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• php / mysql - select id from one table excepting ids which are in second table

  - by John

  hello. for example i have 2 tables: 1 . users: id Name 1 Mike 2 Adam 3 Tom 4 John 5 Andy 6 Ray 2 . visits: userID date 1 ... 3 ... 6 ... i want to make a page which can be visited once in 12 hours, when user visits that page his id is included in database ( visits ), how i can select all users ( from database users) excepting users who visited page in <= 12 hours ( users from database visits )?

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• MySQL foreign key constraint disappearing

  - by Bramjam

  This is my table: /* oefenreeks leerplan */ CREATE TABLE leerplan_oefenreeks ( leerplan_oefenreeks_id INT PRIMARY KEY AUTO_INCREMENT NOT NULL, leerplan_id INT NOT NULL, oefenreeks_id INT NOT NULL, plaats INT NOT NULL ); /* fk */ ALTER TABLE leerplan_oefenreeks ADD CONSTRAINT fk_leerp_oefenr_leerplan FOREIGN KEY(leerplan_id) REFERENCES leerplan (leerplan_id) ON DELETE CASCADE; ALTER TABLE leerplan_oefenreeks ADD CONSTRAINT fk_leerp_oefenr_oefenreeks FOREIGN KEY(oefenreeks_id) REFERENCES oefenreeks (oefenreeks_id) ON DELETE CASCADE; /* when I execute the nexline, my fk_leerp_oefenr_leerplan constraint vanishes/disappears*/ ALTER TABLE leerplan_oefenreeks ADD CONSTRAINT un_leerp_oefenr UNIQUE(leerplan_id, oefenreeks_id); ALTER TABLE leerplan_oefenreeks ADD CONSTRAINT un_leerp_oefenr_plaats UNIQUE(leerplan_id, plaats); When I go and check only 3 constraints exist. fk_leerp_oefenr_leerplan disappears. I don't understand why this happens.

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• I need to auto_increment a field in MySQL that is not primary key

  - by behrk2

  Hey everyone, Right now, I have a table whose primary key is an auto_increment field. However, I need to set the primary key as username, date (to ensure that there cannot be a duplicate username with a date). I need the auto_increment field, however, in order to make changes to row information (adding and deleting). What is normally done with this situation? Thanks!

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• PHP and MySQL echoing out a Table

  - by user1631702

  Okay, so I've done this before, and it worked. I am trying to echo out specific rows on my database in a table. Here is my code: <?php $connect = mysql_connect("localhost", "xxx", "xxx") or die ("Hey loser, check your server connection."); mysql_select_db("xxx"); $quey1="select * from `Ad Requests`"; $result=mysql_query($quey1) or die(mysql_error()); ?> <table border=1 style="background-color:#F0F8FF;" > <caption><EM>Student Record</EM></caption> <tr> <th>Student ID</th> <th>Student Name</th> <th>Class</th> </tr> <?php while($row=mysql_fetch_array($result)){ echo "</td><td>"; echo $row['id']; echo "</td><td>"; echo $row['twitter']; echo "</td><td>"; echo $row['why']; echo "</td></tr>"; } echo "</table>"; ?> It gives me no errors, but It just shows a blank table with none of these rows. My Question: How come this wont show any rows in the table, what am I doing wrong?

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• access denied for user root, mysql database

  - by Yang

  when i am using sequel pro to connect to a remote database, the server says access denied. I am 100% percent sure that the username and password are correct. I also try to use phpmyadmin to connect to the server, it works. I don't know what happened when I am using sequel pro to connect to the server.

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• MySQL Need some help with a query

  - by Jules

  I'm trying to fix some data by adding a new field. I have a backup from a few months ago and I have restored this database to my server. I'm looking at table called pads, its primary key is PadID and the field of importance is called RemoveMeDate. In my restored (older) database there is less records with an actual date set in RemoveMeDate. My control date is 2001-01-01 00:00:00 meaning that the record is not hidden aka visible. What I need to do is select all the records from the older database / table with the control date and join with those from the newer db /table where the control date is not set. I hope I've explained that correctly. I'll try again, with numbers. I have 80,000 visible records in the older table (with control date set) and 30,000 in the newer db/table. I need to select the 50,000 from the old database, to perform an update query. Heres my query, which I'd can't get to work as I'd like. jules-fix-reasons is the old database, jules is the newer one. select p.padid from `jules-fix-reasons`.`pads` p JOIN `jules`.`pads` ON p.padid = `jules`.`pads`.`PadID` where p.RemoveMeDate <> '2001-01-01 00:00:00' AND `jules`.`pads`.RemoveMeDate = '2001-01-01 00:00:00'

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• Mysql Query problem ?

