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  • Python - Checking for membership inside nested dict

    - by victorhooi
    heya, This is a followup questions to this one: http://stackoverflow.com/questions/2901422/python-dictreader-skipping-rows-with-missing-columns Turns out I was being silly, and using the wrong ID field. I'm using Python 3.x here. I have a dict of employees, indexed by a string, "directory_id". Each value is a nested dict with employee attributes (phone number, surname etc.). One of these values is a secondary ID, say "internal_id", and another is their manager, call it "manager_internal_id". The "internal_id" field is non-mandatory, and not every employee has one. (I've simplified the fields a little, both to make it easier to read, and also for privacy/compliance reasons). The issue here is that we index (key) each employee by their directory_id, but when we lookup their manager, we need to find managers by their "internal_id". Before, when employee.keys() was a list of internal_ids, I was using a membership check on this. Now, the last part of my if statement won't work, since the internal_ids is part of the dict values, instead of the key itself. def lookup_supervisor(manager_internal_id, employees): if manager_internal_idis not None and manager_internal_id!= "" and manager_internal_id in employees.keys(): return (employees[manager_internal_id]['mail'], employees[manager_internal_id]['givenName'], employees[manager_internal_id]['sn']) else: return ('Supervisor Not Found', 'Supervisor Not Found', 'Supervisor Not Found') So the first question is, how do I check whether the manager_internal_id is present in the dict's values. I've tried substituting employee.keys() with employee.values(), that didn't work. Also, I'm hoping for something a little more efficient, not sure if there's a way to get a subset of the values, specifically, all the entries for employees[directory_id]['internal_id']. Hopefully there's some Pythonic way of doing this, without using a massive heap of nested for/if loops. My second question is, how do I then cleanly return the required employee attributes (mail, givenname, surname etc.). My for loop is iterating over each employee, and calling lookup_supervisor. I'm feeling a bit stupid/stumped here. def tidy_data(employees): for directory_id, data in employees.items(): # We really shouldnt' be passing employees back and forth like this - hmm, classes? data['SupervisorEmail'], data['SupervisorFirstName'], data['SupervisorSurname'] = lookup_supervisor(data['manager_internal_id'], employees) Thanks in advance =), Victor

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  • Xcode "Build and Archive" from command line

    - by Dan Fabulich
    Xcode 3.2 provides an awesome new feature under the Build menu, "Build and Archive" which generates an .ipa file suitable for Ad Hoc distribution. You can also open the Organizer, go to "Archived Applications," and "Submit Application to iTunesConnect." Is there a way to use "Build and Archive" from the command line (as part of a build script)? I'd assume that xcodebuild would be involved somehow, but the man page doesn't seem to say anything about this. UPDATE Michael Grinich requested clarification; here's what exactly you can't do with command-line builds, features you can ONLY do with Xcode's Organizer after you "Build and Archive." You can click "Share Application..." to share your IPA with beta testers. As Guillaume points out below, due to some Xcode magic, this IPA file does not require a separately distributed .mobileprovision file that beta testers need to install; that's magical. No command-line script can do it. For example, Arrix's script (submitted May 1) does not meet that requirement. More importantly, after you've beta tested a build, you can click "Submit Application to iTunes Connect" to submit that EXACT same build to Apple, the very binary you tested, without rebuilding it. That's impossible from the command line, because signing the app is part of the build process; you can sign bits for Ad Hoc beta testing OR you can sign them for submission to the App Store, but not both. No IPA built on the command-line can be beta tested on phones and then submitted directly to Apple. I'd love for someone to come along and prove me wrong: both of these features work great in the Xcode GUI and cannot be replicated from the command line.

