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  • mysql rollback when auto commit is on

    - by devang
    hi, by mistake i fired a update query and all the records in the table in dat field got updated nd also cannot rollback as auto_commit is on..is der ny other way in which i can retreive the records.plz help its urgent.. Thanks in advance

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  • MySql Alter Syntax error with mulitple FK

    - by acidzombie24
    If i do the first one i have no problem. When i do addition i get a syntax error. What is wrong with the syntax? The error says syntax error near [entire 2nd line] alter table `ban_Status` add FOREIGN KEY (`banned_user`) REFERENCES `user_data`(`id`) alter table `ban_Status` add FOREIGN KEY (`banned_user`) REFERENCES `user_data`(`id`), FOREIGN KEY (`banning_user`) REFERENCES `user_data`(`id`), FOREIGN KEY (`unban_user`) REFERENCES `user_data`(`id`)

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  • mysql to codeigniter active record help

    - by JoeM05
    Active record is a neet concept but sometimes I find it difficult to get more complicated queries to work. I find this is at least one place the CI docs are lacking. Anyway, This is the sql I wrote. It returns the expected results of quests not yet completed by the user that are unlocked and within the users level requirements: SELECT writing_quests . * FROM `writing_quests` LEFT OUTER JOIN members_quests_completed ON members_quests_completed.quest_id = writing_quests.id LEFT OUTER JOIN members ON members.id = $user_id WHERE writing_quests.unlocked =1 AND writing_quests.level_required <= $userlevel AND members_quests_completed.user_id IS NULL This is the codeigniter active record query, it returns all quests that are unlocked and within the users level requirement: $this->db->select('writing_quests.*'); $this->db->from('writing_quests'); $this->db->join('members_quests_completed', 'members_quests_completed.quest_id = writing_quests.id', 'left outer'); $this->db->join('members', "members.id = $user_id", 'left outer'); $this->db->where('writing_quests.unlock', 1); $this->db->where('writing_quests.level_required <=', $userlevel); $this->db->where('members_quests_completed.user_id is null', null, true); I'm guessing there is something wrong with the way I am asking for Nulls. To be thorough, I figured I'd include everything.

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  • How to display mysql records as preselected checkboxes?

    - by Jennifer
    I have a table column called post_tags within a table called posts where assigned tags are stored separated by the @ symbol. I also have a table called tags where all tag names are stored. I would like to design my database in a more normalized way but for the purpose I am trying to achieve this is the easiest option. Anyway, I want to display on the screen all the entries from the tags table as checkboxes, so I do: $query = mysql_query("SELECT * FROM tags ORDER BY name"); while ($row = mysql_fetch_assoc($query)) { $tag = $row['name']; echo "<input type='checkbox' name='tags[]' value='$tag' />\n"; } Next I want to have the tags that are assigned to a particular post be preselected. For example, if I have a post with the following in it's post_tags column: party@beaches@dolphins@ I want the "party", "beaches" and "dolphin" checkboxes to be checked by default (while the checkboxes for the other options are unchecked). How can this be done?

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  • MySQL Query, Date Range From "Blacklist"

    - by erbaker
    I have 2 databases. One is properties and the other is dates. In dates I have associated the land_id and a date (In YYYYMMDD format) which means that the date is not available. I need to formulate a query that a user can specify a start and end date, and then choose a property for which dates are available (not in the date database). How do airline and hotel websites do this kind of logic? I was thinking about taking the date range and picking all days in between and doing a query where the dates do not match and ordering it by number of results, but I can see how that could easily turn into an intense query. CREATE TABLE IF NOT EXISTS `dates` ( `id` int(11) NOT NULL AUTO_INCREMENT, `land_id` int(11) NOT NULL, `date` varchar(255) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=44 ; -- -- Dumping data for table `dates` -- INSERT INTO `dates` (`id`, `land_id`, `date`) VALUES (43, 1, '20100526'), (39, 1, '20100522'), (40, 1, '20100523'), (41, 1, '20100521'), (42, 1, '20100525');

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  • How can I update a field in a MySQL database table by addition in MySQL database in a single query

    - by undefined
    I have a table that stores a value that will be added to over time. When I want to add to the value I would like to do so in a single query rather than - Get oldValue from database newValue = oldValue + X update row with newValue $query1 = "SELECT value FROM table WHERE id = thisID"; $result1 = mysql_query($query1); while($row=mysql_fetch_array($result)) { $oldValue = $row['value']; } $newValue = $oldValue + x $query1 = "UPDATE table SET value = $newValue WHERE id = thisID"; Can this be done in a single query?

