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  • Sharing same properties of ViewController for iPhone Stroryboard and iPad Story Board

    - by Ruhul Amin
    I'm developing a universal application. in the first view, I have the login screen for the user. In iPhone storyBoard, I have added 2 text field and one button( login check). I have added properties in ViewController.h file by dragging those objects(Ctrl key + Dragg) to .h file. I have added code for login check and it is working fine for iPhone. This is the code in ViewController.h @property (strong, nonatomic) IBOutlet UITextField *txtUserId; @property (strong, nonatomic) IBOutlet UITextField *txtUserPwd; @property (strong, nonatomic) IBOutlet UIButton *btnLogin; In the iPad storyBoard, I have added 2 text field( userid and password) and i button for login. So now, I want to bind those objects with the veriable which I declared already in ViewController.h file in case of iPhone. My questions: 1. What is the right way to bind properties for both storyboard? 2. Am I on the right direction or should I think in a different way to do it? I am new with iPhone development. Please help. Thanks. --Amin

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  • Codeigniter Inputting session data from model for a simple authentication system

    - by user1616244
    Trying to put together a simple login authentication. Been at this for quite sometime, and I can't find where I'm going wrong. Pretty new to Codeigniter and OOP PHP. I know there are authentication libraries out there, but I'm not interested in using those. Model: function login($username, $password){ if ($this->db->table_exists($username)){ $this->db->where('username', $username); $this->db->where('password', $password); $query = $this->db->get($username); if($query->num_rows >= 1) { return true; $data = array( 'username' => $this->input->post('username'), 'login' => true ); $this->session->set_userdata($data); } } } Controller function __construct(){ parent::__construct(); $this->logincheck(); } public function logincheck(){ if ($this->session->userdata('login')){ redirect('/members'); } } If I just echo from the controller: $this-session-all_userdata(); I get an empty array. So the problem seems to be that the $data array in the model isn't being stored in the session.

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  • The post->success->data variable is empty..

    - by Asaf
    Hello, I tried sending some data like so: <form action="http://www.someurl.com/something.php" id="login"> <input type="textbox" id="UserName" value="user"> <input type="textbox" id="Password" value="password"> <input type="submit" value="submit"> </form> <div id="result"></div> <script type="text/javascript"> $('form#login').submit(function() { $.post($('form#login').attr('action'), $('form#login').serialize(), function(data) { $('#result').html(data+'222') }); return false; }); </script> Now, the value of #result div change to 222... that is: the post was successful but for some reason there is no data, and when I go directly to something.php and post manually, it does bring back data (am I mistaken or does the post(success(data)) variable returns the whole page returned after you post something? if so, how could it be?) Thank you very much for your help

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  • What would be a better implementation of shared variable among subclass

    - by Churk
    So currently I have a spring unit testing application. And it requires me to get a session cookie from a foreign authentication source. Problem what that is, this authentication process is fairly expensive and time consuming, and I am trying to create a structure where I am authenticate once, by any subclass, and any subsequent subclass is created, it will reuse this session cookie without hitting the authentication process again. My problem right now is, the static cookie is null each time another subclass is created. And I been reading that using static as a global variable is a bad idea, but I couldn't think of another way to do this because of Spring framework setting things during run time and how I would set the cookie so that all other classes can use it. Another piece of information. The variable is being use, but is change able during run time. It is not a single user being signed in and used across the board. But more like a Sub1 would call login, and we have a cookie. Then multiple test will be using that login until SubX will come in and say, I am using different credential, so I need to login as something else. And repeats. Here is a outline of my code: public class Parent implements InitializingBean { protected static String BASE_URL; public static Cookie cookie; ... All default InitializingBean methods ... afterPropertiesSet() { cookie = // login process returns a cookie } } public class Sub1 extends Parent { @resource public String baseURL; @PostConstruct public void init() { // set parents with my baseURL; BASE_URL = baseURL; } public void doSomething() { // Do something with cookie, because it should have been set by parent class } } public class Sub2 extends Parent { @resource public String baseURL; @PostConstruct public void init() { // set parents with my baseURL; BASE_URL = baseURL; } public void doSomethingElse() { // Do something with cookie, because it should have been set by parent class } }

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  • How can I debug PEAR auth?

    - by croceldon
    I have a directory on my site that I've implemented PEAR's Auth to run my authentication. It is working great. However, I've tried to make a copy of my site (it's going to be translated to a different language), and on this new site, the Auth process doesn't seem to be working correctly. I can login properly, but every time I try to go to a different page in the same directory, and use Auth to authorize, it forces me to login again. Here's my logic: $auth_options = array( 'dsn' => mysql://user:password@server/db', 'table' => 'users', 'usernamecol' => 'username', 'passwordcol' => 'password', 'db_fields' => '*' ); $auth = new Auth("DB", $auth_options, "login_function"); $auth->setFailedLoginCallback('bad_login'); $auth->start(); if (!$auth->checkAuth()) { die('cannot succeed in checkAuth') exit; } else { include("nocache.php"); } This is part of a file that's included in every php page I that I desire to require authentication. I can login properly once, but whenever I then try to go to a different page that requires authentication, it makes me login again (and I see the 'cannot succeed' die message at the bottom of the page). Again, this solution works fine on my original site, I copied all the files, and only changed the db server/password - it still doesn't work. And I'm using the same webhost for both. What am I doing wrong here? Or how can I debug this further?

