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• Spring Security - Persistent Remember Me Issue

  - by Taylor L

  I've been trying to track down why Spring Security isn't creating the Spring Security remember me cookie (SPRING_SECURITY_REMEMBER_ME_COOKIE). At first glance, the logs make it seem like the login is failing, but the login is actually successful in the sense that if I navigate to a page that requires authentication I am not redirected back to the login page. However, the logs appear to be saying the login credentials are invalid. I'm using Spring 3.0.1, Spring Security 3.0.1, and Google App Engine 1.3.1. Any ideas as to what is going on? Mar 16, 2010 10:05:56 AM org.springframework.security.web.authentication.rememberme.PersistentTokenBasedRememberMeServices onLoginSuccess FINE: Creating new persistent login for user [email protected] Mar 16, 2010 10:10:07 AM org.springframework.security.web.authentication.rememberme.AbstractRememberMeServices loginFail FINE: Interactive login attempt was unsuccessful. Mar 16, 2010 10:10:07 AM org.springframework.security.web.authentication.rememberme.AbstractRememberMeServices cancelCookie FINE: Cancelling cookie Below is the relevant portion of the applicationContext-security.xml. <http auto-config="false"> <intercept-url pattern="/css/**" filters="none" /> <intercept-url pattern="/img/**" filters="none" /> <intercept-url pattern="/js/**" filters="none" /> <intercept-url pattern="/app/admin/**" filters="none" /> <intercept-url pattern="/app/login/**" filters="none" /> <intercept-url pattern="/app/register/**" filters="none" /> <intercept-url pattern="/app/error/**" filters="none" /> <intercept-url pattern="/" filters="none" /> <intercept-url pattern="/**" access="ROLE_USER" /> <logout logout-success-url="/" /> <form-login login-page="/app/login" default-target-url="/" authentication-failure-url="/app/login?login_error=1" /> <session-management invalid-session-url="/app/login" /> <remember-me services-ref="rememberMeServices" key="myKey" /> </http> <authentication-manager alias="authenticationManager"> <authentication-provider user-service-ref="userDetailsService"> <password-encoder hash="sha-256" base64="true"> <salt-source user-property="username" /> </password-encoder> </authentication-provider> </authentication-manager> <beans:bean id="userDetailsService" class="com.my.service.auth.UserDetailsServiceImpl" /> <beans:bean id="rememberMeServices" class="org.springframework.security.web.authentication.rememberme.PersistentTokenBasedRememberMeServices"> <beans:property name="userDetailsService" ref="userDetailsService" /> <beans:property name="tokenRepository" ref="persistentTokenRepository" /> <beans:property name="key" value="myKey" /> </beans:bean> <beans:bean id="persistentTokenRepository" class="com.my.service.auth.PersistentTokenRepositoryImpl" />

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• MP4 plays on Safari 4 (desktop) but not on Safari Mobile (iphone)

  - by deb

  I'm encoding the video with ffmpeg and displaying it using the HTML 5 video tag. It works fine on Firefox (i'm also providing a ogg version) and Safari 4. However, when I try to open it on the iphone I get a "Cannot Play Movie" error. Here is the ffmpeg command I'm using: ffmpeg -y -i movie.mov -acodec libfaac -ar 44100 -ab 96k -vcodec libx264 -vpre hq -level 41 -crf 20 -bufsize 20000k -maxrate 1500k -g 250 -s 320X200 -coder 1 -flags +loop -cmp +chroma -partitions +parti4x4+partp8x8+partb8x8 -flags2 +dct8x8+bpyramid -me_method umh -subq 7 -me_range 16 -keyint_min 25 -sc_threshold 40 -i_qfactor 0.71 -rc_eq 'blurCplx^(1-qComp)' -bf 16 -b_strategy 1 -bidir_refine 1 -refs 6 -deblockalpha 0 -deblockbeta 0 movie.mp4 I reduced the maxrate to 1500 because I read that if the bit rate is too high the iphone won't play the video, but still didn't work. I don't know where else to look... any ideas? Thanks in advance

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• Installing flex on Mac Parallels

  - by Ali Syed

  Hello folks, I am trying to install Flex 3 on my Windows 7 Virtual machine (parallels desktop) on my Mac Pro. The problem seems to be some sort of conflict between the copy of Flex 3 Builder installed on Mac OS X. The installer tries to install Flex in x:/Program Files/Adobe/Flex Builder 3/ but since Parallels Desktop connects all directories, there resides the Flex Builder 3 installation of MAC. I get this error Log: !SESSION 2010-04-22 16:09:23.031 ----------------------------------------------- eclipse.buildId=unknown java.version=1.5.0_11 java.vendor=Sun Microsystems Inc. BootLoader constants: OS=win32, ARCH=x86, WS=win32, NL=de_DE Framework arguments: -application org.eclipse.update.core.standaloneUpdate -command install -from file:\C:\Program Files\Adobe\Flex Builder 3 Windose\com.adobe.flexbuilder.update.site/ -featureId com.adobe.flexbuilder.feature.standalone -version 3.0.214193 Command-line arguments: -application org.eclipse.update.core.standaloneUpdate -command install -from file:\C:\Program Files\Adobe\Flex Builder 3 Windose\com.adobe.flexbuilder.update.site/ -featureId com.adobe.flexbuilder.feature.standalone -version 3.0.214193 !ENTRY org.eclipse.update.core 4 0 2010-04-22 16:09:29.187 !MESSAGE Cannot install featurecom.adobe.flexbuilder.feature.standalone 3.0.214193

