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• Bookmarkable URLs after Ajax for Wicket

  - by Wolfgang

  There is this well-known problem that browsers don't put Ajax request in the request history and cause problems for bookmarkability, forward/back button, and refresh. Also, there is a common solution to that problem that appends the hash symbol # and some additional parameters to the URL by using Javascript window.location.hash = .... In this question a basic solution to this problem is proposed, for example. = My question is if such a solution has been integrated in Wicket, so that existing Wicket facilities are used and no custom Javascript had to be added. If not, I'd be interested in how this could be done. Such a solution had to answer the question what should be put after the hash. I like the idea that the bookmarkable URL that (in the non-Ajax case) were in front of the hash could be put behind it. For example, when you are on http://host/catalog and reach a page http://host/product/xyz the Ajax-triggered URL would be http://host/catalog#/product/xyz. Then it would be easy to write an onload handler that checks for the # and does a redirect to the URL after the hash.

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• create dynamic navigation from xml file in flash cs3

  - by mjr

  action script newbie here :-) What I want to do is this, hand an xml file to a swf and have the swf generate a dynamic text box and button for each of the links in the xml file a rudimentary navigation here's the xml <?xml version="1.0" encoding="UTF-8"?> <page> <page name="Page Name 1" url="/page-1/" /> <page name="Page Name 2" url="/page-2/" /> <page name="Page Name 3" url="/page-3/" /> <page name="Page Name 4" url="/page-4/" /> </page> and in my fla I have a button in my library named 'nav_button' there's a layer named actions and in frame 1 I have this var xml:XML; var xmlList:XMLList; var xmlLoader:URLLoader = new URLLoader(); var button:Button = new Button(); xmlLoader.load(new URLRequest("links.xml")); xmlLoader.addEventListener(Event.COMPLETE, xmlLoaded); function xmlLoaded(event:Event):void { xml = XML(event.target.data); xmlList = xml.children(); trace(xml.length()); for(var i:int = 0; i < xmlList.length(); i++) { button = new Button(); button.x = 25; button.y = i * 50 +25; addChild(button); } } the xml imports fine, but when it comes to the for loop and adding the buttons and text boxes to the stage, I'm toast

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• CSS div rounded corners

  - by Ulkmun

  I'm attempting to do the following... Here's what I've got right now.. but it's not rendering correctly. Does anyone have any idea as to how I'd fix this? CSS /* Curved Corners */ .bl { background: url(bl.gif) 0 100% no-repeat; /*background-color:#EFFBEF;*/ width: 700px; margin-left: auto ; margin-right: auto ;} .br { background: url(br.gif) 100% 100% no-repeat; } .tl { background: url(tl.gif) 0 0 no-repeat; } .tr { background: url(tr.gif) 100% 0 no-repeat; } .clear {font-size: 1px; height: 1px} HTML <div class="bl"><div class="br"><div class="tl"><div class="tr"> <div id="header"> </div> <div id="footer"> </div> </div></div></div></div>

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• Chrome extension custom cursor

  - by the_nakos

  Hi, I building an Google Chrome extension that place some IMG tag in sites. This img tag on :hover must show a custom cursor. The extension uses jQuery as its injected core script. I tried the following methods: 1. var cursor = 'url('+chrome.extension.getURL('icons/cursor.cur')+')'; $('#myImgId').css({ 'position': 'absolute', 'top':'5px', 'left':'5px', 'cursor':cursor }); This is the best working. On smaller sites its shows the cursor. On slower loading sites it does not. But on little sites it fails sometimes. 2. var cursor = 'url('+chrome.extension.getURL('icons/cursor.cur')+')'; $('<style>#myImgId{cursor:'+cursor+'}</style>').appendTo('head'); This did nothing at all. 3. In manifest.json I injected the css. "content_scripts": [ { "matches": ["http://*/*"], "css": ["css/style.css"], "js": ["j/c.js", "j/s.js"] } The css file just had the cursor:url(icons/cursor.cur) as I don't have idea, how to get real url in a css file. This isn't working at all. I think it must work like this, I didn't find reference for this on code.google though.

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• Accessing a share point site using the object model.