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  • javax.xml.bind.MarshalException

    - by sandeep
    Hi, I am getting javax.xml.bind.MarshalException error. I am sending List from my webservice to the backingbean and I have this error. Here is my code: Backing bean @WebServiceRef(wsdlLocation = "http://localhost:26565/Login_webserviceService/Login_webservice?WSDL") public String login() { System.out.println("Login Phase entered"); int result = 0; List list; List finalList = null; try { Weblogin.LoginWebserviceService service = new Weblogin.LoginWebserviceService(); Weblogin.LoginWebservice port = service.getLoginWebservicePort(); result = port.login(voterID, password); Weblogin.LoginWebservice port1 = service.getLoginWebservicePort(); list = port1.candDetails(1); finalList = list; this.setList(finalList); } catch (Exception e) { e.printStackTrace(); } if (result == 1) return "polling"; else return "login"; } Webservice public List candDetails(int pollEvent) { List resultList = null; List finalList = null; try { if (pollEvent == 1) { resultList = em.createNamedQuery("Cantable.findAll").getResultList(); finalList = resultList; } } catch (Exception e) { e.printStackTrace(); } return resultList; }

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  • Kohana Auth Library Deployment

    - by Steve
    My Kohana app runs perfectly on my local machine. When I deployed my app to a server (and adjust the config files appropriately), I can no longer log into the app. I've traced through the app login routine on both my local version and the server version and they both agree with each other all the way through until you get to the auth.php controller logged_in() routine where suddenly, at line 140 - the is_object($this-user) test - the $user object no longer exists!?!?!? The login() function call that calls the logged_in() function successfully passes the following test, which causes a redirect to the logged_in() function. if(Auth::instance()->login($user, $post['password'])) Yes, the password and hash, etc all work perfectly. Here is the offending code: public function logged_in() { if ( ! is_object($this->user)) { // No user is currently logged in url::redirect('auth/login'); } etc... } As the code is the same between my local installation and the server, I reckon it must be some server setting that is messing with me. FYI: All the rest of the code works because I have a temporary backdoor available that allows me to use the application (view pages of tables, etc) without being logged in. Any ideas?

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  • PHP checking/refreashing functions

    - by user1284360
    ok i have a main document that displays a chatbox, what i want is for the chatbox to refreash on everyone who is logged in's screen whenever someone posts a new message... ive tried many methods including sleep timers and new functions that call then sleep and get recalled but this just generates an endless line of the same or little diffrent data making the form unusable until error... this is my code <?php // set error reporting level if (version_compare(phpversion(), "5.3.0", ">=") == 1) error_reporting(E_ALL & ~E_NOTICE & ~E_DEPRECATED); else error_reporting(E_ALL & ~E_NOTICE); require_once('inc/login.inc.php'); require_once('inc/chat.inc.php'); // initialization of login system and generation code $oSimpleLoginSystem = new SimpleLoginSystem(); $oSimpleChat = new SimpleChat(); // draw login box echo $oSimpleLoginSystem->getLoginBox(); // draw chat application $sChatResult = '<font color="0x99000"> <a href="Register_form.html">New Account</a><br> login to send a message<br> or register for a new account</font>'; if ($_COOKIE['member_name'] && $_COOKIE['member_pass']) { if ($oSimpleLoginSystem->check_login($_COOKIE['member_name'], $_COOKIE['member_pass'])) { $sChatResult = ""; if($oSimpleLoginSystem->check_privledges($_COOKIE['member_name']) >= 2) { $sChatResult .= "<br>privledge check Working<br>"; } $sChatResult .= "<form action=$_SERVER[PHP_SELF] method='post'> <input type='hidden' name='foo' value='<?= $foo ?>' /> <input type='submit' name='submit' value='Refresh Messages' /> </form>"; $sChatResult .= $oSimpleChat->acceptMessages(); $sChatResult .= "<br><br>"; $sChatResult .= $oSimpleChat->getMessages(); } } echo $sChatResult; ?>

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  • $_SERVER['HTTP_REFERER'] not working with Header

    - by EmmyS
    I have a site that allows public access to some pages, but requires a login for others. I have a link to the login from all pages, and what I'd like to do after a successful login is send the user back to the page they were on when they clicked the login link. I know the HTTP_REFERER can be spoofed, and sometimes stripped out by certain hosts and proxies, but since it's strictly within my own site, and only a convenience for users, I'm not too worried about it. I am curious about why it isn't working in conjunction with a redirect, though. I've set a visible field to contain the value of the http referer, and it displays correctly. So the page is getting the value of the referrer variable. But when I try this: $home_url = $_SERVER['HTTP_REFERER']; header('Location: ' . $home_url); it doesn't work. This, on the other hand, does: $home_url = 'http://' . $_SERVER['HTTP_HOST'].dirname($_SERVER['PHP_SELF']).'/discussions.php'; header('Location: ' . $home_url); So I know the header location part works. Any idea why it doesn't want to work in conjunction with the http_referer variable? (Also, does it drive anyone else nuts that referer is spelled incorrectly? I keep mistyping it using the OED spelling, silly me...)

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  • How can I automate new system provisioning with scripts under Mac OS X 10.6?

    - by deeviate
    I've been working on this for days but simply cannot find the correct references to make it work. The idea is to have a script that will baseline newly purchased Macs that comes into the company with basic stuffs like set autologin to off, create a new admin user (for remote admins to access for support, set password to unlock screensaver and etc) . Sample list for baseline that admins have to do on each new machine: Click the Login Options button Set Automatic Login: OFF Check: Show the Restart, Sleep, and Shutdown buttons Uncheck: Show input menu in login window Uncheck: Show password hints Uncheck: Use voice over in the login window Check: Show fast user switching menu as Short Name (note: this is only part of a long list to do on each machine) I've managed to find some references to make some parts work. Like autologin can be unset with: defaults write /Library/Preferences/.GlobalPreferences com.apple.userspref.DisableAutoLogin -bool TRUE and I've kinda found ways to muscle in a new user creation (including prompts) with AppleScript and shell commands. But generally its tough finding ways to do somewhat simple things like turn on password to get out of screensaver or to allow fast user switching. References are either too limited or just no where to be seen (e.g. I can unset autologin via cli but the very next setting on the system preference "show restart, sleep and shutdown buttons" is somewhere else and I can't find any command line to make it set) Does anyone have any ideas on a list, document, reference or anything of where each setting on the system resides so that I can be pointed to make it work? or maybe sample scripts for the above example... My thanks for reading thus far—a huge thank you for whoever that has any info on the above.

