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  • Berkeley DB tuple with unknown datatype

    - by Ronnie
    I'm working with a Berkeley database (in Java). I need to read a tuple where the sequence is a string, either an int or long, then another string. How can I determine if the tuple holds an int or a long? Depending on what the tuple holds, I'll do one of the following: String s1 = input.readString(); int num1 = input.readInt(); String s2= input.readString(); or String s1 = input.readString(); long num1 = input.readLong(); String s2= input.readString(); The int is 4 bytes and the long is 8 bytes. If the tuple holds an int and I read it in as a long, I get an invalid value as it converts the 4 byte int + 4 bytes of the following string into a long.

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  • How to ignore the validation of Unknown tags ?

    - by infant programmer
    One more challenge to the XSD capability,I have been sending XML files by my clients, which will be having 0 or more undefined or [call] unexpected tags (May appear in hierarchy). Well they are redundant tags for me .. so I have got to ignore their presence, but along with them there are some set of tags which are required to be validated. This is a sample XML: <root> <undefined_1>one</undefined_1> <undefined_2>two</undefined_2> <node>to_be_validated</node> <undefined_3>two</undefined_3> <undefined_4>two</undefined_4> </root> And the XSD I tried with: <xs:element name="root" type="root"></xs:element> <xs:complexType name="root"> <xs:sequence> <xs:any maxOccurs="2" minOccurs="0"/> <xs:element name="node" type="xs:string"/> <xs:any maxOccurs="2" minOccurs="0"/> </xs:sequence> </xs:complexType XSD doesn't allow this, due to certain reasons. The above mentioned example is just a sample. The practical XML comes with the complex hierarchy of XML tags .. Kindly let me know if you can get a hack of it. By the way, The alternative solution is to insert XSL-transformation, before validation process. Well, I am avoiding it because I need to change the .Net code which triggers validation process, which is supported at the least by my company.

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  • Unknown reason for code executing the way it does in python

    - by Jasper
    Hi I am a beginner programmer, using python on Mac. I created a function as a part of a game which receives the player's input for the main character's name. The code is: import time def newGameStep2(): print ' ****************************************** ' print '\nStep2\t\t\t\tCharacter Name' print '\nChoose a name for your character. This cannot\n be changed during the game. Note that there\n are limitations upon the name.' print '\nLimitations:\n\tYou cannot use:\n\tCommander\n\tLieutenant\n\tMajor\n\t\tas these are reserved.\n All unusual capitalisations will be removed.\n There is a two-word-limit on names.' newStep2Choice = raw_input('>>>') newStep2Choice = newStep2Choice.lower() if 'commander' in newStep2Choice or 'lieutenant' in newStep2Choice or 'major' in newStep2Choice: print 'You cannot use the terms \'commander\', \'lieutenant\' or \'major\' in the name. They are reserved.\n' print time.sleep(2) newGameStep2() else: newStep2Choice = newStep2Choice.split(' ') newStep2Choice = [newStep2Choice[0].capitalize(), newStep2Choice[1].capitalize()] newStep2Choice = ' ' .join(newStep2Choice) return newStep2Choice myVar = newGameStep2() print myVar When I was testing, I inputted 'major a', and when it asked me to input another name, i inputted 'a b'. However, when it returned the output of the function, it returns 'major a'. I went through this with a debugger, yet I still can't seem to find where the problem occurred. Thanks for any help, Jasper

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  • Tomcat Failed to start

    - by user71538
    I have installed Tomcat on windows XP through the Tomcat installer. I have installed JDK 1.6. But when I start Tomacat from services.msi on XP, I get the following error: java.lang.ClassNotFoundException: org.apache.catalina.core.AprLifecycleListener at java.net.URLClassLoader$1.run(Unknown Source) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(Unknown Source) at sun.misc.Launcher$ExtClassLoader.findClass(Unknown Source) at java.lang.ClassLoader.loadClass(Unknown Source) at java.lang.ClassLoader.loadClass(Unknown Source) at org.apache.commons.digester.ObjectCreateRule.begin(ObjectCreateRule.java:204) at org.apache.commons.digester.Rule.begin(Rule.java:152) at org.apache.commons.digester.Digester.startElement(Digester.java:1286) at com.sun.org.apache.xerces.internal.parsers.AbstractSAXParser.startElement(Unknown Source) at com.sun.org.apache.xerces.internal.parsers.AbstractXMLDocumentParser.emptyElement(Unknown Source) at com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl.scanStartElement(Unknown Source) at com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl$FragmentContentDriver.next(Unknown Source) at com.sun.org.apache.xerces.internal.impl.XMLDocumentScannerImpl.next(Unknown Source)

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  • Images with unknown content: Dangerous for a browser?