  - by Prashanth

  Hi I am trying to access a share point site using the SP object model from a console application. I am trying to do something like this.. SPSite site = new SPSite(sitePath) //Operations go here This works fine when the share point site and the console app are on the same machine. However when the console app and the site are on different machines, I get an error "The Web application at "http://server/url" could not be found. Verify that you have typed the URL correctly. If the URL should be serving existing content, the system administrator may need to add a new request URL mapping to the intended application" Here are the things that I have already done: 1) I have tried accessing the site via both IP address as well as machine name, assuming that it could be a DNS resolution issue. 2) Initially I impersonated using a farm admin account, still i could not access. Then I added myself as the farm admin, still no joy. 4) The site is accessible via IE. So it is not a permission issue I guess. 5) I have tried almost all the solutions suggested by various links obtained by googling the error message. I am trying this on share point 2010. A similar issue occurs on 2007 also. Sometimes its kind of frustrating to do SharePoint development , since I get the feeling of stumbling from one error to the next, with no clue as to what could be wrong and the error messages not being helpful in the least :(

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• CSS3 background-origin property does work in firefox?

  - by hh54188

  I want use CSS3 property to make a complicated background image which with corner shadow and so on.Including background image,left border image,right border image.So,for the <div class="outer"></div>I write the CSS below: .outer { background:url("title_main.png"); background-repeat:repeat-x; background-clip: content; background-origin:content; -moz-background-clip: content; -moz-background-origin: content; -webkit-background-clip: content; -webkit-background-origin:content; -webkit-border-image:url("title_border.png") 0 15 0 15 stretch; -moz-border-image: url("title_border.png") 0 15 0 15 stretch; border-image:url("fancy_title.png") 0 15 0 15 stretch; border-width:0 15px ; width:80px; height:32px; } In chrome browser it work well like: But the firefox doesn't like this: Why would this happened?How can I fix this?Make the firefox effect like the chrome?

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• Apply a specific class to the first item in a series with PHP

  - by Thomas

  I have a php script that echoes a series of uploaded images and I need to apply a class to the first image echoed in the series. Is this possible? For example, if I want to display 10 images and apply a class to only the first image, how would I go about it? Here is the code, I am working with: <div id="gallery"> <?php query_posts('cat=7'); while(have_posts()) { the_post(); $image_tag = wp_get_post_image('return_html=true'); $resized_img = getphpthumburl($image_tag,'h=387&w=587&zc=1'); $url = get_permalink(); $Price ='Price'; $Location = 'Location'; $title = $post->post_title; echo "<a href='$url'><img src='$resized_img' width='587' height='387' "; echo "rel=\"<div class='gallery_title'><h2>"; echo $title; echo "</h2></div>"; echo "<div class='pre_box'>Rate:</div><div class='entry'>\$"; echo get_post_meta($post->ID, $Price, true); echo "</div><div class='pre_box'>Location:</div><div class='entry'>"; echo get_post_meta($post->ID, $Location, true); echo "</div>\""; echo "'/></a>"; echo ""; } ?> On line 13, the code looks like this: echo "<a href='$url'><img src='$resized_img' width='587' height='387' "; For the first item only, I need it to look like this: echo "<a href='$url' class='show'><img src='$resized_img' width='587' height='387' ";

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• facebook open graph meta property og:type of 'website'. The property 'object-name' requires an object of og:type 'object-name'

  - by chinmayahd

  in cake php 1.3 in view ctp i have follow code: $url = 'http://example.com/exmp/explus/books/view/'.$book['Book']['id']; echo $this->Html->meta(array('property' => 'fb:app_id', 'content' => '*******'),'',array('inline'=>false)); echo $this->Html->meta(array('property' => 'og:type', 'content' => 'book'),'',array('inline'=>false)); echo $this->Html->meta(array('property' => 'og:url', 'content' => $url ),'',array('inline'=>false)); echo $this->Html->meta(array('property' => 'og:title', 'content' => $book['Book']['title']),'',array('inline'=>false)); echo $this->Html->meta(array('property' => 'og:description', 'content' => $book['Book']['title']),'',array('inline'=>false)); $imgurl = '../image/'.$book['Book']['id']; echo $this->Html->meta(array('property' => 'og:image', 'content' => $imgurl ),'',array('inline'=>false)); ?> and it gives the following error when i am posting it' { "error": { "message": "(#3502) Object at URL http://example.com/exmp/explus/books/view/234' has og:type of 'website'. The property 'book' requires an object of og:type 'book'. ", "type": "OAuthException", "code": 3502 } } is any one know how to solve it?