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  • How to avoid notice in php when one of the conditions is not true

    - by user225269
    I've notice that when one of the two conditions in a php if statement is not true. You get an undefined index notice for the statement that is not true. And the result in my case is a distorted web page. For example, this code: <?php session_start(); if (!isset($_SESSION['loginAdmin']) && ($_SESSION['loginAdmin'] != '')) { header ("Location: loginam.php"); } else { include('head2.php'); } if (!isset($_SESSION['login']) && ($_SESSION['login'] != '')) { header ("Location: login.php"); } else { include('head3.php'); } ?> If one of the if statements is not true. The one that is not true will give you a notice that it is undefined. In my case it says that the session 'login' is not defined. If session 'LoginAdmin' is used. What can you recommend that I would do in order to avoid these undefined index notice.

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  • Redirection Still not working (updated on earlier question)

    - by NoviceCoding
    So earlier I asked this question: JQuery Login Redirect. Code Included The php file is sending the following: $return['error'] = false; $return['msg'] = 'You have successfully logged in!!'; I've tried all the suggestions, quoting the error on php and ajax end, 2 equals instead of 3, I've also tried DNE true which should be the same as an else statement: $(document).ready(function(){ $('#submit').click(function() { $('#waiting').show(500); $('#empty').show(500); $('#reg').hide(0); $('#message').hide(0); $.ajax({ type : 'POST', url : 'logina.php', dataType : 'json', data: { type : $('#typeof').val(), login : $('#login').val(), pass : $('#pass').val(), }, success : function(data){ $('#waiting').hide(500); $('#empty').show(500); $('#message').removeClass().addClass((data.error === true) ? 'error' : 'success') .text(data.msg).show(500) if(data.error != true) window.location.replace("http://blahblah.com/usercp.php"); if (data.error === true) $('#reg').show(500); $('#empty').hide() }, error : function(XMLHttpRequest, textStatus, errorThrown) { $('#waiting').hide(500); $('#message').removeClass().addClass('error') .text("There was an Error. Please try again.").show(500); $('#reg').show(500); $('#empty').hide(); Recaptcha.reload(); } }); return false; }); And it still wont work. Any ideas on how to make a redirection work if login is successful and error returns false? Also while I am asking, can I put a .delay(3000) 3s at the end of window.location.replace("http://blahblah.com/usercp.php")?

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  • Is OpenID too complicated?

    - by John Leidegren
    I'm beginning to seriously doubt the OpenID community despite that fact that it works. I'm in the process of currently evaluating OpenID as an authentication service for 'this' site and while the promises are great, I just can't get it to work. And I'm really lost. I ask of the SO community to help me out here. Give me answers and show me examples so I can leverage this in the way it was meant to be. My scenario is very typical. I want to authenticate users through a specific Google Apps domain. If you have access to this Google Apps domain, then you have access to my web application. Where I get lost, is all the prerequisites and dependencies involved. What is XRD? What is Yadis? Why do I need XRD and Yadis? What do I need to do to deploy OpenID authentication on my website? Also, this is really important to me. When I login to SO, I use my Google Account. When I click the login button I'm presented with this confirmation page. Where I'm granting SO the right to use my Google Account credentials. Somehow, Google knows that it's "Stackoverflow.com" that's asking me if it's okay to login. And I wish to know what manner of control I have over this little text. I intend to deploy OpenID on several different domains but I would prefer if they would all work without having to be individually configured with special parameters, such as secret API keys and what not. However, I don't know for sure if this is a prerequisite of OpenID, that or the Federated Login API that Google provides.

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  • php session_start() error

    - by tooepic
    Hi, i've used a sample found on online and applied it to my code: <?php session_start(); if (isset($_REQUEST["email"])) { $_SESSION["name"] = true; $host = $_SERVER["HTTP_HOST"]; $path = dirname($_SERVER["PHP_SELF"]); $sid = session_name() . "=" . session_id(); header("Location: index.php?$sid"); exit; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> ... ... and rest of the html code When I open this page, I got an error: Warning: session_start() [function.session-start]: Cannot send session cookie - headers already sent by (output started at /data/server/user/directory/sub-directory/login.php:1) in /data/server/user/directory/sub-directory/login.php on line 2 Warning: session_start() [function.session-start]: Cannot send session cache limiter - headers already sent (output started at /data/server/user/directory/sub-directory/login.php:1) in /data/server/user/directory/sub-directory/login.php on line 2 I looked around to resolve this issue and saw few posts about this in this site also, but I just can't get a good grip on this...can't find the answer. Please help. Thanks.

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  • jquery an div tags used in a ordered list

    - by shan2on
    hello everyone, i'm not sure where my errors are lying but here is my scenario... i have an un-ordered list in html that handles my main link bar... <ul id="navlist"> <li><a href="/" id="current">home</a></li> <li><a href="#" id="search">search</a></li> <li><a href="#" id="users">login</a></li> </ul> and what i want done is to call each id and have jQuery handle each and dislpay it where specified in my css file... for now, lets just ignore my "home" link... here is a snippet of my inline jquery $(document).ready(function() { $("a").click(function () { $("div#login").slideToggle("fast"); }); }) Now, whichever div i specify, it calls that ... however it will only call one div, using either from the un-orderd list, as mentioned above in the html. My Goal is to call a search bar when search is clicked, and to call a login box when login is clicked. to my knowledge (noob), i believe use an as a class, however that is what brings me here. i believe my error is in my jquery and not my css, as stated above, either instance will be displayed when the jquery function calls either tag. any help is greatly appreciated. thanks in advance shan2on

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  • Need for J2me source code

