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  • Union Distinct rows but order them by number of occurrences in mysql

    - by Baversjo
    Hi I have the following query: SELECT o.id,o.name FROM object o WHERE ( o.description LIKE '%Black%' OR o.name LIKE '%Black%' ) UNION ALL SELECT o2.id,o2.name FROM object o2 WHERE ( o2.description LIKE '%iPhone%' OR o2.name LIKE '%iPhone%' ) Which procude the following: id name 2 New Black iPhone 1 New White iPhone 2 New Black iPhone I would like to UNION DISTINCT, but I would also like the result ordered by the number of occurrences of each identical row (primary: id).

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  • mysql: get all rows into 1 column

    - by andufo
    hi, i have 3 tables: post (id_post, title) tag (id_tag, name) post_tag (id_post_tag, id_post, id_tag) Lets suppose that id_post 3 has 4 linked tags 1,2,3,4 (soccer, basket, tennis and golf). Is there a way to return something like this in ONE row? col 1 id_post = 3 col 2 tags = soccer basket tennis golf Thanks

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  • JQuery Ajax Updating MySQL Database, But Not Running Success Function

    - by myrmidon16
    I am currently using the JQuery ajax function to call an exterior PHP file, in which I select and add data in a database. Once this is done, I run a success function in JavaScript. What's weird is that the database is updating successfully when ajax is called, however the success function is not running. Here is my code: <!DOCTYPE html> <head> <script type="text/javascript" src="jquery-1.6.4.js"></script> </head> <body> <div onclick="addtask();" style="width:400px; height:200px; background:#000000;"></div> <script> function addtask() { var tid = (Math.floor(Math.random() * 3)) + 1; var tsk = (Math.floor(Math.random() * 10)) + 1; if(tsk !== 1) { $.ajax({ type: "POST", url: "taskcheck.php", dataType: "json", data: {taskid:tid}, success: function(task) {alert(task.name);} }); } } </script> </body> </html> And the PHP file: session_start(); $connect = mysql_connect('x', 'x', 'x') or die('Not Connecting'); mysql_select_db('x') or die ('No Database Selected'); $task = $_REQUEST['taskid']; $uid = $_SESSION['user_id']; $q = "SELECT task_id, taskname FROM tasks WHERE task_id=" .$task. " LIMIT 1"; $gettask = mysql_fetch_assoc(mysql_query($q)); $q = "INSERT INTO user_tasks (ut_id, user_id, task_id, taskstatus, taskactive) VALUES (null, " .$uid. ", '{$gettask['task_id']}', 0, 1)"; $puttask = mysql_fetch_assoc(mysql_query($q)); $json = array( "name" => $gettask['taskname'] ); $output = json_encode($json); echo $output; Let me know if you have any questions or comments, thanks.

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  • MySQL Join Comma Separated Field

    - by neeraj
    I have two tables. First Table is a batch table that contain comma separated student id in field "batch" batch -------------- id batch -------------- 1 1,2 2 3,4 Second Table is marks marks ---------------------- id studentid subject marks 1 1 English 50 2 2 English 40 3 3 English 70 4 1 Math 65 5 4 English 66 6 5 English 75 7 2 Math 55 How we can find those students of first batch id =1 who have scored more than 45 marks in English without using sub query. Problem i found to get this done using a single query is that we can not use IN as an association operator in JOIN statement What changes are required in below query to make it work? SELECT * FROM batch INNER JOIN marks ON marks.studentid IN(batch.batch) where batch.id = 1

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  • Can't connect to MySQL database hosted in CloudBees

    - by user3692698
    I have a free CloudBees account and created a free ClearDB database using their wizards. My trouble is when I use their connection information (whether I try to connect from my Java app, or an outside tool - SQLyog to be exact) I take the error: Access denied for user 'b51dbc5757d79f'@'%' to database 'mywiki. The username provided by CloudBees does not contain those extra characters that the error message is displaying which seems like it would be a problem, but I'm not sure there is anything I can do about that since everything is configured for me. The username I am given is: b51dbc5757d79f - which I can delete and rebuild after sharing here :)

