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  • php, mySQL & AJAX: Unable to use sessions across the scripts in the same domain

    - by Devner
    Hi all, I have the following pages: page1.php, page2.php and page3.php. Code in each of them is as below CODE: page1.php <script type="text/javascript"> $(function(){ $('#imgID').upload({ submit_to_url: "page2.php", file_name: 'myfile1', description : "Image", limit : 1, file_types : "*.jpg", }) }); </script> <body> <form action="page3.php" method="post" enctype="multipart/form-data" name="frm1" id="frm1"> //Some other text fields <input type="submit" name="submit" id="submit" value="Submit" /> </form> </body> page2.php <?php session_start(); $a = $_SESSION['a']; $b = $_SESSION['b']; $c = $_SESSION['c']; $res = mysql_query("SELECT col FROM table WHERE col1 = $a AND col2 = $b AND col3 = $c LIMIT 1"); $num_rows = mysql_num_rows($res); echo $num_rows; //echos 0 when in fact it should have been 1 because the data in the Session exists. //Ok let's proceed further //... Do some stuff... //Store some more values and create new session variables (and assume that page1.php is going to be able to use it) $_SESSION['d'] = 'd'; $_SESSION['e'] = 'e'; $_SESSION['f'] = 'f'; if (move_uploaded_file($_FILES['file']['tmp_name'], $file)) { echo "success"; } else { echo "error ".$_FILES['file']['error']; } ?> page3.php <?php session_start(); if( isset($_POST['submit']) ) { //These sessions are non-existent although the AJAX request //to page2.php may have created them when called via AJAX from within page1.php echo $_SESSION['d'].$_SESSION['e'].$_SESSION['f']; ?> } ?> As the code says it I am posting some info via AJAX call from page1.php to page2.php. page2.php is supposed to be able to use the session values from page1.php i.e. $_SESSION['a'], $_SESSION['b'] and $_SESSION['c'] but it does not. Why? How can I fix this? page2.php is creating some more sessions after some processing is done and a response is sent back to page1.php. The submit button of the form on page1.php is hit and the page gets POST'ed to page3.php. But when the SESSION info that gets created in page2.php is echoed, it's blank signifying that SESSIONS from page2.php are not used. How can I fix this? I looked over a lot of information and have spent about 50 hours trying to do different things with my scripts before arriving at the above conclusions. My app. is custom made using function (not OOPS) and does not use any PHP frameworks & I am not even about to use any as my knowledge of OOP concepts is limited any many frameworks are object oriented. I came across race conditions, but the solutions provided don't help too much. One more solution of using DB to hold sessions and seek and retrieve from DB is the last thing on my mind and I really want to avoid creating table, coding and maintaining code for a task as simple as just keeping sessions across pages in the same domain. So my request is: Is there a way that I can solve the above problem(s) via simple coding in present conditions? Any help is appreciated. Thank you.

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  • Single Column Multiple Filter In Mysql Intersection

    - by Jeebus
    Here is a table CarID| Attribute | Value 1 | Color | Red 2 | Color | Blue 3 | Color | Red 1 | Type | Coupe 2 | Type | Hatch Back 3 | Type | Coupe 3 | Make | Honda 2 | Make | Toyota 1 | Make | Ford Now I would like to run a filter Like Select * From Cars WHERE (Attribute = Color AND Value = Red) AND (Attribute = Make AND Value = Honda).... and Hope to get the CarID as 3 ! This is simple case of Intersection of 2 queries but I don't know how to get it done in a single query. Any help appriciated.

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  • How to match multiple field in mySQL

    - by Mint
    Im trying to match forum_id with several different forum_id's, something like forum_id = 5,7,12,43,63,78 I currently have this code: SELECT topic_title, topic_id, forum_id FROM $MYSQL_TOPIC WHERE topic_title LIKE '%%%s%%' AND forum_id = 5 LIMIT 50 (using mysql_real_escape_string and sprintf) I tried: forum_id = 5 OR 7 forum_id = 5|7 forum_id = 5 AND 7 forum_id = 5 & 7 But none of them will match them all and therefore search though them all.

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  • mySQL Query JOIN in same table

    - by jeerose
    Table structure goes something like this: Table: Purchasers Columns: id | organization | city | state Table: Events Columns: id | purchaser_id My query: SELECT purchasers.*, events.id AS event_id FROM purchasers INNER JOIN events ON events.purchaser_id = purchasers.id WHERE purchasers.id = '$id' What I would like to do, is obviously to select entries by their id from the purchasers table and join from events. That's the easy part. I can also easily to another query to get other purchasers with the same organization, city and state (there are multiples) but I'd like to do it all in the same query. Is there a way I can do this? In short, grab purchasers by their ID but then also select other purchasers that have the same organization, city and state. Thanks.

