Search Results

Search found 41996 results on 1680 pages for 'facebook php sdk'.

Page 224/1680 | < Previous Page | 220 221 222 223 224 225 226 227 228 229 230 231  | Next Page >

  • Looping through values in NSDictionary throws fault

    - by jud
    I have a plist file that I am loading into an NSDictionary *setDictionary that contains a set of fields, pictureDesc1, pictureDesc2, etc. Once the NSDictionary is loaded, I can retrieve a value using [setDictionary objectForKey:@"pictureDesc1"]; But I cannot do a loop like this: for (int i=1; i<=numberOfPictures; i++) { NSString *keyName = [NSString stringWithFormat:@"pictureDesc%d",i]; NSString *description = [NSString stringWithFormat:@"%@", [setDictionary objectForKey:keyName]]; } Is there a different way to dynamically call keys from within an NSDictionary?

    Read the article

  • xcode - defining integer variables

    - by Mike
    If I have #define myVariable 10 and later I use this as in [self doSomething:myVariable]; Supposing doSomethign method is like - (void) doSomething:(int)myNumber; I receive a warning telling me that a "]" is expected before the ";" why is that and how to solve this? thanks for any help.

    Read the article

  • SIMPLE PHP MVC Framework [closed]

    - by Allen
    I need a simple and basic MVC example to get me started. I don't want to use any of the available packaged frameworks. I am in need of a simple example of a simple PHP MVC framework that would allow, at most, the basic creation of a simple multi-page site. I am asking for a simple example because I learn best from simple real world examples. Big popular frameworks (such as code igniter) are to much for me to even try to understand and any other "simple" example I have found are not well explained or seem a little sketchy in general. I should add that most examples of simple MVC frameworks I see use mod_rewrite (for URL routing) or some other Apache-only method. I run PHP on IIS. I need to be able to understand a basic MVC framework, so that I could develop my own that would allow me to easily extend functionality with classes. I am at the point where I understand basic design patterns and MVC pretty well. I understand them in theory, but when it comes down to actually building a real world, simple, well designed MVC framework in PHP, I'm stuck. Edit: I just want to note that I am looking for a simple example that an experienced programmer could whip up in under an hour. I mean simple as in bare bones simple. I don't want to use any huge frameworks, I am trying to roll my own. I need a decent SIMPLE example to get me going.

    Read the article

  • Loading table sections when using headers

    - by Luis Tovar
    I cant seem to wrap my head around this. I have googled, and overstacked for hours now looking for examples that i can relate to. What I have is two arrays. The name of my first NSMutableArray is "showDates". I have 3 objects in here. Object 0: "Today, May 20th" Object 1: "Tomorrow, May 21st" Object 2: "Saturday, May 22nd" Then I have my second NSMutableArray named "showTimes" I have about 15 objects in there with strings in each object. ( i hope that makes sense? ) Each object is structured like this: Object 0: showID @"98022" eventID @"833" showTime @"1:30pm" showDate @"Today, May 20th" auditorium @"9" venue @"2991" Object 1: showID @"98222" eventID @"813" showTime @"2:30pm" showDate @"Tomorrow, May 21st" auditorium @"9" venue @"2991" Etc, etc, .... I have the headers working great in my tableView, but I cant seem to figure out how to add the objects in my "showTimes" array under the correct header. Any help would be greatly appreciated.

    Read the article

  • Lack of security in many PHP applications?

    - by John
    Over the past year of freelancing, I inherited two web projects, both of them built in PHP, both of them with sensitive information like credit card info, bank info, etc... In one application, when I typed http://thecompany.com/admin/, and without being asked for a username and password, I saw every user's sensitive information, including credit card numbers, bank account numbers etc... In another application, I was able to bypass the login screen by simply typing http://the2ndcompany.com/customer.php?user_id=777, and again, without any prompts for username and password, i was able to see user 777's credit card info. I cycled through a few more user_ids (any integer) and saw each person's credit card info. Is something wrong here? Or is this the quality of work that the "average" programmer produces? Because if this is what the average programmer produces, does that means I'm an...gasp...elite programmer?? No..that can't be right....something doesn't make sense. So my question is, is it just coincidence that I inherited two applications both of which are dangerously lacking in security? Or are there are a lot of bad PHP programmers out there?

