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  • Parameters lost on login form submitted with post in JBoss

    - by Supowski
    My login page contains two forms: one for logging in and one for signing up. Shorten like this: <form name="LoginForm" id="LoginForm" method="post" action="j_security_check" > <input type="text" name="j_username" /> <input type="text" name="j_password" /> <input type="submit" value="Sing In" /> <form> <form name="SignUpForm" id="SignUpForm" method="post" action="/homepage" > <input type="text" name="loginName" /> <input type="password" name="password1" /> <input type="password" name="password2" /> <input type="submit" value="Sing Up" /> <form> I If 'Sing Up', than values of input are lost during processing and not passed into my Servlet. It works fine with GET, but than there is password in URL, so it's not the right solution :) Similar problem has been posted to community.jboss.org, but with no response: http://community.jboss.org/message/7150#7150. I'm using JBoss 4.3eap. Any help?

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  • Asp.net login problem.

    - by Catarrunas
    Hello, im building a asp.net web site with 2.0 framework. I've been "fighting" with web.config, i've changed it quiet some times. So to start from scracht this is what i have: <?xml version="1.0" encoding="utf-16"?> <configuration> <connectionStrings> <remove name="LocalSqlServer"/> <add name="ABC" connectionString="Database=jsilvaqqc.mdf; Data Source=213.175.208.3;Initial Catalog=jsilvaqqc;User ID=jsilva;Password=joao123#;" providerName="System.Data.SqlClient"/> <add name="LocalSqlServer" connectionString="Database=jsilvaqqc.mdf; Data Source=213.175.208.3;Initial Catalog=jsilvaqqc;User ID=jsilva;Password=joao123#;" providerName="System.Data.SqlClient"/> </connectionStrings> <location path="Members"> <system.web> <authorization> <allow users="*"/> <deny users="?"/> </authorization> </system.web> </location> <system.web> <compilation debug="true"/> </system.web></configuration> It works fine im my machine. I've created the users for the login and the role to access the "Members" folder. But in my host company, it doesnt work. I have the aspnet database from my computer in that databese "jsilvaqqc.mdf". When i try to log on pops up box requiring autentication. But i've alreadu given that in the log in form. Do i need aspnet "authentication" tag? Why dont i need it in my machine if i access the same database? Thanks for you help.

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  • Using the login Details via Application

    - by ramin ss
    I have a CURL(in C++) to send my user and pass to remauth.php file so i think i do something wrong on remuth.php ( because i am basic in php and my program can not run because the auth not passed.) I use login via Application. my CURL: bool Auth_PerformSessionLogin(const char* username, const char* password) { curl_global_init(CURL_GLOBAL_ALL); CURL* curl = curl_easy_init(); if (curl) { char url[255]; _snprintf(url, sizeof(url), "http://%s/remauth.php", "SITEADDRESS.com"); char buf[8192] = {0}; char postBuf[8192]; _snprintf(postBuf, sizeof(postBuf), "%s&&%s", username, password); curl_easy_setopt(curl, CURLOPT_URL, url); curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, AuthDataReceived); curl_easy_setopt(curl, CURLOPT_WRITEDATA, (void*)&buf); curl_easy_setopt(curl, CURLOPT_USERAGENT, "IW4M"); curl_easy_setopt(curl, CURLOPT_FAILONERROR, true); curl_easy_setopt(curl, CURLOPT_POST, 1); curl_easy_setopt(curl, CURLOPT_POSTFIELDS, postBuf); curl_easy_setopt(curl, CURLOPT_POSTFIELDSIZE, -1); curl_easy_setopt(curl, CURLOPT_SSL_VERIFYPEER, false); CURLcode code = curl_easy_perform(curl); curl_easy_cleanup(curl); curl_global_cleanup(); if (code == CURLE_OK) { return Auth_ParseResultBuffer(buf); } else { Auth_Error(va("Could not reach the SITEADDRESS.comt server. Error code from CURL: %x.", code)); } return false; } curl_global_cleanup(); return false; } and my remauth.php: <?php ob_start(); $host=""; // Host name $dbusername=""; // Mysql username $dbpassword=""; // Mysql password $db_name=""; // Database name $tbl_name=""; // Table name // Connect to server and select databse. mysql_connect("$host", "$dbusername", "$dbpassword") or die(mysql_error()); mysql_select_db("$db_name") or die(mysql_error()); // Define $username and $password //$username=$username; //$password=md5($_POST['password']); //$password=$password; $username=$_POST['username']; $password=$_POST['password']; //$post_item[]='action='.$_POST['submit']; // To protect MySQL injection (more detail about MySQL injection) $username = stripslashes($username); $password = stripslashes($password); $username = mysql_real_escape_string($username); $password = mysql_real_escape_string($password); $sql="SELECT * FROM $tbl_name WHERE username='$username'"; $result=mysql_query($sql); // Mysql_num_row is counting table row $count=mysql_num_rows($result); // If result matched $username and $password, table row must be 1 row if($count==1){ $row = mysql_fetch_assoc($result); if (md5(md5($row['salt']).md5($password)) == $row['password']){ session_register("username"); session_register("password"); echo "#"; return true; } else { echo "o"; return false; } } else{ echo "o"; return false; } ob_end_flush(); ?> ///////////////////////////////////