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  • Help with MySQL Query?

    - by Devyn
    I have two tables rooms and users. I want to get only rooms.room_id, users.user_name with user_id = 1. I can get the result of all users with following sql... select rooms.room_id, rooms.user_id, users.user_name from rooms LEFT JOIN users ON rooms.user_id = users.user_id When I do like this to filter the result with user_id = 1 ... I got error. select rooms.room_id, rooms.user_id, users.user_name from rooms where rooms.user_id = 1 LEFT JOIN users ON rooms.user_id = users.user_id What should I do?

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  • MySQL Database Query - Codeigniter

    - by user2450349
    I am building an application with Codeigniter and need some help with a DB query. I have a table called users with the following fields: user_id, user_name, user_password, user_email, user_role, user_manager_id In my app, I pull all records from the user table using the following: function get_clients() { $this->db->select('*'); $this->db->where('user_role', 'client'); $this->db->order_by("user_name", "Asc"); $query = $this->db->get("users"); return $query->result_array(); } This works as expected, however when I display the results in the view, I also want to display a new column called Manager which will display the managers user_name field. The user_manager_id is the id of the user from the same table. Im guessing you can create an outer join on the same table but not sure. In the view, I am displaying the returned info as follows: <table class="table table-striped" id="zero-configuration"> <thead> <tr> <th>Name</th> <th>Email</th> <th>Manager</th> </tr> </thead> <tbody> <?php foreach($clients as $row) { ?> <tr> <td><?php echo $row['user_name']; ?> (<?php echo $row['user_username']; ?>)</td> <td><?php echo $row['user_email']; ?></td> <td><?php echo $row['???']; ?></td> </tr> <?php } ?> </tbody> </table> Any idea of how I can form the query and display the manager name is the view? Example: user_id user_name user_password user_email user_role user_manager_id 1 Ollie adjjk34jcd [email protected] client null 2 James djklsdfsdjk [email protected] client 1 When i query the database, i want to display results like this: Ollie [email protected] James [email protected] Ollie

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  • Retrieving specific tuples using Mysql

    - by Narayanan
    Hi, I have some problems retrieving specific tuples. I am actually a student trying to build a Room management system. I have two tables: Room(roomID,hotelname,rate) and Reservation(resID,arriveDate,departDate,roomID). I am not sure how to retrieve the rooms that are available between 2 specific dates. This was the query that i used. SELECT Room.roomID,hotelname,rate FROM Room LEFT JOIN Reservation on ( Room.roomID=Reservation.resID and arriveDate >='2010-02-16' and departDate <='2010-02-20' ) GROUP BY roomID,hotelname,rate HAVING count(*)=0;' but it returns an empty set. Can any1 be kind enough to tell me what mistake i am doing??

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  • mySQL query not returning correct results!

    - by Pete Herbert Penito
    Hi! This query that I have is returning therapists whose 'therapistTable.activated' is equal to false as well as those set to true! so it's basically selecting all of the db, any advice would be appreciated! ` $query = "SELECT therapistTable.* FROM therapistTable WHERE therapistTable.activated = 'true' ORDER BY therapistTable.distance "; `

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  • Help getting the following create table function to work with mysql and C#

    - by Matt
    string createTable = "CREATE TABLE IF NOT EXISTS " + m_strDatabase + "_TimeLogs (logName VARCHAR(16), logTime INTEGER, logCountry TEXT, UNIQUE(logName)) TYPE=MyISAM;"; When this runs, no table is created. No errors either. Im using an ODBC connector. the variable passes in the db name, so that the table created would be users_TimeLogs if the database was called users for example. Am I doing something wrong?

