Search Results

Search found 24229 results on 970 pages for 'users rights'.

Page 212/970 | < Previous Page | 208 209 210 211 212 213 214 215 216 217 218 219  | Next Page >

  • 'Unable to read symbols' error

    - by cannyboy
    When I 'Build and Go' on the device, the console shows: warning: Unable to read symbols for ""/Users/Steve/Blue/build/Debug-iphoneos"/Blue.app/Blue" (file not found). warning: Unable to read symbols for ""/Users/Steve/Blue/build/Debug-iphoneos"/Blue.app/Blue" (file not found). Is this something I should worry about? If so, where should I look to find the root of the issue? The app works OK, but I'm just worried that this might be an AppStore approval issue.

    Read the article

  • How to build a widget for my website

    - by Gublooo
    Hey guys I'm very new to the whole programming - so far I only have experience with building websites, database etc. I currently have a website where users can share their online purchases. I want to build a widget that other websites can integrate on their site. Users should be able to insert their purchases directly through this widget without having to come to my website. Thats the idea but I have no idea how to go about it - can anyone point me in the right direction. Thanks

    Read the article

  • How to add a new page in Lift framework

    - by portoalet
    How can I add a new page in the webapp directory in lift that can be accessed by users? Currently only the index.html can be accessed through http://localhost:8080/ or http://localhost:8080/index.html Say I add a static file newpage.html into webapp dir, then what can I do so users can access it through http://localhost:8080/newpage.html ?

    Read the article

  • home directory and .emacs file in Windows 7

    - by prosseek
    I installed emacs 23.3.1 in c:/emacs-23.3. Following the hints in this page, I updated the site-start.el to set HOME environment variable. (setenv "HOME" "c:/users/USER/emacs") And I made c:/users/USER/.emacs (like I did in unix/mac) to write the code for using slime, but it doesn't seem to start slime correctly. Is this a correct way of setting emacs in Windows 7? Where do I put the .emacs file?

    Read the article

  • Django - 2 fields unique together

    - by webvulture
    Suppose, I want to record say poll choices by users everyday. In this case, i have a table named vote which has columns poll , choice and user-id . So how can i out the constraint (maybe in the django models or wherever possible) that poll and user-id both should not be the same for any entry but like the same user can vote for various different polls once and obviously various users can vote for the same poll. I hope I am clear.

    Read the article

  • Paging in MVC + Jquery

    - by kart
    Dear all, I need to add paging for my users view page, i got all the datas using Json to show in the table..i need to add paging and and also i can able to change number of users to show in a particular page. any simple Jquery plugin or source code will be very much helpful to me. thanks in advance, K

    Read the article

  • Checking up remotely on Website Usage

    - by Raj More
    A client of mine has a pure HTML website that was built in the dark ages - they want me to find where their users are coming from, how many individual users there are, etc. They want to know if the site is being used enough for them to invest the money into renovating it. I am remote from their site and do not have access to their web server. Is there something like ComScore for small sites that I can go into to check their usage statistics?

    Read the article

  • Reading a Text file in xcode

    - by Nicolaj Zefting
    First off, I'm a complete beginner. This might be a stupid question, but here it goes: I'm currently working on an App than contains Latin texts that the users can view and read. I'm using Xcode 4 with the storybord function. Theway the app is built: user selects author - then the book - then app shows the text. I am kind of confused because i need to have various text files, depending on the users choice.

    Read the article

  • mysql multi count() in one query

    - by atno
    Hi, I'm trying to count several joined tables but without any luck, what I get is the same numbers for every column (tUsers,tLists,tItems). My query is: select COUNT(users.*) as tUsers, COUNT(lists.*) as tLists, COUNT(items.*) as tItems, companyName from users as c join lists as l on c.userID = l.userID join items as i on c.userID = i.userID group by companyID The result I want to get is --------------------------------------------- # | CompanyName | tUsers | tlists | tItems 1 | RealCoName | 5 | 2 | 15 --------------------------------------------- what modifications do i have to do to my query to get those results? Cheers

    Read the article

  • Hibernate not Loading a class

    - by Noor
    Hi, I have a class Auction that contains a Class Item and Users but when I am getting the class, the class item and Users are not being loaded. Auction Class Mapping File: <?xml version="1.0"?> <!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd"> <!-- Generated Dec 28, 2010 9:14:12 PM by Hibernate Tools 3.4.0.Beta1 --> <hibernate-mapping> <class name="com.BiddingSystem.Models.Auction" table="AUCTION"> <id name="AuctionId" type="long"> <column name="AUCTIONID" /> <generator class="native" /> </id> <property name="StartTime" type="java.util.Date"> <column name="STARTTIME" /> </property> <property name="EndTime" type="java.util.Date"> <column name="ENDTIME" /> </property> <property name="StartingBid" type="long"> <column name="STARTINGBID" /> </property> <property name="MinIncrement" type="long"> <column name="MININCREMENT" /> </property> <many-to-one name="CurrentItem" class="com.BiddingSystem.Models.Item" fetch="join" cascade="all"> <column name="ItemId" /> </many-to-one> <property name="AuctionStatus" type="java.lang.String"> <column name="AUCTIONSTATUS" /> </property> <property name="BestBid" type="long"> <column name="BESTBID" /> </property> <many-to-one name="User" class="com.BiddingSystem.Models.Users" fetch="join"> <column name="UserId" /> </many-to-one> </class> </hibernate-mapping> When I am doing this: Query query=session.createQuery("from Auction where UserId="+UserId); List <Auction> AllAuctions= new LinkedList<Auction>(query.list()); The Users and Item are null

