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  • How to rename dir under Mac (10.6.4) via super user?

    - by user56990
    This is my dir list on my NFS: macbook-pro-andrey-k:Download Andrey$ ls 1289816143_PL_t1181913 1289816171_PL_t1183807 1290117075_BFD_DVD02(Drums) I can't delete "1290117075_BFD_DVD02(Drums)" using sudo rm -Rf 1290117075_BFD_DVD02(Drums) because I get error message -bash: syntax error near unexpected token `(' Hlp plz, how can I either rename the dir so that the error message would not show up or delete the dir right away omitting rename procedure? Thank you.

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  • What are potential reasons a user could be connected to a home network, but not to the internet?

    - by Matthew
    I have a friend that recently started using Ubuntu, and I've been answering his questions via the internet. However, I'm stuck on this one. He bought Linksys WPC11 wireless card, and says he was able to create a network connection, but was unable to ping or use a browser. I'm not quite sure where to start in figuring this out--what are some common causes of this sort of problem?

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  • mysql subquery strangely slow

    - by aviv
    I have a query to select from another sub-query select. While the two queries look almost the same the second query (in this sample) runs much slower: SELECT user.id ,user.first_name -- user.* FROM user WHERE user.id IN (SELECT ref_id FROM education WHERE ref_type='user' AND education.institute_id='58' AND education.institute_type='1' ); This query takes 1.2s Explain on this query results: id select_type table type possible_keys key key_len ref rows Extra 1 PRIMARY user index first_name 152 141192 Using where; Using index 2 DEPENDENT SUBQUERY education index_subquery ref_type,ref_id,institute_id,institute_type,ref_type_2 ref_id 4 func 1 Using where The second query: SELECT -- user.id -- user.first_name user.* FROM user WHERE user.id IN (SELECT ref_id FROM education WHERE ref_type='user' AND education.institute_id='58' AND education.institute_type='1' ); Takes 45sec to run, with explain: id select_type table type possible_keys key key_len ref rows Extra 1 PRIMARY user ALL 141192 Using where 2 DEPENDENT SUBQUERY education index_subquery ref_type,ref_id,institute_id,institute_type,ref_type_2 ref_id 4 func 1 Using where Why is it slower if i query only by index fields? Why both queries scans the full length of the user table? Any ideas how to improve? Thanks.

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  • Is Family Tree Maker 2011 the right upgrade for a FTM 11 user?

    - by bill weaver
    My father has used Family Tree Maker for years, but hasn't upgraded since version 11. It is difficult to tell from reviews at Amazon and other places whether upgrading to FTM 2011 is a good choice. File incompatibilities and upgrade woes sound like customer service is lacking, and i've read reports of it uploading your data to their database but then trying to sell you a download of data. Looking at the ancestry.com site makes me think it's solely about selling add-ons and upgrades. On the other hand, the feature set seems fairly rich and the software has a pretty strong following. I was able to get Gramps working on my system, but that's not going to work for my dad. Any advice on a good upgrade path?

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  • User not in the sudoers file. This incident will be reported

    - by Sergiy Byelozyorov
    I need to install a package. For that I need root access. However the system says that I am not in sudoers file. When trying to edit one, it complains alike! How I am supposed to add myself to the sudoers file if I don't have the right to edit one? I have installed this system and only administrator. What can I do? Edit: I have tried visudo already. It requires me to be in sudoers in the first place. amarzaya@linux-debian-gnu:/$ sudo /usr/sbin/visudo We trust you have received the usual lecture from the local System Administrator. It usually boils down to these three things: #1) Respect the privacy of others. #2) Think before you type. #3) With great power comes great responsibility. [sudo] password for amarzaya: amarzaya is not in the sudoers file. This incident will be reported. amarzaya@linux-debian-gnu:/$

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  • Is there any user-friendly way to deliver an In-app purchase subscription to multiple devices?

    - by mkvakin
    Hi everybody, Apple requires an in-app purchase subscription purchased on one device to be available on all devices associated with the user: “...subscriptions must be provided on all devices associated with a user. In App Purchase expects subscriptions to be delivered through an external server that you will provide. You must provide infrastructure to deliver subscriptions to multiple devices.” Is there any way to propagate a subscription to another device transparently without user having to create a server side user account and log in each time he needs to enable the subscription on another device? E.g. by reading a username from some kind of API and using it as a key on a server to store information about subscriptions. I tried to find an API for retrieving user account info but couldn't find any.