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  • Html LogIn form not functioning

    - by Tony C
    Ok, I have a login form that looks like this: <form id="loginForm" name="loginForm" method="post" action="login-exec.php"> <table width="300" border="0" align="center" cellpadding="2" cellspacing="0"> <tr> <td width="112"><b>Login</b></td> <td width="188"><input name="login" type="text" class="textfield" id="login" /></td> </tr> <tr> <td><b>Password</b></td> <td><input name="password" type="password" class="textfield" id="password" /></td> </tr> <tr> <td>&nbsp;</td> <td><input type="submit" name="Submit" value="Login" /></td> </tr> </table> </form> Now, This form is on a page in a directory called members. When i put it on a page in the home directory and change the action to "members/login-exec.php" When I try to logIn it just refreshes the page, but the name of the page in the browser changes to the actions taking place in the form. Any ideas on making this work guys? EDIT, heres the login-exec.php code: <?php //Start session session_start(); //Include database connection details require_once('config.php'); //Array to store validation errors $errmsg_arr = array(); //Validation error flag $errflag = false; //Connect to mysql server $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); if(!$link) { die('Failed to connect to server: ' . mysql_error()); } //Select database $db = mysql_select_db(DB_DATABASE); if(!$db) { die("Unable to select database"); } //Function to sanitize values received from the form. Prevents SQL injection function clean($str) { $str = @trim($str); if(get_magic_quotes_gpc()) { $str = stripslashes($str); } return mysql_real_escape_string($str); } //Sanitize the POST values $login = clean($_POST['login']); $password = clean($_POST['password']); //Input Validations if($login == '') { $errmsg_arr[] = 'Login ID missing'; $errflag = true; } if($password == '') { $errmsg_arr[] = 'Password missing'; $errflag = true; } //If there are input validations, redirect back to the login form if($errflag) { $_SESSION['ERRMSG_ARR'] = $errmsg_arr; session_write_close(); header("location: login-form.php"); exit(); } //Create query $qry="SELECT * FROM members WHERE login='$login' AND passwd='".md5($_POST['password'])."'"; $result=mysql_query($qry); //Check whether the query was successful or not if($result) { if(mysql_num_rows($result) == 1) { //Login Successful session_regenerate_id(); $member = mysql_fetch_assoc($result); $_SESSION['SESS_MEMBER_ID'] = $member['member_id']; $_SESSION['SESS_FIRST_NAME'] = $member['firstname']; $_SESSION['SESS_LAST_NAME'] = $member['lastname']; session_write_close(); header("location: members.php"); exit(); }else { //Login failed header("location: login-failed.php"); exit(); } }else { die("Query failed"); } ?>

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  • Add login / logout to drupal menu that's not a primary or secondary menu

