Search Results

Search found 5202 results on 209 pages for 'char'.

Page 186/209 | < Previous Page | 182 183 184 185 186 187 188 189 190 191 192 193  | Next Page >

  • rotate a star in opengl (2D)

    - by nova a
    I have a 2D star, and I don't know how to rotate it around its center, and I also don't know how to do it with a keyboard key. Also how can I make my object bigger or smaller by a certain percentage (because when I tried to do it by changing pixels, the star goes wrong). This is my code: #include <GL/glut.h> #include <GL/gl.h> #include <GL/freeglut.h> void init (void) { glClearColor(0.0,0.0,0.0,00); glMatrixMode(GL_PROJECTION); gluOrtho2D(0.0,200.0,0.0,200.0); } void LineSegment(void) { glClear(GL_COLOR_BUFFER_BIT); glColor3f(1.0,1.0,1.0); glBegin(GL_LINE_LOOP); glVertex2i(20,120); glVertex2i(180,120); glVertex2i(45,20); glVertex2i(100,190); glVertex2i(155,20); glEnd(); glFlush(); } int main(int argc,char** argv) { glutInit(&argc,argv); glutInitDisplayMode(GLUT_SINGLE|GLUT_RGB); glutInitWindowPosition(50,100); glutCreateWindow("STAR"); init(); glutDisplayFunc(LineSegment); glutMainLoop(); return 0; }

    Read the article

  • Template function overloading with identical signatures, why does this work?

    - by user1843978
    Minimal program: #include <stdio.h> #include <type_traits> template<typename S, typename T> int foo(typename T::type s) { return 1; } template<typename S, typename T> int foo(S s) { return 2; } int main(int argc, char* argv[]) { int x = 3; printf("%d\n", foo<int, std::enable_if<true, int>>(x)); return 0; } output: 1 Why doesn't this give a compile error? When the template code is generated, wouldn't the functions int foo(typename T::type search) and int foo(S& search) have the same signature? If you change the template function signatures a little bit, it still works (as I would expect given the example above): template<typename S, typename T> void foo(typename T::type s) { printf("a\n"); } template<typename S, typename T> void foo(S s) { printf("b\n"); } Yet this doesn't and yet the only difference is that one has an int signature and the other is defined by the first template parameter. template<typename T> void foo(typename T::type s) { printf("a\n"); } template<typename T> void foo(int s) { printf("b\n"); } I'm using code similar to this for a project I'm working on and I'm afraid that there's a subtly to the language that I'm not understanding that will cause some undefined behavior in certain cases. I should also mention that it does compile on both Clang and in VS11 so I don't think it's just a compiler bug.

    Read the article

  • write a program that prompts the user to input five decimal numbers : C++

    - by user312309
    This is the question. write a program that prompts the user to input five decimal numbers. the program should then add the five decimal numbers, convert the sum to the nearest integer,m and print the result. This is what I've gotten so far: // p111n9.cpp : Defines the entry point for the console application. // #include <iostream> using namespace std; double a, b , c , d , e, f; int main(int argc, char* argv[]) { cout << "enter 5 decimals: " << endl; cin >> a >> b >> c >> d >> e; f = a + b + c + d + e; return 0; } Now I just need to convert the sum(f) to the nearest integer, m and print the result. How do I do this?

    Read the article

  • Textbox time validations (javascript)

    - by unos
    I have a textbox in which user can enter time (eg- 01:00) and also a drop down box for entering AM/PM fields. (Since the AM/PM field is used, 12-hour time format is used.) The text box allows a max entry of 5 chars only (eg - 01:00). Pls let me know how I can set the 3rd char as a default -colon : , so that the user simply has to enter only the time. How to check if the time entered by the user is numeric or not?. Autocompletion feature : for eg, if user enters 1 then it would automatically be set to 01:00 Javascript Validations for 12-hour format. Eg: if user enters 13:00 then it should change to 01:00 How can I append the text box time values with the am/pm value selected in the drop down box?. Once the values are appended, automatically populate another text box (text box 2) with the result. Eg: 01:00 + pm should be set as 01:00p in the new text box (text box 2). Any help would be appreciated.

    Read the article

  • How to make smooth movements in OpenGL?

