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  • Insert statement with where clause.

    - by debraj
    I had a table with unique Date_t1 date type field, but in Table description field is not mentioned as unique, now while inserting new row i need to validate if date exist or not, If already exist i should not allow to make changes on that row, neither a new row needs to be created, Any idea how to resolve this problem in efficient way,

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  • How does mysql define DISTINCT()

    - by goran
    AFAIK SQL defines two uses of DISTINCT keywords - SELECT DISTINCT field... and SELECT COUNT(DISTINCT field) ... However in one of web applications that I administer I've noticed performance issues on queries like SELECT DISTINCT(field1), field2, field3 ... DISTINCT() on a single column makes no sense and I am almost sure it is interpreted as SELECT DISTINCT field1, field2, field3 ... but how can I prove this? I've searched mysql site for a reference on this particular syntax but could not find any. Does anyone have a link to definition of DISTINCT() in mysql or knows about other authoritative source on this? Best

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  • MySqli Prepared Statment Fetch Row

    - by pws5068
    I'm looking for an efficient way to select a specific row with a php prepared statement. $iDB = new mysqliDB(); $stmt = $iDB->prepare($sql); $stmt->bind_param('s',$searhStr); $stmt->execute(); $stmt->store_result(); $stmt->bind_result($objID,$typeID,$year,$updated); // Now jump to row $rowNumber echo("Obj ID = {$objID}"); Any suggestions? Thanks!

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  • How can I order by the result of a recursive SQL query

    - by Tony
    I have the following method I need to ORDER BY: def has_attachments? attachments.size > 0 || (!parent.nil? && parent.has_attachments?) end I have gotten this far: ORDER BY CASE WHEN attachments.size > 0 THEN 1 ELSE (CASE WHEN parent_id IS NULL THEN 0 ELSE (CASE message.parent ...what goes here ) END END END I may be looking at this wrong because I don't have experience with recursive SQL. Essentially I want to ORDER by whether a message or any of its parents has attachments. If it's attachment size is 0, I can stop and return a 1. If the message has an attachment size of 0, I now check to see if it has a parent. If it has no parent then there is no attachment, however if it does have a parent then I essentially have to do the same query case logic for the parent. UPDATE The table looks like this +---------------------+--------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +---------------------+--------------+------+-----+---------+----------------+ | id | int(11) | NO | PRI | NULL | auto_increment | | message_type_id | int(11) | NO | MUL | | | | message_priority_id | int(11) | NO | MUL | | | | message_status_id | int(11) | NO | MUL | | | | message_subject_id | int(11) | NO | MUL | | | | from_user_id | int(11) | YES | MUL | NULL | | | parent_id | int(11) | YES | MUL | NULL | | | expires_at | datetime | YES | MUL | NULL | | | subject_other | varchar(255) | YES | | NULL | | | body | text | YES | | NULL | | | created_at | datetime | NO | MUL | | | | updated_at | datetime | NO | | | | | lock_version | int(11) | NO | | 0 | | +---------------------+--------------+------+-----+---------+----------------+ Where the parent_id refers to the parent message, if it exists. Thanks!

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  • How to output JOINed tables?

    - by ilhan
    $id=(int)$_GET["id"]; $result = mysql_query("SELECT questionstable.*, categorytable.name FROM questionstable INNER JOIN categorytable ON categorytable.id = questionstable.category WHERE id=$id"); $row = mysql_fetch_assoc($result); Warning: mysql_fetch_assoc() expects parameter 1 to be resource, boolean given in C:\Program Files\EasyPHP-5.3.4.0\www\scsoru.php on line 33

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  • How to query AD to get name email from lan id

    - by Kumar
    I have some code in asp.net ( kindly given by someone else ) to query AD to get user name and email etc. using System.DirectoryServices; using System.DirectoryServices.ActiveDirectory; using ActiveDs; DirectorySearcher search = new DirectorySearcher(new DirectoryEntry(), string.Format("(samaccountname={0})", id)); if (search == null) return id; if (search.FindOne() == null) return id; DirectoryEntry usr = search.FindOne().GetDirectoryEntry(); IADsUser oUsr = (IADsUser)usr.NativeObject; return string.Format("{0} {1}", usr.Properties["givenname"].Value, usr.Properties["sn"].Value); However this requires impersonation with an id that's required to be changed every 2 weeks and then updated in the web.config which is often forgotten Is there any non impersonation code to achieve the same result ? UPDATE - it's a config tool and it looks up name, email id etc. I like the service a/c idea Q - How is it possible to run ( impersonate ) just the AD code with a "service" a/c ? any samples/code ? how do you impersona

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  • Listing mysql row entries from tags into one single row

    - by Derrick
    Hi guys, Ive got two tables, one a listings and another representing a list of tags for the listing table. In the listings table the tag ids are stored in a field called tags as 1-2-3- this has worked out very well for me regular expressions and joins to seperate and display the data, BUT... I now need to pull the titles of those tags into a single row. See below. listings table id tags 1 1-2-3- 2 4-5-6- tags table id title 1 pig 2 dog 3 cat 4 mouse 5 elephant 6 duck And what I need to produce out of the listings table is: id tags 2 mouse, elephant, duck any suggestions?

