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  • Referencing java resource files for cold fusion

    - by Chimeara
    I am using a .Jar file containing a .properties file in my CF code, however it seems unable to find the .properties file when run from CF. My java code is: String key =""; String value =""; try { File file = new File("src/test.properties"); FileInputStream fileInput = new FileInputStream(file); Properties properties = new Properties(); properties.load(fileInput); fileInput.close(); Enumeration enuKeys = properties.keys(); while (enuKeys.hasMoreElements()) { key = (String) enuKeys.nextElement(); value = properties.getProperty(key); //System.out.println(key + ": " + value); } } catch (FileNotFoundException e) { e.printStackTrace(); key ="error"; } catch (IOException e) { e.printStackTrace(); key ="error"; } return(key + ": " + value); I have my test.properties file in the project src folder, and make sure it is selected when compiling, when run from eclipse it gives the expected key and value, however when run from CF I get the caught errors. My CF code is simply: propTest = CreateObject("java","package.class"); testResults = propTest.main2(); Is there a special way to reference the .properties file so CF can access it, or do I need to include the file outside the .jar somewhere?

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  • How to get base url with php?

    - by shin
    I am using XAMPP on windows vista. In my development, I have http://127.0.0.1/test_website/ Now I would like get this http://127.0.0.1/test_website/ with php. I tried something like these, but none of them worked. echo dirname(__FILE__) or echo basename(__FILE__); etc. I will appreciate any help. Thanks in advance.

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  • PHP: Fastest way possible to read contents of a file.

    - by SoLoGHoST
    Ok, I'm looking for the fastest possible way to read all of the contents of a file via php with a filepath on the server, also these files can be huge. So it's very important that it does a READ ONLY to it as fast as possible. Is reading it line by line faster than reading the entire contents? Though, I remember reading up on this some, that reading the entire contents can produce errors for huge files. Is this true?

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  • [NSData dataWithContentsOfFile:path] doesn't work

    - by Felics
    Hello, when I have the fallowing code to read a binary file: NSString* file = [NSString stringWithUTF8String:fileName]; NSString* filePath = resource ? [[NSBundle mainBundle] pathForResource:file ofType:nil] : [[NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES) objectAtIndex:0] stringByAppendingPathComponent: file]; NSData* fileData = [NSData dataWithContentsOfFile:filePath]; Where "fileName" and resource are load function parameters. "resource" is used to know if the file is located in application bundle or in Documents. Sometimes this code works well and sometimes it doesn't. As far I saw this problem is random. I can run the code 10 times in a row and it works fine and after that it gives me nil data without any modification. Does anybody knows what could be the problem? Could it be related with file extension or file name? Thank you. PS: I use this code on iPhone Simulator and the file exists in application bundle.

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  • Need to have JProgress bar to measure progress when copying directories and files

    - by user1815823
    I have the below code to copy directories and files but not sure where to measure the progress. Can someone help as to where can I measure how much has been copied and show it in the JProgress bar public static void copy(File src, File dest) throws IOException{ if(src.isDirectory()){ if(!dest.exists()){ //checking whether destination directory exisits dest.mkdir(); System.out.println("Directory copied from " + src + " to " + dest); } String files[] = src.list(); for (String file : files) { File srcFile = new File(src, file); File destFile = new File(dest, file); copyFolder(srcFile,destFile); } }else{ InputStream in = new FileInputStream(src); OutputStream out = new FileOutputStream(dest); byte[] buffer = new byte[1024]; int length; while ((length = in.read(buffer)) > 0){ out.write(buffer, 0, length); } in.close(); out.close(); System.out.println("File copied from " + src + " to " + dest); }

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  • Is there a way to efficiently yield every file in a directory containing millions of files?

    - by Josh Smeaton
    I'm aware of os.listdir, but as far as I can gather, that gets all the filenames in a directory into memory, and then returns the list. What I want, is a way to yield a filename, work on it, and then yield the next one, without reading them all into memory. Is there any way to do this? I worry about the case where filenames change, new files are added, and files are deleted using such a method. Some iterators prevent you from modifying the collection during iteration, essentially by taking a snapshot of the state of the collection at the beginning, and comparing that state on each move operation. If there is an iterator capable of yielding filenames from a path, does it raise an error if there are filesystem changes (add, remove, rename files within the iterated directory) which modify the collection? There could potentially be a few cases that could cause the iterator to fail, and it all depends on how the iterator maintains state. Using S.Lotts example: filea.txt fileb.txt filec.txt Iterator yields filea.txt. During processing, filea.txt is renamed to filey.txt and fileb.txt is renamed to filez.txt. When the iterator attempts to get the next file, if it were to use the filename filea.txt to find it's current position in order to find the next file and filea.txt is not there, what would happen? It may not be able to recover it's position in the collection. Similarly, if the iterator were to fetch fileb.txt when yielding filea.txt, it could look up the position of fileb.txt, fail, and produce an error. If the iterator instead was able to somehow maintain an index dir.get_file(0), then maintaining positional state would not be affected, but some files could be missed, as their indexes could be moved to an index 'behind' the iterator. This is all theoretical of course, since there appears to be no built-in (python) way of iterating over the files in a directory. There are some great answers below, however, that solve the problem by using queues and notifications. Edit: The OS of concern is Redhat. My use case is this: Process A is continuously writing files to a storage location. Process B (the one I'm writing), will be iterating over these files, doing some processing based on the filename, and moving the files to another location. Edit: Definition of valid: Adjective 1. Well grounded or justifiable, pertinent. (Sorry S.Lott, I couldn't resist). I've edited the paragraph in question above.

