Search Results

Search found 25888 results on 1036 pages for 'image map'.

Page 186/1036 | < Previous Page | 182 183 184 185 186 187 188 189 190 191 192 193  | Next Page >

  • CSS Rollovers: how to maintain "hit area" size when hidden image is larger than anchor area

    - by nukefusion
    I have a small problem and I don't think what I want to do can be achieved with just pure CSS, but I figured I'd ask anyway. Basically, I have one DIV which contains a hyperlinked element that is smaller in size to it's parent DIV. So in effect I have a square within a square with the inner square being the "hit area". When I mouse over this inner square I want the background of the outer square to change. I know it's not possible to change the parent DIV's background on a:hover, but I figured I could give the illusion of it happening by nesting a hidden image inside the anchor. This works great until I want to "roll off". The problem is that I want the image to disappear when I leave the area of the anchor tag, not the larger hidden image. Is this possible? For the benefit of everyone I've provided an example to demonstrate what I mean: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta content="text/html; charset=utf-8" http-equiv="Content-Type" /> <title>Test Rollover</title> <link href="main.css" rel="stylesheet" type="text/css" /> </head> <body> <div id="d1"> <a href="#nogo"> <b id="b1"></b> <b id="b2"></b> </a> </div> </body> And the css: #b1 { width: 200px; height: 200px; top: 100px; left: 100px; background-color:aqua; position: absolute; z-index: 100; } #b2 { width: 400px; height: 400px; background-color:lime; position: absolute; display: none; z-index: 90; } #d1 { width: 400px; height: 400px; background-color:fuchsia; position: relative; } #d1 a:hover #b2 { display: block; } In this example I want the green outer square to disappear when I leave the bounds of the hidden inner blue square.

    Read the article

  • Reducing Time Complexity in Java

    - by Koeneuze
    Right, this is from an older exam which i'm using to prepare my own exam in january. We are given the following method: public static void Oorspronkelijk() { String bs = "Dit is een boodschap aan de wereld"; int max = -1; char let = '*'; for (int i=0;i<bs.length();i++) { int tel = 1; for (int j=i+1;j<bs.length();j++) { if (bs.charAt(j) == bs.charAt(i)) tel++; } if (tel > max) { max = tel; let = bs.charAt(i); } } System.out.println(max + " keer " + let); } The questions are: what is the output? - Since the code is just an algorithm to determine the most occuring character, the output is "6 keer " (6 times space) What is the time complexity of this code? Fairly sure it's O(n²), unless someone thinks otherwise? Can you reduce the time complexity, and if so, how? Well, you can. I've received some help already and managed to get the following code: public static void Nieuw() { String bs = "Dit is een boodschap aan de wereld"; HashMap<Character, Integer> letters = new HashMap<Character, Integer>(); char max = bs.charAt(0); for (int i=0;i<bs.length();i++) { char let = bs.charAt(i); if(!letters.containsKey(let)) { letters.put(let,0); } int tel = letters.get(let)+1; letters.put(let,tel); if(letters.get(max)<tel) { max = let; } } System.out.println(letters.get(max) + " keer " + max); } However, I'm uncertain of the time complexity of this new code: Is it O(n) because you only use one for-loop, or does the fact we require the use of the HashMap's get methods make it O(n log n) ? And if someone knows an even better way of reducing the time complexity, please do tell! :)

    Read the article

  • Reversing permutation of an array in Java efficiently

    - by HansDampf
    Okay, here is my problem: Im implementing an algorithm in Java and part of it will be following: The Question is to how to do what I will explain now in an efficient way. given: array a of length n integer array perm, which is a permutation of [1..n] now I want to shuffle the array a, using the order determined by array perm, i.e. a=[a,b,c,d], perm=[2,3,4,1] ------ shuffledA[b,c,d,a], I figured out I can do that by iterating over the array with: shuffledA[i]=a[perm[i-1]], (-1 because the permutation indexes in perm start with 1 not 0) Now I want to do some operations on shuffledA... And now I want to do the reverse the shuffle operation. This is where I am not sure how to do it. Note that a can hold an item more than once, i.e. a=[a,a,a,a] If that was not the case, I could iterate perm, and find the corresponding indexes to the values. Now I thought that using a Hashmap instead of the the perm array will help. But I am not sure if this is the best way to do.

