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  • How to display records below form on submission in php without the use of database?

    - by OM The Eternity
    I have a form with multiple fields in it along with a image input field, just below the form i have a list to be displayed on every submit of this form... this has to be done without the use of DB.. I think this can be achieved by using session but its not working with me, as evrytime page gets refreshed and session gets recreated/reset.. Please help me in resolving this issue

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  • Is it possible to make ListView display a text obtained through its ListViewItem.Tag?

    - by Dimitri C.
    I'd like to fill System.Windows.Forms.ListView with the items I've stored in a separate System.Collections.Generics.List<. I would like to avoid to store the data twice, once in the List< and once as a string in ListViewItem. Is there a way to make ListViewItem use some callback function to obtain the text to put in its columns from the Tag property, instead of using its Text property?

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  • How to Display Validation Error Messages on a Page?

    - by Yardstermister
    I am pretty new to ASP.NET and C# I have spent the day learning the basics of the ASP.NET Membership provider I have built all my validator but are getting stuck at outputting my error message on the page. private void LogCreateUserError(MembershipCreateStatus status, string username) { string reasonText = status.ToString(); switch (status) { case MembershipCreateStatus.DuplicateEmail: case MembershipCreateStatus.DuplicateProviderUserKey: case MembershipCreateStatus.DuplicateUserName: reasonText = "The user details you entered are already registered."; break; case MembershipCreateStatus.InvalidAnswer: case MembershipCreateStatus.InvalidEmail: case MembershipCreateStatus.InvalidProviderUserKey: case MembershipCreateStatus.InvalidQuestion: case MembershipCreateStatus.InvalidUserName: case MembershipCreateStatus.InvalidPassword: reasonText = string.Format("The {0} provided was invalid.", status.ToString().Substring(7)); break; default: reasonText = "Due to an unknown problem, we were not able to register you at this time"; break; } //CODE TO WRITE reasonText TO THE HTML PAGE ?? } What is the best way to output the varible result onto the page as I have relied upon the built in ASP:Validators until now.

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  • Display web page from another site in asp page.

    - by Daniel
    hi all, Our customer has a requirement to extend the functionality of their existing large government project. It is an ASP.NET 3.5 (recently upgraded from 2.0) project. The existing solution is quite a behemoth that is almost unmaintainable so they have decided that they want to provide the new functionality by hosting it on another website that is shown within the existing website. As to how this is best to be done I'm not quite sure right now and if there is any security issues preventing it or that need to be considered. Essentially the user would log on to the existing web site as normal and when cliicking on a certain link the page would load as normal with some kind of frame or control that has within it the contents of the page from the other site. IE. They do not want to simply redirect to the other site they want to show it embedded within the current one such that the existing menus etc are still available. I believe if information needed to be passed to the embedded page it would be done using query strings as I'm not sure if there is even another way to accomplish this. Can anyone give me some pointers on where to start at looking to implement this or any potential pitfalls I should be aware of. Thanks

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  • Can I accesss an external file when testing an R package?

    - by Abe
    I am using the testthat package to test an R package that is within a larger repository. I would like to test the contents of a file outside of the R package. Can I reference a file that is located outside of an R package while testing? What I have tried A reproducible example can be downloaded as MyRepo.tar.gz My repository is called "myRepo", and it includes an R package, "myRpkg" and a folder full of miscellaneous scripts ~/MyRepo/ ~/MyRepo/MyRpkg ~/MyRepo/Scripts The tests in "MyRpkg" are in the /tests/ folder ~/myRepo/myRpkg/tests/test.myscript.R And I want to be able to test a file in the Scripts folder: ~/MyRepo/Scripts/myscript.sh I would like to read the script to test the contents of the first line doing something like this: check.script <- readLines("../../../Scripts/myscript.sh")[1] expect_true(grepl("echo", check.script)) This works fine if I start from the MyRepo directory: cd ~/MyRepo R CMD check MyRpkg But if I move to another directory, it fails: cd R CMD check MyRepo/MyRpkg

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  • ActionScript Local X And Y Coordinates Of Display Object?

