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  • Which part of this simple script is breaking internet explorer?

    - by user961627
    I'm writing a simple virtual keyboard for Arabic (indic) digits. Just links that, when clicked, produce the corresponding Unicode Indic character. The following is my HTML, in the body tag: <a href="#" id='start'>Start</a> <div id='vkb' style='padding:20px;font-size:16pt; border:2px solid #eee; width:250px' dir='ltr'> <a class='key' href='#' id='0'>&#1632;</a> <a class='key' href='#' id='1'>&#1633;</a> <a class='key' href='#' id='2'>&#1634;</a> <a class='key' href='#' id='3'>&#1635;</a> <a class='key' href='#' id='4'>&#1636;</a><br /> <a class='key' href='#' id='5'>&#1637;</a> <a class='key' href='#' id='6'>&#1638;</a> <a class='key' href='#' id='7'>&#1639;</a> <a class='key' href='#' id='8'>&#1640;</a> <a class='key' href='#' id='9'>&#1641;</a> <br /> <a href="#" id='stop'>Stop</a> </div> <div id='output' /></div> This is my CSS: a { text-decoration:none; } .key { padding:7px; background-color:#fff; margin:5px; border:2px solid #eee; display:inline-block; } .key:hover { background-color:#eee; } And this is my javascript: <script type="text/javascript" src="js/jquery.js"></script> <script> $(document).ready(function(){ var toprint = ""; $('#vkb').hide(); $('#start').click(function(e){ toprint = ""; $('#vkb').show(); }); $('#stop').click(function(e){ $('#vkb').hide(); ret = ar2ind(toprint); $('#output').text(ret); toprint = ""; }); $('#vkb').click(function(e){ var $key = $(e.target).closest('.key'); var pressed = $key.attr('id'); if(pressed === undefined){ pressed = ""; } toprint = toprint + pressed; }); }); function ar2ind(str) { str = str.replace(/0/g, "?"); str = str.replace(/1/g, "?"); str = str.replace(/2/g, "?"); str = str.replace(/3/g, "?"); str = str.replace(/4/g, "?"); str = str.replace(/5/g, "?"); str = str.replace(/6/g, "?"); str = str.replace(/7/g, "?"); str = str.replace(/8/g, "?"); str = str.replace(/9/g, "?"); return str; } </script> It seems simple enough but it's crashing in IE9. (Might be crashing in earlier versions too but haven't been able to check.)

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  • Capistrano asks for SSH password when deploying from local machine to server