  - by deep

  ID NAME AMT 1 Name1 1000 2 Name2 500 3 Name3 3000 4 Name1 5000 5 Name2 2000 6 Name1 3000 consider above table as sample. am having a problem in my sql query, Am using like this. Select name,amt from sample where amt between 1000 and 5000 it returns all the values in the table between 1000 and 5000, instead I want to get maximum amount record for each name i.e., 3 name3 3000 4 name1 5000 5 name2 2000

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• VB.Net MySql command parameter MD5

  - by lampej

  Is it possible to execute a command like this? select * from tbl where col1=md5(@param1) or will the parameter throw off the md5 function? I have been unsuccessful in getting the command to work so far. Please let me know if this needs any further explanation and thank you in advance!

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• mysql : Recieve data only per months

  - by Tristan

  Hello, few times ago, i asked how to do to display datas per month, i must told a bad explanation because i just figured out that it's not what i want : Here's what I got : $req1 = ... AND v.date > (DATE_SUB(CURDATE(), INTERVAL 2 MONTH)) AND v.date < (DATE_SUB(CURDATE(), INTERVAL 1 MONTH)) $req2= ... AND v.date > (DATE_SUB(CURDATE(), INTERVAL 3 MONTH)) AND v.date < (DATE_SUB(CURDATE(), INTERVAL 2 MONTH)) But the problem, imagine that today you are the 10th june, it's going to calculate ALL the data between the 10 june to the 10 may then the 10 may until the 10 april... But what i want is data : from 1st may to 1 st june, from 1st june to 1st july... do you see what i mean ? thank you ;)

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• PHP returns invalid MySQL resource

  - by DeadMG

  $LDATE = '#' . $_REQUEST['LDateDay'] . '/' . $_REQUEST['LDateMonth'] . '/' . $_REQUEST['LDateYear'] . '#'; $RDATE = '#' . $_REQUEST['RDateDay'] . '/' . $_REQUEST['RDateMonth'] . '/' . $_REQUEST['RDateYear'] . '#'; include("../../sql.php"); $myconn2 = mysql_connect(/*removed*/, $username, $password); mysql_select_db(/*removed*/, $myconn2); $LSQLRequest = "SELECT * FROM flight WHERE DepartureDate = ".$LDATE; $LFlights = mysql_query($LSQLRequest, $myconn2); $RSQLRequest = "SELECT * FROM flight WHERE DepartureDate = ".$RDATE; $RFlights = mysql_query($RSQLRequest, $myconn2); Assuming that all the $_REQUESTs are valid numerical values for their appropriate fields in the day/month/year field, how can LFlights and RFlights be invalid? When I polled the whole database I got hundreds of results so I know that the database and connection data is fine, and the field DepartureDate exists too.

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• How to search a MySQL database for a specific string

  - by Nadia

  I am trying to set up a search feature on my site that will only return exact matches to keyword entered by the user. So if the user searches "dog" I don't want an article titled "Doggy Style" to appear in the search results (just an example I don't really have an article by that name). This of course does exactly that: SELECT * FROM articles WHERE article_title LIKE '%$searchQuery%' $searchQuery here is a PHP variable taken from the user's input form. So is there any way to return only exact matches?

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• MySQL date query only returns one year, when multiple exist

  - by Bowman

  I'm a part-time designer/developer with a part-time photography business. I've got a database of photos with various bits of metadata attached. I want to query the database and return a list of the years that photos were taken, and the quantity of photos that were taken in that year. In short, I want a list that looks like this: 2010 (35 photos) 2009 (67 photos) 2008 (48 photos) Here's the query I'm using: SELECT YEAR(date) AS year, COUNT(filename) as quantity FROM photos WHERE visible='1' GROUP BY 'year' ORDER BY 'year' DESC Instead of churning out all the possible years (the database includes photos from 2010-2008), this is the sole result: 2010 (35 photos) I've tried a lot of different syntax but at this point I'm giving in and asking for help!

