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  • How do I find out what process Id and thread id / name has a file open

    - by peter
    Hi All, I am using C# in an application and am having some problems with a file becoming locked. The piece of code does this, while (true) { Read a packet from a socket (with data in it to add to the file) Open a file Writes data to it Close a file } But in the process the file becomes locked. I don't really understand how, we are are definately catching and reporting exceptions so I don't see how the file doesn't get closed every time. My best guess is that something else is opening the file, but I want to prove it. Can someone please provide a piece of code to check whether the file is open and if so report what processid and threadid has the file open. For example if I had this code, StreamWriter streamWriter1 = new StreamWriter(@"c:\logs\test.txt"); streamWriter1.WriteLine("Test"); // code to check for locks?? StreamWriter streamWriter2 = new StreamWriter(@"c:\logs\test.txt"); streamWriter1.Close(); streamWriter2.Close(); That will throw an exception because the file is locked when we try and open it the second time. So where the comment is what could I put in there to report that the current app (process Id) and the current thread (thread Id) have the file locked? Thanks.

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  • Ruby: Is there a better way to iterate over multiple (big) files?

    - by zxcvbnm
    Here's what I'm doing (sorry for the variable names, I'm not using those in my code): File.open("out_file_1.txt", "w") do |out_1| File.open("out_file_2.txt", "w") do |out_2| File.open_and_process("in_file_1.txt", "r") do |in_1| File.open_and_process("in_file_2.txt", "r") do |in_2| while line_1 = in_1.gets do line_2 = in_2.gets #input files have the same number of lines #process data and output to files end end end end end The open_and_process method is just to open the file and close it once it's done. It's taken from the pickaxe book. Anyway, the main problem is that the code is nested too deeply. I can't load all the files' contents into memory, so I have to iterate line by line. Is there a better way to do this? Or at least prettify it?

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  • python gio waiting for async operations to be done

    - by pygabriel
    I have to mount a WebDav location and wait for the operation to be finished before to proceed (it's a script). So I'm using the library in this way: location = gio.File("dav://server.bb") location.mount_enclosing_volume(*args,**kw) # The setup is not much relevant location.get_path() # Returns None because it's not yet mounted since the call is async How to wait until the device is mounted?

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  • How to walk through two files simultaneously in Perl?

    - by Alex Reynolds
    I have two text files that contain columnar data of the variety position-value. Here is an example of the first file (file A): 100 1 101 1 102 0 103 2 104 1 ... Here is an example of the second file (B): 20 0 21 0 ... 100 2 101 1 192 3 193 1 ... Instead of reading one of the two files into a hash table, which is prohibitive due to memory constraints, what I would like to do is walk through two files simultaneously, in a stepwise fashion. What this means is that I would like to stream through lines of either A or B and compare position values. If the two positions are equal, then I perform a calculation on the values associated with that position. Otherwise, if the positions are not equal, I move through lines of file A or file B until the positions are equal (when I again perform my calculation) or I reach EOF of both files. Is there a way to do this in Perl?

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  • Can .NET load and parse a properties file equivalent to Java Properties class?

    - by Tai Squared
    Is there an easy way in C# to read a properties file that has each property on a separate line followed by an equals sign and the value, such as the following: ServerName=prod-srv1 Port=8888 CustomProperty=Any value In Java, the Properties class handles this parsing easily: Properties myProperties=new Properties(); FileInputStream fis = new FileInputStream (new File("CustomProps.properties")); myProperties.load(fis); System.out.println(myProperties.getProperty("ServerName")); System.out.println(myProperties.getProperty("CustomProperty")); I can easily load the file in C# and parse each line, but is there a built in way to easily get a property without having to parse out the key name and equals sign myself? The C# information I have found seems to always favor XML, but this is an existing file that I don't control and I would prefer to keep it in the existing format as it will require more time to get another team to change it to XML than parsing the existing file.