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  • Hibernate - strange order of native SQL parameters

    - by Xorty
    Hello, I am trying to use native MySQL's MD5 crypto func, so I defined custom insert in my mapping file. <hibernate-mapping package="tutorial"> <class name="com.xorty.mailclient.client.domain.User" table="user"> <id name="login" type="string" column="login"></id> <property name="password"> <column name="password" /> </property> <sql-insert>INSERT INTO user (login,password) VALUES ( ?, MD5(?) )</sql-insert> </class> </hibernate-mapping> Then I create User (pretty simple POJO with just 2 Strings - login and password) and try to persist it. session.beginTransaction(); // we have no such user in here yet User junitUser = (User) session.load(User.class, "junit_user"); assert (null == junitUser); // insert new user junitUser = new User(); junitUser.setLogin("junit_user"); junitUser.setPassword("junitpass"); session.save(junitUser); session.getTransaction().commit(); What actually happens? User is created, but with reversed parameters order. He has login "junitpass" and "junit_user" is MD5 encrypted and stored as password. What did I wrong? Thanks EDIT: ADDING POJO class package com.xorty.mailclient.client.domain; import java.io.Serializable; /** * POJO class representing user. * @author MisoV * @version 0.1 */ public class User implements Serializable { /** * Generated UID */ private static final long serialVersionUID = -969127095912324468L; private String login; private String password; /** * @return login */ public String getLogin() { return login; } /** * @return password */ public String getPassword() { return password; } /** * @param login the login to set */ public void setLogin(String login) { this.login = login; } /** * @param password the password to set */ public void setPassword(String password) { this.password = password; } /** * @see java.lang.Object#toString() * @return login */ @Override public String toString() { return login; } /** * Creates new User. * @param login User's login. * @param password User's password. */ public User(String login, String password) { setLogin(login); setPassword(password); } /** * Default constructor */ public User() { } /** * @return hashCode * @see java.lang.Object#hashCode() */ @Override public int hashCode() { final int prime = 31; int result = 1; result = prime * result + ((null == login) ? 0 : login.hashCode()); result = prime * result + ((null == password) ? 0 : password.hashCode()); return result; } /** * @param obj Compared object * @return True, if objects are same. Else false. * @see java.lang.Object#equals(java.lang.Object) */ @Override public boolean equals(Object obj) { if (this == obj) { return true; } if (obj == null) { return false; } if (!(obj instanceof User)) { return false; } User other = (User) obj; if (login == null) { if (other.login != null) { return false; } } else if (!login.equals(other.login)) { return false; } if (password == null) { if (other.password != null) { return false; } } else if (!password.equals(other.password)) { return false; } return true; } }

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  • SQLAlchemy & Complex Queries

    - by user356594
    I have to implement ACL for an existing application. So I added the a user, group and groupmembers table to the database. I defined a ManyToMany relationship between user and group via the association table groupmembers. In order to protect some ressources of the app (i..e item) I added a additional association table auth_items which should be used as an association table for the ManyToMany relationship between groups/users and the specific item. item has following columns: user_id -- user table group_id -- group table item_id -- item table at least on of user_id and group_id columns are set. So it's possible to define access for a group or for a user to a specific item. I have used the AssociationProxy to define the relationship between users/groups and items. I now want to display all items which the user has access to and I have a really hard time doing that. Following criteria are used: All items which are owned by the user should be shown (item.owner_id = user.id) All public items should be shown (item.access = public) All items which the user has access to should be shown (auth_item.user_id = user.id) All items which the group of the user has access to should be shown. The first two criteria are quite straightforward, but I have a hard time doing the 3rd one. Here is my approach: clause = and_(item.access == 'public') if user is not None: clause = or_(clause,item.owner == user,item.users.contains(user),item.groups.contains(group for group in user.groups)) The third criteria produces an error. item.groups.contains(group for group in user.groups) I am actually not sure if this is a good approach at all. What is the best approach when filtering manytomany relationships? How I can filter a manytomany relationship based on another list/relationship? Btw I am using the latest sqlalchemy (6.0) and elixir version Thanks for any insights.

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  • How to cd into smb://[email protected] from terminal?

