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  • [mysql] having a number in

    - by Wiika
    Hi all, ID Name Hidden 1 Mika 1,4,2 2 Loca 0 3 Nosta 4 4 Like 2 can someone give me a query that will return as a result rows ID 1 & 3 something like this SELECT * FROM table WHERE Hidden HAVING(4) Thanks, I Appreciate

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  • delete row from mysql through generated table with records

    - by HennySmafter
    I am using 2 pages. On one page it generates a table with the records and a delete button. After pressing delete it goes to the second page which should delete the record. But it doesn't. Below is the code that I am using. PS: The code is adapted from a tutorial I found through Google a while ago. delete_overzicht.php <?php // Load Joomla! configuration file require_once('../../../configuration.php'); // Create a JConfig object $config = new JConfig(); // Get the required codes from the configuration file $server = $config->host; $username = $config->user; $password = $config->password; $database = $config->db; // Connect to db $con = mysqli_connect($server,$username,$password,$database); if (!$con){ die('Could not connect: ' . mysqli_error($con)); } mysqli_select_db($con,$database); // Get results $result = mysqli_query($con,"SELECT * FROM cypg8_overzicht"); echo "<table border='1' id='example' class='tablesorter'><thead><tr><th>Formulier Id</th><th>Domeinnaam</th><th>Bedrijfsnaam</th><th>Datum</th><th>Periode</th><th>Subtotaal</th><th>Dealernaam</th><th>Verwijderen</th></tr></thead><tbody>"; while($row = mysqli_fetch_array($result)) { echo "<tr>"; echo "<td>" . $row['formuliernummer'] . "</td>"; echo "<td>" . $row['domeinnaam'] . "</td>"; echo "<td>" . $row['bedrijfsnaam'] . "</td>"; echo "<td>" . $row['datum'] . "</td>"; echo "<td>" . $row['periode'] . "</td>"; echo "<td> &euro; " . $row['subtotaal'] . "</td>"; echo "<td>" . $row['dealercontactpersoon'] . "</td>"; echo "<td><a href='delete.php?id=" . $row['id'] . "'>Verwijderen </a></td>"; echo "</tr>"; } echo "</tbody></table>"; mysqli_close($con); ?> delete.php <?php // Load Joomla! configuration file require_once('../../../configuration.php'); // Create a JConfig object $config = new JConfig(); // Get the required codes from the configuration file $server = $config->host; $username = $config->user; $password = $config->password; $database = $config->db; // Connect to db $con = mysqli_connect($server,$username,$password,$database); if (!$con){ die('Could not connect: ' . mysqli_error($con)); } mysqli_select_db($con,$database); // Check whether the value for id is transmitted if (isset($_GET['id'])) { // Put the value in a separate variable $id = $_GET['id']; // Query the database for the details of the chosen id $result = mysqli_query($con,"DELETE * FROM cypg8_overzicht WHERE id = $id"); } else { die("No valid id specified!"); } ?> Thanks to everyone who is willing to help!

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  • MySQL LEFT JOIN, GROUP BY and ORDER BY not working as required

    - by Simon
    I have a table 'products' => ('product_id', 'name', 'description') and a table 'product_price' => ('product_price_id', 'product_id', 'price', 'date_updated') I want to perform a query something like SELECT `p`.*, `pp`.`price` FROM `products` `p` LEFT JOIN `product_price` `pp` ON `pp`.`product_id` = `p`.`product_id` GROUP BY `p`.`product_id` ORDER BY `pp`.`date_updated` DESC As you can probably guess the price changes often and I need to pull out the latest one. The trouble is I cannot work out how to order the LEFT JOINed table. I tried using some of the GROUP BY functions like MAX() but that would only pull out the column not the row. Thanks.