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  • PHP mysql multi-table search returning different table and field data row after row

    - by Kinyanjui Kamau
    Hi Guys, I am building a social networking site that is dedicated to nightclubs and night events. Among other tables, I have a users table, events table and establishments table. I am really intrigued with how Facebook in particular is able to query and return matches of not just users but also pages, ads etc row after row. Im sure most who are reading this have tried the facebook search My question is in my case, should I: Perform 3 separate LIKE %search% on each of the tables on search.php. Draw up 3 separate tables to show the results of what matches in the relevant queries which are collapsed when empty(on the same search.php) ie In search.php //query users table $query_user = "SELECT user_first_name, user_last_name, username, picture_thumb_url, avatar FROM users JOIN picture ON users.user_id = picture.user_id AND picture.avatar=1 ORDER BY users.user_id"; $result_users = mysql_query($query_user, $connections) or die(mysql_error()); $row_result_users = mysql_fetch_assoc($wid_updates); //query events table $query_event = "SELECT event_thumb_url, event_name, event_venue, event_date FROM event WHERE event_name LIKE '%".$search_value."%'"; $event = mysql_query($query_event, $connections) or die(mysql_error()); $row_event = mysql_fetch_assoc($event); $totalRows_event = mysql_num_rows($event); //query establishments table $query_establishment = "SELECT establishment_thumb_url, establishment_name, location_id, establishment_pricing FROM establishment WHERE establishment_name LIKE '%".$search_value."%'"; $establishment = mysql_query($query_establishment, $connections) or die(mysql_error()); $row_establishment = mysql_fetch_assoc($establishment); $totalRows_establishment = mysql_num_rows($establishment); My html: <table max-width="500" name="users" border="0"> <tr> <td width="50" height="50"></td> <td width="150"></td> <td width="150"></td> <td width="150"></td> </tr> </table> <table width="500" name="events" border="0"> <tr> <td width="50" height="50"><a href="#profile.php"><img src="Images/<?php echo $row_event['event_thumb_url']; ?>" border="0" height="50" width="50"/></a></td> <td width="150"><?php echo $row_event['event_name']; ?></td> <td width="150"><?php echo $row_event['event_venue']; ?></td> <td width="150"><?php echo $row_event['event_date']; ?></td> </tr> </table> <table width="500" name="establishments" border="0"> <tr> <td width="50" height="50"><a href="#profile.php"><img src="Establishment_Images/<?php echo $row_establishment['establishment_thumb_url']; ?>" border="0" height="50" width="50"/></a></td> <td width="150"><?php echo $row_establishment['establishment_name']; ?></td> <td width="150"><?php echo $row_establishment['location_id']; ?></td> <td width="150"><?php echo $row_establishment['establishment_pricing']; ?></td> </tr> </table> I haven't populated the PHP echo's for the user table. This is just to give you an idea of what I am trying to do. Any assistance?

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  • mysql join 3 tables and count

    - by air
    Please look at this image here is 3 tables , and out i want is uid from table1 industry from table 3 of same uid count of fid from table 2 of same uid like in the sample example output will be 2 records Thanks

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  • mysql update enums

    - by FFish
    I have a field with enums: 'preview','active','closed' When I query like this: $query = "UPDATE albums SET album_active = preview WHERE album_id = 3"; $result = mysql_query($query); if (!$result) die('Invalid query: ' . mysql_error()); I get : Invalid query: Unknown column 'preview' in 'field list

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  • MySQL: Selecting One Record When Others Have Same Data

    - by LoganFrederick
    I have a table of cities that all share the same area code: 367 01451 Harvard Worcester Massachusetts MA 978 Eastern 368 01452 Hubbardston Worcester Massachusetts MA 978 Eastern 369 01453 Leominster Worcester Massachusetts MA 978 Eastern The table has multiple area codes, all with multiple cities. What I'd like to do is only select one city from each area code and delete any extra cities from duplicate area codes. What would be the best query to accomplish this? I believe: http://stackoverflow.com/questions/596629/mysql4-sql-for-selecting-one-or-zero-record Is coming close to what I need but didn't quite get what/how those answers were working. Note The "978" row is the "area_code" row, table name is "zip_code".

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  • php array into mysql

    - by mckenzie
    Hello, $sql_where = ''; $exclude = '30,35,36,122,123,124,125'; if($exclude != '') { $exclude_forums = explode(',', $exclude); foreach ($exclude_forums as $id) { if ($id > 0) { $sql_where = ' AND forum_id <> ' . trim($id); } } } $sql = 'SELECT topic_title, forum_id, topic_id, topic_type, topic_last_poster_id, topic_last_poster_name, topic_last_poster_colour, topic_last_post_time FROM ' . TOPICS_TABLE . ' WHERE topic_status <> 2 AND topic_approved = 1 ' . $sql_where . ' ORDER BY topic_time DESC'; The above code i use to exclude the id of forum to be displayed on sql queries. Why doesn't it work and still display it? Any solution