    - by chris_l
    Let's say I allow users to link to any images they like. The link would be checked for syntactical correctness, escaping etc., and then inserted in an <img src="..."/> tag. Are there any known security vulnerabilities, e.g. by someone linking to "evil.example.com/evil.jpg", and evil.jpg contains some code that will be executed due to a browser bug or something like that? (Let's ignore CSRF attacks - it must suffice that I will only allow URLs with typical image file suffixes.)

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  • WordPress SEO For Achieving Top Google Rankings

    If you have hung around the internet and gotten a little whiff of the SEO updates, you would have already gathered that if you have your website optimized, you stand the chance of getting better hits and more profits and ranking on the search engines. However, it might seem like something unattainable since you might not have any idea of how you can get the necessary optimization for your blog. At first, most bloggers are often undecided on the kind of software that would be ideal for their blogging enterprise, but with time, they come to settle...

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  • Create variables for unknown amount of arguments?

    - by user347600
    Working on an rsync script and the portion below is in a for loop. What I want to achieve is assign a variable to every arguement after 3. Just confused if I need to create another loop for that or not: #1: name name=$1 #2: ip ip=$2 #3: user user=$3 #4+: folder exlusion #any lines higher than 3 will be created as exlcude folders ex[ARG_NUMBER]=

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  • Excel: Automating the Selection of an Unknown Number of Cells

    - by user1905080
    I’m trying to automate the formatting of an excel file by a macro and am seeking a solution. I have two columns titled Last Name and First Name which I would like to concatenate into a separate column titled Last Name, First Name. This is simple enough when done by hand: create one cell which does this, then drag that cell to include all cells within the range. The problem appears when trying to automate this. Because I can’t know the number of names that need to be concatenated ahead of time, I can’t automate the selection of cells by dragging. Can you help me automate this? I’ve tried a process of copying the initial concatenated cell, highlighting the column, and then pasting. I’ve also tried to use a formula which returned the concatenation only if there is text in the “Last Name” and “First Name” columns. However, in both cases, I end up with some 100,000 rows, putting a serious cramp on my ability to manipulate the worksheet. The best solution I can think of is to create concatenations within a fixed range of cells. Although this would create useless cells, at least there wouldn’t be 99,900 of them.

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  • Google Sites API - File Cabinets: Spaces and extension separator (.) are removed from file names

    - by user1299447
    We have a series of internal reports that we update regularly from our internal databases. We built an application in C# that uploads these reports to a Google Site. Everything works fine, except that the name of the file shown to the final user in the File Cabinet does not include the original spaces nor the extension separator (.) For example, Stock per warehouse.pdf is shown as : Stockperwarehousepdf Below is a simplified version of the code. private AtomEntry UploadAttachment(string filename, AtomEntry parent, string title, string description) { SiteEntry entry = new SiteEntry(); AtomCategory category = new AtomCategory(SitesService.ATTACHMENT_TERM, SitesService.KIND_SCHEME); category.Label = "attachment"; entry.Categories.Add(category); AtomLink parentLink = new AtomLink(AtomLink.ATOM_TYPE, SitesService.PARENT_REL); parentLink.HRef = parent.SelfUri; entry.Links.Add(parentLink); entry.MediaSource = new MediaFileSource(filename, MediaFileSource.GetContentTypeForFileName(filename)); entry.Content.Type = MediaFileSource.GetContentTypeForFileName(filename); entry.Title.Text= title; entry.Summary.Text = description; AtomEntry newEntry = null; newEntry = service.Insert(new Uri(makeFeedUri("content")), entry); } The key line is where the MediaFileSource object is created. Any idea of what we are missing? I've tried all sort of changes :(

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  • Google and the SEO Hosting Network

    When you are choosing any type of SEO Company, what you have to remember is that it is very important that you get your hands on the very best SEO hosting network as such a type of networking company can help you to ensure that your website can do much better than any other. Another great advantage that is associated with choosing such type of SEO hosting network is that you are doing whatever is possible to ensure that your website can do very well in a search engine.

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  • simple JQuery example is causing me troubles for unknown reason

    - by cerr
    I'm relatively new to JQuery and would like to try something. I just followed a simple tutorial to start up with on http://docs.jquery.com/Tutorials:Getting_Started_with_jQuery So I specified my script in the : <script type="text/javascript"> $(document).ready(function() { $("a").click(function() { alert("Hello world!"); }); }); </script> and included a test link in the : <a href="">Link</a> however, when I refresh thet document my browser keeps saying TypeError: Property '$' of object [object Window] is not a function which I can understand for "normal" JavaScript but I believe this kind of function is new in JQuery. Can someone assist mer here, please? links:http://wittmerperformance.com/site/

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