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  • Using JavaScript's split to chop up a string and put it in two arrays

    - by Pieter
    I can use JavaScript's split to put a comma-separated list of items in an array: var mystring = "a,b,c,d,e"; var myarray = mystring.split(","); What I have in mind is a little more complicated. I have this dictionary-esque string: myvalue=0;othervalue=1;anothervalue=0; How do I split this so that the keys end up in one array and the values end up in another array?

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  • Javascript help - compare two dates in Euro (dd/MMM/yyyy) format

    - by Kettenbach
    Hi All, I am trying to compare to textbox values on an aspx form. Both the values represent dates. The are formatted like "dd/MMM/yyyy". How can I compare them in javascript to see if they are not equal and which one is greater etc... Does javascript have a date constructor for strings like this? Any tips would be appreciated. Thanks for the help. Cheers, ~ck in San Diego

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  • filter that uses elements from two arrays at the same time

    - by Gacek
    Let's assume we have two arrays of the same size - A and B. Now, we need a filter that, for a given mask size, selects elements from A, but removes the central element of the mask, and inserts there corresponding element from B. So the 3x3 "pseudo mask" will look similar to this: A A A A B A A A A Doing something like this for averaging filter is quite simple. We can compute the mean value for elements from A without the central element, and then combine it with a proper proportion with elements from B: h = ones(3,3); h(2,2) =0; h = h/sum(h(:)); A_ave = filter2(h, A); C = (8/9) * A_ave + (1/9) * B; But how to do something similar for median filter (medfilt2 or even better for ordfilt2)

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  • How can give third child div within one parent div

    - by Mubeen
    I have one Parent div. Top of the Parent div contains two child divs. How can i give third child div below the first child div <div class=parent1> <div class=child1>some text</div> /*this is in top left of the parent div */ <div class=child2>some text</div> /*this is in top right of the parent div */ <div class=child3>some text</div> /*how can i write css for this div come as left bottom*/

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  • How to calculate the time difference between two time fields , with respect to the date changes

    - by Tiru
    I want to calculate the time difference.I have three EditTexts , I want to input the times in the first two edittexts in HH:MM format. And then calculate the time difference and the result will show on third edittext field in same format. If the date changes, the time difference will calculate according that, i.e If first time = 23:00 and second time = 01:00 then, the time difference = 02:00 hours public class TimeCalculate extends Activity { private String mBlock; private String mBlockoff; private String mBlockon ; // String mHours, mMinutes; Date date1, date2; /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); EditText blockoff = (EditText) findViewById(R.id.blockoff); mBlockoff = blockoff.getText().toString(); EditText blockon = (EditText) findViewById(R.id.blockon); mBlockon = blockon.getText().toString(); SimpleDateFormat simpleDateFormat = new SimpleDateFormat("hh:mm"); try { date1 = simpleDateFormat.parse(mBlockoff); } catch (ParseException e) { // TODO Auto-generated catch block e.printStackTrace(); } try { date2 = simpleDateFormat.parse(mBlockon); } catch (ParseException e) { // TODO Auto-generated catch block e.printStackTrace(); } mBlock = getDifference(date1, date2); EditText block = (EditText) findViewById(R.id.block); block.setText(mBlock.toString()); } public static String getDifference(Date startTime, Date endTime) { if (startTime == null) return "corrupted"; Calendar startDateTime = Calendar.getInstance(); startDateTime.setTime(startTime); Calendar endDateTime = Calendar.getInstance(); endDateTime.setTime(endTime); long milliseconds1 = startDateTime.getTimeInMillis(); long milliseconds2 = endDateTime.getTimeInMillis(); long diff = milliseconds2 - milliseconds1; /*int hours = (int)diff / (60 * 60 * 1000); int minutes = (int) (diff / (60 * 1000)); minutes = minutes - 60 * hours; long seconds = diff / (1000); */ //timeDiff = DateUtils.formatElapsedTime(seconds); SimpleDateFormat simpleDateFormat = new SimpleDateFormat("HH:MM"); Date date = new Date(diff); return simpleDateFormat.format(date); } } I executed this code ,but gives error as Source not found.I think error at getDifference method.Please give any other logic

