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  • PHP/Javascript: Need help removing line break from code

    - by Josh K
    I am trying to get names from a .txt file. I am using file('filename.txt') but if i use a php for loop to try and trim the names, it comes out on multiple lines: This is the actual line that prints the javascript (NOTE: I am going to be putting these names into a select box, if you can fix the problem at hand the rest of the code should work so unless you a big problem with it you don't need to comment) <?php for($i=1; $i < 27; $i++){ echo "selbox.options[selbox.options.length] = new Option('".lines[$i]."','".$lines[$i]."');\n"; } ?> Heres how it comes out on the browser: selbox.options[selbox.options.length] = new Option('Djamal ABDOUN ','First1 Last1 '); selbox.options[selbox.options.length] = new Option('Chadli AMRI ','First2 Last2 '); I need those to be on one line so i dont get a unterminated string literal js error Any ideas on what i can do here? EDIT: Oh i should probably mention, the $lines var is initiated like this: $lines = file('filename.txt'); and inside that file i have formatted like this First1 Last1 First2 Last2 First3 Last3 etc. and i hit delete after each Last name until the next first name is touching, then hit enter to put it on a new line (Editor is notepad++)

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  • Error 100 When Attempting to post from app to Facebook wall?

    - by IMAPC
    I'm playing around with the Facebook API, and have gotten far enough to get the access token into my app, but when I go to actually send a post to my Facebook wall I get the error message, {"error":{"message":"(#100) You can't post this because it has a blocked link.","type":"OAuthException","code":100}}1 I'm not attempting to send any kind of link, just "Hello, World!" so this seems pretty weird to me :\ Here's my code so far: $content = urlencode("Hello, World!"); $accesstoken = urlencode($row['fbid']); $result = getPageWithPOST("https://graph.facebook.com/me/feed", "access_token=" . $accesstoken . "&message=" . $content); echo $result; where getPageWithPOST is, function getPageWithPOST($url, $posts) { $c = curl_init(); curl_setopt($c, CURLOPT_URL, $url); curl_setopt($c, CURLOPT_POST, true); curl_setopt($c, CURLOPT_POSTFIELDS, $posts); $content = curl_exec ($c); curl_close ($c); return $content; } thanks!

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  • php form submit and the resend infromation screen

    - by Para
    Hello, I want to ask a best practice question. Suppose I have a form in php with 3 fields say name, email and comment. I submit the form via POST. In PHP I try and insert the date into the database. Suppose the insertion fails. I should now show the user an error and display the form filled in with the data he previously inserted so he can correct his error. Showing the form in it's initial state won't do. So I display the form and the 3 fields are now filled in from PHP with echo or such. Now if I click refresh I get a message saying "Are you sure you want to resend information?". OK. Suppose after I insert the data I don't carry on but I redirect to the same page but with the necessary parameters in the query string. This makes the message go away but I have to carry 3 parameters in the query string. So my question is: How is it better to do this? I want to not carry around lots of parameters in the query string but also not get that error. How can this be done? Should I use cookies to store the form information.

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  • Zend Framework Form Element Validators - validate a field even if not required

    - by Jeremy Hicks
    Is there a way to get a validator to fire even if the form element isn't required? I have a form where I want to validate the contents of a texbox (make sure not empty) if the value of another form element, which is a couple of radio buttons, has a specific value selected. Right now I'm doing this by overriding the isValid() function of my form class and it works great. However, I'd like to move this to either its on validator or use the Callback validator. Here's what I have so far, but it never seems to get called unless I change the field to setRequired(true) which I don't want to do at all times, only if the value of the other form element is set to a specific value. // In my form class's init function $budget = new Zend_Form_Element_Radio('budget'); $budget->setLabel('Budget') ->setRequired(true) ->setMultiOptions($options); $budgetAmount = new Zend_Form_Element_Text('budget_amount'); $budgetAmount->setLabel('Budget Amount') ->setRequired(false) ->addFilter('StringTrim') ->addValidator(new App_Validate_BudgetAmount()); //Here is my custom validator (incomplete) but just testing to see if it even gets called. class App_Validate_BudgetAmount extends Zend_Validate_Abstract { const STRING_EMPTY = 'stringEmpty'; protected $_messageTemplates = array( self::STRING_EMPTY => 'please provide a budget amount' ); public function isValid($value) { echo 'validating...'; var_dump($value); return true; } }

