Search Results

Search found 17563 results on 703 pages for 'remote login'.

Page 219/703 | < Previous Page | 215 216 217 218 219 220 221 222 223 224 225 226  | Next Page >

  • Using CookieJar in Python to log in to a website from "Google App Engine". What's wrong here?

    - by brilliant
    Hello everybody, I've been trying to find a python code that would log in to my mail box on yahoo.com from "Google App Engine" . Here (click here to see that page) I was given this code: import urllib, urllib2, cookielib url = "https://login.yahoo.com/config/login?" form_data = {'login' : 'my-login-here', 'passwd' : 'my-password-here'} jar = cookielib.CookieJar() opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(jar)) form_data = urllib.urlencode(form_data) # data returned from this pages contains redirection resp = opener.open(url, form_data) # yahoo redirects to http://my.yahoo.com, so lets go there instead resp = opener.open('http://mail.yahoo.com') print resp.read() The author of this script looked into HTML script of yahoo log-in form and came up with this script. That log-in form contains two fields, one for users' Yahoo! ID and another one is for users' password. Here is how HTML code of that page for both of those fields looks like: User ID field: <input type="text" maxlength="96" class="yreg_ipt" size="17" value="" id="username" name="login"> Password field: <input type="password" maxlength="64" class="yreg_ipt" size="17" value="" id="passwd" name="passwd"> However, when I uploaded this code to Google App Engine I discovered that this log-in form keeps coming back to me, which, I assume, means that logging-in process didn't succeed. Why is it so?

    Read the article

  • Using CookieJar in Python to log in to a website from "Google App Engine". What's wrong here?

    - by brilliant
    Hello everybody, I've been trying to find a python code that would log in to my mail box on yahoo.com from "Google App Engine" . Here (click here to see that page) I was given this code: import urllib, urllib2, cookielib url = "https://login.yahoo.com/config/login?" form_data = {'login' : 'my-login-here', 'passwd' : 'my-password-here'} jar = cookielib.CookieJar() opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(jar)) form_data = urllib.urlencode(form_data) # data returned from this pages contains redirection resp = opener.open(url, form_data) # yahoo redirects to http://my.yahoo.com, so lets go there instead resp = opener.open('http://mail.yahoo.com') print resp.read() The author of this script looked into HTML script of yahoo log-in form and came up with this script. That log-in form contains two fields, one for users' Yahoo! ID and another one is for users' password. Here is how HTML code of that page for both of those fields looks like: User ID field: <input type="text" maxlength="96" class="yreg_ipt" size="17" value="" id="username" name="login"> Password field: <input type="password" maxlength="64" class="yreg_ipt" size="17" value="" id="passwd" name="passwd"> However, when I uploaded this code to Google App Engine I discovered that this log-in form keeps coming back to me, which, I assume, means that logging-in process didn't succeed. Why is it so?

    Read the article

  • Why i get everytime the error-message that i've already sent the headers

    - by mikep
    Hey, i've another question about web-programming. I programmed a login script, but everytime when i try to login it says that i've send the header informations already. Here are the 2 files: <?php if($_GET['logout'] == 1) { setcookie('authorized', 1, time()-3600); } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Login - photoAdminSite</title> </head> <style type="text/css"> body { text-align: center; font-family: helvetica; } #loginForm { padding: 1em; background: #e3e3e3; width: 260px; margin: 3em auto 0; text-align: left; } </style> <body> <div id="loginForm"> <form method="post" action="confirm_login_credentials.php"> <h2>LOGIN</h2> <p>Username: <input type="text" name="username" /></p> <p>Password: <input type="password" name="password" /></p> <p><input type="submit" value="Login" name="submit" /></p> </form> </div> </body> </html> <?php $username = $_POST['username']; $password = $_POST['password']; require 'database.php'; $q = "SELECT id FROM users_photoadminsite WHERE user_name = '$username' AND password = '$password'"; $result = $mysqli->query($q) or die(mysqli_error()); if (mysqli_num_rows($result) == 1) { setcookie('authorized', 1, 0); header("Location: index.php"); } else { header("Location: login.php"); } ?> i would be really happy about some helpful answers.