    - by tikamchandrakar
    For J2me It strikes me as odd that you need an extra "api key" and so on. But actually, what I really want is NOT create an extra facebook application that needs to be registered on Facebook. I don't want to create any extra configuration effords necessary for the user of my application to undergo. All my user should need is his well-known login data for facebook. Everything else should be completely transparent to him. So, I thought maybe would u can do the login process, creating a request to the REST server via http. I know this would provide me with an XML. I hope that the this API will somehow automatically transform that XML into an intuitive object model that represents the facebook user data of the respective user. So, I would expect something like userData = new FacebookData(new FacebookConnection("user_name", "password")). Done. If you get, what I mean. No api key. No secret key. Just the well-known login data. Practically, the equivalent to thunderbird webmail, which allows you to access your MSN hotmail account via Thunderbird. Thunderbird webmail will automatically converts the htmls obtained from a hotmail browser login into the data structure usually passed on to a mail client. Hope you get what I mean. I was expecting the equilalent for the your API.

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  • PHP session corrupt

    - by Baversjo
    Using symfony framework 1.4 I have created a website. I'm using sfguard for authentication. Now, this is working great on WAMP (windows). I can login to several accounts on different browsers and use the website. I have ubuntu server 9.10 running apache (everything up to date and default configuration). On my server, when I login to the website in one browser it works great. When I on my other computer login with another user account on the public website, the login is successful. But when I refresh/go to another page the first user is shown as logged in instead! Also, when I press logout, It's not showing that I'm logged out after page load. When I press f5 again I'm logged out. As mentioned, all this works as expected on my local installation. I'm thinking there something wrong with my PHP session configuration on my ubuntu server, but I've never touched it.. Please help me. This is a school project and I'm presenting it today :(

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  • What's a good way to integrate FB and Twitter into my commenting system (PHP)

    - by Jason
    Hi Guys, There are so many options out there for integration. At the moment I have comments that are posted on my articles, where a user types in their name and the comment. This is then sent to a moderation queue and displayed when approved. I want to acheive this: Comment with facebook login (ie facebook account listed as the name w/ avatar) Comment with twitter login (ie twitter account name listed as the name w/ avatar) Push comment from my website to twitter and to facebook I could go down a few paths as far as I know: Integrate with XFBML, which I don't like because I find it annoying to setup and messy. Integrate facebook comments system, although this can't push to twitter, or allow me to moderate comments from my backend (as far as I can tell i'd have to login under the facebook login for the dev account to moderate the comment) Find a php class that does open auth and integrate with both face book and twitter at once find a pre-created php class Anyone have a solution that will bias: a. easy to integrate b. lightweight c. is free Thanks for your suggestions in advance.

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  • Zend Framework How can I print a logged in user name from a Zend_Session_Namespace

    - by IrishStudent76
    Hi all I have created the following login controller for my site and it works fine in relation to logging users in a logging them out. The thing I want to do is echo the logged in users name into the FlashMessenger for the success page how ever as my code stands I only get the following message when redirected to the success page, "you have been successfully logged in as Array". Can I also ask the following does the line $session-user =$adaptergetResultArray('Password'); create an array of user information less the password value from the database. Many Thanks in advance, IrishStudent76 <?php class LoginController extends Zend_Controller_Action { public function init(){ $this->view->doctype('XHTML1_STRICT'); } // login action public function loginAction() { $form = new PetManager_Form_Login; $this->view->form = $form; /* check for valid input from the form and authenticate using adapter Add user record to session and redirect to the original request URL if present */ if ($this->getRequest()->isPost()) { if ($form->isValid($this->getRequest()->getPost())) { $values = $form->getValues(); $adapter = new PetManager_Auth_Adapter_Doctrine( $values['username'], $values['password'] ); $auth = Zend_Auth::getInstance(); $result = $auth->authenticate($adapter); if ($result->isValid()) { $session = new Zend_Session_Namespace('petmanager.auth'); $session->user = $adapter->getResultArray('Password'); if (isset($session->requestURL)) { $url = $session->requestURL; unset($session->requestURL); $this->_redirect($url); } else { $this->_helper->getHelper('FlashMessenger') ->addMessage('You have been successfully logged in as '.$session- >user); $this->_redirect('/login/success'); } } else { $this->view->message = 'You could not be logged in. Please try again.'; } } } } public function successAction() { if ($this->_helper->getHelper('FlashMessenger')->getMessages()) { $this->view->messages = $this->_helper ->getHelper('FlashMessenger') ->getMessages(); } else { $this->_redirect('/login'); } } public function logoutAction() { Zend_Auth::getInstance()->clearIdentity(); Zend_Session::destroy(); $this->_redirect('/'); } }

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  • OFM 11g: OAM SSO for Forms and ADF Faces

