialising my JSON output problem in JQuery

    - by davykiash
    Am trying to validate my form using an AJAX call $("#button").click(function() { $.ajax({ type: "POST", url: "<?php echo $this->baseUrl() ?>/expensetypes/async", data: 'fs=' + JSON.stringify($('#myform').serialize(true)), contentType: "application/json; charset=utf-8", dataType: "json" }); }); On my controller my code is as follows //Map the form from the client-side call $myFormData = Zend_Json::decode($this->getRequest()->getParam("fs") ,Zend_Json::TYPE_ARRAY); $form = new Form_Expensetypes(); $form->isValid($myFormData); However from firebug my output is as follows fs="id=&expense_types_code=AAA&expense_types_desc=CCCC&expense_types_linkemail=XXXX&expense_types_budgetamount=22222&expense_types_budgetperiod=22222" What I expect is something similar to fs{"expense_types_code":"AAA","expense_types_desc":"CCCC","expense_types_linkemail":"XXXX","expense_types_budgetamount":"22222"} How do I achieve this type of serialisation?

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  • EF Stored Procedure Complex Type

    - by Web Dev
    I am using EF4. I am somewhat confused on on the Entity Framework Complex name. When I go to Functional Import of a Stored Procedure name and it ask me to type in the Complex name, is that supposed to be the name of of a class that can handle that output. For examle, say if my stored procedure returns FirstName, LastName. Is the Complex name supposed to be a class that can handle that output in this case PersonName? public class PersonName { public string FirstName {get; set;} public string LastName {get;set} }

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  • How to use the Zend_Log instance that was created using the Zend_Application_Resource_Log in a model

    - by Alex
    Our Zend_Log is initialized by only adding the following lines to application.ini resources.log.stream.writerName = "Stream" resources.log.stream.writerParams.mode = "a" So Zend_Application_Resource_Log will create the instance for us. We are already able to access this instance in controllers via the following: public function getLog() { $bootstrap = $this->getInvokeArg('bootstrap'); //if (is_null($bootstrap)) return false; if (!$bootstrap->hasPluginResource('Log')) { return false; } $log = $bootstrap->getResource('Log'); return $log; } So far, so good. Now we want to use the same log instance in model classes, where we can not access the bootstrap. Our first idea was to register the very same Log instance in Zend_Registry to be able to use Zend_Registry::get('Zend_Log') everywhere we want: in our Bootstrap class: protected function _initLog() { if (!$this->hasPluginResource('Log')) { throw new Zend_Exception('Log not enabled'); } $log = $this->getResource('Log'); assert( $log != null); Zend_Registry::set('Zend_Log', $log); } Unfortunately this assertion fails == $log IS NULL --- but why?? It is clear that we could just initialize the Zend_Log manually during bootstrapping without using the automatism of Zend_Application_Resource_Log, so this kind of answers will not be accepted.

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  • Zend_Form: Is this really the way we should be doing things?

    - by Francis Daigle
    OK. I understand how to use Zend_Form and it's implementation of the decorator pattern. My question is, is this the best way to be going about creating forms? Shouldn't a documents forms be left to to the front-end rather than generating forms programmatically? Doesn't this kinda violate the whole idea of keeping things separate? I mean, really, even providing that you have a good understanding of the methodology being employed, does it really save one that much time? I guess what I'm looking for is some guidance as to what might be considered 'best practice'. I'm not saying that Zend_Form doesn't have it's place, I'm just wondering if it should be used in all cases (or not). And this has nothing to do with validation. I'm just thinking that something more akin to using the 'ViewScript' approach might be more appropriate in most cases. Your thoughts?

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