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• Read half precision float (float16 IEEE 754r) binary data in matlab

  - by Michael

  you have been a great help last time, i hope you can give me some advise this time, too. I read a binary file into matlab with bit16 (format = bitn) and i get a string of ones and zeros. bin = '1 00011 1111111111' (16 bits: 1. sign, 2-6. exponent, 7-16. mantissa) According to ftp://www.fox-toolkit.org/pub/fasthalffloatconversion.pdf it can be 'converted' like out = (-1)^bin(1) * 2^(bin(2:6)-15) * 1.bin(7:16) [are exponent and mantissa still binary?] Can someone help me out and tell me how to deal with the 'eeeee' and '1.mmmmmmmmmm' as mentioned in the pdf, please. Thanks a lot! Michael

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• Size Mismatch Between Swing Fonts and Printable Fonts in Java

  - by Caleb Rackliffe

  Hi All, I've got a panel displaying a JTextPane backed by a StyledDocument. When I print a string of text in, say Arial 16, the text it prints is of a different size than the Arial 16 Word prints. Is there some sort of flaw in the translation of Swing fonts to Windows system fonts or something of the sort that makes it difficult (or impossible) to print accurately? I can achieve an approximation by scaling down the size of my font before printing, but this never quite gets me the results I would like, as it's not possible in all cases to reproduce things like equivalent numbers of words on a line, etc. Has anybody run into this before?

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• Strange remoting connection problem

  - by Voyager Systems

  In trying to configure a .NET remoting setup over TCP, I've been having problems accepting outside connections (connections from any computer not on my LAN). I did some investigation and hit netstat -a as soon as my friend started to connect. Here's what I saw: TCP 0.0.0.0:2594 Taylor-PC:0 LISTENING ... TCP 192.168.1.102:2594 24-155-7-16:63588 ESTABLISHED TCP 192.168.1.102:62488 192.168.0.100:1554 SYN_SENT Now here's the weird part: 24.155.7.16 is my friend's IP (modified) and it says the connection is established. But the connection hangs until it times out. I then found out that 192.168.0.100 is his local address on his network. Something screwy's going on somewhere. My server and client are both TCPChannels, the latter initialized 'new TCPChannel( 0 ).' Localhost connections work when I run a client on the same machine as the server, but I can't accept remote connections. There is no port forwarding or firewall issue. Thanks for the help

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• Binding a wpf listbox to a combobox

  - by user293545

  Hi there, I have created a very basic wpf application that I want to use to record time entries against different projects. I havent used mvvm for this as I think its an overkill. I have a form that contains a combobox and a listbox. I have created a basic entity model like this What I am trying to do is bind the combobox to Project and whenever I select an item from the combobox it updates the listview with the available tasks associated with that project. This is my xaml so far. I dont have any code behind as I have simply clicked on that Data menu and then datasources and dragged and dropped the items over. The application loads ok and the combobox is been populated however nothing is displaying in the listbox. Can anyone tell me what I have missed? <Window.Resources> <CollectionViewSource x:Key="tasksViewSource" d:DesignSource="{d:DesignInstance l:Task, CreateList=True}" /> <CollectionViewSource x:Key="projectsViewSource" d:DesignSource="{d:DesignInstance l:Project, CreateList=True}" /> </Window.Resources> <Grid DataContext="{StaticResource tasksViewSource}"> <l:NotificationAreaIcon Text="Time Management" Icon="Resources\NotificationAreaIcon.ico" MouseDoubleClick="OnNotificationAreaIconDoubleClick"> <l:NotificationAreaIcon.MenuItems> <forms:MenuItem Text="Open" Click="OnMenuItemOpenClick" DefaultItem="True" /> <forms:MenuItem Text="-" /> <forms:MenuItem Text="Exit" Click="OnMenuItemExitClick" /> </l:NotificationAreaIcon.MenuItems> </l:NotificationAreaIcon> <Button Content="Insert" Height="23" HorizontalAlignment="Left" Margin="150,223,0,0" Name="btnInsert" VerticalAlignment="Top" Width="46" Click="btnInsert_Click" /> <ComboBox Height="23" HorizontalAlignment="Left" Margin="70,16,0,0" Name="comProjects" VerticalAlignment="Top" Width="177" DisplayMemberPath="Project1" ItemsSource="{Binding Source={StaticResource projectsViewSource}}" SelectedValuePath="ProjectID" /> <Label Content="Projects" Height="28" HorizontalAlignment="Left" Margin="12,12,0,0" Name="label1" VerticalAlignment="Top" IsEnabled="False" /> <Label Content="Tasks" Height="28" HorizontalAlignment="Left" Margin="16,61,0,0" Name="label2" VerticalAlignment="Top" /> <ListBox Height="112" HorizontalAlignment="Left" Margin="16,87,0,0" Name="lstTasks" VerticalAlignment="Top" Width="231" DisplayMemberPath="Task1" ItemsSource="{Binding Path=ProjectID, Source=comProjects}" SelectedValuePath="TaskID" /> <TextBox Height="23" HorizontalAlignment="Left" Margin="101,224,0,0" Name="txtMinutes" VerticalAlignment="Top" Width="42" /> <Label Content="Mins to Insert" Height="28" HorizontalAlignment="Left" Margin="12,224,0,0" Name="label3" VerticalAlignment="Top" /> <Button Content="None" Height="23" HorizontalAlignment="Left" Margin="203,223,0,0" Name="btnNone" VerticalAlignment="Top" Width="44" /> </Grid>