    - by John
    I am using ubuntu and gnome on my computer. When I open up File Browser, on the left hand rail, I see conveniently a folder called "Work Server". When I mouse over it, the following caption appears "smb://[email protected]". If I click on that folder, then I can see the contents of that folder. Everything is great. So now when I open up a terminal/shell, I type in cd smb://[email protected] I get an error saying the directory doesn't exist. How do I enter this directory via shell/terminal?

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  • How to copy symbolic links?

    - by Basilevs
    I have directory that contains some symbolic links: user@host:include$ find .. -type l -ls 4737414 0 lrwxrwxrwx 1 user group 13 Dec 9 13:47 ../k0607-lsi6/camac -> ../../include 4737415 0 lrwxrwxrwx 1 user group 14 Dec 9 13:49 ../k0607-lsi6/linux -> ../../../linux 4737417 0 lrwxrwxrwx 1 user group 12 Dec 9 13:57 ../k0607-lsi6/dfc -> ../../../dfc 4737419 0 lrwxrwxrwx 1 user group 17 Dec 9 13:57 ../k0607-lsi6/dfcommon -> ../../../dfcommon 4737420 0 lrwxrwxrwx 1 user group 19 Dec 9 13:57 ../k0607-lsi6/dfcommonxx -> ../../../dfcommonxx 4737421 0 lrwxrwxrwx 1 user group 17 Dec 9 13:57 ../k0607-lsi6/dfcompat -> ../../../dfcompat I need to copy them to the current directory. The resulting links should be independent from their prototypes and lead directly to their target objects. cp -s creates links to links that is not appropriate behavior. cp -s -L refuses to copy links to directories cp -s -L -r refuses to copy relative links to non-working directory What should I do?

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  • I'm confused with block in ruby, compared to smalltalk.

    - by weakish
    What does block in ruby mean? It looks similar with smalltalk, but you can't send messages to it. For example, in smalltalk: [:x | x + 3] value: 3 returns 6. But in ruby: {|x| x + 3}.call 3 will cause SyntaxError. Well, you can pass messages to lambda in ruby, though: irb(main):025:0> ->(x){x+3}.call 3 => 6 So in ruby, block is not a block, but lambda is a block? Is this true? I mean, are there any differences between ruby lambda and smalltalk block? If this is true, then what is ruby block?

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  • Help with active record relations

    - by Christian Fazzini
    class CreateActivities < ActiveRecord::Migration def self.up create_table :activities do |t| t.references :user t.references :media t.integer :artist_id t.string :type t.timestamps end end def self.down drop_table :activities end end class Fan < Activity belongs_to :user, :counter_cache => true end class Activity < ActiveRecord::Base belongs_to :user belongs_to :media belongs_to :artist, :class_name => 'User', :foreign_key => 'artist_id' end class User < ActiveRecord::Base has_many :activities has_many :fans end I tried changing my activity model too, without any success: class Activity < ActiveRecord::Base has_many :activities, :class_name => 'User', :foreign_key => 'user_id' has_many :activities, :class_name => 'User', :foreign_key => 'artist_id' end One thing to note. Activity is an STI. Fan inherits from Activity. In console, I do: # Create a fan object. User is a fan of himself fan = Fan.new => #<Fan id: nil, user_id: nil, media_id: nil, artist_id: nil, type: "Fan", comment: nil, created_at: nil, updated_at: nil> # Assign a user object fan.user = User.first => #<User id: 1, genre_id: 1, country_id: 1, .... # Assign an artist object fan.artist_id = User.first.id => 1 # Save the fan object fan.save! => true Activity.last => #<Fan id: 13, user_id: 1, media_id: nil, artist_id: 1, type: "Fan", comment: nil, created_at: "2010-12-30 08:41:25", updated_at: "2010-12-30 08:41:25"> Activity.last.user => #<User id: 1, genre_id: 1, country_id: 1, ..... But... Activity.last.artist => nil Why is Activity.last.artist returning nil?