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  • Facebook multiquery result goes wrong?

    - by Simon
    This is my xml result return from facebook <fql_result_set list="true" xmlns="http://api.facebook.com/1.0/"> <comment> <object_id340982187784 </fql_result_set> <fql_result_set list="true" xmlns="http://api.facebook.com/1.0/"> <fql_result_set_elt list="true"> <fql_result_set_elt_elt key="object_id"340982187784811202784 The comment tag part is ok. After the comments you see the fql_result_set_elt and fql_result_elt_elt, this is the part goes wrong. fql_result_set_elt = like tag fql_result_set_elt_elt = object_id tag or user_id instead of having it on key attribute under fql_result_elt_elt

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  • PHP: table structure

    - by A3efan
    I'm developing a website that has some audio courses, each course can have multiple lessons. I want to display each course in its own table with its different lessons. This is my sql statement: Table: courses id, title Table: lessons id, cid (course id), title, date, file $sql = "SELECT lessons.*, courses.title AS course FROM lessons INNER JOIN courses ON courses.id = lessons.cid GROUP BY lessons.id ORDER BY lessons.id" ; Can someone help me with the PHP code? This is the I code I have written: mysql_select_db($database_config, $config); mysql_query("set names utf8"); $sql = "SELECT lessons.*, courses.title AS course FROM lessons INNER JOIN courses ON courses.id = lessons.cid GROUP BY lessons.id ORDER BY lessons.id" ; $result = mysql_query($sql) or die(mysql_error()); while ($row = mysql_fetch_assoc($result)) { echo "<p><span class='heading1'>" . $row['course'] . "</span> </p> "; echo "<p class='datum'>Posted onder <a href='*'>*</a>, latest update on " . strftime("%A %d %B %Y %H:%M", strtotime($row['date'])); } echo "</p>"; echo "<class id='text'>"; echo "<p>...</p>"; echo "<table border: none cellpadding='1' cellspacing='1'>"; echo "<tr>"; echo "<th>Nr.</th>"; echo "<th width='450'>Lesso</th>"; echo "<th>Date</th>"; echo "<th>Download</th>"; echo "</tr>"; echo "<tr>"; echo "<td>" . $row['nr'] . "</td>"; echo "<td>" . $row['title'] . "</td>"; echo "<td>" . strftime("%d/%m/%Y", strtotime($row['date'])) . "</td>"; echo "<td><a href='audio/" . rawurlencode($row['file']) . "'>MP3</a></td>"; echo "</tr>"; echo "</table>"; echo "<br>"; } ?>

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  • php MySQL snytax error

    - by Jacksta
    my scrip is supposed to look up contacts in a table and present thm on the screen to then be edited. however this is not this case. I am getting the error Parse error: syntax error, unexpected $end in /home/admin/domains/domain.com.au/public_html/pick_modcontact.php on line 50 NOTE: this is the last line in this script. <? session_start(); if ($_SESSION[valid] != "yes") { header( "Location: contact_menu.php"); exit; } $db_name = "testDB"; $table_name = "my_contacts"; $connection = @mysql_connect("localhost", "user", "pass") or die(mysql_error()); $db = @mysql_select_db($db_name, $connection) or die(mysql_error()); $sql = "SELECT id, f_name, l_name FROM $table_name ORDER BY f_name"; $result = @mysql_query($sql, $connection) or die(mysql_error()); $num = @mysql_num_rows($result); if ($num < 1) { $display_block = "<p><em>Sorry No Results!</em></p>"; } else { while ($row = mysql_fetch_array($result)) { $id = $row['id']; $f_name = $row['f_name']; $l_name = $row['l_name']; $option_block .= "<option value\"$id\">$l_name, $f_name</option>"; } $display_block = "<form method=\"POST\" action=\"show_modcontact.php\"> <p><strong>Contact:</strong> <select name=\"id\">$option_block</select> <input type=\"submit\" name=\"submit\" value=\"Select This Contact\"></p> </form>"; ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Modify A Contact</title> </head> <body> <h1>My Contact Management System</h1> <h2><em>Modify a Contact</em></h2> <p>Select a contact from the list below, to modify the contact's record.</p> <? echo "$display_block"; ?> <br> <p><a href="contact_menu.php">Return to Main Menu</a></p> </body> </html>

