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  • Workaround for stopping propagation with live()?

    - by bobsoap
    I've run into the problem that has been addressed here without a workaround: I can't use stopPropagation() on dynamically spawned elements. I've tried creating a condition to exclude a click within the dimensions of the spawned element, but that doesn't seem to work at all. Here is what I got: 1) a large background element ("canvas") that is activated to be "sensitive to clicks on it" by a button 2) the canvas, if activated, catches all clicks on it and spawns a small child form ("child") within it 3) the child is positioned relative to the mouse click position. If the mouse click was on the right half of the canvas, the child will be positioned 200 pixels to the left of that spot. (On the right if the click was in the left half) 4) every new click on the canvas removes the existing child (if any) and spawns a new child at the new position (relative to the click) The problem: Since the spawned child element is on top of the canvas, a click on it counts as a click on the canvas. Even if the child is outside of the boundaries of the canvas, clicking on it will trigger the action as described in 4) again . This shouldn't happen. =========== CODE: The button to activate the canvas: $('a#activate').click(function(event){ event.preventDefault(); canvasActive(); }); I referenced the above to show you that the canvas click-catching is happening in a function. Not sure if this is relevant... This is the function that catches clicks on the canvas: function canvasActive() { $('#canvas').click(function(e){ e.preventDefault(); //get click position relative to canvas posClick = { x : Math.round(e.pageX - $(this).offset().left), y : Math.round(e.pageY - $(this).offset().top) }; //calculate child position if(posClick.x <= $canvas.outerWidth(false)/2) { posChild = { x: posClick.x + 200, //if dot is on the left side of canvas y: posClick.y }; } else { posChild = { x: posClick.x - 600, //if dot is on the right y: posClick.y }; } $(this).append(markup); //markup is just the HTML for the child }); } I left out the unimportant stuff. The question is: How can I prevent a click inside of a spawned child from executing the function? I tried getting the child's dimensions and doing something like "if posClick is within this range, don't do anything" - but I can't seem to get it right. Perhaps someone has come across this dilemma before. Any help is appreciated.

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  • question regarding pointer in c language

    - by din
    char *sample = "String Value"; &sample is a pointer to the pointer of "String Value" is the above statement right? If the above statement right, what is the equivalent of &sample if my declaration is char sample[] = "String Value"

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  • hi this is my css horizontal menu i need the submeus for this?

    - by kalaivani
    /* CSS Document */ . rhm1{ width:780px; height:64px; margin:0 auto; background:url(images/rhm1_bg.g if) repeat-x; } .rhm1-left{ background:url(images/rhm1_l.gi f) no-repeat; width:15px; height:64px; float:left; } .rhm1-right{ background:url(images/rhm1_r.gi f) no-repeat; width:15px; height:64px; float:right; } .rhm1-bg{ background:url(images/rhm1_bg.g if) repeat-x; height:64px; } .rhm1-bg ul{ list-style:none; margin:0 auto; } .rhm1-bg li{ float:left; list-style:none; } .rhm1-bg li a{ float:left; display:block; color:#ffe8cc; text-decoration:none; font:12px 'Lucida Sans', sans-serif; font-weight:bold; padding:0 0 0 18px; height:64px; line-height:40px; text-align:center; cursor:pointer; } .rhm1-bg li a span{ float:left; display:block; padding:0 32px 0 18px; } .rhm1-bg li.current a{ color:#fff; background:url(images/rhm1_hove r_l.gif) no-repeat left 5px; } .rhm1-bg li.current a span{ color:#fff; background:url(images/rhm1_hove r_r.gif) no-repeat right 5px; } .rhm1-bg li a:hover{ color:#fff; background:url(images/rhm1_hove r_l.gif) no-repeat left 5px; } .rhm1-bg li a:hover span{ color:#fff; background:url(images/rhm1_hove r_r.gif) no-repeat right 5px; }

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  • Understanding Git's version control

    - by georgeliquor
    Is there a way to go through different commits on a file. Say I modified a file 5 times and I want to go back to change 2, after I already committed and pushed to a repository. In my understanding the only way is to keep many branches, have I got that right? If I'm right I'm gonna have hundreds of branches in a few days, so I'm probably not understanding it really. Could anyone clear that up please?