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  • Complex MySQL table select/join with pre-condition

    - by Howard
    Hello, I have the schema below CREATE TABLE `vocabulary` ( `vid` int(10) unsigned NOT NULL auto_increment, `name` varchar(255), PRIMARY KEY vid (`vid`) ); CREATE TABLE `term` ( `tid` int(10) unsigned NOT NULL auto_increment, `vid` int(10) unsigned NOT NULL default '0', `name` varchar(255), PRIMARY KEY tid (`tid`) ); CREATE TABLE `article` ( `aid` int(10) unsigned NOT NULL auto_increment, `body` text, PRIMARY KEY aid (`aid`) ); CREATE TABLE `article_index` ( `nid` int(10) unsigned NOT NULL default '0', `tid` int(10) unsigned NOT NULL default '0' ) INSERT INTO `vocabulary` values (1, 'vocabulary 1'); INSERT INTO `vocabulary` values (2, 'vocabulary 2'); INSERT INTO `term` values (1, 1, 'term v1 t1'); INSERT INTO `term` values (2, 1, 'term v1 t2 '); INSERT INTO `term` values (3, 2, 'term v2 t3'); INSERT INTO `term` values (4, 2, 'term v2 t4'); INSERT INTO `term` values (5, 2, 'term v2 t5'); INSERT INTO `article` values (1, ""); INSERT INTO `article` values (2, ""); INSERT INTO `article` values (3, ""); INSERT INTO `article` values (4, ""); INSERT INTO `article` values (5, ""); INSERT INTO `article_index` values (1, 1); INSERT INTO `article_index` values (1, 3); INSERT INTO `article_index` values (2, 2); INSERT INTO `article_index` values (3, 1); INSERT INTO `article_index` values (3, 3); INSERT INTO `article_index` values (4, 3); INSERT INTO `article_index` values (5, 3); INSERT INTO `article_index` values (5, 4); Example. Select term of a defiend vocabulary (with non-zero article index), e.g. vid=2 select a.tid, count(*) as article_count from term t JOIN article_index a ON t.tid = a.tid where t.vid = 2 group by t.tid; +-----+---------------+ | tid | article_count | +-----+---------------+ | 3 | 4 | | 4 | 1 | +-----+------------ Question: Select terms a. of a defiend vocabulary (with non-zero article index, e.g. vid=1 = term {1,2}) b. given that those terms are linked with articles which are linked with terms under vid=2, e.g. = {1}, term with tid=2 is excluded since no linkage to terms under vid=2 SQL: Any idea? Expected result: +-----+---------------+ | tid | article_count | +-----+---------------+ | 1 | 2 | +-----+---------------+

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  • MySQL Query For Copying Contents Into Another Field, Same Row

    - by Rob Adler
    Is there a single query (subqueries in it are allowed) where I can copy the content of one field into another field, per row. Example: price, and priceBackup Records: 45.55 47.77 45.55 copies into priceBackup for that specific row, 47.77 copies into priceBackup for that specific row. I do have a primary key, auto increment on it under 'id'. Thanks guys!

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  • mySql Delete only removes the data not the entire entry

    - by Mick
    Hi all I have this line in my php code $insert = "DELETE FROM allocation_table WHERE job = '$jobnumber' " ; Mysql_query ($insert) ; The problem is it will remove all the values from the the one line in my table but not the entry itself. as you can see in the picture if I delete where job = 315 , it does not delete the line but does delete all the entries Yet in this code that preceeds it (a different table) . it works fine and the whole line is removed $insert = "DELETE FROM event WHERE jobnumber = '$jobnumber' " ; mysql_query ($insert) ;enter code here can anyone offer some advice please ??

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  • mysql multi count() in one query

    - by atno
    Hi, I'm trying to count several joined tables but without any luck, what I get is the same numbers for every column (tUsers,tLists,tItems). My query is: select COUNT(users.*) as tUsers, COUNT(lists.*) as tLists, COUNT(items.*) as tItems, companyName from users as c join lists as l on c.userID = l.userID join items as i on c.userID = i.userID group by companyID The result I want to get is --------------------------------------------- # | CompanyName | tUsers | tlists | tItems 1 | RealCoName | 5 | 2 | 15 --------------------------------------------- what modifications do i have to do to my query to get those results? Cheers

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  • MySQL update query, how to skip empty values?

