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  • Loading var from PHP script using flash

    - by webnoob
    Hi All, I am trying to get a var from a PHP script running on my web server and from every forum post I have read, what I am doing should be working. I have the following: var lvContent = new LoadVars(); lvContent.load("http://{MY_DOMAIN}/Includes/getID.php"); trace("ID: " + lvContent.pageID); The problem is that ID in the trace is always undefined. I have tried the following in the php file: <?php echo "pageID=29"; ?> This is a small test to try and get it working but I cannot seem to. Am I doing something wrong? Thanks in advance for the help. I am using ActionScript 2.0

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  • What is the best way of retrieving a specific post in Wordpress?

    - by Steven
    I need to retrieve a specific post to display on my websites front page. To avoid hard coding the post ID, I've added a custom property where I add the post ID. The following code displays the wanted post: (The code is within the LOOP) // Get content from specific post (in this case, Åpningstider post)) $openingHoursID = get_post_meta($post->ID, "apningstider", true); if (!empty($openingHoursID)) { $openingHoursPost = get_post($openingHoursID); $openingHours = $openingHoursPost->post_content; } else $openingHours = "Åpningstid ikke angitt"; <div class="openinghours"><?php echo $openingHours; ?></div> Is there a better / easier way? The output is striped for HTML. How can I maintain HTML?

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  • Substring extraction using bash shell scripting and awk

    - by rohanbk
    So, I have a file called 'dummy' which contains the string: "There is 100% packet loss at node 1". I also have a small script that I want to use to grab the percentage from this file. The script is below. result=`grep 'packet loss' dummy` | awk '{ first=match($0,"[0-9]+%") last=match($0," packet loss") s=substr($0,first,last-first) print s}' echo $result I want the value of $result to basically be 100% in this case. But for some reason, it just prints out a blank string. Can anyone help me?

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  • Display data requested by an ajax.load() call once complete, not during the call.

    - by niczoom
    My jQuery code (using ajax) request's data from a php script (pgiproxy.php) using the following function: function grabPage($pageURL) { $homepage = file_get_contents($pageURL); echo $homepage; } I then extract the html code i need from the returned data using jQuery and insert it into a div called #BFX, as follows: $("#btnNewLoadMethod1").click(function(){ $('#temp1').load('pgiproxy.php', { data : $("#formdata").serialize(), mode : "graph"} , function() { $('#temp').html( $('#temp1').find('center').html() ); $('#BFX').html( $('#temp').html() ); }); }); This works fine. I get the html data (which is a gif image) i need displayed on screen in the correct div. The problem is i can see the html data loading into the div (dependant on network speed), but what I want is to insert the extracted html code into #BFX ONLY when the ajax request has fully completed.

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  • CakePHP - radio button not showing error message

    - by teepusink
    Hi, I'm unable to get the error message to show up when creating a radio form using the CakePHP form helper. This is what I have now. $options=array('active'=>'Active','inactive'=>'Inactive'); echo $form->input('Status', array( 'type' => 'radio', 'id' => 'EntryStatus', 'name' => 'data[Entry][status]', 'options' => $options )); What am I missing? I'm using CakePHP 1.2.7 and this is what I have in the validation 'status' = array( 'notempty' = array( 'rule' = 'notempty', 'required' = true, 'message' = 'yo' ) ) Tried the answer from http://stackoverflow.com/questions/1388823/form-helper-for-creating-radio-button-in-cakephp and it's giving me a select option form instead. Thanks, Tee

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  • PHP: How can I eliminate quotes around output from CSV file?

    - by brian johnson
    This code: <?php $curl=curl_init(); curl_setopt ($curl,CURLOPT_URL,"http://download.finance.yahoo.com/d/quotes.csv?s=XIN&f=l1c1p2rj1y&e=.csv"); curl_setopt ($curl,CURLOPT_HEADER,0); ob_start(); curl_exec ($curl); curl_close ($curl); $data=ob_get_clean(); $data = explode(",",$data); foreach ($data as $results) echo "<td>$results</td>"; ?> yields these results in my browser: 2.80 +0.02 "+0.72%" 1.85 204.2M 1.44 How can I have this PHP code above eliminate the quotations around the "+0.72%" so the end result is just: 0.72% ?