    - by thyrgle
    So this kind of on topic to my other OpenGL question (not my OpenGL ES question but OpenGL the desktop version). If you have someone press a key to move a square how do you make the square movement naturally and less jumpy but also at the same speed I have it now? This is my code for the glutKeyboardFunc() function: void handleKeypress(unsigned char key, int x, int y) { if (key == 'w') { for (int i = 0; i < 12; i++) { if (i == 1 || i == 7 || i == 10 || i == 4) { square[i] = square[i] + 1; } } glutPostRedisplay(); } if (key == 'd') { for (int i = 0; i < 12; i++) { if (i == 0 || i % 3 == 0) { square[i] = square[i] + 1; } } glutPostRedisplay(); } if (key == 's') { for (int i = 0; i < 12; i++) { if (i == 1 || i == 7 || i == 10 || i == 4) { square[i] = square[i] - 1; } } glutPostRedisplay(); } if (key == 'a') { for (int i = 0; i < 12; i++) { if (i == 0 || i % 3 == 0) { square[i] = square[i] - 1; } } glutPostRedisplay(); } } I'm sorry if this doesn't quite make sense I'll try to rephrase it in a better way if it doesn't make sense.

    Read the article

  • Common Properties: Consolidating Loan, Purchase, Inventory and Sale tables into one Transaction tabl

    - by Frank Computer
    Pawnshop Application: I have separate tables for Loan, Purchase, Inventory & Sales transactions. Each tables rows are joined to their respective customer rows by: customer.pk [serial] = loan.fk [integer]; = purchase.fk [integer]; = inventory.fk [integer]; = sale.fk [integer]; Since there are so many common properties within the four tables, I consolidated the four tables into one table called "transaction", where a column: transaction.trx_type char(1) {L=Loan, P=Purchase, I=Inventory, S=Sale} Scenario: A customer initially pawns merchandise, makes a couple of interest payments, then decides he wants to sell the merchandise to the pawnshop, who then places merchandise in Inventory and eventually sells it to another customer. I designed a generic transaction table where for example: transaction.main_amount DECIMAL(7,2) in a loan transaction holds the pawn amount, in a purchase holds the purchase price, in inventory and sale holds sale price. This is clearly a denormalized design, but has made programming alot easier and improved performance. Any type of transaction can now be performed from within one screen, without the need to change to different tables.

    Read the article

  • When are temporaries created as part of a function call destroyed?

    - by Michael Mrozek
    Is a temporary created as part of an argument to a function call guaranteed to stay around until the called function ends, even if the temporary isn't passed directly to the function? There's virtually no chance that was coherent, so here's an example: class A { public: A(int x) : x(x) {printf("Constructed A(%d)\n", x);} ~A() {printf("Destroyed A\n");} int x; int* y() {return &x;} }; void foo(int* bar) { printf("foo(): %d\n", *bar); } int main(int argc, char** argv) { foo(A(4).y()); } If A(4) were passed directly to foo it would definitely not be destroyed until after the foo call ended, but instead I'm calling a method on the temporary and losing any reference to it. I would instinctively think the temporary A would be destroyed before foo even starts, but testing with GCC 4.3.4 shows it isn't; the output is: Constructed A(4) foo(): 4 Destroyed A The question is, is GCC's behavior guaranteed by the spec? Or is a compiler allowed to destroy the temporary A before the call to foo, invaliding the pointer to its member I'm using?

    Read the article

  • Help with string equality in Java

    - by annayena
    The following function accepts 2 strings, the 2nd (not 1st) possibly containing *'s (asterisks). An * is a replacement for a string (empty, 1 char or more), it can appear appear (only in s2) once, twice, more or not at all, it cannot be adjacent to another * (ab**c), no need to check that. public static boolean samePattern(String s1, String s2) It returns true if strings are of the same pattern. It must be recursive, not use any loops, static or global variables. Also it's prohibited to use the method equals in the String class. Can use local variables and method overloading. Can use only these methods: charAt(i), substring(i), substring(i, j), length(). Examples: 1: TheExamIsEasy; 2: "The*xamIs*y" ---> true 1: TheExamIsEasy; 2: "Th*mIsEasy*" ---> true 1: TheExamIsEasy; 2: "*" ---> true 1: TheExamIsEasy; 2: "TheExamIsEasy" ---> true 1: TheExamIsEasy; 2: "The*IsHard" ---> FALSE I am stucked on this question for many hours now! I need the solution in Java please kindly help me.