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• My SQL query is only returning I need the parent aswell

  - by sico87

  My sql query is only returning the children of the parent I need it to return the parent as well, public function getNav($cat,$subcat){ //gets all sub categories for a specific category if(!$this->checkValue($cat)) return false; //checks data $query = false; if($cat=='NULL'){ $sql = "SELECT itemID, title, parent, url, description, image FROM p_cat WHERE deleted = 0 AND parent is NULL ORDER BY position;"; $query = $this->db->query($sql) or die($this->db->error); }else{ //die($cat); $sql = "SET @parent = (SELECT c.itemID FROM p_cat c WHERE url = '".$this->sql($cat)."' AND deleted = 0); SELECT c1.itemID, c1.title, c1.parent, c1.url, c1.description, c1.image, (SELECT c2.url FROM p_cat c2 WHERE c2.itemID = c1.parent LIMIT 1) as parentUrl FROM p_cat c1 WHERE c1.deleted = 0 AND c1.parent = @parent ORDER BY c1.position;"; $query = $this->db->multi_query($sql) or die($this->db->error); $this->db->store_result(); $this->db->next_result(); $query = $this->db->store_result(); } return $query; }

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• Trying to use jquery ui in google chrome extension in the content level

  - by user135697

  The problem is that the scope of the content script is on the web page that your plugin is suppose to be used at. So the css background:url(images/ui-bg_inset-hard_100_fcfdfd_1x100.png) becomes url('http://webpageforplugin/images/ui-bg_inset-hard_100_fcfdfd_1x100.png') in order for this to work as far as i understood i need to have it to point to: url('chrome-extension://extensionId/images/ui-bg_inset-hard_100_fcfdfd_1x100.png') So i tried to haxorz the document.styleSheets var ss = document.styleSheets; for (var i=0; i<ss.length; i++) { var found=-1, x,i; var rules = ss[i].cssRules || ss[i].rules; for (var j=0; j<rules.length; j++) { if ('.ui-helper-hidden'==rules[j].selectorText){ found=i; break; } } if (found>-1){ for (var j=0; j<rules.length; j++) { if (x=rules[j].style.background){ if ((i=x.indexOf('url'))!=-1) rules[j].style.background = x.replace('http://page/images/','chrome-extension://extensionId/images/'); } } break; } }; I feel that i'm missing the obvious. That there must be an easier way. Even if i manage to change this how will i get the extension id to build the string. Btw this doesn't work, the icons are not properly fetched. (I hardcoded the extension id) Any ideas?

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• Problem in getting Http Response in chrome

  - by Bhaskasr

  Am trying to get http response from php web service in javascript, but getting null in firefox and chrome. plz tell me where am doing mistake here is my code, function fetch_details() { if (window.XMLHttpRequest) { xhttp=new XMLHttpRequest() alert("first"); } else { xhttp=new ActiveXObject("Microsoft.XMLHTTP") alert("sec"); } xhttp.open("GET","url.com",false); xhttp.send(""); xmlDoc=xhttp.responseXML; alert(xmlDoc.getElementsByTagName("Inbox")[0].childNodes[0].nodeValue); } I have tried with ajax also but am not getting http response here is my code, please guide me var xmlhttp = null; var url = "url.com"; if (window.XMLHttpRequest) { xmlhttp = new XMLHttpRequest(); alert(xmlhttp); //make sure that Browser supports overrideMimeType if ( typeof xmlhttp.overrideMimeType != 'undefined') { xmlhttp.overrideMimeType('text/xml'); } } else if (window.ActiveXObject) { xmlhttp = new ActiveXObject("Microsoft.XMLHTTP"); } else { alert('Perhaps your browser does not support xmlhttprequests?'); } xmlhttp.open('GET', url, true); xmlhttp.onreadystatechange = function() { if (xmlhttp.readyState == 4) { alert(xmlhttp.responseXML); } }; } // Make the actual request xmlhttp.send(null); I am getting xmlhttp.readyState = 4 xmlhttp.status = 0 xmlhttp.responseText = "" plz tell me where am doing mistake