    - by GhostRider
    When I try to ssh to a server, I'm able to do it as my id_rsa.pub key is added to the authorized keys in the server. Now when I try to deploy my code via Capistrano to the server from my local project folder, the server asks for a password. I'm unable to understand what could be the issue if I'm able to ssh and unable to deploy to the same server. $ cap deploy:setup "no seed data" triggering start callbacks for `deploy:setup' * 13:42:18 == Currently executing `multistage:ensure' *** Defaulting to `development' * 13:42:18 == Currently executing `development' * 13:42:18 == Currently executing `deploy:setup' triggering before callbacks for `deploy:setup' * 13:42:18 == Currently executing `db:configure_mongoid' * executing "mkdir -p /home/deploy/apps/development/flyingbird/shared/config" servers: ["dev1.noob.com", "176.9.24.217"] Password: Cap script: # gem install capistrano capistrano-ext capistrano_colors begin; require 'capistrano_colors'; rescue LoadError; end require "bundler/capistrano" # RVM bootstrap # $:.unshift(File.expand_path('./lib', ENV['rvm_path'])) require 'rvm/capistrano' set :rvm_ruby_string, 'ruby-1.9.2-p290' set :rvm_type, :user # or :user # Application setup default_run_options[:pty] = true # allow pseudo-terminals ssh_options[:forward_agent] = true # forward SSH keys (this will use your SSH key to get the code from git repository) ssh_options[:port] = 22 set :ip, "dev1.noob.com" set :application, "flyingbird" set :repository, "repo-path" set :scm, :git set :branch, fetch(:branch, "master") set :deploy_via, :remote_cache set :rails_env, "production" set :use_sudo, false set :scm_username, "user" set :user, "user1" set(:database_username) { application } set(:production_database) { application + "_production" } set(:staging_database) { application + "_staging" } set(:development_database) { application + "_development" } role :web, ip # Your HTTP server, Apache/etc role :app, ip # This may be the same as your `Web` server role :db, ip, :primary => true # This is where Rails migrations will run # Use multi-staging require "capistrano/ext/multistage" set :stages, ["development", "staging", "production"] set :default_stage, rails_env before "deploy:setup", "db:configure_mongoid" # Uncomment if you use any of these databases after "deploy:update_code", "db:symlink_mongoid" after "deploy:update_code", "uploads:configure_shared" after "uploads:configure_shared", "uploads:symlink" after 'deploy:update_code', 'bundler:symlink_bundled_gems' after 'deploy:update_code', 'bundler:install' after "deploy:update_code", "rvm:trust_rvmrc" # Use this to update crontab if you use 'whenever' gem # after "deploy:symlink", "deploy:update_crontab" if ARGV.include?("seed_data") after "deploy", "db:seed" else p "no seed data" end #Custom tasks to handle resque and redis restart before "deploy", "deploy:stop_workers" after "deploy", "deploy:restart_redis" after "deploy", "deploy:start_workers" after "deploy", "deploy:cleanup" 'Create symlink for public uploads' namespace :uploads do task :symlink do run <<-CMD rm -rf #{release_path}/public/uploads && mkdir -p #{release_path}/public && ln -nfs #{shared_path}/public/uploads #{release_path}/public/uploads CMD end task :configure_shared do run "mkdir -p #{shared_path}/public" run "mkdir -p #{shared_path}/public/uploads" end end namespace :rvm do desc 'Trust rvmrc file' task :trust_rvmrc do run "rvm rvmrc trust #{current_release}" end end namespace :db do desc "Create mongoid.yml in shared path" task :configure_mongoid do db_config = <<-EOF defaults: &defaults host: localhost production: <<: *defaults database: #{production_database} staging: <<: *defaults database: #{staging_database} EOF run "mkdir -p #{shared_path}/config" put db_config, "#{shared_path}/config/mongoid.yml" end desc "Make symlink for mongoid.yml" task :symlink_mongoid do run "ln -nfs #{shared_path}/config/mongoid.yml #{release_path}/config/mongoid.yml" end desc "Fill the database with seed data" task :seed do run "cd #{current_path}; RAILS_ENV=#{default_stage} bundle exec rake db:seed" end end namespace :bundler do desc "Symlink bundled gems on each release" task :symlink_bundled_gems, :roles => :app do run "mkdir -p #{shared_path}/bundled_gems" run "ln -nfs #{shared_path}/bundled_gems #{release_path}/vendor/bundle" end desc "Install bundled gems " task :install, :roles => :app do run "cd #{release_path} && bundle install --deployment" end end namespace :deploy do task :start, :roles => :app do run "touch #{current_path}/tmp/restart.txt" end desc "Restart the app" task :restart, :roles => :app do run "touch #{current_path}/tmp/restart.txt" end desc "Start the workers" task :stop_workers do run "cd #{current_path}; RAILS_ENV=#{default_stage} bundle exec rake resque:stop_workers" end desc "Restart Redis server" task :restart_redis do "/etc/init.d/redis-server restart" end desc "Start the workers" task :start_workers do run "cd #{current_path}; RAILS_ENV=#{default_stage} bundle exec rake resque:start_workers" end end

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  • Using jQuery to Insert a New Database Record

