How to easily get the unmatched condition in mysql
- by leivli
I have a "server" table which has a column named 'SN' in mysql, when do query to retrive servers with some sns from 'sn1' to 'sn10000', we can:
select * from server where sn in ('sn1','sn2','sn3',...'sn10000');
If there is only one sn in 'sn1'-'sn10000' which not exists in database, then the query above will retrive 9999 rows of result.
The question is how can I easily get which one in 'sn1'-'sn10000' is not exists in database except the additional work, such as handling the result with shell script etc.
I have an ugly sql like below can use:
select * from (select 'sn1' as sn
union select 'sn2'
union select 'sn3'
....
union select 'sn10000') as SN
where not exists (select id from server where server.sn=SN.sn);
Is Anyone has other better methods? Thanks.