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• SQL Server: Database stuck in "Restoring" state

  - by Ian Boyd

  i backed up a data: BACKUP DATABASE MyDatabase TO DISK = 'MyDatabase.bak' WITH INIT --overwrite existing And then tried to restore it: RESTORE DATABASE MyDatabase FROM DISK = 'MyDatabase.bak' WITH REPLACE --force restore over specified database And now the database is stuck in the restoring state. Some people have theorized that it's because there was no log file in the backup, and it needed to be rolled forward using: RESTORE DATABASE MyDatabase WITH RECOVERY Except that, of course, fails: Msg 4333, Level 16, State 1, Line 1 The database cannot be recovered because the log was not restored. Msg 3013, Level 16, State 1, Line 1 RESTORE DATABASE is terminating abnormally. And exactly what you want in a catastrophic situation is a restore that won't work. The backup contains both a data and log file: RESTORE FILELISTONLY FROM DISK = 'MyDatabase.bak' Logical Name PhysicalName ============= =============== MyDatabase C:\Program Files\Microsoft SQL Server\MSSQL.1\MSSQL\DATA\MyDatabase.mdf MyDatabase_log C:\Program Files\Microsoft SQL Server\MSSQL.1\MSSQL\DATA\MyDatabase_log.LDF

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• Letters in base-conversion

  - by tech_geek23

  I have this code written so far and is correct, aside from not using A-F when the value is over 10: public class TenToAny { private int base10; private int newBase; public TenToAny() { } public TenToAny(int ten, int base) { base10 = ten; newBase = base; } public void setNums(int ten, int base) { base10 = ten; newBase = base; } public String getNewNum() { String newNum=""; int orig = base10; //int first = newBase - 1; while(orig > 0) { newNum = orig%newBase + newNum; orig = orig/newBase; } return newNum; } public String toString() { String complete = base10 + " base 10 is " + getNewNum() + " in base " + newBase; return complete; } } Obviously I don't have anything relating to values over 10 converting to A-F as I've never dealt with these before. Any help is appreciated. Here's my runner class: public class Lab09i { public static void main( String args[] ) { TenToAny test = new TenToAny(234, 9); out.println(test); test.setNums(100, 2); out.println(test); test.setNums(10, 2); out.println(test); test.setNums(15, 2); out.println(test); test.setNums(256, 2); out.println(test); test.setNums(100, 8); out.println(test); test.setNums(250, 16); out.println(test); test.setNums(56, 11); out.println(test); test.setNums(89, 5); out.println(test); test.setNums(23, 3); out.println(test); test.setNums(50, 5); out.println(test); test.setNums(55, 6); out.println(test); test.setNums(2500, 6); out.println(test); test.setNums(2500, 13); out.println(test); } } this is what my results should be: 234 base 10 is 280 in base 9 100 base 10 is 1100100 in base 2 10 base 10 is 1010 in base 2 15 base 10 is 1111 in base 2 256 base 10 is 100000000 in base 2 100 base 10 is 144 in base 8 250 base 10 is FA in base 16 56 base 10 is 51 in base 11 89 base 10 is 324 in base 5 23 base 10 is 212 in base 3 50 base 10 is 302 in base 4 55 base 10 is 131 in base 6 2500 base 10 is 9C4 in base 16 2500 base 10 is 11A4 in base 13

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• The Skyline Problem.

  - by zeroDivisible

  I just came across this little problem on UVA's Online Judge and thought, that it may be a good candidate for a little code-golf. The problem: You are to design a program to assist an architect in drawing the skyline of a city given the locations of the buildings in the city. To make the problem tractable, all buildings are rectangular in shape and they share a common bottom (the city they are built in is very flat). The city is also viewed as two-dimensional. A building is specified by an ordered triple (Li, Hi, Ri) where Li and Ri are left and right coordinates, respectively, of building i and Hi is the height of the building. In the diagram below buildings are shown on the left with triples (1,11,5), (2,6,7), (3,13,9), (12,7,16), (14,3,25), (19,18,22), (23,13,29), (24,4,28) and the skyline, shown on the right, is represented by the sequence: 1, 11, 3, 13, 9, 0, 12, 7, 16, 3, 19, 18, 22, 3, 23, 13, 29, 0 The output should consist of the vector that describes the skyline as shown in the example above. In the skyline vector (v1, v2, v3, ... vn) , the vi such that i is an even number represent a horizontal line (height). The vi such that i is an odd number represent a vertical line (x-coordinate). The skyline vector should represent the "path" taken, for example, by a bug starting at the minimum x-coordinate and traveling horizontally and vertically over all the lines that define the skyline. Thus the last entry in the skyline vector will be a 0. The coordinates must be separated by a blank space. If I will not count declaration of provided (test) buildings and including all spaces and tab characters, my solution, in Python, is 223 characters long. Here is the condensed version: B=[[1,11,5],[2,6,7],[3,13,9],[12,7,16],[14,3,25],[19,18,22],[23,13,29],[24,4,28]] # Solution. R=range v=[0 for e in R(max([y[2] for y in B])+1)] for b in B: for x in R(b[0], b[2]): if b[1]>v[x]: v[x]=b[1] p=1 k=0 for x in R(len(v)): V=v[x] if p and V==0: continue elif V!=k: p=0 print "%s %s" % (str(x), str(V)), k=V I think that I didn't made any mistake but if so - feel free to criticize me. EDIT I don't have much reputation, so I will pay only 100 for a bounty - I am curious, if anyone could try to solve this in less than .. lets say, 80 characters. Solution posted by cobbal is 101 characters long and currently it is the best one. ANOTHER EDIT I thought, that 80 characters is a sick limit for this kind of problem. cobbal, with his 46 character solution totaly amazed me - though I must admit, that I spent some time reading his explanation before I partially understood what he had written.