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• Spring security - same page to deliver different content based on user role

  - by Ramesh

  Hello, i tried to search for any previous post related to my issue but couldnt find any. I have a scenario where in page handles 3 different scenarios and one of them not working. This page returns different content depending on if the user is authenticated or anonymous. localhost:8080/myApp/muUrl?test=authenticatedContent - used for Scenario 1 & 2 localhost:8080/myApp/muUrl?test=anonymousContent - used for Scenario 3 Scenario: 1) Authenticated user accesing the page url - the user gets displayed correct information. Works fine 2) Anonymous user accesing page URL with parameters that requires authentication - If anonymous, there is second level of check on the content they are accessing. for example, based on the GET parameters, there is custom logic to determine if the user has to be authenticated. In which case the page gets redirected to login page (WORKS fine). 3) Anonymous user accessing page URL with parameters that doesnt need authentication - in this case i get the SAvedRequest and redirect to the URL which is taking me to an infinite loop. Am i missing something very obvious or is there a way in AuthenticationProcessFilterEntryPoint to say "DON'T redirect to LOGIN page but process it" ? thanks.

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• Adding a variable href attribute to a hyperlink using XSLT

  - by Pete

  I need to create links using dynamic values for both the URL and the anchor text. I have column called URL, which contains URL's, i.e., http://stackoverflow.com, and I have a column called Title, which contains the text for the anchor, i.e., This Great Site. I figure maybe all I need to do is nest this tags, along with a little HTML to get my desired result: <a href="> <xsl:value-of select="@URL">"> <xsl:value-of select="@Title"/> </xsl:value-of> </a> In my head, this would render: <a href=" http://stackoverflow.com"> This Great Site </a> I know there's more to it, but I haven't been able to clearly understand what more I need. I think this issue has been addressed before, but not in a way I could understand it. I'd be more than happy to improve the question's title to help noobs like myself find this item, and hopefully an answer. Any help is greatly appreciated.

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• App-Engine Parse a UrlFetch UTF-8 encoded stream

  - by Davidrd91

  I am trying to parse an XML from a URL using the xml.sax parser. I know there are other libraries to use but coming from Java this is the one I am most familiar with and seems the least complicated to me. The code I'm using to parse is as follows: parser = xml.sax.make_parser() handler = MangaHandler() parser.setContentHandler(handler) url = urlfetch.Fetch('http://www.mangapanda.com/alphabetical', allow_truncated = False, follow_redirects = False, deadline = False) xml.sax.parseString(url.content, handler) This returns a SaxException (invalid token) once the parser reaches the first & sign: SAXParseException: <unknown>:582:34: not well-formed (invalid token) Because urlfetch returns a string and not a stream I cannot use the parse() (which only works with streams) and am left to use parseString() instead. To see if parsing as a stream would fix this I tried: parser.parse(io.StringIO(url.content).encode('utf-8')) but this returns: TypeError: initial_value must be unicode or None, not str I have also tried to use the urllib2 libraries which do return a stream instead of urlfetch but the file is too large and is automatically truncated, leaving me with missing data. Any Sort of work-around for this would be greatly appreciated as I've spent days getting around one obstacle just to be stopped by another.

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• Twitter bootstrap modal loads wrong remote data

  - by Victor S

  I'm using Twitter Bootstrap modal featurs and loading data from remote locations. I'm providing the remote url for a set of thumbnails with the hope that once the thumbnail is clicked, the appropriate data (a large version of the image) is displayed. I'm using the html declarative style to define the remote urls and all the features of the modal. What I find is that Twitter bootstrap modal loads first remote url then does not display subsequent remote data, (although a request to the proper url is made in Chrome) but displays first loaded data always. How do I get it to show the proper data? View: #gallery-navigation %ul - @profile.background_images.each do |image| %li = link_to image_tag(image.background_image.url(:thumb)), remote_image_path(image.id), :role => "button", :data => {:toggle => "modal", :target => "#image-modal", :remote => remote_image_path(image.id)}, :id => "image-modal" / Modal #image-modal.modal.hide.fade(role="dialog" aria-hidden="true" data-backdrop="true") .modal-body Controller: def remote_image @image = current_user.profile.background_images.find(params[:image_id]) respond_to do |format| format.html { render :partial => "remote_image", :locals => { :image => @image } } end end