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  • Check to see if file transfer is complete

    - by Cymon
    We have a daily job that processes files delivered from an external source. The process usually runs fine without any issues but every once in a while we have an issue of attempting to process a file that is not completely transferred. The external source SCPs these files from a UNIX server to our Windows server. From there we try to process the files. Is there a way to check to see if a file is still being transferred? Does UNIX put a lock on a file while SCPing it that we could check on the Windows side?

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  • Java Scanner won't follow file

    - by Steve Renyolds
    Trying to tail / parse some log files. Entries start with a date then can span many lines. This works, but does not ever see new entries to file. File inputFile = new File("C:/test.txt"); InputStream is = new FileInputStream(inputFile); InputStream bis = new BufferedInputStream(is); //bis.skip(inputFile.length()); Scanner src = new Scanner(bis); src.useDelimiter("\n2010-05-01 "); while (true) { while(src.hasNext()){ System.out.println("[ " + src.next() + " ]"); } } Doesn't seem like Scanner's next() or hasNext() detects new entries to file. Any idea how else I can implement, basically, a tail -f with custom delimiter. ok - using Kelly's advise i'm checking & refreshing the scanner, this works. Thank you !! if anyone has improvement suggestions plz do! File inputFile = new File("C:/test.txt"); InputStream is = new FileInputStream(inputFile); InputStream bis = new BufferedInputStream(is); //bis.skip(inputFile.length()); Scanner src = new Scanner(bis); src.useDelimiter("\n2010-05-01 "); while (true) { while(src.hasNext()){ System.out.println("[ " + src.next() + " ]"); } Thread.sleep(50); if(bis.available() > 0){ src = new Scanner(bis); src.useDelimiter("\n2010-05-01 "); } }

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  • Spaces while using "Print" in VBA

    - by Josh
    For some reason I am getting a lot of spaces in front of each value while trying to print to a flat text file. 'append headers Cells(start_row - 2, 1).Select For i = 1 To ActiveCell.SpecialCells(xlLastCell).Column If ActiveCell.Offset(0, 1).Column = ActiveCell.SpecialCells(xlLastCell).Column Then Print #finalCSV, Cells(start_row - 2, i) & "\n", Else Print #finalCSV, Cells(start_row - 2, i) & ",", End If Next i Example output: DC Capacity:hi, Resistive Capacity:lo, Resistive Capacity:hi, Reactive Capacity:lo, Is there any way to get rid of these spaces?

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  • Getting Error When Opening Files

    - by Nathan Campos
    I'm developing a simple Text Editor to understand better PocketC language, then I've done this: #include "\\Storage Card\\My Documents\\PocketC\\Parrot\\defines.pc" int filehandle; int file_len; string file_mode; initComponents() { createctrl("EDIT", "test", 2, 1, 0, 24, 70, 25, TEXTBOX); wndshow(TEXTBOX, SW_SHOW); guigetfocus(); } main() { filehandle = fileopen(OpenFileDlg("Plain Text Files (*.txt)|*.txt; All Files (*.*)|*.*"), 0, FILE_READWRITE); file_len = filegetlen(filehandle); if(filehandle = -1) { MessageBox("File Could Not Be Found!", "Error", 3, 1); } initComponents(); editset(TEXTBOX, fileread(filehandle, file_len)); } Then I tried to run the application, it opens the Open File Dialog, I select a file(that is at \test.txt) that I've created with notepad, then I got my MessageBox saying that the file wans't found. Then I want to know why I'm getting this if the file is all correct? *PS: When I click to exit the MessageBox, I saw that the TextBox is displaying where the file is(I've tested with many other files, and with all I got the error and this).