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  • Formating a table date field from the Model in Codeigniter

    - by Landitus
    Hi, I', trying to re-format a date from a table in Codeigniter. The Controller is for a blog. I was succesfull when the date conversion happens in the View. I was hoping to convert the date in the Model to have things in order. Here's the date conversion as it happens in the View. This is inside the posts loop: <?php foreach($records as $row) : ?> <?php $fdate = "%d <abbr>%M</abbr> %Y"; $dateConv = mdate($fdate, mysql_to_unix($row->date)); ?> <div class="article section"> <span class="date"><?php echo $dateConv ;?></span> ... Keeps going ... This is the Model: class Novedades_model extends Model { function getAll() { $this->db->order_by('date','desc'); $query = $this->db->get('novedades'); if($query->num_rows() > 0) { foreach ($query->result() as $row) { $data[] = $row; } } return $data; } } How can I convert the date in the Model? Can I access the date key and refactor it?

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  • Need a better way to execute console commands from python and log the results

    - by Wim Coenen
    I have a python script which needs to execute several command line utilities. The stdout output is sometimes used for further processing. In all cases, I want to log the results and raise an exception if an error is detected. I use the following function to achieve this: def execute(cmd, logsink): logsink.log("executing: %s\n" % cmd) popen_obj = subprocess.Popen(\ cmd, shell=True, stdout=subprocess.PIPE, stderr=subprocess.PIPE) (stdout, stderr) = popen_obj.communicate() returncode = popen_obj.returncode if (returncode <> 0): logsink.log(" RETURN CODE: %s\n" % str(returncode)) if (len(stdout.strip()) > 0): logsink.log(" STDOUT:\n%s\n" % stdout) if (len(stderr.strip()) > 0): logsink.log(" STDERR:\n%s\n" % stderr) if (returncode <> 0): raise Exception, "execute failed with error output:\n%s" % stderr return stdout "logsink" can be any python object with a log method. I typically use this to forward the logging data to a specific file, or echo it to the console, or both, or something else... This works pretty good, except for three problems where I need more fine-grained control than the communicate() method provides: stdout and stderr output can be interleaved on the console, but the above function logs them separately. This can complicate the interpretation of the log. How do I log stdout and stderr lines interleaved, in the same order as they were output? The above function will only log the command output once the command has completed. This complicates diagnosis of issues when commands get stuck in an infinite loop or take a very long time for some other reason. How do I get the log in real-time, while the command is still executing? If the logs are large, it can get hard to interpret which command generated which output. Is there a way to prefix each line with something (e.g. the first word of the cmd string followed by :).

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  • hy i dont get the check value in check box?

    - by udaya
    Hi I have a check box when check that check box the id corresponding to the check box is placed on a text box ... but when there is only single value in the database i cant get the check value why? here is my code <? if(isset($AcceptFriend)) {?> <form action="<?=site_url()?>friends/Accept_Friend" name="orderform" id="orderform" method="post" style="background:#CCCC99"> <input type="text" name="chId" id="chId" > <table border="0" height="50%" id="chkbox" width="50%" > <tr> <? foreach($AcceptFriend as $row) {?> <tr> <td>Name</td><td><?=$row['dFrindName'].'</br>';?></td> <td> <input type="checkbox" name="checkId" id="checkId" value="<? echo $row['dMemberId']; ?>" onClick="get_check_value()" ></td> </tr> <? }}?> </tr> <tr> <td width="10px"><input type="submit" name="submit" id="submit" class="buttn" value="AcceptFriend"></td></tr> </table> </form> This is the script i am using function get_check_value() { var c_value = ""; for (var i=0; i < document.orderform.checkId.length; i++) { if (document.orderform.checkId[i].checked) { c_value = c_value + document.orderform.checkId[i].value + "\n"; } } alert(c_value); document.getElementById('chId').value= c_value; }

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  • How to test jQuery Ajax with php?

