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  • [Cocoa] Placing an NSTimer in a separate thread

    - by ndg
    I'm trying to setup an NSTimer in a separate thread so that it continues to fire when users interact with the UI of my application. This seems to work, but Leaks reports a number of issues - and I believe I've narrowed it down to my timer code. Currently what's happening is that updateTimer tries to access an NSArrayController (timersController) which is bound to an NSTableView in my applications interface. From there, I grab the first selected row and alter its timeSpent column. From reading around, I believe what I should be trying to do is execute the updateTimer function on the main thread, rather than in my timers secondary thread. I'm posting here in the hopes that someone with more experience can tell me if that's the only thing I'm doing wrong. Having read Apple's documentation on Threading, I've found it an overwhelmingly large subject area. NSThread *timerThread = [[[NSThread alloc] initWithTarget:self selector:@selector(startTimerThread) object:nil] autorelease]; [timerThread start]; -(void)startTimerThread { NSAutoreleasePool *pool = [[NSAutoreleasePool alloc] init]; NSRunLoop *runLoop = [NSRunLoop currentRunLoop]; activeTimer = [[NSTimer scheduledTimerWithTimeInterval:1.0 target:self selector:@selector(updateTimer:) userInfo:nil repeats:YES] retain]; [runLoop run]; [pool release]; } -(void)updateTimer:(NSTimer *)timer { NSArray *selectedTimers = [timersController selectedObjects]; id selectedTimer = [selectedTimers objectAtIndex:0]; NSNumber *currentTimeSpent = [selectedTimer timeSpent]; [selectedTimer setValue:[NSNumber numberWithInt:[currentTimeSpent intValue]+1] forKey:@"timeSpent"]; } -(void)stopTimer { [activeTimer invalidate]; [activeTimer release]; }

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  • asp.net mvc script and style references

    - by tom
    I'm trying to include script and style references that will not break on deployment, however I can not even get the references to work locally. I have tried using Url.Content() and MVCContrib's <%=Html.ScriptInclude("")%>. My scripts are in a Scripts folder on the root of the site; my styles are in the usual Content/css/ folder. The scripts render like this: <script type="text/javascript" src="/Scripts/MicrosoftAjax.debug.js" ></script> This will not work in a view page in the Views folder. What am I doing wrong and what is the best way to handle this? I would have thought Url.Content() would at least work for styles but used in my master page, the link rendered <link href="/Content/css/Site.css rel="stylesheet" type="text/css" /> This does not work, because the Master Page is in a Shared folder, so what is really the way forward with this?

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  • Using NSUserDefaults to load data depending on which table view cell is pressed

    - by Bad_APPZ
    I want my app to work just like the 'contacts' app on iOS. When a user selects a certain TableViewCell, i want to load certain data. No Matter which cell is pressed, Either "Joseph, Richard, or Shannon", This view comes up: Both of the views look the exact same, but they just display different information. So i guess my question is: How can I programmatically set a key @"cell1" @"cell2", etc... for each cell using NSUserDefaults? But here is the catch, I dont know how many cells will be added, so i cant hard code this, How can I create a key for each table view cell for how ever many is added? Thanks for the help!

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  • Django: How do I get logging working?

    - by swisstony
    I've added the following to my settings.py file: import logging ... logging.basicConfig(level=logging.DEBUG, format='%(asctime)s %(levelname)s %(message)s', filename=os.path.join(rootdir, 'django.log'), filemode='a+') And in views.py, I've added: import logging log = logging.getLogger(__name__) ... log.info("testing 123!") Unfortunately, no log file is being created. Any ideas what I am doing wrong? And also is their a better method I should be using for logging? I am doing this on Webfaction.

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  • Coldfusion 9 Inter portlet communication?

    - by Jakub
    I am having a hard time trying to find documentation at achieving IPC using Coldfusion 9 portlets under JBOSS. Does anyone have any good references I can take a look at? Or maybe some example code that I can go off of? So far I've been successful in getting my portlets working under Liferay (JBOSS), form submission, different views (edit/help) all work fine. Just need to know how to have one portlet on the page talk with another portlet. So far have been unsuccessful :( Anyone?