    - by Pawel
    I've got such query: $sql = "UPDATE test_accs SET acc_owner = '$owner_id', acc_policy_version = '$version', acc_policy_last_update = '$approved', acc_policy_next_update = '$renewed' WHERE acc_id = '1'"; Now, all of these values on the web folmular are optional, one can set one of these values, two, or so. Now, after I submit the form, it goes in the query like that: UPDATE test_accs SET acc_owner = '2', acc_policy_version = '1.2', acc_policy_last_update = '2012-12-19', acc_policy_next_update = '2012-12-18' WHERE acc_id = '1' It works only when I submit all values from the form. Can you please show me how could it work even if not all the values has been sent, just for example one of them? When I set one value (f.ex. policy version), it looks like that: UPDATE test_accs SET acc_owner = '', acc_policy_version = '1.2', acc_policy_last_update = '', acc_policy_next_update = '' WHERE acc_id = '1' and it isn't working. It might be possible cause of the acc_owner table values? #1366 - Incorrect integer value: '' for column 'acc_owner' at row 1 Thanks in advice.

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  • MySQL Query to get count of unique values?

    - by RD
    Hits Table: hid | lid | IP 1 | 1 | 123.123.123.123 2 | 1 | 123.123.123.123 3 | 2 | 123.123.123.123 4 | 2 | 123.123.123.123 5 | 2 | 123.123.123.124 6 | 2 | 123.123.123.124 7 | 3 | 123.123.123.124 8 | 3 | 123.123.123.124 9 | 3 | 123.123.123.124 As you can see, there following are the unique hits for the various lid: lid 1: 1 unique hit lid 2: 2 unique hits lid 3: 1 unique hit So basically, I need a query that will return the following: lid | uhits | 1 | 1 | 2 | 2 | 3 | 1 | Anybody know how to get that?

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  • MySQL subquery and bracketing

    - by text
    Here are my tables respondents: field sample value respondentid : 1 age : 2 gender : male survey_questions: id : 1 question : Q1 answer : sample answer answers: respondentid : 1 question : Q1 answer : 1 --id of survey question I want to display all respondents who answered the certain survey, display all answers and total all the answer and group them according to the age bracket. I tried using this query: SELECT res.Age, res.Gender, answer.id, answer.respondentid, SUM(CASE WHEN res.Gender='Male' THEN 1 else 0 END) AS males, SUM(CASE WHEN res.Gender='Female' THEN 1 else 0 END) AS females, CASE WHEN res.Age < 1 THEN 'age1' WHEN res.Age BETWEEN 1 AND 4 THEN 'age2' WHEN res.Age BETWEEN 4 AND 9 THEN 'age3' WHEN res.Age BETWEEN 10 AND 14 THEN 'age4' WHEN res.Age BETWEEN 15 AND 19 THEN 'age5' WHEN res.Age BETWEEN 20 AND 29 THEN 'age6' WHEN res.Age BETWEEN 30 AND 39 THEN 'age7' WHEN res.Age BETWEEN 40 AND 49 THEN 'age8' ELSE 'age9' END AS ageband FROM Respondents AS res INNER JOIN Answers as answer ON answer.respondentid=res.respondentid INNER JOIN Questions as question ON answer.Answer=question.id WHERE answer.Question='Q1' GROUP BY ageband ORDER BY res.Age ASC I was able to get the data but the listing of all answers are not present. Do I have to subquery SELECT into my current SELECT statement to show the answers? I want to produce something like this: ex: # of Respondents is 3 ages: 2,3 and 6 Question: what are your favorite subjects? Ages 1-4: subject 1: 1 subject 2: 2 subject 3: 2 total respondents for ages 1-4 : 2 Ages 5-10: subject 1: 1 subject 2: 1 subject 3: 0 total respondents for ages 5-10 : 1

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  • how to get needed data from mysql tables

    - by I Like PHP
    i have 3 tables tbl_faculty(f_id,f_school) tbl_school(s_id,s_city_s_role) tbl_city(c_id,c_name) in one school there may be many teacher(s_role=2) can be appointed, but would be appointed only one principle(s_role=1) first we need to create a school, then we appoint faculty. now i want to appoint principle( where teachers may b already appointed or may b not) so i need all school_id and city name where there is no principle appointed yet references in tables f_school--->s_id s_city---->c_id i used below query but, it show not the exact result i want SELECT s_id,c_name FROM tbl_school LEFT JOIN tbl_city ON c_id=s_city LEFT JOIN tbl_faculty ON f_school=s_id WHERE s_role<>1";

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  • MySQL join problem

    - by snaken
    Whats wrong with this SQL? It should return results but returns nothing SELECT `pid` FROM `products` LEFT JOIN `prods_to_features` ON (`ptf_pid` = `pid`) WHERE (`ptf_id` = '66' OR `ptf_id` = '67') AND (`ptf_id` = '76') Is it not possible to have the 2nd where clause for the table that has been used in the left join?