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• How can I successfully dechiper Instruments Messages for iPhone Leak

  - by dubbeat

  Hi, I have a memory leak in my app. (This is the first of many I'm sure :() I've being trying to use Instruments to find it. Instruments gives me a lot of information but I think I must just not know how to use this information. What I did so far was 1) Run the app with Instruments 2) Memory Leak Occurs named general -stack 16 3) Find general - stack 16 in the object allocations part of instruments 4) The information here says the event type is a malloc, that webcore is responsible and the something named WKSetCurrentGraphicContext is the responsible caller. How can I use this given information to discover where in my code the leak is being caused? If I comment out the following function I don't get the leak warning so I guess it should be in there somewhere but I can't see where -(void)constructFeatured { NSString *imageName =[[NSString alloc] initWithFormat:@"%@%@%@",@"http://myweb/avatar_", featuredValueObject.featured_promo_artistid, @".jpg"]; NSURL *url = [NSURL URLWithString:imageName]; CGRect frame; frame.size.width=100; frame.size.height=100; frame.origin.x=20; frame.origin.y=39; [imageName release]; imageName=nil; SDWebImageManager *manager = [SDWebImageManager sharedManager]; UIImage *cachedImage = [manager imageWithURL:url]; if (cachedImage) { cachedImage =[ImageManipulator makeRoundCornerImage:cachedImage : 10 : 10]; UIImageView *avatarimageview = [[UIImageView alloc]initWithImage:cachedImage ]; avatarimageview.frame=frame; [self.view addSubview:avatarimageview]; UIView *spinny = [self.view viewWithTag:SPINNY_TAG]; [spinny removeFromSuperview]; [avatarimageview release]; } else { [manager downloadWithURL:url delegate:self]; } NSURL *url2 =[NSURL URLWithString:[NSString stringWithFormat:@"%@%@%@",@"http://myweb/", featuredValueObject.featured_promo_artistcountry , @".png"]]; CGRect flagframe; flagframe.size.width=16; flagframe.size.height=11; flagframe.origin.x=130; flagframe.origin.y=40; NSData* data = [[NSData alloc] initWithContentsOfURL:url2]; UIImage* img = [[UIImage alloc] initWithData:data]; UIImageView *imageflagview = [[UIImageView alloc] initWithImage: img]; imageflagview.frame=flagframe; [self.view addSubview:imageflagview]; [imageflagview release]; imageflagview=nil; [data release]; [img release]; [url release]; artistname =[[UILabel alloc]initWithFrame:CGRectMake(130,75, 200, 15)]; [artistname setFont:[UIFont fontWithName:@"Arial" size:(16.0)]]; artistname.backgroundColor= [UIColor clearColor]; artistname.textColor=[UIColor whiteColor]; artistname.text=featuredValueObject.featured_promo_artistname; [self.view addSubview:artistname]; [artistname release]; hasConstructedFeatured=YES; [featuredValueObject release]; featuredValueObject=nil; }

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• Custom UISwitch & App Store approval

  - by pix0r

  After doing some reading, I've found that you can customize the text and color on a UISwitch control. I'm curious if these methods will cause problems trying to get my app approved and included in the App Store. Sample code taken from iPhone Developer's Cookbook Sample Code: // Custom font, color switchView = [[UICustomSwitch alloc] initWithFrame:CGRectZero]; [switchView setCenter:CGPointMake(160.0f,260.0f)]; [switchView setLeftLabelText: @"Foo"]; [switchView setRightLabelText: @"Bar"]; [[switchView rightLabel] setFont:[UIFont fontWithName:@"Georgia" size:16.0f]]; [[switchView leftLabel] setFont:[UIFont fontWithName:@"Georgia" size:16.0f]]; [[switchView leftLabel] setTextColor:[UIColor yellowColor]];

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• Runtime error of TASM language help!