    Read the article

  • So, I guess I can't use "&&" in the Python if conditional. What should I use in this case? Any help?

    - by Sergio Tapia
    Here's my code: # F. front_back # Consider dividing a string into two halves. # If the length is even, the front and back halves are the same length. # If the length is odd, we'll say that the extra char goes in the front half. # e.g. 'abcde', the front half is 'abc', the back half 'de'. # Given 2 strings, a and b, return a string of the form # a-front + b-front + a-back + b-back def front_back(a, b): # +++your code here+++ if len(a) % 2 == 0 && len(b) % 2 == 0: return a[:(len(a)/2)] + b[:(len(b)/2)] + a[(len(a)/2):] + b[(len(b)/2):] else: #todo! Not yet done. :P return I'm getting an error in the IF conditional. What am I doing wrong? Edit: I meant no arrogance here. Someone edited my question title to make it sound douchy. I was genuinely confused about what to use, didn't think 'and' would be a keyword. Please don't downvote as other newbies might be confused about it as well.

    Read the article

  • compilation error

    - by Bond
    #include<dirent.h> #include<stdio.h> #include<stdlib.h> #include<sys/stat.h> int main () { struct dirent **namelist; int i,j; char userd[20]; struct stat statBuf; printf("Enter a directory %s\n",userd); scanf("%s",&userd); printf("the dir is %s\n",*userd); i=scandir(".",&namelist,0,alphasort); printf("enter a directory name %s",*userd); printf("scandir returned i=%d\n",&i); if (i<0) perror("Scandir failed to open directory I hope you understand \n"); else { for(j=0;j<i;j++) { printf("j=%d i=%d %s\n",j,i,namelist[j]->d_name); // lstat free(namelist[j]); } } free(namelist); } Can some one help to understand why am I getting warning in above code?

    Read the article

  • Java: Incompatible Types

    - by user2922081
    import java.text.*; import java.util.*; public class Proj3 { public static void main(String[]args){ // DecimalFormat df = new DecimalFormat("#0.00”); Scanner s = new Scanner(System.in); int TotalHours = 0; int TotalGrade = 0; System.out.print("How many courses did you take? "); int Courses = Integer.parseInt(s.nextLine()); System.out.println(""); int CourseNumber = Courses - (Courses - 1); while (Courses > 0){ System.out.print("Course (" + CourseNumber +"): How many hours? "); int Hours = Integer.parseInt(s.nextLine()); TotalHours = TotalHours + Hours; System.out.print("Course (" + CourseNumber +"): Letter grade? "); char Grade = s.nextLine().charAt(0); if (Grade == 'A'){ TotalGrade = TotalGrade + (4 * Hours); } if (Grade == 'B'){ TotalGrade = TotalGrade + (3 * Hours); } if (Grade == 'C'){ TotalGrade = TotalGrade + (2 * Hours); } if (Grade == 'D'){ TotalGrade = TotalGrade + (1 * Hours); } Courses = Courses - 1; CourseNumber = CourseNumber + 1; } Double GPA = TotalGrade / TotalHours; System.out.println(df.format(GPA)); } } This is for an assignment and I don't know how to fix my problem. The Double GPA = TotalGrade / ToutalHours; line is coming up with the Incompatible Types error. Also I'm supposed to include the DecimalFormat df = new DecimalFormat("#0.00”);line at the beginning of the main but its not working. Anything is very helpful. Thanks

    Read the article

  • when will come the new C++ standard? C++0x

    - by Oops
    Hi, when will the new C++ standard became official? C++ was standardized in 1998 and the standard is called C++98 the C++ standard was updated in 2003 and is called C++03 so the unofficial name "C++0x" lead us to the wrong conclusion that it will come within the first decade of the 20th century. Have u also mentioned that we all make the year 2000 bug again? Now we have 2010 so if you take the X as the latin sign for 10 it should come out this year. But no, also this would be wrong. The answer: The name of the language was always part of the language itself. As we all know the ++ operator means: one more But we have learned in some situations it would be better to write ++C so the other way around often is better. and what does the characters 0x mean in the C++ language? Right it's the prefix for a hexadecimal number. Now the question is easy to answer, it's meaning is: 0x++C int main(){ std::cout << "When will the new C++ standard come out? " << std::endl; int x0_ = 0x7D0, _0x = x0_, C = 0xC, Y1 = C+++_0x, Y2 = x0_+++C; std::cout << "it will be standardized between the Years: " << Y1 << " and " << Y2 << std::endl; char c; std::cin >> c; return 0; } do you agree? regards Oops

    Read the article

  • QMetaMethods for regular methods missing?