    - by Stephen Walther
    The goal of this blog entry is to explore the easiest way of inserting a new record into a database using jQuery and .NET. I’m going to explore two approaches: using Generic Handlers and using a WCF service (In a future blog entry I’ll take a look at OData and WCF Data Services). Create the ASP.NET Project I’ll start by creating a new empty ASP.NET application with Visual Studio 2010. Select the menu option File, New Project and select the ASP.NET Empty Web Application project template. Setup the Database and Data Model I’ll use my standard MoviesDB.mdf movies database. This database contains one table named Movies that looks like this: I’ll use the ADO.NET Entity Framework to represent my database data: Select the menu option Project, Add New Item and select the ADO.NET Entity Data Model project item. Name the data model MoviesDB.edmx and click the Add button. In the Choose Model Contents step, select Generate from database and click the Next button. In the Choose Your Data Connection step, leave all of the defaults and click the Next button. In the Choose Your Data Objects step, select the Movies table and click the Finish button. Unfortunately, Visual Studio 2010 cannot spell movie correctly :) You need to click on Movy and change the name of the class to Movie. In the Properties window, change the Entity Set Name to Movies. Using a Generic Handler In this section, we’ll use jQuery with an ASP.NET generic handler to insert a new record into the database. A generic handler is similar to an ASP.NET page, but it does not have any of the overhead. It consists of one method named ProcessRequest(). Select the menu option Project, Add New Item and select the Generic Handler project item. Name your new generic handler InsertMovie.ashx and click the Add button. Modify your handler so it looks like Listing 1: Listing 1 – InsertMovie.ashx using System.Web; namespace WebApplication1 { /// <summary> /// Inserts a new movie into the database /// </summary> public class InsertMovie : IHttpHandler { private MoviesDBEntities _dataContext = new MoviesDBEntities(); public void ProcessRequest(HttpContext context) { context.Response.ContentType = "text/plain"; // Extract form fields var title = context.Request["title"]; var director = context.Request["director"]; // Create movie to insert var movieToInsert = new Movie { Title = title, Director = director }; // Save new movie to DB _dataContext.AddToMovies(movieToInsert); _dataContext.SaveChanges(); // Return success context.Response.Write("success"); } public bool IsReusable { get { return true; } } } } In Listing 1, the ProcessRequest() method is used to retrieve a title and director from form parameters. Next, a new Movie is created with the form values. Finally, the new movie is saved to the database and the string “success” is returned. Using jQuery with the Generic Handler We can call the InsertMovie.ashx generic handler from jQuery by using the standard jQuery post() method. The following HTML page illustrates how you can retrieve form field values and post the values to the generic handler: Listing 2 – Default.htm <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Add Movie</title> <script src="http://ajax.microsoft.com/ajax/jquery/jquery-1.4.2.js" type="text/javascript"></script> </head> <body> <form> <label>Title:</label> <input name="title" /> <br /> <label>Director:</label> <input name="director" /> </form> <button id="btnAdd">Add Movie</button> <script type="text/javascript"> $("#btnAdd").click(function () { $.post("InsertMovie.ashx", $("form").serialize(), insertCallback); }); function insertCallback(result) { if (result == "success") { alert("Movie added!"); } else { alert("Could not add movie!"); } } </script> </body> </html>     When you open the page in Listing 2 in a web browser, you get a simple HTML form: Notice that the page in Listing 2 includes the jQuery library. The jQuery library is included with the following SCRIPT tag: <script src="http://ajax.microsoft.com/ajax/jquery/jquery-1.4.2.js" type="text/javascript"></script> The jQuery library is included on the Microsoft Ajax CDN so you can always easily include the jQuery library in your applications. You can learn more about the CDN at this website: http://www.asp.net/ajaxLibrary/cdn.ashx When you click the Add Movie button, the jQuery post() method is called to post the form data to the InsertMovie.ashx generic handler. Notice that the form values are serialized into a URL encoded string by calling the jQuery serialize() method. The serialize() method uses the name attribute of form fields and not the id attribute. Notes on this Approach This is a very low-level approach to interacting with .NET through jQuery – but it is simple and it works! And, you don’t need to use any JavaScript libraries in addition to the jQuery library to use this approach. The signature for the jQuery post() callback method looks like this: callback(data, textStatus, XmlHttpRequest) The second parameter, textStatus, returns the HTTP status code from the server. I tried returning different status codes from the generic handler with an eye towards implementing server validation by returning a status code such as 400 Bad Request when validation fails (see http://www.w3.org/Protocols/rfc2616/rfc2616-sec10.html ). I finally figured out that the callback is not invoked when the textStatus has any value other than “success”. Using a WCF Service As an alternative to posting to a generic handler, you can create a WCF service. You create a new WCF service by selecting the menu option Project, Add New Item and selecting the Ajax-enabled WCF Service project item. Name your WCF service InsertMovie.svc and click the Add button. Modify the WCF service so that it looks like Listing 3: Listing 3 – InsertMovie.svc using System.ServiceModel; using System.ServiceModel.Activation; namespace WebApplication1 { [ServiceBehavior(IncludeExceptionDetailInFaults=true)] [ServiceContract(Namespace = "")] [AspNetCompatibilityRequirements(RequirementsMode = AspNetCompatibilityRequirementsMode.Allowed)] public