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  • Trouble rendering a view inside a generic class

    - by Horace Loeb
    I'm trying to encapsulate the logic for generating my sitemap in a separate class so I can use Delayed::Job to generate it out of band: class ViewCacher include ActionController::UrlWriter def initialize @av = ActionView::Base.new(Rails::Configuration.new.view_path) @av.class_eval do include ApplicationHelper end end def cache_sitemap songs = Song.all sitemap = @av.render 'sitemap/sitemap', :songs => songs Rails.cache.write('sitemap', sitemap) end end But whenever I try ViewCacher.new.cache_sitemap I get this error: ActionView::TemplateError: ActionView::TemplateError (You have a nil object when you didn't expect it! The error occurred while evaluating nil.url_for) on line #5 of app/views/sitemap/_sitemap.builder: I assume this means that ActionController::UrlWriter is not included in the right place, but I really don't know

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  • KeyError this says that key(partner) is not in dict ?

    - by Ansh Jain
    I am trying to make an chat application using python and django. I almost complete it and its working fine for 8-10 minutes when two persons are chatting after that certain time it shows an error. here is the traceback : - Traceback (most recent call last): File "\Django_chat\django_chat\chat\views.py", line 55, in receive message = chatSession.getMessage(request.session['partner'],request.session['uid'],afterTime) File "C:\Python26\lib\site-packages\django\contrib\sessions\backends\base.py", line 47, in __getitem__ return self._session[key] KeyError: 'partner' here is the receive module :- def receive(request): message received by this user chatSession = chat() data = request.POST afterTime = data['lastMsgTime'] try: message = chatSession.getMessage(request.session['partner'],request.session['uid'],afterTime) except: #partnerId = virtual_users.objects.get(id=request.session['uid']).partner print('there is an error in receive request') traceback.print_exc(file=open("/myapp.log","a")) msg = serializers.serialize("json", message) return HttpResponse(msg) Please Help me :( thanks Ansh J

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  • Sinatra: How do I provide access to a login form while preventing access to the rest of my Sinatra a

    - by Brandon Toone
    I recently created a Sinatra app with a login form (no basic auth). To prevent access to the app unless the user logged in I put a before block in place before do unless request.path_info == '/login' authenticated? end end I quickly realized that this prevented me from accessing resources in the public directory like my style sheet and logo unless authenticated first as well. To get around that I changed my filter to the following: before do unless request.path_info == '/login' || request.path_info == "/stylesheets/master.css" || request.path_info == "/images/logo.png" authenticated? end end If there were lots of resources I needed to provide exceptions to this way of making them would quickly become overwhelming. What is a better way to code this so I can make exceptions for the public directory or even its specific sub-directories and files like /stylesheets, /images, /images/bg.png but not /secret or /secret/eyes-only.pdf? Or ... Is there a completely different best-practice to handle this situation of locking down everything except the stuff related to logging in (handlers, views, resources)?

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  • How Does a Login system generally work with OOP?

    - by fakingfantastic
    Sorry if this is a badly formed question, but I'm trying to make my web applications (using PHP) more OO. *EDIT* I'm developing the Framework myself */EDIT* Everything is great so far, I've made a Front Controller system that taps into a MVC system. The FC figures out what page you want, loads the specific page Controller (*EDIT* which extends an abstract Controller Object */EDIT*), which gets anything it needs from Models, and then calls the appropriate View. Very basic. But now, I need to make an admin section (quasi-CMS). How does a login system fit into the grand scheme of things? Do you set controllers as needing a login? If so, how? What If you only want certain views of a controller requiring login? Thanks in advance.

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  • Relation/Sort not working in rails controller?

    - by Elliot
    I have the following relation in my rails app: genre - has many - authors authors - belong to genre and has many books books - belongs to authors and belongs to users (users can add books to the db) in my controller I have: @books=current_user.books(:include => [:author => :genre], :order => 'created_at DESC') While I am able to use the @books variable in my views - nothing is done correctly (i.e. its not showing me only books added by that user, and its not descending by created_at)... any ideas? -- Also I'm using clearance for the user auth, so current_user without the @ in the controller seems to work fine Actually, I think the relation is working, only the sort might not be working...

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  • Click events not working in Rails view

    - by Fdr
    I have following view (html.erb): <h3>My view</h3> <script> function test() { alert("hello"); } </script> <input type="button" onClick="test();" value="test" /> For reasons I cannot understand the onClick event never gets fired when I access the view through rails(tried static apache hosting - no problems there). Here is rendered html: http://pastebin.com/LmGysgUG I feel quite stupid, is this something to do the way Rails renders views?