    Read the article

  • Update Facebook Page's status using pyfacebook

    - by thornomad
    I am attempting to add functionality to my Django app: when a new post is approved, I want to update the corresponding Facebook Page's status with a message and a link to the post automatically. Basic status update. I have downloaded and installed pyfacebook - and I have read through the tutorial from Facebook. I have also seen this suggestion here on SO: import facebook fb = facebook.Facebook('YOUR_API_KEY', 'YOUR_SECRET_KEY') fb.auth.createToken() fb.login() # THIS IS AS FAR AS I CAN GET fb.auth.getSession() fb.set_status('Checking out StackOverFlow.com') When I get to the login() call, however, pyfacebook tries to open lynx so I can login to Facebook 'via the web' -- this is, obviously, not going to work for me because the system is supposed to be automated ... I've been looking, but can't find out how I can keep this all working with the script and not having to login via a web browser. Any ideas?

    Read the article

  • Form Not Submitting

    - by John
    Hello, When I try to click on the "submit" button for the form below, nothing happens. Any ideas why not? Thanks in advance, John submit.php: <?php require_once "header.php"; $u = $_SESSION['username']; if (!isLoggedIn()) { // user is not logged in. if (isset($_POST['cmdlogin'])) { // retrieve the username and password sent from login form & check the login. if (checkLogin($_POST['username'], $_POST['password'])) { show_userbox2(); } else { echo "Incorrect Login information !"; show_loginform(); } } else { show_loginform(); } } else { . show_userbox2(); } echo '<div class="submittitle">Submit an item.</div>'; echo '<form action="http://www...com/.../submit2.php" method="post"> <input type="hidden" value="'.$_SESSION['loginid'].'" name="uid"> <div class="submissiontitle"><label for="title">Story Title:</label></div> <div class="submissionfield"><input name="title" type="title" id="title" maxlength="1000"></div> <div class="urltitle"><label for="url">Link:</label></div> <div class="urlfield"><input name="url" type="url" id="url" maxlength="500"></div> <div class="submissionbutton"><input name="submit" type="submit" value="Submit"></div> </form> '; ?> submit2.php: <?php //if($_SERVER['REQUEST_METHOD'] == "POST"){header('Location: http://www...com/.../submit2.php');} require_once "header.php"; if (isLoggedIn() == true) { $remove_array = array('http://www.', 'http://', 'https://', 'https://www.', 'www.'); $cleanurl = str_replace($remove_array, "", $_POST['url']); $cleanurl = strtolower($cleanurl); $cleanurl = preg_replace('/\/$/','',$cleanurl); $title = $_POST['title']; //$url = $_POST['url']; $uid = $_POST['uid']; $title = mysql_real_escape_string($title); $cleanurl = mysql_real_escape_string($cleanurl); $site1 = 'http://' . $cleanurl; $displayurl = parse_url($site1, PHP_URL_HOST); function isURL($url1 = NULL) { if($url1==NULL) return false; $protocol = '(http://|https://)'; $allowed = '[-a-z0-9]{1,63}'; $regex = "^". $protocol . // must include the protocol '(' . $allowed . '\.)'. // 1 or several sub domains with a max of 63 chars '[a-z]' . '{2,6}'; // followed by a TLD if(eregi($regex, $url1)==true) return true; else return false; } if(isURL($site1)==true) mysql_query("INSERT INTO submission VALUES (NULL, '$uid', '$title', '$cleanurl', '$displayurl', NULL)"); else echo "<p class=\"topicu\">Not a valid URL.</p>\n"; } else { // user is not loggedin show_loginform(); } if (!isLoggedIn()) { // user is not logged in. if (isset($_POST['cmdlogin'])) { // retrieve the username and password sent from login form & check the login. if (checkLogin($_POST['username'], $_POST['password'])) { show_userbox(); } else { echo "Incorrect Login information !"; show_loginform(); } } else { // User is not logged in and has not pressed the login button // so we show him the loginform show_loginform(); } } else { // The user is already loggedin, so we show the userbox. show_userbox(); } require_once "footer.php"; ?>

    Read the article

  • Zend redirect problem

    - by John
    I'm trying to redirect to http://localhost/site/public/admin/login from http://localhost/site/public but for some reason, it keeps redirecting to http://localhost/admin/login The code I am using is: $this->_response->setRedirect('/admin/login')->sendResponse(); This is really frustrating me, and any help would be grealy appreciated

    Read the article

  • get rid of red X in IE for non-existing images

    - by hubertg
    I have a 3rd website (Confluence) which references images which are secured by a login. If the current user is logged in the image is shown if not the image url would redirect to a login form. Example When you enter this url in the browser a redirect to the login page is done. The problem now: IE shows a the dreaded red X icon for the image even though there should be just nothing (like in Firefox). Anyone knows how to get around this?