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  • Not able to open a file in php

    - by ehsanul
    The following code works when invoking through the command line with php -f test.php, from root. It does not work though when being invoked via apache when loading the php page. The code chokes at fopen() and the resulting web page just says "can't open file". <?php $fp = fopen("/path/to/some_file.txt","a") or die("can't open file"); fwrite($fp,"some text"); fclose($fp); ?> I tried to play with the file permissions, but to no avail. I changed the user/group with chown apache:apache test.php and changed permissions with chmod 755 test.php. Here is the relevant result of ls -l /path/to/some_file.txt: -rwxr-xr-x 1 apache apache 0 Apr 12 04:16 some_file.txt

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  • Execute a Application On The Server Using PHP

    - by Nathan Campos
    I have an application on my server that is called leaf.exe, that haves two arguments needed to run, they are: inputfile and outputfile, that will be like this example: pnote.exe input.pnt output.txt The executable is at exec/, inputfile is at upload/ and outputfile is on compiled/. But I need that a PHP could run the application like that, then I want to know: How could I do this? How could I echo the output of the program?

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  • question about fgets

    - by user105033
    Is this safe to do? (does fgets terminate the buffer with null) or should I be setting the 20th byte to null after the call to fgets before i call clean. // strip new lines void clean(char *data) { while (*data) { if (*data == '\n' || *data == '\r') *data = '\0'; data++; } } // for this, assume that the file contains 1 line no longer than 19 bytes // buffer is freed elsewhere char *load_latest_info(char *file) { FILE *f; char *buffer = (char*) malloc(20); if (f = fopen(file, "r")) if (fgets(buffer, 20, f)) { clean(buffer); return buffer; } free(buffer); return NULL; }

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  • Ten latest files on disk

    - by Artic
    I need effective algorithm to keep only ten latest files on disk in particular folder to support some kind of publishing process. Only 10 files should present in this folder at any point of time. Please, give your advises what should be used here.

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  • Import and Export for CSV are both broken in Mathematica

    - by dreeves
    Consider the following 2 by 2 array: x = {{"a b c", "1,2,3"}, {"i \"comma-heart\" you", "i \",heart\" u, too"}} If we Export that to CSV and then Import it again we don't get the same thing back: Import[Export["tmp.csv", d]] Looking at tmp.csv it's clear that the Export didn't work, since the quotes are not escaped properly. According to the RFC which I presume is summarized correctly on Wikipedia's entry on CSV, the right way to export the above array is as follows: a b c, "1,2,3" "i ""heart"" you", "i "",heart"" u, too" Importing the above does not yield the original array either. So Import is broken as well. I've reported these bugs to [email protected] but I'm wondering if others have workarounds in the meantime. One workaround is to just use TSV instead of CSV. I tested the above with TSV and it seems to work (even with tabs embedded in the entries of the array).

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  • How do I take advantage of Android's "Clear Cache" button

    - by Jay Askren
    In Android's settings, in the "Manage Applications" activity when clicking on an app, the data is broken down into Application, Data, and cache. There is also a button to clear the cache. My app caches audio files and I would like the user to be able to clear the cache using this button. How do I store them so they get lumped in with the cache and the user can clear them? I've tried storing files using both of the following techniques: newFile = File.createTempFile("mcb", ".mp3", context.getCacheDir()); newFile = new File(context.getCacheDir(), "mcb.mp3"); newFile.createNewFile(); In both cases, these files are listed as Data and not Cache.

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  • ASP.net file operations delay

    - by mtranda
    Ok, so here's the problem: I'm reading the stream from a FileUpload control, reading in chunks of n bytes and writing the array in a loop until I reach the stream's end. Now the reason I do this is because I need to check several things while the upload is still going on (rather than doing a Save(); which does the whole thing in one go). Here's the problem: when doing this from the local machine, I can see the file just fine as it's uploading and its size increases (had to add a Sleep(); clause in the loop to actually get to see the file being written). However, when I upload the file from a remote machine, I don't get to see it until the the file has completed uploading. Also, I've added another call to write the progress to a text file as the progress is going on, and I get the same thing. Local: the file updates as the upload goes on, remote: the token file only appears after the upload's done (which is somewhat useless since I need it while the upload's still happening). Is there some sort of security setting in (or ASP.net) that maybe saves files in a temporary location for remote machines as opposed to the local machine and then moves them to the specified destination? I would liken this with ASP.net displaying error messages when browsing from the local machine (even on the public hostname) as opposed to the generic compilation error page/generic exception page that is shown when browsing from a remote machine (and customErrors are not off) Any clues on this? Thanks in advance.