    - by oleks
    Hi, I'm new in QT, and I'm just testing out the MOC. For a given class: class Counter : public QObject { Q_OBJECT int m_value; public: Counter() {m_value = 0;} ~Counter() {} int value() {return m_value;} public slots: void setValue(int value); signals: void valueChanged(int newValue); }; I want to get a list of all methods in a class, but seem to only be getting a list of signals and slots, although the documentation says it should be all methods? Here's my code: #include <QCoreApplication> #include <QObject> #include <QMetaMethod> #include <iostream> using std::cout; using std::endl; int main(int argc, char *argv[]) { QCoreApplication app(argc, argv); const QMetaObject cntmo = Counter::staticMetaObject; for(int i = 0; i != cntmo.methodCount(); ++i) { QMetaMethod qmm(cntmo.method(i)); cout << qmm.signature() << endl; } return app.exec(); } Please beware this is my best c/p, perhaps I forgot to include some headers. My output: destroyed(QObject*) destroyed() deleteLater() _q_reregisterTimers(void*) valueChanged(int) setValue(int) Does anyone know why this is happening? Does qt not recognise int value() {return m_value;} as a valid method? If so, is there a macro I've forgotten or something like that? P.S. I'm using 4.6.2 UPDATE I forgot the implementation of the setValue method, not that it makes too much a difference to my actual question. void Counter::setValue(int value) { if(value != m_value) { m_value = value; emit valueChanged(value); } }

    Read the article

  • When to use () with classes?

    - by SoulBeaver
    This is really starting to confuse the hell out of me. When do I use them, when don't I? For example I was reading a .cpp on linked lists whose class declaration was: struct CarPart { long PartNumber; char Partname[40]; double UnitPrice; CarPart *next; }; class ListOfParts { int size; public: CarPart *head; ListOfParts(); ~ListOfParts(); const int count() const; void insert( CarPart *item ); CarPart *retrieve( int pos ); }; With this code, why am I allowed to write ListOfParts *pPart = new ListOfParts(); CarPart *pCarPart = new CarPart; Declaring an instance of ListOfParts requires (), but not my CarPart? That's confusing me. When I asked a question before and people told me that such a declaration is a function that returns a ListOfParts object, but not the actual constructor. So I'm guessing this is still something different. What's happening here? PS: Am I correct to assume that the const to the right of count() means I cannot modify any values in count?

    Read the article

  • multiple mysql_real_query() in while loop

    - by Steve
    It seems that when I have one mysql_real_query() function in a continuous while loop, the query will get executed OK. However, if multiple mysql_real_query() are inside the while loop, one right after the other. Depending on the query, sometimes neither the first query nor second query will execute properly. This seems like a threading issue to me. I'm wondering if the mysql c api has a way of dealing with this? Does anyone know how to deal with this? mysql_free_result() doesn't work since I am not even storing the results. //keep polling as long as stop character '-' is not read while(szRxChar != '-') { // Check if a read is outstanding if (HasOverlappedIoCompleted(&ovRead)) { // Issue a serial port read if (!ReadFile(hSerial,&szRxChar,1, &dwBytesRead,&ovRead)) { DWORD dwErr = GetLastError(); if (dwErr!=ERROR_IO_PENDING) return dwErr; } } // Wait 5 seconds for serial input if (!(HasOverlappedIoCompleted(&ovRead))) { WaitForSingleObject(hReadEvent,RESET_TIME); } // Check if serial input has arrived if (GetOverlappedResult(hSerial,&ovRead, &dwBytesRead,FALSE)) { // Wait for the write GetOverlappedResult(hSerial,&ovWrite, &dwBytesWritten,TRUE); //load tagBuffer with byte stream tagBuffer[i] = szRxChar; i++; tagBuffer[i] = 0; //char arrays are \0 terminated //run query with tagBuffer if( strlen(tagBuffer)==PACKET_LENGTH ) { sprintf(query,"insert into scan (rfidnum) values ('"); strcat(query, tagBuffer); strcat(query, "')"); mysql_real_query(&mysql,query,(unsigned int)strlen(query)); i=0; } mysql_real_query(&mysql,"insert into scan (rfidnum) values ('2nd query')",(unsigned int)strlen("insert into scan (rfid) values ('2nd query')")); mysql_free_result(res); } }

    Read the article

  • What encoding does c32rtomb convert to?