    Read the article

  • Using C# to HttpPost data to a web page

    - by druffmuff
    I want to log in into a website using C# code. Here's the html code of the example form: <form action="http://www.site.com/login.php" method="post" name="login" id="login"> <table border="0" cellpadding="2" cellspacing="0"> <tbody> <tr><td><b>User:</b></td><td colspan=\"2\"><b>Password:</b></td></tr> <tr> <td><input class="inputbg" name="user" type="text"></td> <td><input class="inputbg" name="password" type="password"></td> <td><input type="submit" name="user_control" value="Submit" class="buttonbg"></td> </tr> </tbody></table> </form> This is what I have tried so far with unsuccessful results: HttpWebRequest request = (HttpWebRequest)WebRequest.Create("http://www.site.com/login.php"); request.Method = "POST"; using (StreamWriter writer = new StreamWriter(request.GetRequestStream(), Encoding.ASCII)) { writer.Write("user=user&password=pass&user_control=Eingabe"); } HttpWebResponse response = (HttpWebResponse)request.GetResponse(); using (StreamReader reader = new StreamReader(response.GetResponseStream())) { stream = new StreamWriter("login.html"); stream.Write(reader.ReadToEnd()); stream.Close(); } Any Ideas, why this is failing?

    Read the article

  • ASP.NET MVC - ValidationSummary set from a different controller

    - by Rap
    I have a HomeController with an Index action that shows the Index.aspx view. It has a username/password login section. When the user clicks the submit button, it POSTs to a Login action in the AccountController. <% Html.BeginForm("Login", "Account", FormMethod.Post); %> In that action, it tests for Username/Password validity and if invalid, sends the user back to the Login page with a message that the credentials were bad. [HttpPost] public ActionResult Login(LoginViewModel Model, string ReturnUrl) { User user = MembershipService.ValidateUser(Model.UserName, Model.Password); if (user != null) { //Detail removed here FormsService.SignIn(user.ToString(), Model.RememberMe); return Redirect(ReturnUrl); } else { ModelState.AddModelError("", "The user name or password provided is incorrect."); } // If we got this far, something failed, redisplay form return RedirectToAction("Index", "Home"); // <-- Here is the problem. ModelState is lost. } But here's the problem: the ValidationSummary is always blank because we're losing the Model when we RedirectToAction. How do I send the user to the action on a different controller without a Redirect?

    Read the article

  • How to get the root path in JavaScript?

    - by Axel
    I am using mod_rewrite to remap the URLs in my website in the following format: http://www.mydomain.com/health/54856 http://www.mydomain.com/economy/strategy/911025/ http://www.mydomain.com/tags/obama/new The problem is that I am making AJAX calls to a file: http://www.mydomain.com/login.php And I don't want to write the FULL url or even use the ../ trick because there isn't a fixed level of folders. So, what i want is something to access the login.php from the root, whatever the domain name is: $.ajax({ type: "POST", url: "http://www.mydomain.com/login.php" });

    Read the article

  • PrimeFaces commandButton doesn't navigate or update

    - by Sven
    I'am using Primefaces to make my app a little bit more beautiful. I noticed that p:commandButton and h:commandButton don't work the same way. The p:commandButton calls the method and nothing else hapens. The h:commandButton calls the method and returns a navigation. I have got trouble with redirecting after pressing the login button when using p:commandButton. How to deal with that? I do have an update parameter: <p:commandButton value="Login" action="#{login.login}" type="submit" update="msgs" />

    Read the article

  • PHP question about global variables and form requests

    - by user220201
    Hi, This is probably a stupid question but will ask anyway sine I have no idea. I have written basic php code which serve forms. Say I have a login page and I serve it using the login.php page and it will be called in the login.html page like this - <form action="login.php" method="post"> By this it is also implied that every POST needs its own php file, doesn't it? This kind of feels weird. Is there a way to have a single file, say code.php, and just have each of the forms as functions instead? EDIT: Specifically, say I have 5 forms that are used one after the other in my application. Say after login the user does A, B, C and D tasks each of which are sent to the server as a POST request. So instead of having A.php, B.php, C.php and D.php I would like to have a single code.php and have A(), B(), C() and D() as functions. Is there a way to do this? Also on the same note, how do I deal with say a global array (e.g. an array of currently logged in users) across multiple forms? I want to do this without writing to a DB. I know its probably better to write to a DB and query but is it even possible to do it with a global array? The reason I was thinking about having all the form functions in one file is to use a global array. Thanks, - Pav