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  • need help fixing unique key in rails. rails is adding id causing duplicate key

    - by railsnew
    I need some help in fixing the below issue. I had transaction blocks in my rails code like below: @sqlcontact = "INSERT INTO contacts (id,\"cid\", \"hphone\", mphone, provider, cemail, email, sms , mail, phone) VALUES ('"+@id1+"','" + @id1 + "', '"+ params[:hphone] + "', '"+params[:mphone]+ "', '" + params[:provider] + "', '" + params[:cemail]+ "', '" + @varemail+ "', '"+@varsms+ "', '"+ @varmail+"', '"+@varphone+"')" my app was deployed to heroku so I was advised by them to remove transaction blocks. So I changed the above to: @cont = Contact.new(:id => @id1, :cid => @id1, :hphone => params[:hphone], :mphone => params[:mphone], :provider => params[:provider], :cemail => params[:cemail], :email => @varemail, :sms => @varsms, :mail => @varmail, :phone => @varphone) @cont.save My app also already had data stored. Now the problem is that when I try to save a record ...I keep getting the error: duplicate key value violates unique constraint "contacts_pkey" The error also shows the sql query trying to insert data ...however, in that sql query i Do not see id value. As you can see from my code that I am passing the id. then why is rails not accepting it? does it always include its own sequential id? can I not overwrite the default rails magic? and if it does that...does it not look at data that is already in the DB?? I am really stuck here. What should I do? should I just go back to my transaction block

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  • Creating one row of information in excel using a unique value

    - by user1426513
    This is my first post. I am currently working on a project at work which requires that I work with several different worksheets in order to create one mail master worksheet, as it were, in order to do a mail merge. The worksheet contains information regarding different purchases, and each purchaser is identified with their own ID number. Below is an example of what my spreadsheet looks like now (however I do have more columns): ID Salutation Address ID Name Donation ID Name Tickets 9 Mr. John Doe 123 12 Ms. Jane Smith 100.00 12 Ms.Jane Smith 300.00 12 Ms. Jane Smith 456 22 Mr. Mike Man 500.00 84 Ms. Jo Smith 300.00 What I would like to do is somehow sort my data so that everythign with the same unique identifier (ID) lines up on the same row. For example ID 12 Jane Smith - all the information for her will show up under her name matched by her ID number, and ID 22 will match up with 22 etc... When I merged all of my spreadsheets together, I sorted them all by ID number, however my problem is, not everyone who made a donation bought a ticket or some people just bought tickets and nothing us, so sorting doesn't work. Hopefully this makes sense. Thanks in advance.

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  • In App Purchase Unique Identifying Data

    - by dageshi
    O.K so I'm writing a iPhone travel guide, you purchase a subscription to a travel guide for 3 months, it downloads a fairly hefty database and for 3 months that database gets updated weekly with new stuff. Now what I'd like to do is make the user enter their email address as a one off action before they purchase their first guide, for China say. The purpose for doing this is 1) To allow me to contact the user by email when they add a note/tip for a particular place (the app will allow them to send notes & information to me) 2) To Uniquely identify who has purchased the subscription so that if they wipe their device and reinstall the app they can plug the email address in and pickup their subscriptions again. Or so they can use the same subscription on another device they own. My concerns are 1) Will Apple allow the email method of restoring functionality to a second or restored device? 2) As long as I tell the user what I'm using their email address for (aka I won't sell it to anyone else and use it for X purposes) will it be o.k to ask for said email address? And as a side note, can I tack the devices unique id onto my server comms to track devices or is apple going to through a hissy fit about that as well?

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  • Safari doesn't detect my Extension Certificate

    - by Questor
    Hello, all! I have registered for the Safari Development Program and have a valid Apple ID. I've followed all the steps given by Apple. The problem is that Windows XP (Service Pack 2) does not recognize the command 'certreq', whereas the instructions said it would work on any Windows machine. However, the command 'certreq' was working on Windows Vista on the machine of my co-worker's, I downloaded the certificate (the .cer file) and installed it and Safari detected it. However, I don't have Windows Vista. I installed Windows 7 now on my machine, the command 'certreq' works and I have the Safari Extension Certificate (the .cer file) but when I open Safari's Extension Builder, my certificate does not appear there. I entered mmc in Start -- Run and checked if the certificate was installed there. It was in the 'Other People' but not in 'Personal'. Even on Internet Explorer 7+, when I go to Tools -- Internet Options -- Content (Tab) -- Certificates, the certificate is not there in the Personal tab, (WHEREAS IT GOT INSTALLED IN THE PERSONAL FOLDER AUTOMATICALLY IN WINDOWS VISTA). I tried importing the certificate (the .cer file) into the Peronal folder, the import is successful but still neither does it appear in the personal folder nor does Safari recognize/detect it when I go to the Extension Builder. ANY HELP?! I need to make an extension for my office project and the deadline is approaching. I really need to get it done. Thanks a million in anticipation.