    - by R. Martinho Fernandes
    The functions c32rtomb and mbrtoc32 from <cuchar>/<uchar.h> are described in the C Unicode TR (draft) as performing conversions between UTF-321 and "multibyte characters". (...) If s is not a null pointer, the c32rtomb function determines the number of bytes needed to represent the multibyte character that corresponds to the wide character given by c32 (including any shift sequences), and stores the multibyte character representation in the array whose first element is pointed to by s. (...) What is this "multibyte character representation"? I'm actually interested in the behaviour of the following program: #include <cassert> #include <cuchar> #include <string> int main() { std::u32string u32 = U"this is a wide string"; std::string narrow = "this is a wide string"; std::string converted(1000, '\0'); char* ptr = &converted[0]; std::mbstate_t state {}; for(auto u : u32) { ptr += std::c32rtomb(ptr, u, &state); } converted.resize(ptr - &converted[0]); assert(converted == narrow); } Is the assertion in it guaranteed to hold1? 1 Working under the assumption that __STDC_UTF_32__ is defined.

    Read the article

  • storing user input into string array in C

    - by Jcmoney1010
    I'm writing a program that is supposed to take in a list of names from the user, store them in an array, and then search through the list to check and see if the next name the user enters is part of the original list of names. The issue I'm having is that when I go to enter a list of names, it only saves the last name entered into the list. I've searched the web and this site for similar issues, but I can't seem to find anything that answers this issue specifically. Here is the part of code where I have problem void initialize(char names[][],const int MAX_NAMES,const int MAX_NAMELENGTH) { int i,Number_entrys; printf("How many names would you like to enter to the list?"); scanf("%d",&Number_entrys); if(Number_entrys>MAX_NAMES){ printf("Please choose a smaller entry"); }else{ for (i=0; i<Number_entrys;i++){ scanf("%s",names); } } printf("%s",names); } trying very hard to teach myself, so be gentle lol.

    Read the article

  • HELP IN JAVA!! URGENT

    - by annayena
    The following function accepts 2 strings, the 2nd (not 1st) possibly containing *'s (asterisks). An * is a replacement for a string (empty, 1 char or more), it can appear appear (only in s2) once, twice, more or not at all, it cannot be adjacent to another * (ab**c), no need to check that. public static boolean samePattern(String s1, String s2) It returns true if strings are of the same pattern. It must be recursive, not use any loops, static & global variables. Also it's PROHIBITED to use the method equals in the String class. Can use local variables & method overloading. Can use only these methods: charAt(i), substring(i), substring(i, j), length(). Examples: 1: TheExamIsEasy; 2: "The*xamIs*y" --- true 1: TheExamIsEasy; 2: "Th*mIsEasy*" --- true 1: TheExamIsEasy; 2: "*" --- true 1: TheExamIsEasy; 2: "TheExamIsEasy" --- true 1: TheExamIsEasy; 2: "The*IsHard" --- FALSE I am stucked on this question for many hours now! I need the solution in Java please kindly help me.

    Read the article

  • C related, store a signed long int (32bit) as 4 octets?

    - by Doori Bar
    I managed to get a unsigned long int octets-representation (BE) by reading IPv4 methods, and I managed to read about how signed integers are using the MSB as the sign indicator, which makes 00 00 00 00 to be 0, while 7F FF FF FF is 2147483647. But I can't manage how to do the same for signed long integers? #include <stdio.h> #include <string.h> int main (void) { unsigned long int intu32; unsigned char octets[4]; intu32 = 255; octets[3] = (intu32) & 255; octets[2] = (intu32 >> 8) & 255; octets[1] = (intu32 >> 16) & 255; octets[0] = (intu32 >> 24) & 255; printf("(%d)(%d)(%d)(%d)\n", octets[0], octets[1], octets[2], octets[3]); intu32 = (octets[0] << 24) | (octets[1] << 16) | (octets[2] << 8) | octets[3]; printf("intu32:%lu\n", intu32); return 0; } Thanks in advance, Doori bar

    Read the article

  • QMetaMethod for regular methods missing?