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  • MySQL query problem

    - by Luke
    Ok, I have the following problem. I have two InnoDB tables: 'places' and 'events'. One place can have many events, but event can be created without entering place. In this case event's foreign key is NULL. Simplified structure of the tables looks as follows: CREATE TABLE IF NOT EXISTS `events` ( `id` int(11) unsigned NOT NULL AUTO_INCREMENT, `name` varchar(255) COLLATE utf8_bin NOT NULL, `places_id` int(9) unsigned DEFAULT NULL, PRIMARY KEY (`id`), KEY `fk_events_places` (`places_id`), ) ENGINE=InnoDB; ALTER TABLE `events` ADD CONSTRAINT `events_ibfk_1` FOREIGN KEY (`places_id`) REFERENCES `places` (`id`) ON DELETE CASCADE ON UPDATE NO ACTION; CREATE TABLE IF NOT EXISTS `places` ( `id` int(9) unsigned NOT NULL AUTO_INCREMENT, `name` varchar(255) COLLATE utf8_bin NOT NULL, PRIMARY KEY (`id`), ) ENGINE=InnoDB; Question is, how to construct query which contains name of the event and name of the corresponding place (or no value, in case there is no place assigned?). I am able to do it with two queries, but then I am visibly separating events which have place assigned from the ones that are without place. Help really appreciated.

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  • codeigniter active record and mysql

    - by sea_1987
    I am running a query with Active Record in a modal of my codeigniter application, the query looks like this, public function selectAllJobs() { $this->db->select('*') ->from('job_listing') ->join('job_listing_has_employer_details', 'job_listing_has_employer_details.employer_details_id = job_listing.id', 'left'); //->join('employer_details', 'employer_details.users_id = job_listing_has_employer_details.employer_details_id'); $query = $this->db->get(); return $query->result_array(); } This returns an array that looks like this, [0]=> array(13) { ["id"]=> string(1) "1" ["job_titles_id"]=> string(1) "1" ["location"]=> string(12) "Huddersfield" ["location_postcode"]=> string(7) "HD3 4AG" ["basic_salary"]=> string(19) "£20,000 - £25,000" ["bonus"]=> string(12) "php, html, j" ["benefits"]=> string(11) "Compnay Car" ["key_skills"]=> string(1) "1" ["retrain_position"]=> string(3) "YES" ["summary"]=> string(73) "Lorem Ipsum is simply dummy text of the printing and typesetting industry" ["description"]=> string(73) "Lorem Ipsum is simply dummy text of the printing and typesetting industry" ["job_listing_id"]=> NULL ["employer_details_id"]=> NULL } } The job_listing_id and employer_details_id return as NULL however if I run the SQL in phpmyadmin I get full set of results, the query i running in phpmyadmin is, SELECT * FROM ( `job_listing` ) LEFT JOIN `job_listing_has_employer_details` ON `job_listing_has_employer_details`.`employer_details_id` LIMIT 0 , 30 Is there a reason why I am getting differing results?

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  • best way to prgram php and mysql query

    - by air
    most of times in our pages we need to print only 1 field value of table in loop. for example <?php for($i=1;$i<=mysql_num_rows($result);$i++) { echo $row['name']; $sql1="select industry from table_industry where profid='".$row['prof']."'"; $result1=mysql_query($sql1); $row1=mysql_fetch_array($result1); echo $row1['industry']; ?> } ?> above is one PHP code just for example where we think that $row['prof'] carry value of profession ID and we print profession of each person. for example we have 5000+ record in table and above loop will execute for 5000+ times what will be the best way to print value of industry field from table table_industry Same code which i write above ? any other php code suggestion for faster execution and less use of resources? Thanks

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  • mysql stored funtion usage

    - by shikhar
    I just wrote a stored function to calculate the working days between two dates. This works select CountWeekDays('2010-03-07','2010-04-07') This doesn't work select CountWeekDays(o.order_date,o.created_date) from orders o; Any idea how to make this one work ?? function definition delimiter $$; CREATE FUNCTION CountWeekDays (sdate VARCHAR(50), edate VARCHAR(50)) RETURNS INT BEGIN DECLARE wdays, tdiff, counter, thisday smallint; DECLARE newdate DATE; SET newdate := sdate; SET wdays = 0; if DATEDIFF(edate, sdate) = 0 THEN RETURN 1; END IF; if DATEDIFF(edate, sdate) < 0 THEN RETURN 0; END IF; label1: LOOP SET thisday = DAYOFWEEK(newdate); IF thisday BETWEEN 2 AND 6 THEN SET wdays := wdays + 1; END IF; SET newdate = DATE_ADD(newdate, INTERVAL 1 DAY); IF DATEDIFF(edate, newdate) < 0 THEN LEAVE label1; END IF; END LOOP label1; RETURN wdays; END

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  • MySQL: difference of two result sets