    Read the article

  • Unable to register achievements

    - by abe
    I've been unable to register any achievements. I keep getting the following: {"error":{"message":"(#3502) Object at achievement URL is not of type game.achievement","type":"OAuthException","code":3502}} When I run my URL through the linter, I get: Open Graph Warnings That Should Be Fixed Inferred Property: The 'og:url' property should be explicitly provided, even if a value can be inferred from other tags. Inferred Property: The 'og:title' property should be explicitly provided, even if a value can be inferred from other tags. Although when I load the URL myself I clearly see those set in the meta tags. My HTML looks like: <html> <head prefix="og: http://ogp.me/ns# fb: http://ogp.me/ns/fb# game: http://ogp.me/ns/game#"> <meta property="fb:app_id" content="<MY_APP_ID>" /> <meta property="og:type" content="game.achievement" /> <meta property="og:url" content="http://<MY_DOMAIN>/ach10.html" /> <meta property="og:title" content="Title" /> <meta property="og:description" content="Description" /> <meta property="og:image" content="http://placekitten.com/g/200/300" /> </head> <body> Hmm.. </body> </html> Also interesting, is the graph API sees it as: { "url": "http://<MY_DOMAIN>/ach10.html", "type": "website", "title": "http://<MY_DOMAIN>/ach10.html", "updated_time": "2012-03-09T19:49:14+0000", "id": "<ID>" } And the scraped URL returns nothing ... anyone have any ideas? I've also tried adding the Game Achievement object in the Open Graph settings and every combination of Sandbox Mode/Social Discovery enabled and disabled.

    Read the article

  • Getting a UIImage from MySQL using PHP and jSON

    - by Daniel
    I'm developing a little news reader that retrieves the info from a website by doing a POST request to a URL. The response is a jSON object with the unread-news. E.g. the last news on the App has a timeStamp of "2013-03-01". When the user refreshes the table, it POSTS "domain.com/api/api.php?newer-than=2013-03-01". The api.php script goes to the MySQL database and fetches all the news posted after 2013-03-01 and prints them json_encoded. This is // do something to get the data in an array echo $array_of_fetched_data; for example the response would be [{"title": "new app is coming to the market", "text": "lorem ipsum dolor sit amet...", image: XXX}] the App then gets the response and parses it, obtaining an NSDictionary and adds it to a Core Data db. NSDictionary* obtainedNews = [NSJSONSerialization JSONObjectWithData:responseData options:kNilOptions error:&error]; My question is: How can I add an image to the MySQL database, store it, pass it using jSON trough a POST HTTP Request and then interpret it as an UIImage. It's clear that to store an UIImage in CoreData, they must be transform into/from NSData. How can I pass the NSData back and forth to a MySQL db using php and jSON? How should I upload the image to the db? (Serialized, as a BLOB, etc)

    Read the article

  • "No database selected" even when db clearly selected

    - by Someone
    One of my webpages gets a recurring error: "No database selected", even though the DB is selected. Right about now it's a 50-50 chance whether the page will load just fine, or whether I receive this error. After one or two reloads, the page works again. I am including the exact same connection file on my other pages, and I don't have this problem. What could be the cause of this? I'm using ensim pro for webhosting. TIA.

    Read the article

  • iPhone - Switch Tab from UIWebView

    - by user269737
    I have a webview and I want to manually switch to another tab during a specific event. The event is arbitray, but I can't figure out hwo to switch teh tab. On my other views, I have the following code: self.tabBarController.selectedViewController = [self.tabBarController.viewControllers objectAtIndex:2]; However, this does not work in my custom UIWebView class. Is there a simple solution to this? Thanks

    Read the article

  • How to cleverly stop "while loop" (php)