    - by TheDarkIn1978
    i'm trying to trace the x and y coordinates from within a sprite. i've added a rectangle to the stage: var rect:Rectangle = new Rectangle(10, 10, 200, 200); addChild(rect); adding a Mouse_Move event to the rect, i can trace mouseX and mouseY to receive the coordinates of the stage while moving over the rect, but how do i get the local x and y coordinates? so if i mouse over the very top left of the rect sprite, the mouseX and mouseY return 10 as the global coordinates, but how do i make it return 0 and the local coordinates of the sprite? i assumed localX and localY was what i was looking for, but this doesn't work: function mouseOverTraceCoords(evt:MouseEvent):void { trace(mouseX, mouseY, evt.localX, evt.localY); }

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  • How do I display and calculate numbers from a database on iPhone?

    - by JoshD
    I am new to designing apps and have a basic understand of Ob-C and how everything works. What I would like to do is have two tabs, one is a home screen that displays numbers and percentages that are entered on the second tab. The user will be able to store that information and refer back to it and update it. What is the best way to complete that math from the database to the "home screen"? Any tutorials, advice is great! Thanks.

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  • How to avoid lost calls to an external JS file before loading it.

    - by David
    Hi, My issue is that multiple websites are going to include my JS file and when calling something like this: <script src="..."></script> hello.say("yay"); there going to be a race issue so sometimes it could make it sometimes not. i know that i can solve that easily by putting every function in a window.onload but that wouldn't be clean as i've seen other websites magically solve that like google analytics: .. Calling google analytics JS.. <script type="text/javascript"> try{ var pageTracker = _gat._getTracker("UA-xxxxxx-x"); <-- this an object ! pageTracker._trackPageview(); } catch(err) {} </script> How to do that?

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  • How to display popup from code-behind in ASP.net ?

    - by user359706
    hello I wonder how it would be possible to launch a series of popups, containing a form, from code-behind. I possess a list of objects 'Products' and I wish I could change one property (quantity) of each "product". Here's how I build my list (normally I use a database). Private List<Product> listProduct; listProduits = new List<Product>(); Product objProduit_1 = new Produit; objProduct_1.ref = "001"; objProduct_1.article = "G900"; objProduct_1.quantity = 30; listProducts.Add(objProduct_1); ProductobjProduit_2 = new Product; objProduct_2.ref = "002"; objProduct_2.article = "G900"; objProduct_2.quantity = 35; listProduits.Add(objProduct_2); And I would like displayed popup one after one. Thank you in advance for your help

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  • Display "custom" view (various images, various text). Should I use UIWebView?

    - by aw
    First: No, none of the content should be loaded from the web. All content parts are shipped with the main bundle. I have n images and mass of text (including lists). Instead of building all view parts programmatically in objective-c if was thinking of using an UIWebView and build "only" the HTML dynamically. Does anything speaks against it? How does UIWebView work with local content? Links and resources welcome. Thanks

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  • Using PHP's exec() function (or the likes), how can you display terminal error output?

    - by Miciah Amberong
    Previous Reference I am just wondering if there's a way (using PHP) to output the compile error information from the terminal to the browser? For example: If you use this code to execute in the terminal... gcc -o try try.c ...and assuming the "try.c" have some errors. The terminal will output something like this: try.c In function 'main': try.c:27 'x' undeclared (first use in this function) try.c:27 (Each undeclared identifier is reported only once try.c:27 for each function it appears in.) Meanwhile, using this PHP code... <?php exec("gcc -o try try.c"); ?> The browser does not return any output like the terminal does. Is there a possible way direct or indirect that the error details that the terminal showed can be passed to the be displayed on a browser? Thank you very much.

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  • Should the program logic reside inside the gui object class or be external to the class?