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  • Is this a bug in plist or Xcode?

    - by Pedro
    G'day All If you create a date item in the plist editor of Xcode or Apple's standalone plist editor you get something of the form <date>2010-05-29T10:30:00Z</date> which is a nice well formed ISO date at UTC (indicated by the "Z"). Because I'm in timezone UTC +10 when that's read into my app & then displayed I get 8:30 PM out, still good. However if that is a time in my timezone it should be <date>2010-05-29T10:30:00+10</date> (replacing "Z" with my timezone offset). All of my attempts at reading such dates into my iPhone app have had the plist rejected as if it is malformed & editing a plist with such a date in Apple's editors changed the "+10" to "Z" without adjusting the time. Do others think I'm correct in thinking this is a bug in either plist or Xcode? My feeling is that the implementation of ISO date & time in plist is incomplete. Cheers, Pedro :)

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  • Carriage Return\Line feed in Java

    - by Manu
    Guys, i have created text file in unix enviroment using java code. For writing the text file i am using java.io.FileWriter and BufferedWriter. and for newline after each row i am using bw.newLine() method. (where bw is object of BufferedWriter ) and sending that text file by attaching in mail from unix environment itself (automated that using unix commands). My issue is, after i download the text file from mail in windows system, if i opened that text file the data's are not properly aligned. newline() character is not working i think so. I want same text file alignment as it is in unix environment, if i opened the text file in windows environment also. How to resolve the problem.Please help ASAP. Thanks for your help in advance. pasting my java code here for your reference..(running java code in unix environment) File f = new File(strFileGenLoc); BufferedWriter bw = new BufferedWriter(new FileWriter(f, false)); rs = stmt.executeQuery("select * from jpdata"); while ( rs.next() ) { bw.write(rs.getString(1)==null? "":rs.getString(1)); bw.newLine(); }

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  • VSTO - Outlook 2007 How do I show a user property even when it's not present?

    - by Yandros
    I have added user property in a mail folder, let's call it UserProperty01. Some of the folder items have this property, some don't. I need to show in the folder's view if that property is set or not, so I added another property called UserProperty01Present, and I set it to true when I set the original property and false when I deleted it; then I added it to the folder's view. The problem is that the little checkbox appears checked in those mails where the property is set, blank in those where the property was deleted... and nowhere at all in those where the property was never set in the first place. My question is, is there any way to show the blank checkbox when the property is not set? The only alternative I found so far is looking in every mail item and setting it to false when it's not set every time the folder is opened; needless to say, I'm not very happy with this solution. Is there any other way? Thank you for your time.

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  • Using Reachability for Internet *or* local WiFi?

    - by randallmeadows
    I've searched SO for the answer to this question, and it's not really addressed, at least not to a point where I can make it work. I was originally only checking for Internet reachability, using: self.wwanReach = [Reachability reachabilityWithHostName:@"www.apple.com"]; [wwanReach startNotifer]; I now need to support a local WiFi connection (in the absence of reaching the Internet in general), and when I found +reachabilityForLocalWiFi, I also noticed there was +reachabilityForInternetConnection. I figured I could use these, instead of hard-coding "www.apple.com" in there, but alas, when I use self.wwanReach = [Reachability reachabilityForInternetConnection]; [wwanReach startNotifer]; self.wifiReach = [Reachability reachabilityForLocalWiFi]; [wifiReach startNotifer]; the reachability callback that I've set up "never" gets called, for values of "never" up to 10, 12, 15 minutes or so (which was as long as my patience lasted. (User's patience will be much less, I'm sure.) Switching back to +reachabilityWithHostName: works within seconds. I also tried each "pair" individually, in case there was an issue with two notifiers in progress simultaneously, but that made no difference. So: what is the appropriate way to determine reachability to either the Internet/WWAN or a local Wifi network (either one, or both)? [This particular use case is an iPhone or iPad connecting to a Mac mini computer-to-computer network; I'm sure other situations apply.]