    - by user3735697
    I'm having trouble with creating code that echoes a bunch of stuff that is corresponding to the mysql database row. It needs to keep creating the content until all rows are used and then stop. But for some reason the php file causes the browser to keep loading (it never ends). Any help would be appreciated! Thanks! <?php mysql_connect ("localhost", "root", "") or die ("We couldn't connect!"); mysql_select_db ("dr"); mysql_query ("SELECT * FROM songs"); $result = mysql_query ("SELECT * FROM songs"); while ($row=mysql_fetch_array($result)) { $name = $row ['songname']; $genres = $row ['songgenres']; $mediafire = $row ['mediafirelink']; $dropbox = $row ['dropboxlink']; $source = $row ['audiosource']; echo " <div class='playing'> <!-- ======== Song Name ======== --> <li class='songnameli' id='$source'> <span class='info'>$name</span> <audio> <source src='music/singles/$source.mp3'> <source src='music/singles/$source.ogg'> </audio> </li> <!-- ======== Playlist ======== --> <li class='playlistli'> <img src='icons/addtoplaylist.png' title='Add tot the playlist!' /> </li> <!-- ======== Genres ======== --> <li class='genresli'> <img src='icons/genres.png' title='Related genres' /> <span class='addedtext genres'>$genres</span> </li> <!-- ======== Social Media links ======== --> <li> <span> <img src='icons/share.png' alt='Share this with your friends!' title='Share this!'> <!-- /// facebook /// --> <a href='http://www.facebook.com/sharer.php?u=http://www.declassified-recordings.com' class='addedtext nlink' target='blank_' onclick='popup (this.href, 800, 500); return false'>Facebook </a> <span>/</span> <!-- /// Twitter /// --> <a href='http://twitter.com/share? text=Thank%20you%20For%20Sharing!%20It%20means%20the%20world%20to%20us!%40Declassifi3d%20 &url=http://www.declassified-recordings.com' class='twitterlink nlink' target='blank_' onclick='popup (this.href, 800, 500); return false'>Twitter</a> </span> </li> <!-- ======== Download links ======== --> <li> <img src='icons/download.png' title='Download!' /> <span> <!-- /// Mediafire /// --> <a href='$mediafire' class='addedtext nlink' target='_blank'>Mediafire</a> <span class='genres'>/</span> <!-- /// Dropbox /// --> <a href='$mediafire' class='twitterlink nlink' target='_blank'>Dropbox</a> </span> </li> </div>"; } mysql_close (); ?>

    Read the article

  • Refactoring or Rewriting Monolithic PHP Spaghetti Codebase

    - by nategood
    I've inherited a really poorly designed PHP spaghetti code project. It's been gaining a good bit of traffic recently and is starting to have performance issues on top of the poor monolithic code base. Its maxing out performance on a chunky 16GB dedicated machine when it really shouldn't be. I'm planning on doing some performance tweaks right off the bat to help the performance issue, but this still won't really help the horrible code base. The team is small but expecting to grow very soon. I've read Joel's article on the troubles of doing a complete rewrite and see the concerns. But how bad does the code base have to be before you consider a rewrite? There is PHP handling logic interjected into what one would usually consider a "view". Even worse, in some places SQL statements are in these same files! The only real separation of presentation and logic are a few PHP scripts that serve as function libraries. These scripts do most of the ORM stuff... if you can even call it that. Trying to slowly refractor this seems like a nightmare. Open to your thoughts and opinions... however not interested in hearing, "Run away, Run away!".

    Read the article

  • Execute javascript in PHP

    - by Andreas Bonini
    I'm generating your typical Web 2.0 HTML page with PHP: it contains a lot of <script> tags and javascript code that will substantially change the DOM after the load event. Is there a way to get the final HTML code directly from PHP, without opening the page with any browser? For example, let's say the HTML for the page is (it's just an example): <html> <head> <script>...the jquery library code...</script> <script>$(document).ready(function() { $("body").append("<p>Hi!</p>");</script> </head> <body> </body> </html> This HTML is saved in the $html PHP variable. Now, I want to pass that variable to some function that will return $result = <html>....<body><p>Hi!</p></body></html>. Is this possible?

    Read the article

  • Retrieving database column using JSON [migrated]