class MovieService { private MoviesDBEntities _dataContext = new MoviesDBEntities(); [OperationContract] public bool Insert(string title, string director) { // Create movie to insert var movieToInsert = new Movie { Title = title, Director = director }; // Save new movie to DB _dataContext.AddToMovies(movieToInsert); _dataContext.SaveChanges(); // Return movie (with primary key) return true; } } }   The WCF service in Listing 3 uses the Entity Framework to insert a record into the Movies database table. The service always returns the value true. Notice that the service in Listing 3 includes the following attribute: [ServiceBehavior(IncludeExceptionDetailInFaults=true)] You need to include this attribute if you want to get detailed error information back to the client. When you are building an application, you should always include this attribute. When you are ready to release your application, you should remove this attribute for security reasons. Using jQuery with the WCF Service Calling a WCF service from jQuery requires a little more work than calling a generic handler from jQuery. Here are some good blog posts on some of the issues with using jQuery with WCF: http://encosia.com/2008/06/05/3-mistakes-to-avoid-when-using-jquery-with-aspnet-ajax/ http://encosia.com/2008/03/27/using-jquery-to-consume-aspnet-json-web-services/ http://weblogs.asp.net/scottgu/archive/2007/04/04/json-hijacking-and-how-asp-net-ajax-1-0-mitigates-these-attacks.aspx http://www.west-wind.com/Weblog/posts/896411.aspx http://www.west-wind.com/weblog/posts/324917.aspx http://professionalaspnet.com/archive/tags/WCF/default.aspx The primary requirement when calling WCF from jQuery is that the request use JSON: The request must include a content-type:application/json header. Any parameters included with the request must be JSON encoded. Unfortunately, jQuery does not include a method for serializing JSON (Although, oddly, jQuery does include a parseJSON() method for deserializing JSON). Therefore, we need to use an additional library to handle the JSON serialization. The page in Listing 4 illustrates how you can call a WCF service from jQuery. Listing 4 – Default2.aspx <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Add Movie</title> <script src="http://ajax.microsoft.com/ajax/jquery/jquery-1.4.2.js" type="text/javascript"></script> <script src="Scripts/json2.js" type="text/javascript"></script> </head> <body> <form> <label>Title:</label> <input id="title" /> <br /> <label>Director:</label> <input id="director" /> </form> <button id="btnAdd">Add Movie</button> <script type="text/javascript"> $("#btnAdd").click(function () { // Convert the form into an object var data = { title: $("#title").val(), director: $("#director").val() }; // JSONify the data data = JSON.stringify(data); // Post it $.ajax({ type: "POST", contentType: "application/json; charset=utf-8", url: "MovieService.svc/Insert", data: data, dataType: "json", success: insertCallback }); }); function insertCallback(result) { // unwrap result result = result["d"]; if (result === true) { alert("Movie added!"); } else { alert("Could not add movie!"); } } </script> </body> </html> There are several things to notice about Listing 4. First, notice that the page includes both the jQuery library and Douglas Crockford’s JSON2 library: <script src="Scripts/json2.js" type="text/javascript"></script> You need to include the JSON2 library to serialize the form values into JSON. You can download the JSON2 library from the following location: http://www.json.org/js.html When you click the button to submit the form, the form data is converted into a JavaScript object: // Convert the form into an object var data = { title: $("#title").val(), director: $("#director").val() }; Next, the data is serialized into JSON using the JSON2 library: // JSONify the data var data = JSON.stringify(data); Finally, the form data is posted to the WCF service by calling the jQuery ajax() method: // Post it $.ajax({   type: "POST",   contentType: "application/json; charset=utf-8",   url: "MovieService.svc/Insert",   data: data,   dataType: "json",   success: insertCallback }); You can’t use the standard jQuery post() method because you must set the content-type of the request to be application/json. Otherwise, the WCF service will reject the request for security reasons. For details, see the Scott Guthrie blog post: http://weblogs.asp.net/scottgu/archive/2007/04/04/json-hijacking-and-how-asp-net-ajax-1-0-mitigates-these-attacks.aspx The insertCallback() method is called when the WCF service returns a response. This method looks like this: function insertCallback(result) {   // unwrap result   result = result["d"];   if (result === true) {       alert("Movie added!");   } else {     alert("Could not add movie!");   } } When we called the jQuery ajax() method, we set the dataType to JSON. That causes the jQuery ajax() method to deserialize the response from the WCF service from JSON into a JavaScript object automatically. The following value is passed to the insertCallback method: {"d":true} For security reasons, a WCF service always returns a response with a “d” wrapper. The following line of code removes the “d” wrapper: // unwrap result result = result["d"]; To learn more about the “d” wrapper, I recommend that you read the following blog posts: http://encosia.com/2009/02/10/a-breaking-change-between-versions-of-aspnet-ajax/ http://encosia.com/2009/06/29/never-worry-about-asp-net-ajaxs-d-again/ Summary In this blog entry, I explored two methods of inserting a database record using jQuery and .NET. First, we created a generic handler and called the handler from jQuery. This is a very low-level approach. However, it is a simple approach that works. Next, we looked at how you can call a WCF service using jQuery. This approach required a little more work because you need to serialize objects into JSON. We used the JSON2 library to perform the serialization. In the next blog post, I want to explore how you can use jQuery with OData and WCF Data Services.