    - by vladv
    I tried to just send some information to a php file using Jquery Ajax. I wanted to send some info to the php file every time a click is made. <script> $(document).ready(function() { $('#checkbox').click(function() { $.ajax({type : "POST", url : "test.php", data : "ffs=somedata&ffs2=somedata2", succes : function() { alert("something"); } }); }); }); </script> <body> <input type = "checkbox" name = "checkbox" id = "checkbox"> </body> The php file looks like this: <?php echo $_POST['ffs']; ?> Now, I see the POST going, (using firebug). I get no errors, but nothing happens in the php file. Also success is never reached, so no alert is triggered. What should I do in the php file so that I can trigger success and also see the sent info?

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  • Error with MySQL Query

    - by Ken
    Okay, I must be an idiot, because this is my 3rd question for today. Here's my code: date_default_timezone_set("America/Los_Angeles"); include("mainmenu.php"); $con = mysql_connect("localhost", "root", "********"); if(!$con){ die(mysql_error()); } $usrname = $_POST['usrname']; $fname = $_POST['fname']; $lname = $_POST['lname']; $password = $_POST['password']; $email = $_POST['email']; mysql_select_db("`users`, $con) or die(mysql_error()"); $query = ("INSERT INTO `users`.`data` (`id`, `usrname`, `fname`, `lname`, `email`, `password`) VALUES (NULL, '$usrname', '$fname', '$lname', '$email', 'password'))"); mysql_query('$query') or die(mysql_error()); mysql_close($con); echo("Thank you for registering!"); I always get the error returned as: "You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '$query' at line 1. Help a newbie. I'm about to stab my monitor.

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  • MySQL SELECT Statement not working when executed from PHP

    - by Andrew K
    Hello all, I have the following piece of code, executing a pretty simple MySQL query: $netnestquery = 'SELECT (`nested`+1) AS `nest` FROM `ipspace6` WHERE `id`<='.$adaddr.' AND `subnet`<='.$postmask.' AND `type`="net" AND `addr` NOT IN(SELECT `id` FROM `ipspace6` WHERE `addr`<'.$adaddr.' AND `type`="broadcast") ORDER BY `id`,`subnet` DESC LIMIT 1'; $netnestresults = mysql_query($netnestquery); $netnestrow = mysql_fetch_array($netnestresults); $nestlvl = $netnestrow['nest']; echo '<br> NESTQ: '.$netnestquery; Now, when I execute this in PHP, I get no results; an empty query. However, when I copy and paste the query echoed by my code (for debug purposes) into the mysql command line, I get a valid result: mysql> SELECT (`nested` + 1) AS `nest` FROM `ipspace6` WHERE `id`<=50552019054038629283648959286463168512 AND `subnet`<=36 AND `type`='net' AND `addr` NOT IN (SELECT `id` FROM `ipspace6` WHERE `addr`<50552019054038629283648959286463168512 AND `type`='broadcast') ORDER BY `id`,`subnet` DESC LIMIT 1; +------+ | nest | +------+ | 1 | +------+ 1 row in set (0.00 sec) Can anybody tell me what I'm doing wrong? I can't put quotes around my variables, as then MySQL will try to evaluate the variable as a string, when it is, in fact, a very large decimal. I think I might just be making a stupid mistake somewhere, but I can't tell where.

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  • Help with an RSS Feed

    - by Pete Herbert Penito
    Hi Everyone! I've spent ages on this, all I'm trying to do is extract the "title" contents from an rss feed, everything else can be ignored. I've looked into simplepie, magpie and all that stuff, but I feel its kind of overkill for what I need to do. I realise there are google gadgets that are made that can do this, but I didn't want all the google logo stuff, and I wanted to personally make this. theres a whole bunch of unneeded tags thats coming in from the rss feed all I need is the title tag, it looks like this <title> My Title 3.0 </title> My server has PHP 5+ so I know I can use some of these simple xml functions which look promising. so far I've got <?php $blogfeed = file_get_contents("http://myblog.blogspot.com/feeds/posts/default?alt=rss"); echo $blogfeed; ?> And it gives me all the data, I was thinking of running through it with strpos and searching for <title> but is there any easier way to do this?? Thanks alot!