    - by user367766
    Hello, Im trying to append an item to a menu that I created. I know its get the primary and secondary menus using "menu_secondary_local_tasks()" etc, and then add items within preprocess page. How would I go about this with a menu that I created? Here is the code I am using to check is the user is logged in... function themeName_check_login() { global $user; if ($user->uid) { print l("Log out, " . $user->name,"logout"); } else { print l("Log In ","user"); } } Thanks in advance, -Matt

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  • Windows Login Integration

    - by Dusty Roberts
    Hi Peeps. I am building facial recognition software for a certain purpose, however, as a spin-off i would like to use that same software / concept, to automatically recognize me when i sit in front of the PC, and log me in. recognition is handled.. however, i need to incorporate this into windows, the same way fingerprint logins work. where can i go to get some more info on the doing this?

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  • ASP.NET MVC Login ReturnUrl always NULL?

    - by aherrick
    Using Forms Authentication in ASP.NET MVC when trying to log back into a site, it puts a ReturnUrl parameter in the query string. My Logon action method accepts a "returnUrl" string. However it seems that returnUrl string is always null, even when it is clearly in the query string. Any thoughts on why this might be the case or a possible fix?

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  • Login Script for PostGreSQL and PHP not working =[

    - by MrEnder
    Ok I'm quite new at logins what not so bare with me here lol but I gota learn so don't discourage me. I tried this so far <?php $error = ""; $conn = pg_connect("host=localhost dbname=brittains_db user=brittains password=XXXX" ); $sql = "SELECT * FROM logins"; $result = pg_query($conn, $sql); if($_SERVER["REQUEST_METHOD"] == "GET") { $userName=""; $password=""; } else if($_SERVER["REQUEST_METHOD"] == "POST") { $userName=trim($_POST["userNameLogin"]); $password=trim($_POST["passwordLogin"]); if(pg_fetch_result($results, $userName, "userName")==true && pg_fetch_result($results, $password, "userName")==true) { setcookie("userIDforDV", $userName, time()+43200); } else { $error = "Your username and or password is incorrect"; } } $userName = $_COOKIE['userIDforDV']; if(isset($userName) && $userName!="") { echo "Welcome " . $userName; } echo $error; ?> <form> <table> <tr> <td class="signupTd"> User Name:&nbsp; </td> <td> <input type="text" name="userNameLogin" value="" size="20" /> </td> </tr> <tr> <td class="signupTd"> Password:&nbsp; </td> <td> <input type="password" name="passwordLogin" value="" size="20" /> </td> </tr> <tr> <td class="signupTd" colspan="2"> <input type="submit" name="submit" value="Submit"/> </td> </tr> </table> </form> that was the idea I came up with... but its prolly a really bad idea and it doesn't work... how might I go about this properly? I need really detailed descriptions please. Thanks a tun Shelby

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  • Making a login Using JavaScript, Will Incorporate PHP Later

    - by TIMOTHY
    not sure why my code wont work, im teaching myself javascript i know php moderatly and i also know the intelligence of using java to hold a password and username, but at the moment i just want the script to work. <html> <head> <title>34webs</title> <link rel="stylesheet" href="css/lightbox.css" type="text/css" media="screen" /> <link rel="stylesheet" type="text/css" media="screen" href="main.css"> <script type="text/javascript" src="js/prototype.js"></script> <script type="text/javascript" src="js/scriptaculous.js?load=effects,builder"></script> <script type="text/javascript" src="js/lightbox.js"></script> <script type="javascript" > function logintry (){ var usern = document.logn.username.value; var passw = document.logn.password.value; if(usern == blue && passw == bluee){ alert('password is correct!'); }else{ alert('password is wrong'); } } </script> </head> <body> <div id="bod"> <div id="nav"> <p id="buttonhead">34 web</p> <a href="#" class="button">HOME</a> <a href="#" class="button">NEWS</a> <a href="#" class="button">DOWNLOADS</a> <a href="#" class="button">ERA</a> <a href="#" class="button">IE BROWSER</a> <a href="#" class="button">DRIVERS</a> <form name="logn"> <table style="margin:0 auto; background:#0174DF; color:white;"> <tr> <td> Username<br> <input type="text" name="username" value=""> </td> </tr> <tr> <td> Password<br> <input type="password" name="password" value=""> </td> </tr> <tr> <td style="text-align:center;"> <input type="button" name="Submit" value="submit" onclick= javascript: logintry()> </td> </tr> </table> </form> </div>