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  • How can I get my Web API app to run again after upgrading to MVC 5 and Web API 2?

    - by Clay Shannon
    I upgraded my Web API app to the funkelnagelneu versions using this guidance: http://www.asp.net/mvc/tutorials/mvc-5/how-to-upgrade-an-aspnet-mvc-4-and-web-api-project-to-aspnet-mvc-5-and-web-api-2 However, after going through the steps (it seems all this should be automated, anyway), I tried to run it and got, "A project with an Output Type of Class Library cannot be started directly" What in Sam Hills Brothers Coffee is going on here? Who said this was a class library? So I opened Project Properties, and changed it (it was marked as "Class Library" for some reason - it either wasn't yesterday, or was and worked fine) to an Output Type of "Windows Application" ("Console Application" and "Class Library" being the only other options). Now it won't compile, complaining: "*Program 'c:\Platypus_Server_WebAPI\PlatypusServerWebAPI\PlatypusServerWebAPI\obj\Debug\PlatypusServerWebAPI.exe' does not contain a static 'Main' method suitable for an entry point...*" How can I get my Web API app back up and running in view of this quandary? UPDATE Looking in packages.config, two entries seem chin-scratch-worthy: <package id="Microsoft.AspNet.Providers" version="1.2" targetFramework="net40" /> <package id="Microsoft.Web.Infrastructure" version="1.0.0.0" targetFramework="net40" /> All the others target net451. Could this be the problem? Should I remove these packages? UPDATE 2 I tried to uninstall the Microsoft.Web.Infrastructure package (its description leads me to believe I don't need it; also, it has no dependencies) via the NuGet package manager, but it tells me, "NuGet failed to install or uninstall the selected package in the following project(s). [mine]" UPDATE 3 I went through the steps in again, and found that I had missed one step. I had to change this entry in the Application web.config File : <dependentAssembly> <assemblyIdentity name="System.Web.Mvc" publicKeyToken="31bf3856ad364e35" /> <bindingRedirect oldVersion="1.0.0.0-5.0.0.0" newVersion="5.0.0.0" /> </dependentAssembly> (from "4.0.0.0" to "5.0.0.0") ...but I still get the same result - it rebuilds/compiles, but won't run, with "A project with an Output Type of Class Library cannot be started directly" UPDATE 4 Thinking about the err msg, that it can't directly open a class library, I thought, "Sure you can't/won't -- this is a web app, not a project. So I followed a hunch, closed the project, and reopened it as a website (instead of reopening a project). That has gotten me further, at least; now I see a YSOD: Could not load file or assembly 'System.Web.WebPages.Razor, Version=3.0.0.0, Culture=neutral, PublicKeyToken=31bf3856ad364e35' or one of its dependencies. The system cannot find the file specified. UPDATE 5 Note: The project is now (after being opened as a web site) named "localhost_48614" And...there is no longer a "References" folder...?!?!? As to that YSOD I'm getting, the official instructions (http://www.asp.net/mvc/tutorials/mvc-5/how-to-upgrade-an-aspnet-mvc-4-and-web-api-project-to-aspnet-mvc-5-and-web-api-2) said to do this, and I quote: "Update all elements that contain “System.Web.WebPages.Razor” from version “2.0.0.0” to version“3.0.0.0”." UPDATE 6 When I select Tools Library Package Manager Manage NuGet Packages for Solution now, I get, "Operation failed. Unable to locate the solution directory. Please ensure that the solution has been saved." So I save it, and it saves it with this funky new name (C:\Users\clay\Documents\Visual Studio 2013\Projects\localhost_48614\localhost_48614.sln) I get the Yellow Strip of Enlightenment across the top of the NuGet Package Manager telling me, "Some NuGet packages are missing from this solution. Click to restore from your online package sources." I do (click the "Restore" button, that is), and it downloads the missing packages ... I end up with the 30 packages. I try to run the app/site again, and ... the erstwhile YSOD becomes a compilation error: The pre-application start initialization method Start on type System.Web.Mvc.PreApplicationStartCode threw an exception with the following error message: Could not load file or assembly 'System.Web.WebPages.Razor, Version=3.0.0.0, Culture=neutral, PublicKeyToken=31bf3856ad364e35' or one of its dependencies. The system cannot find the file specified.. Argghhhh!!! (and it's not even talk-like-a-pirate day).