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• Webview shouldoverrideurlloading doesn't work

  - by Zak

  I have this code in my app: public class Home extends Activity{ @Override public void onCreate(Bundle savedInstanceState){ super.onCreate(savedInstanceState); setContentView(R.layout.home); final ProgressDialog progressBar; if(isOnline()){ WebView webView = (WebView) findViewById(R.id.home_web); webView.setBackgroundColor(Color.parseColor(getString(R.color.colore_bg))); webView.getSettings().setJavaScriptEnabled(true); webView.getSettings().setBuiltInZoomControls(true); webView.getSettings().setPluginsEnabled(true); webView.setWebViewClient(new MyWebViewClient()); progressBar = ProgressDialog.show(this,getString(R.string.caricamento),getString(R.string.attendere)); webView.setWebViewClient(new WebViewClient(){ public void onPageFinished(WebView view, String url) { if (progressBar.isShowing()) { progressBar.dismiss(); } } }); webView.loadUrl("http://www.mysite.com/android.php"); }else{ Toast.makeText(this,getString(R.string.no_connessione),Toast.LENGTH_LONG).show(); } } private class MyWebViewClient extends WebViewClient { @Override public boolean shouldOverrideUrlLoading(WebView view, String url) { System.out.println("here"); if (Uri.parse(url).getHost().equals("mysite.com")) { // This is my web site, so do not override; let my WebView load the page return false; } // Otherwise, the link is not for a page on my site, so launch another Activity that handles URLs Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse(url)); startActivity(intent); return true; } } public boolean isOnline(){ ConnectivityManager cm=(ConnectivityManager)getSystemService(Context.CONNECTIVITY_SERVICE); NetworkInfo ni = cm.getActiveNetworkInfo(); if(ni==null){ return false; } return ni.isConnected(); } } The shouldOverrideUrlLoading doesn't work, neither print the system.out, it seems to be never called. How can I repair this? I need to open all the link (except the main page www.mysite.com/iphone.php) in the default browser

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• Java Trying to get a line of source from a website

  - by dsta

  I'm trying to get one line of source from a website and then I'm returning that line back to main. I keep on getting an error at the line where I define InputStream in. Why am I getting an error at this line? public class MP3LinkRetriever { private static String line; public static void main(String[] args) { String link = "www.google.com"; String line = ""; while (link != "") { link = JOptionPane.showInputDialog("Please enter the link"); try { line = Connect(link); } catch(Exception e) { } JOptionPane.showMessageDialog(null, "MP3 Link: " + parseLine(line)); String text = line; Toolkit.getDefaultToolkit( ).getSystemClipboard() .setContents(new StringSelection(text), new ClipboardOwner() { public void lostOwnership(Clipboard c, Transferable t) { } }); JOptionPane.showMessageDialog(null, "Link copied to your clipboard"); } } public static String Connect(String link) throws Exception { String strLine = null; InputStream in = null; try { URL url = new URL(link); HttpURLConnection uc = (HttpURLConnection) url.openConnection(); in = new BufferedInputStream(uc.getInputStream()); Reader re = new InputStreamReader(in); BufferedReader r = new BufferedReader(re); int index = -1; while ((strLine = r.readLine()) != null && index == -1) { index = strLine.indexOf("<source src"); } } finally { try { in.close(); } catch (Exception e) { } } return strLine; } public static String parseLine(String line) { line = line.replace("<source", ""); line = line.replace(" src=", ""); line = line.replace("\"", ""); line = line.replace("type=", ""); line = line.replace("audio/mpeg", ""); line = line.replace(">", ""); return line; } }

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• Problem with Xpath PHP

  - by user294597

  Im tring to access some links through Google using xpath. The below does works fine and all the links are shown. $query = $xpath->evaluate("/html/body//a"); for ($x=0 ; $x < $query -> length; $x++) { $href=$query->item($x); $url=$href->getAttribute('href'); echo $url."<br>"; } But when i try the below xpath nothing is shown..Im sure that the xpath is correct coz its evaluated and the result is shown in xpather.. /html/body[@id='gsr']/div[@id='cnt']/div[@id='res']/div[1]/ol/li/div//cite for ($x=0 ; $x < $query -> length; $x++) { $href=$query->item($x); $url=$href->getAttribute('cite'); echo $url."<br>"; } can some one please tell me what i am doin wrong? any help will be much appreciated

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• Why are Facebook Likes Insisting on using Wrong Product Image...?