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  • Rails wont install at create Makefile stage

    - by mattc
    I am getting this error after running sudo gem install rails /System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/bin/ruby extconf.rb creating Makefile make xcrun cc -I. - I/System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/1.8/universal-darwin12.0 -I/System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/1.8/universal-darwin12.0 -I. -DJSON_GENERATOR -D_XOPEN_SOURCE -D_DARWIN_C_SOURCE -fno-common -arch i386 -arch x86_64 -g -O3 -pipe -fno-common -DENABLE_DTRACE -fno-common -pipe -fno-common -c generator.c xcrun: Error: failed to exec real xcrun. (No such file or directory) cc -arch i386 -arch x86_64 -pipe -bundle -undefined dynamic_lookup -o generator.bundle generator.o -L. -L/System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib -L. -arch i386 -arch x86_64 -lruby -lpthread -ldl -lobjc i686-apple-darwin11-llvm-gcc-4.2: generator.o: No such file or directory i686-apple-darwin11-llvm-gcc-4.2: generator.o: No such file or directory lipo: can't figure out the architecture type of: /var/tmp//ccHCNNwM.out make: *** [generator.bundle] Error 1 I have Homebrew installed, Xcode 4.4 with command line tools installed, Osx 10.6.2 I run gem env and get this but not sure what I'm looking for: RubyGems Environment: - RUBYGEMS VERSION: 1.8.24 - RUBY VERSION: 1.8.7 (2012-02-08 patchlevel 358) [universal-darwin12.0] - INSTALLATION DIRECTORY: /Library/Ruby/Gems/1.8 - RUBY EXECUTABLE: /System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/bin/ruby - EXECUTABLE DIRECTORY: /usr/bin - RUBYGEMS PLATFORMS: - ruby - universal-darwin-12 - GEM PATHS: - /Library/Ruby/Gems/1.8 - /Users/matthewcleghorn/.gem/ruby/1.8 - /System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/gems/1.8 - GEM CONFIGURATION: - :update_sources => true - :verbose => true - :benchmark => false - :backtrace => false - :bulk_threshold => 1000 - REMOTE SOURCES: - http://rubygems.org/ Any help greatly appreciated. Thanks.

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  • Vim hanging after parsing .vimrc (even a blank one) file on Solaris 10

    - by Seamus
    Hello all, I am having a problem with vim 7.2 hanging (for about 10 seconds) after it parses the .vimrc file. I had a similar issue in the past with tcsh on linux, but it was resolved by setting TERM to xterm-color. The same does not resolve the issue here. Any idea what may be causing this? $ env USER=redacted LOGNAME=redacted HOME=/home/redacted PATH=redacted MAIL=/var/spool/mail/redacted SHELL=/bin/tcsh TZ=redacted LC_COLLATE=C SSH_CLIENT=redacted SSH_CONNECTION=redacted SSH_TTY=/dev/pts/11 TERM=dtterm HOSTTYPE=sun4 VENDOR=sun OSTYPE=solaris MACHTYPE=sparc SHLVL=1 PWD=/home/redacted GROUP=redacted HOST=redacted REMOTEHOST=redacted QUOTA_CHECKED=1 WHOAMI=redacted HOSTNAME=redacted EDITOR=vim PRINTER=redacted INFOPATH=/software/gnu/gcc/2.8.1/sun4os5.10/info:/software/gnu/sun4os5/info:/software/gnu/emacs/20.3.1/sun4os5/info:/software/gnuish/sun4os5/info:/usr/local/gnu/info MANPATH=/software/gnu/gcc/2.8.1/sun4os5.10/man:/software/gnu/sun4os5/man:/software/gnu/emacs/20.3.1/sun4os5/man:/opt/rational/clearcase/doc/man:/usr/openwin/man:/usr/share/man:/usr/local/man:/usr/dt/man:/software/gnuish/sun4os5/man H_ARCH=sun4 H_ARCHOS=sun4os5 H_ARCHOS_SUB=sun4os5.10 H_OSTYPE=SUNOS H_OSREV=51000 T_ARCH=sun4 T_ARCHOS=sun4os5 T_ARCHOS_SUB=sun4os5.10 T_OSTYPE=SUNOS T_OSREV=51000 X11HOME=/usr/local/x11/sun4os5 OPENWINHOME=/usr/openwin LD_LIBRARY_PATH=/usr/dt/lib:/usr/openwin/lib MOTIFHOME=/usr/dt XINITRC=/usr/openwin/lib/Xinitrc GCC_REV=281

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  • (PHP) Converting an array of arrays from one format into another