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  • Operator overloading in C++

    - by user265260
    If you overload - like operator-(), it is to be used to the left of the object, however overloading () like operator()() it is used to the right of the object. How do we know which operator is to be used on the left and which ones to be used on the right?

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  • Disable button when clicked and make other buttons enabled

    - by tito11
    i have three buttons what is the best way to disable button when clicked and make other two button enabled <Button Name="initialzeButton" Width="50" Height="25" Margin="460,0,0,0" HorizontalAlignment="Left" VerticalAlignment="Center" Click="initialzeButton_Click" Content="Start" Cursor="Hand" /> <Button Name="uninitialzeButton" Width="50" Height="25" Margin="0,0,64,0" HorizontalAlignment="Right" VerticalAlignment="Center" Click="uninitialzeButton_Click" Content="Stop" Cursor="Hand" /> <Button Name="loadButton" Width="50" Height="25" Margin="0,0,9,0" HorizontalAlignment="Right" VerticalAlignment="Center" Click="loadButton_Click" Content="Load" Cursor="Hand" />

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  • circular shift c

    - by simion
    I am doing some past papers and noticed a question where i have to shift the int one place to the right and return it i no in java i can just return n 1; is this possible in c? or is there a typically more compelx way of doing it :D. The method we were given is as follows // Return n after a right circular 1-bit shift unsigned int right_circular_shift_1(unsigned int n) {

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  • how do you setup apache web server in netbeans 6.8?

    - by dde
    I'd like to debug PHP apps, but I want to setup Apache web server (httpd.exe). I right clicked SERVERS, Add Server..., then noticed there is no option for httpd.exe, just for Glashfiish, JBoss, Apache Tomcat, and some other servers. So, how can I add Apache Web Server (right from within the IDE just like other servers), and then properly debug PHP apps?

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  • Two List Boxes side by side and stretchable

    - by Ilya Biryukov
    I have two list boxes like show below, side by side. They both have anchors on top, bottom, left and right. When I stretch the window the left listbox grows over the right one. While I want the margin between them to stay and for both listboxes to expand evenly. Is there anyway to achieve this? Thanks!

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  • Incorrect output on changing sequence of declarations