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  • checkbox, php and update mysql!

    - by Ronnie Chester Lynwood
    Hello now I got this form. i get values with "while": mysql_query("select * from mp3 where aktif = '0'"); <form name="form" method="post" action=""> <input type="text" size="10" name="id" value="<?=$haciosman['id']?>" /> <input type="text" name="baslik" value="<?=$haciosman['baslik']?> <textarea name="sarkisozu"><?=$haciosman['sarkisozu']?></textarea> <input type="text" name="a3" value="<?=$haciosman['ekleyen']?"> <input type="checkbox" name="onay[]" /> <input type="submit" name="0" id="0" value="Onayla" /> <form> and updating values with: <? if (isset($_POST['onay'])) { $cikti = mysql_query("update mp3 set aktif = '1', baslik = '$_POST[baslik]' where id = '$_POST[id]'"); if ($cikti) { echo "islem tamam"; exit; } } ?> but this code only updating only one value. how can i let it update multiple values?

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  • Specific query in Mysql

    - by Radhe
    I have two tables reports and holidays. reports: (username varchar(30),activity varchar(30),hours int(3),report_date date) holidays: (holiday_name varchar(30), holiday_date date) select * from reports gives +----------+-----------+---------+------------+ | username | activity | hours | date | +----------+-----------+---------+------------+ | prasoon | testing | 3 | 2009-01-01 | | prasoon | coding | 4 | 2009-01-03 | | prasoon | designing| 2 | 2009-01-04 | | prasoon | coding | 4 | 2009-01-06 | +----------+-----------+---------+------------+ select * from holidays gives +--------------+---------------+ | holiday_name | holiday_date | +--------------+---------------+ | Diwali | 2009-01-02 | | Holi | 2009-01-05 | +--------------+---------------+ Is there any way by which I can output the following? +-------------+-----------+---------+-------------------+ | date | activity | hours | holiday_name | +-------------+-----------+---------+-------------------+ | 2009-01-01 | testing | 3 | | | 2009-01-02 | | | Diwali | | 2009-01-03 | coding | 4 | | | 2009-01-04 | designing| 2 | | | 2009-01-05 | | | Holi | | 2009-01-06 | coding | 4 | | +-------------+-----------+---------+-------------------+

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  • PHP mySQL - select unique value that not being used from dirrefent table

    - by apis17
    Updates : Please see below i have table: data +-----------------------+--------------+-----------+ | State | d_country | d_postcode| +-----------------------+--------------+-----------+ | State1 | Country1 | 1111 | | State2 | Country2 | 2222 | | State3 | Country3 | 3333 | | State4 | Country4 | 4444 | +-----------------------+--------------+-----------+ And another table: user +-----------------------+--------------+-----------+ | Name | u_country | u_postcode| +-----------------------+--------------+-----------+ | Name1 | Country3 | 3333 | | Name2 | Country5 | 5555 | | Name3 | | 6666 | | Name4 | Country6 | 6666 | | Name5 | Country6 | 6666 | +-----------------------+--------------+-----------+ What SQL should i use to: Determine the number (count) of country that are not listed on table data. For example u_postcode is not listed in d_postcode is 5555 and 6666. It will return 2. List down name and what country not available in table data yet. Updates I want to use grouping to filter postcode and make Name3 and Name4 as different rows. For example: +-----------------------+--------------+-----------+ | Name | u_country | u_postcode| +-----------------------+--------------+-----------+ | Name2 | Country5 | 5555 | | Name3 | | 6666 | | Name4 | Country6 | 6666 | +-----------------------+--------------+-----------+ Any possible idea?