    - by oleks
    Hi, I'm new in QT, and I'm just testing out the MOC. For a given class: class Counter : public QObject { Q_OBJECT int m_value; public: Counter() {m_value = 0;} ~Counter() {} int value() {return m_value;} public slots: void setValue(int value); signals: void valueChanged(int newValue); }; I want to get a list of all methods in a class, but seem to only be getting a list of signals and slots, although the documentation says it should be all methods? Here's my code: #include <QCoreApplication> #include <QObject> #include <QMetaMethod> #include <iostream> using std::cout; using std::endl; int main(int argc, char *argv[]) { QCoreApplication app(argc, argv); const QMetaObject cntmo = Counter::staticMetaObject; for(int i = 0; i != cntmo.methodCount(); ++i) { QMetaMethod qmm(cntmo.method(i)); cout << qmm.signature() << endl; } return app.exec(); } Please beware this is my best c/p, perhaps I forgot to include some headers. My output: destroyed(QObject*) destroyed() deleteLater() _q_reregisterTimers(void*) valueChanged(int) setValue(int) Does anyone know why this is happening? Does qt not recognise int value() {return m_value;} as a valid method? If so, is there a macro I've forgotten or something like that? P.S. I'm using 4.6.2

    Read the article

  • Returning a dynamically created array from function

    - by informer2000
    I'm trying to create a function that would dynamically allocate an array, sets the values of the elements, and returns the size of the array. The array variable is a pointer that is declared outside the function and passed as a parameter. Here is the code: #include <cstdlib> #include <iostream> using namespace std; int doArray(int *arr) { int sz = 10; arr = (int*) malloc(sizeof(int) * sz); for (int i=0; i<sz; i++) { arr[i] = i * 5; } return sz; } int main(int argc, char *argv[]) { int *arr = NULL; int size = doArray(arr); for (int i=0; i<size; i++) { cout << arr[i] << endl; } return 0; } For some reason, the program terminates on the first iteration of the for loop in main()! Am I doing something wrong?

    Read the article

  • MySQL Check and compare and if necessary create data.

    - by user2979677
    Hello I have three different tables Talk ID type_id YEAR NUM NUM_LETTER DATE series_id TALK speaker_id SCRIPREF DONE DOUBLE_SID DOUBLE_TYP LOCAL_CODE MISSING RESTRICTED WHY_RESTRI SR_S_1 SR_E_1 BCV_1 SR_S_2 SR_E_2 BCV_2 SR_S_3 SR_E_3 BCV_3 SR_S_4 SR_E_4 BCV_4 QTY_IV organisation_id recommended topic_id thumbnail mp3_file_size duration version Product_component id product_id talk_id position version Product id created product_type_id last_modified last_modified_by num_sold current_stock min_stock max_stock comment organisation_id series_id name subscription_type_id recipient_id discount_start discount_amount discount_desc discount_finish discount_percent voucher_amount audio_points talk_id price_override product_desc instant_download_status_id downloads instant_downloads promote_start promote_finish promote_desc restricted from_tape discontinued discontinued_reason discontinued_date external_url version I want to create a procedure that will check if select the id from talk and compare it with the id of product to see if there is a product id in the table and if there isn't then create it however my problem is that my tables talk and product can't talk, as id in talk is related to talk_id in product_component and id in product is related to product_id in product_component. Are there any ways for this to be done? I tried this, CREATE DEFINER=`sthelensmedia`@`localhost` PROCEDURE `CreateSingleCDProducts`() BEGIN DECLARE t_id INT; DECLARE t_restricted BOOLEAN; DECLARE t_talk CHAR(255); DECLARE t_series_id INT; DECLARE p_id INT; DECLARE done INT DEFAULT 0; DECLARE cur1 CURSOR FOR SELECT id,restricted,talk,series_id FROM talk WHERE organisation_id=2; DECLARE CONTINUE HANDLER FOR NOT FOUND SET done=1; UPDATE product SET restricted=TRUE WHERE product_type_id=3; OPEN cur1; create_loop: LOOP FETCH cur1 INTO t_id, t_restricted, t_talk, t_series_id; IF done=1 THEN LEAVE create_loop; END IF; INSERT INTO product (created,product_type_id,last_modified,organisation_id,series_id,name,restricted) VALUES (NOW(),3,NOW(),2,t_series_id,t_talk,t_restricted); SELECT LAST_INSERT_ID() INTO p_id; INSERT INTO product_component (product_id,talk_id,position) VALUES (p_id,t_id,0); END LOOP create_loop; CLOSE cur1; END Just wondering if anyone could help me.