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  • Nested Resource testing RSpec

    - by Joseph DelCioppio
    I have two models: class Solution < ActiveRecord::Base belongs_to :owner, :class_name => "User", :foreign_key => :user_id end class User < ActiveRecord::Base has_many :solutions end with the following routing: map.resources :users, :has_many => :solutions and here is the SolutionsController: class SolutionsController < ApplicationController before_filter :load_user def index @solutions = @user.solutions end private def load_user @user = User.find(params[:user_id]) unless params[:user_id].nil? end end Can anybody help me with writing a test for the index action? So far I have tried the following but it doesn't work: describe SolutionsController do before(:each) do @user = Factory.create(:user) @solutions = 7.times{Factory.build(:solution, :owner => @user)} @user.stub!(:solutions).and_return(@solutions) end it "should find all of the solutions owned by a user" do @user.should_receive(:solutions) get :index, :user_id => @user.id end end And I get the following error: Spec::Mocks::MockExpectationError in 'SolutionsController GET index, when the user owns the software he is viewing should find all of the solutions owned by a user' #<User:0x000000041c53e0> expected :solutions with (any args) once, but received it 0 times Thanks in advance for all the help. Joe

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  • In datastore, confused on how to pass a list of key_names as an argument to somemodel.get_or_insert(

    - by indiehacker
    Are there examples of how to pass a list of key_names to Model.get_or_insert() ? My Problem: With a method of ParentLayer I want to make the children. The key_names of the new (or editable) entities of class Child will come from such a list below: namesList = ["picture1","picture2"] so I should be able to build a list of key_names with method from the parent class as follows: class ParentLayer(db.Model): def getOrMakeChildren(self, namesList): keyslist = [ db.Key.from_path( 'Child' , name , parent = self.key() ) for name in namesList ] the problem is next where I simply want to get_or_insert entities based on keylist defined above: childrenEntitiesList = Child.get_or_insert(keyslist) # no works? also none of the below attempts worked: #childrenEntitiesList = Child.get_or_insert(keyslist, parent = u'TEST') #childrenEntitiesList = Child.get_or_insert(keyslist, parent=self.key().name() ) #childrenEntitiesList = Child.get_or_insert(keyslist, parent=self.key()

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  • How is it possible to list all folders that a particular user/group has permissions on?

    - by Lord Torgamus
    Is it possible to list all folders/files that a given group has explicit permissions on, for a machine running Windows Server 2003? If so, how? It would be nice to see inherited permissions as well, but I could do with just explicit permissions. A little background: I'm trying to update groups/permissions on a test server. One of the groups, Devs, wasn't implemented correctly when it was created, and my goal is to remove it from the system. It has been replaced by LeadDevelopers, which has permissions on many — but naturally not all — of the same folders. I want to make sure that I don't accidentally orphan any folders or cause any other issues when I remove Devs. It did have some admin-level permissions.

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  • I'm confused, how do I control cache so my clients can see website edits.

    - by Jared Christensen
    I host about 10 websites for clients. Every so often a client will ask for an update to their website. It may be a simple image change, new PDF or a simple text change. I make the change and then send them a link to the web page with the update. About an hour later I will get an email back from the client telling me they still see the old page. I will then explaining to them how to empty their browsers cache. What I'm trying to figure out is if there is a way I can tell their browser that I made an update to the website and that it should reload the page and update the cache. I thought about trying a meta tag but I read that they are not very reliable. Also I would still like the page to cache I just want to be able to clear it when I make an update. Is this possible? I'm an advanced front end web developer (HTML, CSS, Javascript) and know some PHP. Cache is just one of those things I don't really understand that well.

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  • Syncing Large Directories/Filesystems using USB Drive

    - by Alan Lue
    Does anyone have a solution for syncing large directories/filesystems using just a USB flash drive (and specifically without using a network connection)? The objective is simply to sync a user directory between two computers. The contents of the user directory could amount to a large quantity of data—say, a quantity larger than could be stored on any single USB drive—but the aggregate size of changes that must be propagated by a single sync could easily fit on a USB drive. As an example, suppose a user directory is already synchronized between a desktop and a laptop computer. Here's a use case: Some changes are made in the user directory on the desktop. We mount a USB drive onto the desktop and copy whatever changes need to be applied to the laptop user directory in order to synchronize the desktop and laptop user directories. We now mount the USB drive onto the laptop and apply the changes. The desktop and laptop user directories are now synchronized. Any ideas? Alan

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  • JavaScript and PHP - A little confused on how to work them together.

    - by Doug
    So right now, I'm just using a basic form to check a password. I want it to check the password and basically remain on page.html so I can use JavaScript to alert incorrect password or something. I'm not really sure how to do that. It seems it would bring me to check.php. I'm not too sure on the whole process, any help appreciated! Thanks! Page.html <form action="check.php" method="post"> <input type="password" name="password" /> <input type="submit" value="Submit" /> </form> check.php <?php $password = $_POST['password']; if ( $password != "testing" ) { die(); } ?>

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