    Read the article

  • How to handle alpha in a manual "Overlay" blend operation?

    - by quixoto
    I'm playing with some manual (walk-the-pixels) image processing, and I'm recreating the standard "overlay" blend. I'm looking at the "Photoshop math" macros here: http://www.nathanm.com/photoshop-blending-math/ (See also here for more readable version of Overlay) Both source images are in fairly standard RGBA (8 bits each) format, as is the destination. When both images are fully opaque (alpha is 1.0), the result is blended correctly as expected: But if my "blend" layer (the top image) has transparency in it, I'm a little flummoxed as to how to factor that alpha into the blending equation correctly. I expect it to work such that transparent pixels in the blend layer have no effect on the result, opaque pixels in the blend layer do the overlay blend as normal, and semitransparent blend layer pixels have some scaled effect on the result. Can someone explain to me the blend equations or the concept behind doing this? Bonus points if you can help me do it such that the resulting image has correctly premultiplied alpha (which only comes into play for pixels that are not opaque in both layers, I think.) Thanks! // factor in blendLayerA, (1-blendLayerA) somehow? resultR = ChannelBlend_Overlay(baseLayerR, blendLayerR); resultG = ChannelBlend_Overlay(baseLayerG, blendLayerG); resultB = ChannelBlend_Overlay(baseLayerB, blendLayerB); resultA = 1.0; // also, what should this be??

    Read the article

  • Display an Image using C# in Web Application

    - by Josh
    Hello again, I have a Web Application that I built a C# class in that generates a Report. This report takes nearly 40 seconds to generate because it searches hundreds of folders for certain files. So I was hoping there was a way to display a "Loading.." icon as this report is generating. I have a gif stored in my Images folder that would be perfect. The research that I've done at this point mostly talks about picturebox's and image controls that can hold the image but I was hoping there was just a way of displaying the image above the report while its being created. The Web Application is from a Web ADF Geocortex website and again I created a C# class that generates this report. Below is some code that may help. /// <summary> /// Generates HTML for the current report using the data in /// the given table. /// </summary> /// <param name="reportLayers">The layers to include in the report.</param> /// <returns> public override string GenerateReportHtml(List<ReportLayer> reportLayers) { StringBuilder htmlString = new StringBuilder(); StringWriter stringWriter = new StringWriter(htmlString); HtmlTextWriter writer = new HtmlTextWriter(stringWriter); string holdAPI = ""; List<string> exclusions = GetExcludedFields(); foreach (ReportLayer layer in reportLayers) { string[] strFiles = null; Boolean val = false; if (layer.Layer.Name == "Bottom Hole Location (OP)") writer.RenderBeginTag(HtmlTextWriterTag.P); // <p> writer.RenderBeginTag(HtmlTextWriterTag.Strong); // <strong> writer.Write(layer.Layer.Name); writer.RenderEndTag(); // end </strong> writer.RenderEndTag(); // end </p> writer.WriteBreak(); // <br /> foreach (ReportFeature feature in layer.ReportFeatures) { // each feature will be in a table writer.RenderBeginTag(HtmlTextWriterTag.Table); // <table> foreach (ReportField field in feature.ReportFields) { string fieldName = field.Alias; if (!exclusions.Contains(fieldName)) {

    Read the article

  • How to draw a transparent stroke (or anyway clear part of an image) on the iPhone