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  • Oracle get previous day records

    - by Phill Pafford
    Ok I think I'm getting the previous year instead of the previous day, but I need to previous day. SELECT TO_DATE(TO_CHAR(CURRENT_DATE, 'YYYY-MM-DD'),'YYYY-MM-DD') - 1 FROM Dual I'm comparing it to a datetime stamp in this format and wish to get all the rows from the previous day. YYYY-MM-DD HH:MM:SS So I'm trying something like this SELECT field,datetime_field FROM database WHERE datetime_field > TO_DATE(TO_CHAR(CURRENT_DATE, 'YYYY-MM-DD'),'YYYY-MM-DD') - 1

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  • SQl queries searching by date range

    - by tecno
    Hi, I have a table in an Access 2007 database, all fields are of type text. Can the following be done using the where clause. If so how? SELECT * from Table1 WHERE (ColumnDate is between 26th and 19th of march 2010) SELECT * from Table1 WHERE (ColumnAge is between 25 and 40) The usual < <= operators dont seem to work. Thanks,

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  • Unable to Get a Correct Time when I am Calling serverTime using jquery.countdown.js + Asp.net ?

    - by user312891
    When i am calling the below function I unable to get a correct Answer. Both var Shortly and newTime having same time one coming from the client site other sync with server. http://keith-wood.name/countdown.html I am waiting from your response. Thanks $(function() { var shortly = new Date('April 9, 2010 20:38:10'); var newTime = new Date('April 9, 2010 20:38:10'); //for loop divid /// $('#defaultCountdown').countdown({ until: shortly, onExpiry: liftOff, onTick: watchCountdown, serverSync: serverTime }); $('#div1').countdown({ until: newTime }); }); function serverTime() { var time = null; $.ajax({ type: "POST", //Page Name (in which the method should be called) and method name url: "Default.aspx/GetTime", // If you want to pass parameter or data to server side function you can try line contentType: "application/json; charset=utf-8", dataType: "json", data: "{}", async: false, //else If you don't want to pass any value to server side function leave the data to blank line below //data: "{}", success: function(msg) { //Got the response from server and render to the client time = new Date(msg.d); alert(time); }, error: function(msg) { time = new Date(); alert('1'); } }); return time; }

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  • Testing for existence using SELECT WHERE HAVING and NOT HAVING in a grouped subset

    - by IanC
    I have data on which I need to count +1 if a particular condition exists or another condition doesn't exist. I'm using SQL Server 2008. I shred the following simplified sample XML into a temp table and validate it: <product type="1"> <param type="1"> <item mode="0" weight="1" /> </param> <param type="2"> <item mode="1" weight="1" /> <item mode="0" weight="0.1" /> </param> <param type="3"> <item mode="1" weight="0.75" /> <item mode="1" weight="0.25" /> </param> </product> The validation in concern is the following rule: For each product type, for each param type, mode may be 0 & (1 || 2). In other words, there may be a 0(s), but then 1s or 2s are required, or there may be only 1(s) or 2(s). There cannot be only 0s, and there cannot be 1s and 2s. The only part I haven't figured out is how to detect if there are only 0s. This seems like a "not having" problem. The validation code (for this part): WITH t1 AS ( SELECT SUM(t.ParamWeight) AS S, COUNT(1) AS C, t.ProductTypeID, t.ParamTypeID, t.Mode FROM @t AS t GROUP BY t.ProductTypeID, t.ParamTypeID, t.Mode ), ... UNION ALL SELECT TOP (1) 1 -- only mode 0 & (1 || 2) is allowed FROM t1 WHERE t1.Mode IN (1, 2) GROUP BY t1.ProductTypeID, t1.ParamTypeID HAVING COUNT(1) > 1 UNION ALL ... ) SELECT @C = COUNT(1) FROM t2 This will show if any mode 1s & 2s are mixed, but not if the group contains only a 0. I'm sure there is a simple solution, but it's evading me right now. EDIT: I thought of a "cheat" that works perfectly. I added the following to the above: SELECT TOP (1) 1 -- only mode 0 & (null || 1 || 2) is allowed FROM t1 GROUP BY t1.ProductTypeID, t1.ParamTypeID HAVING SUM(t1.Mode) = 0 However, I'd still like to know how to do this without cheating.

