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  • android - how to cache an image from a remote site

    - by Lynnooi
    Hi, Can anyone please provide me some example on how to save an image i fetch from websites into a cache. I had try to include the following function into my code and call it once i run the activity. public void getRemoteImage(String imageUrl) { imageUrl = "http://marga.mobile9.com/download/thumb/295/sexylady7_xo6npovn.jpg"; URL aURL = null; URLConnection conn = null; Bitmap bmp = null; CacheResult cache_result = CacheManager.getCacheFile(imageUrl, new HashMap()); if (cache_result == null) { try { aURL = new URL(imageUrl); conn = aURL.openConnection(); conn.connect(); InputStream is = conn.getInputStream(); cache_result = new CacheManager.CacheResult(); CacheManager.saveCacheFile(imageUrl, cache_result); } catch (Exception e) { //return null; } } bmp = BitmapFactory.decodeStream(cache_result.getInputStream());*/ Toast.makeText(context,"Please work.. namo namo namo", Toast.LENGTH_SHORT).show(); //return bmp; } However, I got a nullPointerException. Can someone please help me with it as i'm quite new in android.

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  • I cannot access my flickr account

    - by AtanuCSE
    I was using Google account to log in to my Flickr. After several days, I entered into the Flickr account and found out that Flickr is moving into only Yahoo login. So I tried the Google login and it shows This account is not connected with any Yahoo account. Sign up for new........ or use existing etc... Can't remember the exact words. So I provided my Yahoo mail credentials. Now every time it is giving me a brand new account, rather taking me to my previous Flickr account. I can view the previous account photos, but After going there, it treated me as a outsider. New account showing me that I've not uploaded any photo. What's wrong? How can I connect with my previous account?

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  • How to access both partitions on a bootable USB flash drive in Windows

    - by Maccyjam
    I have a 16GB USB Flash Drive that is partitioned into two different sizes. The first partition contains a bootable version of Ubuntu, the second partition is for general saving of files. Windows will only recognise the first partition. I have tried using Bootice but this breaks the bootable partition. Disk Management recognises the second partition but does not allow me to do anything with it. Is there a way to make both partitions accessible by Windows and keep the USB disk bootable?

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  • Samba access works with IP address only

    - by Sebastian Rittau
    I added a Debian etch host (hostname: webserver, IP address: 192.168.101.2) running Samba to a Windows network with a Windows 2003 PDC (IP address 192.168.101.3). The Samba server exports a public guest share, called "Intranet". The server shows up fine in the network, but trying to click on it produces an error dialog, stating I don't have the necessary permissions. So does entering \webserver manually and using \webserver\internet states that the path does not exist. Interestingly, accessing the share by IP address (\192.168.101.2 or \192.168.101.2\intranet) works fine. DNS is configured correctly, and "smbclient //webserver/intranet" on another Linux client works fine. One complicating issue is that the webserver is only a VMware virtual machine running on PDC server. Here is our smb.conf: [global] workgroup = Foobar server string = Webserver wins support = yes ; commenting out these wins server = 192.168.101.3 ; two lines has no effect dns proxy = no guest account = nobody [... snipped some unrelated bits, like logging ...] security = share [... snipped some password-related things ...] domain master = no [intranet] comment = Intranet path = /srv/webserver/contents browseable = yes guest ok = yes guest only = yes read only = yes create mask = 0775 directory mask = 0775

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  • LAN connection loses network access randomly

    - by bill11
    Hi, Windows 7 is a great OS but there are some problems which should be solved from Microsoft as fast as possible. On my Computer the LAN connection randomly loses its connection. I don't know why but I think this problem depends on my network driver which is only available for Windows XP (where it always worked perfectly). I can not reproduce this issue. Has anybody here had the same problem?

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  • Can't access YouTube

    - by Agentleader1
    I can not seem to connect to YouTube at all. If I connect directly to YouTube (youtube.com) I get this: And if I try to connect via video directly (youtube.com/watch?v=), I get this: Here's how this isn't a web issue: I have malware on my computer I believe. And the question here is, how do I get rid of it, or what possible issue could this be? I can verify this is not a website issue or wifi issue, I've tried to connect on another computer in my wifi, and it worked. It is the local machine issue. I've tried to get rid of malware at my best and also have tried to disable possible virus extensions. All can out as the same result: no help. Also, I am unable to find these hiding viruses. I used malware-bytes and Microsoft Security Essentials. Edit: This is OBVIOUSLY Windows. I am currently running on a laptop Windows 7 Home Premium 4gb ram 64-bit os Lifebook series manufactured by Fujitsu America, Inc. Intel(R) Core(TM) i3-3110M CPU @ 2.40GHz nslookup youtube.com:

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  • Access to local network machine

    - by Jirka Kopriva
    I have granted new setting from my domain provider. Domain with specific port is pointing on computer in local network (fixed ip) like: mydomain.com:87 -> 192.168.1.1 Local machine is running on win server 2008. Everything works fine on local network. But mydomain.com:87 is not working. Are there extra settings for win server to allow connection from outside? (Firewall is turned off while searching for working result.)