    Read the article

  • PHP Array Key & value Question

    - by Nano HE
    Hi I writed a test code as below. <?php $url = 'http://localhost/events/result/cn_index.php?login'; print_r(parse_url($url)); echo parse_url($url, PHP_URL_PATH); ?> Output Array ( [scheme] => http [host] => localhost [path] => /events/result/cn_index.php [query] => login ) /events/result/cn_index.php Now I inserted the line below echo array[query]; // I want to echo 'login', but failed. How to the the value of 'login'?

    Read the article

  • How to check flash and javascript installed/enable/disable on browser using JQuery

    - by MKS
    Hi Guys, I am using JQuery. I have got one link as given below: <li><a href="http://staging/english/Skywards/skywards.aspx" id="skywardsTopLoginLink">Login</a></li> Now I want to check on page load whether Flash/javascript is installed or disabled and according to output the Login link will work, I mean if flash/javascript is disabled or not installed then it will go to the above Href else it will open jQuery model dialog box for login functionality

    Read the article

  • jquery validation plugin doesn't seem to work ....

    - by Pandiya Chendur
    asp.net mvc's Html.BeginForm() seems to work with jquery validation plugin but the validation plugin doesn't seem to work with a form which i ve added to a page.... This works, <% using (Html.BeginForm("Login", "Registration", FormMethod.Post, new { id = "Loginform" })) {%> <fieldset> <legend>Login</legend> <p> <label for="EmailId">EmailId:</label> <%= Html.TextBox("EmailId", null, new { @class = "text_box_height_14_width_150" })%> </p> <div class="status"></div> <p> <label for="Password">Password:</label> <%= Html.Password("Password",null, new { @class = "text_box_height_14_width_150" }) %> </p> <div class="status"></div> <p> <input type="submit" value="Login" id="login" /> </p> </fieldset> <% } %> But this doesn't work, <form id="Loginform" method="post" action="Registration/Login"> <table cellpadding="0" cellspacing="0" width="100%" style="border:none;"> <tr> <td width="12%">Email Id&nbsp;:&nbsp;</td><td width="15%"> <input id="EmailId" type="text" class="text_box_height_14_width_150 name="EmailId" /></td><td width="20%" class="status"></td> <td width="12%">Password&nbsp;:&nbsp;<td width="15%"><input id="Password" type="password" class="text_box_height_14_width_150 name="Password" /></td> <td width="20%" class="status"></td> <td width="5%"><input type="submit" value="Login" id="BtnLogin" /></td> </tr> </table> </form> and my jquery function has this, $(document).ready(function() { var validator = $("#Loginform").validate({ rules: { EmailId: "required", Password: { required: true, minlength: 6 } }, messages: { EmailId: "Enter your EMail ID", Password: { required: "Please Provide a password", rangelength: jQuery.format("Enter at least {0} characters") } }, // the errorPlacement has to take the table layout into account errorPlacement: function(error, element) { error.appendTo(element.parent().next()); }, // set this class to error-labels to indicate valid fields success: function(label) { // set &nbsp; as text for IE label.html("&nbsp;").addClass("checked"); } }); }); Any suggestion... Am i missing something?

    Read the article

  • How to implement openId java web based application?

    - by satya
    In my web application i want to implement the OpenId just like stackoverflow.com have to login to its web-site. In details you find while login to stackoverflow.com So when if one choose google then it allow the uses to log in through google account. Please tell me how to implement it in java web application in details. Is there any single api for login through different website like(yahoo,google,facebook,etc) Thanks

    Read the article

  • Codeigniter only loads the default controller

    - by fh47331
    I am very new to CodeIgniter, but have been programming PHP for ages. I'm writing some software at the moment and using CI for the first time with it. The default controller is set to the first controller I want to action call 'login' (the controller is login.php, the view is login.php. When the form is submitted it calls the 'authenticate' controller. This executes fine, process the login data correctly and then does a redirect command (without any output to the screen prior) to the next page in this case 'newspage'. The problem is that the redirect, never reaches 'newspage' but the default controller runs again. It doesn't matter what I put ... ht tp://domain.name/anything ... (yes im using .htaccess to remove the index.php) the anything never gets called, just the default controller. I have left the standard 'welcome.php' controller and 'welcome_message.php' in the folders and even putting ht tp://domain.name/welcome all I get is the login screen! (Obviously there shouldn't be a space between the http - thats just done so it does not show as a hyperlink!) Can anyone tell me what i've done wrong!