    - by Richard Carter
    Hi, I currently have an array, created from a database, an example of which looks like the following: Array( [0] => Array ( objectid => 2, name => title, value => apple ), [1] => Array ( objectid => 2, name => colour, value => red ), [2] => Array ( objectid => 3, name => title, value => pear ), [3] => Array ( objectid => 3, name => colour, value => green ) ) What I would like to do is group all the items in the array by their objectid, and convert the 'name' values into keys and 'value' values into values of an associative array....like below: Array ( [0] => Array ( objectid => 2, title => apple, colour => red ), [1] => Array ( objectid => 3, title => pear, colour => green ) ) I've tried a few things but haven't really got anywhere.. Any ideas? Thanks in advance

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  • Low-level Keyboard Hooks/SendInput with Winkey+L possible? (workstation lockout is intercepted in Vi

    - by Brian Jorgensen
    I work on a project called UAWKS (Unofficial Apple Wireless Keyboard Support) that helps Windows users use Apple's bluetooth keyboard. One of the main goals of UAWKS is to swap the Cmd key (which behaves as Winkey in Windows) with Ctrl, allowing users to do Cmd+C for copy, Cmd+T for new tab, etc. It is currently developed using AutoHotkey, which worked pretty well under Windows XP. However, on Vista and Windows 7, Cmd+L causes problems: Regardless of low-level keyboard hooks, Winkey+L is always intercepted by Windows and normally locks the workstation... You can disable workstation locking with this registry hack, but pressing Winkey+L still can't be rebound in AHK Pressing Winkey+L leaves Winkey in the Keydown state until the next (additional) Winkey Up. Simulating a Keyup event doesn't seem to work either! It seems that Winkey+L is a special chord that messes everything else up. I've looked through the AHK source code, and they try to address this problem in SendKey() in keyboard_mouse.cpp (near line 883 in v1.0.48.05), but it doesn't work. I wrote up my own low-level keyboard hook application in C#, and I see the same problem. Has anyone else run into this? Is there a workaround?

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  • a + sing in email address

    - by d.andreykiv
    Hi. I need to submit an email address with a "+" sign and validate in on server. But server receives email like "[email protected]" as "aaa [email protected]". I send all data as POST request with following code NSURL* url = [NSURL URLWithString:[NSString stringWithFormat:@"%@%@", url, @"/signUp"]]; NSString *post = [NSString stringWithFormat:@"&email=%@&userName=%@&password=%@", user.email, user.userName, user.password]; NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:NO]; NSData* data = [self sendRequest:url postData:postData]; post variable before encoding has value &[email protected]&userName=Asdfasdfadsfadsf&password=sdfasdf after encoding it is same &[email protected]&userName=Asdfasdfadsfadsf&password=sdfasdf Method I use to send request looks like following code: -(id) sendRequest:(NSURL*) url postData:(NSData*)postData { // Create request NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init]; NSString *postLength = [NSString stringWithFormat:@"%d",[postData length]]; [request setURL:url]; [request setHTTPMethod:@"POST"]; [request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Current-Type"]; [request setValue:postLength forHTTPHeaderField:@"Content-Length"]; [request setHTTPBody:postData]; NSURLResponse *urlResponse; NSData *data = [NSURLConnection sendSynchronousRequest:request returningResponse:&urlResponse error:nil]; [request release]; return data; }

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  • RetinaJS and LESS : Background image doesn't show on iOS

    - by jidma
    I am trying to make a background image into a retina image using LESS CSS and RetinaJs: in my index.html file : <html> <head> <meta http-equiv="content-type" content="text/html; charset=UTF-8"> <meta name="viewport" content="width=device-width, initial-scale=1.0, user-scalable=0, minimum-scale=1.0, maximum-scale=1.0"> <meta name="apple-mobile-web-app-capable" content="yes"> <meta name="apple-mobile-web-app-status-bar-style" content="black"> [...] <link type="text/css" rel="stylesheet/less" href="resources/css/retina.less"> <script type="text/javascript" src="resources/js/less-1.3.0.minjs" ></script> [...] </head> <body> [...] <script type="text/javascript" src="resources/js/retina.js"></script> </body> </html> in my retina.less file: .at2x(@path, @w: auto, @h: auto) { background-image: url("@{path}"); @at2x_path: ~`"@{path}".split('.').slice(0, "@{path}".split('.').length - 1).join(".") + "@2x" + "." + "@{path}".split('.')["@{path}".split('.').length - 1]`; @media all and (-webkit-min-device-pixel-ratio : 1.5) { background-image: url("@{at2x_path}"); background-size: @w @h; } } .topMenu { .at2x('../../resources/img/topMenuTitle.png'); } I have both topMenuTitle.png (320px x 40px) and [email protected] (640px x 80px) in the same folder. When test this code: In Firefox i have the normal Background In the XCode iPhone simulator I also have the normal Background In the iPhone device, I don't have any background at all. I'm using GWT if that matters. Any suggestions ? Thanks.