    Read the article

  • Update just one field from backup

    - by justSteve
    I'm looking to restore one field from a backup and can't find the syntax for an update statement that can look at 2 different catalogs. Seems like it should be something fairly close to: update users set idUserCompany = (select idUserCompany from .myBackup.dbo.users uT) where uT.idUser = idUser

    Read the article

  • SQLAlchemy: an efficient/better select by primary keys?

    - by hadrien
    Yet another newbie question.. Let's say I have an user table in declarative mode: class User(Base): __tablename__ = 'user' id = Column(u'id', Integer(), primary_key=True) name = Column(u'name', String(50)) When I have a list of users identifiers, I fetch them from db with: user_ids = [1, 2, 3, 4, 5] users = Session.query(User).filter(User.id.in_(user_ids)).all() I dislike using in_ because I think I learned it has bad performance on indexed fields (is that true/false?). Anyway, is there a better way doing that query? Thanks!

    Read the article

  • Anyone know any good backend user online file manager?

    - by skyhigh
    Hi I'm looking for a backend system where your clients can login and upload files to your server, download files from the server and you can delete the users, create users, etc. I do not know the proper name for this kind of software. Maybe its called online file manager? Any recommendations? My server supports PHP, apache and mysq. Thanks

    Read the article

  • PODS + WordPress + User Registration

    - by Sharath
    So I have PODS installed on my wordpress site that I am developing. I need to put up a user registration system such that once the user registers, he/she can be directed to POD pages that I have created. Can I just use the default registration system that comes with wordpress and redirect users based on a default role I assign to them? I basically don't want my potential users to view any part of the admin site. Any help is appreciated.

    Read the article

  • Entity framework 4 add to many-to-many

    - by mehanik
    I have model whith 3 tabels and one is link table with additional field: Groups Id Name Users Id Name Roles Id Name LinkTable Id GroupId UserId RoleId The quuestion is how to add 3 related entities: Code bellow doesn't work. using (var db = new dbEntities()) { db.Groups.AddObject(Group.CreateGroup(1, "TestGroup")); db.Users.AddObject(User.CreateUser(1, "AdminUser")); db.Roles.AddObject(Role.CreateRole(1, "Admin")); db.UserGroupRoles.AddObject(UserGroupRole.CreateUserGroupRole(1, 1, 1, 1)); db.SaveChanges(); }

    Read the article

  • How to get php form data to pdf

    - by Fero
    Hi I am displaying all the users in the form using php where the data are fetched from db. When i click on the icon all users data should be show in a pdf. How should this can be done. kindly advice. thanks in advance

    Read the article

  • Linux directories

    - by Alex Farber
    I am writing installation script for my program, which is supposed to run on Linux/Unix OS. What is the default directory for the following files: Executable files (programs). Program should be executed by typing its name from the command line. Shared libraries. Third-party shared libraries (the program is not open source, so I need to redistribute third-party libraries). Read-only program configuration files for all users. Configuration data available for read/write access for all users.

    Read the article

  • Validation - Data Integrity

    - by Thomas
    A table can only store 10 records in a particular state, 10 users over 30 years for example, the others must be less than 30 years. It is a business rule and as such should be respected. How to ensure that state? Think: multiple users accessing this table.

    Read the article

  • How do you preserve the viewstate while using strongly typed views in asp MVC 2?

    - by Mark Kadlec
    I have an ActionResult returning from a strongly typed view where I manually validate some conditions, pass in an error message, but would like to preserve the users responses. Since my View is strongly typed, I am calling it like this: return View("PrincipalInvestigatorForm", new SmartFormViewModel(sections, questions)); My problem though, is that the error message is displayed but all the users data is wiped. How do I preserve the "ViewState" in MVC? Is there an easy way?