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  • Tricky MySQL Query for messaging system in Rails - Please Help

    - by ole_berlin
    Hi, I'm writing a facebook style messaging system for a Rails App and I'm having trouble selecting the Messages for the inbox (with will_paginate). The messages are organized in threads, in the inbox the most recent message of a thread will appear with a link to it's thread. The thread is organized via a parent_id 1-n relationship with itself. So far I'm using something like this: class Message < ActiveRecord::Base belongs_to :sender, :class_name => 'User', :foreign_key => "sender_id" belongs_to :recipient, :class_name => 'User', :foreign_key => "recipient_id" has_many :children, :class_name => "Message", :foreign_key => "parent_id" belongs_to :thread, :class_name => "Message", :foreign_key => "parent_id" end class MessagesController < ApplicationController def inbox @messages = current_user.received_messages.paginate :page => params[:page], :per_page => 10, :order => "created_at DESC" end end That gives me all the messages, but for one thread the thread itself and the most recent message will appear (and not only the most recent message). I can also not use the GROUP BY clause, because for the thread itself (the parent so to say) the parent_id = nil of course. Anyone got an idea on how to solve this in an elegant way? I already thought about adding the parent_id to the parent itself and then group by parent_id, but I'm not sure if that works. Thanks

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  • change column widths in mysql query

    - by addi
    <?php // Connection Database $search = $_POST ['Search']; mysql_connect("xxxxxx", "xxxxxxxxx", "xxxxxx") or die ("Error Connecting to Database"); mysql_select_db("xxxxxx") or die('Error'); $data = mysql_query("SELECT* FROM course WHERE MATCH (CourseName, CourseDescription, CourseLeader) AGAINST ('". $search ."')") or die (mysql_error()); Print "<table border cellpadding=3>"; while($info = mysql_fetch_array( $data )) { Print "<tr>"; Print "<th>Course Name:</th> <td>".$info['CourseName'] . "</td> "; Print "<th>Course Description:</th><td>".$info['CourseDescription'] . "</td> "; Print "<th>Course Leader:</th><td>".$info['CourseLeader'] . " </td></tr>"; } Print "</table>"; ?> In my php code I print the columns CourseName, CourseDescription, CourseLeader after a search, as a resultset. CourseDescription has a lot of text, how do I print it all? is there a way to change the column widths?

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  • mysql whats wrong with this query?

    - by Hailwood
    I'm trying to write a query that selects from four tables campaignSentParent csp campaignSentEmail cse campaignSentFax csf campaignSentSms css Each of the cse, csf, and css tables are linked to the csp table by csp.id = (cse/csf/css).parentId The csp table has a column called campaignId, What I want to do is end up with rows that look like: | id | dateSent | emailsSent | faxsSent | smssSent | | 1 | 2011-02-04 | 139 | 129 | 140 | But instead I end up with a row that looks like: | 1 | 2011-02-03 | 2510340 | 2510340 | 2510340 | Here is the query I am trying SELECT csp.id id, csp.dateSent dateSent, COUNT(cse.parentId) emailsSent, COUNT(csf.parentId) faxsSent, COUNT(css.parentId) smsSent FROM campaignSentParent csp, campaignSentEmail cse, campaignSentFax csf, campaignSentSms css WHERE csp.campaignId = 1 AND csf.parentId = csp.id AND cse.parentId = csp.id AND css.parentId = csp.id; Adding GROUP BY did not help, so I am posting the create statements. csp CREATE TABLE `campaignsentparent` ( `id` int(11) NOT NULL AUTO_INCREMENT, `campaignId` int(11) NOT NULL, `dateSent` datetime NOT NULL, `account` int(11) NOT NULL, `status` varchar(15) NOT NULL DEFAULT 'Creating', PRIMARY KEY (`id`) ) ENGINE=MyISAM AUTO_INCREMENT=2 DEFAULT CHARSET=latin1 cse/csf (same structure, different names) CREATE TABLE `campaignsentemail` ( `id` int(11) NOT NULL AUTO_INCREMENT, `parentId` int(11) NOT NULL, `contactId` int(11) NOT NULL, `content` text, `subject` text, `status` varchar(15) DEFAULT 'Pending', PRIMARY KEY (`id`) ) ENGINE=MyISAM AUTO_INCREMENT=140 DEFAULT CHARSET=latin1 css CREATE TABLE `campaignsentsms` ( `id` int(11) NOT NULL AUTO_INCREMENT, `parentId` int(11) NOT NULL, `contactId` int(11) NOT NULL, `content` text, `status` varchar(15) DEFAULT 'Pending', PRIMARY KEY (`id`) ) ENGINE=MyISAM AUTO_INCREMENT=141 DEFAULT CHARSET=latin1

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  • Displaying data from a linked table and displaying it as a list with HTML/PHP/MySQL