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  • Passing parameters into ViewModels (Prism)

    - by vXtreme
    Hi I can't figure out how to pass parameters to my viewmodels from other views or viewmodels. For instance, I have a View called Customers. There is a grid inside, and if you double-click the grid, a new view is supposed to come up and allow you to edit that customer's data. But how will the View(Model) responsible for editing data know which customer it's supposed to open if I can't pass any parameters inside? EventAggregator is out of the question because I obviously can't create hundreds of eventargs, each for one view. And besides, it's a lousy solution. So far I was able to come up with: CustomerDataView custView = new CustomerDataView(customerId, currentContext); manager.Regions[RegionNames.Sidebar].AddAndActivate(custView); What do you think about this particular solution? Is this the way it's normally done? What I don't like about this is the fact that I lose out on automatic dependency injection by Unity.

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  • objectWithFieldNAme Best Practice for CoreData

    - by Rafael
    Hello, I'm trying to implements some methods for my CoreData models and I'm wonndering if the way I'm doing it is a good practice. I want to implement methods of the type getObjectsWithFieldName. This methods could be used by severals views. So the way I'm doing it is implementing a Class method in the model in the following way: +(NSArray *)getObjectWithFieldName:(NSString *)fieldName andContext:(NSManagedObjectContext *) context; Is this a good practice? Or there is another way to do it for iPhone Development? Thanks in advanced.

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  • iPhone: TabBarController as second level of Navigation Controller

    - by Nebs
    I'm new to iphone development. I've read tutorials about implementing a tab bar controller on the window (eg as the main controller for the app). But how can I create a tab bar controller as a 'standalone' UIViewController that can be called by a navigation bar controller? Basically my navigation bar controller has an array of UIViewControllers that it displays in the table and then loads the appropriate view/controller when a user selects an item. Now I want one of these loaded views/controllers to be a tab bar controller. How can I do this? I'm not sure how to create a tab bar controller on its own without having an outlet/instance in the application delegate. Hope that made sense. Thanks.

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  • MVC Html Layout C# code formatting

    - by Andrew Florko
    I insert into asp.net mvc views C# logic that manages layout like the following: <% if (Model.People.Count > 0 ) { %> <% foreach (var person in Model.People) { %> ... <% }} else { %> <span class="error">Sorry, no people</span> <%} %> I try to minimize <% % code placing "{" symbol on the same line as it's condition (java-style). Html layout looks more clear to me after that. Do you apply C# formatting rules to <% % html injections "}" should be on a new line or manage layout in different way? Thank you in advance!

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  • Getting camera preview data without using a preview callback

    - by velocipedestrian
    I have an app that does some processing to camera preview frames before displaying them to the user. I'm currently using preview callbacks to access the image data, but the problem I have is that the onPreviewFrame() function stops getting called if you start recording video using a MediaRecorder, and I want the processing to continue when video is being recorded. I've tried doing the following: public static Bitmap convertViewToBitmap(View view) { Bitmap bitmap = Bitmap.createBitmap(view.getWidth(),view.getHeight(), Bitmap.Config.ARGB_8888); view.draw(new Canvas(bitmap)); return bitmap; } to convert the preview surface to a bitmap, but when I pass the preview SurfaceView to the function it returns an all-black bitmap (it works when I test it on normal views though). Is there any other way I can access the image data if preview callbacks are not available?

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  • I am not able to run Asp.Net MVC 2 Application

    - by Vinod B
    Hi I have trying an sample application in Asp.Net MVC 2 Application given in http://www.codeproject.com/KB/aspnet/aspnet_mvc_tutorial.aspx But i am getting the error as below Server Error in '/' Application. The resource cannot be found. Description: HTTP 404. The resource you are looking for (or one of its dependencies) could have been removed, had its name changed, or is temporarily unavailable. Please review the following URL and make sure that it is spelled correctly. Requested URL: /Views/PersonalInformation/Index.aspx Version Information: Microsoft .NET Framework Version:2.0.50727.3053; ASP.NET Version:2.0.50727.3053 Please let mw know wat is the problem

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  • Django: order by count of a ForeignKey field?

    - by AP257
    This is almost certainly a duplicate question, in which case apologies, but I've been searching for around half an hour on SO and can't find the answer here. I'm probably using the wrong search terms, sorry. I have a User model and a Submission model. Each Submission has a ForeignKey field called user_submitted for the User who uploaded it. class Submission(models.Model): uploaded_by = models.ForeignKey('User') class User(models.Model): name = models.CharField(max_length=250 ) My question is pretty simple: how can I get a list of the three users with the most Submissions? I trued creating a num_submissions method on the User model: def num_submissions(self): num_submissions = Submission.objects.filter(uploaded_by=self).count() return num_submissions and then doing: top_users = User.objects.filter(problem_user=False).order_by('num_submissions')[:3] but this fails, as do all the other things I've tried. Can I actually do it using a smart database query? Or should I just do something more hacky in the views file?