  - by Joan Kent

  Firstly, I'm not a web developer so please be patient. I have read the other posts but I think i have everything covered. My website http://www.joaniesgifts.co.uk includes the like button on the product pages. However, I've found that certain product pages are using the incorrect image when a user likes the page. For example - http://www.joaniesgifts.co.uk/terramundi-money-pots/terramundi-money-pot-holiday-fund I think this may have been down to an original incorrect setup which is now corrected. However, the problem remains... The only thing I have to go on :- if i use the facebook url linter (developers.facebook.com/tools/debug) on the above product page, I receive the following error :- Object at URL 'http://www.joaniesgifts.co.uk/terramundi-money-pot-holiday-fund' of type '213689662010141:product' is invalid because the domain 'www.joaniesgifts.co.uk' is not allowed for the application id '213689662010141' which owns the specified object type. If you are the owner of this application, you can verify your configured 'Site Domain' at developers.facebook.com/apps/213689662010141. (I have verified my site's domain) Everything else appears fine except it is also showing the wrong image!! However, under Raw Open Graph Document Information it has the correct link! If I then click graph api - graph.facebook.com/10150450766583352 it again shows the wrong image was linked! I've no idea what else to do - can you help me? Kind Regards, Joan PS Graph API shows the incorrect image after a scrape only minutes ago { "url": "http://www.joaniesgifts.co.uk/terramundi-money-pot-holiday-fund", "type": "website", "title": "Terramundi Money Pot - Holiday Fund", "image": [ { "url": "http://www.joaniesgifts.co.uk/index.php?route=product\u00252Fproduct\u00252Fcaptcha" } ], "updated_time": "2011-11-11T18:54:38+0000", "id": "10150450766583352" }

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• need help with mvc & routes

  - by geoff

  I'm very new to MVC and I'm trying to get a new site set up using it. For SEO reasons we need to make the url of a page something like "Recruiter/4359/John_Smith" or basically {controller}/{id}/{name}. I have that working when I create the url in the code behind like so... //r is a recruiter object that is part of the results for the view r.Summary = searchResult.Summary + "... &lt;a href=\"/Recruiter/" + r.Id + "/" + r.FirstName + "_" + r.LastName + "\"&gt;Read More&lt;/a&gt;" But when I am using the collection of results from a search in my view and iterating through them I am trying to create another link to the same page doing something like <%=Html.ActionLink<RecruiterController>(x => x.Detail((int)r.Id), r.RecruiterName)%> but that doesn't work. When I use that code in the view it gives me a url in the form of /Recruiter/Detail/4359 I was told by a coworker that I should use the Html.ActionLink to create the link in both the view and the controller so that if the route changes in the future it will automatically work. Unfortunately he wasn't sure how to do that in this case. So, my problems are... How can I make the Html.ActionLink work in the view to create a url like I need (like r.Summary above)? How do I use the Html.ActionLink in a controller instead of hardcoding the link like I have above?

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• JQuery SelectList Option Changed doesn't refresh

  - by Jean-Philippe

  Hi. I have this select list: <select url="/Admin/SubCategories" name="TopParentId" id="ParentList"> <option value="">Please select a parent category</option> <option value="1" selected="selected">New Store</option> <option value="2">Extensions</option> <option value="3">Remodel</option> <option value="4">Bespoke Signage</option> <option value="5">Tactical Signage</option> <option value="6">Size Chart</option> <option value="7">Contact Info</option> </select> As you can see the option 1 is marked as selected. When I change the selection, I use this code to do an ajax call to get some values to populate a new select list: $("#ParentList").unbind("change"); $("#ParentList").change(function() { var itemId = $(this).val(); var url = $(this).attr("url"); var options; $.getJSON(url, itemId, function(data) { var defaultoption = '<option value="0">Please select a sub-category</option>'; options += defaultoption; $.each(data, function(index, optionData) { var option = '<option value="' + optionData.valueOf + '">' + optionData.Text + '</option>'; options += option; }); $("#SubParentList").html(options); }); }); My problem is that whenever I change the selection, the itemId is always the id of option 1, because it is marked as selected. It doesn't pick up the value of the option it is being changed too. Can someone please enlighten me of their knowledge. Regards, Jean-Philippe