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  • Bash script function return value problem

    - by Eedoh
    Hi to all. Can anyone help me return the correct value from a bash script function? Here's my function that should return first (and only) line of the file passed as an argument: LOG_FILE_CREATION_TIME() { return_value=`awk 'NR==1' $1` return return_value } And here's my call of that function in the other script: LOG_FILE_CREATION_TIME "logfile" timestamp=$? echo "Timestamp = $timestamp" I always get some random values with this code. If, for example, there's a value of 62772031 in the "logfile", I get Timestamp = 255 as an output. For some other values in the file, I get other random values as a return value, never the correct one. Any ideas?

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  • What's the best way to format long strings of HTML in PHP?

    - by dclowd9901
    I know it's really a subjective question, but for best-practices (and readability), I can't seem to get a fix on the best way to format long strings of HTML. I typically do it like this: echo ' <div> <p>Content Inside</p> <div class="subbox"> <ul> <li>etc.</li> <li>etc.</li> <li>etc.</li> <li>etc.</li> </ul> </div> </div> '; But I still don't like the outcome, especially if this appears in the middle of a large block of code. It just feels messy.

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  • PHP, MVC, 404 - How can I redirect to 404?

    - by Doug
    I'm trying to build my own MVC as a practice and learning experience. So far, this is what I have: <?php require "config.php"; $page = $_GET['page']; if( isset( $page ) ) { echo "isset is true"; if( file_exists( MVCROOT . "/$page.php" ) ) { include "$page.php"; } else { header("HTTP/1.0 404 Not Found"); } } ?> My problem here is, I can't use header to send to a 404 because the headers have been send already. Should I just redirect to a 404.html or is there a better way? Feel free to critique what I have so far (it's very little). I would love suggestions and ideas. Thanks!

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  • How can I set the main theme-font dynamically, in WordPress

    - by windyjonas
    I have created a theme where I already have a custom options page where I let the user set text for footer, twitter user and some other things and that works well. Now i'd like to add the functionality of letting the user select which font that should be used for content on the site. How can i accomplish this? I can probably create a php file that outputs something like: <style type="text/css"> body{ font-family: <?php echo get_option('my-font');?>; } </style> and include that file in header.php, but that means that I have to hit php for every request for this css and I want to avoid that if posssible.

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  • Outputting an HTML entity character from a helper function

    - by morpheous
    I am using Symfony 1.3.2 on Ubuntu. I have written a little helper function (statsfoo) that prints out summary statistics about an item. I am using the helper function in my template like this: // In StatsHelper.php <?php function statsfoo($some_param) { return "<div class=\"sfoo\">&9830; the stats number for item is 42</div>" } //In showStatsSuccess.php <?php use_helper(Stats); <?php echo statsfoo($foobar, ESC_ENTITIES); I tried both ESC_ENTITIES and ESC_RAW. In both instances, the raw number (&9830) was displayed in the page. I want to display the diamond instead. What am I doing wrong and how can I fix this?

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  • Better explanation of $this-> in this example please

    - by Doug
    Referring to this question: http://stackoverflow.com/questions/2035449/why-is-oop-hard-for-me class Form { protected $inputs = array(); public function makeInput($type, $name) { echo '<input type="'.$type.'" name="'.$name.'">'; } public function addInput($type, $name) { $this->inputs[] = array("type" => $type, "name" => $name); } public function run() { foreach($this->inputs as $array) { $this->makeInput($array['type'], $array['name']; } } } $form = new form(); $this->addInput("text", "username"); $this->addInput("text", "password");** Can I get a better explanation of what the $this->input[] is doing in this part: public function addInput($type, $name) { $this->inputs[] = array("type" => $type, "name" => $name); }

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  • Get only new RSS entries with PHP Script ?

    - by ArneRie
    What im trying to do: Fetch X numbers of RSS Feeds from my Blogs and echo only new entries. My Problem is, how to know wich items are already parsed? Solution so far: Fetch the Feed every 5 hours, store all titles inside an Database table or flat file. Next run check if the title is already in database if not print it and save it inside the database. But iam not sure if this is best practise to do this? If someone knows a fast way, it would be great. Sorry for my poor english.

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  • Can't get Javac to work on Mac OS X

    - by elguapo-85
    I am trying to compile with javac on Snow Leopard through the command line. I have Xcode installed. I am just using a simple Hello World file, it works in Eclipse but I can't get it to work using javac. javac -version returns javac 1.6.0_17 HelloWorld.java public class HelloWorld { public static void main(String[] args) { String message = "Welcome to Java!"; System.out.println(message); } } I type: javac HelloWorld.java and get the following error. HelloWorld.java:1: class, interface, or enum expected public class HelloWorld ^ 1 error and... javac -cp . HelloWorld.java returns the same. echo $CLASSPATH just returns blank. Thanks for the help.