    - by devguy
    I have a small app that allows the user to draw on the screen with the finger. Yes, nothing original, but it's part of something larger :) I have a UIImageView where the user draws, by creating a CGContextRef and the various CG draw functions. I primarily draw strokes/lines with the function CGContextAddLineToPoint Now the problem is this: the user can draw lines of various colors. I want to give him the ability to use a "rubber" tool to delete some part of the image drawn so far, with the finger. I initially did this by using a white color for the stroke (set with the CGContextSetRGBStrokeColor function) but it did't work out...because I discovered later that the UIImage on the UIImageView was actually with transparent background, not white...so I would end up with a transparent image with white lines on it! Is there anyway to set a "transparent" stroke color...or is there any other way to clear the content of the CGContextRef under the user's finger, when he moves it? Thanks

    Read the article

  • How to scale an Image in ImageView to keep the aspect ratio

    - by michael
    Hi, In android, I defined an ImageView's layoutWidth to be 'fill_parent' (which takes up the full width of the phone). My question is if the Image i put to ImageView is bigger than the layoutWidth, android will scale it, right? But what about the height? when android scale it, will it keeps the aspect ratio? What I find out is, there is some 'white space' at the top/bottom of the ImageView when android scales an image which is bigger than the ImageView. Is that true? If yes, how can I eliminate that white spaces? Thank you.

    Read the article

  • CSS Rollovers: how to main "hit area" size when hidden image is larger than anchor area

    - by nukefusion
    I have a small problem and I don't think what I want to do can be achieved with just pure CSS, but I figured I'd ask anyway. Basically, I have one DIV which contains a hyperlinked element that is smaller in size to it's parent DIV. So in effect I have a square within a square with the inner square being the "hit area". When I mouse over this inner square I want the background of the outer square to change. I know it's not possible to change the parent DIV's background on a:hover, but I figured I could give the illusion of it happening by nesting a hidden image inside the anchor. This works great until I want to "roll off". The problem is that I want the image to disappear when I leave the area of the anchor tag, not the larger hidden image. Is this possible? For the benefit of everyone I've provided an example to demonstrate what I mean: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta content="text/html; charset=utf-8" http-equiv="Content-Type" /> <title>Test Rollover</title> <link href="main.css" rel="stylesheet" type="text/css" /> </head> <body> <div id="d1"> <a href="#nogo"> <b id="b1"></b> <b id="b2"></b> </a> </div> </body> And the css: #b1 { width: 200px; height: 200px; top: 100px; left: 100px; background-color:aqua; position: absolute; } #b2 { width: 400px; height: 400px; background-color:lime; position: absolute; display: none; } #d1 { width: 400px; height: 400px; background-color:fuchsia; position: relative; } #d1 a:hover #b2 { display: block; } In this example I want the green outer square to disappear when I leave the bounds of the hidden inner blue square.

    Read the article

  • Posting an image and textual based data to a wcf service

    - by James Hay
    I have a requirement to write a web service that allows me to post an image to a server along with some additional information about that image. I'm completely new to developing web services (normally client side dev) so I'm a little stumped as to what I need to look into and try. How do you post binary data and plain text into a servic? What RequestFormat should I use? It looks like my options are xml or json. Can I use either of these? Bit of a waffly question but I just need some direction rather than a solution as I can't seem to find much online.

    Read the article

  • Zoom image using delphi

    - by Himadri
    Hello All, I am working with delphi. I have TImage, to which I assign a bitmap. imgmain.Picture.Bitmap := bmpMain; imgmain.Picture.Bitmap.PixelFormat := pf24bit; imgmain is object of TImage and bmpMain is object of TBitmap I want to zoom my image. I have one trackbar on my form and as I click on trackbar the image should get zoom. What should I do? Thank You.

    Read the article

  • jQuery Ajax load images problem

    - by jackysee
    I have a code that would call $.load() to get an HTML fragment. In the fragment there will be a list of images and a script that would do some calculation based on the list size. The fragment looks like <div> <ul> <li><img .../></li> <li><img .../></li> ... </ul> </div> <script> //... script to do calculation on the list width </script> Originally, I use css's max-width to ensure that the image would not exceed 180px. But as IE has no max-width, I use the expression hack. However, it seems when the image are first load, the script cannot get a correct width of image list. Seems like the script load earlier than the CSS expression. If it is a new page, I can certainly call $(window).load() to ensure all the images are loaded. But what can I do in an ajax html fragment request?