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  • Why is the compiler caching my "random" and NULLED variables?

    - by alex gray
    I am confounded by the fact that even using different programs (on the same machine) to run /compile, and after nilling the vaues (before and after) the function.. that NO MATTER WHAT.. I'll keep getting the SAME "random" numbers… each and every time I run it. I swear this is NOT how it's supposed to work.. I'm going to illustrate as simply as is possible… #import <Foundation/Foundation.h> int main(int argc, char *argv[]) { int rPrimitive = 0; rPrimitive = 1 + rand() % 50; NSNumber *rObject = nil; rObject = [NSNumber numberWithInt:rand() % 10]; NSLog(@"%i %@", rPrimitive, rObject); rPrimitive = 0; rObject = nil; NSLog(@"%i %@", rPrimitive, rObject); return 0; } Run it in TextMate: i686-apple-darwin11-llvm-gcc-4.2 8 9 0 (null) Run it in CodeRunner: i686-apple-darwin11-llvm-gcc-4.2 8 9 0 (null) Run it a million times, if you'd like. You can gues what it will always be. Why does this happen? Why oh why is this "how it is"?

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  • API-based solutions for sending payments to people without bank accounts

    - by Tauren
    I'm looking for inexpensive ways to send payments to hundreds or thousands of individual contractors, even if they do not have a bank account. Currently I only need to support payment in the USA, but may eventually be international. Here's the scenario: I offer a service that allows an organization or manager-type person to coordinate contractors for very short term jobs. These jobs are typically only an hour or two in length. A contractor may get only one job over an entire month, several jobs spread out over a month, multiple jobs on a single day, or any other combination. Thus, a single contractor could earn as little as one job's payment up to potentially payment for dozens. Payment for a month could be as little as $10 up to $1000's. Right now, the system provides payroll reports to the manager and it is the manager's responsibility to produce checks, stuff envelopes, and send mail via the US postal service. I'd like to remove this burden from the manager and have all the payments taken care of for them automatically by the system. I'm not sure where to start or what the best options would be. I'm starting to look into the following solutions, but don't know specifics yet and would like some advice before pursuing them. I'd also like to hear about other ideas or suggestions. PayPal (Send Money, Adaptive Payments, x.com, other???) Amazon (Flexible Payments System?) Fund some sort of pre-paid debit card? Web service with API that mails checks for you? Direct deposit via a bank API (for users with bank accounts)? The problem is that many of these contractors may not be able to obtain bank accounts or credit cards within the USA. I don't mind doing a hybrid of solutions, but are there any that would work well with this issue? I want the solution to be easy to use for the contractors, meaning that they can get the money easily (via check in the mail, debit card ATM withdrawal, etc.)

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  • Error while compiling pjsip 2 for cxode 4.3.2 and SDK 5.1

    - by Linus Persson
    I'm trying to compile pjsip version 2 using the terminal and I'm getting constant error no matter what I try. Been looking for the answer all over the internet including stackoverflow. I downloaded pjsip version 2 using their subversion repository today so all files should be up to date. When following this guide: http://trac.pjsip.org/repos/wiki/Getting-Started/iPhone I get this error after running "make dep && make clean && make": ld: symbol(s) not found for architecture armv7 collect2: ld returned 1 exit status make[2]: *** [../bin/pjsua-arm-apple-darwin9] Error 1 make[1]: *** [pjsua] Error 2 make: *** [all] Error 1 When using the above guide combined with this guide: http://lists.pjsip.org/pipermail/pjsip_lists.pjsip.org/2011-October/013481.html I get this error after running "make dep && make clean && make": ld: symbol(s) not found for architecture arm collect2: ld returned 1 exit status make[2]: *** [../bin/pjsua-arm-apple-darwin10] Error 1 make[1]: *** [pjsua] Error 2 make: *** [all] Error 1 I've included /pjlib/include/pj/config_site.h with the following code: #define PJ_CONFIG_IPHONE 1 #include <pj/config_site_sample.h> How do I get pjsip to compile without errors? Please consider that I'm new to this, thank you!