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  • Login problem with php

    - by shinod
    I want to prevent multiple log in with same log in credentials simultaneously. So I made a column login_status and set it to 1 when some one logging in and change to 0 when logging out besides I set session after successful logged in. If user won't click on log out(in case of user close tab or because of some network problem) it doesn't update database and then one can't use that log in credentials again. So I use a ajax call to set current time stamp in database with related log in credentials and it is updated in each 2 minutes if user not navigate from that page. Then if some one attempts to log in with same log in credentials, it will check these time stamp if column login_status is 1, then if the time stamp is older than 3 minutes it allows the log in.Then it solving that problem. But the new problem is if user closes the tab or browser window and after 3 minutes one can log in with same log in credentials from somewhere and if the previous user open that page automatically it will log in as session is already set. How can I prevent this.

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  • using a stored procedure for login in c#

    - by Jin Yim
    Hi all, If I run a store procedure with two parameter values (admin, admin) (parameters : admin, admin) I get the following message : Session_UID User_Group_Name Sys_User_Name NULLAdministratorsNTMSAdmin No rows affected. (1 row(s) returned) @RETURN_VALUE = 0 Finished running [dbo].[p_SYS_Login]. -- To get the same message in c# I used the code following : string strConnection = Settings.Default.ConnectionString; using (SqlConnection conn = new SqlConnection(strConnection)) { using (SqlCommand cmd = new SqlCommand()) { SqlDataReader rdr = null; cmd.Connection = conn; cmd.CommandText = "p_SYS_Login"; cmd.CommandType = CommandType.StoredProcedure; SqlParameter paramReturnValue = new SqlParameter(); paramReturnValue.ParameterName = "@RETURN_VALUE"; paramReturnValue.SqlDbType = SqlDbType.Int; paramReturnValue.SourceColumn = null; paramReturnValue.Direction = ParameterDirection.ReturnValue; cmd.Parameters.Add(paramReturnValue); cmd.Parameters.Add(paramGroupName); cmd.Parameters.Add(paramUserName); cmd.Parameters.AddWithValue("@Sys_Login", "admin"); cmd.Parameters.AddWithValue("@Sys_Password", "admin"); try { conn.Open(); rdr = cmd.ExecuteReader(); string test = (string)cmd.Parameters["@RETURN_VALUE"].Value; while (rdr.Read()) { Console.WriteLine("test : " + rdr[0]); } } catch (Exception ex) { string message = ex.Message; string caption = "MAVIS Exception"; MessageBoxButtons buttons = MessageBoxButtons.OK; MessageBox.Show( message, caption, buttons, MessageBoxIcon.Warning, MessageBoxDefaultButton.Button1); } finally { cmd.Dispose(); conn.Close(); } } } but I get nothing in SqlDataReader rdr ; is there something I am missing ? Thanks

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  • Login Problem Windows Authentication

    - by user109280
    Duplicate of: http://stackoverflow.com/questions/881928/windows-authentication-trusted-connection-problem I logged in the Windows Server(Machine 1) as "abc\user1 ". Windows Server machine is in abc domain. MSSQL Server is in the "abc" domain on Machine 1 and have mixed mode.authentication. It has account "abc\user1 " and "abc\user2 ". Both has role of sysadmin and serveradmin. I logged in another machine(Machine 2) using "abc\user2 ". Same Domain. Run the ant which connect to MSSQL Server. URL is formed as follows. jdbc:sqlserver://%DB_IP%:%DB_PORT%;SelectMethod=cursor;integratedSecurity=true;DatabaseName=dbname; 1) From Machine 2, If I use "abc\user2" credential for connection, then it works fine. since integratedSecurity=true. 2) From Machine 2, If I use "abc\user1" credential for connection, then it doesn't fine, since integratedSecurity=true and take System Credentials i.e "abc\user2". Even if I make integratedSecurity=false , then also it doesn't connect using "abc\user1" What changes to URL I have make to work for "abc\user1" from Machine2 for connection. what properties to be added in url? OR Driver doesn't support to use another domain\User Credentials? What need to set on MSSQL Server ?? Deepak

