Search Results

Search found 33940 results on 1358 pages for 'line numbers'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 190/1358 | < Previous Page | 186 187 188 189 190 191 192 193 194 195 196 197  | Next Page >

  • How do I find everything between two characters after a word using grep, without outputting the entire line?

    - by Nick Sweeting
    I am downlading the info.0.json file from xkcd and trying to parse just the alt text. I don't care if there are quotes around it or not. The problem it that the info.0.json file is all one line, and the alt text is in quotes after the word "alt=". Trying cat info.0.json | grep alt just returns the whole file (because it's all one line). What is the grep or sed code that will get me the alt text?

    Read the article

  • How do i render and detect a line of sight?

    - by acidzombie24
    If you look at the top right you'll see on a radar an enemy unit line of sight. I was wondering what is the most efficient or easiest way (little code, fairly accurate. doesnt need to be perfect) to detect if something is in your line of sight? I may or may not need to render it (i likely wont). I dont know the formula nor used any math libs/namespaces in C#

    Read the article

  • How to paste in a new line with vim?

    - by static_rtti
    I often have to paste some stuff on a new line in vim. What I usually do is: o<Esc>p Which inserts a new line and puts me in insertion mode, than quits insertion mode, and finally pastes. Three keystrokes. Not very efficient. Any better ideas?

    Read the article

  • How to use an excel data-set for a multi-line ggplot in R?

    - by user1299887
    I have a data set in excel that I am trying to create a multiple line plot with on R. The data set contains 7 food groups and the calories consumed daily associated to the groups. As well, there is that set of data over 38 years (from 1970-2008) and I am attempting to use this data set to create a multiple line plot on R. I have tried for hours on end but can not seem to get R to recognize the variables within the data set.

    Read the article

  • How to delete just one LINE of text (NOT a table-row!) with a single KEYBOARD shortcut in Microsoft Office Word 2010?

    - by Sk8erPeter
    Are there any shortcuts to delete just one row (which is NOT a table row, just a single row in a text) in Microsoft Office Word 2010? If not, how can I assign one to do it? In worst case, can I make a macro (in VB) which could do the same with a custom shortcut? To clarify my problem: I would like to avoid multiple clicks and/or pushing multiple buttons, even if I click in the middle of the line of text. :) For example, in Notepad++ I can delete the entire current line with Ctrl+L, in NetBeans, I can delete an entire line with Ctrl+E, in Eclipse, I can delete current line with Ctrl+D, etc., where it doesn't really matter where my mouse cursor is actually... so there are these simple solutions, which I look for in Word too. It really would simplify my work in huge documents.

    Read the article

  • How to make a increasing numbers after filenames in C?

    - by zaplec
    Hi, I have a little problem. I need to do some little operations on quite many files in one little program. So far I have decided to operate them in a single loop where I just change the number after the name. The files are all named TFxx.txt where xx is increasing number from 1 to 80. So how can I open them all in a single loop one after one? I have tried this: for(i=0; i<=80; i++) { char name[8] = "TF"+i+".txt"; FILE = open(name, r); /* Do something */ } As you can see the second line would be working in python but not in C. I have tried to do similiar running numbering with C to this program, but I haven't found out yet how to do that. The format doesn't need to be as it is on the second line, but I'd like to have some advice of how can I solve this problem. All I need to do is just be able to open many files and do same operations to them.

    Read the article

  • Disk Search / Sort Algorithm

    - by AlgoMan
    Given a Range of numbers say 1 to 10,000, Input is in random order. Constraint: At any point only 1000 numbers can be loaded to memory. Assumption: Assuming unique numbers. I propose the following efficient , "When-Required-sort Algorithm". We write the numbers into files which are designated to hold particular range of numbers. For example, File1 will have 0 - 999 , File2 will have 1000 - 1999 and so on in random order. If a particular number which is say "2535" is being searched for then we know that the number is in the file3 (Binary search over range to find the file). Then file3 is loaded to memory and sorted using say Quick sort (which is optimized to add insertion sort when the array size is small ) and then we search the number in this sorted array using Binary search. And when search is done we write back the sorted file. So in long run all the numbers will be sorted. Please comment on this proposal.