    - by max
    Writing C++ code to implement Sutherland-Hodgeman polygon clipping. This order of declaration of these 2 statements gives correct output, reverse does not. int numberOfVertices = 5; Point pointList[] = { {50,50}, {200,300}, {310,110}, {130,90}, {70,40} }; I am passing the polygon vertex set to clippers in order - LEFT, RIGHT, TOP, BOTTOM. The exact error which comes when the declarations are reversed is that the bottom clipper, produces an empty set of vertices so no polygon is displayed after clipping. Correct: Incorrent: Confirmed by outputting the number of vertices produced after each pass: Correct: Incorrect: What is the reason for this error? Code: #include <iostream> #include <GL/glut.h> #define MAXVERTICES 10 #define LEFT 0 #define RIGHT 1 #define TOP 2 #define BOTTOM 3 using namespace std; /* Clipping window */ struct Window { double xmin; double xmax; double ymin; double ymax; }; struct Point { double x; double y; }; /* If I interchange these two lines, the code doesn't work. */ /**************/ int numberOfVertices = 5; Point pointList[] = { {50,50}, {200,300}, {310,110}, {130,90}, {70,40} }; /**************/ const Window w = { 100, 400, 60, 200 }; /* Checks whether a point is inside or outside a window side */ int isInside(Point p, int side) { switch(side) { case LEFT: return p.x >= w.xmin; case RIGHT: return p.x <= w.xmax; case TOP: return p.y <= w.ymax; case BOTTOM: return p.y >= w.ymin; } } /* Calculates intersection of a segment and a window side */ Point intersection(Point p1, Point p2, int side) { Point temp; double slope, intercept; bool infinite; /* Find slope and intercept of segment, taking care of inf slope */ if(p2.x - p1.x != 0) { slope = (p2.y - p1.y) / (p2.x - p1.x); infinite = false; } else { infinite = true; } intercept = p1.y - p1.x * slope; /* Calculate intersections */ switch(side) { case LEFT: temp.x = w.xmin; temp.y = temp.x * slope + intercept; break; case RIGHT: temp.x = w.xmax; temp.y = temp.x * slope + intercept; break; case TOP: temp.y = w.ymax; temp.x = infinite ? p1.x : (temp.y - intercept) / slope; break; case BOTTOM: temp.y = w.ymin; temp.x = infinite ? p1.x : (temp.y - intercept) / slope; break; } return temp; } /* Clips polygon against a side, updating the point list (called once for each side) */ void clipAgainstSide(int sideToClip) { int i, j=0; Point s,p; Point outputList[MAXVERTICES]; /* Main algorithm */ s = pointList[numberOfVertices-1]; for(i=0 ; i<numberOfVertices ; i++) { p = pointList[i]; if(isInside(p, sideToClip)) { /* p inside */ if(!isInside(s, sideToClip)) { /* p inside, s outside */ outputList[j] = intersection(p, s, sideToClip); j++; } outputList[j] = p; j++; } else if(isInside(s, sideToClip)) { /* s inside, p outside */ outputList[j] = intersection(s, p, sideToClip); j++; } s = p; } /* Updating number of points and point list */ numberOfVertices = j; /* ERROR: In last call with BOTTOM argument, numberOfVertices becomes 0 */ /* all earlier 3 calls have correct output */ cout<<numberOfVertices<<endl; for(i=0 ; i<numberOfVertices ; i++) { pointList[i] = outputList[i]; } } void SutherlandHodgemanPolygonClip() { clipAgainstSide(LEFT); clipAgainstSide(RIGHT); clipAgainstSide(TOP); clipAgainstSide(BOTTOM); } void init() { glClearColor(1,1,1,0); glMatrixMode(GL_PROJECTION); gluOrtho2D(0,1000,0,500); } void display() { glClear(GL_COLOR_BUFFER_BIT); /* Displaying ORIGINAL box and polygon */ glColor3f(0,0,1); glBegin(GL_LINE_LOOP); glVertex2i(w.xmin, w.ymin); glVertex2i(w.xmin, w.ymax); glVertex2i(w.xmax, w.ymax); glVertex2i(w.xmax, w.ymin); glEnd(); glColor3f(1,0,0); glBegin(GL_LINE_LOOP); for(int i=0 ; i<numberOfVertices ; i++) { glVertex2i(pointList[i].x, pointList[i].y); } glEnd(); /* Clipping */ SutherlandHodgemanPolygonClip(); /* Displaying CLIPPED box and polygon, 500px right */ glColor3f(0,0,1); glBegin(GL_LINE_LOOP); glVertex2i(w.xmin+500, w.ymin); glVertex2i(w.xmin+500, w.ymax); glVertex2i(w.xmax+500, w.ymax); glVertex2i(w.xmax+500, w.ymin); glEnd(); glColor3f(1,0,0); glBegin(GL_LINE_LOOP); for(int i=0 ; i<numberOfVertices ; i++) { glVertex2i(pointList[i].x+500, pointList[i].y); } glEnd(); glFlush(); } int main(int argc, char** argv) { glutInit(&argc, argv); glutInitDisplayMode(GLUT_SINGLE | GLUT_RGB); glutInitWindowSize(1000,500); glutCreateWindow("Sutherland-Hodgeman polygon clipping"); init(); glutDisplayFunc(display); glutMainLoop(); return 0; }

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  • Are comonads a good fit for modeling the Wumpus world?