    - by user1672694
    I have three tables. students studentID | FirstName | LastName | Email | Form course CCode | Title courseenrolement courseenrolementid | studentID | ccode | complete | scode With the website, I have a page where I can view all the current enrolements and I wish to be able to view the list displaying the first name, surname and course title. I know I could do it with the following SQL (for the names): SELECT FirstName, LastName FROM student, courseenrolement WHERE courseenrolement.studentID = student.studentID But I am unsure how to get this to work using HTML/PHP. At present I only know how to display the studentID and CCode from the courseenrolement table using the following code: <ul> <?php foreach ($courseenrolements as $ce): ?> <li> <form action="" method="post"> <div> <?php htmlout($ce['studentID']); ?> <?php htmlout($ce['CCode']); ?> <input type="hidden" name="courseenrolementid" value="<?php echo $ce['courseenrolementid']; ?>"> <input type="submit" name="action" value="Edit"> <input type="submit" name="action" value="Delete"> </div> </form> </li> <?php endforeach; ?> </ul> which displays this: But I would like the names and course title. I managed to get it to show the names etc in the dropdown on the 'Add new' form, so I would assume it will be similar, but just unsure on how exactly. Thanks in advance

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  • MySQL Subquery LIMIT

    - by atif089
    As the title says, I wanted a workaround for this... SELECT comments.comment_id, comments.content_id, comments.user_id, comments.`comment`, comments.comment_time, NULL FROM comments WHERE (comments.content_id IN (SELECT content.content_id FROM content WHERE content.user_id = 1 LIMIT 0, 10)) Cheers

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  • MySQL Select statement Where table1.id != table2.id

    - by Michael
    I have a table of data which has posts, then I have a separate table of data which has deleted posts. What happens when a post is deleted is that it's ID get's added to the deleted table rather than removing the post entry. What is a clean efficient way of selecting all the posts from the posts table without selecting the ones that have their ID in the deleted table

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  • mysql select from multiple table

    - by Loon Yew
    I have 3 tables with values like below tbl_product recID pID price colour 1 BDPLA-0001 1.23 White 2 BDPLA-0002 2.23 Black 3 BDPLA-0003 2.28 Blue tbl_product_size recID pID size stock 1 1 2.0cm 10 2 1 3.0cm 20 3 2 2.5cm 30 4 3 3.6cm 40 5 3 3.8cm 50 tbl_order_details recID pID quantity size 201 BDPLA-0001 5 2.0cm 202 BDPLA-0002 10 2.5cm tbl_product.recID = tbl_product_size.pID tbl_product.pID = tbl_order_details.pID how can i combine the tables and produce result like this pID size stock quantity price BDPLA-0001 2.0cm 10 5 1.23 BDPLA-0001 3.0cm 20 null 1.23 BDPLA-0002 2.5cm 30 10 2.23 BDPLA-0003 3.6cm 40 null 2.28 BDPLA-0003 3.8cm 50 null 2.28

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  • Php, mysql selection

    - by cosy
    I have this table ATTRIBUTE id name um 12 capacity MB;GB;TB And this table2 : id id_attribute id_product name value um 1 12 40 hdd maxtor 30 GB 2 12 41 hdd maxtor 40 GB 3 12 42 hdd y 1 TB How can i select from table2 in this order : 30GB 40GB 1TB? Thanks a lot!

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  • Update the rank in a MySQL Table

    - by sammichy
    I have the following table structure for a table Player Table Player { Long playerID; Long points; Long rank; } Assuming that the playerID and the points have valid values, can I update the rank for all the players based on the number of points in a single query? If two people have the same number of points, they should tie for the rank.

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  • mysql data type confusion

    - by zen
    So this is more of a generalized question about MySQLs data types. I'd like to store a 5-digit US zip code (zip_code) properly in this example. A county has 10 different cities and 5 different zip codes. city | zip code -------+---------- city 0 | 33333 city 1 | 11111 city 2 | 22222 city 3 | 33333 city 4 | 44444 city 5 | 55555 city 6 | 33333 city 7 | 33333 city 8 | 44444 city 9 | 22222 I would typically structure a table like this as varchar(50), int(5) and not think twice about it. (1) If we wanted to ensure that this table had only one of 5 different zip codes we should use the enum data type, right? Now think of a similar scenario on a much larger scale. In a state, there are five-hundred cities with 418 different zip codes. (2) Should I store 418 zip codes as an enum data type OR as an int and create another table to reference?