    Read the article

  • Recursive Maze in Java

    - by Api
    I have written a short Java code for solving a simple maze problem to go from S to G. I do not understand where the problem is going wrong. import java.util.Scanner; public class tester { static char [][] grid={ {'.','.'}, {'.','.'}, {'S','G'}, }; static int a=2; static int b=2; static boolean findpath(int x, int y) { if((x > grid.length-1) || (y > grid[0].length-1) || (x < 0 || y < 0)) { return false; } else if(x==a && y==b){ return true; } else if (findpath(x,y-1) == true){ return true; } else if (findpath(x+1,y) == true){ return true; } else if (findpath(x,y+1) == true) { return true; } else if (findpath(x-1,y) == true){ return true; } return false; } public static void main(String[] args){ boolean result=findpath(2,0); System.out.print(result); } } I am giving the starting position directly and goal is defined in a & b. Do help.

    Read the article

  • CSS background image inconsistency in IE6 and IE7

    - by The Machine
    I have a span that is generated through javascript, with its css class as follows: .class1{ width:25px; height:25px; background-image: url(pic.png); background-repeat:no-repeat; background-position: center; cursor:pointer; margin-left:10px; } The problem is on, the html page, i can see the pointer -cursor, but not the background image,over the span, in IE7. In IE6, both get shown , no problems.

    Read the article

  • Background-image toggle using jquery

    - by Jon
    Hi all, bit of a jquery rookie here trying to get something to work. Basically I have a div with a class "nav" and inside that div is a nav list. I want to change the background-image of "nav" when hovering over an item in the navlist, so I made this unsuccesful effort: enter code here $(function(){ $("li#hover-first").mouseover(function(){ $("div.nav").removeClass("nav").addClass("navbg"); .mouseout(function(){$("div.nav").removeClass("navbg").addClass("nav"); }); So the idea is, once the first li item is hovered over, the div with classname "nav" has it's class removed and has "navbg" added (which has the alternate background image). Obviously this isn't working, so any help would be greatly appreciated...thanks.

    Read the article

  • empty() not a valid callback?

    - by user151841
    I'm trying to use empty() in array mapping in php. I'm getting errors that it's not a valid callback. $ cat test.php <? $arrays = array( 'arrEmpty' => array( '','','' ), ); foreach ( $arrays as $key => $array ) { echo $key . "\n"; echo array_reduce( $array, "empty" ); var_dump( array_map("empty", $array) ); echo "\n\n"; } $ php test.php arrEmpty Warning: array_reduce(): The second argument, 'empty', should be a valid callback in /var/www/authentication_class/test.php on line 12 Warning: array_map(): The first argument, 'empty', should be either NULL or a valid callback in /var/www/authentication_class/test.php on line 13 NULL Shouldn't this work? Long story: I'm trying to be (too?) clever and checking that all array values are not empty strings.

    Read the article

  • Draw a Image on FullScreen mode Android

    - by Marcos Vasconcelos
    Hi, I already know how to get my Activity as fullscreen on Android, now I need to draw a Image in this screen. This is my XML layout. <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent"> <ImageView android:id="@+id/image01" android:layout_width="fill_parent" android:layout_height="fill_parent" /> </LinearLayout> This image is dynamic generated and drawed in the ImageView. This is my code on my Activity. public void onCreate(Bundle savedInstance) { super.onCreate(savedInstance); requestWindowFeature(Window.FEATURE_NO_TITLE); getWindow().setFlags(WindowManager.LayoutParams.FLAG_FULLSCREEN, WindowManager.LayoutParams.FLAG_FULLSCREEN); setContentView(R.layout.main); } But when running, the Activity is FullScreen, but the ImageView is adjusted in the center. What's wrong?

    Read the article

< Previous Page | 182 183 184 185 186 187 188 189 190 191 192 193  | Next Page >