    Read the article

  • Find valid assignments of integers in arrays (permutations with given order)

    - by evident
    Hi everybody! I am having a general problem finding a good algorithm for generating each possible assignment for some integers in different arrays. Lets say I have n arrays and m numbers (I can have more arrays than numbers, more numbers than arrays or as much arrays as numbers). As an example I have the numbers 1,2,3 and three arrays: { }, { }, { } Now I would like to find each of these solutions: {1,2,3}, { }, { } { }, {1,2,3}, { } { }, { }, {1,2,3} {1,2}, {3}, { } {1,2}, { }, {3} { }, {1,2}, {3} {1}, {2,3}, { } {1}, { }, {2,3} { }, {1}, {2,3} {1}, {2}, {3} So basically I would like to find each possible combination to assign the numbers to the different arrays with keeping the order. So as in the example the 1 always needs to come before the others and so on... I want to write an algorithm in C++/Qt to find all these valid combinations. Does anybody have an approach for me on how to handle this problem? How would I generate these permutations?

    Read the article

  • Distinct rand() sequences yielding the same results in an expression

    - by suszterpatt
    Ok, this is a really weird one. I have an MPI program, where each process has to generate random numbers in a fixed range (the range is read from file). What happens is that even though I seed each process with a different value, and the numbers generated by rand() are different in each process, the expression to generate the random numbers still yields the same sequence between them. Here's all relevant code: // 'rank' will be unique for each process int rank; MPI_Comm_rank(MPI_COMM_WORLD, &rank); // seed the RNG with a different value for each process srand(time(NULL) + rank); // print some random numbers to see if we get a unique sequence in each process // 'log' is a uniquely named file, each process has its own log << rand() << " " << rand() << " " << rand() << std::endl; // do boring deterministic stuff while (true) { // waitTimeMin and waitTimeMax are integers, Max is always greater than Min waitSecs = waitTimeMin + rand() % (waitTimeMax - waitTimeMin); log << "waiting " << waitSecs << " seconds" << std::endl; sleep(waitSecs); // do more boring deterministic stuff } Here's the output of each process, with 3 processes generating numbers in the range [1,9]. process 1: 15190 28284 3149 waiting 6 seconds waiting 8 seconds waiting 9 seconds waiting 4 seconds process 2: 286 6264 3153 waiting 6 seconds waiting 8 seconds waiting 9 seconds waiting 4 seconds process 3: 18151 17013 3156 waiting 6 seconds waiting 8 seconds waiting 9 seconds waiting 4 seconds So while rand() clearly generates different numbers, the expression to calculate waitSecs still evaluates to the same sequence on all processes. What's even weirder: if I run the program with the same parameteres again, only the first 3 random numbers will change, the rest of the "random" sequence will be exactly the same in each run! Changing the range of numbers will obviously produce a different result from this one, but the same parameters always yield the same sequence, between processes and between executions: except for the first 3 numbers. Just what the hell is going on here?

    Read the article

  • Randomised objects are assigning themselves to more than one array location

    - by Thaddeus Aid
    this.size = 9; this.populationSize = 10; Random rand = new Random(); Integer[][] easy1 = new Integer[size][size]; easy1 = this.initializeEasy1(easy1); this.sudokuArray = new Sudoku[this.populationSize]; for (int i = 0; i < this.sudokuArray.length; i++){ long seed = rand.nextLong(); System.out.println("" + seed); this.sudokuArray[i] = new Sudoku(easy1, this.size, seed); } I am building an evolutionary sudoku solver and I am having a problem where the last Sudoku object is overwriting all the other objects in the array. Where in the code did I mess up? /edit here is the constructor of the class public Sudoku(Integer[][] givensGrid, int s, long seed){ this.size = s; this.givens = givensGrid; this.grid = this.givens.clone(); Random rand = new Random(seed); System.out.println("Random " + rand.nextInt()); // step though each row of the grid for (int i = 0; i < size; i++){ ArrayList<Integer> numbers = new ArrayList<Integer>(); numbers = this.makeNumbers(numbers); // step through each column to find the givens and remove from numbers for (int j = 0; j < size; j++){ if (this.grid[i][j] != 0){ numbers.remove(this.grid[i][j]); } } // go back through the row and assign the numbers randomly for (int j = 0; j < size; j++){ if (this.grid[i][j] == 0){ int r = rand.nextInt(numbers.size()); this.grid[i][j] = numbers.get(r); numbers.remove(r); } } } System.out.println("============="); System.out.println(this.toString()); }

