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  • How can I return default at loop end in Scheme?

    - by Kufi Annan
    I'm trying to implement back-tracking search in Scheme. So far, I have the following: (define (backtrack n graph assignment) (cond (assignment-complete n assignment) (assignment) ) (define u (select-u graph assignment)) (define c 1) (define result 0) (let forLoop () (when (valid-choice graph assignment c) (hash-set! assignment u c) (set! result (backtrack n graph assignment)) (cond ((not (eq? result #f)) result)) (hash-remove! assignment u) ) (set! c (+ c 1)) (when (>= n c) (forLoop)) ) #f ) My functions assignment-complete and select-u pass unit tests. The argument assignment is a hash-table make with (make-hash), so it should be fine. I believe the problem I have is related to returning false at the end of the loop, if no recursive returns a non-false value (which should be a valid assignment).

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  • why assign null value or another default value firstly?

    - by Phsika
    i try to generate some codes. i face to face delegates. Everythings is ok.(Look below) But appearing a warning: you shold assing value why? but second code below is ok. namespace Delegates { class Program { static void Main(string[] args) { HesapMak hesapla = new HesapMak(); hesapla.Calculator = new HesapMak.Hesap(hesapla.Sum); double sonuc = hesapla.Calculator(34, 2); Console.WriteLine("Toplama Sonucu:{0}",sonuc.ToString()); Console.ReadKey(); } } class HesapMak { public double Sum(double s1, double s2) { return s1 + s2; } public double Cikarma(double s1, double s2) { return s1 - s2; } public double Multiply(double s1, double s2) { return s1 * s2; } public double Divide(double s1, double s2) { return s1 / s2; } public delegate double Hesap(double s1, double s2); public Hesap Calculator; ----&#60; they want me assingn value } } namespace Delegates { class Program { static void Main(string[] args) { HesapMak hesapla = new HesapMak(); hesapla.Calculator = new HesapMak.Hesap(hesapla.Sum); double sonuc = hesapla.Calculator(34, 2); Console.WriteLine("Toplama Sonucu:{0}",sonuc.ToString()); Console.ReadKey(); } } class HesapMak { public double Sum(double s1, double s2) { return s1 + s2; } public double Cikarma(double s1, double s2) { return s1 - s2; } public double Multiply(double s1, double s2) { return s1 * s2; } public double Divide(double s1, double s2) { return s1 / s2; } public delegate double Hesap(double s1, double s2); public Hesap Calculator=null; } }

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  • how to configure Postfix to send more emails per hour than the default.

    - by dina-ak
    Hello; My postfix only let me send only 3600 email in an hour ( from which i conclude that there is 1s delay between each email ) while I want to send double that number .. I looked in the postfix configuration .Is there any parameters that i can change to send more than 3600 email in an hour ? this is the output of postconf -n alias_database = hash:/etc/aliases alias_maps = hash:/etc/aliases bounce_queue_lifetime = 1d command_directory = /usr/sbin config_directory = /etc/postfix daemon_directory = /usr/libexec/postfix data_directory = /var/lib/postfix debug_peer_level = 2 default_destination_concurrency_limit = 5 default_destination_rate_delay = 0s html_directory = no inet_interfaces = all inet_protocols = ipv4 initial_destination_concurrency = 2 lmtp_destination_rate_delay = 0s local_destination_rate_delay = 0s mail_owner = postfix mailq_path = /usr/bin/mailq.postfix manpage_directory = /usr/share/man maximal_queue_lifetime = 1d mydestination = $myhostname, localhost.$mydomain, localhost, $mydomain mydomain = example.com myhostname = server01.example.com myorigin = $mydomain newaliases_path = /usr/bin/newaliases.postfix qmgr_message_recipient_limit = 10000 queue_directory = /var/spool/postfix readme_directory = /usr/share/doc/postfix-2.5.6/README_FILES relay_destination_rate_delay = 0s sample_directory = /usr/share/doc/postfix-2.5.6/samples sendmail_path = /usr/sbin/sendmail.postfix setgid_group = postdrop smtp_bind_address = xxx.xxx.xxx.xxx smtp_destination_rate_delay = 0s smtp_generic_maps = hash:/etc/postfix/generic smtpd_banner = $myhostname ESMTP $mail_name smtpd_client_restrictions = check_client_access hash:/etc/postfix/access unknown_local_recipient_reject_code = 550 virtual_alias_maps = hash:/etc/postfix/virtual virtual_destination_rate_delay = 0s

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  • How do I set default host for url helpers in rails?