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  • How do I create a view with a picker on the bottom and a table view on the top?

    - by Andy
    Hi - first time asker, long-time lurker. I am trying to create an iPhone view that has a date/time picker on the bottom half of the screen, and a grouped, single-section, four-row table view on the top half of the screen (almost identical to the one Apple shows in Fig. 2-4 of their View Controller Programming Guide (but then never goes on to explain). Conceptually, I think I understand that what I need is a main view with a pair of subviews - one for the picker, and one for the table view. I'm pretty sure I can make the picker function once I have it on-screen, and I'm pretty sure I can make the table view function too. What I can't for the life of me figure out is how, programmatically speaking, to get the two views onto the screen simultaneously. I can lay it out perfectly in Interface Builder, but then it all goes to hell when I switch to Xcode...the view appears with the picker, but no table view. Thanks, in advance, for any help you can offer.

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  • Your Django Development process/steps (Step by Step)

    - by AJ
    I want to know step by step process of how folks develop on Django here. I have seen that whenever I try to create a website in Django, I always get confused amongst: DB Schema/models.py UI/Template Structure Login module urls.py views.py How do you approach this? I may have missed something. You do not need to elaborate everything, just stepwise what you do. If you do two things at the same time (or side-by-side), that would also be helpful to mention. Thanks a lot.

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  • pyramid - How to handle complex URL in a elegant way?

    - by Lingfeng Xiong
    I'm writing a admin website which control several websites with same program and database schema but different content. The URL I designed like this: http://example.com/site A list of all sites which under control http://example.com/site/{id} A brief overview of select site with ID id http://example.com/site/{id}/user User list of target site http://example.com/site/{id}/item A list of items sold on target site http://example.com/site/{id}/item/{iid} Item detailed information # ...... something similar As you can see, nearly all URL are need the site_id. And in almost all views, I have to do some common jobs like query Site model against database with the site_id. Also, I have to pass site_id whenever I invoke request.route_path. So... is there anyway for me to make my life easier? Thanks in advance.

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  • Does django take SCRIPT_NAME into account when using the default LOGIN_URL

    - by DanJ
    Hi, I'm using Django 1.0.2 and trying to figure out how to get the @login_required working correctly. When I use the built-in server it redirects to the default login_url, or my LOGIN_URL as defined in settings.py as expected. What is not clear to me is how to deploy to the server where my site is not at the root. In my templates I use the url template tag, and in the views I can access request.META['SCRIPT_NAME'], but for some reason it doesn't seem to apply to the LOGIN_URL used. What am I missing? Thanks.

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  • Code is exectuting but the view is not loading when called form a function?

    - by wolverine
    I have a viewBased application with the viewController class mainView. In it I am loading various views(different nibs) depending upon certain actions that I do. I have added a popoverController with a barbutton in the mainView. Its intialized with a tableviewController class named popClass. When I select certain row in the popover, I want the view in my mainView to load someother view(as I do when i do certain actions). For that I have written a function in mainView Controller class and is calling it from the popOver class. Function and the lines of code are executing but nothing is happening. Even the log lines are printed but no action takes place. What is the problem? OR is there anyother way to make the view change in mainView by using the popover?

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  • Is the method addSubview of NSView inherently slow? (Cocoa OSX)

    - by Michael Minerva
    I am trying to speed my gui that loads very slow slow when I am loading a large project (the gui is a representation of groups and sub groups and is made up of many views). During this process I was looking at how long certain code segments take to execute and I have found that a call to addsubview is taking between 10 and 20 milliseconds most of the time. The subview I was looking at is a disclosure button. I am wondering if this method is just inherently slow or is their some other factor at work here? Is the time it takes to add the subview dependent on the complexity of the subview or is that not a factor? Also, is there some other method that can be used to add a subview that might be faster?

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  • SQL Azure server as unit of billing

    - by vtortola
    Hi, One of the azure training kit presentation says: Each account has zero or more logical servers Provisioned via a common portal Establishes a billing instrument Each logical server has one or more databases Contains metadata about database & usage Unit of authentication, geo-location, billing, reporting Generated DNS-based name Each database has standard SQL objects Users, Tables, Views, Indices, etc Unit of consistency So now I'm lost :D. Were not the databases themselves the units of billing? I mean, I thought that servers were just like logical containers and you were charged per number and size of databases. How servers are billed? Thanks.

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