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  • Two Tables Serving as one Model in Rails

    - by matsko
    Is is possible in rails to setup on model which is dependant on a join from two tables? This would mean that for the the model record to be found/updated/destroyed there would need to be both records in both database tables linked together in a join. The model would just be all the columns of both tables wrapped together which may then be used for the forms and so on. This way when the model gets created/updated it is just one form variable hash that gets applied to the model? Is this possible in Rails 2 or 3?

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  • PHP pass associative array from one function to another wihle keeping keys intact

    - by veronica
    I have two functions and one array function A { $segments = array(); $segments['word']=$var1; $segments['word2']=$var2; $segments['word3']=$var3; return $segments; } function B { $someVar=$segments['word']; $someVar1=$segments['word']; $someVar2=$segments['word']; $vars['other_stuff']... return $vars; } but I am not passing $segments['word']...word3'] to the second function. I am passing $segments[0]; $segments[1]; etc... How can I pass the keys to second function $segments['word'] $segments['word1'] $segments['word2'] Thank you,

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  • VB.NET - Convert Unicode in one TB to Shift-JIS in another TB

    - by Yiu Korochko
    Trying to develop a text editor, I've got two textboxes, and a button below each one. When the button below textbox1 is pressed, it is supposed to convert the Unicode text (intended to be Japanese) to Shift-JIS. The reason why I am doing this is because the software VOCALOID2 only allows ANSI and Shift-JIS encoding text to be pasted into the lyrics system. Users of the application normally have their keyboard set to change to Japanese already, but it types in Unicode. How can I convert Unicode text to Shift-JIS when SJIS isn't available in the System.Text.Encoding types?

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  • display one-to-many relationship for a model in Django admin (list mode)

    - by theactiveactor
    In Django admin site, when listing all the objects for a given model, I know we can customize which columns get displayed for a ModelA via list_display Say that ModelA has a one-to-many relationship with ModelB. I would like to add another column on the listing page for ModelA, where each entry is a URL pointing to all objects of ModelB having a foreign key relationship on corresponding instance of Model A in that row. How can I achieve this customization with the admin app?

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  • How can you query for an object using one of its properties' id

    - by James Smith
    I have two entities, say, House and People, where multiple people can live in one house. It's a unidirectional link where each Person has a field for which House they belong to, so the Person table has a column named house_id. I need to be able to return all the Person objects who belong to a certain House, but I only have the id of the house. This can be done like this: House house = houseDAO.findById(houseId); List people = session.createCriteria(Person.class).add(Restrictions.eq("house", house)).list(); But since I don't need the house, that's adding an unnecessary query. I've tried to do: session.createCriteria(Person.class).add(Restrictions.eq("house_id", houseId)).list(); But that doesn't work because house_id is not a property, it's a database column. I could just add an sql restriction, but is there a hibernate way of doing this?

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  • Rotation of two objects in relation

    - by DMan
    I've got a two sprites- I'll say I have a swing and a person. The swing 'swings' back and forth as I passed a rotation variable into spriteBatch.Draw(). Now I want my person to 'sit' on the swing, and am not sure of how to approach it. Since I want a relative to the swing sprite, I tried personPos=swingPos, but that obviously doesn't work as the swing's position is always the same (it's anchored to a point and swings from there). How would I make the person sprite follow the swinging part of the swing sprite, if that makes any sense?

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  • Finding a small image in a bigger one

    - by tur1ng
    Given an image with a large dimension ( 1.000 x 1.000). What is a good approach to find a small image (e.g. 50 x 50) in the big one? The smaller image can be rotated and differ in the size, but only with a 1:1 ratio. It's not related to any programming language - I'm just interested in pattern recognition. Thank you.

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  • Double-tap or two single-taps?