    - by olaf.heimburger
    In my blog entry OFM 11g: Implementing OAM SSO with Forms we set the foundation for providing a complete Single Sign-On solution based on Oracle Access Manager (OAM). This foundation should now be used to combine Forms 11g and ADF Faces 11g applications with a transparent login. The Beginning Before we start, lets re-consider the requirements to achieve the ultimate goal. These are:- Access to the Forms 11g Application must be authenticated by OAM (protected). Access to the ADF Faces 11g Application must be authenticated by OAM (protected). Switching from one application to the other should not result in a re-authentication (aka single sign-on). User identity should be availble to the application without any extra work in the application code. All these are the common requirements for a single sign-on solution. The challenge here is that Forms relies on Oracle AS SSO (OSSO or "the old SSO") while ADF Faces is quite open and can be protected by Oracle AS SSO and Oracle Access Manager SSO (OAM SSO or "the modern SSO"). Both application types can use their own login mechanism. The Forms 11g Application To demonstrate the SSO functionality, we use the standard Forms test (/forms/frmservlet?form=test.fmx). Although this shows nothing specific in the Forms application, it is good enough to demonstrate that it is protected. The ADF Faces 11g Application With ADF 11g you can develop quite a number of useful Faces based applications. Among many features, it comes with the ADF Security feature that provides you with functionality to protect your pages, regions, and even TaskFlows from un-authenticated usage in a declarative way.To demonstrate that functionality a sample application with different access levels plus a login dialog is used. This application comes with a publc page that has protected content (a button). Once you are authenticated for the application, the protected content and some personalisation (the users name) is shown. Protecting Forms 11g As already explained in the OFM 11g: Implementing OAM SSO with Forms, the easiest way to protect a Forms application is to configure it as a OSSO partner application, setup mod_osso, test it, migrate OSSO to OAM SSO with the Upgrade Agent, reconfigure mod_osso, and you are done.Sort of. By default the OAM is configured to run in co-exist mode. This means that a user has to re-authenticate to the Forms application when logged into an OAM SSO application before. To avoid this, you must disable the co-exist mode, for example by using WLST and issue the disableCoexistMode on the OAM server. Protecting ADF Faces 11g To protect an ADF Faces 11g application we have to consider two scenarios: Use a HTTPD server in front of WLS Use WLS without a HTTPD server Both scenarios have their pro's and cons' and we won't get into details and just describe how to configure both. Scenario 1: HTTPD Server with WLS In this scenario we have to setup the environment in some steps:- Configure a WebGate at OAMThis configuration can be done through the OAM console or by a script. No matter which way you choose, the WebGate configuration files will be created for you. Install the OAM WebGate into an HTTPD serverThe type of webgate you need to install depends on you HTTPD server. With Oracle HTTP Server 11g you can use the latest OAM 11g WebGate. With other HTTPD servers you must resort to OAM 10g WebGates. A OAM 11g WebGate can use the pre-created configuration files supplied during the WebGate configuration at OAM. An OAM 10g WebGate asks for the specific configuration and verifies it during installation. Configure the WLS plugin to forward the requests to WLSAgain, depending on your HTTPD Server you have different plugins to forward requests to WLS. With OHS 11g you can use the pre-installed mod_wl_ohs plugin. Its configuration is quite simple and straightforward. Configure an OAM SSPI Provider as a IdentityAsserter in WLS to retrieve the user identifierThis configuration is quite important as it retrieves the user identifier for the next step. If you have a SOA Suite installation within your OFM_HOME, the necessary software is already installed and you only need to setup your Security Realm within WLS.You can do this by pointing your browser to the WLS Console, log in as administrator, select the Security Realm (usually myrealm), and select Providers. We add the OAMIdentityAsserter as the first SSPI Provider. It is important that the Control Flag is set to SUFFICIENT. Every other configuration can be left as is, no changes are necessary here. Configure an OAM Identity Provider to get the real user identityIn OFM 11g: Implementing OAM SSO with Forms we have configured an OID as Identity Store. To get the user identity we need to configure the same OID as an SSPI Provider for WLS. This will retrieve the real user information from OID and creates the JAAS Subject and Principals to be used by any application within WLS.Again, you can do this by pointing your browser to the WLS Console, log in as administrator, select the Security Realm (usually myrealm), and select Providers. Now add the OIDAuthenticator as the second SSPI Provider. It is important that the Control Flag is set to OPTIONAL. After we saved this setup, we need to configure this provider by setting the Provider Specific details to access OID. Scenario 2: WLS only This scenario is a bit easier but requires more work in the WLS setup:- Configure a WebGate at OAMThis configuration can be done through the OAM console or by a script. No matter which way you choose, the WebGate configuration files will be created for you. Configure the OAM SSPI Provider as IdentityAuthenticator to authenticate and set the user identifierWhen using the OAM SSPI Provider as OAMAuthenticator we create it with the Control Flag as SUFFICIENT. Afte saving it, the Provider Specific settings must be configured to allow the OAM SSPI Provider to connect to the OAM Server. Configure an OAM Identity Provider to get the real user identity providerAgain, you can do this by pointing your browser to the WLS Console, log in as administrator, select the Security Realm (usually myrealm), and select Providers. Now add the OIDAuthenticator as the second SSPI Provider. It is important that the Control Flag is set to OPTIONAL. After we saved this setup, we need to configure this provider by setting the Provider Specific details to access OID. Configure ADF 11g Application for OAM Actually, there are no changes to be made within the ADF application. We only need to add the value CLIENT_CERT to the <auth-mode> tag in the <login-config> tag in the web.xml file. Testing To test the configuration, simply point your browser to one of both appliction URLs. OAM should kick in and redirect you to the OAM Login page. After you have entered the correct credentials, access to the URLs is granted and you will see the application. Enjoy!

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  • Configure Forms based authentication in SharePoint 2010