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  • Encoding issue with form and HTML Purifier / MySQL

    - by Andrew Heath
    Driving me nuts... Page with form is encoded as Unicode (UTF-8) via: <meta http-equiv="content-type" content="text/html; charset=utf-8"> entry column in database is text utf8_unicode_ci copying text from a Word document with " in it, like this: “1922.” is insta-fail and ends up in the database as â??1922.â?? (typing new data into the form, including " works fine... it's cut and pasting from Word...) PHP steps behind the scenes are: grab value from POST run through HTML Purifier default settings run through mysql_real_escape_string insert query into dbase Help?

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  • mysql - joining three tables with HAVING

    - by Qiao
    I have table: id name type where "type" is 1 or 2 I need to join this table with two other. Rows with "type = 1" should be joined with first table, and =2 with second. Something like SELECT * FROM tbl INNER JOIN tbl_1 ON tbl.name = tbl_1.name HAVING tbl.type = 1 INNER JOIN tbl_2 ON tbl.name = tbl_2.name HAVING tbl.type = 2 But it does not working. How it can be implemented?

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  • mysql GROUP_CONCAT

    - by user301766
    I want to list all users with their corropsonding user class. Here are simplified versions of my tables CREATE TABLE users ( user_id INT NOT NULL AUTO_INCREMENT, user_class VARCHAR(100), PRIMARY KEY (user_id) ); INSERT INTO users VALUES (1, '1'), (2, '2'), (3, '1,2'); CREATE TABLE classes ( class_id INT NOT NULL AUTO_INCREMENT, class_name VARCHAR(100), PRIMARY KEY (class_id) ); INSERT INTO classes VALUES (1, 'Class 1'), (2, 'Class 2'); And this is the query statement I am trying to use but is only returning the first matching user class and not a concatenated list as hoped. SELECT user_id, GROUP_CONCAT(DISTINCT class_name SEPARATOR ",") AS class_name FROM users, classes WHERE user_class IN (class_id) GROUP BY user_id; Actual Output +---------+------------+ | user_id | class_name | +---------+------------+ | 1 | Class 1 | | 2 | Class 2 | | 3 | Class 1 | +---------+------------+ Wanted Output +---------+---------------------+ | user_id | class_name | +---------+---------------------+ | 1 | Class 1 | | 2 | Class 2 | | 3 | Class 1, Class 2 | +---------+---------------------+ Thanks in advance

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  • I DISTINCTly hate MySQL (help building a query)

    - by Alex Mcp
    This is staight forward I believe: I have a table with 30,000 rows. When I SELECT DISTINCT 'location' FROM myTable it returns 21,000 rows, about what I'd expect, but it only returns that one column. What I want is to move those to a new table, but the whole row for each match. My best guess is something like SELECT * from (SELECT DISTINCT 'location' FROM myTable) or something like that, but it says I have a vague syntax error. Is there a good way to grab the rest of each DISTINCT row and move it to a new table all in one go?

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  • MySQL GROUP_CONCAT + IN() = missing data :-(

    - by Andrew Heath
    Example: Table: box boxID color 01 red 02 blue 03 green Table: boxHas boxID has 01 apple 01 pear 01 grapes 01 banana 02 lime 02 apple 02 pear 03 chihuahua 03 nachos 03 baby crocodile I want to query on the contents of each box, and return a table with each ID, color, and a column that concatenates the contents of each box, so I use: SELECT box.boxID, box.color, GROUP_CONCAT(DISTINCT boxHas.has SEPARATOR ", ") AS contents FROM box LEFT JOIN boxHas ON box.boxID=boxHas.boxID WHERE boxHas.has IN ('apple','pear') GROUP BY box.boxID ORDER BY box.boxID and I get the following table of results: boxID color contents 01 red apple, pear 02 blue apple, pear My question to you is: why isn't it listing ALL the has values in the contents column? Why is my WHERE statement also cropping my GROUP_CONCAT? The table I thought I was going to get is: boxID color contents 01 red apple, banana, grapes, pear 02 blue apple, lime, pear Although I want to limit my boxID results based upon the WHERE statement, I do not want to limit the contents field for valid boxes. :-/ Help?

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  • Java/MySQL: Working with data in classes

    - by skiwi
    What is the best way to deal with accessing/modifying tables in a database? I have read about the Data Access Object approach, but none of the resources I have found so far indicate a clear implementation of it. So assume you have a database with a table called accounts that has columns id, name, password and email. How would you properly access it within Java? I mean most people know how to do SQL statements, but that is not really the point. I hope people here can be of help. Regards.

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