    - by arokia
    I have a database consist of 4 columns (id-symbol-name-contractnumber). All 4 columns with their data are being displayed on the user interface using JSON. There is a function which is responisble to add new column to the database e.g (countrycode). The coulmn is added successfully to the database BUT not able to show the new added coulmn in the user interface. Below is my code that is displaying the columns. Can you help me? table.php $(document).ready(function () { // prepare the data var theme = getDemoTheme(); var source = { datatype: "json", datafields: [ { name: 'id' }, { name: 'symbol' }, { name: 'name' }, { name: 'contractnumber' } ], url: 'data.php', filter: function() { // update the grid and send a request to the server. $("#jqxgrid").jqxGrid('updatebounddata', 'filter'); }, cache: false }; var dataAdapter = new $.jqx.dataAdapter(source); // initialize jqxGrid $("#jqxgrid").jqxGrid( { source: dataAdapter, width: 670, theme: theme, showfilterrow: true, filterable: true, columns: [ { text: 'id', datafield: 'id', width: 200 }, { text: 'symbol', datafield: 'symbol', width: 200 }, { text: 'name', datafield: 'name', width: 100 }, { text: 'contractnumber', filtertype: 'list', datafield: 'contractnumber' } ] }); }); data.php <?php #Include the db.php file include('db.php'); $query = "SELECT * FROM pricelist"; $result = mysql_query($query) or die("SQL Error 1: " . mysql_error()); $orders = array(); // get data and store in a json array while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) { $pricelist[] = array( 'id' => $row['id'], 'symbol' => $row['symbol'], 'name' => $row['name'], 'contractnumber' => $row['contractnumber'] ); } echo json_encode($pricelist); ?>

    Read the article

  • change launch image(default.png)??

    - by hemant
    i am quite new to iphone development but i have been given a old application and told to change the launch image(default.png)..i tried to google it but couldn't get much help from it?? how can i change the default image in my old application?? any information regarding it will be really helpful??

    Read the article

  • Why is my PHP upload script not working?

    - by Turner
    Hello all, I am doing some simple work with uploading a file. I am ignoring error checking and exceptions at this point just to get my uploads working. I have this HTML form: <form action='addResult.php' method='post' enctype='multipart/form-data' target='results_iFrame' onsubmit='startUpload();'> Entry: <input type='text' id='entry' /> Stop: <input type='text' id='stop' /> Final: <input type='text' id='final' /> Chart: <input type='file' id='chart' /> <input type='submit' value='Add' /></form> As you can see, it calls 'addResult.php' within the iFrame 'results_iFrame'. The Javascript is just for animation purposes and to tell me when things are finished. addResult.php has this code in it (along with processing the other inputs): $upload_dir = "../img/"; $chart_loc = $upload_dir.basename($_FILES['chart']['name']); move_uploaded_file($_FILES['chart']['tmp_name'], $chart_loc); print_r($_FILES); It uses the 'chart' input from the form and tries to upload it. I have the print_r() function to display some information on $_FILES, but the array is empty, thus making this fail. What could I be doing wrong?

    Read the article

  • ORDER BY column_name help (via link in HTML table view) (PHP MySQL

    - by Derek
    My output for my table in HTML has several columns such as userid, name, age, dob. The table heading is simply the title of the column name, I want this to be a link, and when clicked, the selected column is sorted in order, ASC, and then DESC (on next click). I thought this was pretty straight forward but I'm having some difficulty. So far, I have produced this, and no output is taken, apart from the URL works by displaying 'users.php?orderby=userid' <?php if(isset($_GET['orderby'])){ $orderby = $_GET['orderby']; $query_sv = "SELECT * FROM users BY ".mysql_real_escape_string($orderby)." ASC"; } //default query else{ $query_sv = "SELECT * FROM users BY user_id DESC"; } ?> <tr> <th><a href="<?php echo $_SERVER['php_SELF']."?orderby=userid";?>">User ID</a></th> Hoefully if I get this working, I can sort the users by D.O.B. next also using the same principles. Does anyone have any ideas?

    Read the article

  • PHP Class Question

    - by Jerry
    Hi all I am trying to build a PHP class to check the username and password in MySql. I am getting "mysql_query(): supplied argument is not a valid MySQL-Link resource in D:\2010Portfolio\football\main.php on line 38" database has errors:" message. When I move my userQuery code out of my Class, it works fine. Only if it is inside my Class. I am not sure if the problem is that I don't build the connection to mysql inside my Class or not. Thanks for any helps!! Here is my code <?php $userName=$_POST['userName']; $userPw=$_POST['password']; class checkUsers { public $userName; public $userPw; function checkUsers($userName='', $userPw=''){ $this->userName=$userName; $this->userPw=$userPw; } function check1(){ if (empty($this->userName) || empty($this->userPw)){ $message="<strong>Please Enter Username and Password</strong>"; }else{ //line 38 is next line $userQuery=mysql_query("SELECT userName, userPw FROM user WHERE userName='$this->userName' and userPw='$this->userPw'", $connection); if (!$userQuery){ die("database has errors: ". mysql_error()); } if(mysql_num_rows($userQuery)==0){ $message="Please enter valid username and password"; } }//end empty check return $message; }//end check1 method }//end Class $checkUser=new checkUsers($userName, $userPw); echo $checkUser->check1(); ?> I appreciate any helps!!!!