    - by sreejukg
      Configuring form authentication is a straight forward task in SharePoint. Mostly public facing websites built on SharePoint requires form based authentication. Recently, one of the WCM implementation where I was included in the project team required registration system. Any internet user can register to the site and the site offering them some membership specific functionalities once the user logged in. Since the registration open for all, I don’t want to store all those users in Active Directory. I have decided to use Forms based authentication for those users. This is a typical scenario of form authentication in SharePoint implementation. To implement form authentication you require the following A data store where you are storing the users – technically this can be active directory, SQL server database, LDAP etc. Form authentication will redirect the user to the login page, if the request is not authenticated. In the login page, there will be controls that validate the user inputs against the configured data store. In this article, I am going to use SQL server database with ASP.Net membership API’s to configure form based authentication in SharePoint 2010. This article assumes that you have SQL membership database available. I already configured the membership and roles database using aspnet_regsql command. If you want to know how to configure membership database using aspnet_regsql command, read the below blog post. http://weblogs.asp.net/sreejukg/archive/2011/06/16/usage-of-aspnet-regsql-exe-in-asp-net-4.aspx The snapshot of the database after implementing membership and role manager is as follows. I have used the database name “aspnetdb_claim”. Make sure you have created the database and make sure your database contains tables and stored procedures for membership. Create a web application with claims based authentication. This article assumes you already created a web application using claims based authentication. If you want to enable forms based authentication in SharePoint 2010, you must enable claims based authentication. Read this post for creating a web application using claims based authentication. http://weblogs.asp.net/sreejukg/archive/2011/06/15/create-a-web-application-in-sharepoint-2010-using-claims-based-authentication.aspx  You make sure, you have selected enable form authentication, and then selected Membership provider and Role manager name. To make sure you are done with the configuration, navigate to central administration website, from central administration, navigate to the Web Applications page, select the web application and click on icon, you will see the authentication providers for the current web application. Go to the section Claims authentication types, and make sure you have enabled forms based authentication. As mentioned in the snapshot, I have named the membership provider as SPFormAuthMembership and role manager as SPFormAuthRoleManager. You can choose your own names as you need. Modify the configuration files(Web.Config) to enable form authentication There are three applications that needs to be configured to support form authentication. The following are those applications. Central Administration If you want to assign permissions to web application using the credentials from form authentication, you need to update Central Administration configuration. If you do not want to access form authentication credentials from Central Administration, just leave this step.  STS service application Security Token service is the service application that issues security token when users are logging in. You need to modify the configuration of STS application to make sure users are able to login. To find the STS application, follow the following steps Go to the IIS Manager Expand the sites Node, you will see SharePoint Web Services Expand SharePoint Web Services, you can see SecurityTokenServiceApplication Right click SecuritytokenServiceApplication and click explore, it will open the corresponding file system. By default, the path for STS is C:\Program Files\Common Files\Microsoft Shared\Web Server Extensions\14\WebServices\SecurityToken You need to modify the configuration file available in the mentioned location. The web application that needs to be enabled with form authentication. You need to modify the configuration of your web application to make sure your web application identifies users from the form authentication.   Based on the above, I am going to modify the web configuration. At end of each step, I have mentioned the expected output. I recommend you to go step by step and after each step, make sure the configuration changes are working as expected. If you do everything all together, and test your application at the end, you may face difficulties in troubleshooting the configuration errors. Modifications for Central Administration Web.Config Open the web.config for the Central administration in a text editor. I always prefer Visual Studio, for editing web.config. In most cases, the path of the web.config for the central administration website is as follows C:\inetpub\wwwroot\wss\VirtualDirectories\<port number> Make sure you keep a backup copy of the web.config, before editing it. Let me summarize what we are going to do with Central Administration web.config. First I am going to add a connection string that points to the form authentication database, that I created as mentioned in previous steps. Then I need to add a membership provider and a role manager with the corresponding connectionstring. Then I need to update the peoplepickerwildcards section to make sure the users are appearing in search results. By default there is no connection string available in the web.config of Central Administration. Add a connection string just after the configsections element. The below is the connection string I have used all over the article. <add name="FormAuthConnString" connectionString="Initial Catalog=yourdatabasename;data source=databaseservername;Integrated Security=SSPI;" /> Once you added the connection string, the web.config look similar to Now add membership provider to the code. In web.config for CA, there will be <membership> tag, search for it. You will find membership and role manager under the <system.web> element. Under the membership providers section add the below code… <add name="SPFormAuthMembership" type="System.Web.Security.SqlMembershipProvider, System.Web, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b03f5f7f11d50a3a" applicationName="FormAuthApplication" connectionStringName="FormAuthConnString" /> After adding memberhip element, see the snapshot of the web.config. Now you need to add role manager element to the web.config. Insider providers element under rolemanager, add the below code. <add name="SPFormAuthRoleManager" type="System.Web.Security.SqlRoleProvider, System.Web, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b03f5f7f11d50a3a" applicationName="FormAuthApplication" connectionStringName="FormAuthConnString" /> After adding, your role manager will look similar to the following. As a last step, you need to update the people picker wildcard element in web.config, so that the users from your membership provider are available for browsing in Central Administration. Search for PeoplePickerWildcards in the web.config, add the following inside the <PeoplePickerWildcards> tag. <add key="SPFormAuthMembership" value="%" /> After adding this element, your web.config will look like After completing these steps, you can browse the users available in the SQL server database from central administration website. Go to the site collection administrator’s page from central administration. Select the site collection you have created for form authentication. Click on the people picker icon, choose Forms Auth and click on the search icon, you will see the users listed from the SQL server database. Once you complete these steps, make sure the users are available for browsing from central administration website. If you are unable to find the users, there must be some errors in the configuration, check windows event logs to find related errors and fix them. Change the web.config for STS application Open the web.config for STS application in text editor. By default, STS web.config does not have system.Web or connectionstrings section. Just after the System.Webserver element, add the following code. <connectionStrings> <add name="FormAuthConnString" connectionString="Initial Catalog=aspnetdb_claim;data source=sp2010_db;Integrated Security=SSPI;" /> </connectionStrings> <system.web> <roleManager enabled="true" cacheRolesInCookie="false" cookieName=".ASPXROLES" cookieTimeout="30" cookiePath="/" cookieRequireSSL="false" cookieSlidingExpiration="true" cookieProtection="All" createPersistentCookie="false" maxCachedResults="25"> <providers> <add name="SPFormAuthRoleManager" type="System.Web.Security.SqlRoleProvider, System.Web, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b03f5f7f11d50a3a" applicationName="FormAuthApplication" connectionStringName="FormAuthConnString" /> </providers> </roleManager> <membership userIsOnlineTimeWindow="15" hashAlgorithmType=""> <providers> <add name="SPFormAuthMembership" type="System.Web.Security.SqlMembershipProvider, System.Web, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b03f5f7f11d50a3a" applicationName="FormAuthApplication" connectionStringName="FormAuthConnString" /> </providers> </membership> </system.web> See the snapshot of the web.config after adding the required elements. After adding this, you should be able to login using the credentials from SQL server. Try assigning a user as primary/secondary administrator for your site collection from Central Administration and login to your site using form authentication. If you made everything correct, you should be able to login. This means you have successfully completed configuration of STS Configuration of Web Application for Form Authentication As a last step, you need to modify the web.config of the form authentication web application. Once you have done this, you should be able to grant permissions to users stored in the membership database. Open the Web.config of the web application you created for form authentication. You can find the web.config for the application under the path C:\inetpub\wwwroot\wss\VirtualDirectories\<port number> Basically you need to add connection string, membership provider, role manager and update the people picker wild card configuration. Add the connection string (same as the one you added to the web.config in Central Administration). See the screenshot after the connection string has added. Search for <membership> in the web.config, you will find this inside system.web element. There will be other providers already available there. You add your form authentication membership provider (similar to the one added to Central Administration web.config) to the provider element under membership. Find the snapshot of membership configuration as follows. Search for <roleManager> element in web.config, add the new provider name under providers section of the roleManager element. See the snapshot of web.config after new provider added. Now you need to configure the peoplepickerwildcard configuration in web.config. As I specified earlier, this is to make sure, you can locate the users by entering a part of their username. Add the following line under the <PeoplePickerWildcards> element in web.config. See the screenshot of the peoplePickerWildcards element after the element has been added. Now you have completed all the setup for form authentication. Navigate to the web application. From the site actions -> site settings -> go to peope and groups Click on new -> add users, it will popup the people picker dialog. Click on the icon, select Form Auth, enter a username in the search textbox, and click on search icon. See the screenshot of admin search when I tried searching the users If it displays the user, it means you are done with the configuration. If you add users to the form authentication database, the users will be able to access SharePoint portal as normal.