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  • Mysql Date formats and url query

    - by jasmine
    I want to make a url query with date. I have confused a little : There is a mysql table: calDate : varchar The query : $sql="select * from calTbl"; $result = mysql_query($sql); while ($row = mysql_fetch_array($result)) { $n = str_replace("/", "",$row['calDate']); echo '<a href="index.php?p='.$n.'">'.$n.'</a>'; } I want to see related event from query. Can I set apart month, day and year from this? Or what is the correct table design here? Thanks in advance

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  • Bash Scripting: I want to open a set of .php files, and add line before html tag

    - by Bashn00b
    Hi guys, I have a set of .php files in a folder, I want to add text just before these lines: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en" > What i want is to insert just before these lines in the html file. So just want to prepend that file before each docType declaration. However the DOCTYPE declaration is never on line 1, as there is loads of php lines before. I have this current script (where FE is the folder containing all the scripts i want to edit): for file in ${fe}*; do echo "$file" done Thanks,

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  • Troubles with DateTime and PHP 5.2

    - by Nate Wagar
    I'm attempting to use the PHP DateTime class on a server with PHP 5.2.6, with a test server running PHP 5.3. Here is the code: <?php try { $dt = new DateTime('2009-10-08'); $dt->setDate(2009,10,8); print_r($dt); }catch (Exception $e) { echo $e->getMessage(); } On the test server, things work flawlessly, this is what prints: DateTime Object ( [date] => 2009-10-08 00:00:00 [timezone_type] => 3 [timezone] => America/New_York ) On the server I need to use it on, however, this is what prints: DateTime Object ( ) Removing the setDate makes no difference whatsoever. Any ideas why this might be happening? Thanks!

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  • PHP and Apache environment variables

    - by Simon
    Hello, I want to pass an environment variable in linux to apache on start up. export MYVAR=5 --I define my environment variable on the command line PassEnv MYVAR --set apache to import the variable in apache config file apachectl restart --when I restart apache I don't get an error message. However I have noticed that if I do not create the environment variable in my first step, I get a warning message, so must be working here echo $_SERVER['MYVAR'] --i try to access the environment variable within PHP but it is not defined I've observed that if I try to PassEnv an environment variable that already exits (one that I havn't created myself) it works fine. The SetEnv directive also works fine. I'd really like to pass an environment variable to apache on the fly without writing it in a file. Help much appreciated. I'm using CentOS, PHP5 and Apache2. Thanks.

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  • jQuery wait for ajax call to be over before continuing

    - by Flo
    Hi all, I have a problem with a jQuery ajax call. I need to wait for the call to be finished in order to return a value. However, the script seems to jump ahead and not wait for the call to be over. my function then returns "undefined". I have tried to use the .ajax() method and set the value of async to false, but this would not work either. I could I get my function to return the value that I could through the ajax call? Thank you! Here is the code: function get_rsrce_name(){ jQuery.post( '<?php echo admin_url( 'admin-ajax.php' ); ?>', { action :'my_action', option_rsrce : 'option_rsrce' }, function( data ) { output = data.option_name; }, "json" ); return output; }

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  • How to make a form using ajax, onchange event, reload to SAME page