    - by Jaka Jancar
    What is the time limit for two taps to be considered a double-tap, on the iPhone OS? // Edit: Why is this important? In order to handle single-tap and double-tap differently, Apple's guide says to do performSelector...afterDelay with some 'reasonable' interval on first tap (and cancel it later if the second tap is detected). The problem is that if the interval is too short (0.1), the single tap action will be performed even when double-tapping (if relying only on tapCount, that is). If it's too long (0.8), the user will be waiting unnecessarily for the single-tap to be recognized, when there is no possibility for a double-tap. It has to be exactly the correct number, in order to work optimally, but definitely not smaller, or there's a chance for bugs (simultaneous single-tap and double-tap).

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  • One hour difference in Python

    - by Joel
    Hello, I have a datetime.datetime property var. I would like to know if it is less than one hour of the current time. Something like var.hour<datetime.datetime.today().hour - 1 Problem with the above syntax is that datetime.datetime.today().hour returns a number such as "10" and it is not really a date comparation but more of a numbers comparation. What is the correct syntax? Thanks! Joel

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  • passing form values from one jsp to another

    - by shil
    hi i need to access form data given entered in one jsp in another.. this is how my code looks fisrt jsp: second jsp: <%=request.getParameter("firstame")% now this prints a null value.. what is the mistake here? how do i get to access the values in my second jsp?

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  • Multi-platform development from one computer

    - by iama
    I am planning to build a new development computer for both Windows & Linux platforms. On Windows, my development would be primarily in .NET/C#/IIS/MSSQL Server. On Linux—preferably Ubuntu—my development would be in Ruby and Python. I am thinking of buying a laptop with Windows 7 pre-installed with 4GB RAM, Intel Core 2 Duo, and 320 GB HD; running 2 VMs for both Windows and Linux development with the host OS as my work station. Of course, I would be running DBs and web servers on the respective platforms. Is this a typical setup? My only concern is running two VMs side by side. Not sure if this configuration would be optimal. Alternative would be to do my Windows development on the host Windows 7 OS. What are your thoughts?

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  • Laravel 4 - Using multiple paginators on one page

    - by Fry Farnsworth
    I've been googling for this question but can't find any good answers. I found that there is a method called setPageName() for the paginator but it only works when used like Paginator::setPageName('page'). I looked up the paginator in the Laravel API (http://laravel.com/api/class-Illuminate.Pagination.Environment.html) and the method is a public function just like setBaseUrl which I am currently using like $albums->setBaseUrl('/album/'); for instance I want to have a Photo paginator (?photoPage=n) and a Comment paginator (?commentPage=n). Is there any way that I can use two paginators that use different page names in the URL on one page, or at least call the setPageName() method like setBaseUrl()?

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  • How to merge data from two separate access 2007 databases

    - by DiegoMaK
    Hi, I have two identical databases with same structure, database a in computer a and database b in computer b. The data of database a*(a.accdb)* and database b*(b.accdb)* are different. then in database a i have for example ID:1, 2, 3 and in database B i Have ID:4,5,6 Then i need merge these databases data in only one database(a or b, doesn't matter) so the final database looks like. ID:1,2,3,4,5,6 I search an easy way to do this. because i have many tables. and do this by union query is so tedious. I search for example for a backup option for only data without scheme as in postgreSQl or many others RDBMS, but i don't see this options in access 2007. pd:only just table could be have duplicate values(I guess that pk doesn't allow copy a duplicate value and all others values will be copied well). if i wrong please correct me. thanks for your help.

