How can I SELECT rows with MAX(Column value), DISTINCT by another column in SQL?
- by Kaptah
My table is:
id home datetime player
resource
---|-----|------------|--------|---------
1 | 10 | 04/03/2009 | john | 399
2 | 11 | 04/03/2009 | juliet | 244
5 | 12 | 04/03/2009 | borat | 555
3 | 10 | 03/03/2009 | john | 300
4 | 11 | 03/03/2009 | juliet | 200
6 | 12 | 03/03/2009 | borat | 500
7 | 13 | 24/12/2008 | borat | 600
8 | 13 | 01/01/2009 | borat | 700
I need to select each distinct "home" holding the maximum value of "datetime".
Result would be:
id home datetime player
resource
---|-----|------------|--------|---------
1 | 10 | 04/03/2009 | john | 399
2 | 11 | 04/03/2009 | juliet | 244
5 | 12 | 04/03/2009 | borat | 555
7 | 13 | 24/12/2008 | borat | 600
8 | 13 | 01/01/2009 | borat | 700
I have tried:
// 1 ..by the MySQL manual:
SELECT DISTINCT home, id, datetime as dt, player, resource
FROM topten t1
WHERE datetime = (SELECT MAX(t2.datetime) FROM topten t2
GROUP BY home )
GROUP BY daytime
ORDER BY daytime DESC
Doesn't work. Result-set has 130 rows although database holds 187.
Result includes some dublicates of 'home'.
// 2 ..join
SELECT s1.id, s1.home, s1.datetime, s1.player, s1.resource
FROM topten s1 JOIN
(SELECT id, MAX(datetime) AS dt
FROM topten
GROUP BY id) AS s2
ON s1.id = s2.id
ORDER BY daytime
Nope. Gives all the records.
// 3 ..something exotic:
With various results.