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  • MYSQL Select statment Order By with Group By

    - by mouthpiec
    I have the following simple SQL statment SELECT id, name, value_name, value_id FROM table GROUP BY id ORDER BY value_id DESC when grouping I would like to get the value_name and value_id of the tuple where the value_id is the biggest. The way it is i am getting the smallest value. For example 1, name1, valuename, 3 (where i know that there is a value_id of 5) Can you please help?

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  • Preventing entire JOINed MYSQL query from failing when one field is missing within a WHERE clause

    - by filip o
    I am doing a couple of joins with a variable in the WHERE clause. I'm not sure if I am doing everything as efficiently as I could, or even using the best practices but my issue is that half my tables have data for when tableC.type=500, and the other half don't resulting in the entire query failing. SELECT tableA.value1 , tableB.value2, tableC.value3 FROM tableA JOIN tableB ON tableB.id=tableA.id JOIN tableC ON tableC.id=tableB.id WHERE tableA.category=$var && tableC.type=500; What I would like to happen is to still get tableA.value1 and tableB.value2 even if there is no field in tableC with a type=500. any thoughts? i'm totally stumped as how to approach this...

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  • Display only latest three results from PHP and MySQL

    - by nogggin1
    <?php $result = @mysql_query('SELECT Article FROM news WHERE ID = (SELECT MAX(ID) FROM News)'); if (!$result) { die('<p>Error performing query: ' . mysql_error() . '</p>'); } while ( $row = mysql_fetch_array($result) ) { echo('<p>' . $row['Article'] . '</p>'); } ?> basically i need to tweak this so that it shows the latest 3 results instead of just the latest one, also i need the order to be: newest 2nd newest 3rd newest any help would be greatly appreciated!

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  • Mysql - Rank field for a query

    - by Mark
    How can I add a field that contains a rows rank within the result set of a query? Initially I used php to rank my results as it was all on a single page. Now I have added multiple pages so now even though I am on the second page the first result on the page is still '1st'. Obviously I could multiply the page number by the number of results per page and add the result number but I imagine there is a better way within the query. Thanks,

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  • MySQL Datefields: duplicate or calculate?

    - by Konerak
    We are using a table with a structure imposed upon us more than 10 years ago. We are allowed to add columns, but urged not to change existing columns. Certain columns are meant to represent dates, but are put in different format. Amongst others: * CHAR(6): YYMMDD * CHAR(6): DDMMYY * CHAR(8): YYYYMMDD * CHAR(8): DDMMYYYY * DATE * DATETIME Since we now would like to do some more complex queries, using advanced date functions, my manager proposed to d*uplicate those problem columns* to a proper FORMATTED_OLDCOLUMNNAME column using a DATE or DATETIME format. Is this the way to go? Couldn't we just use the STR_TO_DATE function each time we accessed the columns? To avoid every query having to copy-paste the function, I could still work with a view or a stored procedure, but duplicating data to avoid recalculation sounds wrong. Solutions I see (I guess I prefer 2.2.1) 1. Physically duplicate columns 1.1 In the same table 1.1.1 Added by each script that does a modification (INSERT/UPDATE/REPLACE/...) 1.1.2 Maintained by a trigger on each modification 1.2 In a separate table 1.2.1 Added by each script that does a modification (INSERT/UPDATE/REPLACE/...) 1.2.2 Maintained by a trigger on each modification 2. On-demand transformation 2.1 Each query has to perform the transformation 2.1.1 Using copy-paste in the source code 2.1.2 Using a library 2.1.3 Using a STORED PROCEDURE 2.2 A view performs the transformation 2.2.1 A separate table replacing the entire table 2.2.2 A separate table just adding the date-fields for the primary keys Am I right to say it's better to recalculate than to store? And would a view be a good solution?