    - by ja.kub.cz
    I would like to do something like this config.default_host = 'www.subdomain.example.com' in some of my configuration files, so that object_url helpers produce link beginning with http://www.subdomain.example.com I have tried to search the docs but I did not find anytnig exept ActionMailer docs and http://api.rubyonrails.org/classes/Rails/Configuration.html which is not usefull for me, because I do not know in which pat to look. Is there a place which describes the whole structure of Rails::Initializer.config? Thanks for helping Jakub

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  • How do I change the default toolspath for Visual Studio 2008?

    - by gersh
    I had Visual Studio 2010 beta 1 installed, and I removed. Now, when I try to crate a project in Visual Studio 2008. I get the error "MSBUildToolsPath is not specified for the ToolsVersion "4.0" defined at "HKEY_LOCAL_MACHINE\SOFTWARE\Microsoft\MSBuild\TOolsVersions\4.0", or the value specified evaluates to the empty string". How do I change the ToolsVersion to "3.5", so it works?

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  • Finding the TextBlock that is part of the default control template ComboBox generated through code.

    - by uriya
    I'm trying to find the TextBlock that is inside the control template of a comboBox. using VisualTreeHelpar.GetChildrenCount is working only if the comboBox is declared in XAML.In that case GetChildrenCount returns 1 and a recursive search is possible. However, if I declare the combo as a member of the Window class using code, allocated and setting it to its place, the function GetChildrenCount return 0. When I run snoop in this scenario It shows the combo children hierarchy. I want to be able to search the comboBox just as snoop does. Any help would be appreciated. code: ComboBox mCombo = null; private void Windows_Loaded(object sender, RoutedEventArgs e) { mCombo = new ComboBox; mGrid.Children.Add(mCombo); Grid.SetRow(mCombo,0); int count = VisualTreeHelpar.GetChildrenCount(mCombo); }

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  • Why did Matz choose to make Strings mutable by default in Ruby?

    - by Seth Tisue
    It's the reverse of this question: http://stackoverflow.com/questions/93091/why-cant-strings-be-mutable-in-java-and-net Was this choice made in Ruby only because operations (appends and such) are efficient on mutable strings, or was there some other reason? (If it's only efficiency, that would seem peculiar, since the design of Ruby seems otherwise to not put a high premium on faciliating efficient implementation.)

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  • Zend Form Radio Elements, using images instead of default radio elements.

    - by Davy
    Hello, Ultimately here is my goal. Using Zend_Form I want to turn this idea http://www.sohtanaka.com/web-design/fancy-thumbnail-hover-effect-w-jquery/ into a list of radio buttons. Kind of using this concept. http://theodin.co.uk/tools/tutorials/jqueryTutorial/fancyRadio/ I know there has to be a way to do this but I can't seem to figure anything out! Any ideas? Thanks! -d

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  • Home screen widget size for large screen or hdpi?

    - by kknight
    From Android widget screen guidelines, http://developer.android.com/guide/practices/ui_guidelines/widget_design.html, we know that, home screen has 4*4 cells, and in portrait orientation, each cell is 80 pixels wide by 100 pixels tall. I think these are for baseline HVGA screen. How about for large screens and hdpi screens, do they still have 4*4 cells for widget and each cell in portrait orientation is still 80 pixels * 100 pixels? Thanks.

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  • UIView: how to do non-destructive drawing?

    - by Caffeine Coma
    My original question: I'm creating a simple drawing application and need to be able to draw over existing, previously drawn content in my drawRect. What is the proper way to draw on top of existing content without entirely replacing it? Based on answers received here and elsewhere, here is the deal. You should be prepared to redraw the entire rectangle whenever drawRect is called. You cannot prevent the contents from being erased by doing the following: [self setClearsContextBeforeDrawing: NO]; This is merely a hint to the graphics engine that there is no point in having it pre-clear the view for you, since you will likely need to re-draw the whole area anyway. It may prevent your view from being automatically erased, but you cannot depend on it. To draw on top of your view without erasing, do your drawing to an off-screen bitmap context (which is never cleared by the system.) Then in your drawRect, copy from this off-screen buffer to the view. Example: - (id) initWithCoder: (NSCoder*) coder { if (self = [super initWithCoder: coder]) { self.backgroundColor = [UIColor clearColor]; CGSize size = self.frame.size; drawingContext = [self createDrawingBufferContext: size]; } return self; } - (CGContextRef) createOffscreenContext: (CGSize) size { CGColorSpaceRef colorSpace = CGColorSpaceCreateDeviceRGB(); CGContextRef context = CGBitmapContextCreate(NULL, size.width, size.height, 8, size.width*4, colorSpace, kCGImageAlphaPremultipliedLast); CGColorSpaceRelease(colorSpace); CGContextTranslateCTM(context, 0, size.height); CGContextScaleCTM(context, 1.0, -1.0); return context; } - (void)drawRect:(CGRect) rect { UIGraphicsPushContext(drawingContext); CGImageRef cgImage = CGBitmapContextCreateImage(drawingContext); UIImage *uiImage = [[UIImage alloc] initWithCGImage:cgImage]; UIGraphicsPopContext(); CGImageRelease(cgImage); [uiImage drawInRect: rect]; [uiImage release]; } TODO: can anyone optimize the drawRect so that only the (usually tiny) modified rectangle region is used for the copy?