  - by dominoos

  .model small .stack 400h .data message db "hello. ", 0ah, 0dh, "$" firstdigit db ? seconddigit db ? thirddigit db ? number dw ? newnumber db ? anumber dw 0d bnumber dw 0d Firstn db 0ah, 0dh, "Enter first 3 digit number: ","$" secondn db 0ah, 0dh, "Enter second 3 digit number: ","$" messageB db 0ah, 0dh, "HCF of two number is: ","$" linebreaker db 0ah, 0dh, ' ', 0ah, 0dh, '$' .code Start: mov ax, @data ; establish access to the data segment mov ds, ax ; mov number, 0d mov dx, offset message ; print the string "yob choi 0648293" mov ah, 9h int 21h num: mov dx, offset Firstn ; print the string "put 1st 3 digit" mov ah, 9h int 21h ;run JMP FirstFirst ; jump to FirstFirst FirstFirst: ;first digit mov ah, 1d ;bios code for read a keystroke int 21h ;call bios, it is understood that the ascii code will be returned in al mov firstdigit, al ;may as well save a copy sub al, 30h ;Convert code to an actual integer cbw ;CONVERT BYTE TO WORD. This takes whatever number is in al and ;extends it to ax, doubling its size from 8 bits to 16 bits ;The first digit now occupies all of ax as an integer mov cx, 100d ;This is so we can calculate 100*1st digit +10*2nd digit + 3rd digit mul cx ;start to accumulate the 3 digit number in the variable imul cx ;it is understood that the other operand is ax ; the result will use both dx::ax ;dx will contain only leading zeros add anumber, ax ;save ;Second Digit mov ah, 1d ;bios code for read a keystroke int 21h ;call bios, it is understood that the ascii code will be returned in al mov seconddigit, al ;may as well save a copy sub al, 30h ;Convert code to an actual integer cbw ;CONVERT BYTE TO WORD. This takes whatever number is in al and ;extends it to ax, boubling its size from 8 bits to 16 bits ;The first digit now occupies all of ax as an integer mov cx, 10d ;continue to accumulate the 3 digit number in the variable mul cx ;it is understood that the other operand is ax, containing first digit ;the result will use both dx::ax ;dx will contain only leading zeros. add anumber, ax ;save ;third Digit mov ah, 1d ;samething as above int 21h ; mov thirddigit, al ; sub al, 30h ; cbw ; add anumber, ax ; jmp num2 ;go to checks Num2: mov dx, offset secondn ; print the string "put 2nd 3 digits" mov ah, 9h int 21h ;run JMP SecondSecond SecondSecond: ;first digit mov ah, 1d ;bios code for read a keystroke int 21h ;call bios, it is understood that the ascii code will be returned in al mov firstdigit, al ;may as well save a copy sub al, 30h ;Convert code to an actual integer cbw ;CONVERT BYTE TO WORD. This takes whatever number is in al and ;extends it to ax, doubling its size from 8 bits to 16 bits ;The first digit now occupies all of ax as an integer mov cx, 100d ;This is so we can calculate 100*1st digit +10*2nd digit + 3rd digit mul cx ;start to accumulate the 3 digit number in the variable imul cx ;it is understood that the other operand is ax ; the result will use both dx::ax ;dx will contain only leading zeros add bnumber, ax ;save ;Second Digit mov ah, 1d ;bios code for read a keystroke int 21h ;call bios, it is understood that the ascii code will be returned in al mov seconddigit, al ;may as well save a copy sub al, 30h ;Convert code to an actual integer cbw ;CONVERT BYTE TO WORD. This takes whatever number is in al and ;extends it to ax, boubling its size from 8 bits to 16 bits ;The first digit now occupies all of ax as an integer mov cx, 10d ;continue to accumulate the 3 digit number in the variable mul cx ;it is understood that the other operand is ax, containing first digit ;the result will use both dx::ax ;dx will contain only leading zeros. add bnumber, ax ;save ;third Digit mov ah, 1d ;samething as above int 21h ; mov thirddigit, al ; sub al, 30h ; cbw ; add bnumber, ax ; jmp compare ;go to compare compare: CMP ax, anumber ;comparing numbB and Number JA comp1 ;go to comp1 if anumber is bigger CMP ax, anumber ; JB comp2 ;go to comp2 if anumber is smaller CMP ax, anumber ; JE equal ;go to equal if two numbers are the same JMP compare ;go to compare (avioding error) comp1: SUB ax, anumber; subtract smaller number from bigger number JMP compare ; comp2: SUB anumber, ax; subtract smaller number from bigger number JMP compare ; equal: mov ah, 9d ;make linkbreak after the 2nd 3 digit number mov dx, offset linebreaker int 21h mov ah, 9d ;print "HCF of two number is:" mov dx, offset messageB int 21h mov ax,anumber ;copying 2nd number into ax add al,30h ; converting to ascii mov newnumber,al ; copying from low part of register into newnumb mov ah, 2d ;bios code for print a character mov dl, newnumber ;we had saved the ascii code here int 21h ;call to bios JMP exit; exit: mov ah, 4ch int 21h ;exit the program End hi, this is a program that finds highest common factor of 2 different 3digit number. if i put 200, 235,312 (low numbers) it works fine. but if i put 500, 550, 654(bigger number) the program crashes after the 2nd 3digit number is entered. can you help me to find out what problem is?

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• mkmapview userlocation annimation issue

  - by Gedeon

  I have issue with userlocation in mkmapview. The thing is that i have navigation controller which pushes mapview , as soon as it pushes it userlocation is queried. But if user pop mapview view before userlocation animation is finished , it throws exception because animation is trying to access deallocated mapview instance. So my question is , how to prevent that. I could do it by disabling back button , but i am not sure if that right way to take. Does anybody know how to stop current animation?