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  • Polling a web URL until event

    - by Jaxo
    I'm really sorry about the crappy title - if anybody has a better way of wording it, please edit it! I basically need to have a C# application run a function if the output of a URL is a certain value. For example, if the website says blue the background colour will be blue, red to make it red, etc. The problem is I don't want to spam my webserver with checks. The 4 bytes it downloads each time is negligible, but if I were to deploy this type of system on multiple computers, it would get slower and slower and the bandwidth would add up quickly. So my question is: How can my desktop application run a piece of code only when a web URL has a different output without checking each time? I can't use sockets, and any sort of LAN protocol won't end up working. My reasoning behind this potentially nefarious code is to be able to mute computers by updating a file on the website (as you may have seen in my previous question today, sorry!). I'd like it to be rather quick, and not have the refresh time minutes apart, a few seconds at the most would be ideal. How can I accomplish this? The website's code is easy, but getting the C# application to check when it changes is the part I'm stuck on. Nothing shows up on the website other than the command. Thanks!

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  • Anyone know any good backend user online file manager?

    - by skyhigh
    Hi I'm looking for a backend system where your clients can login and upload files to your server, download files from the server and you can delete the users, create users, etc. I do not know the proper name for this kind of software. Maybe its called online file manager? Any recommendations? My server supports PHP, apache and mysq. Thanks

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  • how to return url in form file in strut

    - by Najmi
    hai all, i have one problem regarding to return the form file value is validation fail. i have one form that have a few field to be fullfil by the user and one attachment field.if one of the field is blank the system will give the error when submit the form..my problem is, all the field will have the value that we entered before this but for form file it disappear.

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  • Passing HTML form data in the URL on local machine (file://)

    - by atzz
    Hi, I'm building a small HTML/JS application for primary use on local machine (i.e. everything is accessed via file:// protocol, though maybe in the future it will be hosted on a server within intranet). I'm trying to make a form with method="get" and action="target.html", in the hope that the browser will put form data in the URL (like, file://<path>/target.html?param1=aaa&param2=bbb). However, it's not happening (target.html opens fine, but no parameters is passed). What am I doing wrong? Is it possible to use forms over file:// at all? I can always build the url manually (via JS), but being lazy I'd prefer the browser do it for me. ;) Here is my sample form: <form name='config' action="test_form.html" method="get" enctype="application/x-www-form-urlencoded"> <input type="text" name="param1"> <input type="text" name="param2"> <input type="submit" value="Go"> </form>

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  • [Python] How to create a named temporary file in memory?

    - by conradlee
    I would like to use Python's tempfile module to create a temporary file that I will use for communication between processes (use of pipes is awkward). The documentation I've linked to above shows two functions that almost do what I want: tempfile.NamedTemporaryFile # For creating named tempfiles tempfile.SpooledTemporaryFile # For creating tempfiles in memory but actually I want a tempfile that is both named AND in memory. Any ideas?

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  • Beginner servlet question: accessing files in a .war, which path?

    - by Navigateur
    When a third-party library I'm using tries to access a file, I'm getting "Error opening ... file ... (No such file or directory)" even though I KNOW the file is in the WAR. I've tried both packaged (.war) and "exploded" (directory) deployment, and the file is definitely there. I've tried setting full permissions on it too. It's on Unix (Ubuntu). File is war/dict/index.sense and the error is "dict/index.sense (No such file or directory)". It works fine on my Windows computer when running in hosted mode as a GWT app from Eclipse, just not when I transfer it to the Unix machine for deployment. My question is: has anybody experienced this before and/or are there differences in relative path that I should consider i.e. what's the root path for relative file access in a war?

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  • Can I use php's fwrite with 644 file permissions?

    - by filip
    I am trying to set up automated .htaccess updating. This clearly needs to be as secure as possible, however right now the best I can do file permission-wise is 666. What can I do to setup either my server or php code so that my script's fwrite() command will work with 644 or better? For instance is there a way to set my script(s) to run as owner?

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