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  • MySQL : Calculate business day difference between two dates column

    - by yokoyoko
    My sql query returns back two columns, first column is "date created" and second column is "date updated", first column has a prior timestamp with respect to second column. I need to add a third column which can display business day hrs (9:00am to 5:00pm) response i.e. if date created is 2012-01-01 09:00:20 and "dated updated" is 4:00pm same day then third column should display 7 hrs If date created is 2012-01-01 16:00:20 (4:00pm) and "date updated" is 10:00m on 2012:01:02 (2nd Jan) then third column should display 2 hrs. It should exclude Saturday and Sunday. Can you please suggest appropriate SQL query for this.

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  • Export data from mysql table row into an array format

    - by user1804952
    I am trying to output data from table : artists row : artist into this format. Artist Names can have special characters and there are over 16k of them. It needs to be written to a file. called anything artist.php for example $Artist = array( "Name from database", "Name from database", "Name from database", "Name from database", "Name from database" ); ok sorry for not explaining. do this for ajax auto complete.. so i need to create a file with this array in it. here is the exact script http://www.brandspankingnew.net/specials/ajax_autosuggest/ajax_autosuggest_autocomplete.html

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  • MySQL COUNT() multiple columns

    - by liam
    Hello, I'm trying to fetch the most popular tags from all videos in my database (ignoring blank tags). I also need the 'flv' for each tag. I have this working as I want if each video has one tag: SELECT tag_1, flv, COUNT(tag_1) AS tagcount FROM videos WHERE NOT tag_1='' GROUP BY tag_1 ORDER BY tagcount DESC LIMIT 0, 10 However in my database, each video is allowed three tags - tag_1, tag_2 and tag_3. Is there a way to get the most popular tags reading from multiple columns? The record structure is: +-----------------+--------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +-----------------+--------------+------+-----+---------+----------------+ | id | int(11) | NO | PRI | NULL | auto_increment | | flv | varchar(150) | YES | | NULL | | | tag_1 | varchar(75) | YES | | NULL | | | tag_2 | varchar(75) | YES | | NULL | | | tag_3 | varchar(75) | YES | | NULL | | +-----------------+--------------+------+-----+---------+----------------+

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  • convert mysql code to codeigniter

    - by Jethro Tamares Doble
    How can i convert this code into an acceptable codeigniter code: mysql_select_db($database_connection_ched, $connection_ched); $query_Institutions = "SELECT * FROM tb_institutional_profile ORDER BY tb_institutional_profile.institution_name ASC"; $Institutions = mysql_query($query_Institutions, $connection_ched) or die(mysql_error()); $row_Institutions = mysql_fetch_assoc($Institutions); $totalRows_Institutions = mysql_num_rows($Institutions); <td width="192"><select name="institution_id"> <?php do { <option value="<?php echo $row_Institutions['institution_id']?>" ><?php echo $row_Institutions['institution_name']?></option> <?php } while ($row_Institutions = mysql_fetch_assoc($Institutions)); ?> </select></td>

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  • getting rid of repeated customer id's in mysql query

    - by bsandrabr
    I originally started by selecting customers from a group of customers and then for each customer querying the records for the past few days and presenting them in a table row. All working fine but I think I might have got too ambitious as I tried to pull in all the records at once having heard that mutiple queries are a big no no. here is the mysqlquery i came up with to pull in all the records at once SELECT morning, afternoon, date, date2, fname, lname, customers.customerid FROM customers LEFT OUTER JOIN attend ON ( customers.customerid = attend.customerid ) RIGHT OUTER JOIN noattend ON ( noattend.date2 = attend.date ) WHERE noattend.date2 BETWEEN '$date2' AND '$date3' AND DayOfWeek( date2 ) %7 >1 AND group ={$_GET['group']} ORDER BY lname ASC , fname ASC , date2 DESC tables are customer-customerid,fname,lname attend-customerid,morning,afternoon,date noattend-date2 (a table of all the days to fill in the blanks) Now the problem I have is how to start a new row in the table when the customer id changes My query above pulls in customer 1 morning 2 customer 1 morning 1 customer 2 morning 2 customer 2 morning 1 whereas I'm trying to get customer1 morning2 morning1 customer2 morning2 morning1 I dont know whether this is possible in the sql or more likely in the php

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