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• Alternative to Turbo C

  - by Asad Jibran Ahmed

  My university is hosting a Programming Competition, and have decided to support Turbo C (the 16-bit DOS version) as a valid programming environment. I have just read that PC^2, the software that is going to be used to auto-judge the competition, does not support 16-bit programs. So, is there any alternative to Turbo C that I can use. I need the same header files, and the compiler would need to support all the outdated C standards that Turbo C supports. But the output needs to be 32-bit. Is there any compiler that can satisfy these conditions?

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• SVN: Create a dump file of a folder

  - by DarkJaff

  I'm trying to create a dump file of a folder in my SVN repository.(My goal is to import this dump on another repository, but that's another story). I've read like 20 pages about this and they all tell me to use svndumpfilter but I can't seem to make it work. Here is my command: C:\>svnadmin dump d:/SvnData/TestingSVN/ | svndumpfilter include /TestingSVN/Trunk/Fms/ > d:\FMS.txt The output in the command line is this strange thing: Including prefixes: '/TestingSVN/Trunk/Fms' * Dumped revision 0. Revision 0 com*m iDtutmepde da sr e0v.isi n 1. Revision 1 committed as 1. * Dumped revision 2. Revision 2 committed a*s D2u.mpe revision 3. Revisio*n D3u mcpoemdm irtetveids iaosn 34.. Revision* 4D ucmopmemdi trteevdi saiso n4 .5. Revision 5 com*m iDtutmepde da sr e5v.isi n 6. Revision 6 commi*t tDeudm paesd 6r.evi ion 7. Revisio*n D7u mcpoemdm irtetveids iaosn 78.. Revision *8 Dcuommpmeidt treedv iassi o8n. 9. Revision 9* cDoummmpietdt erde vaiss i9o.n 1 . Revisi*o nD u1m0p ecdo mrmeivtitseido na s1 11.0 . Revision 11 *c oDmummiptetde dr eavsi s1i1o.n 1 . Revision 12 committed* aDsu m1p2e.d r vision 13. Revision 13 committ*e dD uamsp e1d3 .rev sion 14. Revision 14 commit*t eDdu mapse d1 4r.evi ion 15. Revision 15 committed as 15. * Dumped revision 16. Revision 16 committed as 16. Dropped 83 nodes: '/Branches' '/Branches/305' '/Branches/305/New Text Document.txt' '/Fms' '/Fms/ADPropertySheet.cpp'** etc. for 83 nodes... Also, the dump file itself is only 3 kb and contain no real data, only things like that (this is not the complete dump, just a sample) SVN-fs-dump-format-version: 2 UUID: 592fc9f0-5994-e841-a4dc-653714c95216 Revision-number: 0 Prop-content-length: 56 Content-length: 56 K 8 svn:date V 27 2009-06-19T15:05:52.001352Z PROPS-END Revision-number: 1 Prop-content-length: 112 Content-length: 112 K 7 svn:log V 38 This is an empty revision for padding. K 8 svn:date V 27 2009-06-19T15:11:29.378511Z PROPS-END Can anybody help me sort this out?

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• How to implement SCORM in Objective C

  - by iranjan

  Hey, Do you know how to implement SCORM (Sharable Content Object Reference Model) in Objective C for eLearning content? Let me explain you what exactly I am looking for. I have one MCQ (multiple choice question) application which has 4 questions. On attempting each question I want my application to interact with a SCORM compatible server with result (whether the user has attempted correct one or not). The communication channel should be to and fro. May be at the end of the MCQ I want to show result which will come from the server with some calculations*(like Score : 85% number of attempts : 16 average score:16.7% etc.)*. How should I go about it? Please guide if you have already achieved it regards Ranjan.

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• Error: Bad Base64Coder input character

  - by sebby_zml

  Hi, I am currently facing an error called "Bad Base64Coder input character at ..." Here is my code in java. String nonce2 = strNONCE; byte[] nonceBytes1 = Base64Coder.decode(nonce2); System.out.println("nonceByte1 value : " + nonceBytes1); The problem now is i get Bad Base64Coder input character error and the nonceBytes1 value is printed as null. I am trying to decode the nonce2 from Base64Coder. My strNONCE value is 16 byte[] nonce = new byte[16]; Random rand; rand = SecureRandom.getInstance ("SHA1PRNG"); rand.nextBytes(nonce); //convert byte array to string. strNONCE = new String(nonce); any help is deeply appreciated

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• DrScheme versus mzscheme: treatment of definitions