    Read the article

  • Javascript + PHP $_POST array empty

    - by Peterim
    While trying to send a POST request via xmlhttp.open("POST", "url", true) (javascript) to the server I get an empty $_POST array. Firebug shows that the data is being sent. Here is the data string from Firebug: a=1&q=151a45a150.... But $_POST['q'] returns nothing. The interesting thing is that file_get_contents('php://input') does have my data (the string above), but PHP somehow doesn't recognize it. Tried both $_POST and $_REQUEST, nothing works. Headers being sent: POST /test.php HTTP/1.1 Host: website.com User-Agent: Mozilla/5.0 (Windows; U; Windows NT 6.1; en-US; rv:1.9.2.3) Gecko/20100401 Firefox/3.6.3 Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8 Accept-Language: en-us;q=0.7,en;q=0.3 Accept-Encoding: gzip,deflate Accept-Charset: utf-8;q=0.7,*;q=0.7 Keep-Alive: 115 Connection: keep-alive Referer: http://website.com/ Content-Length: 156 Content-Type: text/plain; charset=UTF-8 Pragma: no-cache Cache-Control: no-cache Thank you for any suggestions.

    Read the article

  • TouchCode XML parsing error

    - by itsaboutcode
    Hi, I have a xml document which has only one element in the document, which is <error>error string<error> But when i try to parse it, it says this document has no element at all. In other words when i try to access the rootElement it says "null" CXMLDocument *rssParser = [[[CXMLDocument alloc] initWithContentsOfURL:url options:0 error:nil] autorelease]; NSLog(@"Root: %@",[[rssParser rootElement] name]); Please tell me what is wroing with this. Thanks

    Read the article

  • Setting up a LAMP VM server for Development and Testing?

    - by TdotThomas
    Info: I would like to set up a VM server on my local computer which will serve pages in the exact same way as my current hosting (but only to me on my local computer). I currently pay a big web hosting company to host my website & web store and they are doing a great job, but I would like to be able to work on my Web site and its corresponding MySQL DB, HTML, and PHP code without being at risk of messing something completely up on the live servers. My current plan of action: Set up a VM webserver with Debian, MySQL, PHP, Apache. Copy web store (PHP/HTML) code to VM server. Copy my current MySQL databases from my hosting provider and install on VM server. Modify and test new features on VM server. Upload MySQL DB and HTML/PHP code back to web host's server where it should work as before but with new modifications. Questions: Now I'm pretty sure I have steps one and two down correctly but I can't for the life of me figure out how to proceed next, so here are my questions. I have my /etc/host file set up so www.MySite.test redirects to the IP address of the local VM webserver. Once I import my PHP/HTML files and MySQL file whats the best way to navigate around the fact that all of my files and DBs will reference www.MySite.com. I can export my MySQL dbs but do I also have to export my MySQL users and passwords to access those db or are those coded into my html/php code?

    Read the article

  • Finding cause of memory leaks in large PHP stacks

    - by Mike B
    I have CLI script that runs over several thousand iterations between runs and it appears to have a memory leak. I'm using a tweaked version of Zend Framework with Smarty for view templating and each iteration uses several MB worth of code. The first run immediately uses nearly 8MB of memory (which is fine) but every following run adds about 80kb. My main loop looks like this (very simplified) $users = UsersModel::getUsers(); foreach($users as $user) { $obj = new doSomethingAwesome(); $obj->run($user); $obj = null; unset($obj); } The point is that everything in scope should be unset and the memory freed. My understanding is that PHP runs through its garbage collection process at it's own desire but it does so at the end of functions/methods/scripts. So something must be leaking memory inside doSomethingAwesome() but as I said it is a huge stack of code. Ideally, I would love to find some sort of tool that displayed all my variables no matter the scope at some point during execution. Some sort of symbol-table viewer for php. Does anything like that or any other tools that could help nail down memory leaks in php exist?