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  • PHP for loop isn't looping after APC installation

    - by BoRo
    So I installed APC and i all of the sudden my for loops only run once and increment the value then stops. I dont get what's going on, it worked fine before APC was installed. Any Suggestions? EDIT: I managed to narrow it down to the increment. for some reason if I have an array let's say string[], and have the for loop list through the values like with string[$i] It only does it for the first one, I can manually echo/print out the array elements to check if the array is the problem but all elements have the appropriate data/values. EDIT #2: Well the code looks something like (it scrapes a page for images and gets some data from it): $str = explode('<div class="images" align="center">',$str); for($i=1;$i<11;$i++){ $url3 = $str[$i]; $url3 = extstr3($url3,'class="filename">','</div>'); $urlname = extstr3($url3,'<a href="','</a>'); $name = extstr3($urlname,'target="_blank">','.jpg'); $url3 = extstr3($url3,'<a href="','" target="_blank">'); $name = str_replace ('_', ' ', $name); . . .

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  • DOM manipulation in PHP

    - by bluedaniel
    Hello everyone, Im trying to use the DOM in PHP to do a pretty specific job and Ive got no luck so far, the objective is to take a string of HTML from a Wordpress blog post (from the DB, this is a wordpress plugin). And then out of that HTML replace <div id="do_not_edit">old content</div>" with <div id="do_not_edit">new content</div>" in its place. Saving anything above and below that div in its structure. Then save the HTML back into the DB, should be simple really, I have read that a regex wouldnt be the right way to go here so Ive turned to the DOM instead. The problem is I just cant get it to work, cant extract the div or anything. Help me!! UPDATE The HTML coming out of the wordpress table looks like: Congratulations on finding us here on the world wide web, we are on a mission to create a website that will show off your culinary skills better than any other website does. <div id="do_not_edit">blah blah</div> We want this website to be fun and easy to use, we strive for simple elegance and incredible functionality.We aim to provide a 'complete package'. By this we want to create a website where people can meet, share ideas and help each other out. After several different (incorrect) workings all Ive got below is: $content = ($wpdb->get_var( "SELECT `post_content` FROM $wpdb->posts WHERE ID = {$article[post_id]}" )); $doc = new DOMDocument(); $doc->validateOnParse = true; $doc->loadHTMLFile($content); $element = $doc->getElementById('do_not_edit'); echo $element;

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  • I can't insert data into my database

    - by Ken
    I don't know why, but my data doesn't go into my database 'users' with the table 'data'. <html> <body> <?php date_default_timezone_set("America/Los_Angeles"); include("mainmenu.php"); $con = mysql_connect("localhost", "root", "g00dfor@boy"); if(!$con){ die(mysql_error()); } $usrname = $_POST['usrname']; $fname = $_POST['fname']; $lname = $_POST['lname']; $password = $_POST['password']; $email = $_POST['email']; mysql_select_db(`users`, $con) or die(mysql_error()); mysql_query(INSERT INTO `users`.`data` (`id`, `usrname`, `fname`, `lname`, `email`, `password`) VALUES (NULL, '$usrname', '$fname', '$lname', '$email', 'password')) or die(mysql_error()); mysql_close($con) echo("Thank you for registering!"); ?> </body> </html> All i get is a blank page.

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  • Perl: How do I capture Chinese input via SCIM with STDIN?

    - by KCArpe
    Hi, I use SCIM on Linux for Chinese and Japanese language input. Unfortunately, when I try to capture input using Perl's STDIN, the input is crazy. As roman characters are typed, SCIM tries to guess the correct final characters. ^H (backspace) codes are used to delete previously suggested chars on the command line. (As you type, SCIM tries to guess final Asian chars and displays them.) However, these backspace chars are shown literally as ^H and not interpreted correctly. Example one-liner: perl -e 'print "Chinese: "; my $s = <STDIN>; print $s' When I enable SCIM Chinese or Japanese language input, as I type, e.g., nihao = ??, here is the result: ?^H?^H?^H?^H?^H??^H^H??^H^H??^H^H??^H^H??^H^H??^H^H??^H^H??^H^H??^H^H?? At the very end of this string, you can see "??" (nihao/hello). At a normal bash prompt, if I type nihao (with Chinese enabled), the results is perfect. This has something to do with interpretation of backspace chars (or control chars) during Perl's STDIN. The same thing happens when using command 'read' in Bash. Witness: read -p 'Chinese: ' s && echo $s Cheers, Kevin