    - by user1348220
    I've been studying this for a while and I'm not sure if I'm going about this the right way because every form I setup according to examples, it doesn't do what I need. I need to setup a form that will: set session when you select from dropdown menu not reload/refresh page (i've read that using AJAX solves this) submit and stay on SAME page (confused because most AJAX examples send it to different process.php page which is supposedly "invisible" but it doesn't "stay" on the same page, it redirects. Basically, client selects quantity of 1 to 10. If they select "2"... it does NOT reload the page.. but it DOES set a session[quantity]=2. Should be simple... but do I POST to same page as form? or POST to different page and it somehow redirects? Also, one test I did it kept pasting my "echo session[quantity]" down the page like 7, 2, 3, 5, etc. etc. each time instead of replacing it. I would paste code but it's all over the place and I'm hoping for direction on which methods to use. Feel I need to start all over again. Edit: trying to add code below but can't seem to paste it properly. <? ob_start();?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <?php session_start(); ?> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Submit Form with out refreshing page Tutorial</title> <!-- JavaScript --> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.0/jquery.min.js"></script> <script type="text/javascript" > $(function() { $(".submit").click(function() { var gender = $("#gender").val(); var dataString = '&gender=' + gender; if(gender=='') { $('.success').fadeOut(200).hide(); $('.error').fadeOut(200).show(); } else { $.ajax({ type: "POST", url: "join.php", data: dataString, success: function(){ $('.success').fadeIn(200).show(); $('.error').fadeOut(200).hide(); } }); } return false; }); }); </script> <style type="text/css"> body{ } .error{ color:#d12f19; font-size:12px; } .success{ color:#006600; font-size:12px; } </style> </head> <body id="public"> <div style="height:30px"></div> <div id="container"> <div style="height:30px"></div> <form method="post" name="form"> <select id="gender" name="gender"> <option value="">Gender</option> <option value="male">Male</option> <option value="female">Female</option> </select> <div> <input type="submit" value="Submit" class="submit"/> <span class="error" style="display:none"> Please Enter Valid Data</span> <span class="success" style="display:none"> Your gender is <?php echo $_SESSION['gender'];?></span> </div> </form> <div style="height:20px"></div> </div><!--container--> </body> </html> <? ob_flush(); ?> and here is my page where the POST goes called join.php (called that in example so I went with it for now) <?php session_start(); if($_POST) { $gender = $_POST['gender']; $_SESSION['gender'] = $gender; } else { } ?>

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  • How do I move Zend Framework From Development to Production?

    - by dirtylogic
    I'm just wondering if anyone else has had problems moving the Zend Framework from development to production. I changed my docroot to the public folder, updated my library path, but it's still not working out for me. The IndexController is working just fine, but my ServiceController is giving me an internal server error. ServiceController <?php class ServiceController extends Zend_Controller_Action { public function amfAction() { require_once APPLICATION_PATH . '/models/MyClass.php'; $srv = new Zend_Amf_Server(); $srv->setClass('Model_MyClass', 'MyClass'); echo $srv->handle(); exit; } }

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  • How do I rewrite binary data in Java

    - by hayato
    I'm trying to figure out how to replace binary data using Java. below is a PHP example of replacing "foo" to "bar" from a swf file. <?php $fp = fopen("binary.swf","rb"); $size = filesize("binary.swf"); $search = bin2hex("foo"); $replace = bin2hex("bar"); $data = fread($fp, $size); $data16 = bin2hex($data); $data16 = str_replace($search, $replace, $data16); $data = pack('H*',$data16); header("Content-Type:application/x-shockwave-flash"); echo $data; ?> How do I do this in Java.

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  • How to build unlimited level of menu through PHP and mysql

    - by Starx
    Well, to build my menu my menu I use a db similar structure like this To assign another submenu for existing submenu I simply assign its parent's id as its value of parent field. parent 0 means top menu now there is not problem while creating submenu inside another submenu now this is way I fetch the submenu for the top menu <ul class="topmenu"> <? $list = $obj -> childmenu($parentid); //this list contains the array of submenu under $parendid foreach($list as $menu) { extract($menu); echo '<li><a href="#">'.$name.'</a></li>'; } ?> </ul> What I want to do is. I want to check if a new menu has other child menu and I want to keep on checking until it searches every child menu that is available and I want to display its child menu inside its particular list item like this Home ........

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  • Populate FILE field with default text

    - by dclowd9901
    I'm trying to reutilize code that generates FILE fields for use when something is to be added to the database, and grayed out (and disabled) with data already in the database when the item in question is being edited or viewed in detail. However, I can't seem to get the text to fill the field. I'm using this: echo '<input type="file" name="small[]" value="' . $value_from_database . '" DISABLED><br>'; Am I missing anything? If not, are there any decent workarounds?

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  • php with two class

    - by lolalola
    Hi Guys, my sample is good or not? I have a good connection to the database, or too should be in the class? Thanks <?php mysql_connect('localhost','root','admin'); mysql_select_db('test'); class UserDisplay { function getDisplayName() { $sql = 'select first_name, last_name, display_name from users where user_id = "3"'; $results = mysql_query($sql); $row = mysql_fetch_array($results); $this->user_id = $user_id; return $this->user_id; } } class UserInsert function InsertName($name) { mysql_query("INSERT INTO Persons (first_name)VALUES ('".$name."')"); } } $userD = new UserDisplay(); echo "User known as: " . $userD->getDisplayName() . "\n"; $userI = new UserInsert(); $userI->InsertName("Peter"); ?>

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