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  • WPF: DataGrid Cell Double-click

    - by Jonathan Allen
    Is there a better way than this to determine the row a user double-clicked on in a data-grid? Private Sub ResultsGrid_MouseDoubleClick(ByVal sender As System.Object, ByVal e As System.Windows.Input.MouseButtonEventArgs) Dim node As DependencyObject = CType(e.OriginalSource, DependencyObject) Do Until TypeOf node Is Microsoft.Windows.Controls.DataGridRow OrElse node Is Nothing node = VisualTreeHelper.GetParent(node) Loop If node IsNot Nothing Then Dim data = CType((CType(node, Microsoft.Windows.Controls.DataGridRow)).DataContext, Customer) 'do something End If End Sub

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  • MVVM pattern and nested view models - communication and lookup lists

    - by LostInWPF
    I am using Prism for a new application that I am creating. There are several lookup lists that will be used in several places in the application. Therefore it makes sense to define it once and use that everywhere I need that functionality. My current solution is to use typed data templates to render the controls inside a content control. <DataTemplate DataType={x:Type ListOfCountriesViewModel}> <ComboBox ItemsSource={Binding Countries} SelectedItem="{Binding SelectedCountry"/> </DataTemplate> <DataTemplate DataType={x:Type ListOfRegionsViewModel}> <ComboBox ItemsSource={Binding Countries} SelectedItem={Binding SelectedRegion} /> </DataTemplate> public class ParentViewModel { SelectedCountry get; set; SelectedRegion get; set; ListOfCountriesViewModel CountriesVM; ListOfRegionsViewModel RgnsVM; } Then in my window I have 2 content controls and the rest of the controls <ContentControl Content="{Binding CountriesVM}"></ContentControl> <ContentControl Content="{Binding RgnsVM}"></ContentControl> <Rest of controls on view> At the moment I have this working and the SelectedItems for the combo boxes are publising events via EventAggregator from the child view models which are then subscribed to in the parent view model. I am not sure that this is the best way to go as I can imagine I would end up with a lot of events very quickly and it will become unwieldy. Also if I was to use the same view model on another window it will publish the event and this parent viewmodel is subscribed to it which could have unintended consequences. My questions are :- Is this the best way to put lookup lists in a view which can be re-used across screens? How do I make it so that the combobox which is bound to the child viewmodel sets the relevant property on the parent viewmodel without using events / mediator. e.g in this case SelectedCountry for example? Any alternative implementation proposals for what I am trying to do? I have a feeling I am missing something obvious and there is so much info it is hard to know what is right so any help would be most gratefully received.

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  • ControlTemplate Exception: "XamlParseException: Cannot find a Resource with the Name/Key"