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  • How do I write to a file and print to a terminal cuncurrently in Unix?

    - by bias
    I have a little bash function to log my Macports outputs to a file (since installs often spew little tidbits that are easy to lose in terminal noise), then I just cat the file to the terminal: function porti { command sudo port install $@ >> $1.log 2>&1; cat $1.log } Is there a way to do this concurrently? I don't care about it being in Bash, that's just how I started it. BTW I pass $@ to install but only $1 for the file name so that I can do something like: porti git-gore +bash_completion and only get the file git-core.log however someone else might prefer to include variants in the file name ...

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  • C++: ifstream::getline problem

    - by Jay
    I am reading a file like this: char string[256]; std::ifstream file( "file.txt" ); // open the level file. if ( ! file ) // check if the file loaded fine. { // error } while ( file.getline( string, 256, ' ' ) ) { // handle input } Just for testing purposes, my file is just one line, with a space at the end: 12345 My code first reads the 12345 successfully. But then instead of the loop ending, it reads another string, which seems to be a return/newline. I have saved my file both in gedit and in nano. And I have also outputted it with the Linux cat command, and there is no return on the end. So the file should be fine. Why is my code reading a return/newline? Thanks.

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  • Problem with reading file line-by-line

    - by Maulrus
    I'm trying to complete an exercise to write a program that takes the following command line arguments: an input file, an output file, and an unspecified number of words. The program is to read the contents of the input file line by line, find for each word given which lines contain the word, and print the lines with their line number to the output file. Here's my code: #include <iostream> #include <fstream> #include <string> #include <sstream> using namespace std; int main(int argc, char* argv[]) { if (argc < 4) { cerr << "Error #1: not enough arguments provided\n"; return 1; } ifstream in(argv[1]); if (!in.is_open()) { cerr << "Error #2: input file could not be opened\n"; return 2; } ofstream out(argv[2]); if (!out.is_open()) { cerr << "Error #3: output file could not be opened\n"; return 3; } ostringstream oss; for (int i = 3; i < argc; ++i) { int k = 0; string temp; oss << argv[i] << ":\n\n"; while (getline(in, temp)) { ++k; unsigned x = temp.find(argv[i]); if (x != string::npos) oss << "Line #" << k << ": " << temp << endl; } } string copy = oss.str(); out << copy; in.close(); out.close(); return 0; } If I try to run that, I get the predicted output for the first word given, but any words following it aren't found. For example, for the source code above will give the following output: in: Line #1: #include <iostream> Line #2: #include <fstream> Line #3: #include <string> Line #4: #include <sstream> Line #5: using namespace std; Line #7: int main(int argc, char* argv[]) { Line #12: ifstream in(argv[1]); Line #13: if (!in.is_open()) { Line #14: cerr << "Error #2: input file could not be opened\n"; Line #22: ostringstream oss; Line #23: string temp; Line #24: for (int i = 3; i < argc; ++i) { Line #26: int k = 0; Line #28: while (getline(in, temp)) { Line #30: unsigned x = temp.find(argv[i]); Line #31: if (x != string::npos) Line #32: oss << "Line #" << k << ": " << temp << endl; Line #35: string copy = oss.str(); Line #37: in.close(); out: That is, it'll find all the instances of the first word given but not any following. What am I doing wrong here?