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• MYSQL JOIN WHERE ISSUES - need some kind of if condition

  - by Breezer

  Hi Well this will be hard to explain but ill do my best The thing is i have 4 tables all with a specific column to relate to eachother. 1 table with users(agent_users) , 1 with working hours(agent_pers), 1 with sold items(agent_stat),1 with project(agent_pro) the user and the project table is irrelevant in the issue at hand but to give you a better understanding why certain tables is included in my query i decided to still mention them =) The thing is that I use 2 pages to insert data to the working hour and the sold items during that time tables, then i have a third page to summarize everything for current month, the query for that is as following: SELECT *, SUM(sv_p_kom),SUM(sv_p_gick),SUM(sv_p_lunch) FROM (( agent_users LEFT JOIN agent_pers ON agent_users.sv_aid = agent_pers.sv_p_uid) LEFT JOIN agent_stat ON agent_pers.sv_p_uid = agent_stat.sv_s_uid) LEFT JOIN agent_pro ON agent_pers.sv_p_pid=agent_pro.p_id WHERE MONTH(agent_pers.sv_p_datum) =7 GROUP BY sv_aname so the problem is now that i dont want sold items from previous months to get included in the data received, i know i could solve that by simple adding in the WHERE part MONTH(agent_stat.sv_s_datum) =7 but then if no items been sold that month no data at all will show up not the time or anything. Any aid on how i could solve this is greatly appreciated. if there's something that's not so clear dont hesitate to ask and ill try my best to answer. after all my english isn't the best out there :P regards breezer

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• The conceptual process of populating related tables in a database (MySql) from a CSV file

  - by user322772

  I'm new to relational databases and all the material I've read covered primary and foreign keys, normal forms, and joins but left out to populate the database once it's created. How do you import a CSV file so the fields match their related table? Say you were tying to build a beer database and had a CSV file with each line as a record. Header: brewer, beer_name, country, city, state, beer_category, beer_type, alcohol_content Record 1: Anheuser-Busch, Budweiser, United States, St. Louis, Mo, Pale lager, Regular, 5.0% Record 2: Anheuser-Busch, Bud Light, United States, St. Louis, Mo, Pale lager Light, 4.2% Record 3: Miller Brewing Company, Miller Lite, United States, Milwaukee, WI, Pale lager, Light, 4.2% You can create a "Brewer" table and a "Beer" table. When importing how does you connect the primary keys between the tables?

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• MySQL Query exceptions

  - by Wayne

  In one page, it should show records that has the following selected month from the drop down menu and it is set in the ?month=March So the query will do this $sql = "SELECT * FROM schedule WHERE month = '" . Clean($_GET['month']) . "' AND finished='0' ORDER BY date ASC"; But it shows records that has a value of 2 in the finished column and I don't want the query to include this. I've tried $sql = "SELECT * FROM schedule WHERE month = '" . Clean($_GET['month']) . "' AND finished='0' OR finished = '1' OR finished = '3' ORDER BY date ASC"; But it shows records on different months when it shouldn't be. So basically I want the record to exclude the records that has the value of 2 in the record that will not be shown in the page.

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• Levenshtein: MySQL + PHP

  - by user317005

  $word = strtolower($_GET['term']); $lev = 0; $q = mysql_uqery("SELECT `term` FROM `words`"); while($r = mysql_fetch_assoc($q)) { $r['term'] = strtolower($r['term']); $lev = levenshtein($word, $r['term']); if($lev >= 0 && $lev < 5) { $word = $r['term']; } } how can I move all that into just one query? don't want to have to query through all terms and do the filtering in php.

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• cant get ordering mysql results by current date ASC to work

  - by Patrick

  Im trying to order results ASCENDING from the current date this is what im using now; SELECT * FROM friends JOIN bdays ON bdays.user = friends.friendname WHERE username = $userid ORDER BY DATE_FORMAT(date, '%m %d') any ideas?

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• mysql filtering result using left outer join

  - by user288178

  my query: SELECT content.*, activity_log.content_id FROM content LEFT JOIN activity_log ON content.id = activity_log.content_id AND sess_id = '$sess_id' WHERE activity_log.content_id IS NULL AND visibility = $visibility AND content.reported < ".REPORTED_LIMIT." AND content.file_ready = 1 LIMIT 1 The purpose of that query is to get 1 row from the content table that has not been viewed by the user (identified by session_id), but it still returns contents that have been viewed. What is wrong? ( I have checked the table making sure that the content_ids are there) Note: I think this is more efficient than using subqueries, thoughts?