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  • Problems with Getting Remote Contents using Google App Engine

    - by dade
    Here is the client side code. It is running insdide a Google Gadgets var params = {}; params[gadgets.io.RequestParameters.CONTENT_TYPE] = gadgets.io.ContentType.JSON; var url = "http://invplatformtest.appspot.com/getrecent/"; gadgets.io.makeRequest(url, response, params); The response function is: function response(obj) { var r = obj.data; alert(r['name']); } while on the server end, the python code sending the JSON is: class GetRecent(webapp.RequestHandler): def get(self): self.response.out.write({'name':'geocities'}) #i know this is where the problem is so how do i encode json in GAE? which is just supposed to send back a Json encoded string but when i run this, the javascript throws the following error: r is null alert(r['name']); If i were recieving just TEXT contents and my server send TEXT everything works fine. I only get this problem when am trying to send JSON. Where exactly is the problem? Am i encoding the JSON the wrong way on AppEngine? I tried using the JSON library but it looks as if this is not supported. Where is the problem exactly? :(

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  • How to know if a file has 'access' monitor in linux

    - by J L
    I'm a noob and have some questions about viewing who accessed a file. I found there are ways to see if a file was accessed (not modified/changed) through audit subsystem and inotify. However, from what I have read online, according to here: http://www.cyberciti.biz/tips/linux-audit-files-to-see-who-made-changes-to-a-file.html it says to 'watch/monitor' file, I have to set a watch by using command like: # auditctl -w /etc/passwd -p war -k password-file So if I create a new file or directory, do I have to use audit/inotify command to 'set' watch first to 'watch' who accessed the new file? Also is there a way to know if a directory is being 'watched' through audit subsystem or inotify? How/where can I check the log of a file?

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  • Codeigniter deny access to directory of controllers with apache config

    - by MAZUMA
    I’d like to restrict access to a folder of controllers that are used for admin purposes only. I’ve tried a number of ways and not coming up with a solution. These controllers are behind password protection. But, I’d like to just remove it from view if someone happens to stumble upon the right directory. Can this be done? I’d rather not do it from htaccess. I have access to the apache config files, so I’d like to handle it there. Does it have anything to do with the way Codeigniter routes? Or, am I just way off? This what I’m using that doesn’t work <Directory /var/www/application/controllers/folder/> Order deny,allow Deny from all Allow from xxx.xxx.xxx.xxx </Directory>

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  • RewriteRule causes POST data to get dumped before I can access it

    - by MatthewMcGovern
    I'm currently setting up my own 'webserver' (a Ubuntu Server on some old hardware) so I can have a mess around with PHP and get some experience managing a server. I'm using my own little MVC framework and I've hit a snag... In order for all requests to make it through the dispatcher, I am using: <Directory /var/www/> RewriteEngine On RewriteCond %{REQUEST_URI} !\.(png|jpg|jpeg|bmp|gif|css|js)$ [NC] RewriteRule . HomeProjects/index.php [L] </Directory> Which works great. I read on Stackoverflow to change the [L] to [P] to preserve post data. However, this causes every page to return: Not Found The requested URL <url> was not found on this server. So after some more searching, I found, "Note that you need to enable the proxy module, and the proxy_http_module in the config files for this to work." The problem is, I have no idea how to do this and everything I google has people using examples with virtual hosts and I don't know how to 'translate' that into something useful for my setup. I'm accessing my webserver via my public IP and forwarding traffic on port 80 to the web server (like I'm pretending I have a domain/server). How can I get this enabled/get post data working again? Edit: When I use the following, the server never responds and the page loads indefinately? LoadModule proxy_module /usr/lib/apache2/modules/mod_proxy.so LoadModule proxy_http_module /usr/lib/apache2/modules/mod_proxy_http.so <Directory /var/www/> RewriteEngine On RewriteCond %{HTTP_REFERER} !^http://(.+\.)?82\.6\.150\.51/ [NC] RewriteRule .*\.(jpe?g|gif|bmp|png|jpg)$ /no-hotlink.png [L] RewriteCond %{REQUEST_URI} !\.(png|jpg|jpeg|bmp|gif|css|js)$ [NC] RewriteRule . HomeProjects/index.php [P] </Directory>

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  • How can I use Android as a remote control for streaming?

    - by michael
    I would like to know if I can use Android to remote control streaming on my laptop? I would like to use my laptop as my streaming server and use my HDTV to view the stream. And I need some way to remote control my streaming server. I have read about http://maketecheasier.com/install-vlc-shares-in-Ubuntu-and-stream-videos-to-Android/2011/02/25 and http://code.google.com/p/android-vlc-remote/ but those are streaming to Android phone itself. I am just need something to remote control streaming to my TV. Is that possible?