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  • LDAP query using Python: always no result

    - by Grey
    I am trying to use python to query LDAP server, and it always returns me no result. and anyone help me find what wrong with my python code? it runs fine without excpetions, and it always has no result. i played around with the filter like "cn=partofmyname" but just no luck. thanks for help import ldap try: l = ldap.open("server") l.protocol_version = ldap.VERSION3 l.set_option(ldap.OPT_REFERRALS, 0) output =l.simple_bind("cn=username,cn=Users,dc=domian, dc=net",'password$R') print output except ldap.LDAPError, e: print e baseDN = "DC=rim,DC=net" searchScope = ldap.SCOPE_SUBTREE ## retrieve all attributes - again adjust to your needs - see documentation for more options retrieveAttributes = None Filter = "(&(objectClass=user)(sAMAccountName=myaccount))" try: ldap_result_id = l.search(baseDN, searchScope, Filter, retrieveAttributes) print ldap_result_id result_set = [] while 1: result_type, result_data = l.result(ldap_result_id, 0) if len(result_data) == 0: print 'no reslut' break else: for i in range(len(result_set)): for entry in result_set[i]: try: name = entry[1]['cn'][0] email = entry[1]['mail'][0] phone = entry[1]['telephonenumber'][0] desc = entry[1]['description'][0] count = count + 1 print "%d.\nName: %s\nDescription: %s\nE-mail: %s\nPhone: %s\n" %\ (count, name, desc, email, phone) except: pass ## here you don't have to append to a list ## you could do whatever you want with the individual entry #if result_type == ldap.RES_SEARCH_ENTRY: # result_set.append(result_data) # print result_set except ldap.LDAPError, e: print e l.unbind()

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  • How to manage a single-selection (exclusive) list?

    - by Andy
    I've got a detail view that consists of a table view with a few rows of data. I can fill the rows just fine, and moving back and forth from the parent view to the subview works too. This detail view should allow the user to select a single value, placing a checkmark accessory in the cell and then returning to the parent view (where the selected value becomes the cell.textLabel.text property of the cell from which the detail view was called). This all works as of right now. However, when the user taps the cell in the parent view to go back to the detail view (to change their selection), my checkmark has disappeared and I cannot for the life of me figure out how to make it stay. Here's my cellForRowAtIndexPath: method: - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { static NSString *CellIdentifier = @"Cell"; UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier]; if (cell == nil) { cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleSubtitle reuseIdentifier:CellIdentifier] autorelease]; } NSString *labelText = [[phones objectAtIndex:indexPath.row] valueForKey:@"phoneNumberLabel"]; cell.textLabel.text = labelText; NSString *currentLabel = [ruleBuilder.tableView cellForRowAtIndexPath:selectedIndexPath].textLabel.text; if (labelText == currentLabel) { cell.accessoryType = UITableViewCellAccessoryCheckmark; } NSString *detailText = [[phones objectAtIndex:indexPath.row] valueForKey:@"phoneNumber"]; cell.detailTextLabel.text = detailText; return cell; } I've checked out Apple's sample code for exclusive-list management in Table View Programming Guide, but the snippet seems incomplete, and I can't find the related code in Apple's sample code. This doesn't seem like it ought to be that hard to do.

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  • How Session out trigger on browser close?

    - by Hemant Kothiyal
    Hi, Yesterday morning i open gmail account in Internet Exlorer second tab. I checked my mail and closed that tab (not browser). Then at the time of evining i again open second tab of browser and enetr gmail.com, it automatically redirect me at my email account without asking login. I shocked and i thought i should remain browser open for whole night and today open gmail in second tab , it behave similar means without login screen it redirect in my gmail account. Then i closed that tab and open another browser session and enter gmail i again surprised that i redirect me login page. At the same time i open second tab of first browser and it automatically redirect me at mail account page. What i councluded by this behaviour is that might be gmail server keep my browser id at their server so that whenever i eneter gmail.com on second tab of first browser, it automatically redirect me at gmail account. I don't know i am right or not? Please clear me this concept? What happens with my session at gmail server when i closed my browser tab? As per my opinion it should automatically logout me but why this doesn't happened?