    - by Zombies
    How can I get the set difference of two result sets? Say I have a result set (just one column in each): result1: 'a' 'b' 'c' result2: 'b' 'c' I want to minus what is in result1 by result2: result1 - result2 such that it equals: difference of result1 - result2: 'a'

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  • mysql joining three specific tables

    - by sam lim
    Here what i would like to pull date from this three table. Table users i have three columns uid, username , data(text) Table users_order i have three columns uid, orders_id , users_email Table order_products i have three columns orders_id, product_id, product_name I would like to use product_id as the ref/search to pull the user info from those three tables. If product_id = 5 The query will display uid; username; users_email; orders_id; product_name; data (text) how would i right the sql query for this situation. Thanks,

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  • data from few MySQL tables sorted by ASC

    - by Andrew
    In the dbase I 've few tables named as aaa_9xxx, aaa_9yyy, aaa_9zzz. I want to find all data with a specified DATE and show it with the TIME ASC. First, I must find a tables in the dbase: $STH_1a = $DBH->query("SELECT table_name FROM information_schema.tables WHERE table_name LIKE 'aaa\_9%' "); foreach($STH_1a as $row) { $table_name_s1[] = $row['table_name']; } Second, I must find a data wit a concrete date and show it with TIME ASC: foreach($table_name_s1 as $table_name_1) { $STH_1a2 = $DBH->query("SELECT * FROM `$table_name_1` WHERE date = '2011-11-11' ORDER BY time ASC "); while ($row = $STH_1a2->fetch(PDO::FETCH_ASSOC)) { echo " ".$table_name_1."-".$row['time']."-".$row['ei_name']." <br>"; } } .. but it shows the data sorted by tables name, then by TIME ASC. I must to have all this data (from all tables) sorted by TIME ASC. Thank You dev-null-dweller, Andrew Stubbs and Jaison Erick for your help. I test the Erick solution : foreach($STH_1a as $row) { $stmts[] = sprintf('SELECT * FROM %s WHERE date="%s"', $row['table_name'], '2011-11-11'); } $stmt = implode("\nUNION\n", $stmts); $stmt .= "\nORDER BY time ASC"; $STH_1a2 = $DBH->query($stmt); while ($row_1a2 = $STH_1a2->fetch(PDO::FETCH_ASSOC)) { echo " ".$row['table_name']."-".$row_1a2['time']."-".$row_1a2['ei_name']." <br>"; } it's working but I've problem with 'table_name' - it's always the LAST table name. //---------------------------------------------------------------------- end the ending solution with all fixes, thanks all for your help, :)) foreach($STH_1a as $row) { $stmts[] = sprintf("SELECT *, '%s' AS table_name FROM %s WHERE date='%s'", $row['table_name'], $row['table_name'], '2011-11- 11'); } $stmt = implode("\nUNION\n", $stmts); $stmt .= "\nORDER BY time ASC"; $STH_1a2 = $DBH->query($stmt); while ($row_1a2 = $STH_1a2->fetch(PDO::FETCH_ASSOC)) { echo " ".$row_1a2['table_name']."-".$row_1a2['time']."-".$row_1a2['ei_name']." <br>"; }

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  • MySQL: Limit output according to associated ID

    - by Jess
    So here's my situation. I have a books table and authors table. An author can have many books... In my authors page view, the user (logged in) can click an author in a tabled row and be directed to a page displaying the author's books (collected like this URI format: viewauthorbooks.php?author_id=23), very straight forward... However, in my query, I need to display the books for the author only, and not all books stored in the books table (as i currently have!) As I am a complete novice, I used the most simple query of: SELECT * FROM tasks_tb This returns the books for me, but returns every single value (book) in the database, and not ones associated with the selected author. And when I click a different author the same books are displayed for them...I think everyone gets what I'm trying to achieve, I just don't know how to perform the query. I'm guessing that I need to start using more advanced query clauses like INNER JOIN etc. Anyone care to help me out :)

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  • MySQL - Conflicting WHERE and GROUP BY Statements

    - by TaylorPLM
    I have a query returning the counts of some data, but I do NOT want data that has a null value in it... As an example, the code rolls stats from a clicking system into a table. SELECT sh.dropid, ... FROM subscriberhistory sh INNER JOIN subscriberhistory sh2 on sh.subid = sh2.subid WHERE sh.dropid IS NOT NULL AND sh.dropid != "" ... GROUP BY sh.dropid An example of the record set returned would look like this... 400 2 3 4 5 6 401 2 3 6 5 4 NULL 2 3 4 5 1 There are some other where clauses, and a few more selects (as I said, using the count aggregate) that are also within the query. There is also an order by statement. Again, the goal is to keep the NULL data out of the preceding record set. Could someone explain to me why this behavior is occurring and what to do to solve it.