    Read the article

  • Self referencing a table

    - by mue
    Hello, so I'm new to NHibernate and have a problem. Perhaps somebody can help me here. Given a User-class with many, many properties: public class User { public virtual Int64 Id { get; private set; } public virtual string Firstname { get; set; } public virtual string Lastname { get; set; } public virtual string Username { get; set; } public virtual string Email { get; set; } ... public virtual string Comment { get; set; } public virtual UserInfo LastModifiedBy { get; set; } } Here some DDL for the table: CREATE TABLE USERS ( "ID" BIGINT NOT NULL , "FIRSTNAME" VARCHAR(50) NOT NULL , "LASTNAME" VARCHAR(50) NOT NULL , "USERNAME" VARCHAR(128) NOT NULL , "EMAIL" VARCHAR(128) NOT NULL , ... "LASTMODIFIEDBY" BIGINT NOT NULL , ) IN "USERSPACE1" ; Database-table-field 'LASTMODIFIEDBY' holds for auditing purposes the Id from the User who is acting in case of inserts or updates. This would normally be an admin. Because the UI shall display not this Int64 but admins name (pattern like 'Lastname, Firstname') I need to retrieve these values by self referencing table USERS to itself. Next is, that a whole object of type User would be overkill by the amount of unwanted fields. So there is a class UserInfo with much smaller footprint. public class UserInfo { public Int64 Id { get; set; } public string Firstname { get; set; } public string Lastname { get; set; } public string FullnameReverse { get { return string.Format("{0}, {1}", Lastname ?? string.Empty, Firstname ?? string.Empty); } } } So here starts the problem. Actually I have no clue how to accomplish this task. Im not sure if I also must provide a mapping for class UserInfo and not only for class User. I'd like to integrate class UserInfo as Composite-element within the mapping for User-class. But I dont no how to define the mapping between USERS.ID and USERS.LASTMODIFIEDBY table-fields. Hopefully I decribes my problem clear enough to get some hints. Thanks alot!

    Read the article

  • How can I link two Java serialised objects back together?

    - by Kidburla
    Sometimes (quite a lot, actually) we get a situation in Java where two objects are pointing to the same thing. Now if we serialise these separately it is quite appropriate that the serialised forms have separate copies of the object as it should be possible to open one without the other. However if we now deserialise them both, we find that they are still separated. Is there any way to link them back together? Example follows. public class Example { private static class ContainerClass implements java.io.Serializable { private ReferencedClass obj; public ReferencedClass get() { return obj; } public void set(ReferencedClass obj) { this.obj = obj; } } private static class ReferencedClass implements java.io.Serializable { private int i = 0; public int get() { return i; } public void set(int i) { this.i = i; } } public static void main(String[] args) throws Exception { //Initialise the classes ContainerClass test1 = new ContainerClass(); ContainerClass test2 = new ContainerClass(); ReferencedClass ref = new ReferencedClass(); //Make both container class point to the same reference test1.set(ref); test2.set(ref); //This does what we expect: setting the integer in one (way of accessing the) referenced class sets it in the other one test1.get().set(1234); System.out.println(Integer.toString(test2.get().get())); //Now serialise the container classes java.io.ObjectOutputStream os = new java.io.ObjectOutputStream(new java.io.FileOutputStream("C:\\Users\\Public\\test1.ser")); os.writeObject(test1); os.close(); os = new java.io.ObjectOutputStream(new java.io.FileOutputStream("C:\\Users\\Public\\test2.ser")); os.writeObject(test2); os.close(); //And deserialise them java.io.ObjectInputStream is = new java.io.ObjectInputStream(new java.io.FileInputStream("C:\\Users\\Public\\test1.ser")); ContainerClass test3 = (ContainerClass)is.readObject(); is.close(); is = new java.io.ObjectInputStream(new java.io.FileInputStream("C:\\Users\\Public\\test2.ser")); ContainerClass test4 = (ContainerClass)is.readObject(); is.close(); //We expect the same thing as before, and would expect a result of 4321, but this doesn't happen as the referenced objects are now separate instances test3.get().set(4321); System.out.println(Integer.toString(test4.get().get())); } }

    Read the article

  • Ruby on Rails has_many minimun

    - by user273119
    Look: class User < ActiveRecord::Base has_many :scores, :order => 'score DESC',:autosave =>true, end class Score < ActiveRecord::Base belongs_to :user end Now, I want to order the users by the maximun score of each one, The thing is that i need to get a user, two up and two down users like a top 5 scores how can I do that???? please is urgent!!

    Read the article

  • Codeigniter Current Logged in user

    - by KierenT
    In Codeigniter, I have a login/registration form all set up, working perfectly, however how can I output the current users username, i.e. When the user has logged in it would say "Welcome, [username]". I also need to know this, to be able to output from the database the record based on the current users ID, how can I do that? I've browsed the docs on codeigniter but couldn't find what i was looking for. I'm using active record btw. Thanks

    Read the article

  • Can I host an ASP.NET webite outside of IIS?

    - by boraer
    Hi everybody, I need to write an ASP.NET application which must handle a very large number of transactions per second - as many as 5000 users may transact at the same time. I think I will use WCF in back to communicate with SQL server. But in front, can IIS handle 5000 users at the same time effectively, or is there any simple way to host my application outside of IIS?

    Read the article

< Previous Page | 208 209 210 211 212 213 214 215 216 217 218 219  | Next Page >