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  • Is the set of data always normalized in one form or the other in Databases

    - by manugupt1
    Suppose I have a set of data, given the data and the relation schemas can I assume that the set of data is normalized in one form or the other. In my opinion raw data given, has to be normalized into some form. However a discussion with a friend has led to ask me this question here. To expound more on the question, I would say given a set of functional dependencies for a relation or table, is it guaranteed that the table would atleast be in 1NF if not others

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  • Fetch main model and translations in one query with globalize2

    - by J. Pablo Fernández
    Is there a way to fetch the model and the translations in one query when using globalize2? For example, having a model called Language which have two fields, code and name of which the second is translatable I do the following: en = Language.find_by_code("en") and it runs this query: SELECT SQL_NO_CACHE * FROM `languages` WHERE (`languages`.`code` = 'en') LIMIT 1 and when I do: en.name it runs: SELECT SQL_NO_CACHE * FROM `language_translations` WHERE (`language_translations`.language_id = 123 AND (`language_translations`.`locale` IN ('en','root'))) and if I do it again it'll re-run the query. Is there a way to fetch all the translated data in the first query? I've tried: en = Language.find_by_code("en", :joins => "JOIN language_translations ON language_translations.language_id = languages.id") but it made no difference. UPDATE: this is being discussed as an issue in globalize2: http://github.com/joshmh/globalize2/issues/#issue/33

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  • Interoperability between two AES algorithms

    - by lpfavreau
    Hello, I'm new to cryptography and I'm building some test applications to try and understand the basics of it. I'm not trying to build the algorithms from scratch but I'm trying to make two different AES-256 implementation talk to each other. I've got a database that was populated with this Javascript implementation stored in Base64. Now, I'm trying to get an Objective-C method to decrypt its content but I'm a little lost as to where the differences in the implementations are. I'm able to encrypt/decrypt in Javascript and I'm able to encrypt/decrypt in Cocoa but cannot make a string encrypted in Javascript decrypted in Cocoa or vice-versa. I'm guessing it's related to the initialization vector, nonce, counter mode of operation or all of these, which quite frankly, doesn't speak to me at the moment. Here's what I'm using in Objective-C, adapted mainly from this and this: @implementation NSString (Crypto) - (NSString *)encryptAES256:(NSString *)key { NSData *input = [self dataUsingEncoding: NSUTF8StringEncoding]; NSData *output = [NSString cryptoAES256:input key:key doEncrypt:TRUE]; return [Base64 encode:output]; } - (NSString *)decryptAES256:(NSString *)key { NSData *input = [Base64 decode:self]; NSData *output = [NSString cryptoAES256:input key:key doEncrypt:FALSE]; return [[[NSString alloc] initWithData:output encoding:NSUTF8StringEncoding] autorelease]; } + (NSData *)cryptoAES256:(NSData *)input key:(NSString *)key doEncrypt:(BOOL)doEncrypt { // 'key' should be 32 bytes for AES256, will be null-padded otherwise char keyPtr[kCCKeySizeAES256 + 1]; // room for terminator (unused) bzero(keyPtr, sizeof(keyPtr)); // fill with zeroes (for padding) // fetch key data [key getCString:keyPtr maxLength:sizeof(keyPtr) encoding:NSUTF8StringEncoding]; NSUInteger dataLength = [input length]; // See the doc: For block ciphers, the output size will always be less than or // equal to the input size plus the size of one block. // That's why we need to add the size of one block here size_t bufferSize = dataLength + kCCBlockSizeAES128; void* buffer = malloc(bufferSize); size_t numBytesCrypted = 0; CCCryptorStatus cryptStatus = CCCrypt(doEncrypt ? kCCEncrypt : kCCDecrypt, kCCAlgorithmAES128, kCCOptionECBMode | kCCOptionPKCS7Padding, keyPtr, kCCKeySizeAES256, nil, // initialization vector (optional) [input bytes], dataLength, // input buffer, bufferSize, // output &numBytesCrypted ); if (cryptStatus == kCCSuccess) { // the returned NSData takes ownership of the buffer and will free it on deallocation return [NSData dataWithBytesNoCopy:buffer length:numBytesCrypted]; } free(buffer); // free the buffer; return nil; } @end Of course, the input is Base64 decoded beforehand. I see that each encryption with the same key and same content in Javascript gives a different encrypted string, which is not the case with the Objective-C implementation that always give the same encrypted string. I've read the answers of this post and it makes me believe I'm right about something along the lines of vector initialization but I'd need your help to pinpoint what's going on exactly. Thank you!

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