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  • Access to an "upper" instance of a class from another instance of a different class

    - by BorrajaX
    Hello everyone! I have a tricky question and probably what I want to do is not even possible but... who knows... Python seems very flexible and powerful... I'd like to know if there's a way to access to the class (or its fields) where an object is instanciated. Let's say I have: def Class1: def __init__(self): self.title = "randomTitle" self.anotherField = float() self.class2Field = Class2() and the class whose type will be the class2Field: def Class2: def __init__(self): self.field1 = "" self.field2 = "" # . . . # I'd like to know if there's a way to access the instance of Class1 from the instance of Class2 that is declared in Class1 (meaning, accessing the fields of Class1 from the variable self.class2Field in that Class1 instance) I know I can always change the init in Class2 to accept a Class1 parameter, but I'd like to know if there's another way of "climbing" through the class hierachy... Thank you very much!

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  • jQuery access each matched element from '.find' by an index

    - by GHarping
    Using jQuery's .find() method to return a set of elements, I am trying to access items in the returned set by their order in that set. For example, a table with two rows and in each row a select box and two text input fields, accessed with the following: $('table#tbl').find('tr.row').each(function(i) { }); To get the first element I would have thought I could use $('table#tbl').find('tr.row').each(function(i) { alert( $(this).find(':input').get(1).val() ); }); And variations of the above, but apparently this doesn't work. Could anyone suggest the correct method to access item x of n elements returned?

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  • error when using OWA access to mail server exchange 2010

    - by e0594cn
    Suddenly it will come out the below error when accessing the exchange 2010 mail server using OWA after clicking sign in button on initial page? ***The website cannot display the page HTTP 500 Most likely causes: •The website is under maintenance. •The website has a programming error. What you can try: Refresh the page. Go back to the previous page. More information This error (HTTP 500 Internal Server Error) means that the website you are visiting had a server problem which prevented the webpage from displaying. For more information about HTTP errors, see Help.* Any suggestion? Thanks!

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  • Windows clients cannot access machine running DHCP server

    - by science9712
    I'm trying to setup a small LAN, using an Ethernet switch, an Arch Linux server, and around 10 Windows XP machines. This network has no outside connections. The Arch machine has a self configured ip address (configured with ip addr add 192.168.0.1 dev eth0), and acts as a DHCP server(using dhcpd). This portion works great, windows clients get IP addresses, the correct gateway settings, perfect. However, the clients cannot connect to each other, or to the dhcp server. When I run ping 192.168.0.1 on any client, I get no response, same happens if I try to ping any other client. On the gateway machine, I can't ping any of the clients either. Any help would be much appreciated!

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  • Android remote code loading

    - by sehugg
    I am developing a library for Android that requires frequent updates from a central server. I was thinking how nice it would be if my library could update itself -- or if I could just release a bootstrap library that downloads the target library when the app is installed. I see this class in 1.5 called "DexClassLoader" but there seems to be precious little on the web besides the API docs. Has anyone used this successfully for the scenario which I described? Also, do the terms of the Android Market permit such a thing?

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  • cross domain DOM access and manipulation in Java ?

    - by gaqer
    In my Java app, how can I incorporate the browser (which loads and renders URLs) in Swing and access it's DOM and manipulate HTML ? How can you embed such browser in a Rich Internet Application and access it's DOM ? More specifically, Vaadin ? Is there a HTTP proxy class that can load an external URL, and render it to the user ? This was what I was doing on LAMP stack....but I want to switch to Vaadin or some Java web framework where I can just use Java to do everything from server-side to client-side logic design, so I can focus more on application logic. (aka looking for developer friendly frameworks like Vaadin). Thank you and have a great weekend !

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  • "Access violation reading location" troubles retrieveing buffer from directx

    - by numerical25
    Below is my code... ID3D10Texture2D *pBackBuffer; hr = mpSwapChain->GetBuffer(0, __uuidof(ID3D10Texture2D), (LPVOID*) &pBackBuffer); and I get the following error chp1.exe': Unloaded 'C:\Windows\SysWOW64\oleaut32.dll' First-chance exception at 0x757ce124 in chp1.exe: Microsoft C++ exception: _com_error at memory location 0x0018eeb0.. First-chance exception at 0x757ce124 in chp1.exe: Microsoft C++ exception: _com_error at memory location 0x0018edd0.. First-chance exception at 0x757ce124 in chp1.exe: Microsoft C++ exception: _com_error at memory location 0x0018ef1c.. The thread 'Win32 Thread' (0xfc4) has exited with code 0 (0x0). 'chp1.exe': Unloaded 'C:\Windows\SysWOW64\D3D10Ref.DLL' First-chance exception at 0x00b71894 in chp1.exe: 0xC0000005: Access violation reading location 0x00000000. Unhandled ex ception at 0x00b71894 in chp1.exe: 0xC0000005: Access violation reading location 0x00000000. It appears that the error occurs in the last parameter. &pBackBuffer. I added this single line of code and the error occurs.

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