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  • Problem with .release behavior in file_operations

    - by Yannick
    Hello, I'm dealing with a problem in a kernel module that get data from userspace using a /proc entry. I set open/write/release entries for my own defined /proc entry, and manage well to use it to get data from userspace. I handle errors in open/write functions well, and they are visible to user as open/fopen or write/fwrite/fprintf errors. But some of the errors can only be checked at close (because it's the time all the data is available). In these cases I return something different than 0, which I supposed to be in some way the value 'close' or 'fclose' will return to user. But whatever the value I return my close behave like if all is fine. To be sure I replaced all the release() code by a simple 'return(-1);' and wrote a program that open/write/close the /proc entry, and prints the close return value (and the errno). It always return '0' whatever the value I give. Behavior is the same with 'fclose', or by using shell mechanism (echo "..." /proc/my/entry). Any clue about this strange behavior that is not the one claimed in many tutorials I found? BTW I'm using RHEL5 kernel (2.6.18, redhat modified), on a 64bit system. Thanks. Regards, Yannick

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  • php convert european datetime to mysql datetime

    - by Mathlight
    I'm really stuck with this problem. I've got an datetime string like this: 28-06-14 11:01:00 I'm trying to convert it to 2014-06-28 11:01:00 so that i can insert it into the database ( with field type datetime. I've tryed multiple things like this: $datumHolder = new DateTime($data['datum'], new DateTimeZone('Europe/Amsterdam')); $datum1 = $datumHolder -> format("Y-m-d H:i:s"); $datum2 = date( 'Y-m-d', strtotime(str_replace('-', '/', $data['datum']) ) ); $datum3 = DateTime::createFromFormat( 'Y-m-d-:Hi:s', $data['datum']); This is the output i get: datum1: 2028-06-14 11:01:00 datum2: 1970-01-01 And i get an error for datum3: echo "datum3: " . $datum3->format( 'Y-m-d H:i:s'); . '<br />'; Call to a member function format() on a non-object So my question is very clear... What am I doing wrong / how to get this working? Thanks in advantage guys! I know that this question is asked many, many times... But whatever i try, i can't get it working...

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  • Parse error: syntax error, unexpected T_STRING in...

    - by rabidmachine9
    I' making this class to catch twitter posts but I get the error : Parse error: syntax error, unexpected T_STRING in /Applications/XAMPP/xamppfiles/htdocs/classTest/Twitter.php on line 29 I cant find what's wrong...any ideas? class TwitterGrub{ function twitterCapture($user = 'myUsername',$password = 'myPass') { $ch = curl_init("https://twitter.com/statuses/user_timeline.xml"); curl_setopt($ch, CURLOPT_HEADER, 1); curl_setopt($ch,CURLOPT_TIMEOUT, 30); curl_setopt($ch,CURLOPT_USERPWD,$user . ":" . $password); curl_setopt($ch,CURLOPT_RETURNTRANSFER,1); curl_setopt ($ch, CURLOPT_SSL_VERIFYPEER, 0); curl_setopt ($ch, CURLOPT_SSL_VERIFYHOST, 0); $result=curl_exec ($ch); $data = strstr($result, '<?'); $xml = new SimpleXMLElement($data); return $xml; } function twitterDisplay($twitNum){ $xml = this->twitterCapture(); for($i= 0; $i<$twitNum; $i++){ echo "<div class='curvebox'>".$xml->status[$i]->text."</div>"; } } }

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  • database connection OK,result not appear