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  • How can i zip files in Java and not include files paths

    - by Ignacio
    For example, i want to zip a file stored in /Users/me/Desktop/image.jpg I maded this method: public static Boolean generateZipFile(ArrayList<String> sourcesFilenames, String destinationDir, String zipFilename){ // Create a buffer for reading the files byte[] buf = new byte[1024]; try { // VER SI HAY QUE CREAR EL ROOT PATH boolean result = (new File(destinationDir)).mkdirs(); String zipFullFilename = destinationDir + "/" + zipFilename ; System.out.println(result); // Create the ZIP file ZipOutputStream out = new ZipOutputStream(new FileOutputStream(zipFullFilename)); // Compress the files for (String filename: sourcesFilenames) { FileInputStream in = new FileInputStream(filename); // Add ZIP entry to output stream. out.putNextEntry(new ZipEntry(filename)); // Transfer bytes from the file to the ZIP file int len; while ((len = in.read(buf)) > 0) { out.write(buf, 0, len); } // Complete the entry out.closeEntry(); in.close(); } // Complete the ZIP file out.close(); return true; } catch (IOException e) { return false; } } But when i extract the file, the unzipped files have the full path. I don't want the full path of each file in the zip i only want the filename. How can i made this?

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  • IOCP multiple socket completionports in same container

    - by Ohmages
    For the past couple of days I have been thinking about how to solve one of my problems I am facing, and I have tried to research the topic but don't really know what I can do. I have 2 sockets in the same struct that both have the same completionport. Problem is, they both use different protocols. Is there a way that I can find out which socket got triggered? Their called game_socket, and client_socket Example code would be something like... while (true) { error = GetQueuedCompletionStatus(CompletionPort, &BytesTransfered, (PULONG_PTR)&Key, &lpOverlapped, 0); srvc = CONTAINING_RECORD ( lpOverlapped, client , ol ); if ( error == TRUE ) { cout << endl << "SOCKET: [" << srvc->client_socket << "] TRIGGERED - WORKER THREAD" << endl; cout << endl << "BytesTransfered: [" << BytesTransfered << "]" << endl; if ( srvc->game_client triggered ) { // .. this code } else { // .. this code } Any ideas our help would be appreciated :)

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  • serving files using django - is this a security vulnerability

    - by Tom Tom
    I'm using the following code to serve uploaded files from a login secured view in a django app. Do you think that there is a security vulnerability in this code? I'm a bit concerned about that the user could place arbitrary strings in the url after the upload/ and this is directly mapped to the local filesystem. Actually I don't think that it is a vulnerability issue, since the access to the filesystem is restricted to the files in the folder defined with the UPLOAD_LOCATION setting. UPLOAD_LOCATION = is set to a not publicly available folder on the webserver url(r'^upload/(?P<file_url>[/,.,\s,_,\-,\w]+)', 'aeon_infrastructure.views.serve_upload_files', name='project_detail'), @login_required def serve_upload_files(request, file_url): import os.path import mimetypes mimetypes.init() try: file_path = settings.UPLOAD_LOCATION + '/' + file_url fsock = open(file_path,"r") file_name = os.path.basename(file_path) file_size = os.path.getsize(file_path) print "file size is: " + str(file_size) mime_type_guess = mimetypes.guess_type(file_name) if mime_type_guess is not None: response = HttpResponse(fsock, mimetype=mime_type_guess[0]) response['Content-Disposition'] = 'attachment; filename=' + file_name #response.write(file) except IOError: response = HttpResponseNotFound() return response

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  • Abort a slow flush to disk after write?

    - by Therealstubot
    Is there a way to abort a python write operation in such a way that the OS doesn't feel it's necessary to flush the unwritten data to the disc? I'm writing data to a USB device, typically many megabytes. I'm using 4096 bytes as my block size on the write, but it appears that Linux caches up a bunch of data early on, and write it out to the USB device slowly. If at some point during the write, my user decides to cancel, I want the app to just stop writing immediately. I can see that there's a delay between when the data stops flowing from the application, and the USB activity light stops blinking. Several seconds, up to about 10 seconds typically. I find that the app is holding in the close() method, I'm assuming, waiting for the OS to finish writing the buffered data. I call flush() after every write, but that doesn't appear to have any impact on the delay. I've scoured the python docs for an answer but have found nothing.

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