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  • How do I switch out Views in a Cocoa application?

    - by David Garcia
    So I'm beginning to learn how to use Cocoa. I think I've pretty much got it but I'm hung up on creating and switching views. I'm rewriting a game I made a little bit ago for practice. All I want is one window (preferably not resizable) and I want to be able to switch out views for different screens in the game. First, I have the main menu (Start Game, High Scores, Exit). Then I need a window for each screen (Gameplay screen, Highscore screen). What I'm getting confused with is how to design this. I looked up NSViewController thinking it manages views but it doesn't. It only manages one view by loading it really. I don't understand why I'd need to use NSViewController then. Couldn't I just have a window class that contains multiple subclasses of NSView and load them like that? I'm not sure I understand the purpose of the ViewController. Does my Window Class really need to subclass NSWindowController? I was trying to follow the example of Apple's ViewController example and it has a window controller class that's a subclass of NSWindowController. I don't see what the purpose was of subclassing that. All NSWindowController seems to add is - initWithPath:(NSString *)newPath but I fail to see the use in that either when I can just edit the plist file to open the window on start up. Apple's example also has an NSView variable and an NSViewController variable. Don't you only need one variable to store the current view? Thanks in advance guys, I'm really confused as to how this works.

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  • Using CookieJar in Python to log in to a website from "Google App Engine". What's wrong here?

    - by brilliant
    Hello everybody, I've been trying to find a python code that would log in to my mail box on yahoo.com from "Google App Engine" . Here (click here to see that page) I was given this code: import urllib, urllib2, cookielib url = "https://login.yahoo.com/config/login?" form_data = {'login' : 'my-login-here', 'passwd' : 'my-password-here'} jar = cookielib.CookieJar() opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(jar)) form_data = urllib.urlencode(form_data) # data returned from this pages contains redirection resp = opener.open(url, form_data) # yahoo redirects to http://my.yahoo.com, so lets go there instead resp = opener.open('http://mail.yahoo.com') print resp.read() The author of this script looked into HTML script of yahoo log-in form and came up with this script. That log-in form contains two fields, one for users' Yahoo! ID and another one is for users' password. Here is how HTML code of that page for both of those fields looks like: User ID field: <input type="text" maxlength="96" class="yreg_ipt" size="17" value="" id="username" name="login"> Password field: <input type="password" maxlength="64" class="yreg_ipt" size="17" value="" id="passwd" name="passwd"> However, when I uploaded this code to Google App Engine I discovered that this log-in form keeps coming back to me, which, I assume, means that logging-in process didn't succeed. Why is it so?

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  • Using CookieJar in Python to log in to a website from "Google App Engine". What's wrong here?

    - by brilliant
    Hello everybody, I've been trying to find a python code that would log in to my mail box on yahoo.com from "Google App Engine" . Here (click here to see that page) I was given this code: import urllib, urllib2, cookielib url = "https://login.yahoo.com/config/login?" form_data = {'login' : 'my-login-here', 'passwd' : 'my-password-here'} jar = cookielib.CookieJar() opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(jar)) form_data = urllib.urlencode(form_data) # data returned from this pages contains redirection resp = opener.open(url, form_data) # yahoo redirects to http://my.yahoo.com, so lets go there instead resp = opener.open('http://mail.yahoo.com') print resp.read() The author of this script looked into HTML script of yahoo log-in form and came up with this script. That log-in form contains two fields, one for users' Yahoo! ID and another one is for users' password. Here is how HTML code of that page for both of those fields looks like: User ID field: <input type="text" maxlength="96" class="yreg_ipt" size="17" value="" id="username" name="login"> Password field: <input type="password" maxlength="64" class="yreg_ipt" size="17" value="" id="passwd" name="passwd"> However, when I uploaded this code to Google App Engine I discovered that this log-in form keeps coming back to me, which, I assume, means that logging-in process didn't succeed. Why is it so?

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