  - by speciousfool

  One long term project I have is working through all the exercises of SICP. I noticed something a bit odd with the most recent exercise. I am testing a Huffman encoding tree. When I execute the following code in DrScheme I get the expected result: (a d a b b c a) However, if I execute this same code in mzscheme by calling (load "2.67.scm") or by running mzscheme -f 2.67.scm, it reports: symbols: expected symbols as arguments, given: (leaf D 1) My question is: why? Is it because mzscheme and drscheme use different rules for loading program definitions? The program code is below. ;; Define an encoding tree and a sample message ;; Use the decode procedure to decode the message, and give the result. (define (make-leaf symbol weight) (list 'leaf symbol weight)) (define (leaf? object) (eq? (car object) 'leaf)) (define (symbol-leaf x) (cadr x)) (define (weight-leaf x) (caddr x)) (define (make-code-tree left right) (list left right (append (symbols left) (symbols right)) (+ (weight left) (weight right)))) (define (left-branch tree) (car tree)) (define (right-branch tree) (cadr tree)) (define (symbols tree) (if (leaf? tree) (list (symbol-leaf tree)) (caddr tree))) (define (weight tree) (if (leaf? tree) (weight-leaf tree) (cadddr tree))) (define (decode bits tree) (define (decode-1 bits current-branch) (if (null? bits) '() (let ((next-branch (choose-branch (car bits) current-branch))) (if (leaf? next-branch) (cons (symbol-leaf next-branch) (decode-1 (cdr bits) tree)) (decode-1 (cdr bits) next-branch))))) (decode-1 bits tree)) (define (choose-branch bit branch) (cond ((= bit 0) (left-branch branch)) ((= bit 1) (right-branch branch)) (else (error "bad bit -- CHOOSE-BRANCH" bit)))) (define (test s-exp) (display s-exp) (newline)) (define sample-tree (make-code-tree (make-leaf 'A 4) (make-code-tree (make-leaf 'B 2) (make-code-tree (make-leaf 'D 1) (make-leaf 'C 1))))) (define sample-message '(0 1 1 0 0 1 0 1 0 1 1 1 0)) (test (decode sample-message sample-tree))

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• Query for props list with or without values

  - by vitto

  Hi, I'm trying to make a SELECT on three relational tables like these ones: table_materials -> material_id - material_name table_props -> prop_id - prop_name table_materials_props - row_id -> material_id -> prop_id - prop_value On my page, I'd like to get a result like this one but i have some problem with the query: material prop A prop B prop C prop D prop E wood 350 NULL NULL 84 16 iron NULL 17 NULL NULL 201 copper 548 285 99 NULL NULL so the query should return something like: material prop_name prop_value wood prop A 350 wood prop B NULL wood prop C NULL wood prop D 84 wood prop E 16 // and go on with others rows i thought to use something like: SELECT * FROM table_materials AS m INNER JOIN table_materials_props AS mp ON m.material_id = mp.material_id INNER JOIN table_materials_props AS p ON mp.prop_id = p.prop_id ORDER BY p.prop_name the problem is the query doesn't return the NULL values, and I need the same prop order for all the materials regardless of prop values are NULL or not I hope this example is clear!

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• ASM programming, how to use loop?

  - by chris

  Hello. Im first time here.I am a college student. I've created a simple program by using assembly language. And im wondering if i can use loop method to run it almost samething as what it does below the program i posted. and im also eager to find someome who i can talk through MSN messanger so i can ask you questions right away.(if possible) ok thank you .MODEL small .STACK 400h .data prompt db 10,13,'Please enter a 3 digit number, example 100:',10,13,'$' ;10,13 cause to go to next line first_digit db 0d second_digit db 0d third_digit db 0d Not_prime db 10,13,'This number is not prime!',10,13,'$' prime db 10,13,'This number is prime!',10,13,'$' question db 10,13,'Do you want to contine Y/N $' counter dw 0d number dw 0d half dw ? .code Start: mov ax, @data ;establish access to the data segment mov ds, ax mov number, 0d LetsRoll: mov dx, offset prompt ; print the string (please enter a 3 digit...) mov ah, 9h int 21h ;execute ;read FIRST DIGIT mov ah, 1d ;bios code for read a keystroke int 21h ;call bios, it is understood that the ascii code will be returned in al mov first_digit, al ;may as well save a copy sub al, 30h ;Convert code to an actual integer cbw ;CONVERT BYTE TO WORD. This takes whatever number is in al and ;extends it to ax, doubling its size from 8 bits to 16 bits ;The first digit now occupies all of ax as an integer mov cx, 100d ;This is so we can calculate 100*1st digit +10*2nd digit + 3rd digit mul cx ;start to accumulate the 3 digit number in the variable imul cx ;it is understood that the other operand is ax ;AND that the result will use both dx::ax ;but we understand that dx will contain only leading zeros add number, ax ;save ;variable <number> now contains 1st digit * 10 ;---------------------------------------------------------------------- ;read SECOND DIGIT, multiply by 10 and add in mov ah, 1d ;bios code for read a keystroke int 21h ;call bios, it is understood that the ascii code will be returned in al mov second_digit, al ;may as well save a copy sub al, 30h ;Convert code to an actual integer cbw ;CONVERT BYTE TO WORD. This takes whatever number is in al and ;extends it to ax, boubling its size from 8 bits to 16 bits ;The first digit now occupies all of ax as an integer mov cx, 10d ;continue to accumulate the 3 digit number in the variable mul cx ;it is understood that the other operand is ax, containing first digit ;AND that the result will use both dx::ax ;but we understand that dx will contain only leading zeros. Ignore them add number, ax ;save -- nearly finished ;variable <number> now contains 1st digit * 100 + second digit * 10 ;---------------------------------------------------------------------- ;read THIRD DIGIT, add it in (no multiplication this time) mov ah, 1d ;bios code for read a keystroke int 21h ;call bios, it is understood that the ascii code will be returned in al mov third_digit, al ;may as well save a copy sub al, 30h ;Convert code to an actual integer cbw ;CONVERT BYTE TO WORD. This takes whatever number is in al and ;extends it to ax, boubling its size from 8 bits to 16 bits ;The first digit now occupies all of ax as an integer add number, ax ;Both my variable number and ax are 16 bits, so equal size mov ax, number ;copy contents of number to ax mov cx, 2h div cx ;Divide by cx mov half, ax ;copy the contents of ax to half mov cx, 2h; mov ax, number; ;copy numbers to ax xor dx, dx ;flush dx jmp prime_check ;jump to prime check print_question: mov dx, offset question ;print string (do you want to continue Y/N?) mov ah, 9h int 21h ;execute mov ah, 1h int 21h ;execute cmp al, 4eh ;compare je Exit ;jump to exit cmp al, 6eh ;compare je Exit ;jump to exit cmp al, 59h ;compare je Start ;jump to start cmp al, 79h ;compare je Start ;jump to start prime_check: div cx; ;Divide by cx cmp dx, 0h ;reset the value of dx je print_not_prime ;jump to not prime xor dx, dx; ;flush dx mov ax, number ;copy the contents of number to ax cmp cx, half ;compare half with cx je print_prime ;jump to print prime section inc cx; ;increment cx by one jmp prime_check ;repeat the prime check print_prime: mov dx, offset prime ;print string (this number is prime!) mov ah, 9h int 21h ;execute jmp print_question ;jumps to question (do you want to continue Y/N?) this is for repeat print_not_prime: mov dx, offset Not_prime ;print string (this number is not prime!) mov ah, 9h int 21h ;execute jmp print_question ;jumps to question (do you want to continue Y/N?) this is for repeat Exit: mov ah, 4ch int 21h ;execute exit END Start