    - by klox
    hi..all.for now i'm already connected to database but the result not appear at Tuner range is"+res+"this is my code: var str=data[0]; var matches=str.match(/[EE|EJU].*D/i); $.ajax({ type:"post", url:"process1.php", data:"tversion="+matches+"&action=tunermatches", cache:false, async:false, success: function(res){ $('#value').replacewith("<div id='value'><h6>Tuner range is"+res+".</h6></div>"); } }); }); and this is my process file: //connect to database $dbc=mysql_connect(_SRV,_ACCID,_PWD) or die(_ERROR15.": ".mysql_error()); $db=mysql_select_db("qdbase",$dbc) or die(_ERROR17.": ".mysql_error()); switch(postVar('action')) { case 'tunermatches' : tunermatches(postVar('tversion')); break; function tunermatches($tversion)){ $Tuner=mysql_real_escape_string($tversion); $sql= "SELECT remark FROM settingdata WHERE itemname='Tuner_range' AND itemdata='".$Tunermatches."'"; $res=mysql_query($sql) or die (_ERROR26.":".mysql_error()); $dat=mysql_fetch_array($res,MYSQL_NUM); if($dat[0]>0) { echo $dat[0]; } mysql_close($dbc); }

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  • Ajax div can't access address bar variable

    - by Elaine Adams
    Can someone please advise me on how my Ajax div can get an address bar variable. The usual way just doesn't work. My address bar currently looks like this: http://localhost/social3/browse/?locationName=Cambridge Usually, I would use a little php and do this: $searchResult = $_POST['locationName']; echo $searchResult; But because I'm in an Ajax div, I can't seem to get to the variable. Do I need to add some JavaScript wizardry to my Ajax coding? (I have little knowledge of this) My Ajax: <script> window.onload = function () { var everyone = document.getElementById('everyone'), searching = document.getElementById('searching'), searchingSubmit = document.getElementById('searchingSubmit'); everyone.onclick = function() { loadXMLDoc('indexEveryone'); everyone.className = 'filterOptionActive'; searching.className = 'filterOption'; } searching.onclick = function() { loadXMLDoc('indexSearching'); searching.className = 'filterOptionActive'; everyone.className = 'filterOption'; } searchingSubmit.onclick = function() { loadXMLDoc('indexSearchingSubmit'); } function loadXMLDoc(pageName) { var xmlhttp; if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); } else {// code for IE6, IE5 xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4 && xmlhttp.status==200) { document.getElementById("leftCont").innerHTML=xmlhttp.responseText; } } function get_query(){ var url = location.href; var qs = url.substring(url.indexOf('?') + 1).split('&'); for(var i = 0, result = {}; i < qs.length; i++){ qs[i] = qs[i].split('='); result[qs[i][0]] = decodeURIComponent(qs[i][1]); } return result; } xmlhttp.open("GET","../browse/" + pageName + ".php?user=" + get_query()['user'],true); xmlhttp.send(); } } </script> <!-- ends ajax script -->

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  • PHP MySQLi isn't letting me alter a table (adding a new column)

    - by asdasd
    Well thats pretty much it. This is my query: $query = 'ALTER TABLE permissions ADD '.$name.' INT NOT NULL DEFAULT \'0\''; Where $name is already checked to exist with only lower case alpha letters, and not more than 20 length. Im just starting this out with very simple names. The next 4 lines of code after that one are: if($stmt = $db -> prepare($query)) { $success = $stmt -> execute(); $stmt -> close(); if(!$success) echo 'ERROR: Unsuccessful query: ',$db->error,PHP_EOL; } And I get back, every time ERROR: Unsuccessful query: And no error message. Is there a way to get more error messages so I can see what is failing? I can add new columns through phpmyadmin, but that really doesnt help me at all. The $db is fine, i do lots of stuff before and after this one section. It is only adding new column to the table that fails. side question: prepare() rejected my query every time when i tried to make those 2 variables, the $name and the 0 value as ? ? prepared statement values. Thats why they are in the real query and not bound later. If i could change that too I would like that.