    Read the article

  • make it simpler and efficient

    - by gcc
    temp1=*tutar[1]; //i hold input in char *tutar[] if(temp1!='x'||temp1!='n') arrays[1]=malloc(sizeof(int)*num_arrays); //if second input is int a=0; n=i; for(i=1;i<n;++i) { temp1=*tutar[i]; if(temp1=='d') { ++i; j=atoi(tutar[i]); free(arrays[j]); continue; } if(temp1=='x') break; if(temp1=='n')//if it is n { a=0; ++j; arrays[j]=malloc(sizeof(int)*num_arrays);//create and allocate continue; } ++a; if(a>num_arrays) //resize the array arrays[j]=realloc(arrays[j],sizeof(int)*(num_arrays+a)); *(arrays[j]+a-1)=atoi(tutar[i]); printf("%d",arrays[1][1]); } arrays is pointer when you see x exit you see n create (old one is new array[a] new one is array[i+1]) you see d delete arrays[i] according to int after d first number is size of max arrays and where is the error in code input is composed from int and n d x i make a program -taking input(first input must be int) -according to input(there is comman in input like n or d or j , i fill array with number and use memory efficiently -j is jumb to array[x] ( x is int coming after j in input)

    Read the article

  • Reading a text file, and performing actions based on strings read

    - by user1691766
    Let me start off by saying that I really am quite new to C. So basically I have a text file (contains around 30 assembly instructions, separated by new lines), and I am successfully reading them into my program. From here I need to perform certain actions based off each instruction. I would assume the best way to do this would be via a switch-case statement. However I am encountering a lot of problems due to me trying to compare strings that are 33 characters long. Can anyone please offer me advice on what I am doing wrong, or offer an alternative? Thanks in advance. Here is what I have so far: char instruction[29][ 33 ]; int i,run; i = 0; run = 1; FILE *instPtr; /* LOADING INSTRUCTIONS FROM FILE INTO "instruction" ARRAY*/ if ( ( instPtr = fopen("MIPSinstructions.txt", "r") ) == NULL ) { printf("File could not be opened\n"); } // end if else { fscanf( instPtr, "%s", instruction[0]); printf("%s\n", instruction[0]); while (!feof( instPtr ) ){ i++; fscanf( instPtr, "%s", instruction[i]); printf("%s\n", instruction[i]); } fclose( instPtr ); i = 0; // Reset the counter } //end else return 0; }

    Read the article

  • Having trouble deleting a node from a linked list

    - by Requiem
    I've been working on this code for my shell that I'm creating and for some reason it isn't working. I'm implementing a watchuser function that watch's a user when an argument is given (args[1]). However, when a second argument (args[2]) of "off" is given, the user should be deleted from the linked list and should no longer be watched. struct userList * goList; goList = userInventory; do{ if (strcmp(userInventory->username, args[1]) == 0){ printf("%s\n", args[1]); printf("%s\n",userInventory->username); struct userList * temp2; temp2 = userInventory->next; if (userInventory->next != NULL){ userInventory->next = temp2->next; userInventory->next->prev = userInventory; } free(temp2); } goList = goList->next; }while (goList != userInventory); My global struct is also as follows: struct userList{ char * username; struct userList * prev; struct userList * next; } For reason, this code won't delete the user node from my linked list. The adding works, but this remove function won't and I'm not sure why. The print statements are there just to make sure it's executing the condition, which it is. If anyone could help me find the reasoning behind my error, I'd greatly appreciate it. Till then, I'll be trying to debug this. Thanks.

    Read the article

< Previous Page | 182 183 184 185 186 187 188 189 190 191 192 193  | Next Page >