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  • Removing groups of similar records in MySQL query

    - by user1182155
    I'm trying to wrap my head around this... (it may be simple, been a long day!) I have a database with sometimes multiple similar records... ie. Apples 2008-09-03 Apples 2012-01-01 Apples 2013-10-24 Oranges 2012-01-04 What I need to do is do a query that will show only records that haven't been updated today... So in this case, since Apples has an entry that was updated today, none of the records for the Apples should appear in the results. Oranges should be the only record it returns. I have a query similar to this... SELECT fruit FROM fruitnames where date < CURDATE() Which works to remove the record that was updated today... But it keeps the other records for Apples (obviously)... How would I remove those results as well?

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  • mysql add auto increment and a additional key

    - by Lee
    Hey all I am trying to alter a table with adding a new column setting it as auto increment and with a key. The table already has one key and this one will be an addition. The error I get is the following. error : Multiple primary key defined My code is: alter table user add column id int (11) NOT NULL AUTO_INCREMENT PRIMARY KEY FIRST; I have also tries wrapping the key name ie alter table user add column id int (11) NOT NULL AUTO_INCREMENT PRIMARY (id) KEY FIRST; But still no luck. How can it be done ?

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  • MySQL Non Index Queries Analysis

    - by Markii
    I'm using the log queries not using index but it logs all that use indexes but just more advanced or using IFs. Is there a parser or a program out there that can analyze the log and give me a literal output of saying "table.column should be a index" Thanks

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  • Fighing system in Php & MYSQL

    - by Gully
    I am working on a game like Mafia Wars and i am trying to get the fighting system working but i keep getting lose trying to work out who is going to win the fight and it still needs to know if the stats are close then there is a random chace of them winning. $strength = $my_strength; $otherplayerinfo = mysql_query("SELECT * FROM accounts WHERE id='$player_id'"); $playerinfo = mysql_fetch_array($otherplayerinfo); $players_strength = $playerinfo['stre']; $players_speed = $playerinfo['speed']; $players_def = $playerinfo['def']; if($players_strength > $strength){ $strength_point_player = 1; $strength_point_your = 0; }else{ $strength_point_your = 1; $strength_point_player = 0; } I was trying a point system but i still could not do it.

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  • Question about Benchmark funcion in Mysql ( Incredible results ).

    - by xRobot
    I have 2 tables: author with 3 millions of rows. book with 20 miles rows. . So I have benchmarked this query with a join: SELECT BENCHMARK(100000000, 'SELECT book.title, author.name FROM `book` , `author` WHERE book.id = author.book_id ') And this is the result: Query took 0.7438 sec ONLY 0.7438 seconds for 100 millions of query with a join ??? Do I make some mistakes or this is the right result ?

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  • mysql select update

    - by Tillebeck
    Hi I have read quite a few selcet+update questions in here but cannot understand how to do it. So will have to ask from the beginning. I would like to update a table based on data in another table. Setup is like this: - TABLE a ( int ; string ) ID WORD 1 banana 2 orange 3 apple - TABLE b ( "comma separated" string ; string ) WORDS TEXTAREA 0 banana -> 0,1 0 orange apple apple -> BEST:0,2,3 ELSE 0,2,3,3 0 banana orange apple -> 0,1,2,3 Now I would like to for each word in TABLE a append ",a.ID" to b.WORDS like: SELECT id, word FROM a (for each) -> UPDATE b SET words = CONCAT(words, ',', a.id) WHERE b.textarea like %a.word% Or even better: replace the word found in b.textarea with ",a.id" so it is the b.textarea that ends up beeing a comma separeted string of id's... But I do not know if that is possible.

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  • Storing apostrophes, exclamation marks, etc. in mysql database

    - by rein
    I changed from latin1 to utf8. Although all sorts of text was displaying fine I noticed non-english characters were stored in the database as weird symbols. I spent a day trying to fix that and finally now non-english characters display as non-english characters in the database and display the same on the browser. However I noticed that I see apostrophes stored as &#39; and exclamation marks stored as &#33;. Is this normal, or should they be appearing as ' and ! in the database instead? If so, what would I need to do in order to fix that?

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