    Read the article

  • input / output error, drives randomly refusing to read / write

    - by ILMV
    I have an issue with one of our servers running Ubuntu 10.04, it is running BackupPC and collects backups from various machines / servers around the building. On the 8th minute (12:08, 12:18, 12:28 etc) the backups are transferred to an external hard drive, we have three and rotate one drive for another everyday. The problem we are having is we are randomly experiencing input / output errors, when this happens you cannot read / write to the drive, it hasn't unmounted so I can cd to the mount point /media/backup1. The drives are not faulty as it's happening on all of them, so I'm at a loss as to what the problem could be, here is an example of the many errors we get: gzip: stdout: Input/output error /var/lib/backuppc/backuppc_offline: line 47: /media/backup1/Tue/offline.log: Input/output error ls: cannot access /media/backup1/Tue/incr_1083_host1.something.co.uk.tar.gz: Input/output error ls: cannot access /media/backup1/Tue/incr_1088_host1.something.co.uk.tar.gz: Input/output error ls: cannot access /media/backup1/Tue/incr_1089_host1.something.co.uk.tar.gz: Input/output error ls: cannot access /media/backup1/Tue/incr_1090_host1.something.co.uk.tar.gz: Input/output error /var/lib/backuppc/backuppc_offline: line 39: /media/backup1/Tue/offline.log: Input/output error /var/lib/backuppc/backuppc_offline: line 44: /media/backup1/Tue/offline.log: Input/output error /var/lib/backuppc/backuppc_offline: line 45: /media/backup1/Tue/incr_1090_host1.something.co.uk.tar.gz: Input/output error /var/lib/backuppc/backuppc_offline: line 47: /media/backup1/Tue/offline.log: Input/output error ls: cannot access /media/backup1/Tue/incr_591_tech2.something.co.uk.tar.gz: Input/output error /var/lib/backuppc/backuppc_offline: line 44: /media/backup1/Tue/offline.log: Input/output error /var/lib/backuppc/backuppc_offline: line 45: /media/backup1/Tue/incr_591_tech2.something.co.uk.tar.gz: Input/output error /var/lib/backuppc/backuppc_offline: line 47: /media/backup1/Tue/offline.log: Input/output error ls: cannot access /media/backup1/Tue/incr_592_tech3.something.co.uk.tar.gz: Input/output error ls: cannot access /media/backup1/Tue/incr_593_tech3.something.co.uk.tar.gz: Input/output error /var/lib/backuppc/backuppc_offline: line 44: /media/backup1/Tue/offline.log: Input/output error /var/lib/backuppc/backuppc_offline: line 45: /media/backup1/Tue/incr_593_tech3.something.co.uk.tar.gz: Input/output error /var/lib/backuppc/backuppc_offline: line 47: /media/backup1/Tue/offline.log: Input/output error EDIT » Resolved So it turns out Quamis was right, even though I didn't think it was possible it was actually a problem with the drive. You see we have three drives all formatted to ext2, on two of them we were getting I/O errors frequently, I cam back to Quamis' answer and discovered the fsck command, so ran it against the problems drives: fsck /dev/sdb1 This found and fixed a load of problems on the drive, most probably caused by power outages / unsafe removal of drives etc, as the drives are in the xt2 format they aren't journalled and thus aren't protected against such issues. Drives are now working beautifully, thanks all! :D