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  • MySQL query paralyzes site

    - by nute
    Once in a while, at random intervals, our website gets completely paralyzed. Looking at SHOW FULL PROCESSLIST;, I've noticed that when this happens, there is a specific query that is "Copying to tmp table" for a loooong time (sometimes 350 seconds), and almost all the other queries are "Locked". The part I don't understand is that 90% of the time, this query runs fine. I see it going through in the process list and it finishes pretty quickly most of the time. This query is being called by an ajax call on our homepage to display product recommendations based your browsing history (a la amazon). Just sometimes, randomly (but too often), it gets stuck at "copying to tmp table". Here is a caught instance of the query that was up 109 seconds when I looked: SELECT DISTINCT product_product.id, product_product.name, product_product.retailprice, product_product.imageurl, product_product.thumbnailurl, product_product.msrp FROM product_product, product_xref, product_viewhistory WHERE ( (product_viewhistory.productId = product_xref.product_id_1 AND product_xref.product_id_2 = product_product.id) OR (product_viewhistory.productId = product_xref.product_id_2 AND product_xref.product_id_1 = product_product.id) ) AND product_product.outofstock='N' AND product_viewhistory.cookieId = '188af1efad392c2adf82' AND product_viewhistory.productId IN (24976, 25873, 26067, 26073, 44949, 16209, 70528, 69784, 75171, 75172) ORDER BY product_xref.hits DESC LIMIT 10 Of course the "cookieId" and the list of "productId" changes dynamically depending on the request. I use php with PDO.

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  • MySQL: Update table column from subquery result

    - by Jhourlad Estrella
    On the Members table are columns "MemberID" and "PointsEarned". I want to update the PointsEarned column from the result of this query: SELECT m.MemberID, m.UserName, ( (SELECT COUNT(*) FROM EventsLog as e WHERE e.MemberID=m.MemberID AND e.EventsTypeID=2)*10 ) + ( (SELECT COUNT(*) FROM EventsLog as e WHERE e.MemberID=m.MemberID AND e.EventsTypeID=3)*3 ) + ( (SELECT COUNT(*) FROM ChatMessages as c WHERE c.MemberID=m.MemberID)*.1 ) as PointsEarned FROM Members as m Can anybody tell me how I should do it with a single query? Thanks!

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  • MySql Query to return number of photos in each album

    - by GivenPie
    MY table is set up like this, all I need to do is call a query to my Photos table. I have PhotoID as the primary key and GalleryID as the foreign key to Gallery. How can I could the number of unique PhotoID's for each multiple GalleryIDs. So to speak there are may duplicate GalleryIDs because there are many photos in a gallery. So I just need to could the number of unique PhotoIDs associated with that GalleryID. Can it be done in one query?

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  • MySQL Update Statement + File Upload

    - by Jason Sweet
    Greetings! Been staring at this all day and can't seem to figure out why my update statement fails to update the field 'image_filename': $fileName = $_FILES['image_filename']; if($fileName["name"] <> ""){ $imageFile = $fileName['name']; $destination = "../../../../assets/resources/images/".$fileName['name']; move_uploaded_file($fileName['name'], $destination); } $updateSQL = sprintf("UPDATE content SET image_filename='$imageFile' WHERE id=%s", GetSQLValueString($_POST['resource_id'], "int")); mysql_select_db($database_conn_talent, $conn_talent); $Result1 = mysql_query($updateSQL, $conn_talent) or die(mysql_error()); Can a SQL pro tell me what I"m missing? Much thanks in advance for your feedback!

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  • Merging tables in MySQL - sum up columns

    - by Alan Williamson
    I have an interesting problem, that i am sure has a simple answer, but i can't seem to find it in the docs. I have two separate database tables, on different servers. They are both identical table schema with the same primary keys. I want to merge the tables together on one server. But, if the row on Server1.Table1 exists in Server2.Table2 then sum up the totals in the columns i specify. Table1{ column_pk, counter }; "test1", 3 "test2", 4 Table2{ column_pk, counter }; "test1", 5 "test2", 6 So after i merge i want: "test1",8 "test2",10 Basically i need to do a mysqldump but instead of it kicking out raw INSERT statements, i need to do a INSERT..ON DUPLICATE KEY UPDATE statements. What are my options? Appreciate any input, thank you

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