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• Any one point me how to customize facebook share

  - by Venkat

  I am trying to share my own custom url, image, title and description using Facebook and twitter. I am having lot of images and videos in my website. So i want to make my content viral on social websites. I am trying to keep share options for both facebook and twitter for everything individually. If some one share one image i want that image in the sharing thumbnail and url will be the page url with my own title, description. Based on the url i will point the user to that pic in my website. I tried in the below way. Facebook share: <a href="javascript:;" onclick="window.open('http://www.facebook.com/share.php?u=your_page_url','facebook share','resizable=yes,width=700,height=500,scrollbars=yes,status=yes')"><img alt="facebook" src="yourimage.jpg" /></a> Twitter share: <a href="javascript:;" onclick="window.open('https://twitter.com/share','twitter share','resizable=yes,width=700,height=500,scrollbars=yes,status=yes')"><img alt="twitter" src="yourimage.jpg" /></a>

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• Parsing HTML: Call to a member function > children() on a non-object

  - by sm56d

  Hello all, I was just helped with this question but I can't get it to move to the next block of HTML. $html = file_get_html('http://music.banadir24.com/singer/aasha_abdoo/247.html'); $urls = $html->find('table[width=100%] table tr'); foreach($urls as $url){ $song_name = $url->children(2)->plaintext; $url = $url->children(6)->children(0)->href; } It returns the list of the names of the first album (Deesco) but it does not continue to the next album (The Best Of Aasha)? It just gives me this error: Notice: Trying to get property of non-object in C:\wamp\www\test3.php on line 26 Fatal error: Call to a member function children() on a non-object in C:\wamp\www\test3.php on line 28 Why is this and how can I get it to continue to the next table element? I appreciate any help on this! Please note: This is legal as the songs are not bound by copyright and they are available to download freely, its just I need to download a lot of them and I can't sit there clicking a button all day. Having said that, its taken me an hour to get this far.

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• How to display data in spinner from json

  - by user1605913

  I am retrieving values from a json url and then storing it in a string variable. Now I want to display that value in a spinner. I have created an array list in my strings.xml file. The xml file contains following code: <string name="credit_card_title">Card Type</string> <string-array name="credit_card"> <item >Select</item> <item >Visa</item> <item >MC</item> <item >Amex</item> <item >Discover</item> my spinner code is: <Spinner android:id="@+id/crdtcrd_crdtype" android:layout_width="match_parent" android:layout_height="wrap_content" android:entries="@array/credit_card" android:prompt="@string/credit_card_title" /> After retriving the value from the json url I am storing it in variable name String cardtype Now how can I display the value of cardtype in the Spinner crtdcrd_crdtype.... the json url is: http://mygogolfteetime.com/iphone/login/[email protected]/123456 From this URL I have to retrieve the value of cardtype and after retrieving the value i have to display it in the spinner.. There are different values for cardype like visa, mc, amex and discover All these values are in my strings.xml file and after retrieving the value I have to display it in Spinner.. Help needed still not able to find the solution.. Thanks in advance...

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• overwrite parameters passed by querystring

  - by opensas

  I have the following problem I have a web framework built with classic asp that saves the page state in hidden textboxes, and then issues a submit to itself. Before submitting, we have a javascript functions that saves the action in a hidden "action" input, and then performs the submit. The page loads the state from those hidden texts, reads the action issued, reads extra parameters, like the id of the record to edit, and then builds the page accordingly. I'd like to make a url link to automatically start the page with "edit" action on a "x" id. So I was thinking about building the following url, for example http://myapp/user?action=edit&id=23 the problem is that when the page auto-submits, que url string keeps the parameters. I'd like to achieve the following: when the user clicks on http://myapp/user?action=edit&id=23 my page should receive the posted values action=edit and id=23 but the url should be just http://myapp/user and both parameters should be kept in the hidden texts... (I wonder if I make myself clear...) thanks a lot saludos sas ps: I have a couple of ideas about how to solve it, but I'll post them as answers...

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