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  • Help! I got a runaway PHP script. My server is down.

    - by gAMBOOKa
    I got a PHP script that is looping and will continue to do so for about another hour. How do I stop it. The script explicitly overrides the time out and the memory buffer. It's on a shared hosting server with cPanel installed. The entire website is down until the script completes. I had added a usleep(100000) statement, but it doesn't appear to work.

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  • How to run a shell command and selectively ignore the status?

    - by Walter Nissen
    I've got a shell script that I would like to stop with an error on nonzero status most of the time, but in some cases I want to ignore it. For example: #!/bin/tcsh -vxef cp file/that/might/not/exist . #Want to ignore this status cp file/that/might/not/exist . ; echo "this doesn't work" cp file/that/must/exist . #Want to stop if this status is nonzero

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  • Why am I getting a 403 error on a POST to a PHP script?

    - by John Gallagher
    Background I want to allow my users to submit a crash report which will get emailed to me. I'm using UKCrashReporter with the bundled PHP script I've modified. This code does a POST to a specified URL along with the crash report. I'm on a shared server running Linux. My main domain is synapticmishap.co.uk. The Problem When I send the crash report off, on the Cocoa side, it reports as having sent it successfully, but I don't receive an email. The code has been used in lots of other well established Cocoa projects and it was working for me a few months ago. That leads me to conclude that the problems are related to my web server setup, something I know almost nothing about. When I look at my log files, I see entries like this: IP Redacted - - [10/Jun/2010:09:47:53 +0100] "POST /synapticmishap/crashreportform.php HTTP/1.1" 403 74 "-" "UKCrashReporter" What I've tried I've tried accessing the page at http://synapticmishap.co.uk/synapticmishap/crashreportform.php via a browser. It loads fine. I've made sure the permissions on this php script are set so anyone can execute it. I've tried removing the deny entries from the section of .htaccess at various levels starting with root. I've downloaded the URLParams plugin for Firefox which allows you to simulate POSTs. I put in the URL above and tried a post with "crashlog" as the parameter and "test" as the value. This generated a 200 log entry in my log file - it seemed to work, although no mail message was sent. Code I've got the following at http://synapticmishap.co.uk/synapticmishap/crashreportform.php. I've simplified it to just the bare bones in an effort to get it working. <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd"> <html> <head> <title>Crash Report</title> </head> <body> <p>This page contains super special magic which submits a crash report item to me.</p> <p>Nothing to see here - move along.</p> <?php mail( "[email protected]", "Crash Report", "\r\n\r\nThis is a test."); ?> </body> </html> This is my top level .htaccess file: RewriteEngine on # -FrontPage- IndexIgnore .htaccess */.??* *~ *# */HEADER* */README* */_vti* <Limit GET POST> order deny,allow deny from all allow from all </Limit> <Limit PUT DELETE> order deny,allow deny from all </Limit> Options All -Indexes RewriteCond %{HTTP_HOST} ^synapticmishap.co.uk$ [OR] RewriteCond %{HTTP_HOST} ^www.synapticmishap.co.uk$ RewriteCond %{HTTP_HOST} ^lapsusapp.co.uk$ [OR] RewriteCond %{HTTP_HOST} ^www.lapsusapp.co.uk$ RewriteRule ^/?$ "http\:\/\/synapticmishap\.co\.uk\/synapticmishap\/lapsuspromo\/" [R=301,L] RewriteCond %{HTTP_HOST} ^jgtutoring.co.uk$ [OR] RewriteCond %{HTTP_HOST} ^www.jgtutoring.co.uk$ RewriteRule ^/?$ "http\:\/\/synapticmishap\.co\.uk\/tutoring" [R=301,L] RewriteCond %{HTTP_HOST} ^synapticmishap.co.uk$ [OR] RewriteCond %{HTTP_HOST} ^www.synapticmishap.co.uk$ RewriteRule ^/?$ "http\:\/\/synapticmishap\.co\.uk\/synapticmishap" [R=301,L] RewriteCond %{HTTP_HOST} ^jgediting.co.uk$ [OR] RewriteCond %{HTTP_HOST} ^www.jgediting.co.uk$ RewriteRule ^/?$ "http\:\/\/synapticmishap\.co\.uk\/editing" [R=301,L] RewriteCond %{HTTP_REFERER} !^$ RewriteCond %{HTTP_REFERER} !^http://synapticmishap.co.uk/.*$ [NC] RewriteCond %{HTTP_REFERER} !^http://synapticmishap.co.uk$ [NC] RewriteCond %{HTTP_REFERER} !^http://www.synapticmishap.co.uk/.*$ [NC] RewriteCond %{HTTP_REFERER} !^http://www.synapticmishap.co.uk$ [NC] RewriteCond %{HTTP_REFERER} !^http://synapticmishap.co.uk/synapticmishap/crashreportform.php/.*$ [NC] RewriteCond %{HTTP_REFERER} !^http://synapticmishap.co.uk/synapticmishap/crashreportform.php$ [NC] RewriteRule .*\.(jpg|jpeg|gif|png|bmp)$ - [F,NC] Help! I'm at the end of my tether with this and I'm in a very unfamiliar space with all this web stuff. I'd be most appreciative of any thoughts people had on why this isn't working. Thanks.