    - by hd112
    I have a question about how to structure code in relation to GUI objects. Suppose I have a dialog that has a list control that has a bunch of names obtained from a database. The user can edit the names. Does the logic reside inside that dialog class or should it be from the outside. To illustrate what I mean, here’s some pseudo code showing the structure of the code when the logic is handled outside the dialog class: NamesDialog : wxDialog { Private: ..stuff.. Public: ... SetNames(wxStringArray names); wxStringArray GetNames(); ..stuff.. } So the user of the class would do something like: wxStringArray names = DatabaseManager::Get()->GetNames(); names.Sort(); NamesDialogObject.SetNames(names); NamesDialogObject.ShowModal(); wxStringArray modified_names = NamesDialogObject.GetNames(); AddToDatabase(modified_names); //or something like this. On the other hand, the database logic can reside inside the NamesDialog class itself. In the show method I can query the database for the names and as the user interacts with the controls (list control in this case), the database can be updated from the event handlers. As a result the NamesDialog class only has the Show() method as there is no need to use SetNames or GetNames() etc. Which method is generally preferred? I don’t have much work experience so I’m not sure which is the proper way to handle it. Sometimes it's easier to handle everything in the class but getting access to objects it interacts with can be challenging. Generally can do it by having the relevant objects be singletons like the database manager in the above example.

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  • How to split the chance to display SWFs evenly among banner collection?

    - by Michael Mao
    Hi all: I am working on The ausdcf.org to try adding several banner ads in swf format to the top. Everything starts to work, but I've got several questions that need your help: The client chose not to go with Google AdManager, but prefer a "minimal approach" to do this task. What I am trying to do is sort of "mimicking" the way Google AdManager does for banners, that is, to split the chance of each particular swf to be shown to the visitor evenly among the banner collection. Definitely I can add some jQuery code to do this from client-side, a random number generator and if-else statement would work - just $.load() it! However, what if I'd like to make sure those disabled Javascript (is there any now btw?) still be able to see different swfs in each visit. Any suggestion on how to approach this? Many thanks in advance.

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  • How to display after 4 week date from now?I want to pass an argument.

    - by vinothkumar
    echo date( "F jS, Y" , strtotime("now +3 weeks") ); It gives the result as July 2nd, 2010 . Fine.Now I want to pass the argument like this. The original print_r($originalamount) give the result like this Array ( [0] = 4 Months [1] = 3500 ) My code $text=trim($originalamount[0]); $text1="now +".$text; echo date( "F jS, Y" , strtotime($text1)) ; The out put come like this December 31st, 1969 I dont know why?

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  • Setting CSS attributes on Change using jQuery

    - by Nick B
    I want to change css visibility and display attributes using jQuery on click when the state of another div's visibility attribute changes. (Many apologies for the obfuscated markup, but needing to manipulate someone else's construction): There are four instances of [data-label="Checkbox"] [data-label="Checked"] in this page. I want to set [data-label="trash"] and [data-label="Sort Options"] to visibility: visible; display: [empty value] when any of the [data-label="Checkbox"] [data-label="Checked"]'s attributes changes to 'visibility', 'visible'. Else, if none of [data-label="Checkbox"] [data-label="Checked"]'s have the attribute 'visibility', 'visible', I want to set [data-label="trash"] and [data-label="Sort Options"] back to their initial states: display: none; visibility: hidden;. Here's the markup: <div data-label="Sort Options" style="display: none; visibility: hidden;"> <div data-label="trash" style="display: none; visibility: hidden;"></div> </div> <div data-label="Checkbox"> <div data-label="Unchecked"></div> <div data-label="Checked" style="display: none; visibility: hidden;"></div> </div> Here is what I have tried unsuccessfully: $('[data-label="Checkbox"]').click(function() { if ('[data-label="Checkbox"] [data-label="Checked"]').css('visibility', 'visible') { $('[data-label="trash"], [data-label="Sort Options"]').css({'display': '', 'visibility': 'visible'}); } else { $('[data-label="trash"], [data-label="Sort Options"]').css({'display': 'none', 'visibility': 'hidden'}); } }); Any help would be greatly appreciated! Thanks

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  • How do you display a PHPmyadmin table onto a web browser/web page?

    - by user1390754
    Just a simple question, i've been searching around and for some reason i cannot find an answer to this. after creating a database/table in Phpmyadmin using xampp, what command do i need to put into my webpage (PHP) to show the table I made? I know the first step involves connecting to the database and i think i've done that properly. This is the code i found from somewhere about connecting (w3 tutorials I believe) $con = mysql_connect("localhost","xxxxxx,""); if (!$con) { die('Could not connect: ' . mysql_error()); }

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