    Read the article

  • OSError : [Errno 38] Function not implemented - Django Celery implementation

    - by Jordan Messina
    I installed django-celery and I tried to start up the worker server but I get an OSError that a function isn't implemented. I'm running CentOS release 5.4 (Final) on a VPS: . broker -> amqp://guest@localhost:5672/ . queues -> . celery -> exchange:celery (direct) binding:celery . concurrency -> 4 . loader -> djcelery.loaders.DjangoLoader . logfile -> [stderr]@WARNING . events -> OFF . beat -> OFF [2010-07-22 17:10:01,364: WARNING/MainProcess] Traceback (most recent call last): [2010-07-22 17:10:01,364: WARNING/MainProcess] File "manage.py", line 11, in <module> [2010-07-22 17:10:01,364: WARNING/MainProcess] execute_manager(settings) [2010-07-22 17:10:01,364: WARNING/MainProcess] File "/usr/local/lib/python2.6/site-packages/django/core/management/__init__.py", line 438, in execute_manager [2010-07-22 17:10:01,364: WARNING/MainProcess] utility.execute() [2010-07-22 17:10:01,364: WARNING/MainProcess] File "/usr/local/lib/python2.6/site-packages/django/core/management/__init__.py", line 379, in execute [2010-07-22 17:10:01,365: WARNING/MainProcess] self.fetch_command(subcommand).run_from_argv(self.argv) [2010-07-22 17:10:01,365: WARNING/MainProcess] File "/usr/local/lib/python2.6/site-packages/django/core/management/base.py", line 191, in run_from_argv [2010-07-22 17:10:01,365: WARNING/MainProcess] self.execute(*args, **options.__dict__) [2010-07-22 17:10:01,365: WARNING/MainProcess] File "/usr/local/lib/python2.6/site-packages/django/core/management/base.py", line 218, in execute [2010-07-22 17:10:01,365: WARNING/MainProcess] output = self.handle(*args, **options) [2010-07-22 17:10:01,365: WARNING/MainProcess] File "/usr/local/lib/python2.6/site-packages/django_celery-2.0.0-py2.6.egg/djcelery/management/commands/celeryd.py", line 22, in handle [2010-07-22 17:10:01,366: WARNING/MainProcess] run_worker(**options) [2010-07-22 17:10:01,366: WARNING/MainProcess] File "/usr/local/lib/python2.6/site-packages/celery-2.0.1-py2.6.egg/celery/bin/celeryd.py", line 385, in run_worker [2010-07-22 17:10:01,366: WARNING/MainProcess] return Worker(**options).run() [2010-07-22 17:10:01,366: WARNING/MainProcess] File "/usr/local/lib/python2.6/site-packages/celery-2.0.1-py2.6.egg/celery/bin/celeryd.py", line 218, in run [2010-07-22 17:10:01,366: WARNING/MainProcess] self.run_worker() [2010-07-22 17:10:01,366: WARNING/MainProcess] File "/usr/local/lib/python2.6/site-packages/celery-2.0.1-py2.6.egg/celery/bin/celeryd.py", line 312, in run_worker [2010-07-22 17:10:01,367: WARNING/MainProcess] worker.start() [2010-07-22 17:10:01,367: WARNING/MainProcess] File "/usr/local/lib/python2.6/site-packages/celery-2.0.1-py2.6.egg/celery/worker/__init__.py", line 206, in start [2010-07-22 17:10:01,367: WARNING/MainProcess] component.start() [2010-07-22 17:10:01,367: WARNING/MainProcess] File "/usr/local/lib/python2.6/site-packages/celery-2.0.1-py2.6.egg/celery/concurrency/processes/__init__.py", line 54, in start [2010-07-22 17:10:01,367: WARNING/MainProcess] maxtasksperchild=self.maxtasksperchild) [2010-07-22 17:10:01,367: WARNING/MainProcess] File "/usr/local/lib/python2.6/site-packages/celery-2.0.1-py2.6.egg/celery/concurrency/processes/pool.py", line 448, in __init__ [2010-07-22 17:10:01,368: WARNING/MainProcess] self._setup_queues() [2010-07-22 17:10:01,368: WARNING/MainProcess] File "/usr/local/lib/python2.6/site-packages/celery-2.0.1-py2.6.egg/celery/concurrency/processes/pool.py", line 564, in _setup_queues [2010-07-22 17:10:01,368: WARNING/MainProcess] self._inqueue = SimpleQueue() [2010-07-22 17:10:01,368: WARNING/MainProcess] File "/usr/local/lib/python2.6/multiprocessing/queues.py", line 315, in __init__ [2010-07-22 17:10:01,368: WARNING/MainProcess] self._rlock = Lock() [2010-07-22 17:10:01,368: WARNING/MainProcess] File "/usr/local/lib/python2.6/multiprocessing/synchronize.py", line 117, in __init__ [2010-07-22 17:10:01,369: WARNING/MainProcess] SemLock.__init__(self, SEMAPHORE, 1, 1) [2010-07-22 17:10:01,369: WARNING/MainProcess] File "/usr/local/lib/python2.6/multiprocessing/synchronize.py", line 49, in __init__ [2010-07-22 17:10:01,369: WARNING/MainProcess] sl = self._semlock = _multiprocessing.SemLock(kind, value, maxvalue) [2010-07-22 17:10:01,369: WARNING/MainProcess] OSError [2010-07-22 17:10:01,369: WARNING/MainProcess] : [2010-07-22 17:10:01,369: WARNING/MainProcess] [Errno 38] Function not implemented Am I just totally screwed and should use a new kernel that has this implemented or is there an easy way to resolve this?