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  • REST client website login

    - by Jordan
    I have written a REST service that uses WSSE as an authentication method but i want to be able to use this rest service through a browser by creating a website around the service. I want the user to be able to log in on the website then when they view, for example the "view users" page an ajax request is made to test.com/users and back comes the list. The part i'm trying to get my head around is the logging in/out on the website and keeping the user logged in across pages. Since in a true REST implementation there's no state held on the server, i can't use $_SESSION and now i don't know where to start! What is the best way to go about this? Do i still need to store session information on the server then possibly use cURL to make the request? Thanks Jay

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  • How do I get Facebook Application Login to work

    - by Javaaaa
    I just started making an application for Facebook, however I ran into problem early on. The first step I want people to do is to give permission to access their profile. All over the web are examples of how to do this with: $user_id = $facebook->require_login(); However, this is the way it works using the Old PHP API. I have downloaded and installed the new one in my application folder and it is not working anymore. My question is (and i really have been searching for an answer for a long time) what is the code to do this with the new API? (and related question: is it better to use the old API, or learn to work with the new one when I am just starting making apps right now) I have this code now; <?php // Awesome Facebook Application // // Name: - // require_once 'facebook-php-sdk/src/facebook.php'; // Create our Application instance. $facebook = new Facebook(array( 'appId' => $app_id, 'secret' => $app_secret, 'cookie' => true )); $loginUrl = $facebook->getLoginUrl(array( 'req_perms' => 'email,user_birthday,publish_stream,sms,status_update,user_location' )); echo "<p>hello, <fb:name uid=\"$user_id\" useyou=\"false\" />!</p>"; ?>

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  • Searching for the right pattern to handle login data

    - by stevebot
    Hi all, I'm working on a controller that handles logins for a Web app. These logins will come from multiple clients but will all contain the same data. However, depending on the client, this data will be interpreted into common entities for our webapp differently. For instance, we have a user code that gets sent in, and in one case we may use the first four digits of the code, and in another case 12 digits of the code to map to a field on a User entity. Instead of handling this all in the controller and having big nasty if blocks of logic, I would like to use a pattern to handle how this information gets ingested into our application. What are your opinions?

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  • Creating a session user login php

    - by user2419393
    I'm stuck on how to create a session for a user who logs in. I got the part of checking to make sure the log in information corresponds with the database information, but is stuck on how to take the email address and store into a session. Here is my php code below. <?php include '../View/header.php'; session_start(); require('../model/database.php'); $email = $_POST['username']; $password = $_POST['password']; $sql = "SELECT emailAddress FROM customers WHERE emailAddress ='$email' AND password = '$password'"; $result = mysql_query($sql, $db); if (!$result) { echo "DB Error, could not query the database\n"; echo 'MySQL Error: ' . mysql_error(); exit; } while ($row = mysql_fetch_assoc($result)) { echo $row['emailAddress']; } mysql_free_result($result); ?>

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  • Section of website to be protected by a login

    - by shane
    I have a section of my website where I will have forms. I only want people who have registered with the site to be able to use these forms so that I only have serious customers using them. So what i want to have is a way that people can register on the site and once registered the area with the forms will be available to them and I will know who has sent me a form etc.