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  • Access: strange results with queries against MDB file

    - by Craig Johnston
    I am running the following SQL against an MDB file, a copy of which is located here: http://hotfile.com/dl/40641614/2353dfc/test.mdb.html (perfectly clean file, no macros or viruses) SELECT datediff("d", MAX(invoice.date), Now) As Date_Diff , MAX(invoice.date) AS max_invoice_date , customer.number AS customer_number FROM invoice INNER JOIN customer ON invoice.customer_number = customer.number GROUP BY customer.number If the the following was added: HAVING datediff("d", MAX(invoice.date), Now) > 365 would this simply exclude rows with Date_Diff <= 365? What should be the effect of the HAVING clause here?

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  • Any disadvantages to this tagging approach

    - by donpal
    I have a table of tags ID tag --- ------ 1 tagt 2 tagb 3 tagz 4 tagn In my items table, I'm using those tags in serialized format, comma delimited ID field1 tags ---- ------ ----- 1 value1 tagt,tagb 2 value2 tagb 3 value3 tagb,tagn 4 value4 When I need to find items that have this tag, I plan to deserialize the tags. But I'm not actually sure how to do it, and if it's better to have a third table for associations instead between the tags and the items.

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  • Database time data retrieval, time based queries

    - by Raphael Pineda
    I am new to time manipulation or time arithmetic operations and am currently developing a navigation system with Web server based information and currently I have this Database that contains a table peek hours whose columns are id, start_time, end_time , edge_id, day_of_the_week, edge_weight ------------------------------------------------------------------------ | Peek Hours | ------------------------------------------------------------------------ | | | | | | | | id | start_time | end_time | edge_id | day_of_the_week | edge_weight | | | | | | | | ------------------------------------------------------------------------ I am using PHP as a webservice and so based on the current time i want to get all the records that would fit this equation start_time< current_time < end_time

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  • How to match multiple field in mySQL

    - by Mint
    Im trying to match forum_id with several different forum_id's, something like forum_id = 5,7,12,43,63,78 I currently have this code: SELECT topic_title, topic_id, forum_id FROM $MYSQL_TOPIC WHERE topic_title LIKE '%%%s%%' AND forum_id = 5 LIMIT 50 (using mysql_real_escape_string and sprintf) I tried: forum_id = 5 OR 7 forum_id = 5|7 forum_id = 5 AND 7 forum_id = 5 & 7 But none of them will match them all and therefore search though them all.

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  • SQL: GROUP BY after JOIN without overriding rows?

    - by krismeld
    I have a table of basketball leagues, a table af teams and a table of players like this: LEAGUES ID | NAME | ------------------ 1 | NBA | 2 | ABA | TEAMS: ID | NAME | LEAGUE_ID ------------------------------ 20 | BULLS | 1 21 | KNICKS | 2 PLAYERS: ID | TEAM_ID | FIRST_NAME | LAST_NAME | --------------------------------------------- 1 | 21 | John | Starks | 2 | 21 | Patrick | Ewing | Given a League ID, I would like to retrieve all the players' names and their team ID from all the teams in that league, so I do this: SELECT t.id AS team_id, p.id AS player_id, p.first_name, p.last_name FROM teams AS t JOIN players AS p ON p.team_id = t.id WHERE t.league_id = 1 which returns: [0] => stdClass Object ( [team_id] => 21 [player_id] => 1 [first_name] => John [last_name] => Starks ) [1] => stdClass Object ( [team_id] => 21 [player_id] => 2 [first_name] => Patrick [last_name] => Ewing ) + around 500 more objects... Since I will use this result to populate a dropdown menu for each team containing each team's list of players, I would like to group my result by team ID, so the loop to create these dropdowns will only have to cycle through each team ID instead of all 500+ players each time. But when I use the GROUP BY like this: SELECT t.id AS team_id, p.id AS player_id, p.first_name, p.last_name FROM teams AS t JOIN players AS p ON p.team_id = t.id WHERE t.league_id = 1 GROUP BY t.id it only returns one player from each team like this, overriding all the other players on the same team because of the use of the same column names. [0] => stdClass Object ( [team_id] => 21 [player_id] => 2 [first_name] => Patrick [last_name] => Ewing ) [1] => stdClass Object ( [team_id] => 22 [player_id] => 31 [first_name] => Shawn [last_name] => Kemp ) etc... I would like to return something like this: [0] => stdClass Object ( [team_id] => 2 [player_id1] => 1 [first_name1] => John [last_name1] => Starks [player_id2] => 2 [first_name2] => Patrick [last_name2] => Ewing +10 more players from this team... ) +25 more teams... Is it possible somehow?

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