    Read the article

  • How to insert a blank line above my copyright text inside the comment lines in intelliJ IDEA?

    - by tim_wonil
    I'm using intelliJ IDEA 9. It has a function to make a copyright profile and apply to all files I create. What I'm trying to do is to format the copyright comment right. Suppose I have a copyright text as this: Copyright (c) 2010 my.company. All rights reserved. I wish it to be inserted in files automatically as following: //////////////////////////////////////////////////////////////////////////////// // // Copyright (c) 2010 my.company. All rights reserved. // //////////////////////////////////////////////////////////////////////////////// But when I enter the line "Copyright (c) 2010 my.company. All rights reserved." in the copyright profile (without quotes) and configure the formatting to use line comment and borders, and so on, I can only make it to display as below: //////////////////////////////////////////////////////////////////////////////// // Copyright (c) 2010 my.company. All rights reserved. //////////////////////////////////////////////////////////////////////////////// Even when I put the copyright text with blank line above and below to the template, as following, it still comes out like above. Copyright (c) 2010 my.company. All rights reserved. It seems to ignore blank lines in the copyright template. Is there any way to configure it so the copyright text will have blank lines above and below within the comments?

    Read the article

  • Django 1.4.1 error loading MySQLdb module when attempting 'python manage.py shell'

    - by Paul
    I am trying to set up MySQL, and can't seem to be able to enter the Django manage.py shell interpreter. Getting the output below: rrdhcp-10-32-44-126:django pavelfage$ python manage.py shell Traceback (most recent call last): File "manage.py", line 10, in <module> execute_from_command_line(sys.argv) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/__init__.py", line 443, in execute_from_command_line utility.execute() File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/__init__.py", line 382, in execute self.fetch_command(subcommand).run_from_argv(self.argv) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/base.py", line 196, in run_from_argv self.execute(*args, **options.__dict__) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/base.py", line 232, in execute output = self.handle(*args, **options) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/base.py", line 371, in handle return self.handle_noargs(**options) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/commands/shell.py", line 45, in handle_noargs from django.db.models.loading import get_models File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/db/__init__.py", line 40, in <module> backend = load_backend(connection.settings_dict['ENGINE']) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/db/__init__.py", line 34, in __getattr__ return getattr(connections[DEFAULT_DB_ALIAS], item) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/db/utils.py", line 92, in __getitem__ backend = load_backend(db['ENGINE']) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/db/utils.py", line 24, in load_backend return import_module('.base', backend_name) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/utils/importlib.py", line 35, in import_module __import__(name) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/db/backends/mysql/base.py", line 16, in <module> raise ImproperlyConfigured("Error loading MySQLdb module: %s" % e) django.core.exceptions.ImproperlyConfigured: Error loading MySQLdb module: No module named _mysql Any suggestions really appreciated.