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  • Issue Creating SQL Login for AppPoolIdentity on Windows Server 2008

    - by Ben Griswold
    IIS7 introduced the option to run your application pool as AppPoolIdentity. With the release of IIS7.5, AppPoolIdentity was promoted to the default option.  You see this change if you’re running Windows 7 or Windows Server 2008 R2.  On my Windows 7 machine, I’m able to define my Application Pool Identity and then create an associated database login via the SQL Server Management Studio interface.  No problem.  However, I ran into some troubles when recently installing my web application onto a Windows Server 2008 R2 64-bit machine.  Strange, but the same approach failed as SSMS couldn’t find the AppPoolIdentity user.  Instead of using the tools, I created and executed the login via script and it worked fine.  Here’s the script, based off of the DefaultAppPool identity, if the same happens to you: CREATE LOGIN [IIS APPPOOL\DefaultAppPool] FROM WINDOWS WITH DEFAULT_DATABASE=[master] USE [Chinook] CREATE USER [IIS APPPOOL\DefaultAppPool] FOR LOGIN [IIS APPPOOL\DefaultAppPool]

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  • Laptop screen blank after login when external monitor is not connected

    - by Ramon Suarez
    Ubuntu does not switch back automatically to only monitor present when booting after disconnecting external monitor. Here's a video showing what happens. I get to the login window and everything looks ok, then I type my password, the desktop image shows up and... everything goes blank. It does not happen when I just login as a guest. When possible I work with my laptop connected to an external screen via the VGA port. The problem comes when I boot the computer without that secondary screen connected: The login screen comes out ok. After login the screen goes black, but I can hear the login sound. If I hit ctr + alt + backwards-delete and login again sometimes it is fixed, but not all. If I log in as a different user everything is OK. Then I log in as my user and sometimes it works. To have a screen I have to plug a monitor. Although I have turned on the laptop display with that monitor on, if I reboot it goes blank again after login, even if I turn off the external monitor before turning off the computer. I've managed to get my screen back with my username after going into recovery mode, but only sometimes. Failsafe would not load after second screen asking me what I wanted to do (no mouse to click nor keyboard working). My computer is a LDLC Aurore BB1-i5 -8 -S1. Which is the configuration file that keeps the information about the monitors using Displays under lightgdm and where is it? I guess if I could edit it I may have a chance :) One of the things I tried following a solution in another post was removing my monitors.xml file, but it does not work and I don't know how to create a good one that I could use now. When doing DISPLAY=:0 xrandrI get: Screen 0: minimum 320 x 200, current 320 x 200, maximum 8192 x 8192 LVDS1 connected (normal left inverted right x axis y axis) 1366x768 60.0 + 1360x768 59.8 60.0 1024x768 60.0 800x600 60.3 56.2 640x480 59.9 VGA1 disconnected (normal left inverted right x axis y axis) HDMI1 disconnected (normal left inverted right x axis y axis) DP1 disconnected (normal left inverted right x axis y axis) This is the full dmesg after activating sudo xdiagnoseas Bryce sugested. (If you tell me the relevant parts I will paste them here) When conecting the external monitor, only the external will work, although I can see using Displays that the computer thinks that both are working. I've asked the question in Launchpad but have it keeps on expiring without any feedback. In my opinion Ubuntu should be able to detect automatically that there is no external monitor present and switch to the laptop monitor. There's a similar question here, but it does not apply to my case External monitor set as primary even when disconnected from laptop Update: For clarification, the problem happens only with my user and once I log in. I even get to see the screensaver for about a second, and then it goes blank. Tried Bryce's example (see his answer below), but it did not work. This is the info I get from tty1 with Display=:0 xrandr: – Ramon Suarez Jul 9 at 16:36 Screen 0: minimum 320 x 200, current 320 x 200, maximum 8192 x 8192 LVDS1 connected (normal left inverted right x axis y axis) 1366x768 60.0 + 1360x768 59.8 60.0 1024x768 60.0 800x600 60.3 56.2 640x480 59.9 VGA1 disconnected (normal left inverted right x axis y axis) HDMI1 disconnected (normal left inverted right x axis y axis) DP1 disconnected (normal left inverted right x axis y axis)

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