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  • jQuery replaceWith(data) is not correctly doing his job

    - by Tristan
    Hello, i did a small ajax div refresh, but instead of replacing the values with the new ones, jquery adds the new data before the old ones. What possibily causes that please ? <script type="text/javascript"> $(document).ready(function(){ $('#AJAX').click(function(e){ e.preventDefault(); var hebergeur = $('#hebergeurJQUERY').val(); $.post("/statistiques/maj-bloc-commentaires.php", { hebergeur : hebergeur }, function(data){ // déclenchée seulement si succès $("#TOREPLACE").replaceWith(data).val( ); }); }); }); </script> The HTML : print '<div id="a_remplacer"> <div class="detail_commentaires"> <table class="tableau_detail_commentaires"> <tr> <td class="tab_space">Serveur <strong>'.$row['type'].'</strong></td> <td>Qualite</td> <td style="color:'.$c_vote.'">'.htmlentities($row['vote']).'</td> </tr> </div> </div> The PHP ajax echo : print '<div id="a_remplacer"><div class="detail_commentaires" > <table class="tableau_detail_commentaires"> <tr> <td class="tab_space">Serveur <strong>'.$row['type'].'</strong></td> <td>Qualite</td> <td style="color:'.$c_vote.'">'.htmlentities($row['vote']).'</td> </tr></div></div> Thanks

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  • Getting an non-object error in my php script

    - by Disowned
    Hey I was trying to call a script to made some changes to an html file, however when I run the script it tells me that it's making a call to a non-object. Obviously I did something wrong, but what? Here's the script. /*Dom controllers*/ $dom = new DOMDocument(); $dom->loadHTML('index.html'); $id = $dom->getElementById('contact_us'); $p = $dom->appendChild(new DOMElement('p')); $op = $dom->getElementsByTagName('p'); /* Dem POST vars used by dat Ajax mah ziggen, yeah boi*/ if (isset($_POST['Home']) && isset($_POST['About']) && isset($_POST['Contact']) && isset($_POST['sexyText'])){ $home = $_POST['Home']; $about = $_POST['About']; $contact = $_POST['Contact']; $text = $_POST['sexyText']; trim($home); trim($about); trim($contact); trim($text); } function post(){ global $dom, $id, $home, $about, $contact, $text, $textp, $p, $op; $textp = $dom->createTextNode($text); $p->appendChild($textp); $id->replaceChild($p, $op); $dom->saveHTMLFile('index.html'); } post(); echo 1; ?> The error happens at the replaceChild function.

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  • I need to sort php jquery gallery script alphabetically

    - by David Cahill
    know nothing about php, but I have this script that reads a folder and displays a thumbnail gallery, problem is it dosent display alphabetically. Have searched the net and seen that sort does this but have no idea where to start any help would be much appreciated. heres the script $sitename = $row_wigsites['id']; $directory = 'sites/'.$sitename.'/pans'; $allowed_types=array('jpg','jpeg','gif','png'); $file_parts=array(); $ext=''; $title=''; $i=0; $dir_handle = @opendir($directory) or die("There is an error with your image directory!"); while ($file = readdir($dir_handle)) { if($file=='.' || $file == '..') continue; $file_parts = explode('.',$file); $ext = strtolower(array_pop($file_parts)); $title = implode('.',$file_parts); $title = htmlspecialchars($title); $nomargin=''; if(in_array($ext,$allowed_types)) { if(($i+1)%4==0) $nomargin='nomargin'; echo ' <div class="pic '.$nomargin.'" style="background:url('.$directory.'/'.$file.') no-repeat 50% 50%;"> <a href="'.$directory.'/'.$file.'" title="Panoramic Stills taken at '.$title.'°" rel="pan1" target="_blank">'.$title.'</a> </div>'; $i++; } } closedir($dir_handle);

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  • php - create columns from mysql list

    - by user271619
    I have a long list generated from a simple mysql select query. Currently (shown in the code below) I am simply creating list of table rows with each record. So, nothing complicated. However, I want to divide it into more than one column, depending on the number of returned results. I've been wrapping my brain around how to count this in the php, and I'm not getting the results I need. <table> <? $query = mysql_query("SELECT * FROM `sometable`"); while($rows = mysql_fetch_array($query)){ ?> <tr> <td><?php echo $rows['someRecord']; ?></td> </tr> <? } ?> </table> Obviously there's one column generated. So if the records returned reach 10, then I want to create a new column. In other words, if the returned results are 12, I have 2 columns. If I have 22 results, I'll have 3 columns, and so on.

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