    Read the article

  • "import numpy" tries to load my own package

    - by Sebastian
    I have a python (2.7) project containing my own packages util and operator (and so forth). I read about relative imports, but perhaps I didn't understand. I have the following directory structure: top-dir/ util/__init__.py (empty) util/ua.py util/ub.py operator/__init__.py ... test/test1.py The test1.py file contains #!/usr/bin/env python2 from __future__ import absolute_import # removing this line dosn't change anything. It's default functionality in python2.7 I guess import numpy as np It's fine when I execute test1.py inside the test/ folder. But when I move to the top-dir/ the import numpy wants to include my own util package: Traceback (most recent call last): File "tests/laplace_2d_square.py", line 4, in <module> import numpy as np File "/usr/lib/python2.7/site-packages/numpy/__init__.py", line 137, in <module> import add_newdocs File "/usr/lib/python2.7/site-packages/numpy/add_newdocs.py", line 9, in <module> from numpy.lib import add_newdoc File "/usr/lib/python2.7/site-packages/numpy/lib/__init__.py", line 4, in <module> from type_check import * File "/usr/lib/python2.7/site-packages/numpy/lib/type_check.py", line 8, in <module> import numpy.core.numeric as _nx File "/usr/lib/python2.7/site-packages/numpy/core/__init__.py", line 45, in <module> from numpy.testing import Tester File "/usr/lib/python2.7/site-packages/numpy/testing/__init__.py", line 8, in <module> from unittest import TestCase File "/usr/lib/python2.7/unittest/__init__.py", line 58, in <module> from .result import TestResult File "/usr/lib/python2.7/unittest/result.py", line 9, in <module> from . import util File "/usr/lib/python2.7/unittest/util.py", line 2, in <module> from collections import namedtuple, OrderedDict File "/usr/lib/python2.7/collections.py", line 9, in <module> from operator import itemgetter as _itemgetter, eq as _eq ImportError: cannot import name itemgetter The troublesome line is either from . import util or perhaps from operator import itemgetter as _itemgetter, eq as _eq What can I do?

    Read the article

  • How to Set Customer Table with Multiple Phone Numbers? - Relational Database Design

    - by user311509
    CREATE TABLE Phone ( phoneID - PK . . . ); CREATE TABLE PhoneDetail ( phoneDetailID - PK phoneID - FK points to Phone phoneTypeID ... phoneNumber ... . . . ); CREATE TABLE Customer ( customerID - PK firstName phoneID - Unique FK points to Phone . . . ); A customer can have multiple phone numbers e.g. Cell, Work, etc. phoneID in Customer table is unique and points to PhoneID in Phone table. If customer record is deleted, phoneID in Phone table should also be deleted. Do you have any concerns on my design? Is this designed properly? My problem is phoneID in Customer table is a child and if child record is deleted then i can not delete the parent (Phone) record automatically.

    Read the article

  • Does this use of Monitor.Wait/Pulse have a race condition?