    - by akaphenom
    If I move the application resources to a UserControl resources everythgin runs groovy. I still don't understand why. I noticed that my application object MyApp did more than inherit from Application it loaded an XAML for the main template and connected all the plumbing. So I decided to create a user control to remove the template from the applciation (thinking there may be an even order issue not allowing my resource to be found). namespace Module1 type Template() as this = //inherit UriUserControl("/FSSilverlightApp;component/template.xaml", "") inherit UriUserControl("/FSSilverlightApp;component/templateSimple.xaml", "") do Application.LoadComponent(this, base.uri) let siteTemplate : Grid = (this.Content :?> FrameworkElement) ? siteTemplate let nav : Frame = siteTemplate ? contentFrame let pages : UriUserControl array = [| new Module1.Page1() :> UriUserControl ; new Module1.Page2() :> UriUserControl ; new Module1.Page3() :> UriUserControl ; new Module1.Page4() :> UriUserControl ; new Module1.Page5() :> UriUserControl ; |] do nav.Navigate((pages.[0] :> INamedUriProvider).Uri) |> ignore type MyApp() as this = inherit Application() do Application.LoadComponent(this, new System.Uri("/FSSilverlightApp;component/App.xaml", System.UriKind.Relative)) do System.Windows.Browser.HtmlPage.Plugin.Focus() this.RootVisual <- new Template() ; // test code to check for the existance of the ControlTemplate - it exists let a = Application.Current.Resources.MergedDictionaries let b = a.[0] let c = b.Count let d : ControlTemplate = downcast c.["TransitioningFrame"] () "/FSSilverlightApp;component/templateSimple.xaml" <UserControl x:Class="Module1.Template" xmlns:navigation="clr-namespace:System.Windows.Controls;assembly=System.Windows.Controls.Navigation" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" > <Grid HorizontalAlignment="Center" Background="White" Name="siteTemplate"> <StackPanel Grid.Row="3" Grid.Column="2" Name="mainPanel"> <!--Template="{StaticResource TransitioningFrame}"--> <navigation:Frame Name="contentFrame" HorizontalAlignment="Stretch" VerticalAlignment="Stretch" Template="{StaticResource TransitioningFrame}"/> </StackPanel> </Grid> </UserControl> "/FSSilverlightApp;component/App.xaml" <Application xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" x:Class="Module1.MyApp"> <Application.Resources> <ResourceDictionary> <ResourceDictionary.MergedDictionaries> <ResourceDictionary Source="/FSSilverlightApp;component/TransitioningFrame.xaml" /> </ResourceDictionary.MergedDictionaries> </ResourceDictionary> </Application.Resources> </Application> "/FSSilverlightApp;component/TransitioningFrame.xaml" <ResourceDictionary xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:navigation="clr-namespace:System.Windows.Controls;assembly=System.Windows.Controls.Navigation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"> <ControlTemplate x:Key="TransitioningFrame" TargetType="navigation:Frame"> <Border Background="Olive" BorderBrush="{TemplateBinding BorderBrush}" BorderThickness="5" HorizontalAlignment="{TemplateBinding HorizontalContentAlignment}" VerticalAlignment="{TemplateBinding VerticalContentAlignment}"> <ContentPresenter Cursor="{TemplateBinding Cursor}" HorizontalAlignment="{TemplateBinding HorizontalContentAlignment}" Margin="{TemplateBinding Padding}" VerticalAlignment="{TemplateBinding VerticalContentAlignment}" Content="{TemplateBinding Content}"/> </Border> </ControlTemplate> </ResourceDictionary> Unfortunately that did not work. If I remove the template attribute from the navigationFrame element, the app loads and directs the content area to the first page in the pages array. Referencing that resource continues to throw a resource no found error. Original Post I have the following app.xaml (using Silverlight 3) <Application xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" x:Class="Module1.MyApp"> <Application.Resources> <ResourceDictionary> <ResourceDictionary.MergedDictionaries> <ResourceDictionary Source="/FSSilverlightApp;component/TransitioningFrame.xaml" /> </ResourceDictionary.MergedDictionaries> </ResourceDictionary> </Application.Resources> </Application> and content template: <ResourceDictionary xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:navigation="clr-namespace:System.Windows.Controls;assembly=System.Windows.Controls.Navigation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"> <ControlTemplate x:Key="TransitioningFrame" TargetType="navigation:Frame"> <Border Background="{TemplateBinding Background}" BorderBrush="{TemplateBinding BorderBrush}" BorderThickness="{TemplateBinding BorderThickness}" HorizontalAlignment="{TemplateBinding HorizontalContentAlignment}" VerticalAlignment="{TemplateBinding VerticalContentAlignment}"> <ContentPresenter Cursor="{TemplateBinding Cursor}" HorizontalAlignment="{TemplateBinding HorizontalContentAlignment}" Margin="{TemplateBinding Padding}" VerticalAlignment="{TemplateBinding VerticalContentAlignment}" Content="{TemplateBinding Content}"/> </Border> </ControlTemplate> </ResourceDictionary> The debugger says it the contentTemplate is loaded correctly by adding some minimal code: type MyApp() as this = inherit Application() do Application.LoadComponent(this, new System.Uri("/FSSilverlightApp;component/App.xaml", System.UriKind.Relative)) let cc = new ContentControl() let mainGrid : Grid = loadXaml("MainWindow.xaml") do this.Startup.Add(this.startup) let t = Application.Current.Resources.MergedDictionaries let t1 = t.[0] let t2 = t1.Count let t3: ControlTemplate = t1.["TransitioningFrame"] With this line in my main.xaml <navigation:Frame Name="contentFrame" HorizontalAlignment="Stretch" VerticalAlignment="Stretch" Template="{StaticResource TransitioningFrame}"/> Yields this exception Webpage error details User Agent: Mozilla/4.0 (compatible; MSIE 8.0; Windows NT 6.1; Trident/4.0; SLCC2; .NET CLR 2.0.50727; .NET CLR 3.5.30729; .NET CLR 3.0.30729; Media Center PC 6.0; InfoPath.2; .NET4.0C; .NET4.0E) Timestamp: Mon, 24 May 2010 23:10:15 UTC Message: Unhandled Error in Silverlight Application Code: 4004 Category: ManagedRuntimeError Message: System.Windows.Markup.XamlParseException: Cannot find a Resource with the Name/Key TransitioningFrame [Line: 86 Position: 115] at MS.Internal.XcpImports.CreateFromXaml(String xamlString, Boolean createNamescope, Boolean requireDefaultNamespace, Boolean allowEventHandlers, Boolean expandTemplatesDuringParse) at MS.Internal.XcpImports.CreateFromXaml(String xamlString, Boolean createNamescope, Boolean requireDefaultNamespace, Boolean allowEventHandlers) at System.Windows.Markup.XamlReader.Load(String xaml) at Globals.loadXaml[T](String xamlPath) at Module1.MyApp..ctor() Line: 54 Char: 13 Code: 0 URI: file:///C:/fsharp/FSSilverlightDemo/FSSilverlightApp/bin/Debug/SilverlightApplication2TestPage.html

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