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• I am getting an error when trying to use melt() on a dataframe containing Dates

  - by Dan

  I'd like to melt the dataframe so that in one column i have dates in a second i have username as the variable and finally the value. I'm getting this error: Error in as.Date.numeric(value) : 'origin' must be supplied and while I understand the error I'm not exactly sure how to get around it. A small sample of the data is: structure(list(created_at = structure(c(14007, 14008, 14009, 14010, 14011, 14012), class = "Date"), benjamin = c(16, 0, 0, 0, 0, 0), byron = c(0, 0, 0, 0, 0, 0), cameronc = c(0, 0, 0, 0, 0, 0), daniel = c(0, 0, 0, 0, 0, 0), djdiaz = c(0, 0, 0, 0, 0, 0), gene = c(16, 77, 64, 38, 72, 36), joel = c(0, 0, 0, 0, 0, 2), kerem = c(0, 0, 0, 0, 0, 0), sophia = c(0, 0, 0, 0, 0, 0), SuperMoonMan = c(0, 0, 0, 0, 0, 0)), .Names = c("created_at", "benjamin", "byron", "cameronc", "daniel", "djdiaz", "gene", "joel", "kerem", "sophia", "SuperMoonMan"), row.names = c(NA, 6L), class = c("cast_df", "data.frame")) Thanks for your help.

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• migrating from mysql to oracle9i.Equivalent create table syntax

  - by Android_Crazy

  Hi Following is the syntax for creating table in mysql. I want to create table with same properties in oracle9i. Can anyone provide me the equivalent syntax for oracle? CREATE TABLE IF NOT EXISTS "tbl_audit_trail" ( "id" int(11) unsigned NOT NULL, "old_value" text NOT NULL, "new_value" text NOT NULL, "action" varchar(20) CHARACTER SET latin1 NOT NULL, "model" varchar(255) CHARACTER SET latin1 NOT NULL, "field" varchar(64) CHARACTER SET latin1 NOT NULL, "stamp" timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP, "user_id" int(11) NOT NULL, "model_id" varchar(65) CHARACTER SET latin1 NOT NULL, PRIMARY KEY ("id"), KEY "idx_user_id" ("user_id"), KEY "idx_model_id" ("model_id"), KEY "idx_model" ("model"), KEY "idx_field" ("field"), KEY "idx_old_value" ("old_value"(16)), KEY "idx_new_value" ("new_value"(16)), KEY "idx_action" ("action") ) AUTO_INCREMENT=168 ;

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• What's wront in this iban validation code?

  - by Jackoder

  Hello coders, I'm working on a php iban validator but i have a problem I wrote like this: function IbanValidator($value) { $iban = false; $value= strtoupper(trim($value)); # Change US text into your country code if(preg_match('/^US\d{7}0[A-Z0-9]{16}$/', $value)) { $number= substr($value,4,22).'2927'.substr($value,2,2); $number= str_replace( array('A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z'), array(10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35), $number ); $iban = (1 == bcmod($number,97)) ? true; } return $iban; } Thanks. Funny Games

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• When I create PDF in PHP, how do I get the browser to render it correctly?

  - by pavun_cool

  I have used following code to create a simple PDF file. It executes fine in browsers, but I am not able to get the PDF file. It gives me some output when I am running the code in the CLI; my doubt is where I specify the PDF's filename. <?php require('fpdf.php'); $pdf=new FPDF(); $pdf->AddPage(); $pdf->SetFont('Arial','B',16); $pdf->Cell(40,10,'Hello World!'); $pdf->Output(); ?> CLI output: 2 0 obj << /Type /Page /Parent 1 0 R /Contents 3 0 R endobj 3 0 obj << /Length 4 0 R stream 2.834646 0 0 2.834646 0 841.9 cm 2 J 0.2 w BT /F1 5.64 Tf ET BT 11 -16.692 Td (Hello World!) Tj ET

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