    - by jw
    I have a simple producer/consumer scenario, where there is only ever a single item being produced/consumed. Also, the producer waits for the worker thread to finish before continuing. I realize that kind of obviates the whole point of multithreading, but please just assume it really needs to be this way (: This code doesn't compile, but I hope you get the idea: // m_data is initially null // This could be called by any number of producer threads simultaneously void SetData(object foo) { lock(x) // Line A { assert(m_data == null); m_data = foo; Monitor.Pulse(x) // Line B while(m_data != null) Monitor.Wait(x) // Line C } } // This is only ever called by a single worker thread void UseData() { lock(x) // Line D { while(m_data == null) Monitor.Wait(x) // Line E // here, do something with m_data m_data = null; Monitor.Pulse(x) // Line F } } Here is the situation that I am not sure about: Suppose many threads call SetData() with different inputs. Only one of them will get inside the lock, and the rest will be blocked on Line A. Suppose the one that got inside the lock sets m_data and makes its way to Line C. Question: Could the Wait() on Line C allow another thread at Line A to obtain the lock and overwrite m_data before the worker thread even gets to it? Supposing that doesn't happen, and the worker thread processes the original m_data, and eventually makes its way to Line F, what happens when that Pulse() goes off? Will only the thread waiting on Line C be able to get the lock? Or will it be competing with all the other threads waiting on Line A as well? Essentially, I want to know if Pulse()/Wait() communicate with each other specially "under the hood" or if they are on the same level with lock(). The solution to these problems, if they exist, is obvious of course - just surround SetData() with another lock - say, lock(y). I'm just curious if it's even an issue to begin with.

    Read the article

  • Trying to build the basic python extension example fails (windows)

    - by Alexandros
    Hello, I have Python 2.6 and Visual Studio 2008 running on a Win7 x64 machine. When I try to build the basic python extension example in c "example_nt" as found in the python 2.6 sources distribution, it fails: python setup.py build And this results in: running build running build_ext building 'aspell' extension Traceback (most recent call last): File "setup.py", line 7, in <module> ext_modules = [module1]) File "C:\Python26\lib\distutils\core.py", line 152, in setup dist.run_commands() File "C:\Python26\lib\distutils\dist.py", line 975, in run_commands self.run_command(cmd) File "C:\Python26\lib\distutils\dist.py", line 995, in run_command cmd_obj.run() File "C:\Python26\lib\distutils\command\build.py", line 134, in run self.run_command(cmd_name) File "C:\Python26\lib\distutils\cmd.py", line 333, in run_command self.distribution.run_command(command) File "C:\Python26\lib\distutils\dist.py", line 995, in run_command cmd_obj.run() File "C:\Python26\lib\distutils\command\build_ext.py", line 343, in run self.build_extensions() File "C:\Python26\lib\distutils\command\build_ext.py", line 469, in build_extensions self.build_extension(ext) File "C:\Python26\lib\distutils\command\build_ext.py", line 534, in build_extension depends=ext.depends) File "C:\Python26\lib\distutils\msvc9compiler.py", line 448, in compile self.initialize() File "C:\Python26\lib\distutils\msvc9compiler.py", line 358, in initialize vc_env = query_vcvarsall(VERSION, plat_spec) File "C:\Python26\lib\distutils\msvc9compiler.py", line 274, in query_vcvarsall raise ValueError(str(list(result.keys()))) ValueError: [u'path'] What can I do to fix this? Any help will be appreciated