    - by Tim Stewart
    I'm trying to find some practical applications of a comonad and I thought I'd try to see if I could represent the classical Wumpus world as a comonad. I'd like to use this code to allow the Wumpus to move left and right through the world and clean up dirty tiles and avoid pits. It seems that the only comonad function that's useful is extract (to get the current tile) and that moving around and cleaning tiles would not use be able to make use of extend or duplicate. I'm not sure comonads are a good fit but I've seen a talk (Dominic Orchard: A Notation for Comonads) where comonads were used to model a cursor in a two-dimensional matrix. If a comonad is a good way of representing the Wumpus world, could you please show where my code is wrong? If it's wrong, could you please suggest a simple application of comonads? module Wumpus where -- Incomplete model of a world inhabited by a Wumpus who likes a nice -- tidy world but does not like falling in pits. import Control.Comonad -- The Wumpus world is made up of tiles that can be in one of three -- states. data Tile = Clean | Dirty | Pit deriving (Show, Eq) -- The Wumpus world is a one dimensional array partitioned into three -- values: the tiles to the left of the Wumpus, the tile occupied by -- the Wumpus, and the tiles to the right of the Wumpus. data World a = World [a] a [a] deriving (Show, Eq) -- Applies a function to every tile in the world instance Functor World where fmap f (World as b cs) = World (fmap f as) (f b) (fmap f cs) -- The Wumpus world is a Comonad instance Comonad World where -- get the part of the world the Wumpus currently occupies extract (World _ b _) = b -- not sure what this means in the Wumpus world. This type checks -- but does not make sense to me. extend f w@(World as b cs) = World (map world as) (f w) (map world cs) where world v = f (World [] v []) -- returns a world in which the Wumpus has either 1) moved one tile to -- the left or 2) stayed in the same place if the Wumpus could not move -- to the left. moveLeft :: World a -> World a moveLeft w@(World [] _ _) = w moveLeft (World as b cs) = World (init as) (last as) (b:cs) -- returns a world in which the Wumpus has either 1) moved one tile to -- the right or 2) stayed in the same place if the Wumpus could not move -- to the right. moveRight :: World a -> World a moveRight w@(World _ _ []) = w moveRight (World as b cs) = World (as ++ [b]) (head cs) (tail cs) initWorld = World [Dirty, Clean, Dirty] Dirty [Clean, Dirty, Pit] -- cleans the current tile cleanTile :: Tile -> Tile cleanTile Dirty = Clean cleanTile t = t Thanks!

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  • Can I write a test without any assert in it ?

    - by stratwine
    Hi, I'd like to know if it is "ok" to write a test without any "assert" in it. So the test would fail only when an exception / error has occured. Eg: like a test which has a simple select query, to ensure that the database configuration is right. So when I change some db-configuration, I re-run this test and check if the configuration is right. ? Thanks!

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  • Optimal setup for Doxygen in a large multi-application COM project

    - by John
    A system has up to 100 VC++ projects, each spitting out a DLL or EXE. In addition there are many COM components with IDL and generated .h/.c files. What's 'the right way' or at least a good way to organise this with Doxygen? One overall doxy project or one per project/solution? And what's the right way to handle COM, which has generated code and a lot of 'fluff' that will bloat generated HTML files.

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  • traverse a binary decison tree using python?

    - by kaushik
    how to traverse a binary decision tree using python language. given a tree,i want know how can we travesre from root to required leaf the feature of the required leaf are given in an dictionary form assume and have to traverse from root to leaf answering the questions at each node with the details given in feature list.. the decision tree node has format ((question)(left tree)(right tree)) while traversing it should answer question at each node and an choose left or right and traverse till leaf?

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  • How to provide metadata tags,keywords to Windows and fill properties page for a custom file format?

    - by Mode
    Hi, My application uses its own file format (compressed SQLite databases) to store user created data. 1) I would like to know how to provide keywords, tags to Windows so that Vista search function can include my file format when indexing. 2) I would like to provide a properties page like you see when you right click a Microsoft Word document and select properties. Kindly point me in the right direction. Thank you.

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  • XUL - Access to image information

    - by Murali
    Hello All, I trying to figure out how to write a Firefox extension that would give image information when i right-click on the image. Basically, I want image path when user right-clicks on the image. Any help would be greatly appreciated. Thanks.

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  • Is a point inside or outside a polygon which is on the surface of a globe

    - by richard
    How do I determine if a point is inside or outside a polygon that lies on the the surface of the earth? The inside of the polygon can be determined via the right hand rule, ie. the inside of the polygon is on your right hand side when you walk around the polygon. The polygon may Circle either pole Cross the 180 longitude Cover more than 50% of the globe As the globe is a sphere the normal ray crossing algorithms do not work correctly.

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  • Implement two lists in ExtJS

    - by Anandan
    Hi, I am new to ExtJS. I want to implement two tables. First one will have list of possible items to select. Second one can be empty. I will have 4 buttons in between the two tables as "move this item left", "move all to left", "move all to right" and "move this to right". Which component should i use to implement this? Regards, Anandan

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