    Read the article

  • Filter sub-categories like in layered navigation

    - by russjman
    I created a new template file catalog/category/list.phtml. This is to display all sub categories of the current category. I have layered navigation which is displaying sub-categories as one of the filters, but I want this new template to work with these filters as well. Right now when i click the subcategory filter, it filters all products on the page, but still displays all categories of the parent category. $_filters is how i am trying to access these filters, but i get nothing. Is there something i am not initializing correctly to have access to these filters from the layered navigation. <?php $_helper = $this->helper('catalog/output'); $_filters = $this->getActiveFilters(); echo $_filters; if (!Mage::registry('current_category')) return ?> <?php $_categories=$this->getCurrentChildCategories() ?> <?php $_count = is_array($_categories)?count($_categories):$_categories->count(); ?> <?php if($_count): ?> <?php foreach ($_categories as $_category): ?> <?php if($_category->getIsActive()): ?> <?php $cur_category=Mage::getModel('catalog/category')->load($_category->getId()); $layer = Mage::getSingleton('catalog/layer'); $layer->setCurrentCategory($cur_category); $_imgHtml = ''; if ($_imgUrl = $this->getCurrentCategory()->getImageUrl()) { $_imgHtml = '<img src="'.$_imgUrl.'" alt="'.$this->htmlEscape($_category->getName()).'" title="'.$this->htmlEscape($_category->getName()).'" class="category-image" />'; $_imgHtml = $_helper->categoryAttribute($_category, $_imgHtml, 'image'); } echo $_category->getImageUrl(); ?> <div class="category-image-box"> <div class="category-description clearfix" > <div class="category-description-textbox" > <h2><span><?php echo $this->htmlEscape($_category->getName()) ?></span></h2> <p><?php echo $this->getCurrentCategory()->getDescription() ?></p> </div> <a href="<?php echo $this->getCategoryUrl($_category) ?>" class="collection-link<?php if ($this->isCategoryActive($_category)): ?> active<?php endif ?>" >See Entire Collection</a> <a href="<?php echo $this->getCategoryUrl($_category) ?>"><?php if($_imgUrl): ?><?php echo $_imgHtml ?><?php else: ?><img src="/store/skin/frontend/default/patio_theme/images/category-photo.jpg" class="category-image" alt="collection" /><?php endif; ?></a> </div> <?php echo '<pre>'.print_r($_category->getData()).'</pre>';?> </div> <?php endif; ?> <?php endforeach ?> <?php endif; ?>

    Read the article

  • Php - divide time period into equal intervals

    - by experc
    Hi! I am working on my php course project and for the past few days I have stucked at the point where I have to create php function which gets 5 parameters which represents information about the working time of some department - when the work starts/ends, when the lunchtime (or any other break) starts/ends and integer representing minutes into how small piecies we should divide time period. Besides - it's possible that there are not any breaks in the working time. The function should return all intervals from working time. function split_time_into_intervals($work_starts,$work_ends,$break_starts=null; $break_ends=null,$minutes_per_interval=60){ $intervals=array(); //all of the function code return $intervals; } So if I have the following parameters for the function function split_time_into_intervals("8:30","14:50","11:45"; "12:25"){ .. } I would like to retrieve the following array: $intervals[0]['starts']="8:30"; $intervals[0]['ends']="9:30"; $intervals[1]['starts']="9:30"; $intervals[1]['ends']="10:30"; $intervals[2]['starts']="10:30"; $intervals[2]['ends']="11:30"; $intervals[3]['starts']="11:30"; $intervals[3]['ends']="11:45"; //this interval was smaller than 60 minutes - because of the break (which starts at 11:45) $intervals[4]['starts']="12:25";//starts when the break ends $intervals[4]['ends']="13:25"; // interval is again 60 minutes $intervals[5]['starts']="13:25"; $intervals[5]['ends']="14:25"; $intervals[6]['starts']="14:25"; $intervals[6]['ends']="14:50"; //this period is shorter than 60 minutes - because work ends Any advises? I would apriciate any php (or C#) code regarding to this problem!

    Read the article

< Previous Page | 220 221 222 223 224 225 226 227 228 229 230 231  | Next Page >