    Read the article

  • System.ArgumentException: Invalid hex character at DecryptAssemblyResource

    - by Radu094
    My webapp is trowing these exceptions intermitently ever since we migrated to Mono + Apache: The error sounds more like a problem reading/processing some assembly, so I was wondering if I should be worried that there might be a problem with the hard-drive? System.ArgumentException: Invalid hex character at System.Web.Configuration.MachineKeySectionUtils.ToHexValue (Char c, Boolean high) [0x00000] in <filename unknown>:0 at System.Web.Configuration.MachineKeySectionUtils.GetBytes (System.String key, Int32 len) [0x00000] in <filename unknown>:0 at System.Web.Handlers.ScriptResourceHandler.GetBytes (System.String val) [0x00000] in <filename unknown>:0 at System.Web.Handlers.ScriptResourceHandler.DecryptAssemblyResource (System.String val, System.String& asmName, System.String& resName) [0x00000] in <filename unknown>:0 at System.Web.Handlers.ScriptResourceHandler.ProcessRequest (System.Web.HttpContext context) [0x00000] in <filename unknown>:0 at System.Web.Handlers.ScriptResourceHandler.System.Web.IHttpHandler.ProcessRequest (System.Web.HttpContext context) [0x00000] in <filename unknown>:0 at System.Web.HttpApplication+<Pipeline>c__Iterator2.MoveNext () [0x00000] in <filename unknown>:0 at System.Web.HttpApplication.Tick () [0x00000] in <filename unknown>:0 Method: Void Application_Error(System.Object, System.EventArgs) at File: at Line Number: 0 Method: Void ProcessError(System.Exception) at File: at Line Number: 0 Method: Void Tick() at File: at Line Number: 0 Method: Void Start(System.Object) at File: at Line Number: 0 Method: Void System.Web.IHttpHandler.ProcessRequest(System.Web.HttpContext) at File: at Line Number: 0 Method: Void Process(System.Web.HttpWorkerRequest) at File: at Line Number: 0 Method: Void RealProcessRequest(System.Object) at File: at Line Number: 0 Method: Void ProcessRequest(System.Web.HttpWorkerRequest) at File: at Line Number: 0 Method: Void ProcessRequest() at File: at Line Number: 0 Method: Void ProcessRequest(Mono.WebServer.MonoWorkerRequest) at File: at Line Number: 0 Method: Void ProcessRequest(Int32, System.String, System.String, System.String, System.String, System.String, Int32, System.String, Int32, System.String, System.String[], System.String[], System.Object) at File: at Line Number: 0 Method: Void InnerRun(System.Object) at File: at Line Number: 0 Method: Void Run(System.Object) at File: at Line Number: 0

    Read the article

  • Java: Match tokens between two strings and return the number of matched tokens

    - by Cryssie
    Need some help to find the number of matched tokens between two strings. I have a list of string stored in ArrayList (example given below): Line 0 : WRB VBD NN VB IN CC RB VBP NNP Line 1 : WDT NNS VBD DT NN NNP NNP Line 2 : WRB MD PRP VB DT NN IN NNS POS JJ NNS Line 3 : WDT NN VBZ DT NN IN DT JJ NN IN DT NNP Line 4 : WP VBZ DT JJ NN IN NN Here, you can see each string consists of a bunch of tokens separated by spaces. So, there's three things I need to work with.. Compare the first token (WRB) in Line 0 to the tokens in Line 1 to see if they match. Move on to the next tokens in Line 0 until a match is found. If there's a match, mark the matched tokens in Line 1 so that it will not be matched again. Return the number of matched tokens between Line 0 and Line 1. Return the distance of the matched tokens. Example: token NN is found on position 3 on line 0 and position 5 on Line 1. Distance = |3-5| = 2 I've tried using split string and store it to String[] but String[] is fixed and doesn't allow shrinking or adding of new elements. Tried Pattern Matcher but with disasterous results. Tried a few other methods but there's some problems with my nested for loops..(will post part of my coding if it will help). Any advice or pointers on how to solve this problem this would be very much appreciated. Thank you very much.

    Read the article

  • What does the subversion error "Could not read status line" mean?

    - by Jergason
    Exact duplicate: SVN: Could not read status line: connection was closed by server This is not an exact duplicate. The other question was asking about getting the error in a specific situation, and the answer was vauge at best. This is a fairly basic question, but it is driving me nuts. I have set up a brand new repository at beanstalk.com. They give me the url, http://.svn.beanstalkapp.com/blog. They also automatically create the tag, trunk and branches folder in the repository. I have checked out the trunk folder and used svn add to add the new file. I am trying to do my first commit, but I get this error: Commit failed (details follow): CHECKOUT of '/foo/!svn/bln/1': Could not read status line: connection was closed by server. (http://user_name@my_name.svn.beanstalkapp.com) What does this mean, and what causes it? I have googled for a definition of what "Could not read status line" means, but was unable to find anything explaining it. edit: I was getting this error while trying to manipulate my repository from behind a firewall. I still don't know what was causing it, but I don't have this problem at home. Strangeness.

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 186 187 188 189 190 191 192 193 194 195 196 197  | Next Page >