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• Mysql - multiple values and between

  - by realshadow

  Hey, I need to select 10 products and display them. Each product has 3 different prices. The select to get the prices looks like this: SELECT * FROM products_loans WHERE CODE IN('10X15/12', '10X15/Q10-10', '10X15/Q20-10') AND 550 BETWEEN PRICE_FROM AND PRICE_TO; Where 550 is the base price. Now this select returns 3 rows, but I want to modify it so it will return 30 results. I dont like the idea to execute 10 queries at once. I know I can easily achieve that with "OR", but I would like to ask if there is some other more elegant way to this. The select "should" look like this: SELECT * FROM products_loans WHERE KOD IN('10X15/12', '10X15/Q10-10', '10X15/Q20-10') AND (550, 325, 780) BETWEEN CENA_OD AND CENA_DO; Note that there is no "price" column or anything in the table which I could use to do a JOIN and I cant modify the table.

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• MySQL cross table regular expression match

  - by Josef Sábl

  I have a web application and I am working on engine that analyzes referals. Now I have table with pageviews along with referes that looks something like this: pv_id referer ------------------------------------------------------------ 5531854534 http://www.google.com/search?ie=UTF-8... 8161876343 http://google.cn/search?search=human+rights 8468434831 http://search.yahoo.com/search;_... The second table contains sources definitions like: source regex ------------------------------------------------------------ Google ^https?:\/\/[^\/]*google\.([a-z]{2,4})(\/.*|)$ Yahoo ^https?:\/\/[^\/]*yahoo\.com(\/.*|)$ What I want is third table created by joinin these two: pv_id source ------------------------------------------------------------ 5531854534 Google 8161876343 Google 8468434831 Yahoo How to join these tables with regular expression?

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• How to select the last two records for each topic_id in MySQL

  - by Luca Romagnoli

  Hi. I have to select the last two records for every topic. ex: table: msg id | topic_id ------------ 1 | 1 2 | 1 3 | 1 4 | 1 5 | 2 6 | 2 7 | 2 8 | 3 9 | 3 10 | 3 I want to obtain these rows: 3 1 4 1 6 2 7 2 9 3 10 3 How can I do this? thanks

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• Problem with auto increment primary key (MySQL).

  - by mathon12

  I have 2 tables each using other's primary key as a foreign key. The primary keys for both are set to auto_increment. The problem is, when I try to create and entry into one of the tables, I have no idea what the primary key of the entry is and can't figure out what to put in the other table as a foreign key. What should I do? Do I drop auto_increment altogether and cook up a unique identifier for each entry so I can use it to address the created entries? I'm using PHP, if that's relevant. Thanks.

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• mysql - union with creating demarcated field

  - by Qiao

  I need UNION two tables with creating new field, where 1 for first table, and 2 for second. I tried ( SELECT field, 1 AS tmp FROM table1 ) UNION ( SELECT field, 2 AS tmp FROM table2 ) But in result, tmp field was full of "1". How it can be implemented?

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• php code to mysql database export

  - by kumar

  i want php code to import *.sql file to database and export db to *.sql file without going to phpmyadmin

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• two where conditions in a mysql query

  - by Kaartz

  I have a table like below |date|dom|guid|pid|errors|QA|comm| |2010-03-22|xxxx.com|jsd3j234j|ab|Yes|xxxxxx|bad| |2010-03-22|xxxx.com|jsd3j234j|ab|No|xxxxxx|| |2010-03-22|xxxx.com|jsd3j234j|if|Yes|xxxxxx|bad| |2010-03-22|xxxx.com|jsd3j234j|if|No|xxxxxx|| |2010-03-22|xxxx.com|jsd3j234j|he|Yes|xxxxxx|bad| |2010-03-22|xxxx.com|jsd3j234j|he|No|xxxxxx|| I want to retrieve the total count of "dom" referred to each "QA" and also I need the count of "errors" detected by the "QA" SELECT date, count(dom), QA FROM reports WHERE date="2010-03-22" GROUP BY QA |2010-03-22|2|ab| |2010-03-22|2|if| |2010-03-22|2|he| SELECT date, count(dom), count(errors), QA FROM reports WHERE errors="Yes" GROUP BY QA |2010-03-22|1|ab| |2010-03-22|1|if| |2010-03-22|1|he| I want to combine the above two queries, is it possible. If I use the below query, I am not getting the desired result. SELECT date, count(dom), QA, count(errors) FROM reports WHERE date="2010-03-22" AND errors="Yes" GROUP BY QA I want the below output |2010-03-22|2|ab|1| |2010-03-22|2|if|1| |2010-03-22|2|he|1| Please help me.

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