    Read the article

  • How to use prepared statements (named parameters) on a php Class

    - by Mohamed Adib Errifai
    This is my first post here. I've searched in the site, but inforutunaly no matchs. Anyway, i want to know how to use named parameters on a class. so the pdo basic form is something like. $query = $bdd->prepare('SELECT * FROM table WHERE login = :login AND pww = :pww'); $query->execute(array('login' => $login, 'pww' => $pww)); and i want to integrate this on a class regardless of the number of parameters. Currently, i have this code http://pastebin.com/kKgSkaKt and for parameters, i use somethings like ( which is wrong and vulnerable to injection ) require_once 'classes/Mysql.class.php'; $mysql = new Mysql(); $sql = 'SELECT * FROM articles WHERE id = '.$_GET['id'].' LIMIT 1'; $data = $mysql->select($sql); And Thanks.

    Read the article

  • How do I write a spec for a Rails route that does redirecting?

    - by winstonyw
    I am using Omniauth in my Rails project, and I'll like to hide "/auth/facebook" behind a "/login" route. In fact, I wrote a route: match "/login", :to => redirect("/auth/facebook"), :as => :login and this actually works, i.e. a link to login_path will redirect to /auth/facebook. However, how can I write a (rspec) spec to test this route (specifically, the "redirect" option)? Do note that /login is not an actual action nor method defined in application. Thanks in advance!

    Read the article

  • Sharing DefaultHttpClient in Android. To synchronize or not to synchronize?

    - by johnrock
    In an Android app, I am using one static instance of org.apache.http.impl.client.DefaultHttpClient and sharing that instance in all activities and services of the app, so that this client may be used to log in once to a remote server and all subsequent user requests to that remote server will remain authenticated. Every activity or Service that makes a GET or POST to this remote server calls the same method : MyUtilityClass.gettHttpClient() Do I need to worry about synchronization of this httpclient? If so, what is the best way to handle this?

    Read the article

  • Route URL laravel 4

    - by nabil l.
    How can I do this in Laravel 4 URL::route('auth.reset', array('kh34KHh4K342')) Instead of http://domain.tld/auth/reset?kh34KHh4K342 I want to get this : http://domain.tld/auth/reset/kh34KHh4K342 EDIT This my routes.php : The problem is because I have two routes with the same name? How do you explain that ? Should i set a different name event is the same kind, and different methods // Set locale $locale = Request::segment(1); if(in_array($locale, Config::get('app.languages'))) { \App::setLocale($locale); } else { $locale = null; } Route::group( array( 'prefix' => $locale ), function () { Route::get('/'), array( 'uses' => 'HomeController@getIndex', 'as' => '/' )); // Auth Route::group( array( 'prefix' => 'auth' ), function () { // Login Route::get( 'login', array( 'before' => 'guest', 'uses' => 'UserController@getLogin', 'as' => 'auth.login' ) ); Route::post( 'login', array( 'before' => 'guest|csrf', 'uses' => 'UserController@postLogin', 'as' => 'auth.login' ) ); Route::get( 'reset/{$token}', array( 'uses' => 'UserController@getReset', 'as' => 'auth.reset' ) ); Route::post( 'reset', array( 'uses' => 'UserController@postReset', 'as' => 'auth.reset' ) ); } );

    Read the article

  • Regarding Authlogic and page redirection.

    - by Paddy
    I am using authlogic for authentication in my Rails app. Have named routes for the frequent actions, viz: map.login "login", :controller = "user_sessions", :action = "new" map.logout "logout", :controller = "user_sessions", :action = "destroy" map.register "register", :controller = "users", :action = "new" map.edit 'user/edit/:id', :controller = "users", :action = "edit" But also in my routes.rb i have these automatically created REST routes too: map.resources :user_sessions map.resources :users The problem now is that a user can login from two different routes. Ex: From, http://localhost/login and also from http ://localhost/user_sessions/new. How do i restrict access only from the named route i have defined and not allow from user_sessions/new?

    Read the article

< Previous Page | 215 216 217 218 219 220 221 222 223 224 225 226  | Next Page >