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  • How to get the default syle of my Button in WPF?

    - by Ashish Ashu
    I have create a Button style under Resource folder of the main application. I have added the reference of this button syle in the App.xml of the main application. Now this style is applicable to all the buttons in the main application or any other assembly. I want if I want to override my custom style of button to the normal button style , what should I do ?? Please help !!

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  • Flex: Why does setting scaleX/Y in mxml effect the components size but setting it in actionscript do

    - by ChrisInCambo
    Hi, I'm playing around with the scaleX/Y in the canvas tag and have noticed some strange behaviour. When I set scale in in mxml the width and height of the canvas are adjusted accordingly. For example if I have a canvas like this: <mx:Canvas width="1000" height="1000" scaleX="0.1" scaleY="0.1" /> The canvas now appears on screen to have a width and height of 100 and if inside my creationComplete callback I check the width and height property they are indeed 100. But if I do exactly the same thing except I set the scaleX/Y property from actionscript the canvas on screen appears to have a width and height of 100 as expected, but when I check the width and height property of the canvas they are still at the previous values of 1000. Could anyone help me understand what is going on and also tell me if there is any method that will refresh the width and height values so that they are correct? Thanks, Chris

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  • Why is a fixed size buffers (arrays) must be unsafe?

    - by brickner
    Let's say I want to have a value type of 7 bytes (or 3 or 777). I can define it like that: public struct Buffer71 { public byte b0; public byte b1; public byte b2; public byte b3; public byte b4; public byte b5; public byte b6; } A simpler way to define it is using a fixed buffer public struct Buffer72 { public unsafe fixed byte bs[7]; } Of course the second definition is simpler. The problem lies with the unsafe keyword that must be provided for fixed buffers. I understand that this is implemented using pointers and hence unsafe. My question is why does it have to be unsafe? Why can't C# provide arbitrary constant length arrays and keep them as a value type instead of making it a C# reference type array or unsafe buffers?

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  • How can I add a default header to my source files automatically in Eclipse?

    - by John
    Hi. I'm trying to figure out how I can have a comment header automatically added to all new source files in my eclipse java project. I've looked around but I haven't found a simple solution to automate this process. I gave JAutodoc a try, and even though it does allow me to specify a header I still had to tell the plugin manually to inject the header and it didn't seem very fond of my keyword-subsitution. I'm by the way using the Maven2 plugin for Eclipse for most of my projects if that's any help. Any tips?

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  • Getting around the Max String size in a vba function?

    - by Ommit
    The max number of characters you can use in string in a vba function is 255. I am trying to run this function Var1= 1 Var2= 2 . . . Var256 =256 RunMacros= "'Tims_pet_Robot """ & Var1 & """ , """ & Var2 & """ , """ ... """ & Var256 """ '" Runat=TimeValue("15:00:00") Application.OnTime EarliestTime:=Runat, Procedure:=RunMacros & RunMacros2 ', schedule:=True It runs a procedure at a certain time and passes a bunch of variables to it. but the string is too long.

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  • Issues with reversing bit shifts that roll over the maximum byte size?

    - by Terri
    I have a string of binary numbers that was originally a regular string and will return to a regular string after some bit manipulation. I'm trying to do a simple caesarian shift on the binary string, and it needs to be reversable. I've done this with this method.. public static String cShift(String ptxt, int addFactor) { String ascii = ""; for (int i = 0; i < ptxt.length(); i+=8) { int character = Integer.parseInt(ptxt.substring(i, i+8), 2); byte sum = (byte) (character + addFactor); ascii += (char)sum; } String returnToBinary = convertToBinary(ascii); return returnToBinary; } This works fine in some cases. However, I think when it rolls over being representable by one byte it's irreversable. On the test string "test!22*F ", with an addFactor of 12, the string becomes irreversible. Why is that and how can I stop it?

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