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  • Run Sinatra via a Rake Task to Generate Static Files?

    - by viatropos
    I'm not sure I can put this correctly but I'll give it a shot. I want to use Sinatra to generate static html files once I am ready to deploy an application, so the resulting final website would be pure static HTML. During development, however, I want everything to be dynamic so I can use Haml and straight Ruby code to make things fast/dry/clear. I don't want to use Jekyll or some of the other static site generators out there because they don't have as much power as Sinatra. So all I basically need to be able to do is run a rake task such as: rake sinatra:generate_static_files. That would run the render commands for Haml and everything else, and the result would be written to files. My question is, how do I do that with Sinatra in a Rake task? Can I do it in a Rake task? The problem is, I don't know how to include the Sinatra::Application in the rake task... The only other way I could think of doing it is using net/http to access a URL that does all of that, but that seems like overkill. Any ideas how on to solve this?

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  • Java error: Bad version number in .class file error when trying to run Cassandra on OS X

    - by Sam Lee
    I am trying to get Cassandra to work on OS X. When I run bin/cassandra, I get the following error: ~/apache-cassandra-incubating-0.4.1-src > bin/cassandra -f Listening for transport dt_socket at address: 8888 Exception in thread "main" java.lang.UnsupportedClassVersionError: Bad version number in .class file at java.lang.ClassLoader.defineClass1(Native Method) at java.lang.ClassLoader.defineClass(ClassLoader.java:675) at java.security.SecureClassLoader.defineClass(SecureClassLoader.java:124) at java.net.URLClassLoader.defineClass(URLClassLoader.java:260) at java.net.URLClassLoader.access$100(URLClassLoader.java:56) at java.net.URLClassLoader$1.run(URLClassLoader.java:195) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(URLClassLoader.java:188) at java.lang.ClassLoader.loadClass(ClassLoader.java:316) at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:280) at java.lang.ClassLoader.loadClass(ClassLoader.java:251) at java.lang.ClassLoader.loadClassInternal(ClassLoader.java:374) From what I could determine by searching, this error is related to incompatible versions of Java. However, as far as I can tell, I have the latest version of Java: ~/apache-cassandra-incubating-0.4.1-src > java -version java version "1.6.0_13" Java(TM) SE Runtime Environment (build 1.6.0_13-b03-211) Java HotSpot(TM) 64-Bit Server VM (build 11.3-b02-83, mixed mode) ~/apache-cassandra-incubating-0.4.1-src > javac -version javac 1.6.0_13 ~/Downloads/apache-cassandra-incubating-0.4.1-src > echo $JAVA_HOME /System/Library/Frameworks/JavaVM.framework/Versions/1.6/Home Any ideas on what I'm doing wrong?

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